Falling diver. G M, H, T Find mag. Avg force on diver.Mgh=1/2mv^2 for velocity X=1/2 (V+Vo)t for x final V=0 X=VoT + 1/2aT^2 for a neg # F=ma Passenger in car G Vo, Vf, T, M(ofpassenger) Find mag. Of linear impulse F=ma for F Impulse=FT Avg. force experience by passeng. F=ma Speed of golfball G M1,V1,M2,V2 Find speed of M2 just after impact (m1*v1)+(m2*v1)=(m1*v2)=(m2*v2) Superman G M1, M2, VM2 Find VM1 (M1*VM1)=(M2*VM2) Find mim time so that passengers only experience avg. horiz. Force of x by their own weight. a= g*avg. horiz. Force t=v/a far does it go before it stops d=1/2a*t^2 Football G M1, M2, Vf(both) VoM2 Find VoM1 M2*Vo(M2)+M1*Vo(M1)=M2*Vf(M2)+M1*Vf(M1) Inelastic collision G M1, Vo(M2), V(of system) Find M2 Fraction that system moves at minus one then multiplied by M1 Bullet fired into block G M1, M2, H, X Find T T=((2*h)/g)^1/2 Find Vi X=VT (use t from previous) Find Vo of bullet V/((M1)/(M1+M2)) previous V Icy Plank G M1, M2, V(relative to M2) Find Vel. M1 relative to ice surfa. M1V1=M2V2 V(given velocity) Velocity of M2 rel. to surface m(g)*(v(given)-v2)=m(p)*v2 - # Vgiven-V2 subbed for Vi Billiard ball momentum G M1 & M2 is same M1 moving at 2x when hits M2 at rest M1 will move at 0x M2 will move at 2x. If M2 is moving at –x and M1 is moving at 2x M1 will move at –x M2 will move at 2x. Railroad car G M1. Hi, M2. Rotating space station G D Find Angular speed so that they weight the same as they do on earth A=(w^2)r in rads/sec solve for w use 9.81 for A Race track A section of a high speed test track is circular with a radius of curvature R = 1860 m. At what angle of θ should the track be inclined so that a car traveling at 73.0 m/s (163 mph) would keep moving in a circle if there is oil on that section of the track, i.e., it would not slip sideways even with zero friction on that section. (Hint The car's vertical acceleration is zero.) This is easy if you look at his hint from class. There is a right triangle with the y component as W= mass x gravity and the horizontal component is Fnet = mass x acceleration. You have to solve for theta by using trig. The hypotenuse doesn't matter and the masses don't matter because they cancel out in the trig ratio. Gravity you know and acceleration is calculated using a = v^2/r Highway exit The radius of curvature of a highway exit is r = 49.5 m. The surface of the exit road is horizontal, not banked. As part of a physical therapy program following a knee operation, a 13.5-kg object is attached to an ankle and leg lifts are done as sketched in the figure above. What is the torque exerted by the knee when the weight is a the 30-degree angle shown above? F=mg torque= rFsin(theta) units is N*m Point Masses in a plane If the static friction between the tires and the surface of the road is μ s = 0.557, then what is the maximum speed at which the car can exit the highway safely without sliding? R=(V^2)/(U(s)g) U(s)=static friction First and Second cosmic G M, R Find 1st cosmic speed (the speed of a satellite on a low lying circular orbit around this planet) V1 = √[G*M/R] nd Find 2 cosmic speed (min speed for satellite to break free permanently from the planet) V2 = √[2GM/R] G constant= 6.673E-11 R= (GMt^2/4pi^2)^1/3 Escape velocity The escape velocity of a bullet from the surface of planet Y is 1631.0 m/s. Calculate the escape velocity from the surface of the planet X if the mass of planet X is 1.47 times that of Y, and its radius is 0.919 times the radius of Y. KE=PE for x solve for V (just in terms of algebra) KE=PE for y solve for V (Just in terms of algebra) Put eqn for x over eqn for y cancel 2G you get v(of x) = v(of y) squareroot (Mx/My * Ry/Rx) Speed of satellite around earth Find the speed of a satellite in a circular orbit around the Earth with a radius 3.75 times the mean radius of the Earth. Multiply the given number times the radius of earth. Then plug the numbers into sqrt(G*M/R) to find the speed Planets X and Y Two planets X and Y travel counterclockwise in circular orbits about a star, as seen in the figure. The masses are Q=0.800 kg, R=0.400 kg, and S=0.700 kg. Calculate the x and y coordinates of the Center-of-Mass of this three mass system. x=(m1x1+m2x2+m3x3)/(m1+m2+m3) y=(m1y1+m2y2+m3y3)/(m1+m2+m3) Tension in cable A 38.0 kg uniform beam is attached to a wall with a hinge while its far end is supported by a cable such that the beam is horizontal. If the angle between the beam and the cable is θ = 59.0° what is the tension in the cable? (m*g)/2/sin(theta) Moment of inertia The masses are Q=0.300 kg, R=0.500 kg, and S=0.600 kg. Calculate the moment of inertia (of the 3 masses) with respect to an axis perpendicular to the xy plane and passing through x=0 and y=-3. [Since the masses are of small size, you can neglect the contribution due to moments of inertia about their centers of mass.] I= m1*r^2 +... R is the radius from the point they give you and m is the individual masses. Take mass1 * distance for that point + mass2 * radius...etc. Motion of a circle A small mass M attached to a string slides in a circle (x) on a frictionless horizontal table, with the force F providing the necessary tension (see figure). The force is then increased slowly and then maintained constant when M travels around in circle (y). The radius of circle (x) is twice the radius of circle (y). equal to M's angular momentum at x is .... that at y. false While going from x to y there is a torque on M false M's angular velocity at x is half that at y. greater than As M moves from x to y the work done by F is .... 0. true M's kinetic energy at y is four times that at x. Pivoting cylinder M, a solid cylinder (M=2.03 kg, R=0.137 m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder pulls downward with a force F which equals the weight of a 0.830 kg mass, i.e., F = 8.142 N. Calculate the angular acceleration of the cylinder. Find Hf H f = h · ( m 1 / (m 1 + m 2 ))2 Momentum Energy concept The mass m1 enters from the left with velocity v0 and strikes a mass m2 > m1 which is initially at rest. The collision between the bloc ks is perfectly elastic. The mass m2 then compresses the spring an amount x. greater than Immediately after the collision the momentum of m2 is ....... the initial momentum of m1. less than Immediately after the collision the energy of m2 is ...... the initial energy of m1. True Immediately after colliding with m2 the mass m1 moves to the left. less than The maximum energy stored in the spring is ...... the initial energy of m1. Elastic collision G M1, Vo(M1), M2, M2 is at rest Find Vf(M1) V(final of M1) = [(M1-M2)/(M1+M2)]x V(initial of M1) Find fraction of initial kinetic energery transferred to M2 V(final of M2) = [2(M2)/(M1+M2)]x V(initial of M1) to find your final of M2 Find the Kinetic Energy for M1 using KE=.5mv^2 Then find the KE for M2 AFTER collision by plugging in the V(final of M2) into the formula Divide that over the KE of M1 and that's you're fraction Pitcher momentum G M1, M2, V(M2) Find V(M1) M1*V(M1)=M2*V(M2) Find Kin. Energy of M1 KEM2 = .5 mv^2 Then set KEM2 to .5mv^2 for M1 Flatcar A man of mass M1 = 115 kg is standing on a M2 = 6300 kg railroad flatcar that rolls without friction to the right with speed 4.4 m/s. Calculate the change in velocity (in m/s) of the flatcar, if the man runs to the left so that his speed relative to the original velocity of the car is 4.3 m/s M(man) · v(man rel to car) / M(car) Automatic Weapon An automatic weapon can fire 44 bullets per minute at V = 250 m/s. If each bullet has a mass M = 25 g, what is the average force in N on the shoulder of the Marine shooting the weapon? 25·10-3 kg · 250 m/s · (44 / minute) · (1 min/ 60 s) Air puck on table G M1, M2, R Find Tension in string, M2 stays in equilibrium Fnet=T=mg Find mag. Of force that causes centrip. acc. Of M1 Tension causes centripetal acc so above answer T Find speed of puck T=(mv^2)/r solve for V The radii of their orbits are in the ratio 3 1. At some time, they are aligned, as seen in (a), making a straight line with the star. Five years later, planet X has rotated through 86.5°, as seen in (b). By what angle has planet Y rotated through during this time? (Tx^2)/(Ty^2)=(r1^3)/(r2^3) Conical motion Consider the conical pendulum, a mass on the end of a string, with the other end of the string fixed to the ceiling. Given the proper push, this pendulum can swing in a o circle at an angle θ of 39.5 with respect to the vertical, maintaining the same height throughout its motion. If the mass of the pendulum M is 12 kg, and the length of the string L is 1.1 m, what is the speed (in m/s) of the mass as it swings ? v = (tanθ g L sinθ)1/2 Torque, force If the torque required to loosen a nut that is holding a flat tire in place on a car has a magnitude of 43 N*m, what minimum force must be exerted by the mechanic at the end of a 32-cm lug wrench to accomplish the task? M=fd f minimum force d distance/length M given magnitude Wheel A wheel has a radius of 4.3 m. How far (path length) does a point on the circumference travel if the wheel is rotated through angles of Use s=RΘ for all three equations. S=pathlength R=radius theta= angle in radians X degrees convert your angle in degrees to radians. X radians plug and chug X revolutions convert revolutions to radians (rev*2π)=radians Helpcopter The diameters of the main rotor and tail rotor of a single-engine helicopter are 13.8 m and 2.16 m, respectively. The respective rotational speeds are 460 rev/min and 4170 rev/min. What is the speed of the tip of the large rotor? Circumference = diameters * pi then multiply the circumference by the revolutions/min then convert the min into seconds (divide by 60) and finally take that number and divide it by the Vsound. Solar eclips e use the equation F = (GMm)/(r^2) G=6.673 x 10^-11 (constant) M and m are the two masses r is the distance between the two masses Satellite A satellite of mass 350 kg is launched from a site on the Equator into a circular orbit at 4000 km above Earth's surface. What is the acceleration of gravity at this altitude? g'=G*(M/r^2) What is the speed of the satellite? V=(2pi*r)/T What is the period of the orbit? T^2=((4pi^2)/(G*M))*r^3 Tire on a balancing maching A tire placed on a balancing machine in a service station starts from rest and turns through 14.9 revolutions in 6.03 s before reaching its final angular speed. Calculate its angular acceleration. delta theta = w(initial)*t + 0.5*a*t^2 w(initial)=0 2*pi*rev = 0.5*a*t^2 Physical Therapy α=F*2/(M*R) If instead of the force F an actual mass m = 0.830 kg is hung from the string, find the angular acceleration of the cylinder. angular velocity = (2mg)/[(M+2m)r] How far does m travel downward between 0.670 s and 0.870 s after the motion begins? a = g/[(M/2m)+1] then plug that into delta x=.5at^2 The cylinder is changed to one with the same mass and radius, but a different moment of inertia. Starting from rest, the mass now moves a distance 0.462 m in a time of 0.470 s. Find Icm of the new cylinder. Find the acceleration using deltax=1/2at^2 Find the tension using T=m(g-a) then used I=(T(R^2))/a and thats your answer in kg*m^2 A uniform rod of length 1.45 m is attached to a frictionless pivot at one end. It is released from rest from an angle θ = 17.0° above the horizontal . Find the magnitude of the initial acceleration of the rod's center of mass. 3/ 4(G)cos(theta) If the torque required to loosen a nut that is holding a flat tire in place on a car has a magnitude of 43 N*m, what minimum force must be exerted by the mechanic at the end of a 28-cm lug wrench to accomplish the task? 32cm. is 0.32m. (43/0.32) = 134.375N Bicyc le A bicycle is moving at a speed v = 3.70 m/s. If the radius of the front wheel is 0.450 m, how long does it take for that wheel to make a complete revolution? Take the inverse of the velocity (simply 1/v) Then multiply this by the circumference. The meters cancel out and time is what is left. Arm The arm shown above weighs 47.5 N. The force of gravity acting on the arm acts through point A. Determine the magnitudes of the tension force F t in the deltoid muscle. ((Given N* shorter length)/9.8)*sin(theta) all *100=Ft Fs=Ft-fg fg= longer length A solid 18-kg cylinder rolls without slipping on a rough surface. At an instant when its center of gravity has a speed of 4.2 m/s. The kinetic energy due to the motion of the center-of-mass? The translational energy is equal to 0.5 * mass * (velocity)^2 The kinetic energy due to rotation of the block about its center-or-mass? .25 * mass * velocity^2 E for rotation is = to 1/2*I*w^2 and I=1/2*m*r^2 and w=v/r they all cancel out to get E=1/4*m*v^2 The total kinetic energy? add the above two answers together. Car . PU. as shown in the figure above.0 cubic meters of concrete weighs 5. They all place their bowling balls on the same pitch incline and release them from rest at the same time.07^2))*2. PS Force on a airplane wing What is the net upward force on an airplane wing of area 25.alpha=angular accelleration t = I*(alpha) = F*R*sin(theta) L = I*w = mvr Gravity – Et = KE + PE. As her position contracts. VR Equal to VQ is . and the specific gravity of sea water is 1. and its greatest distance being 35 A...57/2) = 1.66 N.0 mm and 2. the flywheel is attached to an electric motor.7 s. momentum and kinetic energy are conserved.3 kg) walks slowly from the rim of the platform toward the center. and that of sea water is 1030 kg/m3. 260-207 = 53 (53/60)*2Pi=5. F = GMm/r^2.U. (Assume non-viscous laminar flow ) greater than The pressure at A is ______________ the pressure at B .0 kg/m for the density of water. Greater than The time it takes for Barney's ball to hit the pins is .. that for Wilma's ball to hit. kinetic energy is not. Two tubes carry the same incompressible fluid with viscosity 1.15 feet) with a rubber seal in between are placed together and air pumped out so that the pressure inside is 17.. required at the end of the handle? F*(x/x+y) F=force from first part of problem x=shorter length y=longer length Infusion If the average gauge pressure in the vein is 1. 2VT Equal to VS is . The students then begin to walk out towards opposite edges..81 m/s2) = 549. The Flintstones and Rubbles decide to try out the new inclined bowling alley.5*118.U.8 cm is attached to a hypodermic needle with a diameter of 2.Energy Initial Energy initial is the original momentum and inertia E= L^2/ 2I Skater concept A figure skater is spinning with her arms and one leg extended as far as she can.18·10-4 m3/s) / (π (6. what must be the minimum height.93 m from the center. If the comet's speed at closest approach is 54 km/s.e. KE = ½(GMm/r) T^2 = 4pi^2r^3/GM Impulse=Force multiplied with the time its applied Momentum=mass*velocity Inelastic collision= momentum is conserved. Betty's ball and Wilma's ball have the same size. One atmosphere is 1013 millibar = 1. What is the speed of the water coming out of the hole? V=sqrt[(g/2)*(x^2/y)] If the hole has a diameter of 3. (Hint The Young's modulus of steel is 200. and Vx is the speed of a non-viscous incompressible fluid at locations x = Q. Equal to The time it takes for Wilma's ball to hit the pins is .8282584885 N .80E+11 Pa.. Consider each action below independently and indicate whether the level of the water in the pond.59 A... What fraction of the total volume of an iceberg is exposed? P(of ice)/ p(of seawater)=fraction 1-fraction=volume exposed. stick together Elastic collision. at the same time and from the same height.8282584885 N The difference is our result Force Down = B.. The relation between pressure and force is p=F/A (p = pressure F = force A = area) Since we exert force on the plunger the area relevant here is A = π d2 / 4 = π (1.570 m. Calculate the force required to pull the two hemispheres apart.58/17. 3 Find the density of the object.93^2))w' Rolling Masses The five masses below all have the same radius and a cylindrically symmetric mass distribution.8 cm)2 / 4 So we get for the force F = p · A = (11 torr) · π (1. True The students produce a net torque on the plate.45N = 4. She then pulls them in tight to her body..013×105 N/m2 ] my numbers were r=0.) Greater than VU is .7 cm? Since the flow is specified and flow is the product of velocity and area we simply have to divide the flow by the area to get the velocity v = Flow / Area = (0.elastic collisions (V of approach) = V of separation *relative velocities Kei = Kef..22 m and y = 1.5*118. Both are wearing life jackets. of the bag in order to infuse glucose into the vein? Assume that the density of the solution is 1.3*2.45 N F(outside)=94000*pi*(0. A tube carries water on the level in a nonturbulent flow condition..U. equal to Then density of the fluid at A is ____________________ the density of the fluid at B .36 N = 94.549. The flow... What is the velocity of the water in m/s when it crosses a part of the tube which has a diameter. that for Barney's ball to hit. The plate is rotated on a frictionless pivot about an axis through its center and perpendicular to its face.70E+7 Pa ∆P=ρ*g*h=W/V*h solve for h ∆P= pressure given in Pa W=weight given in N V= volume in meters cubed H= ? ∆P=(W/V)*h Water is to be pumped to the top of the Empire State Building. The string is pulled downward until the center of rotation has moved to r=20 cm.R.Weight = 643. D. False When the students reach the edge and stop the plate will have the same angular speed as when they started.V) Angu lar acc. which brings the flywheel's rotational speed up to 5800 rev/min. and the puck is moving with a speed of 85 cm/s in a circle. VU Greater than PS is .66x10^4 N for part 1 part 2 you multiply your part 1 answer by 2 and then divide by the N the horses pull so for me it would be (2 * 4. They have lengths L1 = 19 and L2 = 27 m and diameters d1 = 1.7 cm and a diameter of 0.07 m) rotates about a frictionless vertical axle..06 kg/l. = EarthSun distance). So first take your density and convert it to kg/m^3. It accelerates uniformly and the rate of rotation of its wheels increases from 207rpm to 260rpm in a time of 17. but Wilma's ball is hollow. ABCDE DCBAE).39×104 Pa.06 * 1000 = 1060kg/m^3 Now use the equation h=Pressure/(density*g) So 1.07.55(.97 mm when a mass of 320 kg is hung on the lower end.1*3. which is 1200 ft high. Diameter of a wire Find the minimum diameter of an l = 17. What is the original moment of inertia? I=M*r^2 How much work was done in pulling the string? So energy = L^2/2I and work= Energy final . Velocity) Pressure p=F/A Hydrostatic pressure P=Po+pgd Buoyancy force Fb=pfVfg Bernoulli equation p+1/2pv^2+pgh=constant Fluid speed is greatest in narrow areas Fluid pressure is greatest in larger areas A wooden ball thrown from a boat will make water level rise A golden ball thrown from a bat that sinks will make water level decrease When objects put in water force meter will decrease When objects fully submerged in water force meter will stay the same .. The table is effectively frictionless. is Unc hanged or Cannot tell.2 m2 if the speed of air flow is 202 m/s across the top of the wing and 183 m/s across the bottom? (The density of air where the airplane flies is ρair = 1..5/4..5F/sin(θ) So it's basically half the tension of the wire divided by 1/2 because I believe everyone's angle is 30° which = 1/2……same answer as last question. m1V1i + m2V2i = m1Vf + m2V2f inelastic collis ions m1V1 + m2V2 = (m1 + m2)Vf Rotation – v = w*r.39x10^4 Pa/(1060kg/m^3*9. h. what is its speed when it is farthest from the Sun in km/s? R1*V1=R2*V2 V1=(R2/R1)*V2 F=(YA/L)*delta L A= pi r^2 Magdeburg hemispheres Two steel hemispheres of radius 0.2? Same as original momentum since it is conserved. bounce back KE=1/2mv^2 Angular velocity= change in theta/change in time Angular acceleration= change in angular velocity/change in time Torque=rFsin(theta) Newton s second law= angular acceleration= torque/inertia Angular momentum= inertia*angular velocity Rotational kinetic energy=1/2(inertia)(angular velocity)^2 Angular velocity with point mass at radius r (pmrr)= perpendicular V=r(ang. Equal to The time it takes for Fred's ball to hit the pins is .5 m long steel wire that will stretch no more than 8. (Use 1000. The son is holding a large helium filled balloon by a string. They start to roll down an inclined plane.) density of object = density of water/ [1-(weight in water/weight in air)] Boat on pond A fisherman and his young son are in a boat on a small pond. a = (alpha)*r….. The flywheel can be considered as a uniform thin cylinder. Find ω (in rad/s) when the student is 2.72x10^4 N and then you do F(outside) .. Unchanged The fisherman lowers the anchor and it hangs one foot above the bottom of the pond.F. The pipe narrows from a diameter of 5 cm at "A" to a diameter of 3 cm at "B". F.. h. the scale reads 3. Px is the pressure in the pipe. is 0. Minimum force A syringe with a plunger of diameter 1. F=Tension A=area (diameter from mm to m then divide by 2 then square and then multiply by pi) delta L= the amount it is compressed (converted to m) L= the length What is the magnitude of the force on the tooth due to the wires? Disregard the width of the tooth..350 m (1.18 · 10-4 m3/s.T.. determine the force required on piston 1 necessary to support an object with a mass of 980 kg placed on piston 2.5*(density given)*((V above wing)^2-(V below wing)^2)* Area of Wing The density of ice is 920 kg/m3. (1 A. What is the tension in the wire? Y=(F/A)/(delta L/L) Y*(delta L/L) = (F/A) F=Y*(delta L/L)*A y=youngs m.17 kg.72x10^4 N .. as the students walk outward.4682584884995 N Veloc ity of a fluid The puck in the figure has a mass of 0. We know the mass of the man 56 kg.0893 m/s^2 A large horizontal circular platform (M=118.36 N The buoyant force is B. as the students walk outward.50 rad/s when the student is at the rim.66x10^4)/1480N=63 but it needs to be an even number since the horses are pulling in opposite directions and there needs to be the same number of horses on both sides so my answer for part 2 was 64 Hydraulic jack Piston 1 in the figure has a diameter of 1.6)4 = 0. Stays the Same The total angular momentum of the system . Assume that x = 1.94 N in air. Greater than The time it takes for Wilma's ball to hit the pins is .58 m.0 mm and with different elevations. starting from rest. A jet of water squirts out horizontally from a hole near the bottom of the tank. Before a trip. (pmrr)= perp acc. ``Bedslant Bowling''. Rises The son pops the helium balloon..F(inside)=4. that for Betty's ball to hit.400m P(inside)=13 millibar P(outside)=940 millibar First you have to convert millibar to N/m^2 so P(inside)=13*100=1300 N/m^2 and P(outside)=940*100=94000 N/m^2 Then you use F=P*A and A=pi*r^2 F(inside)=1300*pi*(0. The angular velocity ω of the system is 2. that for Betty's ball to hit.1 mm.. equal to The amount of fluid that passes A in one second is _____________________ the amount of fluid that passes B in one second. r=3..95 m and a mass of 575 kg. What gauge pressure is needed in the water line at the base of the building to raise the water to this height? p = (rho) g h where rho is density and h is the height of water column = 1000 kg/m^3 * 9. of 6. and assume that the pistons are massless). remains the same her angular momentum increases her rotational kinetic energy decreases her moment of inertia increases her angular velocity Bicycle problem A bicycle has wheels with a diameter of 0.4^2)=4. A) Icm= 762g cm2 M= 50g B) Icm= 962g cm2 M= 47g C) Icm= 755g cm2 M= 53g D) Icm= 881g cm2 M= 47g E) Icm= 1012g cm2 M= 50g CADEB mass and divided it by the Icm A large plate is balanced at its center and two students of equal mass stand at its center.52 mm. as seen in the figure.5 Pl.00E+4 N. what is the height of the tallest cylindrical concrete pillar that will not collapse under its own weight? The compression strength of concrete (the maximum pressure that can be exerted on the base of the structure) is 1. Decreases The rate of rotation . . What minimum force (in N) must be applied to the plunger to inject into a vein where the pressure is 11 torr above atmospheric. In the absence of friction. If 1. = V ρwater g = (m / ρman) ρwater g = 643. Thus his weight is W = m g = (56 kg) (9. Less than The time it takes for Betty's ball to hit the pins is . Young's modulus for stainless steel is 1.7=.00 millibar.1 kg..=r(angular acceleration) Inertia (pmrr)= I=mr^2 Angular momentum(pmrr) L=rm(perp. Falls The fisherman knocks the tackle box overboard and it sinks to the bottom.01·105 N/m2 / 760 torr) · π (1.F.00510543813883558 m/s Pipe concept with fluids Piston 2 has a diameter of 9. of the water level in the tank? h=(.55 5. What is the ratio of their flow rates F1/F2? ratio = F1/F2 = (L2/L1)·(d1/d2)4 = (27/19)·(1.7·10-2 m)2/4) = 0.5=((.1 mm. The wire has an unstretched length of 2. or U.3*3.4^2)=653. Rises The son gets in the water looses his grip on the string letting the balloon escape upwards. Unchanged The fisherman fills a glass with water from the pond and drinks it. with its closest approach to the Sun being 0.[Note 1 millibar=100 N/m2.A car is designed to get its energy from a rotating flywheel with a radius of 1. F1 = A1*(F2/A2) F2 = M*g A1 and A2 = pi*r^2 What is the magnitude of the force F. PT Less than PR is .58 1. The wire is stretched 0. less than The velocity of the fluid at A is ___________________ the velocity of the fluid at B .81 m/s^2 * (1200 * 0. that for Fred's ball to hit. When it is suspended from a scale and submerged in water.6 cm..07^2)+(68. So 1. Greater than The time it takes for Barney's ball to hit the pins is . Unchanged The fisherman lowers himself in the water and floats on his back. Find the linear acceleration of the bicycle. Greater than PS is .. then what is the height.GMm/(r).23 mm.49 cm. Its original distance from the center of rotation is 50 cm.0160673358875407 Force and buoyancy How much force (in Newtons) does it take to hold a 56 kg man completely under water in the ocean? His density is 913 kg/m3. that for Fred's ball to hit. Falls.07^2)+(68. What is the kinetic energy stored in the flywheel? Angular velocity w = rpm*(2π/60) meaning = (the given rev/min)*[(2*pi)/60] If the flywheel is to supply energy to the car as would a 15-hp motor.653. (Neglect the height difference between the bottom of the two pistons. An incompressible fluid moves through a pipe from left to right as shown above. find the length of time the car could run before the flywheel would have to be brought back up to speed? take the energy you solved for and divide by (746*given horsepower) and that is your time in seconds Halley's comet moves about the Sun in an elliptical orbit.3720816 N Ratio of flow rates A stainless steel orthodontic wire is applied to a tooth.0 GPa. Rises. A student (m=68.8·10-2 m)2 / 4 = 0. PE = . F is the tension (answer) from part one .73 cm. Give their order of arrival at the bottom (i. The atmospheric pressure outside is 950 millibar.5 and d2 = 4.. Fred's ball and Barney's ball are scaled down versions of Betty's ball and Wilma's ball respectively.8 cm)2 / 4 = (11 torr) (1.5*v^2)/g Laminar flow concepts The figure illustrates flow through a pipe with diameters of 1. True The students do work in walking outward.28 kg/m3. What is the original angular momentum of the puck? L=I*w I=M*r^2 L= m*r*w What is the angular momentum after the puck has moved to r=0.) ..3048) m Collisions..1*3. Tooth problem ((I(disk)+(I(student))w = ((I (disk)+(I (student))w' ((.81m/s^2) =1..S.337m Eureka A solid object weighs 13.