MISSING DI QUESTIONS1 DETAILS OF VARIOUS ITEMS SOLD BY SHOPKEEPER 1 If shop keeper earns 5% profit on oil then what percent discount allowed by shop keeper? 25% 30% 20% 18% None of these Markup 5% price of oil profit = means (200*40)/100 selling = 80 → 200+80 price = is Required discount % = (280 – 210)/280 = 25% 2 What percentage of profit earn by the shopkeeper on vegetable? 15% 25% 20% 18% None of these 3If shop keeper allowed 10% discount on mark price of Sugar then what is the selling price of the Sugar? Rs. 575 Rs. 585 Rs. 550 280 210 Rs. 610 None of these 4 If shop keeper Face 20% loss on salt then what is cost price of the salt? Rs. 550 Rs. 580 Rs. 500 Rs. 520 None of these 5 If cost price of the salt is Rs. 350 then what is the approximate profit percentage earn by shopkeeper on salt? 14% 12% 17% 18% None of these Directions for Questions (1-5): Study the given table carefully to answer the given questions. 1. If in city B, 40% of the students (M + F) who completed the course got the job, then how many students got the job? 160 165 166 170 None of these Solution: 2. In city E, ratio of male to the female students who enrolled is 9 : 8 and the ratio of male to female who completed the course is 4 : 3, then find the number of students who got the job? 153 155 160 Cannot be determined None of these Solution: 3.In city D, number of students (M + F) who dropped out is 3/11 of the total number of students who enrolled for the course what % of students (M + F) in city D who completed the course got the job? 80% 82.5% 85% 25% of (M + F) who completed the course got the job. In city C.e. 245 250 . i. number of male students who completed the course is equal to number of female students. then find the number of females who dropped out? 100 110 108 Cannot be determined None of these Solution: 5. 25% of (M + F) who completed course got job? When how may male enrolled. Only 96 students. In city A.Cannot be determined None of these Solution: 4. Complete the missing information and answer the questions using the information given in table and pie-chart. Books sold by 6 shopkeepers in April 2016 (in thousands) . The table has some missing information but it is known that every shopkeeper sold books of every subject.488 Cannot be determined None of these Solution: Directions for Questions (6-10): The questions are based on the table and pie-chart given below. 6. Which shopkeeper sold maximum number of General awareness books as a percentage of the total number of books sold by that shopkeeper? R S P U None of these Solution: . In April 2016. the second highest number of books sold was of which subject? Banking Awareness General awareness Quantitative Aptitude Reasoning Computer Solution: 7. What is the average number of books sold of General awareness.44% 2.32% 2. If a total of 4000 books were returned in April 2016. then what was the number of Reasoning books returned as a percentage of Reasoning books sold in April 2016? 2. then what is the approximate number of English and Banking Awareness books sold as a ratio of the number of English and Banking awareness books returned in April 2016? .8.86% 1. Computer and Reasoning together? 29500 30000 30333 28333 None of these Solution: 9. If the number of General Awareness books returned in April 2016 is 780.92% Solution: 10.74% 1. The cost of fencing of field E is approximately what per cent of the cost of flooring of field C? 1) 10.What is the difference between the cost of fencing of C and that of B? 1)Rs.360 5)Rs.82% 5.180 2)Rs.33:2 41:2 47:3 53:4 65:3 Solution: Directions (1-5): Study the given table carefully to answer the following questions.5000 5)Rs.480 3.13% .36% 5) 13.54% 2) 67.5% 3) 72.71% 4) 15.What is the ratio of the cost of flooring to that of fencing of field D? 1) 4 : 1 2) 6 : 1 3) 8 : 1 4) 9 : 1 5) 5 : 1 4.4400 2.The cost of fencing of field C is what per cent of the cost of fencing of field D? 1) 87.46% 3) 18.4800 4)Rs.120 3)Rs. 1.4600 3)Rs.240 4)Rs.What is the cost of flooring of A? 1)Rs.4000 2)Rs.5% 2) 19. Perimeter of C=4X15=60 m So.5% Answers 1.What is the difference between the selling price of Sugar and that of Rice.2% 5)31.4) 54.50 3)Rs.5% Directions (6-10): Study the table carefully to answer the following questions.90 2)Rs.What is the percentage profit of Milk if its selling price is 80% of the cost price of Rice? 1)28% 2)30% 3)32% 4)30.49% 4)34.09 5)Rs.52 3)Rs.23. Required difference=1080-900=180 .21. What is profit or loss percentage? (The packing cost is zero for all goods) and selling price of Milk is ` 32 per kg? 1)36% 2)32% 3)30.21.58 4)Rs.4 kg Ghee.36 5)Rs.24. 3 kg Rice and 5 kg Milk are sold.(3)A is traingle Area of A=1/2(16X12)=96m^2 Cost of flooring of A=96X50=4800 2.24.(1) Perimeter of B=2(10+20)=60 m cost of fencing of B=60X15=900 Rs.74 9.49% 5)38% 10.09 5)Rs.80 7.22 4)Rs. Cost price=cost of production + transportation + packaging cost 6.15.22 4)Rs.56 2)Rs. then what is its cost of packaging? 1)Rs.23.90 2)Rs.What is the cost of packaging of Pulse? 1)Rs.50 3)Rs. if the cost of transportation is zero for both? 1)Rs. The percentage profit is given on total cost price. cost of fencing of C=60X18=1080 Rs.27.If the percentage of profit on sold Ghee is 10%.72 8.36% 5) 46. 5% 6. (4) selling price of Ghee=120 per kg.74-70.74 9. (5) Selling price of pulse=90 Rs. (3) CP of (4 kg Ghee+3kg Rice+5 kg milk) = 4X(80+8)+3X40+5X(20+3) =352+120+115=587 SP of( 4 kg Ghee+3kg Rice+5kg milk) =4X120+3X42+5X32=480+126+160=766 % profit=(766-587)/587X100=30.74 Cost of packaging of pulse=95.(2) Fencing cost of C=1080 Fencing cost of D=1600 Required %=(1080X100)/1600=67.What is the principal of N if the ratio of interest rate of M to that of N is 2 : 3? 1) Rs.1-5) : Study the following table carefully and answers the following question 1.10=15. (1) CP of Rice=40 SP of milk=40X80/100=32 CP of milk=20+3+2=25 % profit=(32-25)/25X100=28% 10.(4) Area of D=BaseXHeight=20X12=240 m^2 cost of flooring of D=240X60=14400 Perimeter of D=2(20+12)=64 cost of Fencing of D=64X25=1600 Required ratio=14400:1600=9:1 4. 7. (4) Perimeter of E=2PiR=2X22/7X10=440/7 m Cost of Fencing of E=440/7X22=1382.85X100/9000=15.3. Loss=6% Total CP=90X100/94=95. Profit=-10% Total cost price=120X100/110=109. 10449 2) Rs. 25000 .85 Area of C=15^2=225m^2 Cost of flooring of C=225X40=9000 Required %=1382.09-80-8=21.36% 5.09 Cost of packaging=109. 20230 3) Rs.09 Rs.49% Directions (Q. (3) Selling price of Rice=40X105/100=42 Selling price of Sugar=45+5+50=100 Required difference=100-42=58 8. 3201 4) Rs.9 3) Rs.97 3) Rs. 3142 3) Rs. 54974.33% 5) Rs. 133. 60% 4) Rs. 25300. 63.If the ratio of principal of O to that of P is 4 : 5 and the rate of interest of P is 10% more than that of O. 19165. 21218 4) Rs. 20320. 162.What is the amount of O.What is the amount of Q when the principal of Q is 20% more than that of M? 1) Rs. 32321.5 2) Rs. 17952. 25423 2.7 2) Rs.At what rate of interest the amount of N becomes five times that of his principal? 1) Rs.35 . 22418 5) Rs. then what is the interest of P? 1) Rs. 32863.96% 3) Rs.5 3. 17121 5) Rs. 69.58% 5.58% 2) Rs. 13248. 2750 4.24 5) Rs. 3300 2) Rs.4) Rs. 2890 5) Rs. if the interest is compounded yearly for 2 years? 1) Rs.19 4) Rs. Cost price of V = `50 Transportation cost = `30 Total cost price = 50 + 30 = `80 Profit = 4% Selling price = 80 × 104 /100 = `83.2 2. The selling price of X is what percent of the cost price of W? 1) 150% 2) 250% 3) 125% 4) 200% 5) 100% Answer 2.2 2) 89. Then what is its selling price? 1) 91. 1-5): Study the given table carefully to answer the given questions. 5.The percentage profit on V is 4%.Directions (Q. 2.2 Answer 1.5 3) 87.5 4) 85 5) 83. Percentage profit or loss is based on the sum of cost price and transportation cost in Missing Value Data Interpretation SBI PO. Selling price of X = (Cost price + Cost on transportation + Profit) = 250 + 20 + 5 = `275 Cost price of W = Selling price + Loss = 100 + 10 = `110 . 1. 4 4) `195.8 2) `294.Reqd % = 275 *100% / 110 = 250% of the cost price of W.66 : 10 = 833 : 500 4. What is the ratio of the loss on Y to that on W? 1) 133 : 255 2) 65 : 55 3) 75 : 43 4) 833 : 500 5) 233 : 155 Answer 4. What is the difference between the selling price of Z and that of X? 1) `189. Selling price of Z = Cost price of Z + Cost on transportation + Profit = 400 + 40 + 440 *6/100 = `466.7% 5) 79.7% 3) 83.7% Answer 5. 3.4 5. Selling price of V = (Cost price + Cost of Transportation) = 95/100 = (50 + 30) × 95 /100 = `76 .66 Loss on W = `10 Reqd ratio = 16.7% 2) 88. If the loss on V is 5%.5 3) `191.4 Selling price of X = `275 Difference = 466.9 5) `201 Answer 3.66 – 400 = `16.7% 4) 81. Loss on Y = Cost price of Y – Selling price of Y= 400* 100/96 – 400 = 416. then its selling price is what percentage less than the selling price of Z? 1) 85. 3.4 – 275 = `191. 4 Reqd % = 466. 9 5. 8 3. Less than 10 3. What is the difference between the number of female post graduates and male employees who are not post graduates? 1. 12 . 80% of whom are in the production department and the rest equally divided between the marketing and the accounts department. 10 4. twenty five per cent of the post graduates are male.7% less than selling price of Z. 45% 3. What is the percentage of male employees in the production department? 1. 6 2. 50% 4. 55% 5. Less than 14 5. Direction: Answer the following questions based on the information given below: The proportion of male employees and the proportion of post graduates in a company are given below. Less than 8 2. 1. Less than 16 3. The difference between the number of Post graduates in Marketing department and Post graduates in Accounts department is? 1.4 *100% = 83. The company has a total of 800 employees. 60% 2.4 – 76 /466. 40% 2. Less than 12 4.Selling price of Z = `466. In the marketing department. 4. 45% 3.55*640 = 352 Now. 40% 2. 32% 3. What percentage of employees in the marketing department are post graduates? 1. Post graduates in marketing department = 32 Male Post graduates = 25% = 8 Hence. 60% 5. what percent more than the number of males in Accounts department? 1. 35% 2. Male non Post graduates = 48-8 = 40 Required difference = 40-24 = 16 3. Thus. 32% Detail Solution:Total employees = 800 ⇒ total males = 0. Difference = 40-32 = 8 4. 50% 4. 29% 4. female Post graduates = 24 Hence. Required percentage = [32/80]*100 = 40% 5. both has 80-80 employees. rest employees (800-640 = 160 are equally divided between marketing and accounts. Males in Accounts department = 288 Total males = 380 Difference = 92 Required percentage = [92/288]*100 = approx.53*800 = 424 80% employees = in Production department = 640 Number of Post graduates in Production department = 0. 55% 5. 25% 5. .475*800 = 380 Total Post graduates = 0. 39% Solutions 1. The number of Total males from all the departments are approx. Percentage of males in the production department is: [288/640]*100 = 45% 2. 6*80 = 48 Number of males in Accounts = 0.50*80 = 40 Post graduates in Marketing = 424-[352+40] = 32 And number of males in Production = 380-[48+44] = 288 The following table shows the number of new employees added to different categories of employees in a comp also the number of employees from these categories who left the company every year since the foundation of t Company in 1995. Year Managers Technicians Operators Accountants Peons New Left New Left New Left New Left New Left 1995 760 – 1200 – 880 – 1160 – 820 – 1996 280 120 272 120 256 104 200 100 184 96 1997 179 92 240 128 240 120 224 104 152 88 1998 148 88 236 96 208 100 248 96 196 80 .55*80 = 44 Post graduates in Accounts = 0.Number of males in Marketing = 0. What was the total number of Peons working in the Company in the year 1999? A. 96 D. 112 C. 88 EXPLANATION Answer: Option D Explanation: Required difference = (272 + 240 + 236 + 256 + 288) – (200 + 224 + 248 + 272 + 260) = 88. 2. 968 EXPLANATION Answer: Option B . 1192 C. 1312 B. 1088 D. What is the difference between the total number of Technicians added to the Company and the total of Accountants added to the Company during the years 1996 to 2000? A.1999 160 72 256 100 192 112 272 88 224 120 2000 193 96 288 112 248 144 260 92 200 104 1. 128 B. Explanation: Total number of Peons working in the Company in 1999 = (820 + 184 + 152 + 196 + 224) – (96 + 88 + 80 + 120) = 1192. For which of the following categories the percentage increase in the number of employees working in the Company from 1995 to 2000 was the maximum? A. Percentage increase in the number of Managers . Technicians C. Operators D. Managers B. Accountants EXPLANATION Answer: Option A Explanation: Number of Managers working in the Company: In 1995 = 760. In 2000 = (760 + 280 + 179 + 148 + 160 + 193) – (120 + 92 + 88 + 72 + 96) = 1252. 3. What is the pooled average of the total number of employees of all categories in the year 1997? .4. 1325 B. During the period between 1995 and 2000. 1235 EXPLANATION Answer: Option B Explanation: Total number of employees of various categories working in the Company in 1997 are: 5. 1265 D. 1195 C. 21% . 19% B.A. the total number of Operators who left the Company is what percent of total number of Operators who joined the Company? A. Refer to the table and answer the given questions Data related to performance of 6 Batsman in a tournament Batsman Number of matches played in the tournament 8 20 — — 28 — Average Runs scored in the tournament — 81 38 — 55 — Total balls faced in the tournament — — 400 — 1280 — A B C D E F Note: i. 27% D.6 — 114 72 — 66 .C. iii. 29% EXPLANATION Answer: Option D Explanation: I. if it is required to answer the given question. A candidate is expected to calculate the missing value. Few Values are missing in the table (indicated by —). All the given Batsmen could bat in all the given matches played by him. Strike Rate = [Total Runs Scored/Total Balls Faced]*100 ii. Strike Rate 129. on the basis of the given data and information. 200/9% B. 133 E. what are the minimum possible runs scored by E in the 28th match? A. 325/9% E. 137 Explanation : . 141 D.1. D = 72*3x/100 F = D*[(100+y)/100] 264x/100 = 216x/100 * [(100+y)/100] y = 200/9% 2. The respective ratio between total number of balls faced by D and that by F in the tournament is 3:4. If the runs scored by E in last 3 matches of the tournament are not considered. 350/9% D. 150/9% C. If the runs scored by E in the 26th and 27th match are below 128 and no two scores among these 3 scores are equal. 130 Answer & Explanation Answer – A. 100/9% Answer & Explanation Answer – A. Total number of runs scored by F in the tournament is what percent more than the total runs scored by D in the tournament? A. 135 C. his average runs scored in the tournament will decrease by 9. 200/9% Explanation : F = D = [Strike Rate * Total Balls Faced]/100 F = 66*4x/100. 137 B. 6 = [x/x-74]*100 [Strike rate formula given) 129.5 Explanation : 129.5 C. what is the total .5 4.So Assume 26th = 127 then 27th = 126 and therefore 28th = 137 3.4 = 100x x = 324 Average = 324/8 = 40. Batsman B faced equal number of balls in first 10 matches he played in the tournament and last 10 matches he played in the tournament. the total number of balls faced by Batsman A is 74 less than the total number of runs scored by him. 39.5 B. 38 D.6x -9590. In the tournament.5 Answer & Explanation Answer – E.Total runs scored = Number of matches played in the tournament * Average Run = 28 * 55 = 1540 Total runs scored(excluding last 3 matches) = 25 * 46(decrease 9 in avg) = 1150 Total runs of last 3 matches = 1540 – 1150 = 390 Average = 390/3 = 130 26th and 27th match are below 128 and no two scores among these 3 scores are equal. What is the average run scored by Batsman A in the tournament? A. If his Strike rate in first 10 matches of the tournament are 120 and 150 respectively. 44 E. 42. 40. 40. 1000 B. 1200 Explanation : (120/100)*(x/2) + (150/100)*(x/2) = 1620 x = 1200 5. What is the number of matches played by batsman C in the tournament? A. 12 D. 16 C. 10 B. 8 Answer & Explanation Answer – C. 1100 C. 1250 E. 1300 Answer & Explanation Answer – C.number of balls faced by him in the tournament? A. 1200 D. 18 E. 12 Explanation : 114 = (38x / 400)* 100 x = 12 II. Refer to the table and answer the given questions Person A B C D Type of Interest Compound Simple Compund Simple Principal(P) — — 20000 — Amount (A) — — — 29500 Years 2 4 2 3 Rate of Interest(%) 2 — 4 — . If the ratio of interest rate of E to that of D is 2:3 then what is the Principal(P) of D? A.28 . 15000 B. 25000 Explanation : R(%) = 4*3/2 = 6 Principal – x x + (x*3*6/100) = 29500 x = 25000 7. 20497.28 D. If the interest is compounded yearly for three years then what is the amount to be earned by C? A. 25000 E.28 B.04 * 1. 22497. 20000 C.E Compound 10000 — — 4 6.28 Explanation : Amount = P(1 + (R/100)^3) A = 20000 * 1.28 Answer & Explanation Answer – E.04 A = 22497. 22597. 22697.28 C.28 E. 35000 D.04 * 1. 22497. 23497. 30000 Answer & Explanation Answer – D. 60 B. If amount of D equals to five times that of his Principal then what is the Rate of Interest(%)? . 2200 D. What is the Simple Interest(SI) of B ? If the ratio of Principal of C to that of B is 4:5 and the rate of interest is 10% more than that of C. 15684. 12484. 12584. 3300 B. 1100 E. 4400 Explanation : P = 5/4 * 20000 = 25000 The rate of interest is 10% more than that of C. 5500 Answer & Explanation Answer – B. then What is the amount of A? A.4 % SI = [25000 * 4.60 Answer & Explanation Answer – D.8.80 Explanation : Principal(P) of A = 10000 * 120/100 = 12000 A = P(1 + (R/100)^N) = 12000(1 + (2/100)^2) = 12484. A. R(%) = 4 + (4*(10/100)) = 4. 12484.80 10. 4400 C.80 E. 16584. 12694.80 D.60 C.4 * 4]/100 = 4400 9. If the Principal(P) of A is 20% more than that of E. 133. Data related to number of students who got admission and who left the given five colleges 1.33% Read the following table carefully and answer the questions given below it.22% B.33% D. COLLEGE 1 COLLEGE 2 COLLEGE 3 COLLEGE 4 COLLEGE 5 YEARS ADM LEFT ADM LEFT ADM LEFT ADM LEFT ADM LEFT 2008 161 148 179 116 128 2009 148 58 172 60 161 90 208 60 191 50 2010 2011 2012 135 112 141 69 88 39 188 173 151 96 59 48 143 165 179 101 58 66 169 142 155 45 56 108 167 185 142 79 82 91 Ques 1.33% Explanation : Amount of D = Rs. 155. 144. 133.55% E.29500 Principal – x Amount of D = 5x 5x = 29500 => x= 5900 SI = 29500 – 5900 = 23600 R = 23600 * 100 / 5900 * 3 = 133. 122.44% C.3. None of the Above Answer & Explanation Answer – C.4 and 5 during the given years.2.A. What is the average number of students who got admission in College 4 during all the given years taken together? (a) 156 (b) 164 (c) 166 . Number of students in College 5 at the end of 2009 is what percent more than the number of students is College 3 at the end of 2009 ? 1 . What was the total number of students in College 1 at the end of 2011? (a) 335 (b) 347 (c) 329 (d) 363 (e) 341 Ques 5. In which of the given colleges the number of students were the highest at the end of 2009? (a) 1 (b) 2 (c) 3 (d) 4 (e) 5 Ques 4. what was the number of girls in College 2 at the end of 2010? (a) 212 (b) 186 (c) 208 (d) 192 (e) 172 Ques 3.(d) 162 (e) 158 Ques 2. If the respective ratio of number of boys and girls in College 2 at the end of 2010 was 5:6. (a) 9 ---5 1 (b) 11 ---5 4 (c) 3 ---5 3 (d) 7 ---5 4 (e) 5 ---5 Ques 6. 2011 and 2012 together ? (a) 22:17 (b) 11:9 (c) 13:9 (d) 11:7 (e) 22:19 ANSWERS (1) (e) .158 . What is the respective ratio between total number of students who joined College 3 in 2010 and 2011 together and total number of students who left College 5 in 2010. (2) (d) 192 (3) (e) 5 (4) (e) 341 3 (5) (d) 7 ---5 (6) (b) 11:9 SOLUTIONS (1) Average = (116 + 208 + 169 + 142 + 155 ) / = 158 (2) Total admitted student till 2010 = 148 + 172 + 188 = 508 Total number of students who left till 2010 = 60 + 96 = 156 Difference = 352 Number of girls = 6/11 * 352 = 192 (3) College 1 = 161 + 148 .50 = 269 (4) (116 + 148 + 135 + 112 ) .90 = 250 College 4 = 116 + 208 .58 = 251 College 2 = 148 + 172 .(58 + 69 + 88 ) = 341 (5) Students of College 5 at the end of 2009 = 128 + 191 .60 = 260 College 3 = 179 + 161 .90 = 250 .50 = 269 Students of College 3 at the end of 2009 = 179 +161 .60 = 264 College 5 = 128 + 191 . A 10-member family. then what will be the new speed of the train? 1) 475/7 kmph 2) 484/9 kmph 3) 491/2 kmph 4) 503/7 kmph 5) 5311/17 kmph 3.45 = 43 430 4 4 10 3 430 = 40 kmph 2. Speed of train between Kanyakumari and Madurai= 430 11. What is the ratio of adults to children who arrive at Renigunta? 1) 3 : 5 2) 47 : 21 3) 39 : 41 4) 47 : 51 5) 5 : 19 5. 1-5): Study the table carefully to answer the following questions.45 pm –1. 1.00 pm = 430 10. boards the train at Tuticorin and deboards the train at Arakkonam. What is the speed of the train running between Kanyakumari and Madurai? 1) 40 kmph 2) 602/19 kmph 3) 6211/21 kmph 4) 50 kmph 5) 6815/22 kmph 2.Percentage = (269-250) / 250 * 100 = 38/5 (6) Ratio = (143 + 165 ) : (79 + 82 + 91 ) 11 : 9 Directions (Q. What is the fare paid by them? (Given that the ratio of fare of Adult to Child is 5 : 2) 1) ₹ 3034 2) ₹ 2832 3) ₹ 2964 4) ₹ 3544 5) ₹ 3262: Answers With explanations: 1. 5. Total time taken by the train to travel from Kanyakumari to Renigunta . What is the total income of Railways from this train from Kanyakumari to Madurai? (Given – fare for Child is 40% that for an Adult) 1) ₹ 163400 2) ₹ 155980 3) ₹ 173500 4) ₹ 184000 5) ₹ 1925000 4. in which there are 4 children. 1. If there is no any stop between Kanyakumari and Renigunta. 3. The fare paid by the family = fare of 6 adults + fare of 4 children = {6 × (590 – 200) + 4(590 – 200) × 2 5} = `2964 Study the following table carefully and answer the given questions Mobile Cost Price Selling Price % of Profit Profit Samsung 35.000 10% ---- Sony 32.000 ---- 14% ---- ---- 22. Number of adults arriving at Renigunta = (250 + 320 + 150 + 100 + 120 + 80) – (100 + 50+ 230 + 80 + 90) = 470 Number of children arriving at Renigunta = (70 + 90 + 70 + 60 + 40 + 20) – (20 + 30 + 50 + 30 + 10) = 210 Reqd ratio = 470 : 210 = 47 : 21 5.= 11 am – 1 pm = 22 hours Total halt time = 5 + 10 + 20 + 5 + 5 = 45 minutes If there in no halt then time taken = 22hr – 45 minutes = 21 hours 15 minutes Speed = 1140 km 21 hrs 15 minutes = 85 1140 4 = 1140 4 912 5311 kmph 85 17 17 3.000 ---- ---- ---- HTC ---- 33.500 Apple 53.000 ---- ---- 28. 2. Total income of Railways from the train from Kanyakumari to Madurai = (fare of adult × number of adults) + (fare of child × number of children) = (250 × 80) + (70 × 80 × 40 100 ) + {(250 + 320 – 100) (200 – 80) + (70 + 90 – 20) (200 – 80) 40 100 } + {(250 + 320 – 100 + 150 – 50) × (310 – 200) + (70 + 90 + 70 – 20 – 30) (310 – 200 × 40 100 )} = {(20000 + 2240) + (56400 + 6720) + (62700 + 7920)} = `155980 4.000 ---- ---- 4. 2.000 ---- ---- 3.000 Micromax LG . 7450 3.32.10:13 3.10:14 .32.7620 5.5% 2.000 and 23% 2. If Cost Price of Micromax is 3/5 of Cost Price of HTC mobile ? 1.What is the % of Profit Micromax.25 7/9% 3.32.000 and 14 1/7% 2.24 5/9% 5.00 and 15% 3.36.36.What is the selling price and % of profit of LG mobile?.000 and 14 2/7% 4.000 and 18% 4.000 and 12.000 and 15 2/7% 4.000 and 17 5/7% 5.000 and 20% 5. If profit is 5oo more than the profit of Samsung mobile .What is the profit earned on Apple mobile ? 1.7560 5.7360 2.34.34.1.22 2/9% 4.33 1/3% 2.What is the ratio between Cost Price and Selling price of Samsung ? 1.14:15 2.26 4/9% 3.36.What is the selling price and % of Profit of Sony Mobile ? 1.7420 4. 1.36.36.000 and 14 4/7% 3. 000 % of profit on LG = (4000/28.100% (CP) Cost Price of HTC = 30.000 Selling price = 22.110% ? ------.5 Profit on Samsung mobile =3.000 Micromax cost price = 3/5 *30.4.000 ------.000 )*100 = 22 2/9% 3. 1-5): Study the given table carefully to answer the following questions: .420 profit = 60.000+4000=36.000 = 18.3 HTC mobile Selling Price = 33.000=7420 5.000 Selling Price = 35.5% 2.000 % of Profit = 4000/36000 = 12.420-53.000 % of profit = 14% 53.14:15 5.000 -----------.100% ? ----------.10:11 Solutions : 1.5 Cost Price = 35.000 profit = 4.000)*100 = 14 2/7% 4.3 Cost Price = 53.500 from that profit on LG mobile = 3500+500=4000 Selling Price of LG mobile = 32.1 Selling price = 32.000 HTC Mobile % Of Profit = 10% means 33.114% Selling price = 60.000+3500=38500 Ratio = 35000 : 38500 = 10:11 Q.000 % of profit = (4000/18. What is the total fare of an eight-membered family who board at Mathura and deboard the train at Itarsi? Four members out of eight are children and each child’s fare is 55% of the fare for an adult? 1) `2635 2) `2051 3) `2192 4) `1818 5) `2590 3.8% .5 kmph 3) 12.6% 2) 2.1. The total halt time is what per cent of the total travel time? 1) 8.5 kmph 4) 18 kmph 5) None of these 4. How many passengers deboard the train at Nagpur? 1) 2050 2) 1340 3) 1170 4) 1050 5) 150 2. What is difference between the speed of the train from Jhansi to Nagpur and that from Delhi to Jhansi? 1) 11 kmph 2) 10.4% 3) 7. 04 . What is the cost of packaging of Pulse? 1) `22. then what is its cost of packaging? 1) `24. What is the total revenue from this train between Agra and Itarsi? (Assume all passengers pay full fare) 1) `300000 2) `296650 3) `326610 4) `349000 5) `151500 Directions (Q. 6-10): Study the table carefully to answer the following questions.50 3) `22 4) `21.5 2) `20.6% 5) 4.80 7. Cost price = cost of production + transportation cost + packaging cost 6.1% 5.09 5) `27. What is the difference between the selling price of Sugar and that of Rice.90 2) `23. The percentage profit is given on total cost price. if the cost of transportation is zero for both? 1) `56 2) `52 3) `48 4) `36 5) `72 8. If the percentage of profit on sold Ghee is 10%.4) 5. Passengers deboarding the train at Nagpur = Total passengers boardi ng at various stations from Delhi to Itarsi – Total passengers deboarding the train at various stations from Mathura to Itarsi = (500 + 200 + 350 + 250 + 180 + 150) – (80 + 50 + 100 + 200 + 150) = 1630 – 580 = 1050 2. (4).71 5) `15. Total fare of family = Fare of Adults + Fare of Children = 4 × 425 + 4 × 425 × (55/100) = 1700 + 935 = `2635 3.67 kmph Speed of train from Jhansi to Nagpur = 950/12 = 76.91 4) `18. What is profit or loss percentage? (The packing cost is zero for all goods) and selling price of Milk is `32 per kg? 1) 36% 2) 32% 3) 30. 4 kg Ghee. 3 kg Rice and 5 kg Milk are sold.5% Answer:1. Speed of train from Delhi to Jhansi = 400/6 = 66.74 9.49% 4) 34. (3). What is the percentage profit of Milk if its selling price is 80% of the cost price of Rice? 1) 28% 2) 30% 3) 32% 4) 34% 5) 38% 10.2% 5) 31.16 kmph Reqd difference .3) `19. (1). 74 .74 – 70 – 10 = `15.67 = 12. Total revenue between Agra to Itarsi = (Fare of Railway from agra to Itarsi × Number of passengers between stations) = Total revenue from Agra to Jhansi + Total revenue from Jhansi to Bhopal + Total revenue from Bhopal to Itarsi = (500 + 200 + 350 – 80 – 50) × (250 – 130) + (500 + 200 + 350 + 250 – 100 – 80 – 50) × (375 – 250) + (500 + 200 + 350 + 250 + 180 – 200 – 100 – 50 – 80) × (425 – 375) = (920 × 120 + (1070 × 125) + (1050 × 50) = 110400 + 133750 + 52500 = `296650 6.74 Cost of packaging of pulse = Total cost price – Cost of production – Cost of transportation = 95. (3). (5). Selling price of pulse = `90 Loss = 6% Total cost price = 90 × (100/94) = `95. (4).50 kmph 4. Selling price of Ghee = `120 per kg Profit = 10% Total cost price = 120 × (100/110) = `109.09 7.45 pm (one day before) = 18hr 15min = 18 X (15/60)hr = 73/4 hours Total halt time = 5 + 5 + 15 + 7 + 13 = 45 minutes Total halt time is = 45/60 = (3/4) hr Reqd % = (3/4) X (4/73) X 73 Hours = 4. Selling price of Rice = 40 × (105/100) = `42 Selling price of Sugar = 45 + 5 + 50 = `100 Reqd difference = 100 – 42 = `48 8. 5.00 noon – 5. (5).16 – 66.09 Cost of packing = Cost price – Cost of production – Cost of transportation = 109. (2).= 79. Total travel time = 12.10% of the total travel time.09 – 80 – 8 = `21. 49% Directions (Q1-5) Study the following table carefully and answer the questions that follow: Q1. If the number of female qualified candidates from State P in 2008 is 126.9. what is the number of appeared candidates (both male and female) from State P in 2008? . Out of the number of qualified candidates from State P in 2008. the ratio of male to female candidates is 11:7. Cost price of Rice = `40 Selling price of Milk = 40 × (80/100) = `32 Cost price of Milk = Cost of production + Transportation + Packaging = 20 + 3 + 2 = `25 % profit = (32-25)/25 × 100 = 28% 10. Cost price of 4 kg Ghee + 3 kg Rice + 5 kg Milk = 4 × (80 + 8) + 3 × 40 + 5 × (20 + 3) = 352 + 120 + 115 = `587 Selling price of 4 kg Ghee + 3 kg Rice + 5 kg Milk = 4 × 120 + 3 × 42 + 5 × 32 = 480 + 126 + 160 = `766 % profit = (766 – 587)X100/587 = 30. (3). (1). If the average number of qualified candidates from State Q in 2008. If the total number of qualified candidates from State Q in 2006 and 2007 together is 408. what is the number of qualified candidates from State Q in 2010? (1)191 (2)195 (3)183 (4)187 (5)179 Q5. If the ratio of the number of qualified candidates from State P in 2009 to that in 2010 is 14:9. The number of appeared candidates from State Q increased by 100% from 2006 to 2007. what is the number of qualified candidates from State P in 2010? (1)252 (2)207 . What is the difference between the number of qualified candidates from State P in 2006 and that in 2007? (1)12 (2)22 (3)14 (4)24 (5)16 Q4. 2009 and 2010 is 210. (1)630 (2)510 (3)570 (4)690 (5)540 Q2. what is the number of appeared candidates from State Q in 2006? (1)380 (2)360 (3)340 (4)320 (5)300 Q3. (3)216 (4)234 (5)198 . What are the total runs scored by Suresh in the 2nd Match and Chris Gayle in the 3rd match? 137 195 185 127 Answer Answer 195 55 + 140 = 195 3.What is the totals runs scored by the David Warner and Chris Gayle in all the 2nd and 3rd match respectively ? 185 195 180 190 Answer 185 140+45 = 185 2.62% . Type: Missing Value Data Interpretation SBI PO Number of Questions is :10 Match-1 Match-2 Match-3 Match -4 Total Player Name Virat Kohli Suresh Raina Chris Gayle AB De Villiers Yuvraj Singh David Warner Total Of Individual Scores 110 90 82 95 60 153 530 70 75 60 415 90 70 85 72 32 80 72 540 112 89 480 335 287 324 340 320 359 1965 1.What is the maximum possible percentage contribution of Yuvraj Singh in the total runs scored in the four matches? 16. 16.Which player has the highest average in terms of the run scored in all four matches? Yuvraj Singh Suresh Raina David Warner Virat Kohli Answer David Warner 359/4 = 89.Which individual player innings score has the highest contribution percentage by a single inning in the total score of the match? .75 5.62% Explanation: Maximum possible runs scored by Yuvraj in Match-3 = 88 Maximum possible percentage contribution: (60+60+88+112)/(270+300+240+200)x100% = 320/1925 x 100% = 16.62% 4.What is the difference between total runs scored by Suresh Raina and David Warner? 75 62 72 82 Answer Answer 72 287 – 359 = 72 6.60% Answer Answer 16.72% 17.What is the Ration of marks scored by Suresh Raina and Virat Kohli in 3rd Match and marks scored by David Warner and Yuvraj Singh in the same match? 1:1 16:19 32:19 16:13 Answer 1:1 both are 160:160 = 1:1 7.62% 16. 30 *100 =30% Highest 8.What is the ratio of the marks scored by the Virat Kohli in Match 1 and Chris Gayle in Match 3? 14:6 14:5 28:10 14:10 Answer Answer 14:5 140/50 = 28/10=14:5 9.Which player has scored the third least number of runs in all the matches? Chris Gayle Yuvraj Singh AB Devilliers Virat kohli Answer Answer Chris Gayle Virat 335 Suresh Raina 287 Chris gayle 324 . David warner Yuvraj Singh Chris Gayle Virat Kohli Answer Answer David Warner Look at the highest innings score after calculating all you will finally see:David warner contribution percentage is: 153/530 = 0. Moon. The point Index (PI) of each of the companies = The number of lakh units sold during the month × points allotted The following table show the number of lakh units sold of each of the brands .ABD 340 Yuvraj 320 David Warner 359 10.What is the difference between the highest and the lowest individual score of the player in the list? 122 131 121 111 Answer Answer 121 David warner match 1 i.e 32 runs 153-32 = 121 A rating company rates the performance of three companies producing shoes. The points are allotted according to their sales.e (153) – Chris Gayle match 4 i.from Jan 07 to June 07. . Warle and Enivi . Note :1. The sum of PI in any month is not greater than 100. 2. Also the PI in Jan 07 is one more than that of March 07. and Apr 07 is identical. 8. The number of lakh units sold by Moon in Mar 07 and Apr 07 together is equal to that in May 07. 6. a) 59 b) 60 c) 61 d) 58 e) None of The Above Q3. What is the number of lakh units sold by Moon in all the six months together? a) 34 b) 32 c) 36 d) 38 e) None of The Above Q4. 3. The least possible Point Index (PI) is in Apr 07 for the sum of lakh units sold by all three companies. Find the PI of all the three companies in Apr 07. The number of lakh units sold by exactly two companies in each of the months Feb 07. What is the PI of Warle in all the six months together? a) 139 b) 153 c) 138 d) 148 e) None of The Above Solution Answer 1. What is the number of lakh units sold by Enivi in May 07? a) 7 b) 4 c) 5 d) 8 e) None of The Above Q5. Q1. Mar 07. What is the number of lakh units sold by Enivi in Mar 07? a) 5 b) 6 c) 4 d) 7 e) None of The Above Q2. 5. 7. The number of lakh units sold by all the three companies in each of the months is identical. (Option B) Answer 2. The sum of the number of lakh units sold by each of the companies in all the six months together is identical. The Point Index of Jan 07 and May 07 is 26 and 17 less than Feb 07 respectively. (Option D) . 4. The number of lakh units sold by any of the companies in any one of the months is at least 1. 9 kmph 8) What is the ratio of the total passengers of Train A to that of Train B? a) 102 : 79 b) 104 : 87 c) 103 : 87 d) 110 : 79 e) 113 : 87 9) The total income of Train A is what percent of the total income of Train B? a) 180% b) 159. 6-10): Study the given chart carefully and answer the following questions 6) The number of passengers boarding Train A at Vadodara is what percent of the number of passengers boarding Train B at Mumbai? a) 37. (Option A) Answer 4.6 kmph d) 2.30% e) None of these 7) What is the difference between the speed of Train A and that of Train B? a) 2.51% c) 123.03% d) 47.64% 10) If the average speed of Train A increases by 10% then when will it reach to its destination? a) 7:45 am b) 9:45 am c) 8:45 am . (Option D) Directions (Q.62 kmph e) 3.29% d) 125% e) 127.73 kmph b) 1. (Option C) Answer 5.03% c) 27.Answer 3.97 kmph c) 3.03% b) 47. 73 kmph 8. required % = 434000 x 100 / 340000 = 127. Option E Total income of train A = (400 × 50) + (500 × 70) + (590 × 280) + (890 × 100) + (1040 × 120) = Rs.d) 10:45 am e) 11:45 am 6.22 = 15.22 kmph Time taken by train A during the journey = 1280/81. Option A Speed of Train A = 1280 / 10:20 am – 5:00 pm = 1280 / 17 hours 20 minutes = 1280 x 3 / 52 = 73.434000 Total income of train B = (300 × 120) + (450 × 100) + (620 × 280) + (670 × 70) + (770 × 50) = Rs. difference between the speed of train A and train B = 73. Option A Required percentage = 100/270 × 100 = 37. Chetana and Divya appeared for this test and their scores are given in the following table. 4 marks are awarded for every correct answer and one mark is deducted for every wrong answer. Option C If the average speed of train A increases by 10% then its new speed = 73.75 hours = 15 hours 45 minutes The time when the train will reach its destination = 5 pm + 15 hours 45 minutes = 8:45 am Directions for questions 1 to 5: A test paper contains 50 questions.11 kmph So. Further it is also known that Divya has scored the maximum marks.84 kmph Speed of train B = 1280 / 12:00 noon ⎯6:00 pm = 1280/18 hours = 71.Who answered the second highest number of questions correctly(No two students answered same number of questions correctly)? (a) Aryan (b) Bunny (c) Chetana . Complete the following table and answer the questions that follow.84 × 110/100 = 81.84 ⎯71. Aryan. 1. 10. required ratio = 1040 : 870 = 104 : 87 9. Bunny. Option B Total passengers in train A = 400 + 100 + 90 + 300 + 150 = 1040 Total passengers in train B = 300 + 150 + 270 + 50 + 100 = 870 So.64% of the total income of train B.340000 So.11 = 2.03% 7. Choice (c) 2.If the average score of all the four students is a multiple of 5.Choice (d) .If Divya got 4th rank among the four students with the maximum possible marks then what could be the maximum number of questions she attempted? (a) 15 (b) 47 (c) 21 (d) 46 (e) Cannot be determined Answers with explanation: Directions for questions 1 to 5: Following is the complete chart: 1. then which of the following can be the score of Divya? (a) 189 (b) 188 (c) 196 (d) 191 (e) Cannot be determined 4.If all the questions attempted by Divya are not correct.Who answered the maximum number of questions incorrectly? (a) Aryan (b) Bunny (c) Chetana (d) Divya (e) Cannot be determined 3.Choice (a) 3.(d) Divya (e) Cannot be determined 2. then what is the total number of correct answers by all the four? (a) 157 (b) 167 (c) 140 (d) 146 (e) Cannot be determined 5. there are only some scores which she can score.Choice (a) For being the average a multiple of 5 Divya must attempt 48 questions and also all of them must be correct. C.If the absolute difference between the total runs scored by A and C in the four matches is minimum possible then what is the ratio of A and C’s total runs scored by them in the four matches. Directions for questions 6 to 10: A team of 5 players A.What is the maximum possible percentage contribution of A in the total runs scored in the four matches? (a) 19. D and E participated in a tournament and played four matches (1 to 4). 4. These are the runs scored by the two lowest scorers in that match. The following table gives partial information about their individual scores and the total runs scored by the team in each match.Since Divya scored maximum marks. So total correct questions by four becomes = 16 + 46 + 47 + 48 = 157. but note that she cannot score all the scores more than 187.9% (c) 20.What is the maximum possible percentage contribution of E in the total runs scored in the four matches? (a) 18.Divya must score 59 with maximum attempts. (a) 187:189 (b) 189:187 (c) 183:187 (d) 189:188 (e) Cannot be determined . hence his score is more than 187. Thus only a score of 191 is possible.7% (b) 19.2% (e) Cannot be determined 8.1% (d) 20. 6.2% (e) Cannot be determined 7. Each column has two values missing.2% (b) 19.Choice (d) In order to get maximum marks with lowest rank. Which satisfies for x = 21 and y = 25.9% (c) 18. None of the two missing values is more than 10% of the total runs scored in that match. 5.6% (d) 20. Which could be realized by the equation 4x – y = 59. B. Hence the maximum question that he could attempt is 46. Also.Option (a) Maximum possible runs scored by A in Match-1 = 27 Maximum possible runs scored by A in Match-3 = 19 Maximum possible percentage contribution: (27+100+19+53)/(270+300+240+200)x100% = 199/1010x100% = 19.6% 8.Option (c) Individual ranges for total score: A-> 189-199 .Option (c) Maximum possible runs scored by E in Match-2 = 30 Maximum possible runs scored by E in Match-4 = 20 Maximum possible percentage contribution: (60+30+78+20)/(270+300+240+200)x100% = 188/1010x100% = 18. Difference = 189 – 187 = 2 (minimum possible) Subsequently total runs scored by B in the four matches = 88 + 65 + 19 + 52 = 224.9.Option (b) Maximum possible total runs scored by C in the four matches = 27 + 30 + 110 + 20 = 187.The players are ranked 1 to 5 on the basis of the total runs scored by them in the four matches.If the absolute difference between the total runs scored by A and C in the four matches is minimum possible then what is the absolute difference between total runs scored by B and E in the four matches? (a) 32 (b) 37 (c) 35 (d) 27 (e) Cannot be determined 10. In such a case minimum possible total runs scored by A in the four matches = 23 + 100 + 13 + 53 = 189. how many players are there whose ranks can be exactly determined? (a) 0 (b) 1 (c) 3 (d) 5 (e) Cannot be determined Answers with explanation: 6. If it is known that no two players scored the same number of total runs. total runs scored by E in the four matches = 60 + 30 + 78 + 19 = 187 Absolute difference = 224 – 187 = 37 10. In such a case minimum possible total runs scored by A in the four matches = 23 + 100 + 13 + 53 = 189 Difference = 189 – 187 = 2 (minimum possible) So Required ratio is 189:187 9. with the highest scorer getting Rank 1.7% 7.Option (b) Maximum possible total runs scored by C in the four matches = 27 + 30 + 110 + 20 = 187. 6-10): Study the given table carefully to answer the given questions. It is not possible to determine the exact ranks of B and D. 6. The proportion of female employees and the proportion of post graduates in a Bank are given.85% 43.75% None of these Solution: 7.65% 44. The bank has a total of 1500 employees. What percent of employees posted as clerk are post graduates? 41.67% 52.B-> 218-224 C-> 182-187 D-> 223 E-> 187-188 Least total will be of C (Rank 5) 2nd least will be E (Rank 4) Rank 3 must be of A. What is the percentage of total employees posted as SO in the bank are females? 33. 70% of them are on the Clerical post and rest are equally divided as PO and SO.34% 66. Directions (Q.50% 42.89% 65% . 30% employees posted as Clerk who are post graduates are females. The difference between the number of post graduates who are clerks and post graduates who are PO? 350 450 460 360 400 Solution: 10. What is the ratio of total number of post graduates employees posted as Clerk to the total number of female employees posted as SO in the bank? 1:2 1:3 3:1 2:3 .61. What is the difference between the number of male post graduates and female employee who are not post graduates? 670 705 650 750 Cannot be determined Solution: 9.25% Solution: 8. 000 25. Distribution of Salary of Arvind and Akhilesh over 2001 and 2002 1.500 Solution: 2.3:2 Solution: Directions (1-5): Study the following table carefully and answer the questions below.000 18.000 22. What was the Arvind’s salary in 2001? 20.000 18. What was the percentage change Arvind expenditure from 2001 to 2002? 31 1/29% decrease 29 1/25 % decrease 15 1/25% decrease 11 1/11% decrease 11 11/25% decrease Solution: . The percentage increase in the Akhilesh’s savings from 2001 to 2002 is 50%. 30 % Rs 20% Rs 10% Rs 50% Rs None of these Solution: 4. What is the difference between the average salary of Arvind and Akhilesh for two years? 3000 4000 2000 5000 None of these Solution: 5. then find the percentage increment in his salary from 2001 to 2002. What is the total expenditure of Akhilesh and Arvind for two years? 47520 47500 45000 25400 .3. then find the distance travelled by Vatsal? 350 km 210 km 360 km 182 km None of these Solution: .None of these Solution: Directions (6-10): Study the following pie chart and bar graph carefully and answer the following questions. The speed of mohini and vatsal are same. 6. Speed of Akhil is how much percent more less than the speed of Vatsal? 20% less 10% less 50% less 40 % less None of these Solution: 9. Average of all the person’s speed is 39 1/4 km/hr 33 1/4 km/hr 39 1/5 km/hr .7. Find the distance travelled by Anuj? 140 km 180 km 240 km Cannot be determined None of these Solution: 8. 40 1/5 km/hr None of these Solution: 10. What is the ratio of angle made by Bhanu and Anuj ? 5:1 4:3 4:1 3:2 None of these Solution: Directions (1-5): 1. The seller marked the price of the item D same at its Cost price. Find the profit/loss percentage on item D? 10% Loss 20% Loss 10% Profit 20% Profit Data insufficient Solution: CP=MP=350 SP=350*90/100=315 Loss% = (350 – 315)/350 * 100 = 10% 2. The Cost price of item A is same as the cost price of item B. If the seller decides to mark the price 7% more than the Cost price, then how much discount should he offer so that he makes no profit or loss on selling the item? 6.54% 5.54% 6.14% 5.64% Data insufficient Solution: Letthediscountofferedbe‘x’% MP=107/100*100=107 SPissameasCP, 100=107/100*(100–x) 100–x=93.45 x = 6.54% 3. What is the Cost price of item C? Rs 100 Rs 120 Rs 150 Rs 200 Data insufficient Solution: SP=220*80/100=176 CP=176*100/(100+17.34) CP = 150 4. The seller marks the price of item E double the cost price. What is the percentage profit/loss he will make on the item? 25% Profit 100% Profit 25% Loss No Profit No Loss 50% Profit Solution: SP=620*75/100=465 CP=MP/2=620/2=310 % Profit = (465 – 310)/310 * 100 = 50% 5. What is the average of Cost price of the five items? Rs 150 Rs 178 Rs 220 Rs 232 Rs 202 Solution: Average = (100+100+150+350+310)/5=202 Rs Directions (6-10): Study the following graph and answer the questions Table shows the population and percentage increase/decrease of three cities in year 2001 and 2002. below. 6. What was the population (in Lakhs) of Shimla in 2001? 1.36 1.26 1.25 1.10 1.40 Solution: Population of Shimla in 2001 = 1.5 * 100/110 = 1.36 Lakhs 7. The population of Nainital in 2002 was same as that of of Shimla in 2001, then find average of total population of three cities over 2001 and 2002? population increases by 10% every year. then what was the population (approximately) of Shimla in 2005? 1.11 Lakhs 2.5 Lakhs 1.98 Lakhs 1.65 Lakhs 2.36 * Average = (1.48 66 1/3 % 33 2/3 % 33 1/3 % 66 2/3 % 50 % Solution: 9.75 Lakhs 2.02 Lakhs Solution: Population of Nainital in 2001 = 1.50+3+4+1.5* (110/100)*(110/100)*(110/100)=1.11 Lakhs 8.25 Lakhs 2. If in Shimla.36+1.25 Lakhs 2.1.50 Lakhs 2 Lakhs Solution: Population of Shimla in 2005 = 1.The population of Shimla in 2001 is what percent less than population of Ooty in 2002? 33% 55% 22% 66% 76% .36)/6=12. What is the percentage increase in the population of Ooty from 2001 to 2002? 100/92 = 1.99=2 Lakhs 10.7/6=2.48+1. 5% 90.5% None of these Solution: 2.90% 112. What is the average marks obtained by all students in French subject? 53. 1. Find the average score of all the students in Economics. Then marks obtained by Monica in Physics is what percent of marks obtained by Rachel in Physics? 127.5% 92. If score of Ross in Economics would have been 25% more.24 . 93 (2/3) 98 (2/3) 92 94 (1/2) None of these Solution: 3. If the ratio between marks obtained by Monica in Economics and marks obtained in Physics is 2 : 3.Solution: Required % = (4-1. 1-5): Given below is the percentage of marks obtained by six students in different subjects. then it would be 140 marks.36)/4*100=(2.64/4)*100=66% Directions (Q. 83 Solution: 4. then find the total marks percentage of Phoebe.83 85. Given below is the data showing cost price. If total marks obtained by Phoebe in Maths and Geography together is 1 mark less than marks obtained by Ross in Maths and English. 6-10): A person purchased 5 Gadgets from a shop and sold them online. Maths and Economics together is what percent more/less than marks obtained by Ross in Geography. selling price and profit/loss percentage. 82% 86% 80% 88% None of these Solution: Directions (Q.48. Marks obtained by Chandler in French.66 86. .54 64. Physics and Biology? (approximate) 15% more 18% more 12% less 19% less 20% more Solution: 5. If there has been a profit of 12% on Tablet instead of 12% loss.P.? 5216 5396 5336 5316 None of these Solution: 8.P. Profit percentage on Digital camera is what percent more/less than profit percentage on Laptop? 50% more 33. is how much more than the original S.34% less 33. Then the new S.67% more . Cost price of Laptop is what percent of selling price of Tablet? (approximate) 138% 182% 142% 154% 186% Solution: 7.6. 25 Profit percentage =(139203.12% profit 14. What is the ratio between profit percentage of Smart Watch to profit percentage of Smartphone? 5:3 3:2 3:5 2:5 None of these Solution: 10.12% loss 15.25-124150)/124150×100≈12.12% profit 12.15% loss Solution: Overall cost price of all items together =32445+35600+22150+28295+5660=124150 Overall selling price of all items together =40556.50% less 150% less Solution: 9.25+40940+19492+31140+7075 = 139203.12% profit Directions(Q1-5): Given below in the table showing data of a metro travelling from Rajiv Chowk to Noida city: .14% profit 33. What is the overall profit/loss percentage? (approximate) 22. 2 km/hr (e) Data insufficient Q3. If due to some problem. What is the average speed of the train from Rajiv Chowk to Noida city? (a) 75 km/hr (b) 79. If total distance from Rajiv Chowk to Noida city is 20 km.3 km/hr (c) 75. then find time taken to travel from Ashok nagar to Noida city. the train takes 2 more minutes to reach Noida city from Ashok Nagar. (a) 2 Mins (b) 3 Mins (c) 4 Mins (d) 5 Mins (e) Data insufficient Q4.5 Km Q2. By what percent time taken from station Yamuna Bank to Mayur Vihar is more/less than the time taken from Mayur Vihar to Ashok Nagar by the metro? (a) 66 2/3 % (b) 65 1/3 % (c) 62 1/3 % (d) 60 % (e) Data insufficient Q5. then by what percent the average speed of entire journey has changed? (a) 6.6 km/hr (d) 73. if the Metro train takes twice the time it takes to travel from Rajiv Chowk to Mandi house. From Mandi house to Yamuna bank station.Q1.5 Km (d) 7 Km (e) 6.35 % . then what is the distance between Mandi house to Yamuna bank station? (in km) (a) 5 Km (b) 6 Km (c) 7. 6-10): Read the following table is pie chart carefully and answer the questions given below it. Distribution of employees of a company in different department: Total number of employees = 800 Table shows the portion of female employees and portion of employees whose age is under 25 years Q6. The number of males in technical department are 180. then find the number of employees whose age is under 25 in same department? (a) 100 (b) 50 (c) 75 (d) 25 (e) 125 .(b) 7.28% (c) 8.54% (d) None of these (e) Data insufficient Directions (Q. there are no employee under 25. What is the Ratio of number of male employees from marketing department to number of employees under 25 age from content team? (a) 5 : 9 (b) 7 : 8 (c) 2 : 9 (d) 9 : 5 (e) Data insufficient Q8. then by what percent number of employee under 25 in marketing are more than number of employee under 25 in technical? (a) 100% (b) 96% (c) 104% (d) 124% (e) None of these . What percent of employees in content team are male? (a) 10 % (b) 20 % (c) 25 % (d) 40 % (e) 15 % Q9.Q7. If in Administrator department. facebook.facebook.com/groups/1594310187563413/?__mref=message . 25% of males are under 25 age then what is the ratio of number of males who are above 25 to the number of females who are under 25 age? (a) 3 : 2 (b) 2 : 3 (c) 1 : 3 (d) 1 : 2 (e) None of these FOR MORE BANKING IBPS RELATED MATERIAL JOIN https://web. If in marketing department.Q10.com/groups/466385580225591/?__mref=message https://web.