Tank Pneumatic Testing Equations

March 27, 2018 | Author: Doug Phillips | Category: Shell (Projectile), Pound (Mass), Pressure, Materials, Energy And Resource


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ASME PCC-2–2011 Article 5.1, Mandatory Appendix II Stored Energy Calculations for Pneumatic Pressure Test 0.286 ] E= 360 x Pat x V[1-(Pa/Pat) Pa= Absolute atmospheric pressure = PRV setting: Pat= Absolute Test pressure = Tank Demensions Outside Shell ID Inside Shell OD Inside Shell ID Height Distance to interior wall A b a 14.7 psia 3 psig 17.7 psia 119.8125 114.1875 114 96 79.5 70.9 0.70 0.76 in in in in in ft 2 V1= Space between the two shells V2= Water storage V3= methanol Storage 57.43224 ft3 430.9637 ft3 136.0938 ft3 69.15311 sft3 518.9155 sft3 163.868 sft3 based on 50 SCFM 1.38 mins to fill 10.38 mins to fill 3.28 mins to fill Presently compressor is supplying approx. 450 SCFM based on fill times E1= E2= E3= TNT equilivant 1= TNT equilivant 2= TNT equilivant 3= 18930.71 ft lbs 142053.4 ft lbs 44858.98 ft lbs 0.013 Pounds 0.095 Pounds 0.030 Pounds 0.010 pounds of Dynamite 0.076 pounds of Dynamite 0.024 pounds of Dynamite Though both trinitrotoluene (TNT) and dynamite are high explosives, there is little similarity between them. Dynamite is an absorbent mixture soaked in nitroglycerin then compacted into a cylindrical shape and wrapped in paper. TNT is a chemical compound called 2,4,6-trinitrotoluene. The energy density (joules/kilogram or J/kg) of dynamite is approximately 5 MJ/kg, compared to 4.0 MJ/kg of TNT (for TNT r.e.factor=1.00; for Nobel dynamite r.e. factor=1.25;). Dynamite is usually sold in the form of cylinders about 8 in (20 cm) long and about 1.25 in (3.2 cm) in diameter, with a weight of about 0.5 lb A stick of dynamite (0.19 kg, 75% nitroglycerin, no other explosives in the mixture of dynamite) contains roughly 1 MJ of energy. ( 737,000 ft lbs) .28 ft = 1/3 equil = Volume 3 R = 50 (TNT)1/3equil = R = 30 (TNT) R = 15(TNT) R = 5 (TNT) 1/3 equil = 1/3 equil 15.1. an alternative value for Rscaled may be chosen based on Table III-1 for use in the equation.85 ft 13.000 ft-lb R =200 ft for 100. If the minimum calc.000 ft-lb (b) the following equation: R = Rscaled (TNT)1/3equil where Rscaled = scaled consequence factor Value shall be 50 ft/lb1⁄3 or greater.000 < E ≤ 200.71 ft 6.000.. Eardrum rupture Lung damage Fatal Structural Failure Glass windows Concrete block panels Brick walls . dist.56 ft 9.85 ft 2.50 ft 1. Table III-1 Alternative Values for Rscaled Rscaled Volume 1 R = 50 (TNT)1/3equil = R = 30 (TNT) R = 15(TNT) R = 5 (TNT) 1/3 equil = 1/3 equil 11. Mandatory Appendix III Safe Distance Calculations for Pneumatic Pressure Test The minimum distance between all personnel and the equipment being tested shall be the greater of (a) the following: R = 100 ft for E < 100...Article 5.67 ft 1.56 ft = 1/3 equil = .34 ft 4.000.00 ft 3. = 1/3 equil = Volume 2 1/3 R = 50 (TNT) equil = R = 30 (TNT) R = 15(TNT) R = 5 (TNT) 1/3 equil = 1/3 equil 22. cannot be obtained.000.17 ft ft/lb 50 30 15 5 1/3 Biological Effect .67 ft 7.
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