CSIR Chemical Sciences Paper 2

March 21, 2018 | Author: kumber_singh5069 | Category: Molecular Orbital, Molecules, Adsorption, Materials, Chemistry


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Chemical Sciences Paper I(PART ‘B’) 41. Complexes of which of the following metals are used in the treatment of rheumatoid arthritis: 1. 2. 3. 4. 42. Gold Ruthenium Iron Copper Non-heme iron-sulfur proteins are involved in: 1. 2. 3. 4. Electron transfer. Proton transfer. Both electron and proton transfer Oxygen transfer. 43. Active catalytic species for hydroformylation is 1. 2. 3. 4. RuCl2(PPh3)3 HCo(CO)3 RhCl(PPh3)3 K2PtCl6 44. The unit of molar absorptivity is: 1. 2. 3. 4. L mol–1 cm–1 L–1 mol cm–1 L mol cm–1 L mol cm 45. Gelatin is added during polarographic measurements to: 1. 2. 3. 4. reduce streaming motion of falling mercury drop increase Id increase E1/2 eliminate residual current 46. The element that shows both +3 and +4 oxidation states is: 1. 2. 3. 4. Cerium Promethium Gadolinium Holmium www.examrace.com 47. The number of 3c, 2e BHB bonds present in B4H10 is 1. 2. 3. 4. 2 3 4 0 48. In BrF3 as a solvent SnF4 and KF behave as 1. 2. 3. 4. acid and base, respectively base and acid, respectively acids bases 49. The effective nuclear charge (Z*) for the 1s electron of 8O according to Slater’s rules is nearly 1. 2. 3. 4. 4.55 3.45 7.65 5.45 50. Among the species O2+, O2 and O2–, the order of first ionization energy is 1. 2. 3. 4. O 2 + < O2 < O 2 – O 2 – < O2 < O 2 + O 2– < O 2+ < O2 O 2 + < O2 – < O 2 51. CO bond order is lowest in 1. 2. 3. 4. uncoordinated CO CO bonded to one metal CO bridging two metals CO bridging three metals 52. The most unstable species among the following is 1. 2. 3. 4. Ti(C2H5)4 Ti(CH2Ph)4 Pb(CH3)4 Pb(C2H5)4 www.examrace.com An element 'X' emits successively two β particles. 2. the oxidation state and coordination number of Ir changes. CO2 and SO2 NH3 and BH3 CO32– and SO32– SO42– and ClO4– 55. the dipole moment is the highest for 1. 4. 2. Mo2(NMe2)6 Mn2(CO)10 Fe2(CO)9 Re2Cl82- 54. 2. 3. respectively. 3. 2. 4. one α particle. respectively. NH3 trans-[PtCl2(NH3)2] BF3 NF3 58.53. 4. The mass and atomic numbers of the element are decreased by. 1. In which of the following species quadrupole bonding is involved? 1. One electron donor Two electron donor Three electron donor Four electron donor 57. In which one of the following pairs the species have similar geometry? 1. 4 and 1 5 and 1 3 and 2 3 and 1 www. In linear metal nitrosyls NO acts as a/an: 1. 3. by 1. 3.com . one positron and one neutron. 4. On oxidative addition of O2 to Ir(CO)Cl(PPh3)2. 3. 3. 1 and 3 2 and 2 3 and 1 2 and 3 56. Among the following molecules.examrace. 2. 4. 2. 4. 2. 2. [Mn(H2O)6]2+ [Cr(H2O)6]2+ [Co(H2O)6]2+ [Fe(H2O)6]2+ 64. 3. 3. 3. 4. 4. One singlet One multiplet Two singlets Two multiplets 60. 2. The 1H NMR spectrum of (η5-C5H5)2Fe recorded at room temperature has 1. square pyramidal intermediate trigonal bipyramidal intermediate pentagonal bipyramidal intermediate face capped octahedral intermediate www. 4.product also due to the formation of 1. H3PO4 is added to 1. The molar absorptivity at λmax is minimum for 1. 2. 3. all are three dimensional silicates feldspar and zeolite are three dimensional. three dimensional conductor two dimensional conductor insulator one dimensional conductor 62. muscovite mica and zeolite. maintain the pH of the medium decrease the Fe2+/3+ potential increase the oxidizing power of Cr2O72– stabilize the indicator 61. 4. The acid catalyzed hydrolysis of trans-[Co(en)2AX]n+ can give cis. while zeolite and muscovite mica are layered all are layered silicates 63. 4. Among feldspar. while muscovite mica is layered feldspar is three dimensional. In the estimation of Fe2+ by Cr2O72– using barium diphenylamine sulfonate as indicator.59. The polymeric species (SN)n is a / an 1. 2.examrace. 1.com . 3. 4. 2. 3. respectively. − . 3. the chloride 1. 15 and 15 10 and 15 10 and 10 15 and 10 68. 3. 2. six four five three 66. The number of faces and edges in IF7 polyhedron are. 3.examrace. 2. 4. In the inner sphere reduction of [Co(NH3)5Cl]2+ with [Cr(OH2)6)]2+. 4. − N3 and hydrozine N2 and azobenzene − N3 and azobenzene N2 and hydrazine 69. 3. Only one absorption band is observed in visible region of spectrum of 1. bridges the metal centres only mediates electron transfer only bridges and mediates electron transfer both does not play any role 67.65. The total number of lines expected in 1H NMR spectrum of HPF2 is (I = 1/2 for both 19F and 31P) 1. O2 can be converted to O + 2 by using 1. azobenzene and hydrazine. the shortest and longest N–N Among N2. 4. respectively 1. 2. 2. [Ni(H2O)6]2+ [Ti(H2O)6]3+ [Fe(CN)6]4– VO34 www. 3. 4. 3. 4. in 1. 2. N 3 distances are found. PtF6 KF Na2S2O3 Br2 70.com . 4. 2. com .2'-bipyridine) and [Mn(acac)3] (acac = acetylacetonate anion) show the same spin-only magnetic moment? 1. Which two among [Fe(CN)6]3–. [Fe(CN)6]3– and [FeF6]3– [Fe(CN)6]3– and [Cu(bpy)2]2+ [FeF6]3– and [Mn(acac)3] [Cu(bpy)2]2+ and [Mn(acac)3] 73. 2. Heating is observed when N2 gas at 200 atm is expanded at T > 600 K. 3. An exothermic reaction will necessarily follow the condition 1.examrace.71. 3. inversion temperature is smaller than 600 K N2 is a real gas Joule-Thomson coefficient is negative Joule-Thomson coefficient is positive www. 2. 3. 2. 4. It is because 1. In aqueous medium a mixture of KI and I2 converts thiosulfate to 1. 4. [Cu(bpy)2]2+ (bpy = 2. UV-visible spectroscopy IR spectroscopy Microwave spectroscopy NMR spectroscopy 72. 2. [FeF6]3–. 3. S4O62– SO42– S2O62– S2O42– 74. 4. 3. 4. 4. 2. 3. ∆Η < 0 ∆Η > 0 ∆Η = 0 ∆S = 0 75. 4. 2. The unit of rate constant (k) for a zero-order reaction is 1. s-1 L mol-1 s-1 s mol L-1 s-1 76. CFSE of transition metal complexes can be determined by 1. 2. 3. 3. 3. 2. 78. C2h C2v D2h D2d 82. heat is absorbed reversibly at higher temperature heat is absorbed reversibly at lower temperature heat absorbed reversibly is independent of temperature heat absorbed reversibly is independent of phase of the system. 4. ln K ln K ln K ln K = (nFE o / RT ) = − (nFE o / RT ) = ( RT / nFE o ) = − ( RT / nFE o ) 80. 3. 4. 79. 2. Increase in disorder is more if 1. 2n octahedral and n tetrahedral sites n octahedral and n tetrahedral sites 2n octahedral and 2n tetrahedral sites n octahedral and 2n tetrahedral sites 81. The point group symmetry of the molecule CH2Cl2 is 1. 4. 2. 2. 3. 2 2 1 The term symbol of Li + 2 with configuration (1σg) (1σu) (2σg) is 1. 2. The point group symmetries of isosceles and equilateral triangles respectively are 1. C3v and D2d D3h and D2d D3h and C2v C3v and C2v www.77. 1 ∑ + g 1 ∑ − g − g + g 2 2 ∑ ∑ Which one of the following equations is used for the calculation of equilibrium constant (K) of an electrochemical cell reaction (n = number of electrons transferred. 3. 4. Cubic close packing of n spheres generates the following number of interstitial sites 1. 4.examrace.com . F = Faraday constant and E° = standard redox potential)? 1. 4. com . 3. The infrared spectrum of CO2 exhibits the following number of absorptions: 1. 4. 2. one two three four 84. The first line in the rotational Raman spectra of a diatomic molecule appears with a Stokes shift of 12 cm–1. The rotational constant of AX is 1. 4. π → π∗ σ → σ∗ n → π∗ δ → δ∗ www. 3. Which of the following molecules shows EPR resonance? 1. 4. 2. Which of the following electronic transitions is disallowed? 1. 2. 2. 4. The Stokes shift for the second line is 1. 3.examrace. 10 cm–1 20 cm–1 5 cm–1 15 cm–1 87. 3. 36 cm–1 24 cm–1 18 cm–1 20 cm–1 85. 2. The R branch in the vibrational spectra of AX exhibits a set of equally spaced lines with a separation of 10 cm–1. 3. anharmonicity is large anharmonicity is absent vibration and rotational modes are coupled an alternating electric field is applied 88. 4.83. H 2O O2 H2O2 CO2 86. 3. 4. 2. Overtones are observed in the vibrational spectra of diatomic molecules when 1. examrace. 3. When we introduce anharmonicity in the harmonic vibrator model of a diatomic molecule. the energy-level spacing changes from 1. –1 ≤ ρ(x. For a one-electron atom with nuclear charge Z. equal to gradually decreasing gradually decreasing to equal equal to gradually increasing gradually increasing to equal 92. D A C B S then the system rejects heat to the surroundings in going from 1. y) for two variables x and y satisfies 1. 4. 3. B→A A→B D→C C→D The correlation coefficient ρ(x. 90. 3. y) ≤ 1 0 < ρ(x. 4. 2. The optimized variational wavefunction gives 1. vn ∝ vn ∝ vn ∝ vn ∝ Z Z2 Z –1 Z –2 93. 2. T If the Carnot cycle in entropy-temperature diagram looks as below. 2. 3. 4. y) < 1 91. the speed vn of the electron in some n-th stationary orbit satisfies 1. y) < 1 0 ≤ ρ(x. y) ≤ 1 –1 < ρ(x. all properties and energy of same quality properties better than the energy energy better than properties equal kinetic and potential energy values www. 2.com . 2. 4. 3. 4.89. 2. 2. The simple MO theory does not include any ionic terms. The commutator [Ly. The MOs can be delocalized over all the atoms. 2. The following statement is true for any hermitian operator: 1. 3.com . The 2px hydrogenic orbital has the ф-part in its wavefunction of the form 1.94. e–iφ e+iφ sin φ cos φ 98.examrace. 3. zero –iLZ –iηLZ –ηLZ 95. 4. www. 2. The VB theory views molecules as composed of atomic cores and bonding valence electrons. All eigenvalues are real and non-degenerate All eigenfunctions are real All eigenfunctions are complex All eigenvalues are real 96. 3. 2. 3. Lx] has a value equal to 1. 4. The VB uses non-orthogonal basis. Which of the following statements about valence bond (VB) and molecular orbital (MO) theory is false? 1. 4. 4. 4. 3. n=3 ℓ=2 λ=2 mℓ=2 97. A δ molecular orbital of a diatomic molecule is defined by 1. M n = 10.000 will have the number average molar mass equal to: 1.000 and 30. 2. 3. increases exothermicity and activation barrier decreases exothermicity. but irregularly 101. 3.000 M n = 25. but does not change the exothermicity. ˆ 2 ψ is given by ˆ ψ = iη dψ . 2. 4.000 M n = 15.com . 2. 2. but increases barrier increases exothermicity only decreases activation barrier. 3. 3.000 M n = 20.99. 4. ⎛ dψ ⎞ − η2 ⎜ ⎟ ⎝ dx ⎠ d 2ψ − η2 2 dx ⎛ dψ ⎞ η ⎜ ⎟ ⎝ dx ⎠ d 2ψ η2 2 dx 2 2 2 100. An equimolar mixture of two macromolecules of molar masses 10. Addition of a positive catalyst to an exothermic reaction 1.000 102. 4. 4. If all the energy-levels of a system are given a constant shift by an amount α. 103.examrace. then A ˆ an operator and A If A dx 1. superconductor metal semiconductor semimetal www. The electrical conductivity of a crystalline solid increases with temperature. the entropy of the system 1. 4. does not change at all changes by the amount of α decreases increases. 3. 2. The solid is a 1. 2.4 × 10–28 and 1. respectively.6 × 10–24. Heat of coverage varies linearly with temperature Adsorption is multilayer Heat of adsorption is independent of coverage Complete coverage cannot be determined 106. V is the volume of gas adsorbed. 6.3 × 10–18. PbS and ZnS are 8. 2. 4.examrace. Pb2+ Zn2+ Fe2+ Cu2+ 105. IUPAC name of the compound given below is COOH 1. 4-methylcyclohex-4-enecarboxylic acid 4-methylcyclohex-3-enecarboxylic acid 1-methylcyclohexene-4-carboxylic acid 2-methylcyclohexene-5-carboxylic acid www. 2. 1/V 1/P Which of the following statements is true? 1. the second order diffraction from the 200 planes first order diffraction from the 200 planes first order diffraction from the 400 planes first order diffraction from the 100 planes 107. 3. 3. 3. 2. Ksp values for CuS. 3. 3. 4. The second order Bragg diffraction from the 100 planes of a cubic crystal is equivalent to 1. If H2S gas is passed through a solution containing these ions with same molar concentration.com . the ion that will precipitate first is 1.5 × 10–45. 4. 4. The experimental adsorption data of a gas on a solid surface at temperature T exhibits the following variation with pressure. FeS.104. 3]-sigmatropic rearrangement 6π-electrocyclisation reaction 110. NHCHO 3.5]-sigmatropic rearrangement [4+2]-cycloaddition reaction [3. 4. NC 2. 3. Cope rearrangement involves 1.com . The major product formed in the reaction given below is i. 2. www. O 3. NH2OH CHO ii.examrace.108. 4. [1. P2O5 1. 2. NHNH2 COOH 4. The major product formed in the reaction given below is O Cl NH2NH2 KOH Cl 1. CONH2 CN 109. 4.111.3-dichloropropane 1. 3. 3. 113. A>B>C B>A>C B>C>A C>B>A The photochemical Paterno-Büchi reaction is a cycloaddition between 1. 4. the hydrogens HA and HB are 1. 4. are O 2 Me H HO 4 H 1. 2.2-dichloropropane 1. 2. 2E 4S. 2. 2Z 4S. homotopic enantiotopic diastereotopic isotopic An organic compound with molecular formula C3H6Cl2 exhibits only one signal in the 1H NMR spectrum.examrace. two >C=C< groups a >C=O and >C=C< groups a >C=N-R and >C=C< groups a >C=S and >C=C< groups www. The compound is 1. The stereochemical descriptors for the chiral centre and olefin in the compound given below.1-dichloropropane 114. 112. 2Z 4R. 3. 3. 2E HA HB OH In the compound given below. 4. 4R. The order of λmax in the UV-Vis spectra for the compounds A-C is A B C 1.com . 115.2-dichloropropane 1. 2. 3. 4. 2. 2. www. A B C D The LUMO of the ground state buta-1. 4. 4. 4.examrace. 3.3-diene is 1.com . 3.3]-sigmatropic shift upon heating A B C D 1. 118. 3. 2.116. 2. π4s + π2s cycloaddition 4 π s + π2a cycloaddition π4a + π2s cycloaddition π4a + π2a cycloaddition Which one among the dienes A-D will undergo [3. 117. The reaction given below is an example of O + O O ∆ O O O 1. 2. The major product formed in the reaction given below is OH OTs EtOH / ∆ 1. In the reaction given below. BH3. OTs CHO 4. the orientation of two bromine substituents in the product is Br2 Br 1 2 Br 1. 4. 2.119.com . 120. O 3. 121. equatorial at both C-1 and C-2 equatorial at C-1 and axial at C-2 axial at C-1 and equatorial at C-2 axial at both C-1 and C-2 www. 3. 4. The transformation given below can be achieved using O 1. 120 105 77 65 122. OTs 2.THF followed by H2O2 / NaOH alkaline KMnO4 / NaIO4 pyridinium chlorochromate PdCl2 / CuCl2 / O2 / H2O The base peak in the electron impact mass spectrum (EI MS) of acetophenone is 1. 2.examrace. 3. 3. 2. 4. 3. The order of nucleophilicity among PhNH2. EtNH2 and PhNHNH2 is 1. Which one of the following name reactions is an example of atom economy reaction? 1. Which one among the compounds A-D will have highest dipole moment? C C A B C D 1. 4. KOH hydrazine hydrate H2-Pd/C tetrabutylammonium fluoride 124. 4. 4. 125. CF3COOH and CCl3COOH is 1.examrace. 2. 4. 3.com . A B C D The major products formed in the nitration (HNO3 / H2SO4) of aniline and acetanilide are 1. 2. 2. 4. 3. PhNHNH2 > PhNH2 > EtNH2 EtNH2 > PhNH2 > PhNHNH2 PhNHNH2 > EtNH2 > PhNH2 EtNH2 > PhNHNH2 > PhNH2 128. 2. 3. 3. 2. Wittig reaction Grignard reaction Dieckmann condensation Diels-Alder reaction 127.123. The order of acid strengths of CH3COOH. o-nitroaniline and o-nitroacetanilide m-nitroaniline and p-nitroacetanilide p-nitroaniline and m-nitroacetanilide m-nitroaniline and m-nitroacetanilide 126. Cyclohexyl benzyl ether is converted to cyclohexanol using 1. 3. 4. CCl3COOH > CF3COOH > CH3COOH CCl3COOH > CH3COOH > CF3COOH CF3COOH > CCl3COOH > CH3COOH CF3COOH > CH3COOH > CCl3COOH www. 5% aq. 2. examrace. 4. 4. CrO3 / H2SO4 MnO2 KMnO4 / H+ RuCl3 / NaIO4 An optically active compound A having molecular formula C6H12 on catalytic hydrogenation gives an optically inactive compound (C6H14). 2. NH3 www. The most suitable reagent to achieve the transformation. Me 3. 2-methylpentene 3-methylpentene 3. 2.129. The reagent suitable for converting oct-4-yne to trans-oct-4-ene is 1.com . 3. NaOH 1. 130. H2 – Pd/C Pd / CaCO3 / H2 NaBH4 Na / liq. O 2.3-dimethylbutene 4-methylpentene 132. 2. 3. The compound A is 1. is OH O HO HO 1. O O 4. ozonolysis Me O ii. 3. 131. 4. The major product formed in the reaction given below is Me i. given below. is CN i. Cl O 1. 3. Which one of the following is a polar aprotic solvent? 1.N-dimethylformamide 4. is N OH PCl5 MeO NH Cl O NH MeO O NH Cl OMe 134. The major product formed in the reaction. CHO O 2. toluene 2. www. H3O+ 1. acetic acid The major product formed in the reaction. given below. carbon tetrachloride 3. N. given below. Cl O NH Cl 4.examrace.com . NH2 CN 4. 2. EtMgBr ii.133. 3. MeO OMe 135. The most suitable reagent for carrying out the transformation given below. monoterpene sesquiterpene diterpene triterpene The major product formed in the reaction of ethyl acetoacetate with sodium hydride (1 equivalent) and methyl iodide (1 equivalent) is O 1. 4. MeO O OEt O 4. 137. is OH Me Me 1.136. 2. 3. O O O www. 3. 138. given below. 4. OEt Me 2. O Me OEt 3. aq. 2. is a COOH 1. H2SO4 Hg(OAc)2 followed by reaction with NaBH4 / NaOH B2H6 followed by reaction with H2O2 / NaOH m-CPBA followed by reaction with dil H2SO4 Natural product abietic acid.examrace.com . The reaction of phenylacetylene with one equivalent of methylmagnesium bromide followed by reaction with benzaldehyde provides 1. 2. glucose and glucose glucose and galactose glucose and fructose glucose and mannose www. Sucrose is a disaccharide consisting of 1. Me Ph HO 4. 3.139. Ph Ph 3. 4. Ph Me H Ph Ph Me H 140.examrace.com . OH Ph OH 2.
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