7 inch2.5 inch NO MENC L ATU R E 2.5 inch 2.5 inch I N D E X Topic Page No. ORGANIC CHEMISTRY NOMENCLATURE 1. Common Name 01 2. Derived System 14 3. Nomenclature of Saturated unbranched hydrocarbon 17 4 Nomenclature of Saturated branched hydrocarbon 18 5. Nomenclature of Unsaturated unbranched hydrocarbon 22 6. Nomenclature of Unsaturated branched hydrocarbon 23 7. Nomenclature of Functional group compounds 26 8. Nomenclature of Polyfunctional group compounds 32 9. Nomenclature ofAlicyclic/Cyclic compounds 39 10. Nomenclature of Bicyclo compounds 41 11. Nomenclature of Spiro compounds 42 12. Exercise - 1 46 Exercise - 2 53 Exercise - 3 58 Exercise - 4 61 13. Answer Key 63 14. Hints/Solution 64 NO MENC L ATU R E e.I. 4. BANSAL CLASSES Private Ltd. Vinegar Oxalic acid Obtained from oxalis plant. NH2CONH2 Wood spirit or Methyl spirit Urea Obtained by destructive distillation of wood. 11. ‘Gaurav Tower’. Kota-05 .A. C2H5OH Grain alcohol Obtained from barley.1 ACC. Source | OH 8.i. Obtained from urine 3. Road No. CH4 Marsh gas (fire damp) It was produced in marsh places. A-10. CH 3 – CH – COOH 5. S. Formic acid Obtained from formicus [Red ant] Lactic acid Obtained from lactous (milk) 6. CH3OH 2.CH-NOMENCLATURE NOMENCLATURE OF ORGANIC COMPOUNDS Mainly three systems are adopted for naming an organic compound : – (i) (ii) (iii) Common Names or Trivial System Derived System IUPAC system or Geneva System COMMON OR TRIVIAL SYSTEM On the basis of Source Property Discovery Structure (i) On the basis of source from which they were obtained.P. COOH | COOH HCOOH 7. I. 10. Organic Compound Trivial Name 1. CH 2 – COOH | CH(OH)COOH Malic acid Obtain from Apple 9 CH3CH2CH2COOH Butyric acid Obtained from butter.No. CH3COOH Vinegar Obtained from Acetum . CH3(CH2)4COOH Caproic acid Obtained from goats..-1. -) BANSAL CLASSES Private Ltd. R2Zn (Frankland reagent) (iv) On the basis of structure S.A. Glycol . A-10..CH-NOMENCLATURE (ii) On the basis of property 1. 5.Sweet poisnous 2. 3. 2. R–O–R’ Alkyl alkyl’ ether 10.Sweet in test 3. Road No. Glucose . Compound Name 1. 11. R–X R – OH R – SH R – NH2 R–O–R Alkyl halide Alkyl alcohol Alkyl thio alcohol Alkyl amine Dialkyl ether 6. RMgx (Grigard Reagent) 2. 8. Alkyl alkyl’ ketone R–NH–R’ Alkyl alkyl’ amine Alkyl alkyl’ alkyl” amine R is termed as alkyl . (i) (ii) (iii) (iv) (v) (vi) (vii) (viii) (ix) (x) No. ‘Gaurav Tower’. 4.No. 12.I.2 ACC.-1. of Carbon atom 1C 2C 3C 4C 5C 6C 7C 8C 9C 10C Word Root Meth Eth Prop But Pent Hex Hept Oct Non Dec Common Names for Hydrocarbon Derivatives S.P. Glycerol .Sweet) (iii) On the basis of discovery 1. I. Dialkyl ketone 7. Kota-05 .Sweet (Glycus .No. R–NH–R Dialkyl amine Trialkyl amine 9. NOTE : (Optically Active) = If all valency are attached to different atoms.CH-NOMENCLATURE GROUPS Atom or a group of atoms which possess any ‘free valency’ are called as Groups.A.3 ACC.. ‘Gaurav Tower’. I.I.g. If their are two structure of same molecular formula then some prefix (n. Road No. iso. (b) It is represented by following structure - (c) C | CCC | C for eg. neo) are used two differentiate them. n – butyl CH3 – CH2 – CH2 – CH2 – n – propyl CH3 – CH2 – CH2 – Iso group : – When one methyl group is attached to the second last carbon of the straight carbon chain is named as iso group. A-10. Kota-05 CH3 CH CH | | CH3 CH3 Active iso secondary amyl .-1. (c) Free bond will come either on Ist carbon atom or on last carbon atom. Amyl group : – H | CH3 CH2 C CH2 | CH3 Active amyl CH3 CH2 CH – | CH2 | CH3 Secondary amyl CH3 CH2 CH2 CH | CH3 Active secondary amyl BANSAL CLASSES Private Ltd. C | CCC– | C Neo pentyl There should be one 4° carbon and atleast three methyl group on 4° carbon. CH 3 C H CH 2 H3 C CH | CH3 e. (b) Groups having no branch (Straight chain). Normal group : – (a) It is represented by ‘n’.P. CH 3 C H CH 2 CH 2 | | CH 3 Isopropyl CH 3 Isobutyl Isopentyl Exception : CH 3 CH 3 | | CH 3 C C H CH 2 CH 3 C CH 2 C H CH 2 | | | CH 3 CH 3 | CH 3 CH 3 (i) Iso octyl (ii) Iso heptyl Neo group : – (a) When two methyl groups on second last carbon of a straight carbon chain is attached to other four carbon atom group is named as neo group. I. Alkyl alkane H (CnH2n+2) (CnH2n+1) e. (i) CH 3 CH CH 2 CH 3 | (ii) CH 3 CH CH 2 CH 2 – CH 3 | (secondary butyl) (secondary pentyl) Tertiary group : – (a) The carbon having free valency attached to three other carbon . CH3 | | (i) CH3 C CH3 CH3 C CH2 CH3 | | (Tertiary butyl) (Tertiary pentyl) Alkyl group : – When a hydrogen is removed from Alkane (saturated hydrocarbon) then alkyl group is formed. ‘Gaurav Tower’. CH3 – (i) CH4 H Methane Methyl CH3–CH2 – (ii) CH3– CH3 H Ethane (iii) CH3–CH2–CH3 Propane ethyl –H CH3–CH 2–CH 2– n-Propyl CH3–CH–CH3 iso-Propyl (iv) CH3–CH2–CH2–CH3 n-Butane –H CH3–CH2–CH2–CH2– n-Butyl CH3–CH–CH2–CH3 Sec.. (b) It is represented by following structure. Butyl (v) CH 3–CH –CH3 –H CH3–CH–CH2– iso-butyl iso-butane CH3–C–CH3 tertiary-butyl BANSAL CLASSES Private Ltd.A.4 ACC.g. I.-1. Kota-05 . A bond is vacant on alkyl group on which any functional group may come. C | (b) It is represented by following structure - C C C | CH3 e. Road No.CH-NOMENCLATURE Secondary group : – (a) The carbon having free valency attached to two carbon is called secondary carbon.P. A-10. C C C C | eg.g. .CH-NOMENCLATURE CH3–CH2–CH2 –CH2 –CH2 – n-pentyl (vi) CH3–CH –CH2–CH2–CH3 n-pentane –H CH3–CH–CH2 –CH2 –CH3 active secondary amyl C2H5–CH–C2H5 secondary amyl CH3–CH–CH2–CH2– iso-pentyl CH3–C–CH2–CH3 –H (vii) tertiary-pentyl C2H5–CH–CH2– iso-pentane active amyl CH3–CH–CH– Active isosecondary amyl CH3 CH3 –H (viii) CH3 neo-pentane CH3 neo-pentyl Alkenyl group : – Alkenyl alkene H (CnH2n) CH2 = CH – Vinyl CH2= CH – CH2– Allyl (CnH2n–1) CH3 – CH = CH – Propenyl(1-propenyl) CH3 C CH2 | Isopropenyl (1-methyl-1-ethenyl) BANSAL CLASSES Private Ltd. A-10.P.I. Kota-05 . I.A.-1. Road No. ‘Gaurav Tower’.5 ACC. butylene H3C – CH = CH – CH3 .hexylene CH3 – CH2 –CH2 –CH=CH–CH2 –CH2 – CH3 . propylene) H3 C C CH2 | CH3 Isobutylene CH3–CH2–CH=CH–CH2–CH3 .A.CH-NOMENCLATURE Alkynyl group – Alkynyl alkyne H (CnH2n–2) CH C – CH2– Propargyl (2-propynyl) CH C – Ethynyl (CnH2n–3) CH3 – C C – Propynyl (1-propynyl) Alkylidene group – –2 H alkane from Alkylidene same carbon Alkylene group –2 H alkane from Alkylene different carbon Position of double bond : – In an unsaturated hydrocarbon if the posi ti on of double bond is on I st or last carbon then it’s prefix will be (alpha) if it is on 2nd carbon it is termed as (Beta) & the (gamma) & (delta) and so on. eg.octylene COMMON – NAMING OF DIHALIDES (a) (b) When two same halogen atoms are attached to the same carbon such compounds are called Gemdihalides.-1. H2C = CH – CH2 – CH3 . ‘Gaurav Tower’.butylene H3C – CH2 – CH = CH2 . Common names of such compounds are alkylidene halides eg. : Cl Cl Ethylidene chloride Exception : Methylidene halide (wrong) I I H3 Isobutylidene Iodide X X Methylene halide (right) BANSAL CLASSES Private Ltd..P. Kota-05 . I.butylene H2C = CH – CH3 or H3C – CH = CH2 (Both are same positions. Road No.6 ACC. A-10.I. 7 ACC. I. Trimethylene Iodide Exception : – CH2 – X dimethylene halide | CH2 – X ethylene halide Pentamethylene Bromide (wrong) (right) COMMON . Road No. ‘Gaurav Tower’.CH-NOMENCLATURE (c) When two same halogen atoms are attached to adjacent carbon. A-10. these are called as vicinal dihalides. –CH2– 2 3 4 5 6 Poly di tri tetra penta Hexa CH2 CH2 CH2 CH2 CH2 | | Br Br CH2 CH2 CH2 | | eg. Poly Number of CH2 groups.A. these compounds are named as polymethylene glycol. Common names of such compounds are alkylene halide.-1. : CH2 CH2 CH2 CH2 CH2 CH2 | | OH OH CH2 CH2 CH2 CH2 | | OH OH Tetra methylene glycol Hexamethylene glycol Exception : CH2 – OH Dimethylene glycol (wrong) | CH2 – OH Ethylene glycol (right) BANSAL CLASSES Private Ltd.. Kota-05 .NAMING OF DI-HYDROXY COMPOUNDS (a) When two –OH groups are attached to adjacent carbon atoms they are termed as alkylene glycol.I. eg. ‘poly’ word indicates the number of –CH2– groups. CH3 CH CH2 | | eg Cl | H3 C C CH2 Cl | CH3 Propylene Iodide Isobutylene chloride (d) When two same halogen atoms are attached at the two ends of a carbon chain its common naming will be polymethylene halide. CH3 CH2 CH CH2 | | OH OH OH | CH3 CH2 C CH2 OH | CH3 Butylene glycol Active amylene glycol (b) When two –OH group are attached at the two ends of a carbon chain.P. 8 ACC. Trimethylene glycol _________________________________________________________________________________ ANSWERS 1. OH | CH3 C CH2 OH | CH3 4.P. I. CH 3–C CH3 Br Br 2. Road No.-1. Isobutylene glycol 4.I. Isopropylidene Bromide 2.. Isobutylene 5. CH2 CH2 CH2 | CH3 | OH | OH _________________________________________________________________________________ COMMON-NAMING OF THE FUNCTIONAL GROUP HAVING CARBON (Common naming for Hydrocarbon derivatives) S.No.CH-NOMENCLATURE PROBLEMS Make the structure of following organic compounds 1. H3 C C CH2 5. | CH3 C CH2 | CH2 CH3 3. Functional group Suffix (i) O || C OH -ic Acid (ii) (iii) O O || || O || C O R -ic anhydride -ate (iv) O || C NH2 -amide (v) O || C X -yl halide (vi) O || C H -aldehyde (vii) (viii) – C N N C Prefix : – 1 Carbon Form- -o-nitrile -o-isonitrile 2 Carbon Acet- 3 Carbon Propion- 4 Carbon Normal Butyr | Iso 5 Carbon Valer 3 C + (=) double bond = Acryl - 4 C + double bond = Croton- BANSAL CLASSES Private Ltd. Kota-05 . ‘Gaurav Tower’.A. A-10. Active amylene Iodide 3. -1. I. Kota-05 . Formaldehyde Acetic Acid O || CH3 CH C NH2 | CH3 O || CH3 CH2 C Cl Propionyl chloride Isobutyramide O || CH3 C H Acetaldehyde NOMENCLATURE OF ESTER O || C O R The group which is attached to the oxygen is written as alkyl & the remaining structure is named on the basis of Functional Group suffix.I. eg.A. A-10. (i) O || H C O CH3 (ii) O || CH3 O C H Methyl formate O || (iv) CH3 C O CH3 Methyl formate O || (v) CH3 C O CH2 CH3 Methyl acetate (vii) O || (iii) CH3 C O H Ethyl acetate O || CH2 CH C O CH2 CH3 Acetic acid O || (vi) CH3 CH2 C O CH2 CH3 Ethyl propionate O || (viii) CH 3 CH CH C O CH 3 Ethyl acrylate Methyl crotonate NOMENCLATURE OF ANHYDRIDE Rule : – Add the total number of carbon atoms & divide it by 2..CH-NOMENCLATURE O || CH3 C O H O || H C H eg. Road No. the substract will give you the number of C . ‘Gaurav Tower’.P.9 ACC.atom. Now name it according to suffix use for anhydride. Total 2 4 2 =2 = Substract = Number of C atom O O || || Acetic anhydride 6 2 =3 O || O || Propionic anhydride BANSAL CLASSES Private Ltd. A-10. Q. I. || Acetic propionic anhydride (right) Propionic Acetic anhydride (wrong) Divide it in two parts as above & name it by suffixing ic anhydride (alphabatically) O || eg. Q. Sol. Road No.10 ACC. Acryl aldehyde is (A) A saturated aldehyde (C) A polymer D CH2 = CH – CHO unsaturated aldehyde. Sol.1 Which of the following is not a neo structure:– (A) –C (B) –C –C– C (C) (D) Ans. (A) Divinyl ketone (B) Diallyl ketone A CH2 = CH – is called as vinyl group. ‘Gaurav Tower’.. O O || eg. –C–C (B) An alkene (D) An unsaturated aldehyde || O (C) Both A and B BANSAL CLASSES Private Ltd. Sol.2 Ans. C A carbon must be attached with four carbons.3 The common name of the compound CH2 CH C CH CH2 is - Ans. Kota-05 (D) None .-1.I.CH-NOMENCLATURE If R R’. CH3 O O | || | || || O CH3 O Isobutyric Secondary valeric anhydride Butyric propionic anhydride O || O || Acrylic anhydride O SOLVED EXAMPLE Q.A.P. You need not to find out substract. Propargyl Bromide _________________________________________________________________________________ BANSAL CLASSES Private Ltd.A. and b B (c) allyl cyanide (C) only b (d) allyl nitrile (D) a. CH3 CH2 CH CH2 OH | CH3 | CH3 7. CH 3 CH 2 CH 2 C H NH 2 | 6. Isobutyl Iodide 3. I. Neopentyl thio alcohol 11. A-10.Isopropenyl amine 12.CH-NOMENCLATURE Q. CH3 CH CH2 | CH3 | CH3 4.P. CH3 CH2 CH OH | CH2 | CH3 CH 3 CH3 | 10. CH3 – CH2 – CN 3.-1. 9.11 ACC. ‘Gaurav Tower’. Iso pentyl chloride 5. CH3 C CH2 | NH2 CH3 | CH3 CH2 CH2 C NH2 | CH3 12. Active secondary amyl amine 9.I. CH2 = CH – SH 8. CH3 C CH2 SH | CH3 11.6 Write the common names of the following compounds 1. CH C – CH2 – Br _________________________________________________________________________________ ANSWERS 1. CH3 CH CH2 CH2 Cl 5. Vinyl thio alcohol 8. Kota-05 . Road No. Ethyl cyanide 2. Common name of CH2=CH–CN is : (a) acrylonitrile (b) vinyl cyanide (A) a.. Secondary amyl alcohol. Active amyl fluoride 4. Active amyl alcohol 6.5 Ans. Tertiary hexyl amine 7. | CH 3 C CH 2 C H CH 3 | CH 3 | CH 3 1+1 +1 = 3 Q.4 Ans. 10. b and c The number of possible alkyl groups of iso octane are (A) 1 (B) 3 (C) 5 B (D) 6 CH 3 Sol. CH3 CH2 CH CH2 F 2. b and d (B) a. Q. I.A.P.CH-NOMENCLATURE MCQ Q.6 (C) Butyramide The structure of 2–butenyl radical is : | Q. c. c.3 (B) Propionamide (D) Acetic amide (A) CH 3 C H C 2 H 5 (B) CH3–CH=CH–CH2– (C) CH 3 CH 2 C| CH 3 (D) CH 2 CH 2 C CH 3 | Which one is structure of Maleic acid O || H C C OH || (A) HO C C H || O (C) Q.5 (D) Ethylene alcohol O || CH CH Common name of the compound 3 2 C NH2 is - (A) Acetamide Q.-1. b. (D) a. A-10. d Common name of the structure C H 2 OH | CH 2 OH (A) Ethylene Glycol Q. c (C) b. Road No. I. d. ‘Gaurav Tower’. b.7 (B) acryle acetate (C) methyl acrylate (D) Vinyl ethanoate Which is the structural formula of isoprene (A) CH 3 C CH 2 | CH 3 Cl | (C) CH 2 C CH CH 2 CH 3 | (B) CH 2 C CH CH 2 (D) CH3–CH=CH–CH3 BANSAL CLASSES Private Ltd. d (B) a.12 ACC.1 Which of the following are secondary radicals : | Q.2 | (a) CH 3 C H C 2 H 5 (b) CH 2 C CH 3 (c) CH2=CH– (d) (CH3)2CH– (A) a. Kota-05 .4 (B) Ethene dialcohol (C) Glycerol (B) HO CH COOH | CH 2 COOH O || H C C OH || (D) H C C OH || O HO CH COOH | HO CH COOH Common name of the structure CH 3 C O CH CH 2 is : || O (A) vinyl acetate Q.. CH3 C N C | CH3 2.6(A) Q. Kota-05 .3(B) Q. Tri methyl amine 3.8(A) Q. CH3 N CH3 | CH3 4. CH2=CH–CH2–NH–CH2–CH=CH2 3. Isobutyryl chloride 3. Road No.1 Write down the structures of the following 1. 2 (B) 2. O || CH3 CH2 CH C NH2 | CH3 2. Tri neopentyl amine Q. CH3 CH2 CHCH2 NHCH2 CHCH2 CH3 6.2 Write down the common names of the following : CH3 | 1. 1 Q.9(B) _________________________________________________________________________________ PROBLEMS Q.13 ACC.I. I. (2) 1. Secondary Valer amide BANSAL CLASSES Private Ltd.2(A) Q. H3 C CH CH2 CH2 C CH2 CH2 CH CH3 | CH3 || O | CH3 5.5(D) Q.4(B) Q. Di Active amyl amine 6.CH-NOMENCLATURE Q. 2 (D) 1. A-10. O || CH3 CH C Cl | CH3 Ans. Di isopentyl ketone 5.(1) 1. Di normal propyl ether 7. Di allyl amine 2. Tertiary valero-isonitrile 2. Di isobutyl ether 4. CH3–CH2– CH2–O–CH2–CH2– CH3 | CH3 7..8 The number of gem dihalides possible with the molecular formula C2H4X2 and C3H6X2 is given by the set : (A) 1. CH3 | CH3 C CH2 N CH2 | | CH3 CH2 | CH3 C CH3 | CH3 | CH3 CH3 | C CH3 | CH3 Ans.9 Common name of the compound C6H5CHO (A) Anisole (B) Benzaldehyde (C) Salicylaldehyde (D) None of these _________________________________________________________________________________ ANSWERS Q.7(B) Q.1(D) Q. ‘Gaurav Tower’. H3 C CH CH2 O CH2 CH CH3 | H3 C | CH3 3. 1 (C) 2.-1.P.A. 5–Hexyene [2030111749] BANSAL CLASSES Private Ltd. sp (C) sp2.3-trimethyl pentane (D) 2-methyl pentane [2030110120] Asubstance containing an equal number of primary. Thiophene (C) Thiophene.3.7 Q. sp2 (D) sp2.Aniline [2030110360] The compound which has one isopropyl group is : (A) 2. Kota-05 .46 ACC.1 Q. Phenol (D) Furane.3 The hybrid state of C-atoms which are attached to a single bond with each other in the following structure are : CH2=CH–C CH (A ) sp2. 3–Dimethyl–1–propene [2030110543] Q.I. sp (B) sp3.4 Q.2.. 3–Dimethyl–1–butene (C) 2.2–Dimethyl–1–butene (D) 1. Road No. secondary and tertiary carbon atoms is: (A) Mesityl Oxide (B) Mesitylene (C) Maleic acid (D) Malonic acid [2030111693] CH3 Q.P.2–Dimethyl–3–butene (C) Two (D) Three [2030110670] (B) 2. sp3 [2030113501] In the compound HCC–CH2–CH=CH–CH3.-1.5 Q.2 Q. I.CH-NOMENCLATURE EXERCISE-1 (Exercise for JEE Mains) [SINGLE CORRECT CHOICE TYPE] Q.6 Q. the C2–C3 bond is the type of : (A) sp – sp2 (B) sp3 – sp3 (C) sp – sp3 (D) sp2 – sp2 [2030110003] The number of acetynilic bonds in the structure are : CH C C CH CH C N || O (A) 2 Q.3-tetramethyl pentane (B) 2.2.A.9 How many secondary carbon atoms does methyl cyclopropane have ? (A) Nine Q.8 (B) 3 (C) 1 (D) 4 [2030110074] Which of the following is the first member of ester homologous series? (A) Ethyl ethanoate (B) Methyl ethanoate (C) Methyl methanoate (D) Ethyl methanoate [2030110457] Which of the following compound’s prefix ‘iso’ is not correct – (A) Iso pentane (B) Iso Hexane (C) Iso butane (D) Iso octane [2030110640] The group of heterocylic compounds is: (A) Phenol. ‘Gaurav Tower’. 4–Hexenyne (B) 1–Hexen–5–yne (C) 1–Hexyne–5–ene (D) 1.2-dimethyl pentane (C) 2. Furane (B) Furane. A-10.10 (B) One (CH3)3C–CH = CH2 has the IUPAC name : (A) 3.11 IUPAC name of CH2=CH–CH2–CH2–CCH is : (A) 1. Kota-05 .5 Statement-I : The IUPAC name of isoprene is 2-methyl buta-1.3 [2030113674] Statement-I : The IUPAC name of citric acid is 2-hydroxy-propane-1. Statement-II : Pentane is a straight-chain alkane. Statement-II : Double-bond C atoms are sp2-hybridised. If Statement-I is True but the Statement-II is False. 3-tricarboxylic acid. If Statement-I is False but the Statement-II is True.1 Statement-I : Pentane and 2-methyl pentane are homolo-gues. 3-diene. Q.6 Which of the following statements is/are wrong ? (A) CnH2n is the general formula of alkanes (B) In homologous series. all members have the same physical properties (C) IUPAC means International Union of Physics and Chemistry (D) Butane contains two 1º C atoms and 2ºC atom [2030113825] BANSAL CLASSES Private Ltd.A.P. [2030113827] [MULTIPLE CORRECT CHOICE TYPE] Q. Statement-II : Sodium potassium salt of tartaric acid is known as Rochelle’s salt. OH [2030113776] Q. ‘Gaurav Tower’. 2. Q. 3-dihydroxy butane-1. While answering these Questions you are required to choose any one of the following four responses. then it is named as a derivative of the parent alkane which does not include the C atoms of the functional groups. while 2-methyl pentane is a branched-chain alkane. printed as Statement-Iand Statement-II. COOH HOOC COOH OH Citric acid Statement-II : When an unbranched C atom is directly linked to more than two like-functional groups. Statement-II : Isoprene unit is a monomer of natural rubber.I.2 Statement-I : All the C atom o but-2-ene lie in one plane. 4-dioate. [2030113725] Q. I. Road No. [2030113623] Q.CH-NOMENCLATURE EXERCISE-2 (Exercise for JEE Advanced) [REASONING TYPE] (A) (B) (C) (D) These questions consists of two statements each.53 ACC. If both Statement-I & Statement-II are True & the Statement-II is a correct explanation of the StatementI. If both Statement-I & Statement-II are True but Statement-II is not a correct explanation of the Statement-I.4 Statement-I : Rochelle’s salt is used as complexing agent in Tollens reagent.-1. A-10. The IUPAC name of Rochelle’s salt NaOOC OH COOK is sodium potassium -2.. Road No.5 [2030113625] Q.I.A.9 [2030113829] Q.1 [2030113777] Q.6 O2N OH [2030113676] O Q.58 ACC. ‘Gaurav Tower’.10 [2030113524] BANSAL CLASSES Private Ltd. A-10. I.4 [2030113574] Q.. Kota-05 .3 [2030113523] Q.CH-NOMENCLATURE EXERCISE-3 (Miscellaneous Exercise) Q.-1.8 [2030113778] Q.2 [2030113828] Q.7 [2030113727] OH Q.P. 4 The number of sigma and pi-bonds in 1-butene 3-yne are: (A) 5 sigma and 5 pi (B) 7 sigma and 3 pi (C) 8 sigma and 2 pi Q.3-trimethyl-1-propene (C) 3.1-dimethyl-2-propene (B) 3-methyl-1-butene (C) 2-vinyl propane (D) None of the above Q.U.P.6 Write IUPAC name of succinic acid.A. ‘Gaurav Tower’.2 Write the IUPAC name of CH3CH2CH = CHCOOH Q.3.-1.1. A-10.7 The IUPAC name of C6H5COCl is (A) Benzoyl chloride (C) Benzene carbonyl chloride [JEE 1994] [2030110190] (B) Benzene chloro ketone (D) Chloro phenyl ketone BANSAL CLASSES Private Ltd.CH-NOMENCLATURE EXERCISE-4 SECTION-A (IIT JEE Previous Year's Questions) Q.1-trimethyl-2-propene (D) 2.C name of following: (a) (b) [JEE 1984] [2030110004] [JEE 1986] [2030110094] [JEE 1987] [2030110144] [JEE 1989] (D) 6 sigma and 4 pi [2030110299] Me = methyl group CH 3 | H 3C N — CH CH 2CH 3 | | CH 3 C 2 H 5 [JEE 1990] [JEE 1991] [2030110220] Q. Kota-05 [JEE 2006] [2030110303] .2-dimethyl-3-butene Q.61 ACC. I. Road No.3 The IUPAC name of the compound CH2=CH–CH(CH3)2 is: (A) 1.5 Write I. Q.1 The IUPAC name of the compound having the formula is: CH 3 | H 3C C CH CH 2 | CH 3 (A) 3.I.A.3-dimethyl-1-butene (B) 1.P.. 9 (B) 2-Bromo-5-hydroxybenzonitrile (D) 6-Bromo-3-hydroxybenzonitrile [2030110175] The correct structure of ethylenediaminetetraacetic acid (EDTA) is HOOC–CH2 CH2–COOH N–CH=CH–N (A) HOOC–CH2 CH2–COOH HOOC (B) [IIT-JEE 2010] HOOC COOH N–CH2–CH2–N COOH HOOC–CH 2 CH2–COOH N–CH 2–CH 2–N (C) HOOC–CH 2 CH2–COOH COOH HOOC–CH2 CH2 H N– CH – CH – N (D) H CH2 CH2–COOH HOOC [2030110077] SECTION-B (AIEEE Previous Year's Questions) Q.8 The IUPAC name of the following compound is [JEE 2009] CN Br HO (A) 4-Bromo-3-cyanophenol (C) 2-Cyano-4-hydroxybromobenzene Q. Road No. –CHO [2030113578] BANSAL CLASSES Private Ltd. –CHO. –COOH. –CONH2.CH-NOMENCLATURE Q.-1.62 ACC. Kota-05 . –CHO (C) –CONH2. –COOH. –COOH (B) –CHO.P.. –SO3H. –SO3H. I.A. –SO3H.I. A-10. –CONH2 (D) –COOH. –CONH2. ‘Gaurav Tower’.10 The correct decreasing order of priority for the functional groups of organic compounds in the IUPAC system of nomenclature is [AIEEE 2008] (A) –SO3H. 12 Q.22 Q. (C). (C).9 Q.25 Q.35 Q. (D) Q.7 Q.7 (C) .3 (A).45 Q.14 (A)..2 Q.13 Q.17 Q.37 Q. (B).28 Q.I.14 Q. Road No.33 Q.6 Q.47 (C) (D) (B) (A) (C) (C) (D) (C) (D) (D) (C) (B) Q.5 Q. (C) Q. Q. (B).P. (D) P] [(A) R. (C). (C) Q.5 Q. (C). (B) R.10 (A) Q.12 (B) (B) (C).3 Q.18 Q. Kota-05 Q.CH-NOMENCLATURE EXERCISE-1 Q.32 Q. (B).48 (C) (B) (D) (B) (B) (B) (A) (C) (D) (B) (B) (A) (A) (A). (C) (A). (E) U.15 (A). S.31 Q.16 Q. (B) S.46 Q.40 Q. (B) P.42 Q.8 Q. (D) Q.30 Q. (B).A.38 Q.1 Q.2 Q.63 ACC.1 Q.10 Q. (D) EXERCISE-4 SECTION-A Q. (B).23 Q.43 Q.26 Q. (D) (A).4 Q.10 (D) BANSAL CLASSES Private Ltd.11 (B) (A). (B). (C) S ] [(A) R. A-10.49 (A) (D) (C) (A) (B) (D) (B) (B) (C) (C) (B) (D) (D) Q. (B).20 Q.20 [(A) Q.4 Q.17 Q. (C) S. (B).29 Q.44 Q.18 Q.19 Q. (B) P.8 Q.6 Q. (C).19 [(A) R. (B). (C) P.50 (C) (B) (A) (B) (D) (C) (B) (D) (A) (B) (C) (A) (B) Q.3 Q.24 Q. (C) S.9 Q.41 Q.39 Q.7 (A).16 Q. (B) R. R. I.4 (B) SECTION-B Q.9 (B) (C) Q.21 Q. (D) Q.15 Q.27 Q.-1. (C) P ] (A).13 Q.8 (C) (B) Q. (F) T] Q. (D) Q] [(A) Q. (D) EXERCISE-2 Q.1 Q. (D) Q.36 Q. (D) Q.11 Q. ‘Gaurav Tower’.34 Q. 4 Acetynilic group Q.5-dimethyl -5-[1-methyl ethyl] hept-3-ene BANSAL CLASSES Private Ltd.2 HC C – CH 2 – CH = CH – CH 3 1 2 O Q. Kota-05 .13 Compound having hetero -atom (as O.1 3 sp sp H sp2 C=C CC–H sp H H Q.12 6 H2C = CH = C – CH3 1-Hexene-5-yne 1 2 3 CH2 – CH3 4 5 3-methyl-2-pentene Q.64 ACC. A-10.9 3º 2º – C 2 1º Q. Substituent (ethyl) Substituent (methyl) Substituent (ethyl) Substituent CH3 (methyl) CH3 CH2 CH3 CH2– CH3 H3C – CH – C – C = C – CH2 – CH3 7 Q. ‘Gaurav Tower’.6 Iso •• 1º CH3 – CH – CH2 – CH2 Q. I.15 6 5 4 1 CH – CH3 2 3 2 1 CH3 Substituent (1-methylethyl) 3.10 2º H3C – C – CH = CH2 3 4 2 1 CH3 3. 5-diethyl-4. S etc) in cycle are known as heterocyclic compound.3 Q.CH-NOMENCLATURE EXERCISE-1 Q.7 4 O H – C C – C – C–CH = CH – C N CH3 3 2 3 4 5 Q.-1.. N.I.5 CH3 – C – CH2 – CH – CH3 Q.3-dimethyl-1-butene H 2C = CH – CH2 – CH2 – C CH 1 6 CH3 Not Iso group Q.11 5 H – C – O – CH3 CH3 Q.P. Road No.A.8 ISO group •• O •• S •• Furan Thiophene CH3 2º 3º 3º 2º 2º 1º – Carbon 3 1º 2º – Carbon 3 3º – Carbon 3 3º 1º CH3 2º Q. I. 5-dimethyldecane Br H3C – CH2 – CH Br Q.27 10 9 8 7 6 5 4 3 2 1 CH3 – CH2 – CH2 – CH2 – CH2 – CH – C – CH2 – CH2 – CH3 CH2 CH3 4-Ethyl-4. Road No.21 H2C – CH – CH2 CH3 Q.23 sp 3 sp 3 sp H 3C – CH2 – C N Q.26 Functional group H3C – CH2 – CH – O – CH2 – CH3 3 2 1 1-Ethoxy-1-propanamine () not 1-Amino-1-Ethyoxypropane (×) CH3 CH3 Q.I. 4-dimethylpent-1-yne Q.25 * 2 3 OH OH OH 2º 1º CH3 2º 3º 2º 2º 2º (Toluene) NH2 Q.28 C3H6Br2 Terminal gem dibromide Br CH3 – C – CH3 Br Non-terminalgem dibromide BANSAL CLASSES Private Ltd.P. Kota-05 1º – C 1 2º – C 5 3º – C 1º .65 ACC.19 H3C – C C – C – CH3 1 2 3 4 5 1 CH3 4..A. ‘Gaurav Tower’.-1.CH-NOMENCLATURE H3C – CH2 – N – CH = CH2 Q. A-10.17 CH3 Vinyl Methyl Ethyl 5 4 3 2 1 Q.18 H 3C – CH = CH – C CH Pent-3-ene-1-yne Q. 5 inch 2.5 inch 2.5 inch .7 inch 2.