© AMC Consultants Pty Ltd 2005BASIC MINE VENTILATION I have omitted all those things which I have not myself seen, or have not read or heard of from persons upon whom I can rely. That which I have neither seen, nor carefully considered after reading or hearing of, I have not written about. The same rule must be understood with regard to all of my instruction, whether I enjoin things which ought to be done, or describe things which are usual, or condemn things which are done. Georgius Agricola, Preface to De Re Metallica, 1556. Revision 5 © AMC Consultants Pty Ltd 2005 BASIC MINE VENTILATION INTRODUCTION Page i © AMC Consultants Pty Ltd 2005 INTRODUCTION Safe, sustainable underground mining of any scale is not possible without an effective ventilation system. Ventilation is required in the underground workings to: - Dilute gaseous and particulate pollutants to concentrations which are not injurious to the health and safety of the workforce - Maintain thermal comfort through the provision of adequate air velocity - Assist with maintaining workforce morale and productivity through the provision of high quality underground environmental conditions An efficient and effective mine ventilation system is not achieved by accident. It requires incorporation of a solid understanding of scientific ventilation principles into the very core of the mine planning and management process. Important lessons can be learnt from history which has emphasised time and time again is that the knowledge required to implement effective mine ventilation has often been significantly more advanced than the practices adopted in the mines at the time. The terrible loss of life in the British coal industry in the 19 th Century (which did not abate until the belated introduction of legislation early in the 20 th Century) is a sobering example. More recent examples of the same phenomena in Australia include the many cases of mesothelioma contracted by underground miners in Wittenoom in the 1950s and 60s as well as the Moura mine disasters of the 1980s and 1990s. In all of these examples, the health and safety risks were well known, as were the engineering requirements necessary in order to minimise these risks. The costs of installing and managing effective ventilation systems must have been minuscule compared with the subsequent outlays for compensation. One inference which could be drawn from all of this is that ignorance and indifference have been (and perhaps still are) important factors. Brief History of Mine Ventilation P r e M i d d l e A g e s There is evidence to suggest that the need to establish ventilation circuits with intake and return airways was understood and practiced by the Greeks. For example there was twin access development and divided shafts in the Laurium silver mines of Greece (600 BC). In the Roman times, slaves waving palm fronds were used to promote air circulation. (Pliney AD 23-79). More generally, air movement was created by up-draughts of warm air from fires lit for this purpose underground. M i d d l e A g e s I n d u s t r i a l R e v o l u t i o n Mine ventilation practices of the day are illustrated and described in De Re Metallica, by Georgius Agricola, 1556. This was amongst the first books ever printed and remained a standard mining text for the next 200 years. The book describes horse and human powered centrifugal fans; bellows connected to wooden conduits, ventilation doors and shaft collar deflectors, which divert winds into the mine workings. Agricola also described the dangers of blackdamp (oxygen reduced air) and the explosible firedamp (an air and methane mixture likened to the fiery blast of a dragons breath). BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page ii © AMC Consultants Pty Ltd 2005 I n d u s t r i a l R e v o l u t i o n I n f o r m a t i o n A g e This period saw an unprecedented increase in demand for mineral commodities including coal, metalliferous ores and industrial minerals. Substantial growth in mining activity, (much of it underground) was required to satisfy this new demand. Larger scale mining led to increasing numbers of miners suffering from health problems contributed to by poor ventilation, including black lung, mine explosions and fires. Hot working conditions at depth due to ventilation limitations also restricted the extent of mining activities. The increasing slaughter of men, women and children in British coal mines as a result of explosions and fires eventually served as a major impetus to drive the development of the science of underground ventilation in the 19 th Century. John Atkinson, a British mining agent presented his famous paper On the Theory of the Ventilation of Mines in 1854 and Atkinsons Equation still forms the basis for all mine ventilation engineering. Interestingly, whilst the importance of Atkinsons paper and theories were recognised at the time they were published, they received little interest and were considered too much for the engineers of the day. It wasnt until some 60 years after Atkinsons death that his theories were rediscovered. In the 1920s and 1930s large axial fans based originally on aeroplane propeller designs began to become popular. Analogue computer models were used in the 1950s to analyse ventilation networks. The introduction of diesel equipment underground in the 1960s and 1970s required substantial increases in mine ventilation capacity. Many mines of the day embarked on massive upgrades to ventilation shafts and main surface fans. Great advances in large fan design were made in the 1960s and 1970s. At about the same time, improvements in large scale refrigeration technology began to allow very deep orebodies to be accessed, particularly in South Africa. I n f o r m a t i o n A g e The most notable feature has been the development of computerised mine ventilation network analysis. This has made prediction of fan requirements and airflow distributions in complex mine ventilation circuits feasible using desktop computers. BASIC MINE VENTILATION INTRODUCTION Page iii © AMC Consultants Pty Ltd 2005 Table Of Contents 1 CONTAMINANTS AND EXPOSURE STANDARDS............................................... 1 1.1 Peak Limitation ......................................................................................................... 2 1.2 Short Term Exposure Limit (STEL)........................................................................... 2 1.3 Time-Weighted Average (TWA)............................................................................... 3 1.4 Guidance on General Excursion............................................................................... 3 1.5 Adjusting the Eight-hour Exposure Standard for Longer Periods............................. 3 2 OCCUPATIONAL HEALTH AND SAFETY............................................................. 5 2.1 The Respiration System............................................................................................ 5 2.2 Dust........................................................................................................................... 7 2.2.1 The Hazard of Dust ...................................................................................... 7 2.2.2 Effects of Dust ............................................................................................ 11 2.2.3 Dust Exposure Standards........................................................................... 12 2.2.4 Explosive Dusts.......................................................................................... 12 2.3 Heat......................................................................................................................... 13 2.3.1 Air Temperature.......................................................................................... 16 2.3.2 Body Heat Balance..................................................................................... 17 2.3.3 Thermoregulation ....................................................................................... 18 2.3.4 Heat Related Illness ................................................................................... 20 2.3.5 Heat Stress Indices .................................................................................... 21 2.3.6 Air Cooling Power....................................................................................... 24 2.3.7 Management of Hot Working Conditions.................................................... 26 2.4 Mine Gases............................................................................................................. 31 2.4.1 Constituent Gases of the Atmosphere ....................................................... 31 2.4.2 Carbon Dioxide (CO 2 )................................................................................. 31 2.4.3 Oxygen (O 2 ) ................................................................................................ 32 2.4.4 Carbon Monoxide (CO) .............................................................................. 32 2.4.5 Oxides of Nitrogen (NO x )............................................................................ 33 2.4.6 Sulphur Dioxide (SO2)................................................................................ 34 2.4.7 Hydrogen Sulphide (H 2 S) ........................................................................... 34 2.4.8 Methane (CH 4 )............................................................................................ 34 2.4.9 Coal Damps................................................................................................ 35 2.4.10 Ammonia (NH 3 )........................................................................................... 37 2.4.11 Radon (Rn) and Radon Daughters............................................................. 37 2.5 Diesel Engines........................................................................................................ 41 2.5.1 Diesel Exhaust Emissions (DEE) ............................................................... 41 2.5.2 Diesel Particulates...................................................................................... 42 2.5.3 Dilution of Diesel Exhaust Emissions (DEE) .............................................. 44 3 PROPERTIES OF AIR........................................................................................... 47 3.1 Air Temperature...................................................................................................... 47 3.2 Charles Law........................................................................................................... 48 3.3 Boyles Law............................................................................................................. 48 3.4 Universal Gas Law.................................................................................................. 48 3.5 Density of Dry Air .................................................................................................... 48 3.6 Moisture in Mine Air ................................................................................................ 49 3.7 Density of Humid Air ............................................................................................... 50 3.8 Air Pressure ............................................................................................................ 51 3.8.1 Atmospheric Pressure ................................................................................ 52 3.8.2 Barometric Pressure................................................................................... 52 3.8.3 Static Pressure (SP) ................................................................................... 53 3.8.4 Velocity (Dynamic) Pressure (VP).............................................................. 53 3.8.5 Total Pressure (TP) .................................................................................... 53 3.8.6 Measuring Pressure in a Duct .................................................................... 54 3.8.7 Natural Ventilating Pressure....................................................................... 54 BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page iv © AMC Consultants Pty Ltd 2005 3.9 Assignments ........................................................................................................... 57 4 FUNDAMENTALS OF AIRFLOW......................................................................... 58 4.1.1 Laminar Flow.............................................................................................. 59 4.1.2 Turbulent Flow............................................................................................ 59 4.2 Airflow Equation...................................................................................................... 59 4.3 Resistance (The friction factor). .............................................................................. 60 4.3.1 Atkinsons Equation.................................................................................... 62 4.4 Shock Losses.......................................................................................................... 64 4.4.1 Entrance ..................................................................................................... 66 4.4.2 Outlet Losses.............................................................................................. 66 4.4.3 Elbows ........................................................................................................ 67 4.4.4 Expansions and Contractions..................................................................... 68 4.4.5 Junctions and Splitting................................................................................ 68 4.5 Other Methods of Expressing the Shock Factor X ................................................. 69 4.6 Series Circuits......................................................................................................... 70 4.7 Parallel Airway Circuits ........................................................................................... 71 4.8 Complex Circuit (Networks) .................................................................................... 72 4.9 System Resistance Curve ...................................................................................... 73 4.10 Assignments ........................................................................................................... 74 5 MEASURING AIRFLOW....................................................................................... 84 5.1 Vane Anemometer .................................................................................................. 84 5.2 Hot Wire Anemometer ............................................................................................ 85 5.3 Velometer................................................................................................................ 85 5.4 Smoke Tube............................................................................................................ 85 5.5 Pitot-Static Tube ..................................................................................................... 86 5.6 Selection of Measurement Site............................................................................... 87 5.7 Measuring the Airway Cross Sectional Area .......................................................... 88 5.8 Traverse Velocity Measurement ............................................................................. 88 5.9 Spot Reading Method ............................................................................................. 89 5.10 Single Spot Reading Method.................................................................................. 89 6 UNDERSTANDING FANS..................................................................................... 90 6.1 General Description of Fans ................................................................................... 91 6.2 Fan Terminology..................................................................................................... 92 6.3 Axial-Flow Fans ...................................................................................................... 93 6.3.1 Construction of an Axial-Flow fan............................................................... 94 6.4 Centrifugal or Radial-Flow fans .............................................................................. 94 6.4.1 Construction of a Centrifugal Fan............................................................... 95 6.5 The Fan Characteristic (Performance) Curve......................................................... 95 6.6 Interpreting Fan Performance Curves .................................................................. 100 6.7 Fan Stall ................................................................................................................ 101 6.8 Fan Performance Control...................................................................................... 101 6.8.1 System Damper........................................................................................ 102 6.8.2 Outlet Damper .......................................................................................... 102 6.8.3 Inlet-Box Damper...................................................................................... 103 6.8.4 Variable Inlet Vanes ................................................................................. 103 6.8.5 Variable Speed......................................................................................... 104 6.8.6 Variable Pitch ........................................................................................... 104 6.8.7 Fans in Series........................................................................................... 105 6.8.8 Fans in Parallel ......................................................................................... 106 6.8.9 The Eck Line........................................................................................... 107 6.8.10 Fan Diffuser .............................................................................................. 108 6.9 Fan Laws ..............................................................................................................109 6.10 Measuring Fan Performance ................................................................................ 109 6.10.1 Fan Total Pressure................................................................................... 110 BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page v © AMC Consultants Pty Ltd 2005 6.10.2 Fan Velocity Pressure .............................................................................. 110 6.10.3 Fan Static Pressure.................................................................................. 111 6.11 Pressure Fans....................................................................................................... 111 6.11.1 Selection of Measuring Site...................................................................... 111 6.12 Exhausting Fans ................................................................................................... 112 6.13 Air Power .............................................................................................................. 113 6.14 Fan Efficiency ....................................................................................................... 114 6.15 Measurement of Airflow........................................................................................ 115 6.16 Fan Laws ..............................................................................................................117 6.16.1 Density (µ) Change.................................................................................. 117 6.16.2 Speed Change.......................................................................................... 117 6.16.3 Diameter Change ..................................................................................... 117 6.17 Fans Failure.......................................................................................................... 119 6.18 Effect of Reversal of Rotation............................................................................... 119 7 MANAGEMENT................................................................................................... 121 7.1 Primary Airflow Requirements .............................................................................. 122 7.1.1 Determining Primary Air Quantities. ......................................................... 122 7.2 Primary Ventilation Fans....................................................................................... 125 7.2.1 Surface Fan Installation Arrangements.................................................... 126 7.2.2 Underground Primary Fan Arrangements ................................................ 127 7.2.3 Forcing or Exhausting............................................................................... 127 7.3 Circuit Booster Fans ............................................................................................. 127 7.4 Primary Ventilation Circuits................................................................................... 128 7.4.1 Parallel (One Pass) Circuits ..................................................................... 128 7.4.2 Secondary Fans and Parallel Ventilation Circuits. ................................... 129 7.4.3 Series Ventilation Circuits......................................................................... 129 7.4.4 Use of Stope Voids as Airways ................................................................ 129 7.4.5 Recirculation............................................................................................. 130 7.5 Ventilation Controls............................................................................................... 130 7.6 Multiple Access Orepasses .................................................................................. 131 7.7 Secondary Ventilation Systems............................................................................ 131 7.7.1 Installing Secondary Ventilation Fans ...................................................... 132 7.7.2 The Reuse of Air .................................................................................... 133 7.8 Ventilation Duct..................................................................................................... 134 7.9 Duct Leakage........................................................................................................ 135 7.10 Velocities in Primary Airways................................................................................ 137 7.10.1 Velocities in Access Drives....................................................................... 137 7.11 Water in Upcast Shafts ......................................................................................... 138 7.12 Equipment Movement in Underground Airways ................................................... 138 7.13 Re-entry after Blasting in a Development Heading .............................................. 140 7.14 Gases from Sulphide Orebodies........................................................................... 145 7.15 Gasses from Diesel Engines ................................................................................ 146 7.16 Control of Mine Gases .......................................................................................... 146 7.16.1 Prevention................................................................................................. 146 7.16.2 Extraction.................................................................................................. 146 7.16.3 Isolation .................................................................................................... 146 7.16.4 Containment ............................................................................................. 146 7.16.5 Dilution...................................................................................................... 146 7.17 Effect of Atmospheric Changes on Mine Strata Gases ........................................ 147 7.18 Spontaneous Combustion .................................................................................... 147 7.19 Control of Dust ...................................................................................................... 149 7.19.1 Dust Extraction ......................................................................................... 151 7.20 Economics of Airflow............................................................................................. 154 7.20.1 Cost of Airflow........................................................................................... 155 7.20.2 Optimum Airway ....................................................................................... 156 7.20.3 Time Value of Money................................................................................ 157 7.21 Rule-of-Thumb Principles and Design Factors..................................................... 158 BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page vi © AMC Consultants Pty Ltd 2005 8 NETWORKS AND COMPUTER MODELLING................................................... 160 8.1 Ventilation Networks ............................................................................................. 160 8.2 Analysis of a Network ........................................................................................... 161 8.2.1 Hardy Cross.............................................................................................. 162 8.3 Computer Modelling.............................................................................................. 163 8.4 Input Data ............................................................................................................. 164 8.4.1 Simulation Model Layout .......................................................................... 164 8.4.2 Number of Airways ................................................................................... 164 8.4.3 Friction Factors......................................................................................... 165 8.4.4 Shock Losses ........................................................................................... 165 8.4.5 Fans.......................................................................................................... 165 8.4.6 Fixed Airways ........................................................................................... 166 8.5 Results: ................................................................................................................. 166 BASIC MINE VENTILATION Contaminants and Exposure Standards Page1 © AMC Consultants Pty Ltd 2005 All substances are poisons; it is only the dose that separates the poison from the remedy Paracelsus - 15 th Century 1 CONTAMINANTS AND EXPOSURE STANDARDS The basic requirement for the mine ventilation system is to provide air for people to breath and in a state that will not cause any immediate or future ill effects. Because of the processes of mining, if positive airflow through the workings was not provided the air would very quickly become stale, contaminated and unfit for human consumption. The ventilation system must therefore be sufficient to deal with the contaminants released during mining. If they are not adequately dealt with, as they are identified, they may become at best a discomfort to mine workers, and at worst cause serious or even fatal illness. The prime contaminants produced during mining are 1. dust 2. heat 3. gases (including water vapour i.e. Humidity) and the prime method for dealing with these is an effective ventilation system that 1. supplies oxygen and coolth 2. dilutes dust and gases and 3. removes the contaminants from the workplace. It is possible that any known substance will be identified, in either the air we breathe or the food we eat. Although the human body is equipped to reject or absorb these substances this can only be done providing the quantities involved are not excessive. The search to identify specific substances and their harmful concentrations is on going with limits constantly under review. Levels of atmospheric contaminants that are safe in an occupational health and safety environment are often difficult to determine. There are many factors which must be considered including: - Variability in response of individuals to contaminants - Synergistic effects (i.e. combined effect of simultaneous exposure to several contaminants) - Work rate (affects respiration rate) - Work cycle (compressed work cycles give the body less recuperation time between exposures) - Changes in scientific understanding As a result of the above factors, recommended maximum exposures to various contaminants are constantly under review and the latest information should always be sought Worksafe Australia produce a publication titled Exposure Standards for Atmospheric Contaminants in the Occupational Environment which provides comprehensive information on the present exposure standards for known hazardous substances along with information of substances presently under review. This standard represents the concentration of substances that should not cause undue discomfort or impair the health of persons when exposed to these BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 2 © AMC Consultants Pty Ltd 2005 substances. They do not however represent a no-effect level to all persons exposed to the concentrations stated. They are of course based on current knowledge and research and are subject to change. This information can be found on the Internet at www.nohsc.gov.au This website tells us that when interpreting the actual Exposure Standard it is important to note that they
.have been established on the premise of an eight-hour exposure, during work of normal intensity, under normal climatic conditions and where there is a sixteen-hour period between shifts to permit elimination of any absorbed contaminants. And Heavy or strenuous work increases lung ventilation, thereby increasing the uptake of airborne contaminants. Similarly, heavy physical work under adverse climatic conditions, such as excessive humidity or heat, or work at high altitudes, may lead to an increased uptake of contaminants. It is therefore of particular importance that any evaluation of the working environment considers the lung ventilation rate where there is a significant airborne concentration of contaminant. This website also provides descriptions of the specific exposure standards for peak, short term, time weighted average and general excursions. 1.1 Peak Limitation For some rapidly acting substances and irritants, the averaging of the airborne concentration over an eight-hour period is inappropriate. These substances may induce acute effects after relatively brief exposure to high concentrations and so the exposure standard for these substances represents a maximum or peak concentration to which workers may be exposed. Although it is recognised that there are analytical limitations to the measurement of some substances, compliance with these peak limitation' exposure standards should be determined over the shortest analytically practicable period of time, but under no circumstances should a single determination exceed 15 minutes. 1.2 Short Term Exposure Limit (STEL) Some substances can cause intolerable irritation or other acute effects upon brief overexposure, although the primary toxic effects may be due to long term exposure through accumulation of substances in the body or through gradual health impairment with repeated exposures. Under these circumstances, exposure should be controlled to avoid both acute and chronic health effects. Short-term exposure limits (STELs) provide guidelines for the control of short-term exposure. These are important supplements to the eight-hour TWA exposure standards that are more concerned with the total intake over long periods of time. Generally, STELs are established to minimise the risk of the occurrence in nearly all workers of: - intolerable irritation - chronic or irreversible tissue change, and - narcosis to an extent that could precipitate industrial accidents. STELs are expressed as airborne concentrations of substances, averaged over a period of 15 minutes. This short term TWA concentration should not be exceeded at any time during a normal eight-hour working day. Workers should not be exposed at the STEL concentration continuously for longer than 15 minutes, or for more than four such periods per working day. A minimum of 60 minutes should be allowed between successive exposures at the STEL concentration. BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 3 © AMC Consultants Pty Ltd 2005 1.3 Time-Weighted Average (TWA) Except for short-term exposure limits, or where a peak value has been assigned, the exposure standards for airborne contaminants are expressed as a time-weighted average (TWA) concentration of that substance over an eight-hour working day, for a five-day working week. During periods of continuous daily exposure to an airborne contaminant, these TWA exposures permit excursions above the exposure standard provided they are compensated for by equivalent excursions below the standard during the working day. However, it is not necessarily acceptable to expose workers to concentrations significantly higher than the exposure standard solely because the exposure is for less than an eight-hour day or because the exposure occurs only occasionally. Permissible variations in the exposure standard for such situations are dependent on such factors as the acute effects of short-term exposures, or on the relationship between accumulation and elimination of the body burden of the material or its metabolites, and should only be accepted in the light of expert advice. 1.4 Guidance on General Excursion In practice, the actual concentration of an airborne contaminant arising from a particular industrial process may fluctuate widely with time, with some of the major excursions giving rise to a significant proportion of the overall exposure. Even where the TWA exposure standard is not exceeded, there should be some control of concentration excursions. A practical approach to control has been developed, based on observations of the variability in concentrations observed in industrial environments. A process is not considered to be under reasonable control if short term exposures exceed three times the TWA exposure standard for more than a total of 30 minutes per eight-hour working day, or if a single short term value exceeds five times the TWA exposure standard. It should be emphasised that guidance of this type, aimed at placing some restraint on concentration excursions, is not directly health-based and does not supersede any STEL or peak limitation set. Where adequate toxicological or epidemiological data allows the assignment of a STEL, the STEL will supersede this guidance on general excursion. 1.5 Adjusting the Eight-hour Exposure Standard for Longer Periods Compressed work cycles (usually in fly-in/ fly out operations) consisting of 12-hour shifts for up to (and sometimes exceeding) 14 days duration is now commonplace. As yet, there is no agreement on the extent to which TWA exposure standards should be reduced in response to various work patterns. Specialist consideration and expert advice should be sought in the specification of modified exposure standards. NOHSC recommends the use of the Brief and Scala (1975) 1 model to adjust the time-weighted average (TWA). This method was chosen because it is a simple calculation, it is the most conservative model developed and does not require any detailed knowledge of the substance. h 16 Standard Exposure Hour Eight h) - (24 8 Standard Exposure (TWA) Adjusted × × × = Where h = hours worked per day 1 BRIEF, R., SCALA, R., Occupational Exposure Limits for Novel Work Schedules. American Industrial Hygiene Association Journal. 36: pp467-469, 1975. BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 4 © AMC Consultants Pty Ltd 2005 Example The eight-hour exposure standard for Carbon Monoxide is 30 ppm. The adjusted TWA exposure for Carbon Monoxide (CO) assuming a twelve-hour working shift is calculated as follows. 12 16 30 12) - (24 8 TWA Adjusted × × × = = 15 ppm No adjustment is necessary for the excursion limits of peak concentrations or the short-term exposure limit (STEL). A Comparison of some Atmospheric Exposure Standards Adjusted for Shift Duration TWA STEL CONTAMINANT 8-hour 10-hour 12-hour Any * Carbon Monoxide (CO) 30 21 15 400 * Carbon Dioxide (CO 2 ) 5,000 3500 2,500 35,000 * Nitrogen Dioxide (NO 2 ) 3 2 1.5 5 * Nitrous Oxide (NO) 25 18 12 UR * Sulphur Dioxide (SO 2 ) 2 1 1 5 * Hydrogen Sulphide (H 2 S) 10 7 5 15 # Respirable Dust 5.00 3.50 2.50 NA # Quartz Bearing Dust 0.20 0.14 0.10 NA # Respirable Combustible Dusts 2.00 1.40 1.00 NA NOTES: * = ppm # = mg/m 3 UR = Under Review NA = Not Applicable BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page5 © AMC Consultants Pty Ltd 2005 Some mines are so dry that they are entirely devoid of water and this dryness causes the workmen even greater harm, for the dust, which is stirred up and beaten up by digging penetrates the wind- pipe and lungs and produces difficulty in breathing and the disease the Greeks call asthma. If the dust has corrosive qualities, it eats away the lungs, and implants consumption in the body. In the mines of Carpathian Mountains women are found to have married seven husbands, all of whom this terrible consumption has carried off to a premature death. Georgius Agricola - De Re Metallica (1556) 2 OCCUPATIONAL HEALTH AND SAFETY There is a surprisingly broad range of environmental hazards in underground mining, including poisonous, asphyxiant, carcinogenic or explosive dusts and gasses and extremes of heat and humidity. A significant number of these hazards can result in serious health problems, ranging from long-term physical impairment (e.g. lung disease) to immediate death (e.g. carbon monoxide poisoning, or heat stroke). It is the role of a mines ventilation systems to control these hazards, but before any ventilation engineering design work is carried out, it is vital that the hazards are well understood. This chapter describes some of the more common mine environmental hazards. It should be noted that the human body is very resilient and well equipped to deal with natures climatic and atmospheric extremes. However, some processes involved in activities such as mining produce contaminant levels and environmental conditions which are beyond those with which the bodys natural defence systems can cope. The human capacity to function at the maximum potential will reduce rapidly in atmospheres contaminated with dust, gases, heat and humidity and the long term effects of exposure to contaminants may have serious impact on general medical health. 2.1 The Respiration System Medical science has proven the human body to be very resilient and well equipped to deal with nature's climatic and atmospheric extremes. However it has also shown that some processes involved in todays manufacturing and industry may have a detrimental effect on parts within the human body. Gases, vapours and dusts may enter the human body in three ways - Inhaled into the respiratory system - Ingested with food and saliva into the digestive system - Absorbed through the skin However it is the respiratory system which provides the major mode of entry into the body BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 6 © AMC Consultants Pty Ltd 2005 The respiration system is the main point of entry into the body for many of the particulate and gaseous contaminants found in the underground environment. It is therefore important to have a basic understanding of the principles behind the operation of the human respiratory system. Every organ in the body requires oxygen. Oxygen is captured in tiny air sacs (called alveoli) in the lungs. When air is breathed in, it passes through the walls of the alveoli and surrounding capillaries into the blood stream. The blood transports the oxygen to the body tissues, where it is consumed in the process of energy production, producing carbon dioxide as a waste product. The blood stream carries the carbon dioxide back to the air sacs to be breathed out. The difference between oxygen and carbon dioxide concentrations in blood in the capillaries and the air in the alveoli causes an exchange of gases. The respiratory system is basically a ventilation system, which supplies air to the alveoli. By the very nature of their function, the lungs are exposed to any dusts, fumes, smoke, aerosols, mists, gases or vapours small enough to remain airborne. An adult breathes between 2.0 litres and 4.0 litres of air per minute (l/m) and during times of hard work, this can increase to about 8.0 l/min. Because more air is inhaled as work becomes harder, it is easy to understand why workers in heavy dusty jobs such as mining and construction are more likely to suffer from dust and other contaminant-related lung disorders. By the very nature of their function, the lungs are exposed to any dust, fumes, smoke, aerosol, mist, gas or vapour that is small enough to remain airborne. The human respiratory system has a number of defence systems which are designed to deal with the concentrations and size ranges of dust normally found in nature. These include: - Nasal hairs. These act as pre-filters. When we inhale, the mucus coated membranes of the nasal passages and hairs of the nose aid in capturing almost all of the coarser particles. - Cilia. The trachea and bronchi are lined with sticky mucus that is wafted up these airways via the action of cilia, which are hair-like cells acting with a wave-like motion. The dust is moved upwards to the mouth, where it is either expectorated or swallowed. Inhalation of very coarse dust particles causes coughing and sneezing, which has the effect of speeding up the removal process. The finer dust particles will however reach the alveoli. - Macrophages. These are relatively large white cells (up to 10 µm diameter), which lie on the surfaces of the alveoli. T he cells are mobile and their role is to completely engulf the fine foreign particles which enter the alveoli. Once this has occurred, the macrophages BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 7 © AMC Consultants Pty Ltd 2005 usually then move up the respiratory system and are eventually expectorated or swallowed. Certain dusts are toxic to macrophages (including free crystalline silica and asbestos) and these substances cannot therefore be expelled from the lungs. They remain in the lung tissue, resulting in a gradual incapacitation of the lungs. 2.2 Dust In nature dust is mainly formed by the grinding action of wind blown particles on rocks, the impact action of rocks on each other as they knock together during landslides, and the tumbling action in rivers and ocean wave motion. Because this type of impact is limited, dust formed in this way is rather coarse e.g., beach sands, muds and clays. In mining dust is formed by powerful concentrated forces such as blasting, drilling, crushing, and grinding and consequently forms much smaller dust particles than those formed by nature. Dust is a result of the disintegration of matter and the size of the dust particle produced is determined by the impact per unit area. For example striking a rock with a hammer will split the rock into large pieces forming coarse dust particles. If we were to use the same force using a chisel it would break only a small piece of the rock into fine dust particles because the force is directed onto a much smaller area. As an example of dust production, crushing 1mm 3 of rock to 1µm particle sizes would yield 1,000 million dust particles. In a drill hole 3.6m deep and 32mm diameter the volume of rock removed is 2,895,291 mm 3 producing 2.89 x 10 15 dust particles of 1µm diameter. If it takes 10 minutes to bore the hole and there is a ventilating airflow of 20m 3 /s each mm 3 of air would be contaminated with 241 particles. If the particles had a density of 3kg/m 3 the eight-hour exposure level would be 0.7 mg/m 3 . In reality the majority (99%) of drilling particles are much larger than 1µm and are contained in the drilling water. Some of the more significant sources of dust in underground mines include blasting, movement of rock in stopes, mucking operations, mechanical rock cutting (e.g. raise drilling, road-header etc), ore passes, rock breakers, crushers and conveyor transfer points. Dust is also liberated to the ventilating air from by the tyres of passing traffic lifting the dust from the surface of the mine roadway. 2.2.1 The Hazard of Dust The long-term effect of dust inhalation is not necessarily confined to the respiratory system and there is some research that suggests that the respiratory system merely provide the mode of entry into the body, other modes being absorption and ingestion. The respiratory system is very selective with respect to the size and quantity of dust retained in the lungs. It is not simply a matter of the quantity of dust in the atmosphere that dictates the amount deposited in the lungs, it is also the duration of exposure and the rate of deposition to the critical area. The size of dust particles is measured and expressed in microns (µm). The smallest dust particle that can be seen with the naked eye under good conditions (i.e. black on white with good lighting) is around 25µm and It is generally accepted that the smallest particle visible to the naked eye can be as large as 50µm. Dust particles in mine airflow will settle out of laminar airflows according to Stokes Law. If the airflow is turbulent then the motion of airborne particles is unpredictable are more likely to be removed from the airflow by coagulation and impingement rather than settling. 2.2.1.1 Settling The terminal velocity of an airborne dust particle is dependant upon the atmospheric drag force holding the particle up and the gravitational force pulling it down. This is known as Stokes Law. BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 8 © AMC Consultants Pty Ltd 2005 Where G = Gravitational Force d = Geometric diameter of the sphere (m) w S = Density of the sphere (kg/m 3 ) w a = Density of the air (kg/m 3 ) g = Acceleration due to gravity (m/s 2 ) F = Drag Force v = Velocity of the particle (m/s) q = Viscosity of the fluid (kg/m.s) Stokes Law Stokes Law is applied to spheres G = F ( ) v d 3 g w w d 6 1 a S 3 q t = ÷ t Equation 2-1 Stokes Law Therefore ( ) a S 2 w w 18 g d v ÷ q = Brownian Motion The Brownian motion is a random motion that occurs when dust particles collide with gas molecules in the air with no net tendency to move downwards. This motion completely masks observations made on the particle in question and the resistance to the particle becomes less and they tend to slip past the gas molecule at a speed faster than that indicated by stokes law. Slip Corrected Velocity Cunningham (1910) introduced a slip correction | | . | \ | ì + = P C d A 2 1 v v Equation 2-2 Cunninghams slip corrected velocity Where V C = Slip corrected velocity of the particle (m/s) A = a constant which varies from 0.7 to 0.9 ì = the mean free path of the gas molecule (6.53 x 10 -8 m at 20 °C and 101.3kPa) d P = diameter of the falling particle (m) Particles having terminal settling velocities of the same order as the displacement caused by the Brownian motion will remain suspended, even in still air. The terminal settling velocities may be calculated from the above equations. For example a quartz particle with a geometric diameter of 10µm will have a slip corrected settling velocity of 8.04 x 10 -3 m/s and if released from a height of 4.0m would require 8.29 mins to settle to the ground and 1µm particle would take 12.8 hours. In fact because of the turbulence associated with mine ventilation along with the Brownian motion it would be considerably greater. In those cases were the settling velocity is equal to or less than the Brownian displacement the particle will never settle, even in still air. Gravitational Force Drag Force ( )g a w S w 3 ʌd 6 1 ÷ ʌdȘv 3 Gravitational Force Drag Force ( )g a w S w 3 ʌd 6 1 ÷ ʌdȘv 3 BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 9 © AMC Consultants Pty Ltd 2005 Physical Properties of Airborne o-Quartz Particles at 19.0/20.0 °C and 85kPa Equivalent geometric diameter of Quartz particle (µm) Aerodynamic Diameter ( = diameter of unit density sphere) (µm) Stokes diameter (from experimental data d p /d s = 1:1.67) (µm) Stokes Terminal Velocity (m/s) Slip-corrected terminal velocity (m/s) Brownian displacement per second (m) 250 407 417.5 4.977 4.979 4.36 x 10 -7 100 162.8 167.0 0.796 0.797 6.89 x 10 -7 50 81.4 83.5 0.199 0.199 9.74 x 10 -7 40 65.1 66.8 0.127 0.128 1.09 x 10 -7 30 48.8 50.1 7.17 x 10 -2 7.19 x 10 -2 1.26 x 10 -6 20 32.6 33.4 3.18 x 10 -2 3.20 x 10 -2 1.54 x 10 -6 10 16.3 16.7 7.96 x 10 -3 8.04 x 10 -3 2.18 x 10 -6 5 8.14 8.35 1.99 x 10 -3 2.03 x 10 -3 3.08 x 10 -6 2 3.26 3.34 3.19 x 10 -4 3.33 x 10 -4 4.84 x 10 -6 1 1.63 1.67 7.96 x 10 -5 8.69 x 10 -5 6.89 x 10 -6 0.5 0.814 0.835 1.99 x 10 -5 2.35 x 10 -5 9.74 x 10 -6 0.1 0.163 0.167 7.96 x 10 -7 1.52 x 10 -6 2.18 x 10 -5 0.05 0.081 0.084 1.99 x 10 -7 5.63 x 10 -7 3.08 x 10 -5 0.02 0.033 0.033 3.19 x 10 -6 1.77 x 10 -7 4.87 x 10 -5 0.01 0.016 0.017 7.96 x 10 -9 8.08 x 10 -8 6.89 x 10 -5 2.2.1.2 Coagulation Particles of dust in air will coagulate spontaneously and continuously, irrespective of the substance of which they are composed. As soon as they touch they will fuse and stick together. This process continues until the particles become large enough to settle. The rate of coagulation increases with the turbulence of the medium in which they are contained. As eddies and swirls are formed the velocities of the particles relative to each other becomes greater, increasing the chance of collision and therefore increasing the rate of coagulation. 2.2.1.3 Impingement Impingement (impaction) of dust particles occurs when an obstruction to the flow is encountered and the velocity of the medium is great enough. This impaction occurs when the inertia of the particle is high enough to cause the particle to stick to the obstruction. There is also the chance that high velocities will sweep the particles from the obstruction. The impaction of particles on falling water droplets can be used for the removal of airborne particulate (dust) from the airflow. The success of this method is dependant upon the number, concentration and collision efficiency with the efficiency dependant upon size, density and velocity of the particle and the water droplet. The size of dust particles is measured and expressed in microns (µm). The smallest dust particle that can be seen with the naked eye under good conditions (i.e. black on white with good lighting) is around 25µm. It is generally accepted that the smallest particle visible to the naked eye can be as large as 50µm. Dust of particular concern to mining practitioners is that fraction inhaled and retained in the respiratory system. The site of the deposition varies with the size, shape and density of the BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 10 © AMC Consultants Pty Ltd 2005 particles and this was first described in the proceedings from the Pneumoconiosis Conference held in Johannesburg in 1959. 2 Deposition in at these sites was shown to depend on three factors: (1) the percentage removal of particles before reaching the pulmonary lobules as the inhaled air passed through the nasal chamber and air passages; (2) the fraction of tidal air volume which reaches the pulmonary spaces; (3) the dust collection efficiencies of the pulmonary spaces. In short this experimental work shows that: (1) Particles with a diameter larger than 10µm are deposited in the nasal passages. The proportion deposited falling off as the size of the particle decreases. Virtually no 1µm particles are deposited in the nasal passages. (2) Particles with a diameter larger than 2µm tend to be deposited in the branching ducts leading to the lungs (bronchial tubes). For particles below 2µm there is insufficient time for settlement to occur. Below 0.5µm, the probability for deposition increases due to the bombardment of these very fine particles by molecules. (3) Because of the high retention time in the lungs, the remaining particles have a high probability of deposition. Recommendations from the 1959 Johannesburg Pneumoconiosis Conference have formed the basis for dust measurements monitoring in the years following. One of the most significant recommendations adopted from this conference was: That measurements of dust in pneumoconiosis studies should relate to the respirable fraction of the dust cloud, this fraction being defined by a sampling efficiency curve which depends on the falling velocity of the particles and which passes through the following points: effectively 100% efficiency at 1 micron and below, 50 % efficiency at 5 microns, and zero efficiency for particles of 7 microns and upwards; all sizes refer to the equivalent diameters. (the equivalent diameter of a particle is the diameter of a spherical particle of unit density having the same falling velocity in air as the particle in question.) 3 2 HATCH, T., Respiratory Dust Retention and Elimination Proceedings of the Pneumoconiosis Conference. Johannesburg 9 th 24 th February 1959. p 113,132) BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 11 © AMC Consultants Pty Ltd 2005 A simplification of the dust deposition curve was constructed on this basis and recommended by the International Pneumoconiosis Conference held in Johannesburg, South Africa in 1959. This curve has since become known as The Johannesburg Curve and clearly demonstrates that 100% of particles <1µm and, 50% of 5µm particles and, 20% of 6µm particles, and, 0% of particles > 7µm will enter the human lung, therefore it is the dust particles less than 7µm that are the primary concern for mines. A number of health problems may be caused by the excessive and or prolonged inhalation of dust. The biological response is dependent upon the physical, chemical and toxicological properties of the dust involved. Dusts that cause little or no chemical reaction and subsequent tissue scarring are classified as inert, although this may be misleading, as excessive inhalation will result in accumulation in the alveoli region causing mobilisation of the macrophages (which engulf small particles) and are the last line of defence of the respiratory system. Continued accumulation may eventuate with the formation of plaques on the alveoli walls causing shortness of breath and an increase in the frequency of colds and influenza etc. Chemically active dusts (e.g. silica) decrease the active life of the macrophages and eventually result in permanent alteration or destruction of the alveoli. These permanent changes cause scarring of the lung tissue and result in a reduction of the elasticity of the lung tissue and a subsequent less efficient oxygen intake. This becomes very evident with a decreased lung expansion, breathlessness and a lessened capacity for work. The long term effect of dust inhalation is not necessarily confined to the respiratory system and there is some research that suggests that the respiratory system merely provide the mode of entry into the body, other modes being absorption and ingestion. The respiratory system is very selective with respect to the size and quantity of dust retained in the lungs. It is not simply a matter of the quantity of dust in the atmosphere that dictates the amount deposited in the lungs, it is also the duration of exposure and the rate of deposition to the critical area. 2.2.2 Effects of Dust Because the pre filters of the respiratory system are not developed to cater for the much finer dusts produced with mining activities, some of this dust manages to enter the finer passages of the lungs and remain there. It is this accumulation of dust in the lungs, which causes the condition known as pneumoconiosis (from two Greek words meaning dust and lungs). The deposition in the respiratory tract occurs according to the following mechanisms: a) Gravitational settlement as determined by the free falling terminal velocity, b) Impacting due to inertia, c) Diffusion as applied to microscopic particles and, d) Interception due to the physical size of the particles. Of those particles, less than 5µm only 50% penetrate into the alveoli region of the lungs. About 50% of these particles (usually less than 3µm) deposit mainly due to diffusion and impaction. The remaining 50% will remain airborne and will be exhaled. The terminal settling velocity of airborne fibres is almost independent of length. Deposition from gravitational settlement and impaction may be avoided in the upper respiratory tract allowing the fibre to penetrate into the fine air passages of the lungs. In these areas the length becomes the controlling factor for deposition. Interception becomes the mechanism. Fibres of 50µm and up 3 Recommendations Adopted by Pneumoconiosis Conference - Proceedings of the Pneumoconiosis Conference. Johannesburg 9 th 24 th February 1959. p 619 BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 12 © AMC Consultants Pty Ltd 2005 to 200µm have been found in human lungs, the diameter of these fibres is almost always less than 3µm. The longest fibres are usually found in the bronchi and alveoli. In short, the probability of a fibre impacting the wall of an airway becomes greater as the fibre becomes longer. Fibrous materials include asbestos, calcite, mica, magnesite, apatite gypsum and talc. A number of health problems may be caused by the excessive and or prolonged inhalation of dust. The biological response is dependent upon the physical, chemical and toxicological properties of the dust involved. Dusts that cause little or no chemical reaction and subsequent tissue scarring are classified as inert. This may be misleading, as excessive inhalation will result in accumulation in the alveoli region thus causing mobilisation of the macrophages (which engulf small particles) and are the last line of defence of the respiratory system. Continued accumulation may eventuate with the formation of plaques on the alveoli walls causing shortness of breath and an increase in the frequency of colds and influenza etc. Chemically active dusts (e.g. silica) decrease the active life of the macrophages and eventually result in permanent alteration or destruction of the alveoli. These permanent changes cause scarring of the lung tissue and result in a reduction of the elasticity of the lung tissue and a subsequent less efficient oxygen intake. This becomes very evident with a decreased lung expansion, breathlessness and a lessened capacity for work. 2.2.3 Dust Exposure Standards Allowable concentrations of dusts in work places have been determined from epidemiological studies that by their very nature extend over 20 to 30 year periods, or by experimental work on animals. This is because any physiological damage to workers is not usually detected in the early years of exposure and respiratory problems manifest only after a number of years of exposure. As a consequence exposure standards are constantly being reviewed and updated. A number of health problems may be caused by the excessive and/ or prolonged inhalation of respirable dust. The biological response is dependent upon the physical, chemical and toxicological properties of the dust involved. Diseases caused by exposure to various types of dust can range from lung tissue scarring to pneumoconiosis, mesothelioma and lung cancer. Reference should be made to http://www.nohsc.gov.au/databases/ for the most up to date information on exposure standards. Some current dust exposure standards from this internet site which are relevant to the mining industry are: Selected Exposure Standards (FROM HTTP://WWW.NOHSC.GOV.AU/DATABASES/) Dust Type Exposure Standard (TWA) Quartz 0.2 mg/m 3 (respirable) Coal Dust 3 mg/m 3 (respirable) Asbestos including: Amosite, Crocidolite, other forms or mixtures. 0.1 f/ml (respirable) Chrysotile 1 f/ml (respirable) Where there is no exposure standard 10 mg/m 3 (inspirable*) *refer to http://www.nohsc.gov.au for definition of inspirable 2.2.4 Explosive Dusts The most common explosive dust in metalliferous mining is sulphide dust. Sulphide dust explosions can cause considerable damage to underground facilities and will cause the release of poisonous gasses (primarily SO 2 ). BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 13 © AMC Consultants Pty Ltd 2005 Sulphide dust explosions generally occur at firing time in massive pyritic or pyrrhotitic ore bodies and have been documented since at least the early 1920s. The explosions are known to occur in ore and waste rock containing 20% sulphur with reportings of explosions in rocks with as little as 11%. These explosions are significantly more destructive when they occur in stope blasting than in development headings. Because of the large quantities, high concentrations and toxicity of the sulphur dioxide gas produced with these explosions, re-entry into the mine is extended beyond what could normally be expected. Because of this the recommended approach is to eliminate the explosions by adoption of preventative measures prior to and during blasting. The following procedures should be adopted in orebodies that are known to have the potential to produce sulphide dust explosions: Adequate stemming should be used The use of detonating cord should be eliminated All personnel should be removed to a safe place before firing Enright 4 & 5 . (1996) when discussing preventative measures states Murphys Law applies with a vengeance in underground mining and it is inevitable that despite all reasonable precautions sulphide dust explosions will occur. 2.3 Heat The adverse effects of heat range from discomfort, though to life threatening illness, such as heat stroke. Even relatively low levels of heat can lower the workforce morale, with all the attendant problems of high accident rates and low productivity. This simple cause and effect is often not fully appreciated and a number of mines attempt to soldier on without ever facing up to what can be a very important and significant problem which impacts on employee health, safety and mine productivity. The principle for the control of heat build up in a mine, is the same as the principle of a car radiator. For example if a car is allowed to idle for extended period of time (such as when caught in a traffic jam in the middle of summer), the car engine will quickly overheat because there is insufficient airflow passing through the radiator. Air at normal atmospheric temperature flowing through the radiator will absorb some heat from it. If the air is constantly flowing through the radiator then the heat will be removed, and the radiator will be kept at a lower temperature. Up to a point the faster the flow the faster the heat removal. The effect is similar in humans and machinery working in a confined space such as an underground mine. The surrounding air absorbs the heat generated by humans, machinery and the surrounding rock to a temperature equal to the temperature of the person, rock or machinery. Which ever is the highest? Sources of heat in mines can be categorised as either natural (e.g. rock temperatures, ambient air temperatures and auto compression) or artificial (e.g. diesel and electrical powered equipment) and need to be considered at the early stages of any project. As air passes through the mine ventilation circuit it is subject to a number of sources of heat. These include: 4 ENRIGHT, R.J., LEONTE, M. AMIRA Sulphide Dust Explosions Volume 1 Cause and Prevention in Development Headings Project P316-P316A (1990-1994) (11 May 1995) 5 ENRIGHT, R.J., LEONTE, M. AMIRA Sulphide Dust Explosions Volume 2 Detection and Preventative Measures. Project P316A-P316B (1990 1995) (1996). BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 14 © AMC Consultants Pty Ltd 2005 Auto Compression: - As air travels down the intake airways form the surface, its elevation decreases. There is a corresponding conversion of potential energy into enthalpy 6 . The magnitude of the change in enthalpy can be estimated using the steady flow energy equation for a flow from a higher elevation (Z 1 ) to a lower one (Z 2 ), assuming no heat flow and no work done: ) Z Z ( g H H 2 1 1 2 ÷ = ÷ Equation 2-3 Auto Compression Where: H = enthalpy (J/kg) Z = elevation (m) g = acceleration due to gravity (9.81 m/s 2 ) The enthalpy thus increases by 9.81 kJ/kg for every 1,000m decrease in elevation. For dry air, the thermal capacity is 1.005 kJ/°C and the theoretical dry bulb temperature increase is 9.81 kJ/kg/1,000m ÷ 1.005 kJ/kg°C = 9.76 °C/ 1,000m. In other words, the temperature of dry air flowing down a dry 1,000m shaft into a mine would increase by 9.76 °C (assuming there is no heat exchange between the air and the rock surrounding the shaft). The following points should be noted: - Autocompression is not strictly speaking a heat source (it results from a conversion of energy, rather than from the addition of an external heat source). - Autocompression causes the air temperature to increase, therefore as the mining depth increases, the ventilation air has less ability to remove heat. - The temperature rise due to autocompression is independent of the airflow rate. In contrast, as the airflow increases, the temperature rise due to other sources of heat decreases. It is also important to note that water temperature will increase with depth. If the water is contained in pipes then this increase in temperature is in the order of 0.2 0 C per 1000m. If the water is free flowing then this temperature increases to 2.34 0 C per 1000m. Transfer from the surrounding rock: Surface rock temperature is around the annual average air temperature and can provide either cooling or heating depending on the air temperature passing over the rock. As we get deeper it gets hotter because the rock hasnt transferred its heat to the air. It does not always follow that cold places have cold rocks. In some places the rocks are hotter than others simply because they are newer and have yet to cool down and this varies considerably. For example the rock temperatures in Tasmania are hotter than the rock temperatures in the Barkley Tableland of Northern Territory. 6 Enthalpy is the energy per unit mass (in this case of the air), resulting from the random motion of the air molecules. Elthalpy includes the thermal energy and the energy due to the pressure of the air. BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 15 © AMC Consultants Pty Ltd 2005 The rate of temperature increase with depth is known as the geothermal gradient. The geothermal gradient varies depending on many factors, however typical gradients in Australia range from 1 to 3 °C per 100m of vertical depth. The surface rock temperature (i.e. 20 30m below surface, where temperatures are largely unaffected by surface climatic variations) is close to the average annual ambient dry-bulb temperature. For dry airways, the heat flow from the surrounding rock to the ventilation air is proportional to the difference between the virgin rock temperature and the air temperature. The rate of heat flow from the rock to the air increases when the airway is wet. The rock surrounding an airway has the ability to absorb and subsequently release thermal energy, depending on the difference between the rock temperature and the air temperature. This is sometimes known as the thermal flywheel effect. In some mines, oxidation of exposed minerals can also be a significant source of heat. Ground Water Ground water flowing from the rock into an airway acts to transfer heat from the rock to the air. The ground water temperature is almost always the same temperature as the virgin rock temperature. The amount of heat transfer can be limited by use of efficient pumping and drainage practices (e.g. water should be collected in drains and kept off declines). Machine Heat Except in cases of hoisting, hauling or pumping (where potential energy is raised), almost all of the output power of underground machines is used to overcome friction (i.e. it is converted into heat). Diesel engines are thermally inefficient and generate significant heat loads. At full power, they are about 33% efficient (i.e. 33% of the fuel energy value is converted to flywheel power (almost all of which eventually converts to heat anyway), the other 66% is converted directly to heat). For example, a diesel truck operating on a level gradient and producing 200 kW of engine power would emit about 600 kW of heat. In underground mines, secondary ventilation fans are also a major source of heat. For example, a fan consuming 180kW of electrical energy does no useful work in a thermodynamic sense and hence all of the 180 kW of electrical energy is converted to heat. Explosives Only 5% of the energy produced by blasting is used to break the rock, the remaining 95% is released as heat. For many years it was thought that this heat was dissipated directly to the ventilation system and removed during the re-entry period. It is now more widely accepted that this heat is transferred to the broken rock and liberated over a much longer period of time and is variable, depending upon the ventilation rate and the rock surface exposure. Cement Fill Only Hydraulic Fill would add significant quantities of water and therefore heat, to the mine environment. All of the other fill types are non-draining and, except for the flushing water used with Paste Fill, should have minimal impact. As cemented backfill cures in the stopes, heat is produced due to the exothermic reaction of the cement and water. Most of this heat will be absorbed into the surrounding rock and slowly released and generally this would be insignificant on a mine wide basis. However, it may be significant locally during the first few days after placement. If the paste is placed at a temperature of 30ºC and rises by 10ºC then this will raise the temperature of the surrounding rock to 40ºC. In hotter mines heat may flow from the rock to the fill until equilibrium is reached. The radiant heat from the fill in this case would BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 16 © AMC Consultants Pty Ltd 2005 almost be imperceptible. In the worst case some of the excess heat would be released to the ventilating airflow and rejected to the exhaust ventilating system. An appreciation of the proportion of the total heat load contributed by the various heat sources can be gained from the example opposite, which is based on heat load calculations performed for the North Broken Hill mine. At the time the calculations were performed, the mine was operating at a depth of about 1,600m below the surface. It should also be noted that surface ambient conditions can also be an important contributor to underground heat conditions. This is particularly the case in northern Australia, where high surface temperatures and humidity can give rise to heat problems, even in relatively shallow mines. 2.3.1 Air Temperature Temperature should not be confused with heat. Heat is a form of energy and is calculated. Temperature is a state and is measured. For example a bath full of water at 30° contains more heat than a cup of water at 70°. The difference being the thermal capacity which is the ability to raise the temperature of 1kg by 1°C. There are two measurements of air temperature are important to ventilation practitioners, the dry-bulb and the wet-bulb. Dry- bulb temperature is the actual air temperature, measured with a standard thermometer and the wet-bulb temperature is the measure of the evaporative capacity of the air. Together they measure relative humidity. Humidity is the ratio, expressed as a percentage, of the water vapour present in the atmosphere to the amount required to saturate the air at the same temperature. As humidity increases, the cooling from evaporation of sweat decreases. The ability to measure both the wet and dry bulb air temperature is essential, particularly in hot or poorly ventilated mines, to monitor potential heat stress conditions. These two properties are also required to accurately determine the air density. In mining, the most widely used instrument to determine wet and dry bulb air temperature is the whirling hygrometer (sling psychrometer), or wet and dry bulb thermometer. It consists of two identical thermometers (usually the mercury type) mounted side by side in a rigid plastic frame. The frame is attached to a handle via a spindle and is free to rotate. The thermometers are graduated from -5°C to +50 °C. The bulb of one thermometer is surrounded by a cotton wick that is kept moist by a small supply of distilled water in a reservoir. This is known as the wet-bulb. The dry bulb thermometer provides the sensible temperature of the air. The wet bulb thermometer provides a measure of the evaporative rate of the air. When the air is dry, the moisture in the wet cloth will evaporate faster and the temperature will cool. When the air is humid, very little moisture evaporates from the wet cloth, and the cooling process slows. The smaller the difference between the two temperatures, the higher the humidity If required, the BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 17 © AMC Consultants Pty Ltd 2005 relative humidity can be determined by equating these two temperatures using a table or slide rule supplied with the instrument. Equivalent electronic instruments are available, however, they do not compete with the simplicity and reliability of the sling psychrometer. In particular, the humidity sensors on electronic instruments seem to cause trouble unless very good quality, very expensive units are used. 2.3.2 Body Heat Balance Food (fuel) is oxidised in the metabolic process and converted to energy, in the forms of: - Metabolic heat - Mechanical work, and - Change in mass (body growth) The latter is negligible (usually!) and can be ignored. Although metabolic heat production depends primarily on muscular activity (i.e. it is related to the rate of work), it also varies with: - Condition of the individuals health, - Physical fitness, and - Emotional state In essence, the human body is a biological engine of with low mechanical efficiency. Less than 20% (usually much less than 20%) of the available energy is converted into usable mechanical energy. That part of the metabolic process not used to provide the mechanical work (i.e. >80%) will always appear in the body as heat. This metabolic heat must be rejected from the body to the environment; otherwise the bodys core temperatures will increase, possibly to life threatening levels. In fact, if none of the metabolic heat could be rejected, the body temperature would rise by 1°C (the maximum ISO recommended acceptable rise) in 12 minutes during moderate exercise and 4 minutes during strenuous exercise. As we work we release energy in the form of heat and understandably the harder we work the higher is the metabolic heat generation process. The removal of heat generated by the human body is reliant upon our ability to sweat and the rate at which it can be evaporated. This heat is transferred to the external environment and, if the rate of generation is greater than the rate of transfer the body temperature will rise. This heat storage is called the metabolic heat generation or the metabolic heat production rate. Heat transfer between the body and the environment occurs via: - Respiration (breathing) - Radiation - Conduction - Convection, and - Evaporation Respiratory Heat Exchange. In a typical hot underground environment, respiratory heat exchange accounts for about 5% of metabolic energy production. This heat loss is generally considered to be small enough to be ignored. BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 18 © AMC Consultants Pty Ltd 2005 Radiant Heat Exchange The magnitude and direction of radiant heat transfer depends on the temperature difference between the human body (skin) and the object. This type of heat transfer is usually only significant in mines with hot rock temperatures, and in the vicinity of hot diesel equipment. Conductive Heat Exchange Conductive heat transfer occurs when two bodies come into contact. In normal mining activities, conductive heat transfer to or from the human body is usually negligible (unless, for example personnel are wearing cooling jackets). Convective Heat Exchange Convection occurs when a layer of cool air comes in contact with warm skin. The air increases in temperature and its density decreases. As the air becomes lighter, it rises, taking the heat away from the skin. As the air is replaced with cooler, more dense air, the process of heat exchange continues. Convective heat transfer to the surrounding air is typically 15% to 20% of total cooling. It depends on the temperature difference between the skin and the dry bulb temperature of the air, as well as the relative air velocity and body surface area. Evaporative Heat Exchange Evaporation is the main cooling mechanism for the body, contributing about two thirds of total cooling. Evaporative cooling relies on the latent heat of vaporisation of sweat from the body. The effectiveness of this form of heat transfer is dependent upon: - efficiency and rate of sweating and, - the evaporative capacity of the environment (depends mainly on air temperature, humidity, air velocity, and type of clothing). The ability of the body to sweat depends on physical fitness, acclimatisation (training the body to sweat efficiently) and on the body having sufficient fluid. There is considerable variation in the sweat rate of individuals and this is partly associated with the degree of acclimatisation (it also depends on general health and genetic factors). Sweat that drips from the body, serves no cooling function and it begins to drip from the skin surface well before the body is fully wetted. This is primarily because some areas of the human body produce more sweat than others. Sweat begins to drip when the skin surface is approximately 50% wet. In terms of maximising the cooling effect, the most effective place for sweat to evaporate is from the skin. Clothing (particularly clothing made of artificial fibres) can significantly reduce the amount of heat rejected from the body via evaporative heat exchange (it also reduces convective heat exchange). In underground mines, the evaporative capacity of the environment can be increased primarily by increasing the air velocity. In some instances, it becomes necessary to also lower the wet bulb air temperature (e.g. by reducing moisture pick-up in intake airways or through the use of refrigerative mine air cooling). 2.3.3 Thermoregulation The core of the body must be maintained at a stable temperature of between about 35 O C and 40 O C. To do this, the body invokes its thermoregulation processes. These include: - Cold Skin blood flow is reduced to reduce heat losses to environment. Shivering commences to raise the metabolic rate. - Heat Skin blood flow is increased to increase heat transfer rate. Sweating increases to maximise evaporative heat loss. BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 19 © AMC Consultants Pty Ltd 2005 The effectiveness of the bodys thermoregulation system is dependent on a large number of factors, including: - Fitness - Age - Obesity results in excessive fat insulating the body, reducing heat loss - Acclimatisation is the adaptation of the bodys thermoregulatory systems to working in hot conditions. Most of the effects of acclimatisation are generally developed within a week of working in hot conditions, but the process continues for at least 14 days. Conversely, acclimatisation is lost after a period of 7 to 14 days away from hot conditions. The degree of acclimatisation is related to the level of heat stress experienced on the job. Some personnel are heat intolerant and can never be successfully acclimatised to hot working conditions. - Hydration Levels are critical. Even a small decrease in hydration levels will lead to a substantial reduction in the ability to work effectively in heat. Significant fluid intake is required to counter losses through sweating in hot conditions. Hydration levels can also be compromised by diuretics (alcohol, caffeine etc) and also by illness. - Clothing acts as insulation, reducing the bodys ability to reject heat to the environment. The illustration below shows the Temperature Response to Heat Stress there is a tremendous spread in the effectiveness of the bodys thermoregulation system, even across a relatively narrow sample group (in this case, 99 acclimatised, essentially nude men working at the same rate in the same environment). Obtained from Chapter 20 of Environmental Engineering in South African mines, published by the Mine Ventilation Society of South Africa in 1989. BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 20 © AMC Consultants Pty Ltd 2005 2.3.4 Heat Related Illness It is important to be able to recognise the causes and symptoms of overexposure to heat and to know the treatment for these illnesses. Over-exposure to heat occurs when the bodys temperature controlling mechanism (thermoregulation) cannot cope with the thermal environment and rate of exertion. Over-exposure to heat may quickly progress to collapse, unconsciousness (coma) and death. The symptoms and treatments for some of the many classifications of heat illnesses are listed below (in order of increasing severity): Heat Cramps result from an imbalance in the body electrolytes, caused by vigorous activity, dehydration and high temperatures. The body loses more fluids than it is replacing. This fluid debit causes muscles to lose their vital electrolyte balance (complex salts), thus causing muscular contraction (cramps). Signs and Symptoms Treatment Pale, clammy skin. Sweating Cramping pains (in the limbs and/or abdomen). Nausea. Spasms (in the affected limb or limbs). Rest the victim in a cool location. Give sips of water to drink (after nausea has passed). Don't massage affected limbs. Discourage any further exercise. Heat Exhaustion occurs after prolonged moderate elevations of core temperature. Its development is usually attributed to the inability of the circulation system to meet the demands of thermoregulation (i.e. the diversion of significant quantities of blood flow to the skin) whilst also maintaining sufficient blood flow to the vital organs (brain and skeletal muscle). Signs and Symptoms Treatment Pale, clammy skin. Restlessness Cramps in the limbs and/or abdomen Nausea and/or vomiting Headache Weakness Fatigue Rest the victim in a cool location Discourage any further exertion. Cool down casualty by sponging. (use tepid water) Give cool water to drink (cautiously, after nausea has passed). Heat Stroke is a very serious condition known as a Core Temperature Emergency. It occurs as a result of thermoregulatory failure. If appropriate treatment is not instigated promptly, heat stroke carries a mortality rate of up to 80%. High body temperatures associated with heat stroke can result in irreversible damage to organs (especially the brain, kidneys and liver) and the nervous system. The main causes of heat stroke in the mining industry 7 are overly strenuous work in hot environments and dehydration (often associated with excessive alcohol consumption). 7 Mining Industry heat stroke in countries such as South Africa. Note that it is unlikely that there has ever been an underground mining fatality directly attributed to heat stroke in Australia. BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 21 © AMC Consultants Pty Ltd 2005 Signs and Symptoms Treatment Body core temperature above 40.5°C Often a cessation of sweating. Aggressive or irrational behaviour Staggering, Dizziness or Faintness Vomiting Collapse and seizures Coma Cool down the casualty immediately by gently splashing with cool (but not icy) water. If possible, increase evaporative cooling by fanning patient. Continue treatment until medical help arrives. Give frequent small drinks of water if patient is conscious. Prepare to resuscitate if required. 2.3.5 Heat Stress Indices Measurement of hot conditions can either be by measuring the climate, that is the cooling power of the environment or by measuring the heat strain, the effect on persons working there. The four main parameters for directly evaluating heat strain are body core temperature, heart rate, skin temperature and, weight loss through sweating. Although all of these can be measured it is not practical to do so in the workplace. Even if heat strain could be measured accurately, it does not indicate a reason for the problem and hence any possible solution. The degree of heat stress is a function of the parameters outlined in the table below. Parameters Contributing to Heat Stress Metabolic rate Ambient and radiant temperature Water vapour pressure Air velocity Barometric pressure Amount and type of clothing Skin surface area and view factor (e.g. whether sitting, standing etc) Variability in human thermoregulatory response. Development of a measure to determine safe levels for work in hot places has been debated over many years. During the 1900s over 90 heat stress indices have been developed and used around the world with varying success and acceptance by the international community. Generally these indices combine one or two parameters into a single number and therefore only partially represent the complexity of the human thermoregulatory system and the climatic conditions encountered. Broadly heat stress indices can be classified into three types: - - Single measurements - Empirical methods, and - Rational indices 2.3.5.1 Single Measurements Although there has been some attempt to use a single measurement to determine heat stress conditions, there is no single parameter that provides a reliable indicator of physiological reaction. BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 22 © AMC Consultants Pty Ltd 2005 2.3.5.1.1 Psychometric Wet-bulb Temperature For many years, the wet-bulb temperature has generally been considered as the easiest and simplest measure of heat stress and has been used widely in many Australian mines as the sole indicator for climatic acceptability. Australian mining legislation uses a wet-bulb temperature of 25°C, 27°C or 28°C as a trigger point for modified work conditions such as reduced work hours or the introduction of regular rest periods. 32°C is usually set as the upper limit for work being allowed to continue. The psychometric wet-bulb temperature is a measure of the evaporative cooling power of the environment and is therefore of limited value especially in high air velocities and high radiant temperatures. It worthy to note, that in wet-bulb temperatures above 37°C, the environment is unable to support human life for any extended period of time. 2.3.5.1.2 Dry-bulb Temperature Dry-bulb temperature above 45°C can give a burning sensation to exposed skin and is generally accepted as the upper limit for work being allowed to continue. 2.3.5.2 Empirical Methods The most commonly used empirical methods have been, effective temperature (ET), Kata thermometer, predicted four-hourly sweat rate, and wet-bulb globe temperatures index (WBGT). 2.3.5.2.1 Effective Temperature (ET) ET was developed in 1923 as a measure of comfort by the American Society of Heating and Ventilating Engineers and primarily for use in offices. The ET of an environment is the temperature of a saturated environment without movement of air that would produce the same instantaneous thermal sensation as the environment being considered. As this index is based on subjective thermal sensation it has shortcomings in either low (<0.5m/s) or high (>3.5 m/s) air velocities. Although the value can be calculated, it is normal to refer to empirically constructed nomograms such as :- 1. Basic scale developed for essentially nude men and, 2. Normal scale for lightly dressed men. It is not possible to reduce these nomograms to a simple mathematical expression over the entire range. The Basic ET may be calculated to within 0.2 O C from the following equation given:- - The difference between the wet-bulb and dry-bulb temperature is less than 5 O C - The wet bulb temperature is within the range from 25 O C to 35 O C, and - The velocity of air is within the range from 0.5 m/s to 3.5 m/s BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 23 © AMC Consultants Pty Ltd 2005 ET = 20.86 + 0.0354T WB - 0.133V + 0.07V 2 + (4.12 - X 1 + X 2 ) / 0.4129 Where X 1 = [ 8.33 { 17X 3 ( X 3 - 1.35 ) ( T WB 20 ) } ] / [ ( X 3 - 1.35 ) ( T A - T WB ) + 141.6 X 2 = 4.25 [ ( T A - T WB ) X 3 +8.33 ( T WB 20 ) ] / [ ( X 3 - 1.35 ) ( T A - T WB ) + 141.6 X 3 = 5.27 + 1.3V 1.15e -2V T A = Ambient dry-bulb temperature (°C) T WB = Ambient wet-bulb temperature (°C) V = Velocity of air (m/s) e = vapour pressure of the air (kPa) Subsequent to the development of these nomograms, it has become customary to use the temperature of a blackened 150 mm hollow copper sphere in place of the dry bulb temperature. The assumption is to take into account the effects of thermal radiation. Measurements using the blackened sphere are termed corrected effective temperature. ET has been extensively used in the European and British mining industries. In Queensland the Coal Mining Act General Rules for Underground Coal Mines Part 2.7 (1) (a) provides that no person shall be employed where the effective temperature in the workplace is or exceeds 29.4°C and Part 2.7 (3) specifies a shortened shift strategy when the ET exceeds 27.2°C. The use of ET as a tool for prevention of heat related illness has a number of problems 1. ET exaggerates the effects of thermal sensations at high relative humidity 2. Only accounts to climatic conditions and does not consider work rates 3. ET scales are most accurate in warm climates and low heats stress conditions. 4. ET is least accurate in velocities less than 0.5 m/s and, greater than 3.5 m/s. 2.3.5.2.2 Kata Thermometer BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 24 © AMC Consultants Pty Ltd 2005 2.3.6 Air Cooling Power A complete and supportable heat stress index must account for all of the contributing parameters. Currently, the most complete and supportable index of heat stress is the concept of air-cooling power, which was developed by the South African Chamber of Mines. This index was however specific to South African mining practices (in particular, it assumed personnel were essentially nude and fully wetted by perspiration). There have been a number of updates and modifications to the original scales and it is important to state which air cooling power scale is being used. McPherson (1992) 8 describes how to calculate air-cooling power, referred to as the M (McPhersons) Scale Air Cooling Power. The concept of air-cooling power relies on the quantification of the ambient environments ability to remove metabolic heat from the human body. The scale used to determine the rate of generation of heat by the human body and also air-cooling power is W/m 2 of body (skin) surface area 9 . By definition, provided the air cooling power is equal to, or greater than the metabolic rate, then there will be less than a one in one million chance of the healthy, acclimatised and self pacing individual developing dangerous body core temperatures (>40°C), potentially leading to heat stroke. This is held to be an acceptable risk. A widely used thermal acceptance criterion is a minimum air cooling power of 115 W/m 2 (i.e. if the air cooling power is less than 115 W/m 2 , then an individual could not even sustain a moderate work rate without incurring an unacceptable (greater than one in one million) chance of a healthy acclimatised individual suffering from heat stroke. Whilst air-cooling power is the most complete heat stress index, it requires fairly complex calculations (ideally requiring a computer) to solve. The calculations require inputs including; amount and type 8 The Generalisation of Air Cooling Power M.J. McPherson. Fifth International Mine Ventilation Congress The Mine Ventilation Society of South Africa, Johannesburg, 1992. 9 For reference, the average skin surface area of a 1.7m tall, 60.5 kg South African miner has been determined to be 1.8 m 2 . The modified DuBois formula, relating skin surface area (A s , m 2 ) to body mass (m, kg) and height (h, m) is A s = 0.217m 0.425 h 0.725 (From The Mine Ventilation Practicioners Data Book Second Edition, Andrew Patterson et. al. 1999 The Mine Ventilation Society of South Africa, Johannesburg. 18 20 22 24 26 28 30 32 34 36 100 200 300 400 5 m / s 4 m / s 3 m / s 2 m / s 1 . 5 m / s 1 m / s 0.5 m /s 0 m/s 5 m/s 3 m/s 2 m/s 1 m/s 0.5 m/s 0 m/s 5 m/s 3 m/s 1 m/s 0 m/s A i r C o o l i n g p o w e r ( M s c a l e ) o r M e t a b o l i c H e a t W / m Wet Bulb Temperature t C Radiant Temperature = Dry Bulb Temperature Dry Bulb Temperature = Wet Bulb Temperature + 5°C (Note that the graph may be used without undue error for differences between wet bulb and dry bulb temperatures of between 2 and 8 °C) Figure From The Generalisation of Air Cooling Power by M.J. McPherson Fifth International Mine Ventilation Congress The Mine Ventilation Society of South Africa, Johannesburg, 1992. Heavy Clothing (Long Sleeved Overalls and Long Sleeved Shirt) 115 W/mLine 2 (Light Work, 5m/s Air Velocity & Light Clothing) Light Clothing (Thin Trousers, Short Sleeved Shirt) Unclothed w 2 BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 25 © AMC Consultants Pty Ltd 2005 of clothing worn, wet bulb temperature, dry bulb temperature, radiant temperature of surroundings, air velocity, barometric pressure and the work rate of the individual. The large number of required inputs and requirement for a computer to calculate air-cooling power has limited its use to date as a practical tool for determining on the spot whether the thermal conditions in an underground environment are acceptable. Recently this problem has to a large extent been overcome with the development of a robust, portable heat stress meter designed for use underground. The meter uses algorithms based on air-cooling power and is based on an instrument that was originally developed for use by the US military in Operation Desert Storm in Kuwait. For mines which do not have access to the heat stress meter, it should be noted that normal ranges of some of the factors mentioned above in the underground mining context have a relatively weak effect on air cooling power. A generalised Air Cooling Power Chart that assists in the rapid manual assessment of the acceptability of the thermal environment can be produced on this basis. (See McPhersons M Scale Air Cooling Power Chart opposite) The following assumptions were made in order to produce such a chart: Typical Metabolic Work-rate Classifications for Healthy Adults Light Work Moderate Work Hard Work Very Hard Work < 115 W/m 2 115 to 180 W/m 2 180 to 240 W/m 2 >240 W/m 2 Sleeping 40 Seated 60 Standing 70 Walking 5 km/h Trades people Jumbo drilling Diesel Operator Walking 6.5 km/h Building brick walls Scaling Hand-held drilling Shovelling Timbering Barometric pressure Assume P = 100 kPa. Air cooling power is largely unaffected by normal range of pressures found within underground mines. Radiant temperature of surroundings is equal to the dry-bulb temperature (This is usually the case, except near hot surfaces such as diesel radiators etc). Dry-bulb temperature is equal to the wet-bulb temperature + 5°C (Note that the graph may be used without undue error for differences between wet bulb and dry bulb temperatures of between 2 and 8°C.) The majority of underground temperatures except near diesel radiators etc will fall within this range. Clothing - Assumptions were also made about the thermal resistance and area factor of different clothing specifications and also regarding the body posture factor. The above assumptions allow an air-cooling power graph to be produced, which only considers wet-bulb temperature, air velocity (air speed over the individual), and clothing type. The protective clothing worn underground in Australian operations would fall somewhere between the Light and Heavy categories. An example has been outlined with the heavy dashed line in the M scale chart. It assumes light clothing, light work rate (115 W/m 2 ) and air velocity of 0.5 m/s. This line projects down to a wet-bulb temperature of 29.5°C. In other words, at the conditions and work rate outlined, a wet bulb temperature of less than 29.5°C will ensure that there is less than a one in one million chance of heat stroke occurring in a healthy, acclimatised individual. In any mining operation, there will be variation in many of the variables listed earlier . It can however be concluded that based on all the assumptions implied in McPhersons M Scale, an acceptable air cooling power can not be provided for even a light work rate at wet bulb temperatures above 32 °C. BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 26 © AMC Consultants Pty Ltd 2005 It is also important to note that for a range of circumstances (e.g. heavier work rates), conditions which could lead to the development of heat stroke could occur at wet bulb temperatures below 32°C. For the purposes of providing a simple, practical measurement to determine the thermal acceptability of an underground environment, a stop work cut-off of 32°C wet bulb is supported. This temperature cut-off is combined with a requirement that the air velocity must be greater than 0.5 m/s at wet bulb temperatures over 25°C (e.g. refer to W.A. Regulations). 2.3.7 Management of Hot Working Conditions Human heat stress is a health hazard that can be managed by: Instigating working in heat protocols Controlling the underground ambient heat conditions Hot working condition protocols can include the following aspects: Worker training and education e.g. how to recognise and treat the symptoms of heat illness, the importance of drinking sufficient water, the need to self-pace according to conditions and the mechanism of acclimatisation. Refresher training courses should be re-run on a regular basis (ideally just before the onset of summer) Hydration testing e.g. Urine tests on personnel who work in hot areas of the mine. The tests quickly show those who are not coping with hot working conditions (e.g. those not drinking sufficient fluid, those who are ill or those who are heat intolerant). The protocols should spell out the policy regarding those who fail the hydration test (second chance etc). Staff selection. Some mines preclude those with certain medical conditions, those who are overweight, personnel over a specified age and females with child bearing capacity from working in thermal conditions which are beyond a specified level. Stop work. It is very important that a cut-off criterion with respect to acceptable/ unacceptable underground ambient conditions is established. The criterion must be fully supported by management and strict guidelines established to ensure that the criterion is respected under all but exceptional circumstances (and these should be defined in the protocol). Establishing working in heat protocols is of fundamental importance, however it only deals with part of the problem. In a number of deeper mines (or shallower mines hosted in hot rock), it is very difficult to maintain ambient conditions that allow even a light rate of work without incurring an unacceptable risk of the development of heat stroke. In these mines, it is necessary to boost the miners ability to reject metabolic heat by employing one or more of the following methods: Increase the air velocity to improve the air-cooling power. This is effective at lower wet bulb temperatures. As the wet-bulb temperature increases, a diminishing return effect is apparent. In fact, again referring to McPhersons M Scale, it can be seen that increasing the air velocity has very limited effect on the air cooling power, once the wet bulb temperature exceeds about 32°C. It should also be noted that there is a considerable cost penalty associated with increasing the airflow rate: 3 Rate Flow Old Rate Flow New Increase Cost Power | | . | \ | o Microclimate Cooling. This involves cooling the localised area around the miner. One example is the use of air-conditioned cabins on mobile equipment. Another example is the use of cooling jackets (ice vests). These use flexible frozen gel-packs (similar to those used for sports injuries), which special pockets in an insulated vest. They are primarily intended for use in emergency BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 27 © AMC Consultants Pty Ltd 2005 situations (and for sports competitors), but may potentially have some applications for more regular underground use. The gel packs are cooled in a chest freezer (in the crib room) and have a useful life of about 2 hours. The figure opposite is an illustration of a Micro-climate cooling vest. (Reference http://www.steelevest.com/). This is seldom a satisfactory total solution, since there is a very real chance of something going wrong (e.g. forgetting to change the cooling jacket gel-packs and subsequently getting stuck in a hot mining area). Refrigerative Mine Air-cooling In spite of the sometimes considerable capital and operating costs, refrigerative cooling of mine air is often the only supportable option for control of heat stress in very hot mines. A simplified line diagram showing a typical mine refrigeration circuit is shown below. The refrigeration machine generally consists of a screw compressor coupled to plate type heat exchangers (condenser and evaporator). The refrigerant is usually ammonia for surface plants and R134 for underground plants. Rated capacity of machines used in Australian Mines ranges from about 500 kW to 10 MW of refrigerative cooling capacity. As a rule of thumb, the compressor motor power draw is 1/4 to 1/5 th the nominal refrigerative cooling capacity. The amount of (potable) water circulated in the plants can be considerable. For example, a 1MW plant circulates about 25 l/s in each of the (hot and cold) water circuits. A proportion of this flow evaporates and some is also dumped. Make-up water requirements for a 1 MW plant are typically 1.5 l/s in the hot water circuit and 1 l/s on the cold-water circuit. Several plant configurations are possible: Surface Bulk Air Cooling. All of the equipment is located on the surface. The air is cooled at the intake raise collar. This system is simple and easy to maintain. It is not well suited to mines with complex ventilation systems (some of the cooled air may find its way to locations where chilled is not required). Some of the coolth is also inevitably lost in the mine intake airways. Surface Plant with Underground Coolers. With this system, the plant and heat rejection towers are mounted on the surface. Chilled water is reticulated underground to cooling towers that are close to the locations where cooling is required. Advantages of this system are that cooling can be more precisely and more directly delivered to the required locations. The disadvantages are high pumping costs (high volume, high head pumping although some energy losses can be recovered with the use of a Pelton wheel turbine coupled to a generator) and significant maintenance costs (complex system with cold and hot water storage dams insulated chilled water pipes, batch cooling of water, large underground pump stations and Pelton wheels, underground cooling towers which can be fouled with dust etc). Evaporat or Cooled Air To Mine Hot Air Reject ed t o At mosphere Chilled Wat er Circuit Hot Wat er Circuit Cooling Tower Cooling Tower Condenser Refrigerat ion Machine BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 28 © AMC Consultants Pty Ltd 2005 Underground Spot Cooling. All of the equipment is located underground. The refrigeration plant and heat rejection tower are located in a return airway. The cooling tower supplies chilled air to a specific location (often to the inlet of a secondary ventilation fan). The capacity of refrigeration machine is restricted to a size which can be physically transported underground on a skid (e.g. maximum of about 1MW cooling capacity). As a result, the machine generally only has sufficient capacity to cool one or two headings. There are many disadvantages including high maintenance costs due to arduous operating environment and difficult maintenance access as well as logistics problems (e.g. supply of 1.5 to 2.5 l/s of potable make-up water) Some examples of Australian mine air cooling plants are shown in the following illustrations: 600kW Refrigeration Set for Underground Spot Cooler (WMC Olympic Dam) Cooling and Heat Rejection Towers Not Shown 600kW Refrigeration Set for Underground Spot Cooler (WMC Olympic Dam) Cooling and Heat Rejection Towers Not Shown BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 29 © AMC Consultants Pty Ltd 2005 1.1 MW NH 3 Surface Plant at Telfer (1 of 2) (Plant is being gassed up with NH 3 ) Heat rejection tower 1.1 MW NH 3 Surface Plant at Telfer (1 of 2) (Plant is being gassed up with NH 3 ) Heat rejection tower Telfer Bulk Air Cooler Installation Near Collar of VR2 Intake Raise Telfer Bulk Air Cooler Installation Near Collar of VR2 Intake Raise BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 30 © AMC Consultants Pty Ltd 2005 Chilled water is reticulated U/G via insulated pipes to underground cooling towers 10 MW K61 NH3 Refrigeration Plant Mt Isa Cold water storage dam Heat rejection towers Chilled water is reticulated U/G via insulated pipes to underground cooling towers 10 MW K61 NH3 Refrigeration Plant Mt Isa Cold water storage dam Heat rejection towers Close up of one of the Mt Isa K61 Compressors Close up of one of the Mt Isa K61 Compressors BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 31 © AMC Consultants Pty Ltd 2005 2.4 Mine Gases There are a surprisingly wide variety of gasses that can be found in underground mines, abandoned workings and caves. Some of these gasses may be poisonous, irritant, asphyxiant, radioactive or explosive and are hence of particular interest from a ventilation design viewpoint. Mine ventilation systems are required to dilute and remove atmospheric contaminants caused by mining operations. 2.4.1 Constituent Gases of the Atmosphere The atmosphere (fresh air) surrounding the earth surface contains a number of different gases combined as a mixture. Composition of Air GAS VOLUME (%) Oxygen (O 2 ) 20.93 Nitrogen (N 2 ) 78.11 Carbon Dioxide (CO 2 ) 0.03 Minor Inert Gases 0.93 Water Vapour Variable Because this air is a mechanical mixture, it is possible to separate and identify each of the gases in the mixture. Any other substance or variation of these gases contained in the atmosphere are contaminants and are subject to Exposure Standards under legislation. Any additional gasses or variation in the proportions of the gases normally found in the atmosphere are regarded as contaminants. Some characteristics of the more commonly found mine gases are discussed below. 2.4.2 Carbon Dioxide (CO 2 ) Carbon dioxide is colourless, has a pungent or acrid smell and a soda water taste. It has a specific gravity relative to air of 1.53 (significantly heavier than air) and will not support combustion. It doesnt liquefy but will form dry ice at 78°C. CO 2 has a TWA exposure limit of 5,000 ppm and a STEL of 30,000 ppm. It can be found in coal mines and in mines hosted in carbonaceous rocks, such as limestone. It is also produced by diesel engines. The gas is about 20 times more soluble than Oxygen and diffuses rapidly into the bloodstream. The most noticeable effect of the gas is to cause the respiration rate to increase, which serves to alert the miner to the presence of the gas. Physiological Effect of Carbon Dioxide Percentage in Air Effects 0.03 None (Normal atmospheric concentration) 0.5 Respiration increases by 5% 2.0 Respiration increases by 50% 3.0 Respiration increases by 200%. 5 10 Violent panting, leading to fatigue. Headache 10 15 Intolerable panting, severe headache, rapid exhaustion and collapse BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 32 © AMC Consultants Pty Ltd 2005 2.4.3 Oxygen (O 2 ) Oxygen is a colourless, odourless, tasteless gas, with a specific gravity relative to air of 1.1. Oxygen is the only gas whose concentration should be maintained above a recommended value. Oxygen depletion is caused by oxidation of minerals (e.g. Sulphides and Coal). Depletion of Oxygen also results from combustion (e.g. diesel engines, blasting etc). A deficiency of Oxygen implies greater than normal atmospheric concentrations of other gasses (even inert gasses). The physiological effect of various levels of Oxygen concentrations is shown below. Concentration (by Vol.)in Air % Typical Physiological Effects (Vary with individuals and period of exposure) 20.93 Normal content of atmospheric air 17.0 to 20.0 Lowest allowable concentration (variable in mine legislation) 17.0 Noticablely faster and deeper breathing rate (equivalent to 1,500m ASL elevation). Candle will not burn below 16%. 15.0 Dizziness, buzzing in ears, rapid heart beat A safety lamp flame will go out at some point in this range. 13.0 Work is difficult. Breathing becomes rapid and lips become blue. Nausea and headache develop slowly and may become very severe. May lose consciousness if exposure prolonged. Dangerous for exposures over half to one hour. 10.0 Liable to faint and become unconscious. 9.0 Fainting, unconsciousness. 7.0 Life endangered 6.0 Convulsive movement, probable death. Exertion leads to unconsciousness < 6.0 Rapid unconsciousness and death Note: If the oxygen content falls, the rate of breathing tends to increase to maintain the oxygen intake required. This automatic adjustment by the body to oxygen deficiency ends at about 17% oxygen and mental processes begin to become impaired although of course humans are not aware that they are being affected. 2.4.4 Carbon Monoxide (CO) Carbon Monoxide has a high toxicity. Because of this and the fact that it is colourless, odourless and tasteless, it is an extremely dangerous gas. Carbon Monoxide has a specific gravity relative to air of 0.97 (almost exactly the same as air). It is flammable at concentrations of between 12.5 and 74% in air. The compound in red blood cells which transports Oxygen (haemoglobin) has an affinity for CO which is about 300 times greater that that for O 2 . To further exacerbate the problem, the resulting compound (Carboxyhaemoglobin - CO·Hb) is significantly more stable than that formed by a combination of Oxygen and Haemoglobin (Oxyhaemoglobin) and does not readily decompose. The result of Carbon Monoxide exposure is that the red blood cells have a reduced ability to transport Oxygen. The effect is cumulative ie. with each breath, more and more CO is taken up by the blood, therefore reducing the concentration of O 2 . In severe poisoning, the effect may be very sudden and the first warning may be lack of response of the limbs, making escape difficult. CO has a TWA exposure limit of 50 ppm and an STEL of 400 ppm. BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 33 © AMC Consultants Pty Ltd 2005 Effects of Carbon Monoxide in the Blood Stream Blood Saturation (% CO·Hb) Effect 0-10 None 10-20 Possible headache 20-30 Headache, dizziness 30-40 Severe headache, weakness, nausea, loss of judgement, dimming of vision Possible collapse 40-50 Collapse 50-60 Collapse at rest, increased lung ventilation and pulse, convulsions 60-70 Convulsions, coma, depressed lung ventilation and pulse, disturbed judgement >70 Slow weak pulse, respiratory failure and death. Carbon monoxide is produced by fires, the oxidation processes (e.g. blasting) and sometimes issues from rock strata (especially in coal mines). It is also a component of combustion engine exhaust emissions. 2.4.5 Oxides of Nitrogen (NO x ) Oxides of Nitrogen covers a mixture of gases usually found together. The most important of these are Nitric Oxide (NO) and Nitrogen dioxide (NO 2 ), both of which are classified as toxic. The proportion of NO is usually small and NO also readily converts to NO 2 in the presence of air and water vapour. Consequently, NO 2 is the oxide of most interest. This gas is brown in colour and dissolves readily in water to form Nitrous (HNO 2 ) and Nitric (HNO 3 ) acids. In sufficient concentration, these acids cause irritation and corrosion of the respiratory system and eyes. The associated bleeding and accumulation of fluid in the lungs can culminate in death from pulmonary oedema (flooding of the lungs). This can occur up to 24 hours after exposure, even after an apparently early recovery. Oxides of Nitrogen are primarily produced by internal combustion engines and are also a significant constituent of blast fumes. The TWA exposure limit for NO is 25 ppm and that for NO 2 is 3 ppm. As yet an STEL for NO has not been set, but for NO 2 the STEL is 5 ppm. Physiological Effects of NO2 Concentration ppm Typical Physiological Effects for NO 2 3 TWA 50 Moderately irritating to eyes and nose 100 Irritant to respiratory passages and to the eyes. (Headache, tightness of the chest or perhaps pain in chest and a cough). Dangerous if exposed for ½ to 1 hour. 200 Breathed for 20 minutes may cause collapse, this may be delayed for several hours. 250 Severe pulmonary oedema, probably fatal. BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 34 © AMC Consultants Pty Ltd 2005 2.4.6 Sulphur Dioxide (SO2) In massive sulphide orebodies there can be spontaneous oxidation and heating resulting in sulphur dioxide being released to the ventilating air. Sulphur dioxide is colourless and even at relatively low concentrations has a pungent, suffocating sulphurous odour, and acidic taste, making it readily detectable. It is highly toxic. It has specific gravity relative to air of 2.26 and is soluble in water, forming sulphurous acid. It is incombustible and is also not flammable. It is associated with oxidation of reactive sulphide ores. Of particular importance is the fact, that sulphur dioxide is produced by sulphide dust explosions. It is sometimes also noticed in mines that have their intake airways close to smelter stacks. SO 2 exposure limits are a TWA of 2 ppm and an STEL of 5 ppm. Effects of Sulphur Dioxide Concentration (ppm) Effect 3 Detectable by its odour. 100 Irritating to eyes and nose, uncomfortable to breathe. 500 Dangerous to life after only short exposures. 2.4.7 Hydrogen Sulphide (H 2 S) Hydrogen Sulphide is colourless and is readily detected in small concentrations by its unpleasant rotten eggs odour. Unfortunately, continued exposure to the gas (even for relatively short periods of time) leads to paralysis of the olfactory nerves, meaning that the sense of smell cannot thereafter be relied upon. The gas has a specific gravity relative to air of 1.19 and burns in air (in concentrations ranging from 4.5% to 45%), with a bright blue flame producing Sulphur Dioxide (SO 2 ). Acidic action or effects of heating on Sulphide ores produce H 2 S. It is also formed as a result of the decomposition of organic compounds. It is sometimes noticed near stagnant pools of water underground. Hydrogen Sulphide is sometimes associated with natural gas and oil reservoirs and can migrate through strata in solution. H 2 S has a TWA of 10 ppm and a STEL of 15 ppm. It is often associated with methane. Hydrogen Sulphide Effects Concentration (ppm) Effect 0.1 1 Detectable by smell 100 Irritation to eyes and respiratory tract. 200 Intense irritation of eyes and throat. 500 After 30 mins serious inflammation of eyes and throat, coughing, palpitation, fainting, cold sweats. 600 Serious effects after a few minutes, bronchitis and chest pain. 700 Depression, stupor, unconsciousness, and death. 1,000 Paralysis of respiratory system and death. 2.4.8 Methane (CH 4 ) Methane is colourless, odourless and non-toxic. It has a specific gravity relative to air of only 0.55 and as a result, tends to layer against the backs in areas of low air velocity (laminar flow BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 35 © AMC Consultants Pty Ltd 2005 conditions). Methane is of course very dangerous in mines because it forms an explosive mixture with air at concentrations of between 5 and 15 % (it produces an explosion of greatest force at a concentration of 9%). It is found in all coalmines, and has been responsible for many, many thousands of coal mining deaths directly as a result of methane explosions, or after the explosion as a result of Carbon Monoxide poisoning (CO is a product of incomplete methane oxidation). Methane is often associated with other flammable/ explosive hydrocarbon gasses, predominantly hydrogen. The presence of methane in coal mines results from chemical and bacterial action on organic material. Methane is also surprisingly prevalent in metalliferous mining. It is often noted during diamond drilling. The most dangerous situations arise in metalliferous mining where large amounts of methane accumulate (e.g. the stope backs after firing). Cowards Diagram shows the relationship between methane and oxygen concentration and explosibility. 2.4.9 Coal Damps Damp is an old miners term for gaseous products formed in coal mines to distinguish them from pure air. Although still in use they are not commonly used in todays mining. 2.4.9.1 Fire Damp A combustible gas formed by the decomposition or distillation of coal or other carbonaceous matter. Consisting mainly of Methane. (Distillation is the heating of a substance in an atmosphere low in oxygen. This prevents oxidation if the heating was to take place in fresh air.) BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 36 © AMC Consultants Pty Ltd 2005 Usually lighter than air and can accumulate in unventilated mine workings. A change in barometric pressure may cause this to be released to the ventilation system. Produced during mine fires by the distillation of coal. Sometimes simply referred to as gas. 2.4.9.2 Black Damp An atmosphere depleted of oxygen. More specifically an atmosphere containing variable mixtures of Carbon Dioxide (CO 2 ) and nitrogen (N 2 ), generally caused by the oxidation of carbonaceous material or coal and A typical mixture would be 15% CO 2 and 85% N 2 . In it simplest form is the name given to CO 2 . Basically Black Damp is an extinctive atmosphere, hence the term black. Usually heavier than air and can accumulate in unventilated mine workings. A change in barometric pressure may cause this to be released to the ventilation system. 2.4.9.3 Choke Damp A mine atmosphere that causes choking or suffocation due to insufficient oxygen. Could be any combination of CO 2 and CH 4 or other gasses or products of fires, smoke included, that may replace the oxygen content of the air. In some places the name given to black damp. 2.4.9.4 Illawarra Bottom Gas Any mixture of CO 2 and CH 4 ranging from almost 100% CO 2 to almost 100% CH 4 and a little N 2 that is capable of forming a flammable or explosive mixture when mixed with air. Because of its density it tends to layer at the bottom of the drive, hence its name bottom. 2.4.9.5 After Damp That mixture of gasses remaining after, a fire or explosion. (Some times referred to as after gasses. 2.4.9.6 White Damp The term applied to carbon monoxide or more specifically atmospheres containing lethal quantities of CO. 2.4.9.7 Stink Damp Atmospheres containing hydrogen sulphide with the odour the predominate factor. It is worthy to note that when concentrations exceed 50 ppm the sense of smell may be affected and the odour becomes undetectable. 2.4.9.8 Fire Stink This is the smell indicating a spontaneous combustion. The odour is often associated with benzene. 2.4.9.9 Water Gas A combustible mixture of gases with a typical composition being 45% each of CO and hydrogen with smaller amounts of CO 2 , CH 4 , N 2 and oxygen or after damp. Formed when water is hosed onto incandescent masses of coal when extinguishing the fire. The water gas produced could produce a secondary explosion. Considered poisonous because of its high concentration of CO. BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 37 © AMC Consultants Pty Ltd 2005 2.4.9.10 Producer Gas A combustible mixture of gasses formed commercially by the action of air passing through a layer of incandescent fuel (coal, coke or charcoal). A typical mixture would be 10% CO 2 , 15% CO, 74% N 2 and up to 1% of other gasses including CH 4 . An identical mixture may be formed in mine fires. 2.4.10 Ammonia (NH 3 ) Ammonia is colourless, and has a very distinctive, pungent odour (the smell is familiar to those who have used certain disinfectant and window cleaning products). It has a specific gravity relative to air of only 0.65 and as a result, tends to layer against the backs in areas of low air velocity (laminar flow conditions). Ammonia is irritating or corrosive to exposed tissue, especially the eyes and the upper respiratory system. Inhalation of ammonia vapours my result in pulmonary oedema (flooding of the lungs) and chemical pneumonitis. Depending on the concentration, symptoms such as burning sensations, coughing, wheezing, shortness of breath, headache, nausea and eventual collapse may be experienced. NH 3 has a TWA of 25 ppm and a STEL of 35 ppm Ammonia readily passes into and out of solution in water. There are two main sources of ammonia in mines: - As a refrigerant gas in mine cooling plants - Chemical reaction involving ANFO explosive, cement and water. Because of the toxic and irritant effects of ammonia, it is not used as a refrigerant in cooling plants where there is a possibility of the gas leaking into the mine atmosphere (although it is otherwise a particularly suitable gas for the purpose). The main source of ammonia in mines is from a chemical reaction involving ammonium nitrate, cement and water. The ammonium nitrate is sourced from spilt, or un-detonated ANFO. The cement source is generally shot-crete rebound (an increasing problem with more shot-crete usage). The reaction is as follows: Calcium Oxide (a component of the cement) reacts with water to produce an alkali Calcium Hydroxide: 2 2 Ca(OH) O H CaO ÷ + Next, the ammonium nitrate from the ANFO reacts with Calcium Hydroxide to produce ammonia gas (2NH 3 ), Ca(NO 3 ) 2 and water: O 2H ) Ca(NO 2NH Ca(OH) NO 2NH 2 2 3 3 2 3 4 + + | ÷ + There have been an increasing number of ammonia fumings. Worst affected personnel seem to be those on charge-up (working at height, working close to face in poor ventilation, fresh ANFO blow-back, working shortly after shot-crete applied). The only solutions are to remove or isolate one or more of the components of the chemical reaction (i.e. water, ANFO or cement). 2.4.11 Radon (Rn) and Radon Daughters Radon is a colourless and odourless gas. It is one of the isotopes 10 produced by the radioactive decay of uranium to lead. 10 Naturally occurring elements comprise a mixture of isotopes. An isotope may have the same atomic number (number of protons in the nucleus of the atom), but different masses. For example, U238 has 92 protons and 146 neutrons, whereas the isotope U235 has the same number of protons (92), but only 143 neutrons. BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 38 © AMC Consultants Pty Ltd 2005 Decay Series - Uranium to Lead (NOTE THAT THE ISOTOPES IN BOLD ARE RADON DAUGHTERS) Nuclide Radiation Half-life Uranium 238 o 4.5 billion yrs Thorium 234 | ¸ 24 days Protactinium 234 | 1.2 minutes Uranium 234 o 250,000 yrs Thorium 230 o 80,000 yrs Radium 226 o ¸ 1,600 yrs Radon 222 (gas) o 3.8 days Polonium 218 (RaA) o 3 minutes Lead 214 (RaB) | ¸ 27 minutes Bismuth 214 (RaC) | ¸ 20 minutes Polonium 214 (RaC) o 160 µ seconds Lead 210 | ¸ 22 yrs Bismuth 210 | 5 days Polonium 210 o 140 days Lead 206 infinite, stable The half-life is the time taken for one half of the atoms in a radioactive substance to decay. During the decay process, various forms of radiation are released including Alpha (o) and Beta (|) particles as well as gamma (¸) radiation. Alpha particles are low energy, positively charged particles that can travel a few centimetres in air. The respiratory system can be damaged by inhaled alpha particles, but alpha particles do not penetrate the skin surface. Beta particles are electrons. They can penetrate the skin and cause damage to the bodys cells and organs. Gamma radiation is electromagnetic radiation that can penetrate deeply into the body. The half-life of radon is relatively long (at 3.8 days). As a result, it doesnt tend to expose the lungs to a significant amount of radiation energy. It is a different story with the relatively short- lived radon daughters (referred to radon progeny in these more politically correct times)! Inhalation of radon daughters in sufficient concentration over a long enough period of time will increase the likelihood of exposed personnel developing lung cancer. Radon daughters tend to attach themselves to surfaces such as dust particles and aerosols. As a result, the control of ambient dust (especially respirable dust) and diesel soot levels in uranium mines is of particular importance. It is also important in order to reduce the exposure to alpha emitting dust particles. When all else fails, mandatory respiratory protection is sometimes used as a method to limit radon daughter exposure. In underground uranium mines, radon daughters and radioactive dust particles are just some of the radiation hazards. The uranium ore emanates gamma radiation, which also contributes to the total radiation exposure of the workforce. In contrast to dust and radon daughters, Gamma radiation exposure cant be controlled by ventilation. Instead, it is managed by physically BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 39 © AMC Consultants Pty Ltd 2005 shielding the workforce from the ore (particularly high grade ore) and by mine design and shift rotation to limit the time spent in areas where the gamma radiation levels are high. At one, low grade underground uranium mine, the approximate contributions to the total radiation dose are: - Radon daughters 40% - Gamma Radiation 40% - Airborne alpha emitting dust 20% Assuming the ventilation system is well designed and managed, the relative contribution to total dose from gamma radiation will increase for mines with higher uranium grades. It is important to note that the concept of residence time is of critical importance when designing ventilation systems for uranium mines. Once the radon emanates from the rock, it becomes a time bomb, and begins immediately to disintegrate into radon daughters. The aim of the ventilation system design is to remove the radon gas from the underground environment as quickly as possible after it is produced. Depending on the ore grade, ventilation design criteria can specify underground air residence times (after exposure to rock containing uranium) of less than 10 to 15 minutes. Areas of low velocity, with high ore rock surface exposure (e.g. stopes and sealed off workings) are radon daughter breeding grounds. Personnel should not be exposed to the resulting high radon daughter concentrations in the air leaking or exhausted from these locations. This contaminated air should flow to a surface exhaust airway via as direct a route as possible. The ventilation system design should ensure that personnel work in fresh air that has travelled from the surface to the working place via a direct route in low-grade (waste) rock. In order to limit exposure of personnel to radon daughters, considerable care with mine design and scheduling is required in uranium mines and accordingly, ventilation considerations are often the most important mine design criterion. The source of radon in mines is primarily via emanation from rock containing uranium and radium. The gas is found in underground mines (not just uranium mines) and sometimes also in caves (many of which have poor ventilation and therefore long residence times). Determination of a safe or acceptable exposure standard for radon and radon daughters is complex. Exposure to these gasses constitutes just one of several contributors to the total radiation exposure. The total effective radiation dose is measured in units of Sieverts (Sv). The Sievert is a unit of radiation derived health risk. The prevailing annual limit for radiation workers is 20 mSv/ year, averaged over 5 yrs. Note that practice of the ALARA (As Low As is Reasonably Achievable) principle is always the recommended approach with respect to radiation doses and a number of operations have adopted internal standards which aim to achieve dosages that are less than a third or a quarter of the prevailing limits. BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 40 © AMC Consultants Pty Ltd 2005 SUMMARY OF GASSES Name of Gas Symbol Properties Smell Flammable Limits TWA STEL Physiological Effects (ppm) (%) (ppm) (%) Oxygen O2 Colourless Tasteless Nil In contact with oil or grease - 17.0 (19.0 in mines) - 13.0 Essential to maintain life Carbon Monoxide CO Colourless Tasteless Nil 12.5% - 74% 50 0.005 400 0.04 Displaces oxygen in blood - 200 ppm Drowsiness; Headache after 2 hours work - 400 ppm Headache after 45 mins work - 1200 ppm Palpitations after 10 mins work - 2000 ppm Unconsciousness after 10 mins work - >3000 ppm Death possible Carbon Dioxide CO2 Colourless Soda taste Slight pungent Non-flammable 5000 0.5 30000 3.0 Increased respiration Depression of breathing Hydrogen H2 Colourless Tasteless Nil 4.0% - 74% - - - - Non-poisonous Asphyxiant Hydrogen Sulphide H2S Colourless Sweet taste Rotten Eggs 4.5% - 45% 10 0.001 15 0.0015 - 100 ppm Irritation to eyes and throat : Headache - 1000 ppm Immediate unconsciousness Nitrogen N2 Colourless Tasteless Nil Non-flammable - - - - Non-poisonous Asphyxiant Oxides of Nitrogen NOx Firing fumes 25 0.0 - - - 100 ppm irritant to respiratory passage and eyes - 200 ppm After 20 mins may cause collapse usually delayed - 400 ppm after 15 mins exposure may be fatal Nitrogen Dioxide NO2 Brown colour Acrid taste Firing fumes Acrid Non-flammable 3 0.0003 5 0.0005 - 50 ppm Irritating to eyes and nose - 250 ppm severe pulmonary oedema collapse is usually delayed Methane CH4 Colourless Tasteless Nil 5.0% - 14.0% Stop diesel engines when = or > 1.0% Turn off electrical power when = or > 1.25% Remove people when= or > 2.5% Non-poisonous Asphyxiant Sulphur Dioxide SO2 Colourless Acid taste Burning Sulphur Pungent Suffocating Non-flammable 2 0.0002 5 0.0005 Oedema BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 41 © AMC Consultants Pty Ltd 2005 2.5 Diesel Engines Dr. Rudolf Diesel first patented the device and principles for a compression engine in Germany in 1892. The diesel engine as it is now known, is used almost exclusively as the engine of choice in Australian Mines. The exception being some electric LHDs and trucks. Other fuels such as hydrogen have been investigated since the 1960s and there is one hydrogen engine operating in Canada today but generally speaking there use remains in the laboratories until all the safety implications have been overcome. Diesel engines are considered to be reliable, robust and relatively easy to maintain, and particularly efficient at partial loads. These engines do not rely on spark plugs for fuel ignition but rely on the in-cylinder temperature, generated on the compression stroke, for ignition of the injected fuel. For this to occur, air is injected into the cylinder and compressed to a high pressure with a corresponding temperature rise. As the cylinder nears the top of it stroke the temperature of the gases rise to temperatures in excess of 540°C, well above the ignition point for diesel fuel. A fine mist of fuel is injected into the gap where it combusts. The resulting physical and chemical processes lead to auto-ignition just prior to the cylinder reaching top dead centre, the combustion energy released forces the piston down to bottom dead centre in the power stroke. Engines used in mining can be broadly classified as, either direct injection (DI), indirect injection (IDI or otherwise referred to as pre combustion PC) they can be naturally aspirated or turbo charged for increased power and performance. PC engines are considered to be more acceptable for use in underground workings because they generally have lower gas emissions. Electronic fuel management systems are progressively being introduced more extensively into underground hard rock mines, but it is worth a note that electronic fuel management systems have yet to be introduced into underground coal mines and this will only occur once they are able to provide intrinsically safe mechanisms. Although this fuel management system has helped reduce the more visible DPM the side effect has been the increase (albeit minor) in levels of oxides of nitrogen (NO X ). 2.5.1 Diesel Exhaust Emissions (DEE) The production and concentrations of gases in DEE is dependent upon - Engine type and manufacturer - Engine speed - Engine adjustment and maintenance - Working load of the engine - Type of fuel Because of these variables it is extremely difficult to provide absolute values of the quantity and concentrations of DEE gases. Diesel fuels consist primarily of Carbon (84.5%) and Hydrogen (15%) with a small amount of Sulphur (0.5%). Typically diesel fuels contain two hydrogen atoms for each carbon atom and can therefore be represented as C 12 H 24 . Complete combustion of 1kg of diesel fuel would result in Carbon Dioxide (CO 2 ) water vapour (H 2 O) and Sulphur Dioxide (SO 2 ) in the following proportions kg 10 . 3 = 12 44 × 845 . 0 = 2 CO BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 42 © AMC Consultants Pty Ltd 2005 kg 35 . 1 = 2 18 × 150 . 0 = O 2 H kg 01 . 0 32 64 005 . 0 2 SO = × = A total of 4.46kg of gas. For complete combustion the amount of Oxygen required is 4.46 1.00 = 3.46kg and as standard air contains 23.15% Oxygen, by mass, the air required for complete combustion is 14.95kg = 0.2315 3.46 . In other words an air to fuel ratio of 1:14.95, or alternatively each 0.0669kg of fuel requires 1.0kg of air for complete combustion. Fuel to air ratios in normal conditions are 0.01kg at idle and 0.05kg at full throttle up to a maximum of 0.06kg. At full throttle full load this could be as high as 0.08kg but at this ratio there is a large amount of unburnt fuel emitted. When averaged over a full shift the fuel to air ratio would typically be between 22:1 (0.045kg) and 25:1 (0.04kg fuel) In reality diesel engines never operate at 100% efficiency, seldom at full load and consequently complete combustion is never achieved. The products of this incomplete combustion are Carbon Monoxide (CO), Hydrocarbons (including aldehydes) (HC), Carbon (soot defined as diesel particulate matter) (DPM), Oxides of Nitrogen (NO X ) including Nitric Oxide (NO) and Nitrogen dioxide (NO 2 ). Other toxic substances like polyaromatic hydrocarbons (PAH) are also found in both the HC and DPM component of the DEE. The concentrations of gasses in DEE are directly related to the quantity of fuel used. Fuel consumption is related to work load on the engine (i.e. the higher the work load the greater the fuel consumption). Maximum fuel consumption is achieved when the engine is operating at torque stall, therefore maximum concentrations and emission levels of DEE gases. In the case of mining equipment this would be when a LHD unit is bogging and when a truck is hauling fully loaded up an incline. Ideally exhaust gas emission rates should be obtained for all normal operating situations. For example a LHD cycle would include loading, hauling full, dumping full, hauling empty and Idle. Although the liquid fuel droplets in the injected mixture begin to decompose on ignition the fuel rich zones associated with them result in incomplete combustion and the formation of CO rather than CO 2 and as the load increases the amount of excess Oxygen decreases and tends to increase the formation of CO. Because there is a large amount of Nitrogen in the injected air used for combustion this along with the pressure and temperature of combustion some of the nitrogen is oxidised to NO and this then oxidises at a much slower rate to NO 2 to the extent that only 10% is oxidised by the time it is exhausted from the engine. 2.5.2 Diesel Particulates Diesel particulate matter (DPM) is the soot particles emitted with diesel engine exhaust. The size of the particles is almost totally within the respirable range. The particles contain hundreds of adsorbed compounds, some of which are known to be carcinogenic. DPM is thought to be a potential carcinogen but no unequivocal evidence on this matter is currently available and the subject is as a result, still somewhat controversial. Metals Metals Carbon Carbon Sulphate Sulphate + Water + Water Polyaromatic Polyaromatic Hydrocarbons Hydrocarbons (PAH) (PAH) Hydrocarbons Hydrocarbons (HC) (HC) COMPOSITION OF DPM COMPOSITION OF DPM Metals Metals Carbon Carbon Sulphate Sulphate + Water + Water Polyaromatic Polyaromatic Hydrocarbons Hydrocarbons (PAH) (PAH) Hydrocarbons Hydrocarbons (HC) (HC) COMPOSITION OF DPM COMPOSITION OF DPM BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 43 © AMC Consultants Pty Ltd 2005 DPM is a complex substance and has been to object of constant investigation for a number of years. More particularly since the formation of a task force initiated by Coal Services Pty Ltd (formally the Joint Coal Board) in 1997 to determine the management and control of DPM in Coal mines. As yet the hard rock industry has not embraced these studies but will be keeping a watchful eye on proceedings since the introduction of control legislation in the USA in 2001. The American Conference on Governmental Industrial Hygienists (ACGIH) has proposed a general exposure standard for Diesel Particulates (DP) of 0.15 mg/m 3 , but has failed so far to achieve worldwide recognition. Whilst there are currently no diesel particulate exposure standards for mines in Australia, if we were to follow the USA lead then an exposure standard of 0.4mg/m 3 (eight-hour exposure) will be introduced some time in the future. The USA control legislation is pointed at manufacturers and the reduction of DPM in the exhaust emissions. and a standard along these lines was introduced for the USA mining industry in 2001. It is understood that establishing a diesel particulate exposure standard for underground mines in Australia is not on the short-term agenda. Adoption of the ALARA (As Low As Reasonably Achievable) principle to workforce diesel particulate exposures would however be a pragmatic and recommended response to the issue. In recent years design strategies have concentrated on the achieving more complete combustion and minimising the formation of in-cylinder particulate matter. The formation of NO X is the sole function of the available oxygen and the temperature, and the higher in-cylinder temperatures have subsequently increased the amounts of nitrogen that are oxidised to Nitric Oxide (NO), some of which is re-oxidised to Nitrogen Dioxide (NO 2 ). Hence a dilemma, decreased DPM but at the expense of increased NO X emissions. The 1990s has seen some major advances in engine technology to reduce DEE. - Fuel injector design have allowed manufacturers to control the rate of fuel injection resulting in lower emissions of DPM and NO X - Fuel injector pressure has been increased resulting in better atomisation of the fuel in the combustion chamber resulting in decreased DPM - Turbo-charging has resulted in better combustion and decreased DPM whilst cooling the compressed air supplied to the intake manifold reduces the NO X that would result from the increased combustion temperatures. - Improved intake manifold and port configurations have achieved better in-cylinder air distribution eliminating fuel rich spots and inturn decreasing DPM and hydrocarbons emissions. - Combustion chambers have been redesigned to achieve better mixing resulting in improved combustion and decreased DPM and hydrocarbons - Oil control has been improved significantly as prior to 1990 as much as 30% of DPM was attributed to lubricating oil. This improvement has reduced DPM by as much as 10%. A number of exhaust conditioners have been developed over the years. These conditioners are extremely expensive and require a high level of maintenance. Some, such as the CO catalytic converters have been highly successful whilst others are still in development stage. The obvious problem is to get a single conditioner for all contaminants as experience has shown that one problem is solved and another created. Available methods for reducing underground DPM include: - Use more efficient diesel engines (eg engines with electronic engine fuel-air mixture control systems) BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 44 © AMC Consultants Pty Ltd 2005 - Pay close attention to engine maintenance (tuning, air cleaner maintenance etc) - Use low Sulphur fuel (<0.05% Sulphur). This type of fuel is now becoming more readily available in Australia. - Use exhaust particulate filters especially on production equipment where high exhaust temperatures can be maintained for long enough to burn trapped particulates off catalysed ceramic filters. Up to 85% of particulates can be captured using particulate filters. A recommended reference is - Diesel Emissions in Underground Mines Management and Control NSW Minerals Council, October 1999. It states, More research into the effects of ventilation and diesel particulate exposure is required before comprehensive guidance can be provided on this issue one cant help but agree. 2.5.3 Dilution of Diesel Exhaust Emissions (DEE) The concentrations of contaminants in the ambient air are directly related to the total quantity of gases and particulates emitted from the diesel engine and the mine dilution ventilating air. If the engine operating mode, emission characteristics, and the engine exhaust air volume are known, the quantity of emissions from the engine can be calculated. Studies have shown that diesel engines in operating mines have a relatively low effective load factor, some times referred to as the duty cycle, and could be as little as 20% to 40% of full load over the entire shift. One of the questions asked of ventilation engineers is the quantity of ventilating airflow necessary to dilute these contaminants below statutory exposure limits. Most Australian state legislation provides some guideline for this dilution rate and in Western Australian legislation this is very specific. It is good management to check this legislation for the state in which the mine is located. One equation used to calculate this dilution factor is written as g C C g Q N A Q Q ÷ ÷ = Equation 2-4 Dilution Equation Where Q = Quantity of airflow required for dilution (m 3 /s) Q g = Exhaust gas Emission Rate (EGER) (m 3 /s per kW) A C = Maximum allowable gas concentration in the workplace. (m 3 /s) N C = the normal concentration of gas present in the diluting air (m 3 /s) Notes: m 3 /s = ppm / 1,000,000 EGER = Measured concentration x volume of exhaust gasses. Based on the NOHSC 8 hour exposure standard of 30ppm for CO, a text book exhaust emission rate of 0.0015 m 3 /s per kW of installed power and an undiluted concentration of CO of 1500 ppm in the exhaust (i.e. the maximum allowable limit) the dilution airflow required for DEE is 0.075 m 3 /s per kW. 0.0015 0.0015 - 0.0 - 0.00003 0.0015 0.0015 Q × × = = 0.07499m 3 /s BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 45 © AMC Consultants Pty Ltd 2005 The US Bureau of Mines (USBM) recommends the use of the following simplified formula to calculate the dilution factor for DEE. Y VC Q = Equation 2-5 DEE Dilution (USBM) Where Q = Quantity of airflow required for dilution (m 3 /s) V = Volume of gas produced (m 3 /s) C = Concentration of gas in the exhaust (ppm) Y = Maximum allowable concentration in the workplace (ppm) i.e. 30 1500 0.0015 Q × = = 0.07500 m 3 /s per kW Similarly for NO X . TLV = 25ppm eight-hour exposure 25 1000 0.0015 Q × = = 0.0600 m 3 /s per kW From this calculation the minimum dilution airflow should be 0.075m 3 /s per kW of installed diesel power. The use of these equations is fine but only IF the emission rate is known. We can easily determine, by measurement the concentration of the contaminants whereas the rate of emission can be calculated from manufacturers data. Emission rate is a function of the number and dimensions of the cylinders and the speed of the motor. Knowing these the rate at which the gasses are forced from the engine enables the correct calculation of the rate of emission, obviously, the greater the speed of the engine the greater the rate of emission. For example consider the engine data provide by a engine manufacturer shown below. Engine: Inline 6 cylinder 4 stroke Power Rating: 475 HP (354kW) @ 2100 RPM Max Torque: 1550 ft.lb (2101 Nm) @ 1200 RPM Rated Speed Max Torque Speed Exhaust Temperature: 432 degC 518 degC Stroke: 139mm Bore: 130mm From this data we can estimate the exhaust flow (emission) rate for the engine Calculation of exhaust swept volume 6 10 n S 2 2 b D × × × = t | . | \ | Equation 2-6 Engine Displacement Volume Where: D = Engine Displacement Volume (litres) b = Bore diameter (mm) BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Page 46 © AMC Consultants Pty Ltd 2005 t = 3.1428 S = Stroke length (mm) n = Number of Cylinders Therefore 6 10 6 139 2 2 130 D × × × = t | . | \ | = 11.1(litres) 2000 s D SEV × = Equation 2-7 Swept Exhaust Volume (Four stroke Engine) Where: SEV = Swept Exhaust Volume (m 3 /min) D = Engine displacement (litres) s = Engine speed (rpm) 2000 = Four Stroke engine factor 1000 s D SEV × = Equation 2-8 Swept Exhaust Volume (Two stroke Engine) Where: 1000 = Two Stroke engine factor The engine data provided is a four-stroke therefore at the rated speed 2000 2100 11.1 Volume Exhaust Swept × = = 11.7 m 3 /min and at max torque speed 2000 1200 11.1 Volume Exhaust Swept × = = 6.7 m 3 /min Correcting for temperature and assuming pressure (P) is constant 2 T 2 V 2 P 1 T 1 V 1 P = (Universal Gas Law) Where: T = temperature in °K V = Swept Volume (m 3 ) at the rated speed 273 432 2 V 273 25 11.7 + = + = 27.7 m 3 and similarly for maximum torque = 17.8 m 3 A further correction is then made for turbo charging and after cooling. Typically this 1.5 but will vary from engine to engine. Correcting for Turbo charging the emission rates now become 41.5 m 3 /min at the rated speed (i.e. 27.7 x 1.5 = 41.5) and, 26.7 m 3 /min at maximum torque (i.e. 17.8 x 1.5 = 26.7). BASIC MINE VENTILATION PROPERTIES OF AIR Page 47 © AMC Consultants Pty Ltd 2005 I can remember when the air was clean and sex was dirty. George Burns 3 PROPERTIES OF AIR Air is a mixture of a number gasses. Air is a perfectly mixed (homogeneous) mixture of gasses, in spite of the fact that the various component gasses have different densities. Composition of Air Oxygen 20.93% Nitrogen 78.11% Carbon Dioxide 0.03% Inert Gases 0.93% Water Vapour Variable Note that layering of gasses (e.g. methane, which is lighter than air and Carbon Dioxide, which is heavier than air) sometimes occurs in mine airways, where the airflow is very low. If these gasses seep slowly into an area of very low airflow (laminar flow conditions - <<<0.1 m/s), a meniscus can form at the boundary between the gas and the air, leading to separation and layering. Providing a turbulent air can easily break up this layering. The gas will then mix evenly with the air, and will never separate again. Mine air also contains a percentage of water vapour. The vapour is regarded as being a separate component or impurity (i.e. it is not viewed as being part of the air). 3.1 Air Temperature Mine air temperatures are measured in SI units of Degrees Celsius. It is useful to recall that at normal sea level pressure, water freezes at 0°C and boils at 100°C. The lowest (theoretically) possible temperature is 273.15°C (sometimes known as absolute zero). If we change the Celsius scale so that absolute zero (-273.15°C) is reassigned the value of 0 then we will have what is known as the Kelvin temperature scale (K). So 0 K = -273.15C° and 273.15 K = 0°C. In other words, 273.15 C) T( T(K) + ° = Equation 3-1 Relationship Between °C and K There are two types of air temperature readings that we deal with routinely in mining. They are dry bulb and wet bulb temperatures. Dry-bulb temperature is simply the air temperature. When measuring dry-bulb air temperatures it is important to avoid the effect of radiative heat transfer (i.e. temperature readings should not be taken near surfaces whose temperatures differ by more than several degrees form the air temperature e.g. avoid measuring air temperature near a hot diesel engine) Wet-bulb temperature is measured with a thermometer whose bulb is covered with a thin, wet cotton sleeve. As with dry-bulb temperature readings, wet bulb air temperature measurement near surfaces whose temperatures differ by more than a few degrees from the dry-bulb air temperature, are avoided. The bulb must be aspirated by an airflow that is at least 3m/s, to ensure accurate reading. Due to the effect of evaporation, the wet bulb temperature will always be less than, or equal to the dry-bulb temperature. BASIC MINE VENTILATION PROPERTIES OF AIR Page 48 © AMC Consultants Pty Ltd 2005 3.2 Charles Law Charles law states that the same rise of temperature produces in all gasses the same increase in volume, provided the pressure is kept constant. In other words, at constant pressure: 2 1 2 1 V V T T = Equation 3-2 Charles Law Where: T = Absolute temperature (K) V = Volume occupied by gas 3.3 Boyles Law Boyles law states that the volume occupied by a gas is inversely proportional to the absolute pressure exerted upon it, provided the temperature is kept constant. In other words if the pressure on the gases increases its volume will decreases. Conversely if the pressure decreases, the volume of the gas will increase: 2 2 1 1 V P V P = Equation 3-3 Boyles Law Where: P 1 = Initial absolute pressure V 1 = Initial volume occupied by gas P 2 = Final absolute pressure V 2 = Final volume occupied by gas 3.4 Universal Gas Law Charles law and Boyles Law can be combined mathematically to produce what is known as the Universal Gas Law: 2 2 2 1 1 1 T V P T V P = Equation 3-4 Universal Gas Law Therefore, for a given quantity (mass) of a given gas, T PV is a constant. The constant for one kilogram of a given gas is known as R, hence R T PV = . Note that because we now specify that we have one kilogram of gas, then the volume (V) is in units of m 3 /kg i.e. specific volume. R varies depending on the gas type. For dry air, R = 0.2871 kJ/kg, assuming pressure (P) is in kPa, temperature (T) is in K and specific volume (V) is in m 3 /kg). Note that a Joule is 1 N·m. 3.5 Density of Dry Air The density of dry air can now be readily determined using the Universal Gas Law. An example calculation is outlined below: Example What is the density of dry air at a barometric pressure of 95 kPa and a dry bulb temperature of 25°C? BASIC MINE VENTILATION PROPERTIES OF AIR Page 49 © AMC Consultants Pty Ltd 2005 Rearranging Equation 3.4 P RT V = and substituting
95 ) 273 25 ( 2871 . 0 V + × = = 0.90 m 3 /kg Density (µ) kg/m 3 = ) kg / m ( V 1 3 = 1.11 kg/m 3 This is a very useful first pass method to estimate the density of air. It is accurate to within ± 0.5% for any condition between dry air at any temperature and saturated air (100% relative humidity) up to 25°C. Another useful application of the Universal Gas Law is illustrated below: Example 200 m 3 /s of dry air at a temperature of 30°C and barometric pressure of 95 kPa flows down an intake shaft into a mine. At the bottom of the shaft, the air temperature is measured as 37°C and the barometric pressure is 102 kPa. What is the flow rate at the base of the shaft if there is no leakage and no moisture pick-up in the shaft? Rearranging Equation 3.5: 2 1 2 1 1 2 P T T V P V = And substituting: 102 ) 273 30 ( ) 273 37 ( 200 95 V 2 × + + × × = s / m 191 V 3 2 = The result shows that we have lost 9 m 3 /s (4½%) of our airflow before it reaches the base of the shaft. The change in volume flow due to air compression is an important factor when designing and monitoring ventilation systems for deeper (e.g. >1,000m below surface) mines. In these deeper mines, it is therefore often more convenient to deal with air flow rates in terms of mass flow (i.e. kg/s). For the majority of mines however, the change of volume due to compression of the air is small enough to be ignored. 3.6 Moisture in Mine Air Up to now, we have assumed dry air for all of our calculations. This is a simplistic assumption since in mine airways, the air invariably also contains some water vapour. The amount of water vapour contained in a volume of air is dependent on the temperature of the air. At higher temperatures, the amount of water vapour that the air can contain increases. When air contains the maximum possible amount of vapour at a given temperature, it is said to be saturated. Saturated air has a relative humidity of 100%. BASIC MINE VENTILATION PROPERTIES OF AIR Page 50 © AMC Consultants Pty Ltd 2005 If air containing a certain amount of water vapour is cooled, a temperature will be reached where the air is unable to contain all of the water vapour. The vapour will condense out into water droplets. This temperature is known as the dew point temperature. Condensation of water vapour can cause fogging and can sometimes be a problem in mine airways where warm, humid air is cooled below its dew point (e.g. by a mine air cooler). Condensation of water sometimes also occurs in upcast ventilation shafts in this case the cooling of the mine air is caused by the reduction in air pressure as the air travels upwards (the opposite of autocompression). The condensed water droplets can cause problems with surface fan operation. 3.7 Density of Humid Air The Standard density of dry air at 20°C and 101,325 Pa barometric pressure is 1.2 kg/m 3 Unless otherwise stated, the performance figures supplied with mine fans assume that the fans will operate at standard air density. Unfortunately, many mine fans operate in locations where the fan inlet air density is significantly different to standard air density. It is therefore necessary to understand how to calculate the actual air density against which the fans operate. In many situations, Equation 3.4 is sufficiently accurate, however where improved accuracy is important, it is necessary to employ a calculation method that takes into account the effect of the moisture contained within the mine air. The density of air is the mass per unit volume and varies according to the water vapour contained in the air and three input values are required to determine the density of air which contains water vapour. They are: - Barometric Pressure - Dry Bulb Temperature - Wet Bulb Temperature. The air density can be calculated using the relationship described as ( ) d t 15 . 273 287045 . 0 e 378 . 0 P + ÷ = µ , (kg of air/m 3 ) Equation 3-5 Density of Humid Air Where µ = Air Density (kg/m 3 ) (Some texts describe this as vair rather than air, this is to distinguish between dry air and air containing water vapour.) P = Atmospheric Pressure (kPa) t w = Wet-bulb temperature(°C) t d = Dry-bulb temperature (°C) e = Partial Pressure of water vapour (kPa) ( ) ( ) w d w d w d sw t 4 . 0 t 04 . 0 4 . 371 P t t 24 . 0 t 6 . 0 t 24 . 0 4 . 371 e e ÷ + ÷ ÷ ÷ + = Equation 3-6 Partial Pressure of Water Vapour e sw = Saturated vapour pressure at the wet-bulb temperature (kPa) + = w w sw t 3 . 237 t 27 . 17 . exp e Equation 3-7 Saturated Vapour Pressure at the Wet-bulb Temperature BASIC MINE VENTILATION PROPERTIES OF AIR Page 51 © AMC Consultants Pty Ltd 2005 EXAMPLE What is the density of the air in a drive where the wet and dry bulb temperatures are (respectively) 25 and 30°C and the barometric pressure is 97.5 kPa. We will solve this problem using both the approximate method (Equation 3.4) and the more accurate method (Equation 3.5). Approximate Method: Rearranging Equation 3.4
RT P = µ and substituting
3 m / kg ) 30 273 ( 2871 . 0 5 . 97 + × = µ µ = 1.121 kg/m 3 In fact this is the density of dry air. More Accurate Method: Calculate the Saturated vapour pressure at the wet-bulb temperature + × = 25 3 . 237 25 27 . 17 . exp e sw = 3.166 kPa Calculate the Partial Pressure of water Vapour ( ) ( ) ( ) ( ) ( ) ( ) 25 4 . 0 30 04 . 0 4 . 371 5 . 97 25 30 24 . 0 25 6 . 0 30 24 . 0 4 . 371 166 . 3 e × ÷ × + ÷ ÷ × ÷ × + = = 2.852 kPa Use Equation 3.5 to calculate the air density (µ): ( ) ( ) 30 15 . 273 287045 . 0 852 . 2 378 . 0 5 . 97 + × ÷ = µ µ = 1.108 kg/m 3 3.8 Air Pressure Every person who works in an underground mine knows that the fan produces the airflow and generally accept this fact without needing (or wanting) to know any more. The operation, use and placement of fans will be discussed later in these notes. At this point we need to understand that fans create a pressure differential that causes the air to flow through the workings. To assist with understanding consider the following, when we pump up a tyre the pressure in the tyre becomes higher than the pressure of the atmosphere. Similarly if we were to suck the air from a vessel (create a vacuum) the pressure of the air out side the vessel would be greater than the pressure of the air inside the vessel. When the tyre valve is opened the air flows from the tyre and if the vessel is opened the air will flow into the vessel. In both cases the air will flow from the high-pressure area to the low-pressure area until the pressure inside the vessel is the same as the pressure outside the vessel. When this happens the flow will stop. BASIC MINE VENTILATION PROPERTIES OF AIR Page 52 © AMC Consultants Pty Ltd 2005 This is also seen on a weather map where the wind blows from the HIGH pressure to the LOW pressure. The greater the pressure difference the faster the wind blows. In ventilation (mines, buildings or otherwise) for air to flow from one point to another there must be a difference in pressure between the two points. This difference in pressure is known as the ventilating pressure and the following rules apply. (1) Air will always flow from a high pressure point to a low pressure point and as long as this pressure is maintained, air will continue to flow, (2) The larger the pressure difference between these two points the greater the quantity of air will flow. This assumes the resistance between the two points remains unchanged. (3) Resistance to pressure reduces the ventilating pressure, ie the pressure is used up overcoming resistance to the airflow. (4) If the pressure difference between two points remains the same and the resistance to airflow between these points is increased the air quantity will decrease Pressure is the force applied per unit area and in ventilating terms is usually expressed in Pascals. One Pascal (Pa) = One Newton per square metre (N/m 2 ) There are may other expressions for pressure including inches of water gauge, millimetres of mercury all of which are required to be converted to Pascals for use in mine ventilation calculations. Of importance in to mine ventilation practitioners is the different types of pressure. 3.8.1 Atmospheric Pressure The earth is contained in an atmosphere and by the force of gravity, it exerts a pressure on the surface of the earth caused by the weight of the air above. Atmospheric pressure at sea level is equivalent to a mass of 10,000 kg on one square meter (m 2 ) of surface and is expressed in the following ways: - 1 Atmosphere, - 1.013 Bar, - 101.325 kPa, - 1013 mb, The pressure shown on weather chats is usually expressed in millibars (mb) and often referred to as the Barometric Pressure. 3.8.2 Barometric Pressure Barometric pressure is simply a description of the instrument used to measure the pressure of the atmosphere in which it is situated. In mine workings the pressure measured using a barometer includes pressure changes caused by fans and therefore is not always be a true indication of the atmospheric pressure outside the mine. BASIC MINE VENTILATION PROPERTIES OF AIR Page 53 © AMC Consultants Pty Ltd 2005 3.8.3 Static Pressure (SP) Static pressure is the potential or stored energy of the air often called the bursting pressure and this term does in fact make it easier to visualise, because static pressure is the pressure exerted by the air on the walls of the containing vessel. For example when the tyre valve is opened the potential (static) pressure is then converted to kinetic energy as it flows from the tyre. In the case of a ventilation duct it is the pressure holding the duct open. It is called static pressure because it is the same as the pressure of the air, which would exist if the air were not moving. In ventilation ducts the static pressure is measured with a side tube, normal to the direction of airflow. 3.8.4 Velocity (Dynamic) Pressure (VP) Moving air possess kinetic energy which is the energy associated with motion. In mine ventilation this is termed Velocity Pressure. The faster the air moves the greater velocity pressure will be and vice versa. Velocity pressure cannot be measured directly, however it can be measured indirectly using pitot tube. Velocity pressure is calculated from 2 v VP 2 µ = Equation 3-8 Velocity Pressure Where VP = Velocity Pressure (Pa) µ = Density of air (kg/m 3 ) v = Velocity (m/s) 3.8.5 Total Pressure (TP) Total Pressure is the algebraic sum of the static pressure (potential energy) and the velocity pressure (kinetic energy) and is measured with a facing tube, parallel to the direction of flow. Direction of Airflow To gauge To gauge Direction of Airflow To gauge Direction of Airflow BASIC MINE VENTILATION PROPERTIES OF AIR Page 54 © AMC Consultants Pty Ltd 2005 VP SP TP + = Equation 3-9 Ventilating Pressure Where TP = Total Pressure (Pa) SP = Static Pressure (Pa) VP = Velocity Pressure (Pa) 3.8.6 Measuring Pressure in a Duct The static, velocity and total pressure may be obtained for airflow in a duct using a tube and a manometer. 3.8.7 Natural Ventilating Pressure Airflow through a mine will occur whenever there is a pressure difference between the intake and exhaust. Natural Ventilation Pressure (NVP) is formed when there is a difference in air temperature and density between a vertical column of air inside a mine and the corresponding column of air outside the mine. When these columns are connected airflow will occur. This is often referred to as the chimney effect where warm air rises up the opening displacing the colder air above and drawing more air into the bottom. This method for ventilating underground was Direction of Airflow Total Pressure Static Pressure Velocity Pressure Direction of Airflow Total Pressure Static Pressure Velocity Pressure BASIC MINE VENTILATION PROPERTIES OF AIR Page 55 © AMC Consultants Pty Ltd 2005 B = 1.2 kg/m 3 C = 1.3 kg/m 3 A = 1.09 kg/m 3 D = 1.15 kg/m 3 600m 600m B = 1.2 kg/m 3 C = 1.3 kg/m 3 A = 1.09 kg/m 3 D = 1.15 kg/m 3 600m 600m practiced by the Greeks in 600BC when fires were lit at the bottom of shafts to create a draught of air. In mines this occurs when there is a difference in temperature between the workings and the surface. Variations of temperatures will occur form day to night, summer to winter and may in fact flow in opposite directions. For example the heat of summer may cause the air to flow into the workings, whereas in the colder winter months the flow will be from the mine workings and will have an impact on the operating point of the primary ventilating fans. Although this impact on mine fan performance is limited, the potential NVP needs to be quantified. Air will flow from the column with the lowest average temperature to the column with the highest average temperature. The variance of NVP is dependent upon a number of variables including - elevation - depth from surface - geothermal gradient - local climatic conditions In its simplest form NVP can be estimated by assuming a closed circuit (intake ¬ workings ¬ exhaust). ȡgh NVP = Equation 3-10 Natural Ventilating Pressure Where NVP = Pascals g = Acceleration due to Gravity (9.81m/s 2 ) h = Difference in height between start and finish of each branch (m) µ = Mean True Density in each branch (kg/m 3 ) Example From the data shown in the schematic, determine the mine Natural Ventilating Pressure in (Pa) Calculate the mean density in each branch = + = 2 12 . 1 09 . 1 AB 1.105 (kg/m 3 ) BASIC MINE VENTILATION PROPERTIES OF AIR Page 56 © AMC Consultants Pty Ltd 2005 = + = 2 13 . 1 12 . 1 BC 1.125 (kg/m 3 ) = + = 2 15 . 1 13 . 1 CD 1.14 (kg/m 3 ) Calculate NVP in each branch ( ) Pa 6504 105 . 1 600 81 . 9 NVP AB = × × = ( ) Pa 6710 140 . 1 600 81 . 9 NVP CD = × × = Total Mine NVP CD BC AB NVP NVP NVP ÷ ÷ = = 6504 - 6710 = -206(Pa) For mines with surface intake and exhaust point at the same level, this equation can be simplified to: ( ) ME MI ȡ ȡ gh NVP ÷ = Where µ MI = Mean Density of the Intake (kg/m 3 ) µ ME = Mean Density of the Exhaust (kg/m 3 ) BASIC MINE VENTILATION PROPERTIES OF AIR Page 57 © AMC Consultants Pty Ltd 2005 3.9 Assignments 3.9.1 [Q] Calculate the velocity pressure for air quantities of 10 m 3 /s, 20 m 3 /s & 30 m 3 /s in ducts with diameters of 1,000 mm 1,200 mm & 1,400 mm. Assume the density of air is 1.2 kg/m 3 3.9.1 [A] Equations used: 1)
. (Pa) 2 2 v ȡ = VP 2)
.. (m/s) A Q v = 3) ) (m 4 ʌD A 2 2 = Density (kg/m 3 ) 1.2 Diameter (m) 1.0 1.2 1.4 Area (m 2 ) 0.785 1.131 1.539 Q = 10 (m 3 /s) v (m/s) 12.7 8.8 6.5 VP (Pa) 97 47 25 Q = 20 (m 3 /s) v (m/s) 25.5 17.7 13.0 VP (Pa) 389 188 101 Q = 30 (m 3 /s) v (m/s) 38.2 26.5 19.5 VP (Pa) 875 422 228 3.9.2 [Q] Using a pitot static tube the following pressure readings were recorded in a flexible duct 1,200 mm diameter. Measuring Point 1 2 3 4 5 6 7 8 Facing tube 1825 1845 1870 1920 1880 1850 1845 1835 Side tube 1490 1545 1555 1560 1560 1555 1560 1550 If the density of the air was 1.26kg/m 3 calculate 1. the average static pressure 2. the average velocity pressure the quantity of air flowing in the duct 3.9.2 [A] Equations used: 1)
. ) (m 4 ʌD A 2 2 = 2)
.VP=TP-SP 3)
. ȡ 2VP = v 4)
.Q=VA Area of the duct 1.132 (m 2 ) Measuring Point 1 2 3 4 5 6 7 8 Facing tube 1825 1845 1870 1920 1880 1850 1845 1835 Side tube 1490 1545 1555 1560 1560 1555 1560 1550 VP (Pa) 335 300 315 360 320 295 285 285 v (m/s) 23.1 21.8 22.4 23.9 22.5 21.6 21.3 21.3 Average Static Pressure 312 (Pa) Average Velocity 22.2 (m/s) Quantity of air 25.1 (m 3 /s) BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 58 © AMC Consultants Pty Ltd 2005 Ventilation is a science, albeit not always a precise science, because in practice there are usually a number of factors involved which cannot be accurately evaluated. A successful mine ventilation engineer uses about fifty percent common sense in solving the problems he is faced with. In addition he uses about forty percent basic knowledge and perhaps ten percent specialised knowledge W. L. Le Roux Mine Ventilation for Beginners 3rd Edition 4 FUNDAMENTALS OF AIRFLOW The quantity of air that will flow through a system (duct, or mine workings) is dependent upon: - the difference in pressure at the start of the system and the end of the system, and - the size of the opening. Again consider the tyre. With the valve opened the air rushes out until the pressure stops (equalises). The more the valve is opened the faster the air escapes even though the pressure inside the tyre was the same to start with. However there are other factors that cause more or less air to flow. These being: - the roughness of the wall and, - the severity and number of times the air has to change direction. Once something begins to move and the energy remains constant it continues to move at the same velocity. However if the surface roughness changes it becomes difficult to continue at the same velocity and more energy is required to maintain the velocity. The losses in energy due to the roughness of the wall are termed frictional pressure losses. When something is moving in a straight line at a constant velocity, energy is required to change the velocity or direction. These changes occur whenever the airway in which it is flowing changes direction, shape or size. The losses in energy due to a change in direction of the airflow are termed shock pressure losses. In a mine there is a constant conversion of energy from potential (static pressure) to kinetic (velocity pressure) and the energy source must be maintained to ensure that the air continues to flow. If the energy source is removed the flow will stop. Air as we know contains water (humidity) in various quantities. Although not strictly a fluid, there are some similarities. Lets now consider air as a fluid described as a substance, which deforms continuously when subjected to shear stress. To explain, assume the fluid consists of layers parallel to each other and a force is applied, in a direction parallel to its plane. This force divided by the area of the layer is called shear stress and as long as it is applied, the fluid will flow relative to the other layers. BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 59 © AMC Consultants Pty Ltd 2005 4.1.1 Laminar Flow At low fluid velocities the streamlines of flow are almost parallel to each other. The shear resistance between these streamlines is caused by friction between the layers moving at different velocities. If there is no resistance to movement, the fluid is called frictionless or ideal. If the shear movement is resisted then the fluid is called real. In reality ideal fluids do not exist, however in some cases the resistance is small enough to be insignificant. 4.1.2 Turbulent Flow As the velocity is increased, the streamlines become randomly arranged and the flow becomes turbulent with the additional eddy currents adding to the shear resistance. 4.2 Airflow Equation Investigations undertaken in the 1800s recognised that if there is no pressure difference between the start and end of an airway, there will be no flow of air; i.e. if the pressure was equal to zero, then the quantity of air flowing was also equal to zero. They also recognised that as the pressure was increased then the airflow quantity also increased i.e. the pressure is proportional to the quantity of airflow. This relationship was termed the resistance of the system and was expressed as Q P R = Where R = Resistance (Ns 2 /m 8 ) P = Pressure (Pa) Q = Quantity of airflow (m 3 ) This held true whilst the airflow was laminar however, it did not hold true for turbulent airflow and it was noted that in fully turbulent flows that to double the quantity of air flowing then a pressure four times the original was required. Similarly, to increase the quantity three-fold, the pressure required was nine times the original pressure. In other words, the pressure required increases as the square of the quantity 11 (i.e. Pressure is proportional to the quantity squared). This relationship has since been called the Ventilation Equation. 2 RQ P = Equation 11 Ventilation Equation There can be speculation that, when air flows at low velocity through a worked-out area, or where low velocity leakage occurs, the flow pattern is streamlined (laminar) and therefore the 11 Numerous investigations showed that the index actually lies in the range 1.8 to 2.2 for underground mines and approaching 1 in large voids where the airflow becomes laminar. In the vast majority of cases the use of 2 is accepted as the standard. BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 60 © AMC Consultants Pty Ltd 2005 formula relating P, R and Q should revert to P = RQ. Although this is true, in reality the pressure differentials are small enough to be inconsequential and it is generally accepted in mine ventilation that all flows are turbulent and this relationship is seldom, if ever, used. Example Calculate the pressure loss when 4 m 3 /s of air flows through a duct having a resistance of 9.3 Ns 2 /m 8 From the ventilation equation P = R Q 2 = 9.3 x 4 2 = 149 Pa Example Calculate the pressure loss when 8 m 3 /s of air flows through the same duct. From the ventilation equation P = R Q 2 = 9.3 x 8 2 = 595 Pa You should note that in the second example the quantity flowing is double that flowing in the first example and that the pressure required for this increased flow is four times that required in the first case. 4.3 Resistance (The friction factor). In around 1850 Atkinson hypothesised that the value of R was dependant upon on certain characteristics of the airway or duct. For example, if one airway has a small cross sectional area and another a large cross sectional area, and all other factors (P and Q) remain constant, air will flow more easily through the second airway. In other words, the larger the cross sectional area (A) of the airway, the lower the resistance (R) of the airway. Most of the early work on fluid flow was undertaken on the assumption of circular pipes and showed that the drag force (resistance = R) of a pipe depends on the flow velocity (v), the density of the fluid (µ) and the cross sectional area (A) of the pipe. We can therefore say that R = f(v, µ, A) where f is some function of the variables. By substituting C 1 for f and completing a dimensional analysis the equation for this relationship can be written as R = C 1 v 2 µA and would assume C 1 as a constant. Measurements on different pipes and various velocities would show that C 1 is NOT constant and there was a fourth variable, i.e. the viscosity (µ) of the fluid and the relationship for R is rewritten as R = f(v, µ, A, µ). Since there are four unknowns it is not possible to obtain a unique solution. By analysis 12 and substitution the equation is written as | | . | \ | µ µ = µ Dv f v D R 1 2 2 or | | . | \ | µ µ = µ Dv v D R 2 2 . The non-dimensional group | | . | \ | µ 2 2 v D R is referred to as the force or Euler coefficient, denoted by C f and the group | | . | \ | µ µDv is referred to as Reynolds Number (R e ). 12 The dimensional analysis and solution is described in Environmental Engineering in South African Mines Chapter 1. (pp1-27) BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 61 © AMC Consultants Pty Ltd 2005 However in addition to Reynolds Number the surface roughness also influences the resistance force. The surface roughness (e) also has a relationship to the area or as above to the diameter (D), and this is described as the relative roughness and defined as D e = c . Further evaluation and relating to Bernoullis Equation 13 ( ( ¸ ( ¸ µ + µ + = µ + µ + 2 2 2 2 1 2 1 1 H g 2 V P H g 2 v P it is shown that 2 2 1 v P k µ = and k is described as the friction component and expressed as D L v P 2 2 1 µ = ì where P is the static pressure loss due to wall friction in a parallel duct diameter D and length L. It is also possible to equate this to rectangular ducts if the diameter (D) is replaced with the equivalent hydraulic diameter D h C A 4 D h = Equation 12 Hydraulic Diameter Where D h = Hydraulic diameter (m) A = Cross sectional Area of Airway (m 2 ) C = Circumference of Airway (m) The equation for friction can now be rewritten as | | . | \ | | | . | \ | µ = ì h 2 D L 2 v P A more complete analysis will show that the friction coefficient is a function of Reynolds Number (R e ), relative roughness (c) and duct shape (s) where Reynolds Number =R e = | | . | \ | µ µDv Surface roughness = D e = c and s = the shape factor of the duct cross section. Experiments showed that the shape factor (s) had very little influence and the non-dimensional parameters had a major influence. After further studies and experimental work on smooth and rough walled ducts. The equation for the actual relationship shown in this test work can be represented by | | . | \ | ì + c ÷ = ì Re 7 . 18 2 log 2 74 . 1 1 Equation 13 Friction Factor Where 13 Bernoullis Equation : Law of Conservation of Momentum is not discussed in these notes but can be found in many texts dealing with fluid flow. BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 62 © AMC Consultants Pty Ltd 2005 h D e = c = Relative roughness e = Average height of surface irregularities or surface roughness (assume 0.35 m for rock wall, 0.02 m for raisebored) D h = Hydraulic Diameter (m) And µ µ = Dv Re µ = Density (kg/m3) µ = Viscosity (kg/ms) D h = Hydraulic Diameter (m) V = Velocity (m/s) In mine ventilation the term ì is usually replaced by k known as the coefficient of friction or Atkinsons k Factor. 4.3.1 Atkinsons Equation Atkinson also noted that if air has to rub against a larger area of surface in one airway than in another, the resistance will be higher in the airway with the largest rubbing surface. This rubbing surface is found by multiplying the perimeter (C) by the length (L). A kCLv P 2 = Equation 14 Atkinsons Ventilation Equation (Velocity) Where P = Pressure (Pa) k = Atkinsons Friction Factor with consideration to surface roughness. C = Circumference of the duct (m) L = Length of duct m) A = Cross sectional Area of the duct (m 2 ) v = Velocity of the fluid (m/s) If we substitute the physical values in the Atkinson equation 2 m N Pa is Pressure side hand Left = and the 2 2 2 2 2 s km m s m m m k A kCLv side hand Right = × × × = . Combining both sides 2 2 2 s km m N = therefore 4 2 m Ns k = Substituting the dimensions of force 2 s m kg N × = then 3 2 2 m kg 4 m s s m kg k = | | . | \ | × | . | \ | × = This is important because it shows that Atkinsons friction factor is not dimensionless and will vary according to the dimensions 3 m kg which is the same dimensions as density. Atkinson had BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 63 © AMC Consultants Pty Ltd 2005 ignored density effects deriving this equation and therefore is valid only for air with standard density. The use Atkinsons equation for any density it need to have a correction applied and it becomes S 2 A kCLv P µ µ × = Where µ = Density if air flowing in the duct (kg/m 3 ) µ S = Density of standard air (1.2 kg/m 3 ) The term S µ µ is in Atkinsons formula to allow for the fact that the pressure requirements depend on the density of the air. Obviously, more pressure will be required to pass heavier (denser) air through a system than the lighter air. In fact, the pressure (P) required is directly proportional to the air density (µ). More often than not it is convenient to express Atkinsons equation in terms of quantity of air rather than velocity and since V = QA this equation is rewritten as; S 3 2 ȡ ȡ A kCLQ P × = Equation 15 Atkinsons Ventilation Equation (Quantity) Where P = Pressure (Pa) K = Atkinsons Friction Factor (Ns 2 /m 4 ) C = Circumference of Airway (m) L = Length of Airway m) A = Cross sectional Area of Airway (m 2 ) Q = Quantity of airflow (m 3 /s) µ = Density if air flowing in the duct (kg/m 3 ) µ S = Density of standard air (1.2 kg/m 3 ) The values of k are determined from measurement and calculation. The values below are sighted in texts, and generally hold up to scrutiny. Some mines may find differing results outside of these values. In practice all mine should measure and determine their specific factor(s) because there will always be more than one factor that could be used. Some Typical Values for Atkinsons Friction Factor (k) at Standard air density Airway Type. k factor (Ns 2 /m 4 ) Smooth pipe 0.0028 Normal rigid ducting 0.0030 to 0.0035 Flexible ducting 0.0030 to 0.0065 Concrete surfaced 0.0035 to 0.0040 Rock surfaced 0.0070 to 0.0200 Raise bored 0.0035 to 0.0050 Timbered Airway 0.0400 to 0.0600 Timbered rectangular Shaft 0.0400 to 0.1000 BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 64 © AMC Consultants Pty Ltd 2005 Example Calculate the pressure required to overcome friction with an airflow of 60 m 3 /s in a 5.O m x 4.0 m haulage drive that is 450 m long and has a friction factor (k) of 0.016 Ns 2 /m 4 . Air density in the haulage is 1.1 kg/m 3 . Given that k = 0.016 Ns 2 /m 4 L = 450 m µ = 1.1 kg/m 3 Q = 60 m 3 /s C = 2(5 + 4) = 18 m A = (5.0 x 4.0) = 20.0 m 2 From Atkinsons equation S 3 2 ȡ ȡ A kCLQ P × = ( ) 2 . 1 1 . 1 0 . 20 60 450 0 . 18 16 . 0 3 2 × × × × = = 53.5 Pa Therefore, the pressure required to overcome the friction in this drive is 54 Pa 4.4 Shock Losses Shock losses are the change in total pressure across all airway elements such as the entrance to a system, a bend, junction, obstruction, change in section and exit from the system. In short shock losses are the result of flow separation that occurs whenever the airflow changes direction. The pressure losses resulting from a change in direction can be determined from the Shock Loss Equation VP X P SHOCK × = Where P SHOCK = Pressure loss due to shock (Pa) X = Dimensionless shock loss factor similar to Atkinsons friction factor and is constant only for a given set of conditions depending upon shape, dimensions and characteristics. (See below) VP = Velocity Pressure of the air (Pa) And 2 v VP 2 × µ = Where µ = Density of the air (kg/m 3 ) v = Velocity of the air (m/s) The shock loss factor X is a function of the: 1. Configuration and flow through the element. 2. Angle of the change in direction, BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 65 © AMC Consultants Pty Ltd 2005 3. Degree the abruptness of the change, 4. Radius of curvature, 5. Ratio of the radius to width of the airway 6. Aspect ratio between the height and width, 7. Velocity in the airway 8. Airway roughness 9. Shape of the airway 10. Airways immediately before and immediately after the change in direction, 11. The number and type of complex elements i.e. two bends, bend followed by an expansion The large number of variables that contribute to shock losses causes the calculation of these losses is extremely complicated and seldom necessary in mine ventilation because of their small magnitude and the inaccuracy of the X value. WARNING- If airflow and pressure surveys have been used to determine the resistance of any part of the mine workings these measurements will include the losses due to shock and any use of additional factors will cause undetectable errors in the results. Shock losses are generally over used in computer ventilation modelling and the calculation methods shown below are approximations of the actual number taken from published texts 14 and suitable for use in most computer ventilation models. Wherever possible ventilation practitioners should determine these values by direct measurement. 14 Fan Engineering Eight Edition Published by Buffalo Forge Company. Buffalo, New York USA (1983) & DALY, B.B. Woods Practical Guide to Fan Engineering Published by Woods of Colchester Limited UK (1978) BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 66 © AMC Consultants Pty Ltd 2005 4.4.1 Entrance Shock losses occur at the entrance to any system due to the acceleration of air from zero velocity in the surrounding atmosphere to the velocity in the airway. 4.4.2 Outlet Losses Air exiting a system decelerates from the airway velocity to zero velocity in the atmosphere. The static pressure in the issuing air stream will be equal to the surrounding atmospheric pressure. If this is taken as a zero gauge pressure then the total pressure at the exit will be equal to the velocity pressure. To reduce this loss, the area of the outlet must be increased (ie the velocity is decreased) this is normally achieved with the use of a diffuser or evasè. The performance of a diffuser will vary with the inlet velocity pressure and the ratio of the outlet to inlet area, the centreline length and the angle of divergence. In an ideal diffuser the regain pressure would be equal to the change in velocity pressure and the loss in total pressure (shock loss) would be zero. In reality this will never occur. A well-designed diffuser would have an outlet to inlet area ratio of 4:1 with an included angle of divergence between 8° and 11°. In practice the length required to regain pressure is excessive and generally the divergence angle is around 25°. As a rule of thumb if the length of the divergence is four times the diameter of the smaller airway, then the shock losses become negligible because the pressure regain of shock loss pressures are overcome by the frictional pressure losses. Entrance Notched X = 0.05 Note that the Notched entry approximates the Bell Mouth and apparently the vortex formed in the notch promotes a smooth flow into the airway. Bell Mouth X = 0.05 Plain X = 0.9 Conical X = 0.2 Flanged X = 0.5 Entrance Notched X = 0.05 Note that the Notched entry approximates the Bell Mouth and apparently the vortex formed in the notch promotes a smooth flow into the airway. Bell Mouth X = 0.05 Entrance Notched X = 0.05 Notched X = 0.05 Note that the Notched entry approximates the Bell Mouth and apparently the vortex formed in the notch promotes a smooth flow into the airway. Bell Mouth X = 0.05 Bell Mouth X = 0.05 Plain X = 0.9 Conical X = 0.2 Flanged X = 0.5 Plain X = 0.9 Plain X = 0.9 Conical X = 0.2 Conical X = 0.2 Flanged X = 0.5 Flanged X = 0.5 Plain Flanged Diffused Outlets In all cases X = 1.0 and the velocity pressure is determined by the velocity in the plane of the exit area Plain Flanged Diffused Outlets In all cases X = 1.0 and the velocity pressure is determined by the velocity in the plane of the exit area Outlets In all cases X = 1.0 and the velocity pressure is determined by the velocity in the plane of the exit area BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 67 © AMC Consultants Pty Ltd 2005 4.4.3 Elbows Elbows, bends and mitres are used to guide the change in direction of flow and restrict flow separation. The relative losses will depend upon the abruptness of the change in direction, Reynolds number (not discussed in these notes) and the wall roughness of the airway. Other considerations include geometrical shape i.e. circular or round, the angle of the bend and the radius ratio and the aspect ratio. Those of most importance in mines are mitre bends with curved bends having a lesser impact due primarily to their lengths such that shock losses are decreased to a point of insignificance compared to the frictional pressure losses. Consider the case of a typical mine curve of radius 20 metres with a height of 4.5 metres and a width of 4.5 metres with a friction factor k of 0.015 Ns 2 m -4 . The angle of the curve is 90° and the airflow is 200 m 3 /s The calculation for X in a smooth bend is described by McElroy (1935) 2 5 . 0 2 90 a m 60 . 0 X | . | \ | u × × = Where m is the radius ratio = Centre line radius Width of the Airway = 4.5 2 = 2.25 a is the aspect ratio = Height of the Airway Width of the Airway = 4.5 4.5 = 1.0 Therefore 2 5 . 0 2 90 90 0 . 1 25 . 2 6 . 0 X | . | \ | × × = = 1.2 The velocity is 200/(4.5 x 4.5) = 9.87 (m/s) Therefore P SHOCK = 1.2 x (0.5 x 1.2 x 9.87 2 ) = 70Pa Smooth Bend X = 0.25 x u 2 m 2 a 0.5 90 2 X = 1.15 Rectangular Mitre Bend X = 1.15 Circular Mitre Bend Mitre Bend other than 90 0 X u = X 90 x u 90 u 0.315 1.5 0.350 1.0 0.425 0.5 0.380 0.325 0.315 X 3.0 2.5 2.0 R/D R D Three Piece Bend 90 0 Smooth Bend X = 0.25 x u 2 m 2 a 0.5 90 2 Smooth Bend X = 0.25 x u 2 m 2 a 0.5 90 2 X = 1.15 Rectangular Mitre Bend X = 1.15 Rectangular Mitre Bend X = 1.15 Circular Mitre Bend X = 1.15 Circular Mitre Bend Mitre Bend other than 90 0 X u = X 90 x u 90 u 0.315 1.5 0.350 1.0 0.425 0.5 0.380 0.325 0.315 X 3.0 2.5 2.0 R/D R D Three Piece Bend 90 0 BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 68 © AMC Consultants Pty Ltd 2005 4.4.4 Expansions and Contractions 4.4.5 Junctions and Splitting These losses depend upon 1. the geometrical aspect of each airway, 2. the branching angle, 3. the branch area ratio, 4. the ratio of the downstream to upstream velocity of air and therefore the quantity of airflow. Gradual Contraction A 2 A 1 Note: If the length of contraction is 4 x the smaller diameter then the shock losses are negligible X = 0.333 [ 1 (A 2 / A 1 )] A 2 Abrupt Contraction X = 0.5 [ 1 (A2 / A1 )] A 1 Abrupt Expansion A 1 X = ( 1 [A1 / A2 ]) 2 A 2 Gradual Expansion A 2 A 1 Note: Expansions are complicated by the regain in static pressure over the length of the change. To keep expansion losses to a minimum the change should take place over the longest available distance and the downstream duct must be at least 4 times the larger diameter to ensure full recovery of the pressure. Gradual Contraction A 2 A 1 Note: If the length of contraction is 4 x the smaller diameter then the shock losses are negligible X = 0.333 [ 1 (A 2 / A 1 )] Gradual Contraction A 2 A 1 Note: If the length of contraction is 4 x the smaller diameter then the shock losses are negligible X = 0.333 [ 1 (A 2 / A 1 )] A 2 Abrupt Contraction X = 0.5 [ 1 (A2 / A1 )] A 1 A 2 Abrupt Contraction X = 0.5 [ 1 (A2 / A1 )] A 1 Abrupt Expansion A 1 X = ( 1 [A1 / A2 ]) 2 A 2 Abrupt Expansion A 1 X = ( 1 [A1 / A2 ]) 2 A 2 Gradual Expansion A 2 A 1 Note: Expansions are complicated by the regain in static pressure over the length of the change. To keep expansion losses to a minimum the change should take place over the longest available distance and the downstream duct must be at least 4 times the larger diameter to ensure full recovery of the pressure. Gradual Expansion A 2 A 1 Note: Expansions are complicated by the regain in static pressure over the length of the change. To keep expansion losses to a minimum the change should take place over the longest available distance and the downstream duct must be at least 4 times the larger diameter to ensure full recovery of the pressure. Deflected branch X = (0.5(Q / Q b ) 2 ) + ((Q / Q b )-1) 2 + X b Splitting u Straight Branch X = 0.5((Q / Q b )-1) 2 Deflected branch X = (0.5(Q / Q b ) 2 ) + ((Q / Q b )-1) 2 + X b Splitting u Straight Branch X = 0.5((Q / Q b )-1) 2 Deflected branch X = (-0.5 ((Q / Q b )-1) 2.5 ) + X b Junction u Straight Branch X = 3.3((tan u/2)0.67).(((Q/Q b ).((1/Cc)-1)) 2 Deflected branch X = (-0.5 ((Q / Q b )-1) 2.5 ) + X b Junction u Straight Branch X = 3.3((tan u/2)0.67).(((Q/Q b ).((1/Cc)-1)) 2 Ideal Junction u u = 30 0 & v1 = v 2 v1 v2 Ideal Junction u u = 30 0 & v1 = v 2 v1 v2 BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 69 © AMC Consultants Pty Ltd 2005 In the deflected branch of a split the pressure loss can be reduced considerably by using a converging taper between the main and the deflected branch. The recommended procedure for development of a junction is to join the upstream main branch with the down stream main by means of a tapered convergence of at least two upstream diameters long made to join the branch to the taper at an angle of 30° with the upstream main branch. The idea is to maintain a constant velocity in the main branch. Obviously this is fine for a duct system in a building but extremely difficult to achieve economically in an underground mine. One important aspect of junctions is that the pressure loss may in fact be negative depending of the ratio of the branch flow to the total flow. This is due to the transfer of momentum from one branch to the other. In the equations for splits and junctions the following applies: Q = Total Airflow Qb = Airflow in the branch being evaluated Xb = X for the deflected branch Cc = Coefficient of Contraction Ao Ac = And Ac = Area of vena contractor Ao = Area of orifice 4.5 Other Methods of Expressing the Shock Factor X Some attempt to increase the friction k as a method to allow for shock losses. This involves the addition of an increment to the friction factor k for each and every airway. The method is tedious and prone to error due to the many variables and is not really recommended for use. This method is inadvertently applied when the results of pressure quantity surveys are used to back calculate the friction factor k because the pressure losses due to shock are included in the measurements. Use of the equivalent-length method is probably the most useful method for mine ventilation because it can be calculated by equating the formulas for friction loss and shock loss. To differentiate between the actual length (L) the subscript e is added to indicate equivalent length k 67 . 6 Dh X Le × = where Dh is the hydraulic diameter of the airway. C A 4 Dh = . WARNING - Mine ventilation computer programmes may include preset values for shock losses. These values are expressed as an equivalent length (Le) of the airway. It is then used to calculate a resistance for the Le and is then added to the resistance of the airway. Some of these values have been taken from a text that used drive sizes of only 2.0m x 2.0m and therefore are not applicable to all mines. Shock losses do not lend themselves to precise calculation because of the great range of variability in occurrence and because of a lack of understanding of their very nature. 15 15 HARTMAN, H.L. Mine Ventilation and Air-conditioning BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 70 © AMC Consultants Pty Ltd 2005 4.6 Series Circuits When one airway is followed by another airway and both have their own physical characteristics, the airways are said to be in series. This becomes obvious when we refer to the sketch below where the total quantity of air flowing through the system is equal to the quantity of air in A, which is equal to the quantity of air flowing in B and likewise in airway C. i.e. Q T = Q A = Q B = Q C The total pressure loss in the system is the sum of the pressure losses in airway A, airway B and airway C. i.e. P T = P A + P B + P C It then follows that the total resistance of the system is the sum of the resistance of airway A and airway B and airway C. i.e. R T = R A + R B + R C This relationship is usually expressed as n ....R 2 R 1 R T R + + = Where R = Resistance (Ns 2 /m 8 ) Example Referring to the sketch above Airway A has a resistance of 0.10 (Ns 2 /m 8 ), Airway B a resistance of 0.07 (Ns 2 /m 8 ) and Airway C a resistance of 0.17 (Ns 2 /m 8 ). Calculate the pressure (P) required to cause a flow of 100 m 3 /s R T = R 1 + R 2 = 0.10 + 0.07 + 0.17 = 0.34 (Ns 2 /m 8 ) and P T = R T x Q T 2 = 0.34 x (100) 2 = 3400 (Pa) Many Australian mines utilise series ventilation circuits in their design. This is a term used to describe a combination of airways with different resistances where the air flows through each in turn. This is a common practice in steeply dipping narrow vein mines, where the air flows from the surface to the lowest working Airway B Airway C Airway A Airway B Airway C Airway A BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 71 © AMC Consultants Pty Ltd 2005 level before being exhausted from the mine. This reuse of air is often confused when people talk of recirculation of air when in fact they mean re-used (series) air. Recirculate implies that the airs goes around in circles and never leaves the circuit. 4.7 Parallel Airway Circuits Airways are in parallel when they have a common inlet and common outlet. In the sketch to the right the points X and Y are common to both airways. Therefore the pressure loss across airway A is equal to the pressure loss across airway B and equal to the pressure loss across the system X-Y i.e. P T = P A = P B X X Airway B Y Y Airway A Common points X X Airway B Y Y Airway A Common points The total quantity flowing in the system is equal to the quantity of air flowing in airway A and airway B. i.e. Q T = Q A + Q B and the overall resistance (R T ) is given by the formula n 2 1 T R 1 .... R 1 R 1 R 1 + + = Where R = Resistance (Ns 2 /m 8 ) Parallel systems exist in mines when air is exhausted on a number of levels. BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 72 © AMC Consultants Pty Ltd 2005 EXAMPLE Three identical airways are developed in parallel. Each airway has a resistance of 0.15 (Ns 2 /m 8 ). Calculate the pressure required to cause a flow of 50 m 3 /s through each airway. Calculate the total airflow Q T = Q A + Q B + Q C Q T = 50 + 50 + 50 = 150 m 3 /s. Calculate the overall resistance (R T ) C B A T R 1 R 1 R 1 R 1 + + = 15 . 0 1 15 . 0 1 1 R 1 15 . 0 T + + = = 0.0167 (Ns 2 /m 4 ) Calculate the pressure P T = R T x Q T 2 = 0.0167 x 150 2 = 375 Pa 4.8 Complex Circuit (Networks) With reference to the sketch for parallel airways it is noted that whilst Airway A and Airway B are in parallel they are also in series with the airway preceding point X and the airway following point Y. Lets now consider the same sketch a new airway that connects Airway A with Airway B. Airway B Airway A New airway Airway B Airway A New airway After examining this sketch you will come to the conclusion It is not possible to reduce this circuit to a series or parallel circuit and an analytical or reiterative technique is required. Complex circuits or networks rely on the use of computers to undertake the numerous calculations required. In order to understand the complexity of network problems the following definitions apply 1. A network is any complex ventilation circuit. 2. A Junction is where two or more airways join 3. A branch is any airway between two junctions 4. A mesh is any closed path that traverses the network. Every airway must be included once in any group of meshes. BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 73 © AMC Consultants Pty Ltd 2005 5. Kirchoffs electrical laws can be restated and will apply. Kirchoffs 1 st Law The algebraic sum of all air quantities at a junction is zero Kirchoffs 2 nd Law The algebraic sum of all pressure losses in a closed mesh is zero. However if a fan is included in the mesh then the algebraic sum of all pressure losses is equal to the pressure provided by the fan. Comprehensive discussion of Network analysis can be found in Chapter 8 of Environmental Engineering in South African Mines. 4.9 System Resistance Curve We have seen and discussed the relationship of pressure (P), quantity (Q) and resistance (R) in the previous sections. For example the ventilation equation ( 2 RQ P = ) shows the relationship between pressure (P) and quantity (Q) is proportional i.e. R Q P 2 = where R was the resistance for a particular system with a specific pressure and quantity. The system) resistance in any duct or mine, is determined by summation of all the appropriate resistance values. Once this calculation is complete we can determine the pressure necessary to cause various quantities of air to flow. . The results of these calculations are then shown graphically to produce the System Resistance Characteristic. A system with a high resistance will be represented by a curve that is steeper than a system with a lower resistance. High Resistance Low Resistance P r e s s u r e Quantity 0 BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 74 © AMC Consultants Pty Ltd 2005 4.10 Assignments 4.10.1 [Q] Calculate the pressure loss in 250 m of a rigid plastic duct with diameter of 1,200 mm & 1,400 mm for air quantities of 15 m 3 /s & 25 m 3 /s. State the k factors used and assume the density of air is 1.2 kg/m 3 . 4.10.1 [A] Equations used: 1) s 3 2 ȡ ȡ × A kCLQ = P 2) ) (m 4 ʌD A 2 2 = 3) (m) D ʌ = C Determine area (A) and circumference (C) for ducts Diameter (mm) C (m) A (m 3 ) 1,200 3.7699 1.1310 1,400 4.3982 1.5394 Calculate pressure assuming k = 0.0035 s 3 2 ȡ ȡ × A kCLQ = P 1,200 Diameter 2 . 1 2 . 1 × 1310 . 1 15 × 250 × 7699 . 3 × 0035 . 0 = P 3 2 = 513 Pa 1,200 Diameter 2 . 1 2 . 1 × 1310 . 1 25 × 250 × 7699 . 3 × 0035 . 0 = P 3 2 = 1425 Pa 1,400 Diameter 2 . 1 2 . 1 × 5394 . 1 15 × 250 × 3982 . 4 × 0035 . 0 = P 3 2 = 237 Pa 1,400 Diameter 2 . 1 2 . 1 × 5394 . 1 25 × 250 × 3982 . 4 × 0035 . 0 = P 3 2 = 659 Pa 4.10.2 [Q] Repeat 4.10.1 but assume an air density of 1.15 kg/m 3 and 1.25 kg/m 3 4.10.2 [A] 1,200 Diameter 2 . 1 15 . 1 × 1310 . 1 15 × 250 × 7699 . 3 × 0035 . 0 = P 3 2 = 492 Pa 1,200 Diameter 2 . 1 15 . 1 × 1310 . 1 25 × 250 × 7699 . 3 × 0035 . 0 = P 3 2 = 1365 Pa 1,400 Diameter 2 . 1 15 . 1 × 5394 . 1 15 × 250 × 3982 . 4 × 0035 . 0 = P 3 2 = 227 Pa 1,400 Diameter 2 . 1 15 . 1 × 5394 . 1 25 × 250 × 3982 . 4 × 0035 . 0 = P 3 2 = 632 Pa 1,200 Diameter 2 . 1 25 . 1 × 1310 . 1 15 × 250 × 7699 . 3 × 0035 . 0 = P 3 2 = 534 Pa BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 75 © AMC Consultants Pty Ltd 2005 1,200 Diameter 2 . 1 25 . 1 × 1310 . 1 25 × 250 × 7699 . 3 × 0035 . 0 = P 3 2 = 1484 Pa 1,400 Diameter 2 . 1 25 . 1 × 5394 . 1 15 × 250 × 3982 . 4 × 0035 . 0 = P 3 2 = 247 Pa 1,400 Diameter 2 . 1 25 . 1 × 5394 . 1 25 × 250 × 3982 . 4 × 0035 . 0 = P 3 2 = 686 Pa 4.10.3 [Q] Repeat 4.10.1 using flexible ducting. 4.10.3 [A] Calculate pressure assuming k = 0.0065 s 3 2 ȡ ȡ × A kCLQ = P 1,200 Diameter 2 . 1 2 . 1 × 1310 . 1 15 × 250 × 7699 . 3 × 0065 . 0 = P 3 2 = 953 Pa 1,200 Diameter 2 . 1 2 . 1 × 1310 . 1 25 × 250 × 7699 . 3 × 0065 . 0 = P 3 2 = 2647 Pa 1,400 Diameter 2 . 1 2 . 1 × 5394 . 1 15 × 250 × 3982 . 4 × 0065 . 0 = P 3 2 = 441 Pa 1,400 Diameter 2 . 1 2 . 1 × 5394 . 1 25 × 250 × 3982 . 4 × 0065 . 0 = P 3 2 = 1225 Pa 4.10.4 [Q] Calculate the pressure loss for air quantities of 13.5 m 3 /s, 55 m 3 /s & 165 m 3 /s in a decline 350 m long 5.5m high and 5.0m wide. State the k factor used and assume the density of air is 1.2 kg/m 3 . 4.10.4 [A] Determine area (A) and circumference (C) for drive Height (m) Width (m) C (m) A (m 3 ) 5.5 5.0 21.0 27.5 Calculate pressure assuming k = 0.012 s 3 2 ȡ ȡ × A kCLQ = P 2 . 1 2 . 1 × 5 . 27 5 . 13 × 350 × 0 . 21 × 012 . 0 = P 3 2 = 0.7 Pa 2 . 1 2 . 1 × 5 . 27 55 × 350 × 0 . 21 × 012 . 0 = P 3 2 = 12.8 Pa BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 76 © AMC Consultants Pty Ltd 2005 2 . 1 2 . 1 × 5 . 27 165 × 350 × 0 . 21 × 012 . 0 = P 3 2 = 115 Pa 4.10.5 [Q] Calculate the velocity (m/s) and pressure loss (Pa) for air quantities of 60 m 3 /s, 125 m 3 /s, 190 m 3 /s & 250 m 3 /s in a vertical raisebored shaft 350 m long and 4.0m diameter. State your assumptions. 4.10.5 [A] Assumptions: K Factor = 0.0045 Ns 2 /m 4 Density of air 1.2 kg/m 3 Determine area (A) and circumference (C) for raisebored shaft Diameter (m) C (m) A (m 3 ) 4.0 12.5664 12.5664 Calculate velocity A Q = v 5664 . 12 60 = v = 4.8 m/s 5664 . 12 125 = v = 9.9 m/s 5664 . 12 190 = v = 15.1 m/s 5664 . 12 250 = v = 19.9 m/s Calculate pressure: s 3 2 ȡ ȡ × A kCLQ = P 2 . 1 2 . 1 × 5664 . 12 60 × 350 × 5664 . 12 × 0045 . 0 = P 3 2 = 36 Pa 2 . 1 2 . 1 × 5664 . 12 125 × 350 × 5664 . 12 × 0045 . 0 = P 3 2 = 156 Pa 2 . 1 2 . 1 × 5664 . 12 190 × 350 × 5664 . 12 × 0045 . 0 = P 3 2 = 360 Pa 2 . 1 2 . 1 × 5664 . 12 250 × 350 × 5664 . 12 × 0045 . 0 = P 3 2 = 623 Pa 4.10.6 [Q] Determine the pressure losses contributed by the shock in a 90° bend of a blasted rock airway 5.0m high and 5.0m wide for air quantities of 20 m 3 /s, 75m 3 /s 125 m 3 /s. Assume standard air density. 4.10.5 [A] Shock factor X for 90° rectangular bend = 1.15 Determine area of drive = h x w = 5 x 5 = 25.0 m 2 BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 77 © AMC Consultants Pty Ltd 2005 Calculate velocity in drive: A Q = v 0 . 25 20 = v = 0.8 m/s 0 . 25 75 = v = 3.0 m/s 0 . 25 125 = v = 5.0 m/s Calculate velocity pressure (Pa) 2 2 v ȡ = VP 2 2 8 . 0 × 2 . 1 = VP = 0.4 Pa 2 2 0 . 3 × 2 . 1 = VP = 5.4 Pa 2 2 0 . 5 × 2 . 1 = VP = 15.0 Pa Calculate shock loss XVP = P SHOCK 4 . 0 × 15 . 1 = P SHOCK = 0.46 Pa 4 . 5 × 15 . 1 = P SHOCK = 6.2 Pa 15 × 15 . 1 = P SHOCK = 17.25 Pa 4.10.7 [Q] Determine the pressure losses contributed by the shock in a 90° smooth bend with a centre line radius of 15 m in a 1.2m diameter flexible duct with an air quantity of m 3 /s. Assume standard air density. 4.10.7 [A] Shock factor X for 90° circular bend = 2 2 5 . 0 2 90 ș × a m 25 . 0 = X 2 . 1 20 = m = 16.6667 2 . 1 2 . 1 = a = 1 2 2 5 . 0 2 90 90 × 1 6667 . 16 25 . 0 = X = 0.0009 Determine area of duct = 2 r ʌ = 2 6 . 0 × ʌ = 1.1310 m 2 Calculate velocity in drive: A Q = v 1310 . 1 30 = v = 26.5 m/s BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 78 © AMC Consultants Pty Ltd 2005 Calculate velocity pressure (Pa) 2 2 v ȡ = VP 2 2 5 . 26 × 2 . 1 = VP = 422 Pa Calculate shock loss XVP = P SHOCK 422 × 0009 . 0 = P SHOCK = 0.38 Pa 4.10.8 [Q] Determine the equivalent airway length of shock losses in a 90° bend in a blasted rock airway 5.0m high and 5.0m wide for velocities of 1.0 m/s, 2.5 m/s, 5.0 m/s, 7.5m/s & 10.0 m/s. Assume standard air density 4.10.8 [A] k 67 . 6 XD = Le h 012 . 0 × 67 . 6 5 × 15 . 1 = Le 71.8m and will be the same irrespective of flow. 4.10.9 [Q] Determine the pressure loss when an airway reduces abruptly in size from 6.0m high and 6.0m wide to an airway 3.0m high and 3.0m wide for air quantities of 10 m 3 /s, 50 m 3 /s & 100 m 3 /s. Assume standard air density. 4.10.9 [A] Abrupt Contraction X= 0.5 (1- (A 2 /A 1 )) A 1 = 6 x 6 = 36 m 2 A 2 = 3 x 3 = 9 m 2 X = 0.5 (1 (9/36) = 0.5 (1 - 0.25) = 0.375 Pressure loss occurs in the entry airway Velocity in A 1 = 36 10 = 0.2778 m/s and 2 2 2778 . 0 × 2 . 1 = VP = 0.0463 Pa Therefore 0463 . 0 × 375 . 0 = P SHOCK Pa Velocity in A 1 = 36 50 = 1.3889 m/s and 2 2 3889 . 1 × 2 . 1 = VP = 1.1574 Pa Therefore 1574 . 1 × 375 . 0 = P SHOCK = 0.4340 Pa Velocity in A 1 = 36 100 = 2.7778 m/s and 2 2 7778 . 2 × 2 . 1 = VP = 4.6296 Pa Therefore 6296 . 4 × 375 . 0 = P SHOCK = 1.7361 Pa 4.10.10 [Q] Determine the pressure loss when an airway increases abruptly in size from 6.0m high and 6.0m wide to an airway 3.0m high and 3.0m wide for air quantities of 10 m 3 /s, 50 m 3 /s & 100 m 3 /s. Assume standard air density. 4.10.10 [A] Abrupt Expansion X= (1- (A 1 /A 2 )) 2 A 1 = 3 x 3 = 9 m 2 A 2 = 6 x 6 = 36 m 2 X = (1 (9/36)) 2 = (1 - 0.25) 2 = 0.5625 BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 79 © AMC Consultants Pty Ltd 2005 Pressure loss occurs in the entry airway Velocity in A 1 = 9 10 = 1.1111 m/s and 2 2 1111 . 1 × 2 . 1 = VP = 0.7407 Pa Therefore 7407 . 0 × 5625 . 0 = P SHOCK = 0.4167 Pa Velocity in A 1 = 9 50 = 5.5556 m/s and 2 2 5556 . 5 × 2 . 1 = VP = 18.5185 Pa Therefore 5185 . 18 × 5625 . 0 = P SHOCK = 10.4167 Pa Velocity in A 1 = 9 100 = 11.1111 m/s and 2 2 1111 . 11 × 2 . 1 = VP = 74.0739 Pa Therefore 0739 . 74 × 5625 . 0 = P SHOCK = 41.6666 Pa 4.10.11 [Q] Calculate the frictional pressure loss for the following systems. State your assumptions for Atkinsons factors. Assume standard air density. i) Airflow 30 m 3 /s Airway A 50m long, 5.5m high x 5.0m wide Airway B 100m long, 4.5m high x 4.0m wide Airway C 25m long, 4.0m high x 4.0m wide ii) Airflow 100 m 3 /s Airway A Decline 750m long, 5.5m high x 5.0m wide Airway B Level Development 200m long, 4.5m high x 4.0m wide Airway C Raisebore shaft 125m long, 4.0m diameter 4.10.11 [A] 1) Assume friction factor 0.012 Ns 2 /m 4 for rock walled air way Determine the resistance for each airway. 3 A kCL = R Ns 2 /m 8 Airway A Area = 27.5 m 2 Circumference = 21 m and 3 A 5 . 27 50 × 21 × 012 . 0 = R = 0.0006 Ns 2 /m 8 Airway B Area = 18 m 2 Circumference = 17 m and 3 B 18 100 × 17 × 012 . 0 = R = 0.0035 Ns 2 /m 8 Airway C Area = 16 m 2 Circumference = 16 m and 3 A 16 25 × 16 × 012 . 0 = R = 0.0012 A B C A B C A B C BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 80 © AMC Consultants Pty Ltd 2005 Ns 2 /m 8 R T = R A +R B +R C = 0.0006 + 0.0035 + 0.0012 = 0.0053 Ns 2 /m 8 Calculate frictional pressure loss P = RQ 2 = 0.0053 x 30 2 = 5 Pa 2) Assume friction factor 0.012 Ns 2 /m 4 for rock walled air way and 0.0045 Ns 2 /m 4 for raise bored airway Determine the resistance for each airway. 3 A kCL = R Ns 2 /m 8 Airway A Area = 27.5 m 2 Circumference = 21 m and 3 A 5 . 27 750 × 21 × 012 . 0 = R = 0.0091 Ns 2 /m 8 Airway B Area = 18 m 2 Circumference = 17 m and 3 B 18 200 × 17 × 012 . 0 = R = 0.0070 Ns 2 /m 8 Airway C Area = 12.56 m 2 Circumference = 12.56 m and 3 A 56 . 12 125 × 56 . 12 × 0045 . 0 = R = 0.0036 Ns 2 /m 8 R T = R A +R B +R C = 0.0091 + 0.0070 + 0.0036 = 0.0197 Ns 2 /m 8 Calculate frictional pressure loss P = RQ 2 = 0.0197 x 100 2 = 197 Pa 4.10.12 [Q] Two sections of a mine are depicted in the following figure 1. Determine the airflow through each section of the mine 2. Calculate the pressure drop necessary to achieve 100m 3 /s. 4.10.12 [A] Section 1 is in parallel with section two and the pressure is the same across both sections of the mine. Calculate the resistance 2 SECTION 1 N SECTIO T R 1 + R 1 = R 1 100 m 3 /s 0.3 Ns 2 /m 8 0.1 Ns 2 /m 8 Section 1 Section 2 100 m 3 /s 0.3 Ns 2 /m 8 0.1 Ns 2 /m 8 Section 1 Section 2 BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 81 © AMC Consultants Pty Ltd 2005 1 . 0 1 + 3 . 0 1 = R 1 T = 1.8257 + 3.1623 =4.9880 R T = 2 9880 . 4 1 = 0.0402 Ns 2 /m 8 As 2 RQ = P and since P is constant R T Q T 2 = R 1 Q 1 2 The airflow in Section 1 0.0402 x 100 2 = 0.3 x Q 1 2 2 2 1 100 × 3 . 0 0402 . 0 = Q =1,3387.75 75 . 13387 = Q 1 = 36.6 m 3 /s Similarly the airflow in Section 2 is 0.0402 x 100 2 = 0.1 x Q 1 2 Q 2 = 63.4 m 3 /s. Pressure is P = RQ 2 = 0.0402 x 100 2 = 402 Pa 4.10.13 [Q] The raise bored airway for a mine has become unstable and must be sprayed with shotcrete to prevent it collapsing. The shaft is 3.2m diameter and 200 m in length. The concrete will be applied to a thickness of 100mm. The current airflow is 90 m 3 /s. What will the airflow be once the shotecreting has been completed?. Assume the same pressure drop. 4.10.13 [A] Determine the existing resistance. 3 A kCL = R Ns 2 /m 8 Diameter = 3.2m 3 04 . 8 200 × 05 . 10 × 0045 . 0 = R = 0.0174 Ns 2 /m 8 Determine the new resistance. 3 A kCL = R Ns 2 /m 8 Diameter = 3.2 (2 x 0.100) = 3.0m 3 07 . 7 200 × 42 . 9 × 0045 . 0 = R = 0.0240 Ns 2 /m 8 Since pressure is constant R 1 Q 1 2 = R 2 Q 2 2 2 2 2 90 × 0240 . 0 0174 . 0 = Q 5 . 5872 = Q 2 = 76.6 m 3 /s 4.10.14 [Q] The figure below represents the workings of an underground mine. BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 82 © AMC Consultants Pty Ltd 2005 It is proposed to develop a new shaft (FE) and increase the mine airflow from 125 m 3 /s up to 240 m 3 /s. It is also necessary to provide equal air to each section of the mine. What diameter should the new shaft be? Assume the new shaft can be raisebored. 4.10.14 [A] Determine the resistance of the decline. 3 A kCL = R Ns 2 /m 8 At 1:7 the decline will be 200 x 7 = 1,400 m long Area = 25 m 2 an Circumference = 20 m. Assume a friction factor of the decline = 0.012 Ns 2 /m 4 3 AB 25 1400 × 20 × 012 . 0 = R = 0.0215 Ns 2 /m 8 Determine the resistance of A,B, Area 2,C R=0.0215 + 0.0100 = 0.0315 Ns 2 /m 8 For an equal split the resistance in both sections must be equal R AB Area 2 C = R FE Area 1 C Therefore R FE = R AB Area 2 C R Area 1 =0.0315 0.0150 = 0.0165 Ns 2 /m 8 Calculate the diameter Area = t 4 D ʌ = Area 2 and Circumference D ʌ = Substituting in 3 A kCL = R 3 2 4 D ʌ DL ʌ k R = Solving for D Decline 5m x 5m gradient 1:7 240 m 3 /s Area 1= 0.015 Ns 2 /m 8 Area 2 = 0.010 Ns 2 /m 8 Shaft 4.0m diam. 200m long Proposed Shaft A B C D F E 120 m 3 /s 120 m 3 /s Decline 5m x 5m gradient 1:7 240 m 3 /s Area 1= 0.015 Ns 2 /m 8 Area 2 = 0.010 Ns 2 /m 8 Shaft 4.0m diam. 200m long Proposed Shaft A B C D F E 120 m 3 /s 120 m 3 /s BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Page 83 © AMC Consultants Pty Ltd 2005 D =(4/R 1/3 t) 3/5 (ktL) 1/5 D =(4 / 0.0165 1/3 t) 3/5 (0.0045 t 200) 1/5 D = 3.2339m diameter BASIC MINE VENTILATION MEASURING AIRFLOW Page 84 © AMC Consultants Pty Ltd 2005 Reason, Observation and Experience the Holy Trinity of Science. Robert G. Ingersoll (1833-99) US Lawyer and Agnostic. The Gods. 5 MEASURING AIRFLOW Airflow is measured in units of cubic metres per second (m 3 /s). To measure airflow, the airway cross-sectional area and air velocity need to be known. There are a large variety of air velocity measuring instruments, however the following are most applicable to mining requirements: - Vane Anemometer - Hot Wire Anemometer - Velometer - Smoke Tube 5.1 Vane Anemometer The instrument consists simply of a light impeller that rotates at a speed dependent on flow rate. The impeller rotational speed is converted into an air velocity reading using either electronic or mechanical means. Most anemometers used in mine ventilation survey work are capable of measuring velocities in the range of 0.2 to 25 m/s, with an absolute accuracy of ± 0.5 m/s, or better. They are ideally suited to conducting primary ventilation surveys and for routine determination of air velocity. Air velocities below 0.2 m/s should be measured with another technique such as a smoke tube or hot wire anemometer. Mechanical anemometers (particularly the Lambrecht 1406a) are used in the majority of Australian mines. The mechanical instruments are preferred to the electronic ones for the following reasons: - They automatically engage their clutch to commence measurement about five seconds after the mechanical start lever is depressed. This gives the operator sufficient time to move the instrument away from the body to the position where the traverse will be commenced. - When they are fitted with a timing mechanism, they can integrate velocity readings over a fixed time period (usually one minute), making them ideally suited to traversing measurement techniques. Traversing is the fastest way of averaging air velocity over an airway cross-sectional area, with accuracy sufficient for a primary ventilation survey. Electronic instruments will generally only provide spot readings. Some can integrate, but this requires a switch to be held down. This can often be difficult to accomplish when the instrument is mounted on a pole. - Mechanical instruments are usually smaller and easier to carry. They seem to also be more reliable and robust than their electronic counterparts. Mechanical anemometers are delicate instruments and must be treated with care. They should always be transported in the instrument case. Recalibration can be organised through the CSIRO or the supplier and should be undertaken at least annually. BASIC MINE VENTILATION MEASURING AIRFLOW Page 85 © AMC Consultants Pty Ltd 2005 5.2 Hot Wire Anemometer The hot wire anemometer consists of an electrically heated wire at the end of an extendible wand. In the most popular type of instrument, the wire is maintained at a constant temperature. The amount of current required to do this is related to the speed of the air. The instrument contains a second internal hot wire to provide compensation for changes in air temperature. Hot wire anemometers are very useful for accurately measuring low air velocities (down to about 0.05 m/s). Before making a velocity measurement, it is important that the flow distribution and direction be checked first, using smoke tubes. Hot wire anemometers are generally not designed for use in the traversing measurement technique. They are suitable for taking spot measurements and most instruments have the facility to electronically average a number of spot readings. They are generally not directionally sensitive. 5.3 Velometer The velometer is a mechanical instrument that consists simply of a hinged vane that swings in a rectangular passage. A port in the side of the instrument casing is connected to the passage. When the instrument is held in an airstream, airflow through the port deflects the vane against spring pressure. The vane is connected directly to a velocity indication scale. Pitot type tubes can be attached to the port with hosing to enable velocity to be checked in ducts. This instrument provides fast, accurate measurements of velocities down to about 0.2 m/s. It is well suited to routine work such as determining face velocities in secondary ventilation surveys. The velometer is directionally sensitive and can only be used for spot surveys. It must be read while being held by the observer and care must be taken to hold the instrument sufficiently far from the observer to avoid interference with the reading. Velometers are not widely used in Australian mines. 5.4 Smoke Tube A smoke tube consists of a glass tube (similar to a gas detector tube) that emits a highly visible smoke when air is aspirated through it via a rubber bulb. Smoke tubes give superior results to other less satisfactory improvised alternatives such as spray paint, a handful of fine dry dust or, cigarette smoke! Measurements are taken by marking out a fixed distance in a drive with two paint lines on the roadway. The distance should be that which the smoke travels in about 30 seconds (the smoke cloud usually dissipates after this period of time). Smoke tubes are used for velocities of less than 0.1 m/s to 0.5 m/s and a measurement distance of about 5m is usually therefore appropriate. The smoke is released in the centre of the airway about an arm's length upstream of the first mark. Two observers are required to determine the time interval between when the centre of the smoke cloud passes the first and second mark. The distance that the smoke travelled divided by the time taken, then multiplied by a correction factor (typically 0.8) calculates the velocity of the air. The correction factor allows for the effects of smoke dispersal and the fact that the velocity in the centre of the drive is usually higher than the average velocity. It is always a good idea to check the flow distribution in the airway before commencing a smoke tube measurement. In hot, inclined airways with low velocities, the magnitude and even direction at the backs may be different to that on the floor. Smoke tubes can also be used to trace air leakage (e.g. into draw-points) and to help visualise the flow distribution. BASIC MINE VENTILATION MEASURING AIRFLOW Page 86 © AMC Consultants Pty Ltd 2005 5.5 Pitot-Static Tube The Pitot-static tube (often referred to as the Pitot Tube) consists of two concentric "L" shaped tubes. A pitot static tube is used to determine pressure at a point. A variety of designs have been developed with advantages between the different designs generally applicable to research work. The pitot static tube can be used successfully without the need for corrections given if: a) The head is aligned to the direction of airflow within 15 ° (2.5% error in the velocity). b) The tube diameter must not exceed 1/25 the duct diameter in circular ducts and 1/20 the length of the smallest side in a rectangular duct. c) The tube diameter should not exceed 15 mm. d) The velocity should be between 3m/s and 70m/s. The pitot-static tube can be used to measure static, total and velocity pressure when connected to a manometer. BASIC MINE VENTILATION MEASURING AIRFLOW Page 87 © AMC Consultants Pty Ltd 2005 With an accurate manometer, good measurement technique and steady flow conditions, velocities can be measured to within ± 1% for velocities above 5 m/s. The accuracy below 5 m/s is limited by the inability of most manometers to resolve very low pressures (less than 10 Pa). Because Pitot-static tubes are essentially a medium - high velocity measurement instrument, they are not used for surveys in underground drives. They are most useful for the measurement of the higher air velocities often found in ducts. Typically, a pitot-static tube would be used for fan testing and flow measurement in secondary ventilation ducts. The most useful length for many mines is 1.5m. Of the above instruments, a vane anemometer, smoke tube set and pitot-static tube are considered essential for any underground mine. Summary - Air Velocity Measurement Instruments Instrument Velocity Range (m/s) Comments Vane Anemometer 0.2 - 25 * Versatile and accurate - the most useful ventilation instrument particularly for ventilation surveys. Mechanical type is preferred. Hot Wire Anemometer 0.05 - 15 Good for accurate spot measurement of low velocities Velometer 0.2 - 15 Useful for quick, routine spot air velocity measurement. Method not accurate enough for ventilation surveys. Smoke Tube 0.05 - 0.5 Enables air flow distribution to be "seen". Cumbersome method to use Pitot-Static Tube 5 50 Best instrument for measuring airflow in ducts. * Instruments capable of reading up to 50 m/s are available, but not generally required for mine ventilation work. 5.6 Selection of Measurement Site The ideal airflow-measuring site will have a smooth or undisturbed airflow distribution pattern. This is will be an area in a drive that is: - as straight as possible, - of uniform shape and size and, - unobstructed. As a rule of thumb, the measurement site should be located at least six drive diameters downstream and a minimum of three drive diameters upstream of any disturbing influence (bend, obstruction, etc). This is often not possible in an underground operation, and a compromise is necessary. In many cases this will mean taking extra measurements at site that better fit the selection criteria. BASIC MINE VENTILATION MEASURING AIRFLOW Page 88 © AMC Consultants Pty Ltd 2005 5.7 Measuring the Airway Cross Sectional Area Several methods are available to determine ventilation station area. When conducting ventilation surveys that require a high level of accuracy the mine surveyors should be utilised to accurately determine the shape and area of all permanent ventilation stations. For primary ventilation surveys, permanent ventilation stations must be clearly marked with a paint line on the walls and backs. The station number and surveyed cross-sectional area should also be marked. The most reliable method is to write this information on a steel or plastic tag that is attached to the wall using surveyor's putty. For temporary ventilation stations a tape measure is required to determine a minimum of five equally spaced heights (offsets). Using these measurements the area can be calculated using Simpsons Rule. The area enclosed by a curvilinear figure divided into an even number of strips of equal width is equal to one- third of the width of the strip, multiplied by the sum of the two extreme offsets, twice the sum of the remaining offsets, and four-times the sum of the even offsets. ( ) E 4 O 2 A 3 X Area + + = Where X = distance between offsets. (m) A = sum of the first and last off sets. (m) O = sum of the remaining odd offsets. (m) E = sum of the even offsets. (m) For example In this case ( ) ( ) ( ) | | 6 4 2 5 3 7 1 O O O 4 O O 2 O O 3 X Area + + + + + + × = Note that the area is dived into an even number of sections i.e. an odd number of offsets are measured. It is very important to note that in trackless mining, the ventilation station cross-sectional areas will change over time. This is mainly due to extra road base material being applied. In one mine, it was found that over about 10 years, the cross-sectional areas of a number of ventilation stations had decreased by over 10%. In recognition of this change ventilation stations maintained in main access declines should be remeasured at least every two years. 5.8 Traverse Velocity Measurement The traverse method is the quickest way to determine air velocity with sufficient accuracy for a ventilation survey. An integrating anemometer is required for this technique and the vane anemometer is generally the only instrument with this facility. BASIC MINE VENTILATION MEASURING AIRFLOW Page 89 © AMC Consultants Pty Ltd 2005 The principle of the traverse technique is to slowly traverse the anemometer across the airway at a uniform speed and in a pattern that ensures that the entire airway cross- sectional area is evenly represented. In order to ensure acceptable accuracy, traverse speed should be limited to less than 0.4 m/s (less than 0.2 m/s when measuring air velocities below 0.75 m/s). When using an anemometer with a 60 second timer two readings will be required to complete one traverse one for each side of the opening, and the velocity for the area will be the average of both of these readings). Multiple traverses readings will be undertaken until a minimum of two traverse sets agree to within ±5% of one another. 5.9 Spot Reading Method For spot readings, the airway cross-section is subdivided into a number of equal areas. A velocity reading is taken in the centre of each of these smaller areas. The velocity for the area will be the average of all spot readings. It should be noted that for acceptable accuracy, the size of the squares should not be significantly larger than 1m x 1m. This is a precise, but also time-consuming method. Because of this, it is not commonly used for routine work. 5.10 Single Spot Reading Method A simple, quick, and rough form of spot reading is to take a single velocity measurement in the centre of a drive, or duct. This reading will almost always over-estimate the average velocity, because the fastest velocity is usually found in the centre of the airway. A correction factor (often between 0.8 and 0.9) therefore needs to be applied. This method is useful for routine work, but is not accurate enough for a primary ventilation survey. It also requires smooth, unobstructed flow conditions in the airway. BASIC MINE VENTILATION UNDERSTANDING FANS Page 90 © AMC Consultants Pty Ltd 2005 I will now speak of ventilating machines. If the shaft is very deep and no tunnel reaches to it, or no drift from another shaft connects with it, or when a tunnel is of great length and no shaft reaches it, then the air does not replenish itself. In such a case it weighs heavily on the miners, causing them to breath with difficulty and some times they are even suffocated and burning lamps are also extinguished. There is therefore a necessity for machines which enable the miners to breathe easily and carry on their work Agricola De Re Metallica (1556) 6 UNDERSTANDING FANS In Chapter 3 we discussed the effect of natural ventilating pressure and how it can cause air to flow through mine workings. Airflow through the large mechanised mining operations of today, could not exist in the quantities required, unless there was sufficient pressure difference to overcome the resistances in the circuit. This requires mechanical energy input provided by fans. The first evidence of mechanical methods for ventilating mine were described by Agricola in 1556 and involved methods such as human powered centrifugal fans, bellows connected to wooden conduits and shaft collar deflectors, which divert winds into the mine workings. Although large centrifugal fans were in use in the early to mid 1850s, airflow through the underground workings was generally provided only by natural draft. It was not until the turn of the 20 th century that fans were used extensively in mines. Typically, these impellers (pictured opposite) were fitted with backward curved paddle blades, between 240 inch (6.0m) and 520 inch (13.0m) diameter and rotating at very slow speeds between 0.67 revolutions per second (rps) (40 rpm) and 1.0 rps (60 rpm) and, driven by large steam powered engines. One of the early makes of this type of fan was the double inlet Walker Indestructible 16 . In around 1900, Samuel Davidson developed a forward curved multi bladed fan to handle hot air for the purpose of drying tealeaves from their Colombo plantations in Ceylon, now Sri Lanka. The fan impeller was much smaller in diameter with forward curved blades designed to run at significantly higher speeds. The fan was called a Sirocco after the hot winds that blow across the Mediterranean from the coast of North Africa. 16 de la HARPE, J,H., JENNER, L.W. The History of Mine Fans in South Africa The Journal of the Mine Ventilation Society of South Africa. (December 1986) BASIC MINE VENTILATION UNDERSTANDING FANS Page 91 © AMC Consultants Pty Ltd 2005 It was one of these new generation fans that are believed to be the first mechanical means of ventilation installed in Australia. This fan was installed around 1917 at on No. 4 Shaft Zinc Mine Broken Hill and had an airflow capacity of 45,000 cfm (21.0m 3 /s) and remained in operation at this location until it was replaced in 1921. The replacement was a larger Sirocco fan (pictured left), which was manufactured in Belfast Ireland by Davidson& Co. Ltd. This fan was fitted with a 119-inch (3.0m) impeller designed to produce 195,200 cfm (92m3/s) at 6 of inches water gauge (1495 Pa) when rotating at 244 rpm. 6.1 General Description of Fans A fan is a rotating machine in which air is continuously drawn in at one pressure and delivered at a higher pressure i.e. the mechanical energy delivered to the fan is transformed into potential energy (pressure) and kinetic energy (velocity) by the fan. This pressure is necessary to overcome the resistance of the particular duct or mine, in which the fan is operating. Fans are named according to the type of impeller fitted into the casing. In mining applications the main fan types are: 1. Axial-flow. - In an axial fan the air flows through the impeller parallel to and at a constant distance from the axis. The pressure rise is provided by the direct action of the blades. 2. Centrifugal or Radial-flow. - In centrifugal fans the air enters parallel to the axis of the fan turns through 90º and is discharged radially through the blades. The blade force is tangential causing the air to spin with the blades and the main pressure rise is attributed to the centrifugal force. 3. Mixed flow. - In a mixed flow fan the air enters parallel to the axis of the fan turns through an angle which may range from 30º to 90º The pressure rise is partially by direct blade action and partially by centrifugal action. BASIC MINE VENTILATION UNDERSTANDING FANS Page 92 © AMC Consultants Pty Ltd 2005 6.2 Fan Terminology The principal component of a fan is the impeller, consisting of the hub and blades. The impeller is mounted on a shaft inside the housing, or casing, of the fan that is driven directly or indirectly by a motor. In addition, the fan is generally equipped with an inlet cone and an outlet evasè to improve the flow characteristics of the fan. There may also be guide vanes to control the direction of airflow through the fan. Centrifugal Reproduced from Air Moving and Conditioning Association Inc. AMCA Fan Application Manual BASIC MINE VENTILATION UNDERSTANDING FANS Page 93 © AMC Consultants Pty Ltd 2005 Axial Reproduced from Air Moving and Conditioning Association Inc. AMCA Fan Application Manual 6.3 Axial-Flow Fans Axial flow fans are divided into three categories 1. Free air - The impeller is not confined e.g. Desk fan 2. Tube axial - The impeller is confined in a casing BASIC MINE VENTILATION UNDERSTANDING FANS Page 94 © AMC Consultants Pty Ltd 2005 3. Vane axial - Same as a tube axial except guide vanes are fitted inside the casing to reduce swirl The impeller may have two or more blades. Generally speaking, high-pressure fans have a greater number of blades than low-pressure fans. The shape and pitch of the blades vary considerably in different designs. 6.3.1 Construction of an Axial-Flow fan The principal components of an axial fan are the impeller, the motor and the casing. The impeller comprises two parts, the hub and the blades. Blades may be manufactured from flat plate or cast from alloy in an aerodynamic shape. It is also possible that the blades are fixed or adjustable. The number of blades on an impeller may be expressed in terms of solidity with 100% solidity the maximum number of blades for that particular design. Generally speaking the higher the solidity the higher the pressure. The hub to blade ratio is indicative of the performance of the fan. For a given overall diameter, long blades and a small diameter hub indicates high airflow and low pressure, obviously shorter blades and a larger hub indicates higher pressure and lower airflow. The clearance between the blade tips and the casing must be kept small to prevent pressure loss. This calls for accurate machining of the casings and blades, resulting in increased cost. The air leaving the axial-flow fan usually has a rotary motion, or swirl. This results in a loss of energy. This loss is reduced by the installation of vanes called guide vanes fitted to straighten the flow of air. Axial-flow fans are particularly suitable for mounting directly in ducts. A second impeller, rotating in a direction opposite to the first, can also be fitted. This result in the swirl induced by the first set of blades being neutralised by the swirl imparted by the second set. Fans fitted with this type of additional impeller are known as contra-rotating fans 6.4 Centrifugal or Radial-Flow fans When a stone attached to a string is swung in circles and then let go it will fly outwards. In fact anything that revolves tends to move away from the centre of rotation with centrifugal force. The word centrifugal meaning moving or directed away from the centre. The impeller of a centrifugal fan consists of a hollow wheel, rotor or runner, with a number of blades BASIC MINE VENTILATION UNDERSTANDING FANS Page 95 © AMC Consultants Pty Ltd 2005 around its circumference, similar to the paddle wheel of old steamships. The blades are generally relatively short, and can be arranged in three ways: - Radially - Forward-curved, or forward-sloping - Backward-curved, or backward sloping. When the impeller rotates, the air between the blades is thrown outwards by centrifugal force and leaves the impeller at right angles to the axis. The air is guided by the shape of the fan casing to the fan outlet, and is then replaced by air that enters along the direction of the axis from either one side only, when the fan is termed a single-inlet fan, or from both sides, when the fan is termed a double- inlet fan. 6.4.1 Construction of a Centrifugal Fan In practice the shapes of the blades differ considerably in different types of fans The performance of the fan depend upon the design of the blades and the design of the volute (scroll) which is the section of the fan casing along which the air flows after leaving the impeller. It is the design of the volute that determines the amount of velocity pressure in the air after leaving the blades that will be converted into static pressure. On some centrifugal fans, a certain amount of control of performance is provided by the installation of variable inlet guide vanes. 6.5 The Fan Characteristic (Performance) Curve The performance of a fan is generally presented in the form of a graph on which is plotted the airflow quantity (Q) along the horizontal axis and the fan pressure (P) along the vertical axis. These points are obtained from tests where the actual fan performance is measured. A line joins these points in the form of a curve. This curve is termed the fan characteristic curve. The power and fan efficiency is shown for each airflow point and similarly joined to form a curve. Fan performance curves are supplied by fan manufacturers and show the predicted airflow volumes for a given pressure. As the pressure requirements increase, the airflow volume decreases. It should be noted that these curves apply only for the particular fan and at a particular density of air. Any variations of density along with blade pitch angle will result in a change to the characteristic. These changes can be predicted and incorporated into the design. However, there are changes that cannot be predicted and are caused by dirty or worn fan blades. Fan performance curves are presented in many differing forms. Some examples of fan curves are shown in the following figures. Quantity P r e s s u r e 0 Quantity P r e s s u r e 0 Quantity P r e s s u r e 0 BASIC MINE VENTILATION UNDERSTANDING FANS Page 96 © AMC Consultants Pty Ltd 2005 In order to make the correct selection people interpreting these curves should be aware of the following: 1. Two curves represent the total pressure performance whilst the other show static pressure performance. 2. All curves show the fan shaft power expressed in different ways 3. Although only one of the curves shows the efficiency (for the pressure) drawn on the chart it is easily interpreted by calculation from the information provided. (this is discussed later in Section 6.13 and Section 6.14) Some examples of fan curves are provided below BASIC MINE VENTILATION UNDERSTANDING FANS Page 97 © AMC Consultants Pty Ltd 2005 BASIC MINE VENTILATION UNDERSTANDING FANS Page 98 © AMC Consultants Pty Ltd 2005 600 800 1000 1200 1400 1600 1800 20.0 22.0 24.0 26.0 28.0 30.0 32.0 34.0 36.0 38.0 40.0 Air volume (m 3 /s) P r e s s u r e ( P a ) 40 45 50 55 60 65 70 75 80 Fan total pressure Absorbed power AL12-500 Diameter: 1200 mm Speed: 1000 rpm (nominal) Power: 55 kW Single stage Axial Ph: (08) 9455 4433 Fx: (08) 9455 1819 Density 1.20 kg/m3 A b s o r b e d p o w e r ( k W ) x 1 fan Full bladed BASIC MINE VENTILATION UNDERSTANDING FANS Page 99 © AMC Consultants Pty Ltd 2005 BASIC MINE VENTILATION UNDERSTANDING FANS Page 100 © AMC Consultants Pty Ltd 2005 6.6 Interpreting Fan Performance Curves The correct interpretation of fan curves is essential to ensure that the fan selection will meet the requirements. MULGA HILL FAN COMPANY QWER 1250-2300-12 990 rpm 1.2kg/m 3 0 500 1000 1500 2000 2500 3000 3500 0 20 40 60 80 100 120 140 160 180 200 F a n S t a t i c P r e s s u r e ( P a ) 0 100 200 300 400 500 600 700 0 20 40 60 80 100 120 140 160 180 200 Volume (m 3 /s) F a n S h a f t P o w e r ( k W ) 10 20 30 40 50 60 70 10 20 30 40 50 60 70 Reference P'nW 2345 Impeller blade pitch setting Pressure sometimes given as Fan Total Pressure Manufacturers reference number Fan performance sets Manufacturers Code for the fan type usually provides, fan type, hub diameter, impeller diameter, number of blades, fan Speed & air density Fan operating point AP = P x Q Fan Shaft power at the operating point BASIC MINE VENTILATION UNDERSTANDING FANS Page 101 © AMC Consultants Pty Ltd 2005 The example curve shown above represents an adjustable pitch axial flow fan. Some points to consider are: 1. A fan designed and manufactured to operate at setting 40 does not mean that it can operate at settings above this point. In this case the fan would typically be fitted with a 300 kW electric motor and if the fan pitch angle were increased the potential for the fan to stall would be extremely high. It would be necessary to increase the size of the motor. 2. It may not be possible to increase the size of the motor because it must be small enough to fit inside the housing and retain the same centreline. 6.7 Fan Stall A fan will stall if the resistance of the system is (or becomes) excessive and as this resistance curve becomes steeper the intersection point with the fan performance characteristic changes and moves to a point of higher pressure (lower quantity) on the fan characteristic. At this point, both the fan pressure and airflow quantity increase simultaneously (i.e. both the fan characteristic and the system characteristic have a positive slope) this is opposed to the normal operation where the pressure increases as the quantity decreases. Eventually, the pressure and quantity become unstable and fluctuate wildly. This condition is known as hunting or stall. This zone is usually not shown on manufacturers curves, but it can be assumed to occur above the highest pressure shown. If a fan is operating in this stall zone, the air tends to separate from the blade surfaces, causing excessive vibration. These vibrations may damage the fan if it is allowed to operate for any length of time. This zone may be very noticeable in some fans and hardly noticeable in others. Stall Zone Signs 1. The fan vibrates excessively 2. The fan makes unusual noises (whines because of increased pressure) 3. Input power amps show rapid oscillations or surging at a slower frequency (every couple of seconds) 4. The quantity and pressure points alter considerably Action to be taken Continued operation of a fan in stall may eventually cause damage to the fan and the blades may disintegrate. To remove the fan from this condition some air may be allowed to enter the system at a position close to the fan (ie short circuit the system) this will have the effect of reducing the overall system resistance). This should only be a temporary solution until the cause of the stall is identified and rectified. 6.8 Fan Performance Control Although fans are required for a particular duty, it should not be forgotten that mining by its very nature is dynamic. Over the life of the mine, fans may be required to operate at a number of Quantity P r e s s u r e 0 Quantity P r e s s u r e 0 Quantity P r e s s u r e 0 Stable portion of curve Un-stable portion of curve Quantity P r e s s u r e 0 Quantity P r e s s u r e 0 Quantity P r e s s u r e 0 Stable portion of curve Un-stable portion of curve BASIC MINE VENTILATION UNDERSTANDING FANS Page 102 © AMC Consultants Pty Ltd 2005 specific duties. To cater for these changes, fans must have flexible characteristics. Some of the causes for differing fan duties include; - Increased resistance - increased airflow requirements - change in air density - power saving The output of a fan can be controlled by adjusting the system (mine resistance) or using outlet dampers, inlet-box dampers, variable inlet vanes, variable pitch, variable speed or varying the number of fans. 6.8.1 System Damper Dampers (regulators) installed in fan ducts (mine openings) to act as throttling devices have the effect of altering the system resistance. The fan will operate at different points on its characteristic without change to the pressure, quantity and power curves. This method is sometimes used to cause a fan to operate at a more efficient section of its performance characteristic. In these cases efficiency may be improved but, at the cost of decreased airflow and some times increased power. There is usually very little economic justification for the change and is not recommended as a control system. 6.8.2 Outlet Damper A fan outlet damper acts on the fan in the same way as a system damper i.e. it will change the overall system characteristic by altering the resistance. Consider the graph to the left in the figure below. Points A, B, C, D & E lie on the intersection of the fan curve and a number of parabolic system characteristics with the same origin. These curves represent the combined system and damper at various settings of the outlet damper control. Point A would represent the damper wide open and the other points represent the damper at other settings up to point E fully closed (FC). In this case the operating points D and E are potentially unstable and it would not be recommended to operate the fan with the damper set in this position. BASIC MINE VENTILATION UNDERSTANDING FANS Page 103 © AMC Consultants Pty Ltd 2005 Reproduced from Fan Engineering Buffalo Forge Company Eighth Edition It is possible to represent the various settings of the damper as fan characteristic curves similar to that shown to the right in the figure below. Obviously there are an infinite number of settings between fully open and fully closed. There is a caution when interpreting this graph. Consider the point C (½ open). In this case the vertical distance from the base line to C is the pressure loss in the system and the vertical distance C-C is the pressure loss caused by the outlet damper. There is some suggestion that because the intersection points A, B, C, D, & E all lie on the negative section of the performance characteristics then the operation will be stable even when fully closed. There is some evidence that outlet dampers can be evaluated in this way and IF the principle resistance is on the inlet side of the fan but it is not suitable if the principle resistance is on the outlet side of the fan. In essence the damper is considered to be part of the system rather than part of the fan. 6.8.3 Inlet-Box Damper The performance of an inlet-box damper (IBD) is considered in two parts. The first part is the pressure loss cause by the resistance of the damper, similar to the outlet damper. The second part is due to changes caused by the inlet-box damper to the swirl of the air onto the impeller. This pre-swirl reduces the amount of work for the impeller therefore affecting the impeller output and resulting in a different performance characteristic. The performance of an inlet-box damper can be considered in the manner shown in the figure opposite. Here again there is some evidence to suggest that IF significant swirl exists then the intersection points A, B, C, D, & E all lie on the negative section of the performance characteristics and the operation will be stable. There is also some evidence that if the principle resistance is on the outlet side even without pre-swirl the operation will be stable. However, if the principle resistance is on the inlet side then the operating points should be considered as A, B, C, D, & E and in this case the points D & E lie on the positive part of the fan characteristic and therefore the operation is likely to be unstable. Like the outlet damper the inlet-box damper is generally considered to be part of the system rather than part of the fan. 6.8.4 Variable Inlet Vanes Variable inlet vanes (VIVs) are similar in appearance to a camera iris and is slightly superior to inlet damper control in respect of efficiency and stable operation. VIVs provide the same effect on fan performance as the inlet-box damper because they are designed to create a pre-swirl to the air. Again they have two components that caused by the resistance of the structure and that caused by the pre-swirl given to the air. BASIC MINE VENTILATION UNDERSTANDING FANS Page 104 © AMC Consultants Pty Ltd 2005 VIVs are always installed as part of the fan and very close to the impeller. Because of this operating points are always considered to be points A, B, C, D, & E and highly unlikely to operate in the unstable positive characteristic points D & E. The use of VIVs in Australian mines is usually confined to primary centrifugal fans but their use with axial flow fans is common particularly in the deep mines of southern Africa. Maintenance of this component is usually very poor and most become seized at a particular setting. This component should be greased weekly and exercised daily. Exercising requires the vanes to be closed then again open to the desired setting. This is a very simple operation that can be undertaken automatically, particularly given todays technology of PLCs. 6.8.5 Variable Speed Speed control can be achieved in a number of ways - Changing drive pulley ratios. - Reduction gearbox drives. - Variable speed controllers - Number of poles in the motor Poles of No Hz 120 Speed Motor × = (can only be an even number) Variable speed characteristics can easily be determined from the fan laws detailed in section 6.9. The performance characteristic curves would be identical except that all devices to alter the speed must have some slip to transmit torque. 6.8.6 Variable Pitch The figure opposite shows the performance characteristic for a fan and the operation points with the blades set at different angles. The system is depicted by the curve drawn through points E, D, C, B, A & Z. A fan would normally be selected to operate a point A as this would be the most BASIC MINE VENTILATION UNDERSTANDING FANS Page 105 © AMC Consultants Pty Ltd 2005 Effect of NVP Quantity P r e s s u r e 0 + NVP - NVP efficient use of power. Higher flow rates would be achieved at point Z and lower rates at points B, C, D, & E. Altering the blade pitch is normally done by stopping the fan, loosening the nut holding the blade to the hub and then turning the blade to the required pitch setting. The nut is then again tightened to secure the blade in its new position. On certain fans, this adjustment can be carried out by means of a single lever or series of linkages when the fan is in operation. These are termed variable- pitch in motion fans. 6.8.7 Fans in Series If we assume that air is incompressible then the potential performance of two identical fans is obtained simply by multiplying by two the pressure at a particular quantity. In the figure opposite one fan will operate in the system at B by adding an identical fan the combined operating point will be at A. Fan in series are generally well recognised as most auxiliary development fans are configured to operate in this manner and there are many instances where primary ventilation fans have two stages. Fans are generally installed in series to overcome an increased system resistance or maintain a particular quantity. In most cases fans installed in series are designed for that purpose. However it is possible to install unlike fans in series but this is the exception rather than the rule. NOTE that the NVP acts in the same way as a series fan with the exception that NVP can have a negative pressure that is subtracted form the fan pressure characteristic. When two unlike fans are installed in series then the combined pressure generated at a given airflow quantity will be the sum of the pressures of the individual fans at that quantity. The A One Fan Two Fans A B BASIC MINE VENTILATION UNDERSTANDING FANS Page 106 © AMC Consultants Pty Ltd 2005 A A B One Fan Two Fans exception being contra rotating fans when the pressure can be three times that of each individual fan. In practice, the overall flow is increased with the installation of a second fan in series however, in most auxiliary fan duct installations there will be little to no increase in flow discharged at the end of the duct, only an increase in leakage along the length of the duct. 6.8.8 Fans in Parallel The potential performance of two identical fans operating in parallel is obtained simply by multiplying by two the quantity at a particular pressure. In the figure opposite one fan will operate in the system at B by adding an identical fan the combined operating point will be at A. When fans are selected to operate in parallel, it is essential to ensure they operate in the stable area of the combined characteristic. When combining parallel fan performance curves the only the quantities are added and the pressure will remain the same. The important thing is to note is that both fans MUST operate at the same pressure. When unlike fans are installed in parallel they will provide different quantities of air but will operate at the same pressure. The use of fans in parallel is not uncommon in mines and in fact many mine circulating large quantities use fans in parallel as it offers the opportunity for maintaining some airflow should one fan fail. Some mine choose to install two or even three fans and use one as an insitu spare and only operated in an emergency when an operating fan fails. BASIC MINE VENTILATION UNDERSTANDING FANS Page 107 © AMC Consultants Pty Ltd 2005 The use of multiple fans in parallel may cause problems when starting. Some fan performance curves have a decided dip in the performance and if the fan being started has to pass through this dip or the positive slope side of the performance characteristic then it will enter the Stall position and never recover. Fan manufacturers seldom show the positive slope side of the curve and it can be misleading. As a precaution the fan manufacturer must be questioned specifically as to the possibility of having to pass through the dip on the stall side of the fan performance. Fan 1 Fan 1 Fan 2 Fan 2 Fan 3 Fan 3 Fan 4 desired Fan 4 desired operating position operating position T0 get to the desired position Fan 4 must pass T0 get to the desired position Fan 4 must pass through the dip in the curve. Usually the fan enters through the dip in the curve. Usually the fan enters stall and never recovers, eventually destroying the stall and never recovers, eventually destroying the impeller impeller Fan 1 Fan 1 Fan 2 Fan 2 Fan 3 Fan 3 Fan 4 desired Fan 4 desired operating position operating position T0 get to the desired position Fan 4 must pass T0 get to the desired position Fan 4 must pass through the dip in the curve. Usually the fan enters through the dip in the curve. Usually the fan enters stall and never recovers, eventually destroying the stall and never recovers, eventually destroying the impeller impeller 6.8.9 The Eck Line When a fan enters the unstable part of its curve it will start to stall. Operating two or more fans in parallel, will induce stalling at a lower operating pressure. This is because succeeding fans must start up against the pressure already being developed by the operating fan or fans. The calculated unstable portion of the combined curve is known as the Eck line 17 . The determination of this line will show the lower maximum useful pressure to ensure operation in the stable portion of the combined fan performance curve. Consider the combined curves for one, two and three identical fans in parallel shown in the figure below. The combined Eck lines can be determined in the following manner. For a single fan the unstable portion of the performance curve is shown as a dashed line and the fan can be operated at any point to the right of the dashed line. For two fans, the combined curve (labelled 2 Fans) shows two unstable portions. The first is due to the combination of the two fan curves and is shown as a bold black line. Point A on this curve is obtained by doubling the air quantity at point a on the single fan curve. The second unstable portion of the two-fan system is due to the unstable part of each fan and is shown as a dotted line. This portion is constructed by marking a point to the left of the combined curve at distance a-c as measured for a single fan. Other points on this unstable portion of the curve are constructed in the same manner to obtain the dotted line for two parallel fans. Hence for two fans in parallel, the stable portion of the fans is to the right of the curve a-b. Finally, the curve for three fans in parallel (labelled 3 Fans) has three unstable portions: 17 Eck - In recognition of the work undertaken by Professor Bruno Eck on this subject. BASIC MINE VENTILATION UNDERSTANDING FANS Page 108 © AMC Consultants Pty Ltd 2005 1. due to the combined P-Q curve for three fans; 2. due to the unstable portion of two fans; and 3. due to the unstable portion of a single fan. The stable part of the curve lies to the right of the Eck line. 0 10 20 30 40 50 60 70 80 90 Quantity (m 3 /s) 1000 2000 P r e s s u r e ( P a ) Eck Lines (dotted) a A b b c a c 1 Fan 2 Fans 3 Fans R e s i s t a n c e X R e s i s t a n c e Y Stable portion of the combined curve Diagrammatic only Diagrammatic only 0 10 20 30 40 50 60 70 80 90 Quantity (m 3 /s) 1000 2000 P r e s s u r e ( P a ) Eck Lines (dotted) a A b b c a c 1 Fan 2 Fans 3 Fans R e s i s t a n c e X R e s i s t a n c e Y Stable portion of the combined curve Diagrammatic only Diagrammatic only In the figure above, two system resistance curves are plotted. Resistance X has a resistance higher than Resistance Y. If these fans were operated in parallel against Resistance X, the third fan would have to pass through the unstable part of the combined curve on the run up to the system pressure. In reality, this would not occur and the fan would stall. If these fans were operated in parallel against Resistance Y, the third fan would run up to the system pressure by passing underneath the Eck line. In this case the probable maximum duty would be 65 m 3 /s at 1,500 Pa. 6.8.10 Fan Diffuser Fan diffusers ultimately cause a little extra airflow through the fan. As shown in Section 2 system shock losses can be reduced by the installation of an effective diffuser at the discharge. The diffuser may be fitted with an internal fairing. They vary in shape from rectangular to round and the included angle, the outlet to inlet ratio and the cross sectional shape affect the efficiency. The best pressure regain is achieved on a diffuser without an inlet fairing, and with an outlet to inlet area ratio of 4:1 and the optimum included angle between 8 o and BASIC MINE VENTILATION UNDERSTANDING FANS Page 109 © AMC Consultants Pty Ltd 2005 11°. Because of the length required for this optimum in practice this angle can be much larger (up to 25°) P V REGAINED = q(P V INLET - P V OUTLET ) Where q = Efficiency of the evasè (%) 6.9 Fan Laws Fan performance curves are determined for a specific speed and density. Unless otherwise specified the density for a fan curve can be assumed as standard air (1.2 kg/m 3 ). Standard air is a definition of convenience that is widely adopted. The actual values of temperature, pressure and moisture content are not important. Should the speed or density of the fan inlet air be altered, the following fan laws will apply. Change Density (µ) Speed (rpm) Diameter Quantity (Q) 2 1 Q Q = 2 1 2 1 rpm rpm Q Q = 3 2 1 2 1 D D Q Q | | . | \ | = Pressure (P) 2 1 2 1 P P µ µ = 2 2 1 2 1 rpm rpm P P | | . | \ | = 2 2 1 2 1 D D P P | | . | \ | = Power (kW) 2 1 2 1 kW kW µ µ = 3 2 1 2 1 rpm rpm kW kW | | . | \ | = 5 | | . | \ | = 2 1 2 1 D D kW kW Efficiency (%) q 1 = q 2 q 1 = q 2 q 1 = q 2 When considering the diameter the fans must have the same geometric dimensions, and if the size difference is great then it can be expected that the fan total pressure may be larger than that given by these laws (scale effect). It is also possible that a change in density due to compression of the air will occur affecting the results from the use of these laws. This is normally only of concern at pressures above 2.5 kPa. This is discussed more fully in Woods Practical Guide to Fan Engineering or Fan Engineering published by the Buffalo Forge Company. 6.10 Measuring Fan Performance Performance testing is undertaken to determine the actual operating performance of fans particularly at time of installation for comparison with the manufacturers predicted performance. Fan performance testing is detailed in standards such as Australian Standard 2936 and British Standard 848 and is usually specified in fan tender documents as the measure of compliance. BASIC MINE VENTILATION UNDERSTANDING FANS Page 110 © AMC Consultants Pty Ltd 2005 Standards tests are performed using standardised airways with devices fitted to straighten flow and alter the operating pressure. The installation of such components for site measurements is generally considered to be too costly and is seldom (if ever) used. Precision laboratory type testing cannot be carried out on site. Measurements made to determine site performance must be agreed with the fan manufacturer at the time of the purchase order being placed. Aside from the regular three monthly intervals to comply with some mining legislation the measurement of fan performance is also undertaken: 1. For acceptance testing at time of purchase and commissioning. 2. Prior to making an operational change to the fan (i.e. altering the speed, changing a motor etc.). 3. After making an operational change to the fan to ensure the desired (predicted) result has been achieved. 4. To determine if a measured decrease in system airflow quantity is due to system resistance or the operational performance of the fan. The main objective of measurements is to accurately determine: 1. fan inlet airflow quantity 2. fan pressure 3. fan efficiency Measurements of fan performance are made to represent the actual airflow through the fan and must therefore be sited to ensure there is no change in the properties of the airflow between the measuring site and the fan inlet. Such changes may include density, caused by differing temperature and pressure as well as airflow quantity caused by leakage into or out of the system. Fans are primarily categorised as pressure, exhausting, in line, or diaphragm mounted. 6.10.1 Fan Total Pressure The fan total pressure (FTP) is equal to the total pressure at the fan outlet (TP O ) minus the total pressure at the fan inlet (TP I ). I O TP TP FTP ÷ = Equation 6-1 Fan Total Pressure 6.10.2 Fan Velocity Pressure The fan velocity pressure (FVP) is equal to the velocity pressure at the fan outlet (VP O ). PRESSURE FAN Free inlet, ducted outlet EXHAUST FAN Ducted inlet, free outlet DIAPHRAGM FAN Free inlet, free outlet INLINE FAN Ducted inlet, ducted outlet Fan Categories PRESSURE FAN Free inlet, ducted outlet EXHAUST FAN Ducted inlet, free outlet DIAPHRAGM FAN Free inlet, free outlet INLINE FAN Ducted inlet, ducted outlet PRESSURE FAN Free inlet, ducted outlet PRESSURE FAN Free inlet, ducted outlet EXHAUST FAN Ducted inlet, free outlet EXHAUST FAN Ducted inlet, free outlet DIAPHRAGM FAN Free inlet, free outlet DIAPHRAGM FAN Free inlet, free outlet INLINE FAN Ducted inlet, ducted outlet INLINE FAN Ducted inlet, ducted outlet Fan Categories BASIC MINE VENTILATION UNDERSTANDING FANS Page 111 © AMC Consultants Pty Ltd 2005 O VP FVP = Equation 6-2 Fan Velocity Pressure 6.10.3 Fan Static Pressure The fan static pressure (FSP) is equal to the FTP minus the fan velocity pressure. FVP FTP FSP ÷ = Equation 6-3 Fan Static Pressure 6.11 Pressure Fans The figure below shows the side tube and facing tube measurements for a pressure (forcing) fan (most mine secondary fans). From these measurements of pressure we can determine the Fan Pressures By definition FTP = TP O TP I in this case TP I = 0 therefore FTP = 2000 0 = 2000 Pa By definition FVP = VP O From the equation for ventilation pressure TP = SP + VP then VP O = TP O - SP 0 = 2000 1500 = 500 Pa = FVP and FSP = FTP FVP = 2000 500 = 1500 Pa Therefore, a static pressure reading downstream of a pressure fan is equal to the Fan Static Pressure (minus the frictional pressure losses between the fan outlet and the measuring site). 6.11.1 Selection of Measuring Site Satisfactory measurements can only be made in a plane where the airflow is substantially free of swirl and air turbulence and generally should be no closer than 1.5 duct diameters upstream of the fan inlet or 2.5 diameters from the fan outlet. It is preferred that airflow measurements are made upstream of the fan (the fan intake). If it is necessary to measure downstream (fan discharge) this distance should be equal to the effective duct length (described in the figure opposite). This is to allow for the velocity profile to become evenly distributed in the duct. Discharge Duct Outlet Area Fan Housing Cutoff Blast Area Area 25% 50% 75% 100% Effective Duct Length To calculate the effective duct length assume a minimum 2.5 duct diameters for each 12.5 m/s and add 1 duct diameter for each additional 5.0 m/s Example: 25 m/s = 5 duct diameters. If the duct is rectangular with side dimensions a and b, the equivalent duct diameter is equal to t ab 4 Discharge Duct Outlet Area Fan Housing Cutoff Blast Area Area 25% 50% 75% 100% Effective Duct Length To calculate the effective duct length assume a minimum 2.5 duct diameters for each 12.5 m/s and add 1 duct diameter for each additional 5.0 m/s Example: 25 m/s = 5 duct diameters. If the duct is rectangular with side dimensions a and b, the equivalent duct diameter is equal to t ab 4 BASIC MINE VENTILATION UNDERSTANDING FANS Page 112 © AMC Consultants Pty Ltd 2005 6.12 Exhausting Fans The figure below shows the side tube and facing tube measurements for a suction (exhausting) fan (as installed for most mine primary ventilation). From these measurements we can determine the fan pressures. In this case, the static pressure at the fan outlet (SP 0 ) would equal zero. Since TP = SP + VP And SP 0 = 0 Then TP O = VP O By definition FSP = FTP FVP And by substitution FSP = (TP O TP I ) - VP O Since TP O = VP O Then by substitution FSP = VP O - (TP I ) - VP O =- TP I = - 2580 Pa Therefore, a facing tube measuring the inlet total pressure of an exhausting fan is equal to the FSP. Now as SP I = TP I - VP I And TP O = VP O = VP I (no change in diameter) then by substitution SP I = TP I TP O Rearranging SP I = TP O - TP I and as TP O - TP I = FTP then FTP = -SP I = -(-2000) = 2000 Pa Therefore, a side tube measuring the static pressure of an exhausting fan is equal to the FTP (fan total pressure). Examples (Qi) The following measurements were recorded at a surface fan installation exhausting air from a mine. Determine the FSP, FVP and FTP. Total Pressure 1200 Static Pressure 1800 (Ai) Both measurements would be negative ie. on the suction side of a fan. FSP = -1200 Pa FTP = -1800 Pa FVP = VP O = VP = (-1200)-(-1800) EXHAUST FAN Ducted inlet, free outlet TP= -2580 Pa SP= -2600 Pa EXHAUST FAN Ducted inlet, free outlet TP= -2580 Pa SP= -2600 Pa BASIC MINE VENTILATION UNDERSTANDING FANS Page 113 © AMC Consultants Pty Ltd 2005 = -1200 + 1800 = 600 Pa Note Velocity Pressure is always positive. (Qii) The following measurements were made downstream of a development fan in a 1200 mm diameter duct at a site 4 duct diameters from the fan discharge. No duct was installed upstream of the fan. Average velocity pressure 480 Pa Duct Static Pressure 2500 Pa Determine the FSP. (Aii) In a pressure system the FSP is equal to the static pressure of the duct. FSP = SP 0 = 2500 Pa less the frictional pressure losses in the duct. Duct area = t 2 2 2 . 1 | . | \ | = 1.13m 2 Duct Perimeter = t1.2 = 3.77m Assume K = 0.003 Then R = ( ) ( ) 3 13 . 1 2 . 1 4 77 . 3 003 . 0 × × × = 0.037Ns 2 m -8 Velocity of airflow ȡ VP 2 = 2 . 1 480 2 × = = 28.3m/s Airflow = V x A = 28.3 x 1.13 = 32m 3 /s and P = RQ 2 duct losses = 0.037 x (32) 2 = 37.8 = Say 40Pa Fan SP = 2500 40 = 2460 Pa 6.13 Air Power Air power is the energy required to move a specific quantity (Q) of air over a specific resistance and can be calculated from Q P AP × = Equation 6-4 Air Power Where AP = Air Power (watts) BASIC MINE VENTILATION UNDERSTANDING FANS Page 114 © AMC Consultants Pty Ltd 2005 P = Pressure (Pa) and also = N/m 2 Q = Quantity of air (m 3 /s) Substituting P x Q = N/m 2 x m 3 /s = Nm/s and 1 Nm = 1 Joule and 1 Joule/second = 1 watt therefore AP = watts Example A fan requiring 1500Pa to move 400m 3 /s of air has an air power of AP = 1500 x 400 = 600,000watts 6.14 Fan Efficiency Fan efficiency is important as it determines the cost of power necessary to operate the fan. For example a primary ventilation fan providing 250m 3 /s at a pressure of 2000Pa will absorb 667kW of electrical power when operating at an efficiency of 75% and only 588kW when operating at an efficiency of 85%. Power costs at remote mine sites can be as high as $0.17/kW hour, therefore over one year the savings are considerable. In this case $116,800 each year of operation. The efficiency (q) of the fan is calculated from the equation W P Q× = q . In this equation W is the impeller power measured with a swinging frame dynamometer. Because suitable dynamometers are not readily available this is usually measured as the motor input power (MIP). The multiplication of air quantity (Q) and pressure (P) results in the power exerted to the air and is simply termed Airpower (AP). The equation for fan efficiency (q) is therefore usually written as MIP AP = q The efficiency of any fan can be expressed as either Fan Total Efficiency (FTE) where the FTP is used to determine the Airpower, Fan Static Efficiency (FSE) where the FSP is used to determine the Airpower, and the Fan Overall Efficiency (FOE). In the case of FOE this includes losses in the electric driving motor, any speed change device between the motor and the impeller and any other source of power. Caution must be used when interpreting fan curve efficiency. Some curves show static efficiency. Others show total efficiency. Of particular interest to ventilation practitioners is the overall fan efficiency as this determines the final electrical input power to the motor. 100 (MIP) Power Input Motor Power Air FOE × = This is often mistaken as the Static or Total efficiencies that do not include the power losses for gearboxes, motors etc. BASIC MINE VENTILATION UNDERSTANDING FANS Page 115 © AMC Consultants Pty Ltd 2005 Example Determine the FSE and FTE for a mine exhausting fan delivering 300m 3 /s of air. The fan inlet total pressure has been determined as 1500Pa and the Inlet Static pressure as 2000Pa. The motor input power is 700kW. For an exhausting fan FSP = Total Pressure measured at the Fan Inlet = 1500Pa Overall FSP efficiency MIP AP FSP = 700 300 500 . 1 × = 700 450 = = 64% and FTP = Static pressured at the fan outlet relative to atmosphere = -(-2000) = 2000Pa Therefore the Total Efficiency MIP AP FTP = 700 300 000 . 2 × = 700 600 = = 86% 6.15 Measurement of Airflow The most common methods used to determine airflow in ducts is with an anemometer or a pitot- static tube. Anemometers are used most often in walk-in airways with velocities between 0.2m/s and 14m/s. Fan ducts usually require the use of a pitot static tube, as velocities can be greater than 25m/s. The velocity at a point is calculated from the equation for velocity pressure µ = VP 2 v The velocity in a duct will vary from point to point and the more points measured (on a designed basis) the more accurate is the result. The duct is divided into equal areas and a measurement made at the centre point of each area. The Velocity at each point is calculated and the arithmetical average of all sections is determined and used as the duct velocity. The airflow quantity is determined by A * v Q = The figure below shows measuring sites in circular and rectangular ducts derived from the British Fan Test Code. BASIC MINE VENTILATION UNDERSTANDING FANS Page 116 © AMC Consultants Pty Ltd 2005 The Australian Standard AS 2936 does not identify sites for rectangular ducts and for circular ducts shows 8 or 10 measuring sites on 3 diameters, as opposed to the 4 diameters in the British Standard. The 8-point measuring system is for general use with the 10 measuring point system used for swirling flow in circular ducts Measurement Distances for Pitot Static Tube in Circular Ducts 8 Point System 10 Point System 0.021d 0.019d 0.117d 0.077d 0.184d 0.153d 0.345d 0.217d 0.655d 0.361d 0.816d 0.639d 0.883d 0.783d 0.979d 0.847d 0.923d 0.981d Note d = diameter BASIC MINE VENTILATION UNDERSTANDING FANS Page 117 © AMC Consultants Pty Ltd 2005 6.16 Fan Laws Fan performance curves are determined for a specific speed and density. If density for a fan curve is not shown it can be assumed as standard air (1.2 kg/m 3 ). Standard air is a definition of convenience that is widely adopted. The actual values of temperature, pressure and moisture content are not important. Should the diameter, speed or density of the fan inlet air be altered, the following fan laws will apply. 6.16.1 Density (µ) Change Quantity (Q) 2 1 Q Q = Pressure (P) 2 1 2 1 P P µ µ = Power (kW) 2 1 2 1 kW kW µ µ = Efficiency (q) 2 1 q = q 6.16.2 Speed Change Quantity (Q) 2 1 2 1 rpm rpm Q Q = Pressure (P) 2 2 1 2 1 rpm rpm P P | | . | \ | = Power (kW) 3 2 1 2 1 rpm rpm kW kW | | . | \ | = Fan total efficiency (q) q q 1 = 2 6.16.3 Diameter Change When the diameter (D) is increased and the fan is geometrically similar the following laws apply: Quantity (Q) 3 2 1 2 1 D D Q Q | | . | \ | = Pressure (P) 2 2 1 2 1 D D P P | | . | \ | = Power (kW) 5 2 1 2 1 D D kW kW | | . | \ | = If the size difference is great then it can be expected that the fan total pressure may be larger than that given by these laws (scale effect). BASIC MINE VENTILATION UNDERSTANDING FANS Page 118 © AMC Consultants Pty Ltd 2005 It is also possible that a change in density due to compression of the air will occur affecting the results from the use of these laws. This is normally only of concern at pressures above 2.5 kPa. This is discussed more fully in Woods Practical Guide to Fan Engineering or Fan Engineering published by the Buffalo Forge Company. These laws should be used with caution as they are not applicable to all fans. Example A 1000m diameter fan tested at 1380 rpm and an inlet airflow density of 1.16 kg/m 3 gave the following results, Quantity (Q) = 20 m 3 /s Pressure (P) = 1520 Pa Power (kW) = 40 kW What is the expected operating performance at 1470 rpm at standard air inlet density of 1.2 kg/m 3 . From equations in sections 6.16.1 and 6.16.2 Note that density change has no affect on the quantity. 2 1 2 1 rpm rpm Q Q = Therefore Q 2 = 1380 1470 20 × = 21.3 m 3 /s The pressure change can be calculated by combining the effects of density and speed changes. 2 2 1 2 1 rpm rpm P P | | . | \ | = and 2 1 2 1 P P µ µ = Therefore | | . | \ | µ µ | | . | \ | = 2 1 2 2 1 2 1 rpm rpm P P And P 2 = | . | \ | | . | \ | × 16 . 1 2 . 1 1380 1470 1520 2 = 1790 Pa The change in power change can also be calculated by combining the effects of density and speed changes. 2 1 2 1 kW kW µ µ = and 3 2 1 2 1 rpm rpm kW kW | | . | \ | = Therefore | | . | \ | µ µ | | . | \ | = 2 1 3 2 1 2 1 rpm rpm kW kW BASIC MINE VENTILATION UNDERSTANDING FANS Page 119 © AMC Consultants Pty Ltd 2005 And kW 2 | . | \ | | . | \ | × = 16 . 1 2 . 1 1380 1470 40 3 = 50 kW 6.17 Fans Failure Fan failure is more often than not caused by: a) Poor preventative maintenance including regular cleaning of guide vanes and impellers, b) Unrecognised increasing fan pressure caused by increasing mine resistance, c) Rocks and other foreign materials are often found in fan housings and simple things like rags, plastic etc. can become caught on an impeller, d) An accumulation of dust and salts on impellers may also cause the fan to run out of balance, All of which cause the fan to run out of balance. If a fan is allowed to run for extended periods while out of balance it can potentially cause bearing failure and fatigue cracking in either the impeller, the shaft or the fan casing. 6.18 Effect of Reversal of Rotation 1. An axial flow fan will deliver a reduced volume of air in the opposite direction at a greatly reduced pressure and efficiency, particularly if aerofoil blades are used 2. A centrifugal fan will deliver a reduced volume in the same direction at a greatly reduced pressure and efficiency There is often suggestion that fans can be reversed in times of emergency to reverse the direction of flow in the mine. Although this is true the fan performance is significantly reduced. This could be 70%. BASIC MINE VENTILATION UNDERSTANDING FANS Page 120 © AMC Consultants Pty Ltd 2005 Before attempting this in an emergency the final affect must be completely understood and more importantly tried, tested and evaluated long before it becomes part of any emergency procedure. BASIC MINE VENTILATION MANAGEMENT Page 121 © AMC Consultants Pty Ltd 2005 It remains for me to speak of the ailments and accidents of miners and the methods by which they can guard against these, for we should always devote more care to maintaining our health, that we may freely perform our bodily functions, than to making profits. Agricola - De Re Metallica (1556) 7 MANAGEMENT There has been significant change in underground metalliferous mine design and operations over the past ten to fifteen years. Hoisting shafts are now rare in all but very deep, high tonnage operations. In most mines, all ore and waste is brought to the surface in diesel trucks. More diesel equipment per tonne of ore is therefore required. The use of ancillary diesel equipment (e.g. cable bolting, mechanical scaling, charge-up secondary breaking and shot-creting equipment) is increasing. There is a greater prevalence of mining methods that require little permanent development apart from the decline. This has made the establishment of appropriately placed primary ventilation infrastructure difficult and increased the reliance on secondary ventilation techniques. The regulatory framework has changed and is now much less prescriptive. Instead of designing to satisfy minimum statutory requirements, there is now much more reliance on the principle of an employers duty of care. There has been a dilution of technical expertise brought about by a number of factors, including the recent rapid growth in the industry. As a result, there is an increasing requirement for ventilation systems to be simple, robust and reliable so that minimal intervention or management is required. Mine ventilation practice has had to evolve to keep pace with these changes. And many long established rules of thumb are now no longer appropriate. Of all the ventilation problems encountered in mines, the vast majority are caused by higher than acceptable concentrations of smoke, dust and heat. Smoke reported during the shift is generally from poorly tuned and/or maintained diesel engines. Dust is almost always from handling of dry broken rock, drilling and raiseboring operations. Increases in temperature are due to change in ambient surface conditions or ventilation flows being reduced (changes due to rock temperatures should be well recognised long before they cause problems). Identification of the source of the contaminant provides the opportunity to control the problem at this point. However, solutions of this type are more often than not met with resistance from production and maintenance personnel. Most cases are resolved by a compromise between removing the source and increasing the airflow. In those situations where the source cannot be successfully controlled, for whatever reason, then rescheduling of activities may remove the symptoms and allow work to continue. Unfortunately it is only the most severe cases of undesirable conditions that are adequately dealt with and the others are allowed to continue because we will be out of there soon. As a consequence operators are usually only looking for a quick fix. Of all the problems identified the solutions could quite easily be found in the Top Ten Solutions below 1. Holes in auxiliary ventilation duct BASIC MINE VENTILATION MANAGEMENT Page 122 © AMC Consultants Pty Ltd 2005 2. Excessive tees NOT tied off 3. Fan re-circulation 4. Poor fan selection 5. Leaking ventilation walls 6. Poor primary airflow distribution (caused by incorrectly adjusted and/or lack of controls) 7. Lack of dust control measures when loading and transporting broken dirt 8. Short-circuiting of air through stope voids, ore passes and disused vertical openings. 9. Activities and diesel equipment has outgrown the original ventilation system design. 10. Poor records of airways (particularly vertical openings), dimensions, development method, location and purpose All are problems that could (and should) have been avoided by better planning and management. 7.1 Primary Airflow Requirements There are many Rules of Thumb (ROT) and a few empirical equations that have been developed to estimate the airflow requirements for mines. Some are realistic and based on recent mechanised mines but many are unrealistic and based on older non-mechanised mines. All are based on past experience. There use is acceptable as long as they are taken exactly for what they are that is an idea of the magnitude of the result that will be achieved by calculation. Some time the results will be surprisingly close to a calculated result and many times it will be way off the mark. Determination of the primary airflow requirement is the starting point for ventilation design. The design airflow needs to be known before the required number, and size of surface ventilation shafts can be estimated. Design primary airflow requirements are almost always under-estimated, probably due to the use of ROT or some empirical equation, but also due to a failure to allow for increases in mine size, depth and complexity beyond initial estimates. Even then the cost of providing the necessary airflow under-goes pruning in an effort to keep project capital and operating costs to the minimum. Under-estimated (or reducing) primary airflow rates will adversely affect the project economics in the following ways: Operating Costs: Power costs increase dramatically with airflow rate. If airflow rates need to be increased beyond initial estimates, there will be a substantial increase in operating costs, particularly if airways are inadequately sized: 3 Rate Flow Old Rate Flow New Increase Cost Power | | . | \ | o Capital Costs: An increase in airflow rate may require the purchase of new fans and excavation of new airways. The cost and just as importantly the disruption to mining in doing so are usually considerably greater than would be the case if the original airways sizes were based on realistic primary airflow estimates. 7.1.1 Determining Primary Air Quantities. When estimating primary airflow requirements, we need ask ourselves why ventilation is being provided in the first place. In many cases, in mechanised mines the criterion for dilution of diesel exhaust emissions is the overriding factor. It is however also necessary to consider equally BASIC MINE VENTILATION MANAGEMENT Page 123 © AMC Consultants Pty Ltd 2005 relevant requirements such as control of thermal conditions and adequate dilution of dust and mine gasses. Analysis of airflow requirements for individual work places is usually carried out when determining primary airflow requirements. Design airflow rates are often based on exceeding 0.04 to 0.06 m 3 /s of airflow per rated kW of diesel engine power in all active mining areas. This analysis can become quite complex for larger operations and requires a thorough understanding of the individual facets of the development and production process. The design airflow rate must include an allowance for leakage (both primary leakage and leakage in secondary ventilation ducts) and service areas such as ore passes, grizzlies, crushers, conveyor drives, fuel bays, pump stations, workshops etc. The first process is to work with the designers and schedulers to allocate air quantities and with consideration to predicted heat loads, strata gas emissions, diesel exhaust emissions, legislation, OH&S and Industrial relations to allocate airflow requirements for; Location Airflow required for Scheduled production activity Drilling, blasting, loading, filling. Equipment in use in each area Dimensions and layout of access and loading routes Scheduled development activities Equipment in use in each area Dimensions and layout of access and loading routes Auxiliary ventilation system Haulage routes Equipment in use in each area Dimensions and layout of access and loading routes Rock handling including: Rock breaking Crushing, Loading station, Hoisting Equipment in use in each area Dust dilution/collection/removal Operator protection Servicing areas including: Maintenance workshops, Electrical sub- stations, Pumping stations, General maintenance and construction work areas, Refrigeration plants Equipment in use in each area Dust & fume dilution/collection/removal Fire protection Operator protection Storage and supply areas: Explosive, Diesel fuel, General consumables and stores Equipment in use in each area Dust & fume dilution/collection/removal Fire protection Operator protection Lunch rooms and waiting areas Airflow Temperature Obviously not all of the above locations/activities will apply to all mining operations. Circuit design is ultimately determined by the production schedule. The siting of dedicated ventilation airways will be determined by mining methods and production design layouts. The determination of total mine airflow is only the first step toward a mine ventilation system and requires the most attention because it is at this point that the final and cost to the operation will be determined. Ventilation planning and design is complicated and those who are responsible for ventilation and believe otherwise have the potential to cost their organisation a great deal of money. Example Lets consider a new narrow vein mine with an optimum production rate of 300,000 tonnes per year. It has been decided that predominately one pass ventilation will be required. Ore will be loaded from the stope to an orepass from where it will be trucked in the main decline out of the BASIC MINE VENTILATION MANAGEMENT Page 124 © AMC Consultants Pty Ltd 2005 mine. Backfill will delivered to the stope void using a 10 tonne truck. Assume a ROT for narrow vein mechanised mine to be 0.5 m 3 /s per 1000 tonne. (0.5 x 300 = 150 m 3 /s) The production and development schedule has been evaluated and the active locations during each month have been determined. In this case an active location is taken as any development face, raise bore location, production drilling location, production bogging location or stope filling location. The number of active locations during any one-month is then summed. For this example assume the results shown graphically below. Active Locations 0 20 40 60 80 100 120 140 160 0 6 12 18 24 30 36 42 48 54 60 Month N u m b e r Development Raisebore Mining Backf ill After consideration to diesel exhaust emissions, dust and heat etc. the air quantities for each activity have been determined as: Activity Airflow (m 3 /s) Decline development 80 In ore Development 12 Production 5 Raiseboring 5 Backfill 8 This airflow was then allocated to the respective activity and summed for each month. This particular schedule will require primary airflow ranging from 80 m 3 /s during initial development peaking at 227 m 3 /s during the start up of production then tapering off to less than 50 m 3 /s toward the end of the scheduled period. BASIC MINE VENTILATION MANAGEMENT Page 125 © AMC Consultants Pty Ltd 2005 Airflow Requirements 0 50 100 150 200 250 6 12 18 24 30 36 42 48 54 60 Month Q u a n t i t y ( m 3 / s ) Development Raiseboring Mining Backf ill Initial Development Production Start up Production Production Taper 191 m 3 /s 157 m 3 /s There are four distinct periods that require some comment. 1. Initial development (month 1 to 12) to establish the access decline and the exhaust ventilation shaft will be ventilated with secondary fans and will not form part of the primary ventilation requirements. 2. Production Start-up (month 13 to 18). The peak airflow during this period is 227 m 3 /s. This peak at the end of initial access development and the commencement of production is common. This occurs because of the flurry of activities necessary to bring the mine into full production in as short a time as possible. The difficulty of this period is the cost for providing extra air when it is not required over the longer term. Most designers opt to bypass this period and attempt to manage their way through it. (Not a good time to be the ventilation officer). The alternative is to purchase and install primary fans with some form of control that will enable the airflow requirements to be turned down after production settles down. 3. Main production period (month 19 to 46). In a new mine there will be teething problems and the production and development schedules will undergo constant updating before eventually settling down. With input from the ventilation engineer the airflow peaks and troughs will be smoothed settling somewhere around the median of 160 m 3 /s. (Always round UP its hard enough to get so dont give it away). 4. End of the life of the project (month 47 onwards). A detailed mining schedule is only valid until the next update. Any schedule beyond three years should be viewed with some scepticism. Because of increasing geological information, changing economics etc most mine schedules beyond year three do not have the same confidence level contained in the three-year plan. Because of the very nature of mining there will be an end and the tapering off period will vary from mine to mine, and year to year. 7.2 Primary Ventilation Fans Primary ventilation fans are found in many different sizes, types and locations. For example they could be any combination of - Forcing or exhausting. - Axial or centrifugal. - Single or multiple fans. BASIC MINE VENTILATION MANAGEMENT Page 126 © AMC Consultants Pty Ltd 2005 - Single or multiple shafts. - Horizontal or vertical mounted. - Horizontal or vertical discharge. - Surface or underground. Each has their advantages and disadvantages. Some are designed to meet predicted requirements and some are found lying around and installed in the hope that they will provide the necessary airflow. The preference of any particular combination is usually a matter of individual choice driven by past experience, environmental issues and capital cost. Most fans are selected to meet the immediate short-term budget and not the long-term future ventilation requirements of the mine. Because of this they are not suitable for the life of the mine and have to be either upgraded or replaced both very expensive options. 7.2.1 Surface Fan Installation Arrangements Primary ventilation fans are arranged in many different ways some of which are depicted in the figure below. BASIC MINE VENTILATION MANAGEMENT Page 127 © AMC Consultants Pty Ltd 2005 7.2.2 Underground Primary Fan Arrangements Primary ventilation fans may also be installed underground. The underground locations could be at the bottom of the shafts or at some intermediate point between the surface and the bottom of the mine. Although underground fans installations are predominantly the axial flow type, centrifugal are also used. The use of primary fans installed underground has generally been avoided for a couple of reasons: 1. Excavation and preparation of the site is costly. 2. If the fan fails access for repairs is restricted because the only ventilation flow is from the natural ventilation pressure. 3. Construction is more difficult as the use of large mobile cranes is restricted. 7.2.3 Forcing or Exhausting The vast majority of primary fans installed in Australian mines are located on the surface to exhaust air from the mine. The choice of location is usually made as a matter of convenience rather than any specific engineering aspect. For example a simple mine will have one primary intake airway (be it shaft or decline) and one primary exhaust shaft. Exhaust shafts are by their very nature dirty and the air contaminated with dust and fumes making it undesirable for the movement of men and equipment as it is much more desirable to enter the mine in clean intake air. If the fan is installed in the intake airway it limits the accessibility to the shaft for the movement of men and equipment. 7.3 Circuit Booster Fans Circuit booster fans are used to alter the pressure distribution and supply ventilating air to specific areas of the mine. They are often necessary when a mine has BASIC MINE VENTILATION MANAGEMENT Page 128 © AMC Consultants Pty Ltd 2005 Stope Advance Stope Void been developed below the mining area defined in the original mine designs. They are also misused in many mines as a method to supply air to areas of mines in an attempt to counteract the poor management of the primary ventilation circuit. Poor selection of fan location and capacity has potential to create more problems that they solve. For example they may result in recirculation of large quantities of air, as they tend to pressurise the exhaust system forcing the out to flow back into the primary intake airflow. 7.4 Primary Ventilation Circuits Primary ventilation circuits are designed to supply fresh air to workplaces and dilute and remove contaminants resulted from the mining processes. The time required to flush blasting contaminants from the mine can range from a few minutes up to many hour. The effective and timely removal of contaminants particularly after blasting is high on the priority lists for mine managers, as time lost on production waiting for fumes to clear is very costly. There are two basic circuits used 1. Parallel circuits, and 2. Series circuits. Both have their advantages and disadvantages and many mines use a combination of both circuit types. 7.4.1 Parallel (One Pass) Circuits Parallel circuits adopt a general design philosophy of one pass, flow through air. This concept ideally lends itself to large tonnage stopes or stoping blocks and may not be suitable for use in some narrow vein steeply dipping orebodies. In this situation, a circuit is established to direct air from the primary intake circuit over the areas of activity and exhaust directly to the return air circuit. It is usual for return air circuits to be areas requiring minimal access and therefore all contaminants are removed directly from the mine. This is particularly important in the event of a fire occurring in the work place as it minimises the areas (and personnel) affected by the smoke, gases and particulates. With multiple level accesses, it is necessary to control the air entering the activity area (usually by regulation of the exhaust). The down side of this To Primary Exhaust To Primary Exhaust TYPE A: End Access TYPE B: Central Access Not Longer Than 250m BASIC MINE VENTILATION MANAGEMENT Page 129 © AMC Consultants Pty Ltd 2005 type of circuit is that short-circuiting occurs each time a stope is opened or a ventilation control is damaged. Whilst providing improved conditions in work areas, these circuits also decrease re-entry times but only if the access does not form part of the return air circuit. It is usual to provide airflow to all scheduled production locations, even when not in use. This provides flexibility to move from one location to another without the necessity to adjust ventilation circuits. Mine operators often plan to minimise total airflow by campaigning air from one location to another, however experience tells us that this seldom, if ever, occurs and all locations operate with less than desirable airflow rates. For this type of circuit to be successful, ventilation controls must be well maintained. 7.4.2 Secondary Fans and Parallel Ventilation Circuits. Because of the geometry of narrow vein orebodies, it may prove difficult to maintain the philosophy of flow through ventilation without the need for extensive development and therefore the use of secondary fans during production must be considered. This type of circuit is normally adapted to narrow vein orebodies with long strike lengths. LHD tramming distances are usually kept below 250m. In these circuits, air intakes via the access (decline) and is returned to the primary exhaust at each orebody access. 7.4.3 Series Ventilation Circuits A system most often used in narrow plunging orebodies, is a simple series ventilation circuit. These circuits rely on secondary fans to ventilate in orebody development and production with the return air from these activities being mixed with the primary intake airflow and re-used at the next activity. This type of circuit has the advantage of simplicity of control and minimal development for ventilation. Although the utilisation rate (total airflow to the working areas / total airflow through the mine) can be as high as 75%, it is typically 65% with 40% not uncommon. These circuits have disadvantages including (but not limited to): - The need for high pressure fans (hence higher power costs), - Low fan power efficiency for the majority of the operating period (the fan only operates at maximum efficiency in a fully developed mine). - Decreasing airflow with depth, and - Contaminants from activities (and fires) affect all down stream personnel. Although not encouraged, it is recognised that this is the system used in development areas and in reality will continue to be used in some production areas. 7.4.4 Use of Stope Voids as Airways There is often a misconception that stope voids will upcast airflow causing much frustration when the air downcasts through the stope. Because stope voids form connections between levels they create airways parallel to the ramp or intake shaft. Generally the pressure distribution is such that the air in the ramp (intake system) is down casting and it follows that the air in the stope will also downcast air. Obviously if the air in the ramp is up casting then it follows that the air in the stope void will also upcast. BASIC MINE VENTILATION MANAGEMENT Page 130 © AMC Consultants Pty Ltd 2005 If stope voids are required to up cast air, then it is necessary to design and install the appropriate ventilation controls to cause the pressure distribution required. In general, if stope voids are required to upcast, the primary return airway must not be lower than the top of the stope void. The reliance on stope voids also has the high probability of production blasting covering the stope brow thus preventing flow through ventilation. 7.4.5 Recirculation Recirculation occurs when air is kept within a closed circuit. It should not be confused with the situation when air is reused, as in series ventilation circuits. Recirculation occurs when a fan is installed in an airway in which the natural flow of air along the airway is less than the operating capacity of the fan. In some Australian legislation there is a requirement to install secondary fans such that the air delivered to the fan is greater than 1.3 times its open circuit capacity. This legislation was introduced in times when small drives (2.0m x 2.0m) and low capacity fans (5 to 7 m 3 /s) were common. As a general Rule of thumb an airflow of at least 1.5 times the open circuit capacity of the fan is required in airways with large cross sections and higher capacity fans. Even then minor recirculation is possible, depending upon the siting of the fan in the airway. Although not recommended, some minor recirculation may be acceptable provided the, work place temperature, contaminants in the airflow and the clearing time for blasting gasses remain within acceptable levels. 7.5 Ventilation Controls Regulators commonly used in Australian mine are rectangular openings in walls that are open or closed by the placing or removal of boards. Other less common regulators are the louvre type (either vertical or horizontal), or a sliding door (again either vertical or horizontal). It is normal for persons to open or close a regulator in order to increase or decrease airflow to a certain area. Sometimes this is meet with much frustration because the desired airflow cannot be achieved. This frustration is a result of the lack of understanding of the pressure distribution across the mine and the fact that altering one regulator effects the WHOLE mine distribution and not just the area being adjusted. There is often an attempt to compare the opening in a wall to an orifice (vena contracta). In a perfect orifice the opening is circular and relatively small compared to the plate (wall), which is very thin. As the air flows through the opening it converges and at a distance equal to half the orifice diameter the jet is at its smallest area. This area is called the vena contracta and at this point the velocity of the air is 1.613 times greater than in the orifice itself. At the vena contracta the velocity pressure is 1.613 2 or 2.5 times higher than the orifice. Using the equation for velocity pressure 2 v VP 2 µ = and knowing the velocity we can determine the velocity pressure. Similarly if the pressure across the plate is known, then the velocity in the area of vena contracta can be determined and we can back calculate the area of the orifice. Considering a mine regulator, the wall thickness can be proportionally greater BASIC MINE VENTILATION MANAGEMENT Page 131 © AMC Consultants Pty Ltd 2005 than the thin orifice plate and the ratio of the area of the opening to the area of the wall is different and this affects the coefficient of contraction (1.613) that becomes larger as opening increases in size forming an increase in percentage of the opening to the airway wall. For any calculation to be reasonably accurate the area of the regulator should be no greater than one- tenth the size of the airway in which it is constructed. To estimate the area, quantity or pressure at a regulator the following algorithm can be used P Q 2 . 1 A µ = Equation 5 Area of a Regulator opening Where A = the area of the opening (m 2 ) Q = Quantity of airflow (m 3 /s) P = Pressure across the opening (Pa) µ = Density of the air flowing (kg/m 3 ) Like the calculation of shock losses in practice there are so many unknown factors that the calculated result is seldom correct and further adjustment is required. In practice the airflow through regulators is set by trial and error until the desired, or at least close to the desired result is achieved. It is often the case that operators, to gain increased airflow, adjust regulators. Although they achieve their desired result it is more often than not that they have caused a detrimental effect else where in the mine. All adjustment to regulators should only be undertaken once the airflow distribution across the mine has been planned and scheduled as it may be necessary to adjust more than one opening to achieve the desired result for all areas. The suggested method for any adjustment programs it to go to the bottom of the mine (lowest pressure area) and fully open this regulator. All other adjustments are then made to this opening. Commence adjustment (setting the desired airflow) at the top of the mine (highest pressure) and progress to the bottom of the mine (lowest pressure). By the time you get to the lowest regulator a measurement of the airflow should show that the airflow is around the quantity required. 7.6 Multiple Access Orepasses Multiple access and uncontrolled orepasses will, when empty, form an airway parallel to the decline potentially reducing the airflow on the decline to unacceptable levels. In addition to short-circuiting airflows, multiple access orepasses are often a significant source of dust. As rock falls down the pass it generates dust and acts like a pump compressing air in the pass and forcing it out on to each open sub-level below. Efforts to prevent this by creating a positive airflow into the ore pass from all access points are generally unsuccessful. The problem is best managed by sealing, if necessary with temporary seals, all but one of the tipping points. ALL other openings should be sealed or otherwise connected to the RAR system via a dedicated airway. 7.7 Secondary Ventilation Systems There are three predominant secondary ventilation systems used. 1. Forcing, 2. Exhausting and 3. Exhaust overlap BASIC MINE VENTILATION MANAGEMENT Page 132 © AMC Consultants Pty Ltd 2005 Forcing ventilation system is the predominant system used in hard rock mines. These systems provide advantages including - The fan is located in clean intake air making it accessible for maintenance for maintenance and repair - Allows the use of flexible ventilation ducting (less expensive than rigid ducting) Exhaust ventilation systems require the use of rigid ducting and because of the extra cost involved with the purchase and installation of rigid ducting, systems of these types are seldom used in development headings in hard rock mining. However, it is the accepted practice in coalmines and many tunnelling operations that use cutting or boring machines. Re-entry times may be reduced by the use of an exhausting or exhaust overlap ventilation system where the air is removed via the ducting allowing immediate re-entry to the face in fresh air. Although not commonly used this system has benefits when developing long drives. In its original concept the exhausting fan was slightly larger than the forcing fan, was installed clean air and used rigid ducting. This allowed air to flow in the overlap position and prevented re- circulation. Because of the cost of rigid ducting as opposed the less expensive flexible type this arrangement lost favour. In recent times it has been adapted for use using flexible ducting and two exhausting fans. The use of two exhausting fans was simply to standardise the fans being used. Because the fans are located in the developing heading if the was to be a power failure to both fans then repairs are restricted until the area is ventilated by another fan. It is also inconvenient to move the position of the overlap as it is necessary to remove and relocate the exhausting fans. 7.7.1 Installing Secondary Ventilation Fans Auxiliary ventilation fans are a fact of life and used in ALL mines yet they are still installed where it is convenient rather than where it is best suited. Poor location of auxiliary fans will result in recirculation of air and obviously recirculation of contaminants with the resultant less than desirable conditions at the working face. In most cases once the fan is installed it is seldom relocated, no matter how bad conditions become. There have been instances where fans have been poorly located to the extent that the recirculation is almost 100%. This can go undetected simply because the fan is running and you can feel the breeze at the face. BASIC MINE VENTILATION MANAGEMENT Page 133 © AMC Consultants Pty Ltd 2005 The ultimate reason that fans recirculate is the lack of air flowing passed the fan inlet. This can occur for three reasons: 1. There is insufficient airflow in the drive, 2. The fan is to close to the exhaust 3. The seal around the fan is damaged. One of the simplest means for detecting recirculation is to use a smoke tube (particularly near the backs) to check the direction of the exhausting airflow. Sometimes it is extremely difficult to get close enough to the backs and it will be necessary to undertake measurements of air flowing in the drive and in the duct down stream of the fan. In all cases the airflow in the drive must be greater than the airflow in the duct. In general auxiliary fans should be located approximately 20m upstream of the drive they are ventilating, and there is a rule of thumb that the airflow passed the fan should be 1.3 to 1.5 times the open circuit capacity of the fan. If one or both of these factors does not apply the fan must be sealed into and appropriate airway to prevent any re- circulation. Many mine designs now incorporate the return air rise (RAR) adjacent to the intake air decline. This allows contaminated air to be exhausted from the mine without being reused. (See Secondary Fans and Parallel Ventilation Circuits above). In many of these cases the truck is loaded near the stockpile bay adjacent to the RAR and care must be taken to ensure that there is a flow of air in this area. In the same way that the exhausting fans are sized to cause a flow in the overlap, a flow must be caused between the fan and the exhausting point. If this is not achieved the truck loading area very quickly becomes contaminated with high concentrations of dust and diesel exhaust emission. Some options are shown in the figure opposite. 7.7.2 The Reuse of Air As discussed above, it is an acceptable practice to reuse ventilating air. The success or otherwise of this practice in force ventilated areas lies in the correct selection and location of secondary fans. Many attempts are made in development areas to install multiple BASIC MINE VENTILATION MANAGEMENT Page 134 © AMC Consultants Pty Ltd 2005 parallel fans in an effort to get extra fresh air to the working faces. In the vast majority of these installations the airflow passed the fans is insufficient, resulting in the recirculation of the return air through the fans. The final result is increased heat and contaminants in the working areas. There are a number of solutions the obvious ones being, increase the primary intake air, only operate one fan at a time, construct a seal around the fans to prevent the recirculation. Only increasing the primary airflow would not restrict the flexibility of multiple workplaces or cause some interference with activities in the area. Another solution is to relocate one of the secondary fans. 7.8 Ventilation Duct. Flexible ventilation duct is an extremely versatile and convenient method of providing secondary ventilation. Unfortunately, its limitations are very poorly understood. Some practical tips for installation include: - The largest possible ventilation duct size should be used to lower resistance and hence reduce leakage. In almost all cases, using duct size which is smaller than the fan diameter is not acceptable. - No one seems to get particularly concerned with holes and rips in ventilation duct. Like BASIC MINE VENTILATION MANAGEMENT Page 135 © AMC Consultants Pty Ltd 2005 compressed air leaks, the very high cost of these problems are often not appreciated, or are simply ignored. It is a common experience to almost have ones head blown off by leakage from a ventilation duct near the fan and to then be asked why there doesnt seem to be much flow at the face. - The importance of ensuring adequate clearance between mobile equipment and the duct is also not clearly understood. This wasnt the case in the old days when steel duct was used! The equipment and drive size must be selected so that there is no chance of the duct being hit. - The importance of installation standards is also not often appreciated. The knocker line must be hung straight from lined up attachment points (not from the nearest convenient split set). Sharp corners require the use of specially manufactured elbow pieces. Every eyelet must be used when connecting Lo k® or similar joints. Care must be taken to ensure that Minsup® clips are not left in the ends of ventilation duct when new bag is connected. The last one or two ventilation ducts should be sacrificial face bags to avoid the rest of the duct sustaining blast damage. - There seems to be a common belief that an unlimited number of T pieces can be connected to a ventilation duct and left open. This is incorrect. There is usually only sufficient flow to ventilate one face, possibly two and all other T pieces should be tied off. - There is a perception that more air can be supplied to the face by using a more powerful fan. With electrical power costs of 10¢ per kWh, and 170 kW power draw, a fan would consume $149,000 per annum in power costs. It is not unusual to find 1400 mm diameter fan and duct installations, which over 500 m deliver only 7 m 3 /s to the face! This is insufficient flow for even one LHD. For comparison, 23 m 3 /s can be delivered, with very well installed 1,200 mm low leakage ducting using a 1,200 mm diameter, 110 kW fan. - Use of the low leakage ducting described above can also enable large amounts of capital to be saved. With the use of low leakage, well installed flexible ventilation ducting it is possible to advance development headings in excess of 2000 m. This may result in the savings of many millions of dollars by not having to excavate ventilation airways at various points along the development heading. 7.9 Duct Leakage Generally, the prime consideration for the purchase of ventilation ducting is cost, not only with the original purchase price but also with the cost of transport and handling. Secondary to this is the ease and convenience of installation and thirdly there may be occasional consideration of the material friction factor but very seldom is any consideration given to the rate of leakage from the duct. Prior to the 1960s the ventilation ducting of choice was usually a rigid type manufactured from galvanised iron or plastics of some type. Lay-flat flexible ventilation ducting has been used extensively in Australian Mines since around the middle of the 1960s. In its original form it was manufactured from a terylene material with wire hoops sewn into each end. These hoops were overlapped one inside the other and prevented from coming apart by tying a length of wire around the duct in between the hoops. BASIC MINE VENTILATION MANAGEMENT Page 136 © AMC Consultants Pty Ltd 2005 Prior to the introduction of trackless diesel equipment auxiliary fans had relatively low airflow rates (6 to 7 m 3 /s) and low pressures (2000Pa). Since the late 1960s and the introduction of diesel powered trackless equipment, airflow requirements for auxiliary fans have increased and as a consequence so have fan pressures. In response to a need to lower operating costs in the 1970s different materials were introduced as was a different type of join (spigot type). This development process has introduced three potential areas of leakage, the material, holes created for stitching the seams and, the type of join. The requirement for increased airflow has grown to the extent that auxiliary ventilation fans now provide up to 50m 3 /s at pressures in excess of 4000Pa resulting in increased leakage quantities. The air that leaks from a duct is a function of many variables including; type of material, type of joint, performance of the fan, and the number and size of holes in the duct. The combined affect is reduced airflow discharged to the working face. Many of the early development problems have been recognised and material coatings have been improved. Stitching has been replaced with welding and the hoop type joint has been resurrected and improved by holding it together with a specifically designed clamp. These improvements have all come at increased purchase price. The high leakage rates from some spigot low cost ducting currently available in Australia limits its use to lengths of up to 400m in some cases this can be as little as 200 m. After this point leakage from the system can be as high as 50% of the air produced by the fan. The leakage rate in a well installed and well maintained low cost ducting may cause only slight inconvenience in short (less than 400m) development headings and the use of the lower cost stitched, ducting and the spigot joint continues to serve this purpose. Because most mines have spare development fans any excessive leakage is fixed by installing an additional fan either in series or parallel. Although ventilation ducting with a high leakage factor may be considered suitable for short development headings, its use in long development headings is questionable. There are some who believe that the introduction of extra fan power (i.e. another fan in the duct) will deliver the required quantity of airflow to the face. In Section 6.3 page 93 we showed how we could predict the airflow through a system using a fan performance curve and the system resistance curve. Calculating the resistance curves for various duct lengths can also allow us to predict the airflow achievable at various lengths. The shortfall in this methodology is that it assumes leakless ducting. In the example shown opposite a two-stage contra rotating fan in a leakless duct will provide 43 m 3 /s at 200m and 32 m 3 /s at 800m. In reality ducts are seldom (if ever) free of leaks and this is particularly true of flexible, lay flat types of ducting, and as a consequence the pressure requirement is reduced and the stall point is seldom reached. With leakage in a good quality ducting the airflow through the fan at a distance of 800m, would be slightly higher (say 38m 3 /s) and the flow to the face would be significantly less and would probably be closer to 20m 3 /s, and is barely adequate for the operation of one truck and one LHD. BASIC MINE VENTILATION MANAGEMENT Page 137 © AMC Consultants Pty Ltd 2005 The air that leaks from a duct is a function of many variables including; type of material, type of joint, performance of the fan, and the number and size of holes in the duct. The combined affect is reduced airflow discharged to the working face. The other important point to note is the air through the fan has not significantly changed and is operating very low on its performance characteristic curve. With this in mind the location of the fan becomes important if recirculation is to be avoided. As discussed earlier a general rule of thumb for auxiliary ventilation fans is to locate them in airflow that is equal to 1.5 times the open circuit capacity of the fan. In the case of a 1400mm diameter fan this is 67.5 m 3 /s (1.5 x 45). If this airflow is not available then it may be necessary to install a seal around the fan to prevent any recirculation. Vutukuri (1984) 18 developed a methodology for use in a computer program necessary to solve the complexity of two components: - Duct friction resistance - Duct leakage resistance Without leakage, determining duct friction resistance is straightforward enough. It can be determined simply using Atkinsons equation. Similarly, consideration of duct leakage resistance on its own is relatively simple. The leakage resistance is often expressed as a leakage flow per unit length for a given duct diameter at a given pressure, or more intuitively, as an equivalent mm 2 of holes per m 2 of duct. The problems commence when the interaction of the above two resistances is considered. In particular, determining fan pressure requirements for a given flow is difficult, because the flow rate along the duct is not constant. The only constant in ventilation duct system is the fact that it will leak but how much is anyones guess. 7.10 Velocities in Primary Airways The economic optimum diameter of any ventilation airway can be determined by the total development and operating costs over the useful life of the airway. Other engineering factors include; - dust entrainment, - cooling power of the air, - pressure losses caused by conveyances (cages in shafts, conveyors in drives, trucks in declines etc.), - effect on equipment in the airway (harmonics in rope guides in hoisting shafts), - activities being undertaken in the airway, - type of equipment to be used for development of the airway, or - any combination of these and other factors. 7.10.1 Velocities in Access Drives There is a generally accepted guideline for a maximum air velocity of 5.0 m/s to be used in declines and other access drives. The purpose of this is to ensure that dust is not entrained in 18 VUTUKURI, V.S. Design of Auxiliary Ventilation Systems for Long Drives Fifth Australian Tunnelling Conference, Sydney (1984) BASIC MINE VENTILATION MANAGEMENT Page 138 © AMC Consultants Pty Ltd 2005 the primary airflow and that unnecessarily high ventilation pressures (and consequently high electric fan power costs) are not imposed on the mine ventilation system. Velocities above 6.0 m/s can be cost effective over short distances providing that good dust management systems in place to ensure that: - dirt in the trucks is sufficiently wetted, and - roadway surfaces are sufficiently stable (wetted) to prevent dust pick up from tyres being entrained into the ventilating air. 7.11 Water in Upcast Shafts The processes of mining rely on the use of water for dust suppression and air-cooling. As the ventilating air flows through the mine workings it takes up this water as vapour until it becomes, to some degree, saturated. As this saturated air rises from the bottom to the top (surface) of the exhaust shaft the barometric pressure is constantly decreasing and as a consequence the temperature of the air, and water vapour mix, is also decreasing. This results with water condensing out of the air. This condensation process is evident by a foggy appearance of the air. This fog is small droplets of water that may coagulate to form larger droplets. A large water droplet of greater than 3mm diameter has a terminal velocity of 8.0m/s. If the velocity of the air is less than 8.0m/s then the water droplet will fall down the shaft and if the velocity is greater than 8.0m/s the water droplet will be pulled up the shaft. Obviously if the velocity of the air is 8.0 m/s it stands to reason that the water droplet will neither rise nor fall and will remain suspended at this critical velocity. As droplets accumulate they form a water blanket that increases the resistance in the shaft thus lowering the quantity of air flowing. At times this may be sufficient to cause the fan to go into stall. As the stall point is reached the water blanket drops out and the fan may recover to recommence the cycle of water blanket formation and drop out. If allowed to continue unchecked this may eventually cause mechanical failure of the fan. Although 8.0m/s is seen as the critical velocity this is not an exact figure and will vary according to a number of factors. Water droplets may coagulate to larger droplets, and the air velocity in the shaft will vary inversely according to the density. This results in a critical range of air velocity between 7.0m/s and 12.0m/s in which this phenomenon occurs. When designing exhaust ventilation shafts in deep mines with potential for saturated air the velocity range between 7.0m/s and 12.0m/s should be avoided. The effect is not as pronounced in shallow dry mines but the critical velocity range should be avoided if there is potential for ground water to be present in the shaft. 7.12 Equipment Movement in Underground Airways Trucks (or other vehicles) travelling in underground drives can cause pressure losses up to 200Pa depending upon a number of variables such as the size of the vehicle in relation to the cross sectional area of the drive and the direction of the airflow in the ramp. Consider the following: A truck having dimensions of 3.1m high x 3.5m wide is travelling at 20kmph against an airflow of 100 m 3 /s in a drive 5.5 m high and 5.2 m wide. The shock loss pressure drop can be calculated from BASIC MINE VENTILATION MANAGEMENT Page 139 © AMC Consultants Pty Ltd 2005 ( ) 2 T A Shock y 1 V V y 2 P | | . | \ | ÷ ÷ × µ = Where: P Shock = the shock loss pressure drop (Pa) µ = the density of the air (kg/m 3 ) y = ) (m Drive the of Area ) (m truck the of Area 2 2 V A = Velocity of the air in the unobstructed drive (m/s) V T = Velocity of the truck relative to the airflow (m/s) Assuming standard air density of 1.2 kg/m 3 then the pressure drop caused by the truck is 185 Pa. i.e. Area of the truck = 18.85 m 2 Area of the drive = 28.6 m 2 y = 0.659 V A = 3.5 m/s V T = -5.56 (- since the truck is travelling against the airflow) m/s Substituting these values into the equation: ( ) 2 Shock 659 . 0 1 6 . 5 5 . 3 659 . 0 2 2 . 1 P | . | \ | ÷ ÷ ÷ × × = = 185 Pa In the same situation and only 25 m 3 /s the pressure drop would be 94 Pa In some cases the airflow in the decline may in fact reverse direction as the truck travels in the drive, usually returning to the norm once it has passed. This only occurs in areas with extremely low ventilating pressure and other connections that operate in parallel with the decline. This fluctuation of airflow may also occur in workings connected via a hoisting shaft. The consequences of any fluctuation cause by vehicles travelling around the mine are seldom great enough to warrant rectification. The main area for concern is when trucks travel up ramps as they do so in an envelope (recirculation) of engine exhaust contaminants. This occurs irrespective of the direction of airflow but when the direction of flow is UP the ramp and the truck is travelling in the same direction there is an increase in the potential for contaminants to build up to levels that will exceed the recommended TWA limits. For example, if we assume trucks travel up ramps at a speed of 10 kph (2.8 m/s) and the airflow in the 5.5 m x 5.5 m ramp is 50 m 3 /s then the air velocity in the ramp is 1.7m/s. This gives a relative velocity between the truck and the air of 4.5 m/s, with the air flowing down the ramp and 1.1 m/s with the air flowing up the ramp. In the second case, it should be noted that the truck is travelling faster than the air. To achieve a reduction in exhaust emission contamination levels the direction of airflow should be down the ramp. This increases the relative velocity between the air and the truck, which in turn increases the turbulence of air around the vehicle causing the envelope to break up and significantly reduce the level of exhaust emission and dust contamination to which the operator is potentially exposed. BASIC MINE VENTILATION MANAGEMENT Page 140 © AMC Consultants Pty Ltd 2005 In development headings causing air to flow down the ramp will require the installation of an exhaust overlap ventilation system. This has the disadvantage of providing contaminated airflow to the working face whilst the trucks (or for that matter any other diesel powered equipment) are operating in the ramp. Because of the relative periods of time spent at the face and the hauling in the ramp, forcing ventilation systems are almost always used. To reduce potential for exhaust emissions to build up to concentrations in excess of the MACs while travelling up ramps it is vital to ensure that engine performance is matched to the work rate required of the vehicle (i.e. the power to weight ratio). It is also essential to ensure that the engine is tuned and maintained to manufacturers specifications. 7.13 Re-entry after Blasting in a Development Heading Blasting is an intermittent activity carried out when people are removed from the underground areas affected by the fumes (gases and dust) generated by the blast. The concentration of contaminants in the affected parts of the mine often greatly exceeds the maximum TWA concentrations for a brief period of time until the fumes are diluted by the ventilation currents and removed from the mine. These peaks generally have duration of a few minutes and occur whenever blasting takes place. Planning and scheduling for rates of advance are usually based upon experience of crews and the normal geotechnical and materials handling requirements of short development headings. For this reason estimates for long heading development rates can and are usually overstated as most neglect to consider the extended re-entry time as a direct result of the length of the heading and the subsequent time required to clear the blasting fumes. For example consider a long development heading 5.0m x 5.0m x 500m, and an airflow of 25m 3 /s delivered in a forcing system. The velocity in the drive (Q/A) is 1.0m/s. Assuming that all contaminants are contained in the plug that is being removed and all of the 25m 3 /s is sweeping the face the minimum clearing time from the face to the primary ventilation circuit, would be only 8.3 minutes and in the scheme of things this is not considered to be of any concern. Because of duct leakage, duct discharge velocity profiles and the distance of the duct discharge from the face it can be expected that these times could be increased by a minimum of 15 to 25 minutes (i.e. re-entry times from 20 minutes up to 35 minutes). Gases produced by blasting are to a significant and variable degree either trapped in the blasted muck pile to be released slowly as the muck is removed or dissolved in water naturally present in BASIC MINE VENTILATION MANAGEMENT Page 141 © AMC Consultants Pty Ltd 2005 the mine or used for dust suppression. It is estimated that up to 60% of the gases produced by blasting are either trapped in the muck pile or removed by dissolution. Gases produced from blasting include carbon monoxide (CO), carbon dioxide (CO 2 ), ammonia gases (NH 3 ), sulphur dioxide (SO 2 ) and oxides of nitrogen (NO X ). The key contaminants are considered to be CO and NO x . Factors that impact on gas production include product manufacture and quality control, the degree of confinement of the explosives (i.e. hole burden and spacing), moisture in the drill holes and the effectiveness of the initiating process. A wide range of estimates exists of the amount of gas produced per kg of explosives used. In the case of CO references have been found to gas production rates between 1.25 litres per kg and 50 litres per kg. In the case of oxides of nitrogen the range is from 19 litres/kg to 33 litres/kg. Skochinsky (1969) and De Sousa (1993) have developed algorithms for calculation of gas clearance after blasting in development headings. These algorithms are useful to gain some idea of what to expect but should not be relied on as the sole indicator of when it is safe to return to a blasted area. The only real indicator for safe re-entry is accurate measurement of the contaminants involved. Skochinsky (1969) ( ) 3 1 2 Drive Explosives V M Q 8 . 7 t × × = Equation 6 Blast Gas Clearing (Skochinsky (1969)) t =Time for the air to clear (seconds) Q =Quantity of air sweeping the face (m 3 /s) M Explosives =Mass of explosives used in the blast (kg) V Drive =Volume of the excavated drive prior to the blast (m 3 ) EXAMPLE Consider a development heading 5.5m high and 5.5m wide 350 metres from the secondary fan. Assuming 200 kg of explosives used in the blast and 20 m 3 /s is sweeping the face then Volume of the drive = 5.5 x 5.5 x 350 = 10587.5 m 3 And ( ) 3 1 2 587 , 10 200 20 8 . 7 t × × = = 1,097 seconds = 18.2 minutes deSousa (1993) ( ) ( ) Et A 2 Q C Et 4 vt x t , x 2 t = ÷ ÷ Equation 7 Blast Gas Clearing (deSousa (1993)) C (x,t) = Gas concentration (multiply by 10 6 to get ppm) t = Time after blast (seconds) x = Distance to face (m) Q = Quantity of Contaminant (m 3 ) BASIC MINE VENTILATION MANAGEMENT Page 142 © AMC Consultants Pty Ltd 2005 A = Cross sectional area of the drive (m 2 ) V = velocity of the ventilating air (m/s) E = Dispersion co-efficient (m 2 /s) r Rh v 8 . 28 E ì ì × × × = v = Velocity of the ventilating air (m/s) Rh = Hydraulic Radius (Area/[height + width]) (m) Ȝ = Friction Factor of a smooth walled drive. (0.008) Ȝ r = Friction factor of the drive (if unknown use 0.015) This methodology will determine the concentration of the particular gas at a particular time. EXAMPLE Consider the development heading above and calculate the gas concentration for NO 2 19 minutes after the blast. t = 19 x 60 = 1,140 (seconds) x = 350 (m) Q = 0.5147 (m 3 ) from table below Gas Gas produced / kg of explosives (kg/kg) Density of gas (g/m 3 ) Volume of gas produced / kg of explosives (m 3 ) Mass of explosives used in firing (kg) Volume of gas produced from firing (m 3 ) CO 0.0163 1.25 0.01304 200 2.61 CO 2 0.1639 1.977 0.082903 200 16.58 NO 2 0.0035 1.36 0.002574 200 0.5147 A = 5.5 x 5.5 = 30.25 (m 2 ) V = 20/30.25 = 0.66 (m/s) E = Dispersion co-efficient (m 2 /s) 015 . 0 008 . 0 75 . 2 66 . 0 8 . 28 E × × × = = 38.17 (m 2 /s) Rh = (30.25/[5.5 + 5.5]) = 2.75(m) Ȝ = 0.008 Ȝ r = 0.015 And ( ) ( ) 1,140 38.17 3.142 30.25 2 0.5147 C 1,140 38.17 4 1,140 0.66 350 t x, 2 × × × = × × × ÷ ÷ = 0.000005 (m 3 ) or 5 (ppm) EXAMPLE 2 This methodology was used to estimate the clearing times for nitrogen dioxide (NO 2 ) from a development heading 5.5m high and 5.5m wide 350 metres from the secondary fan. BASIC MINE VENTILATION MANAGEMENT Page 143 © AMC Consultants Pty Ltd 2005 The gas NO 2 has been used because of its high toxicity, low exposure standard and the fact that it will take longer to dilute to safe levels than other gasses produced by blasting. The results are shown graphically below. This clearly demonstrates the importance of adequate airflow sweeping the workplace. Howes (1982) 19 The following methodology has been adopted by some Australian mining companies as a standard to establish the earliest re-entry time. | | . | \ | × | . | \ | = R C C G G ln Q V t Where: t = Time to achieve the require gas concentration (seconds) V = Volume of the gas filled space (m 3 /s) Q = Quantity of air sweeping the face (m 3 /s) G C = Initial gas concentration (ppm) G R = Gas concentration required (ppm) There are a number of steps required before the use of this equation 1. Calculate the fume throwback distance. (This is the initial volume occupied by the blast fumes ( ) A D F M K L A × × × = Where: L = Length of the fume throwback (m) K = Constant (Assume 25 for development headings) 19 HOWES. M.J., Advanced Ventilation Workshop (1998) 0 5 10 15 20 25 30 35 40 1 11 21 31 41 51 61 71 81 91 101 111 121 131 Time (minutes) C o n c e n t r a t i o n ( p p m ) Safe re-entry level 2ppm 10 m 3 /s 20 m 3 /s 5 m 3 /s 15 m 3 /s Blasting Fume Clearing Times BASIC MINE VENTILATION MANAGEMENT Page 144 © AMC Consultants Pty Ltd 2005 M = Mass of explosives used. (kg) F A = Face advance (m) D = Density of the rock (kg/m 3 ) A = Area of the face (m 2 ) 2. Calculate the Volume of gas produced (m 3 ) (A) (B) (C) (A) x (B) Gas Gas produced / kg of explosives (kg/kg) Density of gas (g/m 3 ) Volume of gas produced / kg of explosives (m 3 ) CO 0.0163 1.25 0.01304 CO 2 0.1639 1.977 0.082903 NO 2 0.0035 1.36 0.002574 3. Calculate the concentration of gas in the in the drive. Assume the drive volume after the blast ) ppm ( 10 ) (m Drive the of Volume (kg) explosives of Quantity /kg) (m G G 6 3 3 PRODUCED DRIVE × × = 4. Calculate the time taken to mix in the drive. (At this step assume perfect mixing of the gas and the ventilating air) ) s / (m Airflow ) (m drive of Area (m)] zone throwback of Distance - (m) drive of [Length (s) mixing for Time 3 3 × = 5. Calculate the time for dilution to the exposure standard using the Blast Clearing Equation above | | . | \ | × | . | \ | = R C C G G ln Q V t 6. Determine the total time for clearing in seconds dilution for Time mixing for Time (s) Time Clearing + = EXAMPLE Consider a development heading 5.5m high and 5.5m wide 350 metres from the secondary fan. Assuming the face advance is 3.0m, the rock density is 3.1 (kg/tonne), 200 kg of explosives used in the blast and 20 m 3 /s is sweeping the face. 1. Calculate the fume throwback distance ( ) A D F M K L A × × × = = 97.75 (m) Where: L = 350 (m) K = 25 M = 200 (kg) F A = 3 (m) D = 3.1 (kg/m 3 ) A = 30.25 (m 2 ) BASIC MINE VENTILATION MANAGEMENT Page 145 © AMC Consultants Pty Ltd 2005 2. Calculate the Volume of gas produced (m 3 /kg) (A) (B) (C) (A) x (B) Gas Gas produced / kg of explosives (kg/kg) Density of gas (g/m 3 ) Volume of gas produced / kg of explosives (m 3 ) CO 0.0163 1.25 0.01304 CO 2 0.1639 1.977 0.082903 NO 2 0.0035 1.36 0.002574 3. Calculate the concentration in drive 6 DRIVE 10 10542 200 0.002574 G × × = = 49 ppm 4. Calculate the mixing time 20 30.25 97.5] - [350 (s) mixing for Time × = =382 seconds = 6.4 minutes 5. Calculate the time taken to dilute the gas. | . | \ | × | . | \ | = 2 49 ln 20 10542 t C = 2,064 seconds 34.4 minutes 6. Calculate the time taken for re-entry Time before re-entry = 6.4 + 24.5 = 30.9 minutes SUMMARY OF EXAMPLES Method Result (minutes) Skochinsky (1969) 18.2 De Sousa (1993) 25.9 Howes (1988) 30.9 Re-entry times are best established by measurement of the relevant contaminants combined with the local knowledge and experience of the people directly involved in the blasting and re- entry process. 7.14 Gases from Sulphide Orebodies See Section 2.2.4 Explosive Dusts page 12 BASIC MINE VENTILATION MANAGEMENT Page 146 © AMC Consultants Pty Ltd 2005 7.15 Gasses from Diesel Engines See Section 2.5 Diesel Engines page 41 7.16 Control of Mine Gases 7.16.1 Prevention Preventing the formation of harmful mine gasses is a simple and obvious control method. Examples of this approach include: Diesel exhaust gas concentrations can be reduced by using high efficiency engines with electronic mixture control or by using alternative power sources (e.g. electric LHDs, shaft hoisting etc). Ammonia formation can be controlled by reducing ANFO spillage and shot-crete rebound. 7.16.2 Extraction The aim with this option is to extract gasses via as direct a route as possible to the surface. Examples include: Uranium mine - ventilation system. Radon daughter laden air is extracted from the stope void and flows directly to the exhaust ventilation system. Coalmine - gas drainage. Methane drainage boreholes are bored into gassy strata in advance of the face. Gas is extracted from the boreholes. 7.16.3 Isolation This involves separating personnel from areas where high concentrations of harmful gasses are known to be present. Examples include: Uranium mine and coalmine return airways. Mine locations that may be affected by blast fumes at firing time. 7.16.4 Containment It is sometimes possible to seal off areas (dangerous gas concentrations occur) from the rest of the mine. An example includes: Bulk-heading off old workings. (i.e. those in which harmful gasses are known to occur). Sealing agents can include shot-crete or urethane coatings. It is normally wise to vent the voids to exhaust, since even with extremely efficient sealing, it is difficult to control leakage due to changes in barometric pressure etc. 7.16.5 Dilution Dilution of undesirable gasses with fresh air represents a simple and effective method of control. The required airflow rate can be calculated from the following formula: NC AC Q Q g ÷ = Equation 8 Dilution Equation Where: Q = The required fresh air flow rate (m 3 /s) Q g = The gas flow rate (m 3 /s) AC = The target gas concentration BASIC MINE VENTILATION MANAGEMENT Page 147 © AMC Consultants Pty Ltd 2005 NC = The normal concentration of the gas in fresh air Example: Methane at 2% concentration has been detected in air flowing out of a stope via a drill drive. The measured flow out of the drill drive is 2 m 3 /s. How much fresh air needs to be supplied to the drill drive (with a flame-proof fan and anti-static vent duct) to bring the methane concentration down to 1%? Methane flow rate = s / m 04 . 0 s / m 2 100 2 3 3 = × The normal concentration (NC) of methane in air is 0. Substituting
s / m 4 0 01 . 0 04 . 0 Q 3 = ÷ = i.e. 4m 3 /s of fresh air is required to dilute the methane to 1% concentration. 7.17 Effect of Atmospheric Changes on Mine Strata Gases Many underground coalmines have goaf areas (old worked out areas), which receive little or no ventilation. These areas are usually sealed off and this allows the accumulation of gases such as methane. As long as the gases remain within the goaf area there is no safety problem. However, when the atmospheric conditions change and the pressure falls, the pressure on the gas decreases and therefore the volume of the gas increases (Boyles Law). Because the volume of the goaf cannot change some of the gas will be forced out into the ventilation system. Designing the ventilation system to prevent this must include; (a) Sufficient airflow to dilute the gases to harmless mixtures (b) Directing them away from men and machinery. The quantity of air will depend on: (a) The total volume of the goaf. The greater the volume of the goaf the more gas will be forced into the ventilation system, (b) The rate of fall of the atmospheric pressure. The actual size of the fall is less important than the rate at which it occurs, since the pressure drop determine the rate of expansion of the gas. The best way to ensure the gas is directed away from the work areas is to ensure that the goaf is connected directly to the exhaust air system. It is important to note that even if the goaf is sealed off they will nearly always breath. 7.18 Spontaneous Combustion Although coal is considered to be a commonplace commodity it is extremely complex and differs widely from seam to seam. Certain coal seams and carbonaceous shales have a tendency to oxidise at normal working temperatures and others are prone to spontaneous combustion. A great deal of work has taken place over many years in an attempt to identify the exact components of coal that cause self-heating but as yet it is still not fully understood. What is known is seams liable to spontaneous combustion are those, - thick or a composite, - are of inferior quality, BASIC MINE VENTILATION MANAGEMENT Page 148 © AMC Consultants Pty Ltd 2005 - are low rank (i.e. relatively young), - contain pyrites, - readily adsorb and desorb moisture when there is a large gap in humidity between the coal and the air, and - have a high moisture holding capacity The spontaneous combustion process starts with oxidation at normal temperature (say 20°C) and the rate of oxidation is dependant upon - the temperature, - percentage of oxygen and, - humidity If the oxygen used up in the oxidation process is not replenished the rate of oxidation will slow and eventually cease when the content fall below 2%. The heat produced by the oxidation process causes a rise in temperature, increasing the rate of oxidation and again increasing the temperature of the coal. The presence of fine coal increases the rate of oxidation due to the relatively large surface area exposed to the ventilating air. Once the temperature reaches 80 - 100°C the oxidation process rapidly increases until the temperature reaches 650°C and ignition occurs. If sufficient heat is removed in the ventilating air then the heating will slow and temperatures will remain below ignition temperatures. The classic spontaneous combustion occurs in broken dry coal of mixed size with sufficient fines to have a large surface exposure and large lumps that create the voids for the passage of humid air. The airflow would be in sufficient quantities to replenish the oxygen but insufficient to remove the heat. Spontaneous combustion is most likely the result of poor mining practices such as: - leakage of air through the goaf (this could be the result of high ventilation pressures) or, - a poor extraction sequence that leaves large stocks of broken coal. There are a number of signs that indicate a heating is in progress. 1. Sweating is the condensation of moisture on the roof, ribs or metal straps and washers used in ground support. This results from high temperatures in the goaf area driving out the moisture contained in the coal. This hot now humid air condenses on the cooler surfaces outside the goaf. 2. Haze or fog caused when the hot humid air from the goaf condenses in the cooler ventilating airflow. 3. A smell comes under many names such as goaf stink, fire stink or stink damp. 4. Hot air from the goaf is an indication that a heating is well advanced. 5. Smoke a fire is imminent. In a longwall retreat goaf there is a region immediately behind the face in which the quantity of air is sufficient to remove the heat of oxidation. Deep within the goaf the quantity of air is insufficient to allow the oxidation process to continue and in fact the oxidation process uses up the oxygen. Between these regions there is a region that is conducive for spontaneous combustion. As the longwall face retreats this region also retreats and remains at the same distance behind the face. The circuits commonly used in Australia to prevent spontaneous combustion are shown below. BASIC MINE VENTILATION MANAGEMENT Page 149 © AMC Consultants Pty Ltd 2005 Bleeder headings must be adopted with extreme caution as they pose a risk of promoting a heating or conversely having an unventilated goaf allowing a build up of gases that could be forced out by a change in atmospheric pressure. Basic Longwall Ventilation (R System) Main Returns GOAF GOAF Main Intakes Bleed Regulator should be kept adjacent to the face line to minimise leakage into the goaf R Bleeder Heading Maingate Tailgate GOAF G O A F Basic Longwall Ventilation (R System) Main Returns GOAF GOAF Main Intakes Bleed Regulator should be kept adjacent to the face line to minimise leakage into the goaf R Bleeder Heading Maingate Tailgate GOAF G O A F Tailgate Return GOAF Back Return System R Maingate Intake Tailgate Intake Return GOAF Maingate Intake Tailgate Intake Y Return System Tailgate Return GOAF Back Return System R Maingate Intake Tailgate Intake Return GOAF Maingate Intake Tailgate Intake Y Return System 7.19 Control of Dust Once dust is liberated from the rock, it is transported to various parts of the mine in airborne form via the mine airways. When the relative velocity between a rock surface and the ventilating air exceeds 5.0 m/s the inspirable dust fraction adhered to the rock surface may be dislodged and will become entrained into the air stream. In underground mines this may occur whenever rock is moved from one point to another. The dust may come from two sources the exposed surface of the rock being transported or, from the roadway surface when dust, picked up by the tyres of vehicles, is entrained into the airstream. These occurrences are usually overcome by wetting the rock on either the load being transported or the roadway surface. Obviously in roadways with air velocities less than 5.0 m/s the problems associated with dust from tyre pick up is much reduced. BASIC MINE VENTILATION MANAGEMENT Page 150 © AMC Consultants Pty Ltd 2005 It is normal practice to apply water from either a water cart or overhead sprays onto underground roadways to allay dust pick up from tyres. The consequences of these systems are either not enough water or some times excessive water, particularly from overhead sprays, that causes erosion of the roadway that in turn requires constant maintenance to the roadway surface. In open-pit mining the use of additives to water has been used in attempts to reduce the roadway maintenance requirements. In recent years a number of underground mines have trailed these additives with varying degrees of success. Dust suppression agents come generally as water additives and are described by their respective manufacturers as either, - Soil wetting agents (detergents), - Binding agents (surfactants), or - Compaction enhancers. Most of these agents have been manufactured with the objective to reduce roadway surfaces breaking up therefore reducing maintenance costs. It is important to note that all products are susceptible to water and have the same requirements for well constructed roadways, sloped to prevent water pooling. Some binding agents cause surfaces to become very slippery and any use of these products must be carefully considered. Water is the main cause of roadway erosion and poorly constructed roadways will always have high maintenance costs irrespective of the use of any wetting or binding agent for dust suppression. The three main methods for controlling dust in underground mines include: - Application of water - Dilution Ventilation - Localised extraction ventilation Water. Application of water is by far the most popular (and usually the most practical) dust control method. Wetting the dust prevents it from becoming airborne. To be effective, the water should be applied (by spray jets) to the point at which the dust is liberated (e.g. at the drill bit, on the roadway, at the drawpoint etc). It is important to try to ensure that the spray water is as clean as possible. Muddy re-cycled mine water may introduce more dust into the mine when the water evaporates. Some dust types may be difficult to wet effectively with water and wetting agents called surfactants may need to be added to the water. A rule of thumb design criterion is to aim to supply between 1 and 5% of water to broken rock (on a weight for weight basis). It is not usually considered safe or advisable to apply water at ore handling facilities. This is because of the serious danger of mud rushes occurring in vertical storage facilities if an excessive build-up of water occurs. Dilution. In most underground mines, dust is produced at diverse and often numerous locations. The amounts of dust produced at the individual locations are sometimes quite small. In these circumstances, the reduction of dust concentration by dilution with an appropriate airflow rate is a legitimate method of dealing with airborne dust. Determining the amount of airflow required to adequately dilute dust on a mine wide basis is surprisingly difficult. The determination is complicated by the cyclic and dynamic nature of the mining process, the effectiveness of watering down dust and many other factors. Some design factors, which may assist, are listed below, however it must be emphasised that no two mines are the same and application of the factors must be tempered with practical experience: BASIC MINE VENTILATION MANAGEMENT Page 151 © AMC Consultants Pty Ltd 2005 - In many mines, it has been found that satisfactory dust levels can be maintained if sufficient air is circulated to satisfy diesel exhaust dilution criteria (e.g. 0.05 m 3 /s per kW of rated diesel engine power). - In all cases, the minimum air velocity to ensure adequate mixing and dilution must be greater than the lower limit of turbulent flow (about 0.1 m/s). - Air velocities in intake airways and in airways in which men travel should be less than about 6 m/s. At higher velocities, increasing problems with re-entrainment of settled dust will be experienced. 7.19.1 Dust Extraction This involves exhausting dust-laden air from a point as close as possible to where the dust is generated, so that dust can be prevented from entering the main intake mine airways. This type of system is best suited to fixed facilities, such as ore passes, crushers and conveyor belt transfer points. In underground mines, it is almost always preferable from an overall cost (capital + operating) viewpoint to exhaust the dusty air directly to an exhaust airway. There may be some circumstances where the dust may need to be filtered so that the extracted air can be re-used. The most suitable filtration systems for the underground environment are generally wet type dust scrubbers, although fabric bag-house type filtration is sometimes also used. Dust is a result of the disintegration of matter and the size of the dust particle produced is determined by the impact per unit area. For example striking a rock with a hammer will split the rock into large pieces forming coarse dust particles. If we were to use the same force using a chisel it would break only a small piece of the rock into fine dust particles because the force is directed onto a much smaller area. Disintegration processes occur in many ways with crushing, grinding, blasting and drilling being the obvious ones. Other processes that cause dust particles to become airborne are those involving the transportation of previously broken material by loaders, uncovered trucks and conveyor belts. The liberation of dust particles to the atmosphere occurs when the velocity of the air relative to the vehicle is sufficiently high enough to cause dust pick up. Pick Up Velocities (m/s) Particle Size(µm) Quartz Coal 75 to 100 6.3 5.3 35 to 75 5.3 4.2 Dry 10 to 35 3.1 3.2 75 to 100 7.4 6.3 35 to 75 6.3 5.3 Semi Dry 10 to 35 4.2 4.2 Dust is also liberated to the atmosphere whenever broken material is transferred e.g. conveyor, loading and unloading processes. The initial step in the design of a ventilation extraction system requires an accurate assessment of the volume flow required to effectively remove the hazard. If this calculation is incorrect then all following decisions regarding the ducting, fans and filters are also likely to be incorrect. Because a suction exhaust type system requires most of the principles of ventilation to be applied (also that the laws of airflow apply equally to both pressure and exhaust systems) we will focus our attention on the design considerations for an exhausting system. Ensuring adequate 'capture' of the contaminant is the first consideration and must take into account the following variables of the contaminant to be handled. BASIC MINE VENTILATION MANAGEMENT Page 152 © AMC Consultants Pty Ltd 2005 VELOCITIES FOR CAPTURE HOODS Type Of Emission Capture Velocity Example Lazy Emission 0.25 to 0.5 m/sec Fume Control Low Velocity Emissions points 05 to 1.0 m/sec Manual Activities e.g. Aspiration Active Emissions mechanical screens 1.0 to 2.5 m/sec Low speed Emissions e.g. Transfer Points, Vibratory Screens. High Velocity 1.0 to 10.0 m/sec High Speed and rotary emissions e.g. Transfer Points, Vibratory Screens e.g. Sawing, Grinding, Polishing Wherever possible capture hoods should be designed to enclose the entire process source. If this is not possible the hood should be located as close to the source as is practical and sited to make use of the direction of flow of the particles caused by the process. This site must be chosen to take account not only of the thermal properties of the process but also the effects of gravity so as to avoid the larger particles falling out before reaching the influence of the hood. It is also important to site the hood in a position that will not allow personnel to come between it and the process source. 7.19.1.1 Hood Design Each hood is designed to control the velocity in all directions at a given distance from a point of exhaust. This is illustrated in the figure opposite that shows the rapid velocity decrease in the vicinity of an exhaust intake. The efficiency of exhaust hoods can be greatly improved if they are shaped to gradually merge into the ducting and thereby improving the aerodynamics of the airflow. Having determined the capture velocity and angle of the hood the next step is the siting of the hood and unfortunately the economic and engineering importance of this procedure is usually ignored or at least misunderstood. As shown in the figure below, if we were to hold a piece of string of length X at the centre of the duct and moved BASIC MINE VENTILATION MANAGEMENT Page 153 © AMC Consultants Pty Ltd 2005 it in any direction we would circumscribe a semi-circle and finally a hemisphere of radius X. To maintain the capture velocity at any point on the surface of this hemisphere we must ensure that sufficient air is drawn through the duct. The airflow required to maintain this velocity may be calculated by the equation: Q = VA 3 Where Q = Exhaust airflow quantity (m 3 /sec) V = Required capture velocity (m/sec) A = Area of the geometric shape (m 2 ) Dalla Valle in the 1930's refined this equation to cater for circular or rectangular hood faces: Q = V (10 x X 2 + A) 3 Where Q = Exhaust airflow quantity (m 3 /sec) V = Required capture velocity (m/sec) X = The distance from the hood face to the process source (m) A = Area of the hood face (m) However this equation also has its limitations as shown by Fletcher in the '80's and should not be used for rectangular hood face areas with an aspect ratio not equal to 1 i.e. they should only be used for hood face areas that are either square or circular. Length Width = ratio Aspect Example What quantity of airflow is required when a hood of 400 mm diameter is placed 320 mm from a dust source with a capture velocity of 3.0 m/sec Q = V(10 x X 2 + A) = 3([10 x 0.32 2 ] + [3.142 x 0.2 2 ]) = 3.45 (m 3 sec) If this same dust hood was repositioned 200 mm from the dust source and the capture velocity remains unchanged then the air volume becomes: Q = V(10 x X 2 + A) = 3([10 x 0.2 2 + [3.142 x 0.2 2 ) = 1.58 (m 2 /sec) These results shows that by moving the hood closer the volume of air required is halved, and the cost of the installation is reduced as a smaller fan will be required. In general hoods should be designed to approximately cover the area (larger never smaller) of the contaminant source and if this source process is hot, the velocity pressure must exceed the thermally induced draught. Although we have shown that the closer the hood is to the source, it must never hinder the process otherwise the operator may remove it. BASIC MINE VENTILATION MANAGEMENT Page 154 © AMC Consultants Pty Ltd 2005 Finally the hood face should be designed to have the smallest possible area that will be acceptable to the process operator. 7.19.1.2 Duct Design After having decided the capture velocities and calculated the airflow requirements for each hood the next step is to determine the optimum transport velocity inside the duct. This velocity should be such to prevent any settling out of the particles as they are transported through the system. It should be noted at this point that the transport velocities should be slightly higher in main ducts than in branch ducts. Air Velocities for Dust Transport Type of Dust (or vapour) Branch Duct Velocity (m/s) Paint fumes 8 to 10 Limestone 13 Metal fumes (welding) 15 Sandblasting 18 to 22 Coal 20 Lead dust 28 Either making use of system damper plates or changing the cross-sectional area of the duct can achieve control of velocity inside ducts. The use of damper plates is very expensive as far as system pressure losses are concerned and should be avoided wherever possible, if however it is intended to expand either the system or the process they must be considered. The other occasion they are used is when the installation space available prevents the use of the desired duct configuration. Duct material, shape, size, branching and bends are all critical as they all have the potential to provide excessive resistance (pressure loss) and add to the size of the fan. To keep these pressure losses to a minimum ducting should be streamlined as far as possible by avoiding sharp bends or sudden changes of cross-section or cross-sectional area. Branch pipe sizes must then be calculated to provide the volume of air required at each point. Duct design should provide for maintenance after the plant has been installed and should therefore provide sufficient inspection and cleaning openings. It is also important to take precautions against corrosion and abrasion as particles may cause rapid wear in ducts, particularly bends and it is therefore necessary to provide protection at these points. 7.20 Economics of Airflow The objective of ventilation economics does not differ from the principles of any investment i.e. to receive the maximum return on the investment. Ventilation circuits are designed to fit the operational requirements for a specific mine. Any economic evaluation is carried out to determine the most cost effective alternative to meet these requirements. Alternatives evaluated may not necessarily include the optimum economic situation. Many times, it is a compromise between the engineering and the scheduling requirements to determine the most cost effective alternative. BASIC MINE VENTILATION MANAGEMENT Page 155 © AMC Consultants Pty Ltd 2005 Ventilation costs should be regularly monitored as changing cost in any of the variables may alter the cost effectiveness of circuit design. It is extremely difficult to provide a single set of economic factors for ventilation studies as costs such as development and power will vary from mine to mine (due to location of the mine from services), rock type, ground conditions, accounting procedures of the mine etc. 7.20.1 Cost of Airflow If the cost per unit of power to operate the fans is known and the airflow and pressure losses in an airway can be determined then it is possible to calculate the cost of power to provide the airflow. Example If the cost of electrical is $0.10/kW hour, what would be the annual cost of power for a flow of 150m 3 /s in a 3.0m diameter 200m long concrete lined airway? From Atkinsons ventilation equation 2 3 Q A KCL P × = then determine the pressure losses for the airway (for a concrete line airway assume k = 0.004 Ns 2 /m 4 ) 2 3 150 064 . 7 200 425 . 9 004 . 0 × × × = = 481 Pa the airpower is AP = P x Q = 481 x 150 = 72,150 watts = 72 kW and the cost of power is $0.10/kW per hour then Cost of Power = AP x unit cost of power = 72 x $0.10 = $7.20/hour or = $63,072/year If the diameter of the shaft was increased to 4.0m then the cost of power would be: 2 3 Q A kCL P × = 2 3 150 566 . 12 200 566 . 12 004 . 0 P × × × = =114 Pa and Air Power (P x Q) =114 x 150 BASIC MINE VENTILATION MANAGEMENT Page 156 © AMC Consultants Pty Ltd 2005 =1710 Watts or = 1.710 kW. and cost of power for 1 year would be: = 17.1 x 0.10 x 24 x 365 = $14,979 From this it becomes obvious that the cost of power decreases as the cross sectional area of the airway increases. Although the cost of power initially decreases quite rapidly it then levels out until the cost savings become relatively insignificant with each incremental increase in airway cross sectional area. 7.20.2 Optimum Airway In most mines, the airways of highest resistance are the primary intake and exhaust airways. The pressure loses in these airways can be 90% of the total mine losses and therefore require most consideration. Besides the operating costs of power there is also the capital cost for development of the airway. Simplistically the larger the cross sectional area of the airway, the more rock to be broken and removed therefore the higher the cost. I.e. the cost for development increase as the cross sectional area of the airway increases. One of the frequently used terms associated with ventilation economics is optimum diameter, optimum velocity or optimum cross-sectional area. Using the variable operating (power) cost and fixed capital (development and fans) the airway can be evaluated to determine the lowest total cost for a specific quantity of air over the life of the airway. This is achieved by the simple addition of the operating costs (power) and the capital costs (development and fans) for a number of airway diameters. In all cases it is simply that point where the total cost over the life of the airway (or system) is at its lowest. Cost of Power Airway Diameter (m) C o s t ( $ ) 0 0 + + Capital Cost Airway Diameter (m) C o s t ( $ ) 0 0 + + BASIC MINE VENTILATION MANAGEMENT Page 157 © AMC Consultants Pty Ltd 2005 Project Cost Airway Diameter (m) C o s t ( $ ) 0 0 + + Decreasing Operating Costs Increasing Capital Costs Operating + Capital Cost Economic Diameter 7.20.3 Time Value of Money When considering the operating costs particularly over a long period of time it is important to consider the time value of money. For example if you were to invest $1,000 at 10% it would be worth $2,593.75 in 10 years time (excluding tax) and if you wanted to have $1,000 in 10 years time you would have to invest $385.54 at 10% today i.e. the Present Value of $1,000 in 10 years discounted at 10% is $385.54. This concept of Present Value makes no mention of inflation. This is because inflation influences the purchasing power of the money not the amount of money. The Time Value of money refers to the effect that interest rates (as returns from potential investment opportunities) can have on the value of money and not the effect of inflation. When considering expenditure on ventilation airways, we should consider that the money need not be spent and it could be invested. Thus for a given project, the expenditure must return the original and operating expenditure equivalent to interest rates which could be earned by investing the money. The future sum of our investment can be calculated from ( ) n i 1 P F + = Where F = Future Value ($) P = Present Value invested ($) i = Interest rate % (rate of return on capital) n = Number of interest compounding periods usually yearly Example What is the future value (F) of $1,000 at the end of 6 years if interest is 10%? F = P(1 + i) n = 1,000(1 + 0.1) 6 BASIC MINE VENTILATION MANAGEMENT Page 158 © AMC Consultants Pty Ltd 2005 = $1,771.56 Similarly, if we know the value of a future sum we can determine the Present Value by solving for P. i.e. ( ) n i 1 F P + = ( ) 20 20 . 0 1 000 , 1 + = = $26.08 This shows that $26.08 invested today for 20 years at 20% interest will grow to $1,000. Both of these functions deal with single payment present values. If we were to invest money as a series of equal investments, each investment draws compound interest for a different number of periods. The future amount of money from this type of investment is calculated by: ( ) i 1 i 1 A F n ÷ + = Where A = Amount Invested ($) Example Calculate the future value (F) 6 years from now with yearly investments of $1,000 at 10% interest. ( ) 1 . 0 1 1 . 0 1 000 , 1 6 ÷ + × = = $77,156.61 This shows the future value of yearly investments of equal value. Should we wish to know the present value (P) of a series of $1,000 payments made at the end of each year of 6 years if the compound interest is 10% per year. We can use the following equation. ( ) ( ) 1 i 1 i 1 i 1 A P n + + = ( ) ( ) n 6 1 . 0 1 1 . 0 1 1 . 0 1 000 , 1 + + × = = $4,355.26 Thus the Present Value of a series of $1,000 payments made each year for 6 years with a compound interest of 10% $4,355.26. 7.21 Rule-of-Thumb Principles and Design Factors There are a large number of ventilation rule-of-thumb (ROT) principles that have evolved over many years, many are contradictory and many are now no longer applicable. When using any BASIC MINE VENTILATION MANAGEMENT Page 159 © AMC Consultants Pty Ltd 2005 ROT they must be placed in the correct context and this can only be done successfully if there is a good understanding of the basis from which the specific ROT has been derived. Although experience should not be ignored and basing ventilation design specification on past and present practices in comparable mines can and has led to near disastrous consequences of over and under ventilated mines. There is some basis for the use of ROT principles particularly when attempting to get a feel for what may be required, but mine ventilation systems must be designed specifically for each and every mine, as no two mines are identical. One site on the Internet (www.mcintoshengineering.com) provides a comprehensive list of ROT principles. Before using any of these values the origin and circumstances of the factor should be fully understood. Listed below are some factors encountered by the author over many years. Rule-of-thumb factor Comment Fresh air quantities (a) 0.024 0.094 m 3 /s per tonne of ore and waste produced in the mine (it is assumed that this refers to a daily production rate) (b) 0.094 0.47 m 3 /s per man underground (c) 0.063 0.126 m 3 /s per kW of operating diesel equipment. Consider a modern mechanised mine producing 1,000,000 tonne of ore and waste. From (a) the quantity of air should lie between 65 and 257 m 3 /s A modern mine may have 50 people underground therefore from (b) the quantity of air required is between 4.7 and 23.5 m 3 /s. However in a labour intensive operation there could be 2,000 people underground and the airflow would be between 188 and 940 m 3 /s. For diesel equipment 4,000 kW will require 252 and 504 m 3 /s Velocities in airways Service Shaft 5.1 7.6 Production Shaft 7.6 10.2 Main Entry 2.6 - 7.6 Conveyor tunnels, declines 2.5 5.1 Inlet and exhaust rises (no access) ±10.0 Inlet and exhaust rises (access required ) 2.5 5.1 Exhaust mains 10.2 15.2 Exhaust shafts (concrete lined) 15.2 - 20.3 Exhaust shafts (rock section) 10.2 - 15.2 Avoid 7.5 to 12.5 m/s in saturated airways. BASIC MINE VENTILATION NETWORKS AND COMPUTER MODELLING Page 160 © AMC Consultants Pty Ltd 2005 in todays increasingly uncertain, competitive and fast moving world, companies must rely more and more on individuals to come up with new ideas, to develop creative responses and push for changes before opportunities disappear or minor irritants turn into catastrophes. Innovations, whether in products, market strategies, technological processes or work practices, are designed not by machines but by people. Rosabeth Moss Kanter - The Change Masters 8 NETWORKS AND COMPUTER MODELLING 8.1 Ventilation Networks In section 4 we looked at simple series and parallel circuits. Mines consist of many airways (including stope voids open orepasses etc.) interconnected in such a way that it is impossible to reduce them to simple series or parallel circuits. This network of airways can, with the use of computers be analysed to predict airflow quantities and pressures. Consider the following figure to represent three possible stages for development of a mine. At first a simple series circuit, expanding when a new area is opened up creating a parallel circuit and finally the connection of the two working areas resulting in a network of airways. Area 1 A H B G D E C F Series circuit ABCDEFGH Area 2 X Y Area 1 A H B G D E C F The construction of airway DY now presents a different problem consisting of branches, junctions and meshes. Branches (connect junctions) and are ABC, CD, DEF, DY, CXY, YF and FGH. (Total 6) Note: a branch is any series of airways and may have different dimensions and must be included at least once in the group of meshes Junctions (two or more branches) C, D, Y and F. (Total 4) Meshes (and closed circuit) CXYDC, DYFED, CXYFEDC and ABCXYGHA. (Total 4) Area 2 X Y Area 1 A H B G D E C F Parallel circuits CDEF and CXYF with common junctions C and F Compound or Network System Area 1 A H B G D E C F Series circuit ABCDEFGH Area 1 A H B G D E C F Area 1 A H B G D E C F Series circuit ABCDEFGH Area 2 X Y Area 1 A H B G D E C F The construction of airway DY now presents a different problem consisting of branches, junctions and meshes. Branches (connect junctions) and are ABC, CD, DEF, DY, CXY, YF and FGH. (Total 6) Note: a branch is any series of airways and may have different dimensions and must be included at least once in the group of meshes Junctions (two or more branches) C, D, Y and F. (Total 4) Meshes (and closed circuit) CXYDC, DYFED, CXYFEDC and ABCXYGHA. (Total 4) Area 2 X Y Area 2 X Y Area 1 A H B G D E C F Parallel circuits CDEF and CXYF with common junctions C and F Compound or Network System BASIC MINE VENTILATION NETWORKS AND COMPUTER MODELLING Page 161 © AMC Consultants Pty Ltd 2005 The solution of the series and parallel was explained in section 4. The solution of networks is undertaken with the following assumptions: 1. Air is incompressible and, 2. The airflow in the network obeys Atkinsons law Kirchhoffs electrical laws can be restated and applied to ventilation networks i.e. 1. The total quantity of air entering a junction is equal to the total quantity leaving the junction. 1 i 0 Q S i = = ¿ 2. The sum of the pressure changes in a mesh is zero. ( ) ( ) 1 i 0 NVP P P m m fi i = = ÷ ÷ ¿ Where density is constant m = number of branches forming a closed mesh P i = frictional pressure drops. P fi = total pressure drop across the fan NVP = natural ventilating pressure. In the simplest case of a mesh without a fan and no NVP this reduces to 1 i 0 P m i = = ¿ These equations are only correct when all terms are considered at standard density 8.2 Analysis of a Network 20 The solution of a network requires the determination of the characteristic of each and every airway, the number of branches, the number of junctions and the number of meshes. From Kirchhoffs 1 st law for a network containing b branches and j junctions there will be b airflows to determine and therefore b equations must be solved. Similarly from Kirchhoffs 2 nd law there will be j equations to be solved. However only j 1 of these are independent because the j th junctions are already defined by flows at other junctions and therefore there are b (j 1) equations to construct. These are obtained by choosing a minimum of, b j +1 meshes and writing equation. ( ) ( ) 0 NVP P P m m fi i = ÷ ÷ ¿ for each of them. This gives j 1 junction equations from Kirchhoffs 1 st law and b j +1 mesh equations from Kirchhoffs 2 nd law. When written in terms of P = RQ 2 a quadratic equation for each mesh can be developed to find the solution. For a network containing m meshes the powers of Q would be 2 m -1 20 For a detailed discussion on Network analysis refer to McPHERSON, M.J., Ventilation Network Analysis Environmental Engineering in South African Mines. (1989) Chapter 8. pp211 - 239 BASIC MINE VENTILATION NETWORKS AND COMPUTER MODELLING Page 162 © AMC Consultants Pty Ltd 2005 In relatively simple networks there is an application of this method but it falls short in large networks in much the same way as simple series and parallel circuits in networks, and other techniques should be considered. 8.2.1 Hardy Cross The technique of fluid network analysis involves making an initial estimate of the flow distribution and calculating an approximate correction to be applied to the flow in each branch and then iterating the correction until and acceptable result has been achieved. The technique that has found its place in mine ventilation calculations is the one developed by Professor Hardy Cross in 1936. Consider the figure below and assume a quantity Q passing through a duct. P r e s s u r e d r o p P Quantity Q P = RQ n Q P Qa Q P = RQ n P = RQa n P r e s s u r e d r o p P Quantity Q P = RQ n Q P Qa Q P = RQ n P = RQa n P r e s s u r e d r o p P Quantity Q P = RQ n QQ PP Qa Q P = RQ n P = RQa n n is the constant for the range of flow considered. To determine Q an estimate of Q a is made i.e. Q Q Q a A + = where AQ is the error for quantity. Similarly AP is the corresponding error for pressure. Differentiating P=RQ n we find Slope of the curve 1 n nRQ Q P ÷ = A A Or at point P a 1 n a nRQ Q P ÷ = A A 1 n a nRQ P Q ÷ A = A But n a n RQ RQ P ÷ = A BASIC MINE VENTILATION NETWORKS AND COMPUTER MODELLING Page 163 © AMC Consultants Pty Ltd 2005 Therefore 1 n a n a n nRQ RQ RQ Q ÷ ÷ = A which is the out of balance equation in a single duct. Considering a network with b branches and applying Kirchhoffs laws and assuming the index n = 2 for a fully turbulent flow we can derive the mesh correction factor Q m to be ( ) ¿ ¿ = = ÷ ¦ ) ¦ ` ¹ ¦ ¹ ¦ ´ ¦ ÷ ÷ = A b 1 i fi ia i fi b 1 i ia ia i m S Q R 2 P Q Q R Q ia Q is the absolute value and S is the slope of the fan characteristic. The procedure for the use of this method is described as follows: (a) Estimate the quantity of air flow through each branch (b) Decide on a pattern of closed meshes and determine the number. The minimum number is determined by No. of branches No. of junctions + 1 (c) For each mesh evaluate the mesh correction factor AQ m . (d) Correct the flow in each branch. (e) Repeat steps (c) and (d) until values of AQ m are below the prescribed value. (f) Repeat steps (b) to (e) for each of a number of changes to the network. 8.3 Computer Modelling Modelling of ventilation systems with computers can be an excellent tool to assist with ventilation system design. However, ventilation simulations are not a magic panacea. They do not replace a good working knowledge of basic ventilation theory and practice and the following problems are very common: - The user friendliness of the latest software and the ability to directly import 3D mine design data has encouraged large numbers of inexperienced, but computer literate engineers to have a go. Impressive graphical output is produced, but the answers are often wrong. - Inexperienced users often use the default input values (because the user is often unsure what the proper values should be). In one popular computer package, the supplied shock loss equivalent lengths are grossly misleading and should never be used. - Some computer packages add shock loss factors automatically (by default) to every mine airway. This can cause significant problems, particularly if the model contains a large number of short airways. - The models are often not checked against reality. This appears to be due to a basic unawareness of how to take simple ventilation pressure measurements and compare these with simulated values. The aim of this section is to provide some practical advice so that some of these problems can be avoided. The user of computer simulation software should have a very clear idea of what questions need to be answered before any data is entered. The main reasons for undertaking a simulation are listed below: BASIC MINE VENTILATION NETWORKS AND COMPUTER MODELLING Page 164 © AMC Consultants Pty Ltd 2005 - Estimation of fan duty requirements (for primary fans and circuit fans). - Estimation of general airflow distribution, in more complex ventilation circuits. It should be appreciated that computer simulations are not a ventilation design black box There are a number of things, which they wont do, including: - Standard (non thermodynamic) computer simulations will not estimate airflow distribution where natural ventilation pressures are significant (i.e. where significant temperature differentials exist, or where the driving pressures in individual parallel circuits are low). - Computer simulations will not provide an accurate estimation of all airflows in every part of the ventilation circuit. In many mines (particularly larger ones), there are too many variables, which change on a regular basis (e.g. ore passes or stopes being bogged empty), for any real certainty in all predicted airflows. - Computer simulations will not design your ventilation system for you! Important aspects like the economically optimum shaft sizes etc must be determined by separate calculations. 8.4 Input Data The old adage of garbage in, garbage out well and truly applies with ventilation simulations. Some brief information is provided here on some aspects of input data. 8.4.1 Simulation Model Layout For many years the use of a skeleton model has been seen as the best approach. In these models main airways are included, but minor ones (e.g. small escape rises etc which do not carry significant airflow) are excluded. There are a number of advantages in this approach including: - The model is a more manageable size, reducing the chances for data entry error - Quicker simulation time and faster screen manipulation for 3-D programs - Minimal loss in accuracy if removal of unimportant airways is done with care As always there are also a number of disadvantages - The person who developed it owns the model, and they are generally the only person who understands it. - Does not allow for any predictive work other than primary fan duty to be undertaken - Does not allow the model to be used to problem solve the ventilation system Todays software packages allow the use of a large number (20,000) of branches to be used. This along with the ability to import data from other software used to design mine openings, means that ventilation models can be constructed to represent every opening in the mine. This provides the advantage of other people being able to view the network in the same manner they would view survey or design plans. 8.4.2 Number of Airways Modern simulation programmes have the facility to import centre line string data from 3D mine planning packages. Before importing the data into the simulation package, it is wise to reduce the number of points used to define the model. For example, the raw data may use 20 or more points in series to define a bend in a decline, whereas this could perhaps be reduced to three or four points, whilst still retaining a presentable 3-D format. The advantages are a less unwieldy simulation model with very little reduction in accuracy. BASIC MINE VENTILATION NETWORKS AND COMPUTER MODELLING Page 165 © AMC Consultants Pty Ltd 2005 8.4.3 Friction Factors Friction factors vary for different types of airways (and different airway sizes). If at all possible, gauge and tube pressure surveys should be undertaken to determine typical local friction factors. 8.4.4 Shock Losses Shock losses seem to be a major source of misunderstanding and error in ventilation simulation work. Two common problems are evident: - One program applies a shock factor to every new airway by default. If the model is constructed from a large number of very short airways in series, the resulting combination of default shock losses can cause the simulation model to substantially overestimate the total mine resistance. Note that the Atkinson Friction Factor for drives, etc includes an allowance for normal shock losses (decline bends etc). Shock factors generally only need to be applied to dog legs, inlet losses and discharge losses in main ventilation raises etc. - One program misleads the user into believing that an equivalent length shock factor can be used to accurately describe a particular shock loss (e.g. right angle bend), regardless of the airway size or roughness. The problems caused by the equivalent length concept are almost universal. Some notes outlining the problem in more detail are presented below: The equation for the equivalent length of a shock loss is given as k 67 . 6 XDh Le = Where: Le = equivalent length of shock loss (m) X = shock factor k = Atkinson Friction Factor). Ns 2 m -4 Dh = Hydraulic diameter (m) =(4 * A)/ C A = cross-sectional area (m 2 ) C = drive perimeter. (m) It can be seen from the above equation that the equivalent length is directly proportional to the hydraulic diameter and inversely proportional to the Atkinson friction factor of the equivalent length airway (i.e. equivalent length for a given shock loss is not constant, but depends on airway size and roughness characteristics). For illustration, using the above formulae, the equivalent length of a discharge loss (X=1) from a 1.2m airleg rise (k = 0.015) = 12m of 1.2m x 1.2m airleg rise. In contrast, the equivalent length of the same discharge loss (X=1) from a 4m diameter raise bored hole (k = 0.004) = 150m of 4m raise bore. That's quite a difference in equivalent length! It is important to recognise and understand the problem outlined above. Until there are some changes made in how shock losses are dealt with in some of the simulation packages, it is strongly recommended that all shock losses be calculated separately. Woods Practical Guide to Fan Engineering Daly, B. B. (1978) is a very useful source of information on shock factors. (Note that Daly uses K for the shock factor, rather than X) 8.4.5 Fans Ventilation programs have the facility to enter fan curves. Most programs require fan pressure in terms of fan static pressure. Unfortunately, some fan suppliers only provide fan total pressure BASIC MINE VENTILATION NETWORKS AND COMPUTER MODELLING Page 166 © AMC Consultants Pty Ltd 2005 curves. A fan static pressure curve (including pressure losses or regains from associated fan inlet and discharge ducting) should always be requested when ordering primary mine fans. When simulating a new mine to determine the required primary fan duties, the required fan static pressures can be determined by fixing the flow in the primary exhaust airway(s). The required fan static pressure can be read off the simulation results. 8.4.6 Fixed Airways Fixed airways should be used very sparingly. Excessive use of fixed airways will overly constrain the simulation model and may result in errors or program crashes. Fixed airways are generally only used for airways where the resistance is difficult to measure (e.g. lack of accessibility etc). Even then this should be a temporary fix and once the resistance has been determined the fixed airflow should be replaced with the appropriate resistance. Most of the time, the only airways that should be fixed are airways with ventilation controls (e.g. fans or regulators). Fixed airways should never be applied to locations where there are no ventilation controls (e.g. the flow in a decline should never normally be fixed, unless a control such as a set of doors or booster fan is planned). If a large number of fixed airflows are required, it generally means that airway resistances have been incorrectly determined and therefore need to be adjusted. (i.e. the wall roughness or the cross sectional area needs to be looked at.) 8.5 Results: For existing mines, Calibration checks against existing fan pressures, regulator pressures and major airway flows should always be made, before using simulation models to predict future ventilation system performances. An appreciation of the limitations in accuracy with the technique (due to uncertainties in input values) is required. Agreement to within 15% of actual airflows is about as good as can be expected. BASIC MINE VENTILATION References & Further Reading Page 167 © AMC Consultants Pty Ltd 2005 the best way to learn the practice of mine ventilation is to slug it out in an environmentally tough underground mine for several years. If a person is devoted full time to the study and practice of mine ventilation and has access to another well qualified mine ventilation engineer the average engineer will start to become reasonably proficient in the basics of mine ventilation after a period of one to two years F. Bossard - Manual of Mine Ventilation Design Practice References & Further Reading 1. AMIRA Mine Ventilation Measurements - A Manual of Recommended Practice 2. BARENBURG, A.W.T. Psychrometry and Psychrometric Charts Third edition Chamber of Mine of South Africa. 3. BOSSARD, F.C. A Manual of Mine Ventilation Design Practices Second Edition (1983) 4. BOOTH-JONES, P. A., ANNEGARN, H.J., BLUHM, S.J. Filtration Of Underground Ventilation Air by Wet Dust Scrubbing. (pp209-213) Proceedings of the 3 rd International Mine Ventilation Congress. Published by The Institute of Mining and Metallurgy. London (1984) 5. BRIEF, R., SCALA, R., Occupational Exposure Limits for Novel Work Schedules. American Industrial Hygiene Association Journal. 36: 467-469, 1975 6. DALY, B.B. Woods Practical Guide to Fan Engineering (Published by Woods of Colchester 1978) 7. de la HARPE, J,H., JENNER, L.W. The History of Mine Fans in South Africa The Journal of the Mine Ventilation Society of South Africa. (December 1986) 8. DeSOUSA, E.; et al (1993) Blasting Fume Prediction and Control as a Means of Reducing Ventilation Costs. Proceedings of the 6 th US Mine Ventilation Symposium, June 21-23, 1993. Society for Mining, Metallurgy and Exploration Inc. 9. ENRIGHT, R.J., LEONTE, M. AMIRA Sulphide Dust Explosions Volume 1 Cause and Prevention in Development Headings Project P316-P316A (1990-1994) (11 May 1995) 10. ENRIGHT, R.J., LEONTE, M. AMIRA Sulphide Dust Explosions Volume 2 Detection and Preventative Measures. Project P316A-P316B (1990 1995) (1996). 11. GILLIES, A.S.D., (Editor.) Proceedings of Fourth International Mine Ventilation Congress Brisbane, Australia. 1988. Australian institution of Mining and Metallurgy. (1988) 12. GREEN, H.L. and LANE, W.R. Particulate Clouds: Dusts, Smokes and Mists, E. & F. N. Spoon Ltd. London (1964) 13. HARTMAN, H. L. - Mine Ventilation and Air Conditioning 14. HATCH, T., Respiratory Dust Retention and Elimination Proceedings of the Pneumoconiosis Conference. Johannesburg 9 th 24 th February 1959. p 113,132) 15. HEMP, R., LANCASTER, F.H. (Editor.) Proceedings of International Mine Ventilation Congress Johannesburg 1975 Mine Ventilation Society of South Africa (1976) 16. HOWES, M.J. Air Pollution - Environmental Engineering in South African Mines. (Chapter 29 pp773-790) Published by The Mine Ventilation Society of South Africa. (1989) 17. HOWES. M.J., Advanced Ventilation Workshop (1998) 18. HOWES, M.J., JONES, M.J. (Editor.) Proceedings of Third International Mine Ventilation Congress, Harrogate, England, 1984 The institution of Mining and Metallurgy (1984) BASIC MINE VENTILATION References & Further Reading Page 168 © AMC Consultants Pty Ltd 2005 19. JORGENSEN, R. (Editor) Fan Engineering Published by Buffalo Forge Company (1983) 20. Le ROUX, W., Mine Environmental Control Fourth Edition (1990) 21. McPHERSON, M.J. - Subsurface Ventilation and Environmental Engineering 22. MOUSSET-JONES, P., (Editor) Proceedings of Second International Mine Ventilation Congress 1979 American Institute of Mining, Metallurgical, and Petroleum Engineers, Inc (1980) 23. ORENSTEIN, A.J. (Editor) Proceedings of the Pneumoconiosis Conference - Johannesburg 9 th 24 th February 1959. South African Council for Scientific and Industrial Research. (Churchill Ltd. London 1960) 24. PARTYKA, J., KRYNICKI, J. and SZYMANSKI, J. Blast Induced Dust Proceedings of the 6 th International Mine Ventilation Congress. Published by Society for Mining, Metallurgy, and Exploration, Inc Littleton, Colorado. (1997) 25. Proceedings of Fifth International Mine Ventilation Congress (1993) 26. RAMINI, R.V. (Editor) Proceedings of Sixth International Mine Ventilation Congress Pittsburgh, Pennsylvania, USA 1997. Society for Mining, Metallurgy, and Exploration, Inc. (1997) 27. SANDYS, M.P.J., QUILLIAM, J.H. Sources and Methods of Dust Control - Environmental Engineering in South African Mines. (Chapter 15 pp379-394) Published by The Mine Ventilation Society of South Africa. (1989) 28. SCHRÖDER, H.H.E. The Properties and Effects of Dust - Environmental Engineering in South African Mines. (Chapter 12 pp313-335) Published by The Mine Ventilation Society of South Africa. (1989) 29. SHRÖDER, H.H.E., RUNGGAS, F.M., KRÜSS, J.A.L. Characterisation of Sonically Atomised Water Spray Plumes. (pp219-228) Proceedings of the 3 rd International Mine Ventilation Congress. Published by The Institute of Mining and Metallurgy. London (1984) 30. New South Wales Department of Mineral Resources - Guidelines for Safe Mining (2001) 31. SKOCHINSKY, A., KOMAROV, V., Mine Ventilation. MIR Publishers, Moscow (1969) 32. STRANG, J., MacKENZIE-WOOD, P., Mines Rescue and Gas Detection (1985) 33. BURROWS, J., (Editor) Environmental Engineering in South African Mines Published by The Mine Ventilation Society of South Africa (1989) 34. VUTUKURI, V.S. Design of Auxiliary Ventilation Systems for Long Drives Fifth Australian Tunnelling Conference, Sydney (1984) © AMC Consultants Pty Ltd 2005 AMC Consultants Pty Ltd www.amcconsultants.com.au MELBOURNE PERTH Level 19 114 William Street Melbourne Vic 3000 Australia Telephone: +61 (0)3 9670 8455 Facsimile: +61 (0)3 9670 8311 email:
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[email protected] BASIC MINE VENTILATION INTRODUCTION INTRODUCTION Safe, sustainable underground mining of any scale is not possible without an effective ventilation system. Ventilation is required in the underground workings to: Dilute gaseous and particulate pollutants to concentrations which are not injurious to the health and safety of the workforce Maintain thermal comfort through the provision of adequate air velocity Assist with maintaining workforce morale and productivity through the provision of high quality underground environmental conditions An efficient and effective mine ventilation system is not achieved by accident. It requires incorporation of a solid understanding of scientific ventilation principles into the very core of the mine planning and management process. Important lessons can be learnt from history which has emphasised time and time again is that the knowledge required to implement effective mine ventilation has often been significantly more advanced than the practices adopted in the mines at the time. The terrible loss of life in the British coal industry in the 19th Century (which did not abate until the belated introduction of legislation early in the 20th Century) is a sobering example. More recent examples of the same phenomena in Australia include the many cases of mesothelioma contracted by underground miners in Wittenoom in the 1950’s and ‘60’s as well as the Moura mine disasters of the 1980’s and 1990’s. In all of these examples, the health and safety risks were well known, as were the engineering requirements necessary in order to minimise these risks. The costs of installing and managing effective ventilation systems must have been minuscule compared with the subsequent outlays for compensation. One inference which could be drawn from all of this is that ignorance and indifference have been (and perhaps still are) important factors. Brief History of Mine Ventilation There is evidence to suggest that the need to establish ventilation circuits with intake and return airways was understood and practiced by the Greeks. For example there was twin access development and divided shafts in the Laurium silver mines of Greece (600 BC). In the Roman times, slaves waving palm fronds were used to promote air circulation. (Pliney AD 23-79). More generally, air movement was created by up-draughts of warm air from fires lit for this purpose underground. Pre Middle Ages Mine ventilation practices of the day are illustrated and described in “De Re Metallica”, by Georgius Agricola, 1556. This was amongst the first books ever printed and remained a standard mining text for the next 200 years. The book describes horse and human powered centrifugal fans; bellows connected to wooden conduits, ventilation doors and shaft collar deflectors, which divert winds into the mine workings. Agricola also described the dangers of “blackdamp” (oxygen reduced air) and the explosible “firedamp” (an air and methane mixture “likened to the fiery blast of a dragon’s breath”). Industrial Revolution Middle Ages Page i © AMC Consultants Pty Ltd 2005 BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY This period saw an unprecedented increase in demand for mineral commodities including coal, metalliferous ores and industrial minerals. Substantial growth in mining activity, (much of it underground) was required to satisfy this new demand. Larger scale mining led to increasing numbers of miners suffering from health problems contributed to by poor ventilation, including “black lung”, mine explosions and fires. Hot working conditions at depth due to ventilation limitations also restricted the extent of mining activities. The increasing slaughter of men, women and children in British coal mines as a result of explosions and fires eventually served as a major impetus to drive the development of the science of underground ventilation in the 19th Century. John Atkinson, a British mining agent presented his famous paper “On the Theory of the Ventilation of Mines” in 1854 and Atkinson’s Equation still forms the basis for all mine ventilation engineering. Interestingly, whilst the importance of Atkinson’s paper and theories were recognised at the time they were published, they received little interest and were considered too much for the engineers of the day. It wasn’t until some 60 years after Atkinson’s death that his theories were “rediscovered”. In the 1920’s and 1930’s large axial fans based originally on aeroplane propeller designs began to become popular. Analogue computer models were used in the 1950’s to analyse ventilation networks. The introduction of diesel equipment underground in the 1960’s and 1970’s required substantial increases in mine ventilation capacity. Many mines of the day embarked on massive upgrades to ventilation shafts and main surface fans. Great advances in large fan design were made in the 1960’s and 1970’s. At about the same time, improvements in large scale refrigeration technology began to allow very deep orebodies to be accessed, particularly in South Africa. The most notable feature has been the development of computerised mine ventilation network analysis. This has made prediction of fan requirements and airflow distributions in complex mine ventilation circuits feasible using desktop computers. Information Age Industrial Revolution – Information Age Page ii © AMC Consultants Pty Ltd 2005 ............... 1 1........................................2 Barometric Pressure.......................................................................................................................................... 31 2.3 Oxygen (O2) .....2........... 53 3........... 26 Mine Gases...................6 Measuring Pressure in a Duct ....................................................................................... 3 Adjusting the Eight-hour Exposure Standard for Longer Periods................................... 49 Density of Humid Air ....................................................... 5 2............................ 52 3.......... 31 2.............................3 3. 5 Dust............. 54 2 OCCUPATIONAL HEALTH AND SAFETY...........7 Natural Ventilating Pressure..............................3....................................................4 Explosive Dusts ................... 3 The Respiration System................... 12 Heat................................... 42 2..............................................4.................................................................................. 48 Density of Dry Air ..........................................................................................................8............................................... 54 3.....2 2................................... 34 2..........3.................................... 41 2.................................................................................................................... 37 Diesel Engines ............................................................................11 Radon (Rn) and Radon Daughters.4...........................1 Diesel Exhaust Emissions (DEE) ............................3............4 1..... 48 Universal Gas Law.....................................................................................................6 Air Cooling Power.....................................................................................4.........5 3 PROPERTIES OF AIR....3....5............................4......................1 3.............................. 7 2....................................................7 Management of Hot Working Conditions................5 3.........2..........................................4 Velocity (Dynamic) Pressure (VP)....................................................................................................8............ 35 2........................2 Body Heat Balance.........................................................................................4...............................1 Constituent Gases of the Atmosphere .................1 Air Temperature..................................................................................................................4...1 Atmospheric Pressure .................................2..............3 2....................................................................................................... 44 Air Temperature ..............10 Ammonia (NH3)... 13 2..........................................BASIC MINE VENTILATION INTRODUCTION Table Of Contents 1 CONTAMINANTS AND EXPOSURE STANDARDS............1 1............................ 47 Charles’ Law ...................................................1 The Hazard of Dust ....................................... 17 2..........................................5 Heat Stress Indices ...3...............8........ 20 2.......... 51 3......4 Heat Related Illness ..........3 Dust Exposure Standards....................................2 Diesel Particulates........................................................................................................................................................ 32 2..4 3.................. 48 Boyle’s Law..............................................................................4.......8 Methane (CH4)................................ 37 2...............................................1 2........................................................................................ 53 3....................................................................3 1............................ 2 Time-Weighted Average (TWA)...................................... 11 2..............................7 3.......................................3 Static Pressure (SP) ......................................................2 1..........5 Oxides of Nitrogen (NOx)...........................4 Carbon Monoxide (CO) .........3..........6 3..4................................. 53 3.........................................3 Dilution of Diesel Exhaust Emissions (DEE) ................ 33 2.................................................. 7 2....................9 Coal Damps.....8.................................................5.........................................4.... 21 2..........6 Sulphur Dioxide (SO2)................. 52 3..........4.................................................................... 41 2.........8....................................................8.............................. 34 2............ 31 2......................................................................8.........................................7 Hydrogen Sulphide (H2S) ............................................................... 24 2....... 2 Short Term Exposure Limit (STEL).............4.3 Thermoregulation ........ 18 2.....8 Page iii © AMC Consultants Pty Ltd 2005 ..... 16 2................................ 32 2.......................................................... 12 2................................................... 47 3...5 Total Pressure (TP) .................................................2 Carbon Dioxide (CO2)..........5........................................................................... 48 Moisture in Mine Air ............................................5 Peak Limitation .........................2 Effects of Dust ................................................................... 3 Guidance on General Excursion..........2 3.......................................... 50 Air Pressure .................4 2.... 34 2...............3................................2..................... ..2 4....................................5 Variable Speed .....10 5 MEASURING AIRFLOW .............................. 74 Vane Anemometer ..........................2 6................................................... 107 6. 92 Axial-Flow Fans ................................................. 67 4..............................................5 5... 59 4.........................................................................................7 4...................3..........................................9 5.......................... 88 Traverse Velocity Measurement .................................................................... 69 Series Circuits...... 73 Assignments ...........................................................................9 4.............................................................................................................................................................................................6 4.. 86 Selection of Measurement Site.......................................................................8 Fans in Parallel........4...........................9 Assignments ................ 89 Single Spot Reading Method .................................................................................................1 Fan Total Pressure ............... 102 6..1 Entrance ................3 4...................109 Measuring Fan Performance .1 Construction of an Axial-Flow fan......1 5........................10 Fan Diffuser ........................... 59 Airflow Equation ........ 90 6.................................. 104 6..............1 Laminar Flow ................................................7 Fans in Series.........................................8 5........8.............3 6................................................ 108 Fan Laws .........3 Elbows .....................................................8.......................................................................................................1 6..................... 91 Fan Terminology ....................................................................................................................8........................................................................................4 Expansions and Contractions......... 106 6...............................................................................................8 4..........................5 Junctions and Splitting...............................8............................... 95 The Fan Characteristic (Performance) Curve................................................................. 87 Measuring the Airway Cross Sectional Area ...................................................................................................................................7 5..........1 System Damper....................................................6 6..........................................................................6 5........................ 89 General Description of Fans ...................................................5 6...............................................................................................7 6.......1 Construction of a Centrifugal Fan...................... 66 4......... 70 Parallel Airway Circuits ............... 103 6..................................................................................................9 6........................8.........................................................................3 Inlet-Box Damper. 85 Pitot-Static Tube ..................... 57 4................1......... 93 6...... 68 Other Methods of Expressing the Shock Factor X ....................................................................................................................................... 94 6..........BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY 3............... 71 Complex Circuit (Networks) .............3 5............................................................4............................4............................................10 6 UNDERSTANDING FANS...................................................................................4 Variable Inlet Vanes ..... 100 Fan Stall .................................................................... 101 6.....8....................3................... 60 4.....1................. 88 Spot Reading Method .....................................................................................................4..................... 72 System Resistance Curve ...................4 4................................................ 85 Smoke Tube..................5 4................................ 85 Velometer.................. 84 5..4.......................... 64 4................................................................................................................................................................................... 110 4 FUNDAMENTALS OF AIRFLOW ................... 101 Fan Performance Control......................... 94 Centrifugal or Radial-Flow fans .................................................................................................................................................................................................9 The ‘Eck’ Line ......................2 Outlet Losses............................................................................................................................6 Variable Pitch ........................................... 66 4...................................2 Turbulent Flow. 102 6................................................................... 68 4.....................4................................10 Page iv © AMC Consultants Pty Ltd 2005 ............. 62 Shock Losses.....8....10.......................... 95 Interpreting Fan Performance Curves ......................................................8................................................................. 84 Hot Wire Anemometer ..........................................1 Atkinson’s Equation .....................2 Outlet Damper .........................2 5......................... 105 6............4 6........................4 5.................. 58 4.......................8 6.. 59 Resistance (The friction factor)..................................................... 103 6...................8.................................... 109 6..............................................................................8............. 104 6.. ............. 146 7.......................................... 146 Effect of Atmospheric Changes on Mine Strata Gases ........ 138 Re-entry after Blasting in a Development Heading ..........................................3 Diameter Change ........................................................ 111 6.............1 Selection of Measuring Site............................................................................................................................... 149 7..............9 7..................19 7....3 7.............5 Dilution........................................19.... 130 Ventilation Controls....................7 7..............16...................................................................2............ 135 Velocities in Primary Airways........20.................................4......................10.........14 6......... 146 7................................ 119 Primary Airflow Requirements ......5 Recirculation. 117 6.................................................2 The “Reuse” of Air ....4 Use of Stope Voids as Airways . ............................... 129 7.....................................................................4 7..................................................................................................................................3 Time Value of Money................... 127 Circuit Booster Fans .........................10...........................................................................................3 Forcing or Exhausting.............................................................. 128 7................................................ 115 Fan Laws ...............16.... 131 Secondary Ventilation Systems .........................16.................................................................1 Determining Primary Air Quantities...21 Page v © AMC Consultants Pty Ltd 2005 ........... 132 7....1. 146 Control of Mine Gases ..................................2 Optimum Airway ... 133 Ventilation Duct...........................................................7...................................... 137 7............3 Fan Static Pressure ...........................11 6.......................... 122 7............. 156 7............................................................................7.........................................................................................2......2 Underground Primary Fan Arrangements ..........................................................................1 Installing Secondary Ventilation Fans ..............................................................................4............................................10............5 7............. 151 Economics of Airflow................................................. 154 7.................................2 7....................................... 117 Fans Failure .......4....................................................................................14 7.................................................................................16 7...................13 7................................................................................................................................... 125 7.........................2 Fan Velocity Pressure .1 Prevention.....................2...........4.............4................................ 114 Measurement of Airflow ......................16.......................20..... 127 7............................................................. 127 Primary Ventilation Circuits................ .............................................18 7............................................................................... 129 7........... 111 Pressure Fans......................... 146 7....2 Extraction......... 147 Spontaneous Combustion ...........117 6.................... 134 Duct Leakage..............................16 6........16.......10 7............................ 121 7...................................................20...........................................1 Surface Fan Installation Arrangements .1 Velocities in Access Drives. 111 Exhausting Fans ............................. 155 7............................. 138 Equipment Movement in Underground Airways ...........................................3 Series Ventilation Circuits...................................1 Cost of Airflow..........................................13 6............... 147 Control of Dust ..........15 6.................... 145 Gasses from Diesel Engines ........................................................................... 146 7.... 112 Air Power .12 6............................16......... 140 Gases from Sulphide Orebodies........................................ 146 7............................................... 157 Rule-of-Thumb Principles and Design Factors ..........11............................................. 113 Fan Efficiency .................................................................................... 131 7.......................................... 130 Multiple Access Orepasses .....4 Containment ......................................................................................................................................................12 7.....2 Secondary Fans and Parallel Ventilation Circuits........................15 7......................17 6.........................................16................................... 110 6..........................................................................................................18 6...................................................................................... 122 Primary Ventilation Fans................................1 7..................................1 Density ( ) Change...............................................16.1 Dust Extraction ....................................6 7...................................................................... 137 Water in Upcast Shafts .3 Isolation ........................................................ 158 7 MANAGEMENT ............................................. 126 7...............1 Parallel (One Pass) Circuits ........................................................................................................................ 129 7...2 Speed Change............................................... 117 6....................................................17 7..............................................8 7. 128 7....20 7........................................................BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY 6.......... 119 Effect of Reversal of Rotation ..................................................11 7.......................... ..........................4................................................................................................................. 161 8.........................................................................................................3 Friction Factors...............................................1 Simulation Model Layout ...............................................................................1 8...........................................4 Shock Losses ............. 166 Results: ..........6 Fixed Airways ................................. 164 8................................................................................................................... 165 8.................................................................................................................2................4...... 166 8........................................................................... 160 Analysis of a Network ........................................................4...........4....... 164 8.......... 164 8......5 Fans. 165 8.......5 Page vi © AMC Consultants Pty Ltd 2005 ... 163 Input Data ...................................................4............................................. 160 8..... 162 Computer Modelling.................1 Hardy Cross.....................4.......BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY 8 NETWORKS AND COMPUTER MODELLING ...2 8...........4 Ventilation Networks ....2 Number of Airways ..................................3 8............................................. 165 8............................................................. The search to identify specific substances and their harmful concentrations is on going with limits constantly under review. It is possible that any known substance will be identified. if positive airflow through the workings was not provided the air would very quickly become stale. and at worst cause serious or even fatal illness. recommended maximum exposures to various contaminants are constantly under review and the latest information should always be sought Worksafe Australia produce a publication titled “Exposure Standards for Atmospheric Contaminants in the Occupational Environment” which provides comprehensive information on the present exposure standards for known hazardous substances along with information of substances presently under review. removes the contaminants from the workplace. dilutes dust and gases and 3. Levels of atmospheric contaminants that are “safe” in an occupational health and safety environment are often difficult to determine. The prime contaminants produced during mining are 1. in either the air we breathe or the food we eat. Because of the processes of mining. If they are not adequately dealt with.15th Century 1 CONTAMINANTS AND EXPOSURE STANDARDS The basic requirement for the mine ventilation system is to provide air for people to breath and in a state that will not cause any immediate or future ill effects. heat 3.e. as they are identified.e. gases (including water vapour i. they may become at best a discomfort to mine workers. it is only the dose that separates the poison from the remedy” Paracelsus . Humidity) and the prime method for dealing with these is an effective ventilation system that 1. dust 2. The ventilation system must therefore be sufficient to deal with the contaminants released during mining. This standard represents the concentration of substances that should not cause undue discomfort or impair the health of persons when exposed to these Page1 © AMC Consultants Pty Ltd 2005 . Although the human body is equipped to reject or absorb these substances this can only be done providing the quantities involved are not excessive. contaminated and unfit for human consumption. supplies oxygen and coolth 2. combined effect of simultaneous exposure to several contaminants) Work rate (affects respiration rate) Work cycle (“compressed” work cycles give the body less recuperation time between exposures) Changes in scientific understanding As a result of the above factors.BASIC MINE VENTILATION Contaminants and Exposure Standards “All substances are poisons. There are many factors which must be considered including: Variability in response of individuals to contaminants Synergistic effects (i. au This website tells us that when interpreting the actual “Exposure Standard” it is important to note that they
….2 Short Term Exposure Limit (STEL) Some substances can cause intolerable irritation or other acute effects upon brief overexposure. averaged over a period of 15 minutes. 1. under normal climatic conditions and where there is a sixteen-hour period between shifts to permit elimination of any absorbed contaminants. exposure should be controlled to avoid both acute and chronic health effects. or work at high altitudes.”have been established on the premise of an eight-hour exposure. Generally. These are important supplements to the eight-hour TWA exposure standards that are more concerned with the total intake over long periods of time. or for more than four such periods per working day. thereby increasing the uptake of airborne contaminants. but under no circumstances should a single determination exceed 15 minutes. Page 2 © AMC Consultants Pty Ltd 2005 . Similarly.nohsc. such as excessive humidity or heat.1 Peak Limitation For some rapidly acting substances and irritants. Although it is recognised that there are analytical limitations to the measurement of some substances. They do not however represent a “no-effect” level to all persons exposed to the concentrations stated. may lead to an increased uptake of contaminants. compliance with these ‘peak limitation' exposure standards should be determined over the shortest analytically practicable period of time. and narcosis to an extent that could precipitate industrial accidents. These substances may induce acute effects after relatively brief exposure to high concentrations and so the exposure standard for these substances represents a maximum or peak concentration to which workers may be exposed. the averaging of the airborne concentration over an eight-hour period is inappropriate. time weighted average and general excursions. short term. A minimum of 60 minutes should be allowed between successive exposures at the STEL concentration. although the primary toxic effects may be due to long term exposure through accumulation of substances in the body or through gradual health impairment with repeated exposures. heavy physical work under adverse climatic conditions. This information can be found on the Internet at www. Short-term exposure limits (STELs) provide guidelines for the control of short-term exposure. They are of course based on current knowledge and research and are subject to change. STELs are established to minimise the risk of the occurrence in nearly all workers of: intolerable irritation chronic or irreversible tissue change. It is therefore of particular importance that any evaluation of the working environment considers the lung ventilation rate where there is a significant airborne concentration of contaminant. 1. Workers should not be exposed at the STEL concentration continuously for longer than 15 minutes. Under these circumstances.” This website also provides descriptions of the specific exposure standards for peak.gov. This short term TWA concentration should not be exceeded at any time during a normal eight-hour working day.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY substances. STELs are expressed as airborne concentrations of substances.” And “ Heavy or strenuous work increases lung ventilation. during work of normal intensity. BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY 1. 1975. It should be emphasised that guidance of this type. R. and should only be accepted in the light of expert advice. “Occupational Exposure Limits for Novel Work Schedules.5 Adjusting the Eight-hour Exposure Standard for Longer Periods “Compressed” work cycles (usually in fly-in/ fly out operations) consisting of 12-hour shifts for up to (and sometimes exceeding) 14 days duration is now commonplace.h) Eight Hour Exposure Standard 16 h h = hours worked per day BRIEF. SCALA. or where a peak value has been assigned. these TWA exposures permit excursions above the exposure standard provided they are compensated for by equivalent excursions below the standard during the working day. for a five-day working week. However. the exposure standards for airborne contaminants are expressed as a time-weighted average (TWA) concentration of that substance over an eight-hour working day. it is the most conservative model developed and does not require any detailed knowledge of the substance. with some of the major excursions giving rise to a significant proportion of the overall exposure.4 Guidance on General Excursion In practice. Specialist consideration and expert advice should be sought in the specification of modified exposure standards. there should be some control of concentration excursions.” American Industrial Hygiene Association Journal. is not directly health-based and does not supersede any STEL or peak limitation set.. aimed at placing some restraint on concentration excursions. 1. the STEL will supersede this guidance on general excursion. Adjusted (TWA) Exposure Standard Where 8 (24 . R. 1 Page 3 © AMC Consultants Pty Ltd 2005 . or on the relationship between accumulation and elimination of the body burden of the material or its metabolites. As yet. the actual concentration of an airborne contaminant arising from a particular industrial process may fluctuate widely with time. NOHSC recommends the use of the Brief and Scala (1975)1 model to adjust the time-weighted average (TWA). 36: pp467-469. This method was chosen because it is a simple calculation. 1.. based on observations of the variability in concentrations observed in industrial environments.3 Time-Weighted Average (TWA) Except for short-term exposure limits. Where adequate toxicological or epidemiological data allows the assignment of a STEL. it is not necessarily acceptable to expose workers to concentrations significantly higher than the exposure standard solely because the exposure is for less than an eight-hour day or because the exposure occurs only occasionally. there is no agreement on the extent to which TWA exposure standards should be reduced in response to various work patterns. Even where the TWA exposure standard is not exceeded. A process is not considered to be under reasonable control if short term exposures exceed three times the TWA exposure standard for more than a total of 30 minutes per eight-hour working day. or if a single short term value exceeds five times the TWA exposure standard. During periods of continuous daily exposure to an airborne contaminant. A practical approach to control has been developed. Permissible variations in the exposure standard for such situations are dependent on such factors as the acute effects of short-term exposures. 500 1.00 0.000 5 UR 5 15 NA NA NA 1.10 STEL Any 400 35.00 NA = Not Applicable Page 4 © AMC Consultants Pty Ltd 2005 . Adjusted TWA 8 (24 .40 1.5 12 1 5 2.000 3 25 2 10 5. The adjusted TWA exposure for Carbon Monoxide (CO) assuming a twelve-hour working shift is calculated as follows.50 0.50 0.14 12-hour 15 2.00 UR = Under Review 10-hour 21 3500 2 18 1 7 3.20 2. A Comparison of some Atmospheric Exposure Standards Adjusted for Shift Duration CONTAMINANT * Carbon Monoxide (CO) * Carbon Dioxide (CO2) * Nitrogen Dioxide (NO2) * Nitrous Oxide (NO) * Sulphur Dioxide (SO2) * Hydrogen Sulphide (H2S) # Respirable Dust # Quartz Bearing Dust # Respirable Combustible Dusts NOTES: * = ppm # = mg/m3 TWA 8-hour 30 5.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Example The eight-hour exposure standard for Carbon Monoxide is 30 ppm.12) 30 16 12 = 15 ppm No adjustment is necessary for the excursion limits of peak concentrations or the short-term exposure limit (STEL). The human capacity to function at the maximum potential will reduce rapidly in atmospheres contaminated with dust. In the mines of Carpathian Mountains women are found to have married seven husbands.g. ranging from long-term physical impairment (e. it eats away the lungs. asphyxiant.g. lung disease) to immediate death (e. However. heat and humidity and the long term effects of exposure to contaminants may have serious impact on general medical health. all of whom this terrible consumption has carried off to a premature death. or heat stroke). Gases. it is vital that the hazards are well understood. It should be noted that the human body is very resilient and well equipped to deal with nature’s climatic and atmospheric extremes. which is stirred up and beaten up by digging penetrates the windpipe and lungs and produces difficulty in breathing and the disease the Greeks call asthma. including poisonous. This chapter describes some of the more common mine environmental hazards.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY “Some mines are so dry that they are entirely devoid of water and this dryness causes the workmen even greater harm. A significant number of these hazards can result in serious health problems. If the dust has corrosive qualities. It is the role of a mine’s ventilation systems to control these hazards. 2.“De Re Metallica” (1556) 2 OCCUPATIONAL HEALTH AND SAFETY There is a surprisingly broad range of environmental hazards in underground mining. some processes involved in activities such as mining produce contaminant levels and environmental conditions which are beyond those with which the body’s natural defence systems can cope. but before any ventilation engineering design work is carried out.1 The Respiration System Medical science has proven the human body to be very resilient and well equipped to deal with nature's climatic and atmospheric extremes. gases. carbon monoxide poisoning.” Georgius Agricola . carcinogenic or explosive dusts and gasses and extremes of heat and humidity. However it has also shown that some processes involved in today’s manufacturing and industry may have a detrimental effect on parts within the human body. vapours and dusts may enter the human body in three ways Inhaled into the respiratory system Ingested with food and saliva into the digestive system Absorbed through the skin However it is the respiratory system which provides the major mode of entry into the body Page5 © AMC Consultants Pty Ltd 2005 . and implants consumption in the body. for the dust. smoke. fumes. which are hair-like cells acting with a wave-like motion. Inhalation of very coarse dust particles causes coughing and sneezing. The dust is moved upwards to the mouth.0 l/min. where it is either expectorated or swallowed. the lungs are exposed to any dusts. aerosols. These are relatively large white cells (up to 10 m diameter). gas or vapour that is small enough to remain airborne. By the very nature of their function. Once this has occurred. it passes through the walls of the alveoli and surrounding capillaries into the blood stream. The blood transports the oxygen to the body tissues. the mucus coated membranes of the nasal passages and hairs of the nose aid in capturing almost all of the coarser particles. These act as pre-filters. T he cells are mobile and their role is to completely engulf the fine foreign particles which enter the alveoli. where it is consumed in the process of energy production. These include: Nasal hairs.0 litres and 4. Oxygen is ‘captured’ in tiny air sacs (called alveoli) in the lungs. mists. Because more air is inhaled as work becomes harder. it is easy to understand why workers in heavy dusty jobs such as mining and construction are more likely to suffer from dust and other contaminant-related lung disorders. The trachea and bronchi are lined with sticky mucus that is wafted up these airways via the action of cilia. producing carbon dioxide as a waste product. fumes. The human respiratory system has a number of defence systems which are designed to deal with the concentrations and size ranges of dust normally found in nature. which supplies air to the alveoli. gases or vapours small enough to remain airborne. The respiratory system is basically a ventilation system. It is therefore important to have a basic understanding of the principles behind the operation of the human respiratory system. When air is breathed in. The difference between oxygen and carbon dioxide concentrations in blood in the capillaries and the air in the alveoli causes an exchange of gases. this can increase to about 8. Cilia.0 litres of air per minute (l/m) and during times of hard work. An adult breathes between 2. The blood stream carries the carbon dioxide back to the air sacs to be breathed out. which has the effect of speeding up the removal process. By the very nature of their function. aerosol. which lie on the surfaces of the alveoli. the lungs are exposed to any dust. The finer dust particles will however reach the alveoli. smoke. Macrophages. When we inhale. Every organ in the body requires oxygen. mist. the macrophages Page 6 © AMC Consultants Pty Ltd 2005 .BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY The respiration system is the main point of entry into the body for many of the particulate and gaseous contaminants found in the underground environment. If the particles had a density of 3kg/m3 the eight-hour exposure level would be 0. 2.g.1. movement of rock in stopes.2. muds and clays. mucking operations. drilling. Dust particles in mine airflow will settle out of laminar airflows according to Stokes Law. beach sands.291 mm3 producing 2. crushing. road-header etc). ore passes. black on white with good lighting) is around 25 m and It is generally accepted that the smallest particle visible to the naked eye can be as large as 50 m. This is known as Stokes Law. As an example of dust production. Some of the more significant sources of dust in underground mines include blasting. If it takes 10 minutes to bore the hole and there is a ventilating airflow of 20m3/s each mm3 of air would be contaminated with 241 particles.000 million dust particles. If we were to use the same force using a chisel it would break only a small piece of the rock into fine dust particles because the force is directed onto a much smaller area. and the tumbling action in rivers and ocean wave motion.2. 2. the impact action of rocks on each other as they knock together during landslides. The smallest dust particle that can be seen with the naked eye under good conditions (i. If the airflow is turbulent then the motion of airborne particles is unpredictable are more likely to be removed from the airflow by coagulation and impingement rather than settling.89 x 1015 dust particles of 1 m diameter. They remain in the lung tissue. In mining dust is formed by powerful concentrated forces such as blasting.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY usually then move up the respiratory system and are eventually expectorated or swallowed.e. In reality the majority (99%) of drilling particles are much larger than 1 m and are contained in the drilling water. Because this type of impact is limited. In a drill hole 3. other modes being absorption and ingestion.2 Dust In nature dust is mainly formed by the grinding action of wind blown particles on rocks. raise drilling.. dust formed in this way is rather coarse e.1 The Hazard of Dust The long-term effect of dust inhalation is not necessarily confined to the respiratory system and there is some research that suggests that the respiratory system merely provide the mode of entry into the body. Dust is also liberated to the ventilating air from by the tyres of passing traffic lifting the dust from the surface of the mine roadway. For example striking a rock with a hammer will split the rock into large pieces forming coarse dust particles. 2.7 mg/m3. Dust is a result of the disintegration of matter and the size of the dust particle produced is determined by the impact per unit area. crushing 1mm3 of rock to 1 m particle sizes would yield 1. it is also the duration of exposure and the rate of deposition to the critical area. rock breakers. Certain dusts are toxic to macrophages (including free crystalline silica and asbestos) and these substances cannot therefore be expelled from the lungs.g. It is not simply a matter of the quantity of dust in the atmosphere that dictates the amount deposited in the lungs.895. The size of dust particles is measured and expressed in microns ( m). Page 7 © AMC Consultants Pty Ltd 2005 . resulting in a gradual incapacitation of the lungs. mechanical rock cutting (e. The respiratory system is very selective with respect to the size and quantity of dust retained in the lungs. and grinding and consequently forms much smaller dust particles than those formed by nature.1 Settling The terminal velocity of an airborne dust particle is dependant upon the atmospheric drag force holding the particle up and the gravitational force pulling it down.6m deep and 32mm diameter the volume of rock removed is 2. crushers and conveyor transfer points. even in still air. even in still air.s) Stokes Law Gravitational Force 1 3 d w S 6 w g a 3 d v Drag Force Stokes Law is applied to spheres G=F 1 3 d wS 6 Therefore Brownian Motion wa g 3 d v Equation 2-1 Stokes Law v d2 g wS 18 wa The Brownian motion is a random motion that occurs when dust particles collide with gas molecules in the air with no net tendency to move downwards.0m would require 8. This motion completely masks observations made on the particle in question and the resistance to the particle becomes less and they tend to “slip” past the gas molecule at a speed faster than that indicated by stokes law. In fact because of the turbulence associated with mine ventilation along with the Brownian motion it would be considerably greater. In those cases were the settling velocity is equal to or less than the Brownian displacement the particle will never settle.29 mins to settle to the ground and 1 m particle would take 12.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Where G = Gravitational Force d = Geometric diameter of the sphere (m) wS = Density of the sphere (kg/m3) wa = Density of the air (kg/m3) g = Acceleration due to gravity (m/s2) F = Drag Force v = Velocity of the particle (m/s) = Viscosity of the fluid (kg/m.04 x 10-3 m/s and if released from a height of 4. The terminal settling velocities may be calculated from the above equations.8 hours.53 x 10-8m at 20 °C and 101. v 1 2A dP Equation 2-2 Cunningham’s slip corrected velocity Page 8 © AMC Consultants Pty Ltd 2005 .7 to 0. Slip Corrected Velocity Cunningham (1910) introduced a slip correction vC Where VC = Slip corrected velocity of the particle (m/s) A = a constant which varies from 0.9 = the mean free path of the gas molecule (6. For example a quartz particle with a geometric diameter of 10 m will have a slip corrected settling velocity of 8.3kPa) dP = diameter of the falling particle (m) Particles having terminal settling velocities of the same order as the displacement caused by the Brownian motion will remain suspended. 19 x 10-4 7.796 0.04 x 10-3 2.033 0.33 x 10-4 8.96 x 10-7 1.34 1. The impaction of particles on falling water droplets can be used for the removal of airborne particulate (dust) from the airflow. irrespective of the substance of which they are composed.18 x 10-2 7.5 167.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Physical Properties of Airborne -Quartz Particles at 19.8 32.18 x 10-6 3.63 0.5 66.09 x 10-7 1.20 x 10-2 8.8 81.03 x 10-3 3.14 3.52 x 10-6 5.199 0.163 0.5 0.167 0.081 0.02 0. It is generally accepted that the smallest particle visible to the naked eye can be as large as 50 m. The smallest dust particle that can be seen with the naked eye under good conditions (i.0/20. This process continues until the particles become large enough to settle.74 x 10-7 1.99 x 10 -5 Slip-corrected terminal velocity (m/s) 4.99 x 10-7 3. There is also the chance that high velocities will sweep the particles from the obstruction.797 0.08 x 10-5 4.01 Aerodynamic Diameter ( = diameter of unit density sphere) ( m) 407 162. shape and density of the Page 9 © AMC Consultants Pty Ltd 2005 . concentration and collision efficiency with the efficiency dependant upon size.033 0. black on white with good lighting) is around 25 m.2.67) ( m) 417.19 x 10-6 7.96 x 10-5 1. The site of the deposition varies with the size.4 16.96 x 10-9 1.977 0.0 83.128 7.1 33.08 x 10-8 2. This impaction occurs when the inertia of the particle is high enough to cause the particle to stick to the obstruction.89 x 10-7 9. Dust of particular concern to mining practitioners is that fraction inhaled and retained in the respiratory system.54 x 10-6 2.835 0.99 x 10-3 3. increasing the chance of collision and therefore increasing the rate of coagulation. The size of dust particles is measured and expressed in microns ( m). The success of this method is dependant upon the number.96 x 10-3 1.8 50.979 0.63 x 10-7 1.89 x 10-6 9.084 0.05 0.3 8.2 Coagulation Particles of dust in air will coagulate spontaneously and continuously.3 Impingement Impingement (impaction) of dust particles occurs when an obstruction to the flow is encountered and the velocity of the medium is great enough.77 x 10-7 8.e.87 x 10-5 6.35 x 10 -5 Brownian displacement per second (m) 4.0 °C and 85kPa Equivalent geometric diameter of Quartz particle ( m) 250 100 50 40 30 20 10 5 2 1 0.19 x 10-2 3.1 0.17 x 10-2 3.74 x 10 -6 7.26 1.69 x 10-5 2.1.89 x 10-5 2. The rate of coagulation increases with the turbulence of the medium in which they are contained.67 0. density and velocity of the particle and the water droplet.1 48.1.017 Stokes Terminal Velocity (m/s) 4.18 x 10-5 3. As eddies and swirls are formed the velocities of the particles relative to each other becomes greater. As soon as they touch they will fuse and stick together.08 x 10-6 4.814 0.36 x 10-7 6.35 3.4 65.7 8.2.199 0.016 Stokes diameter (from experimental data dp/ds = 1:1.84 x 10-6 6.6 16.26 x 10-6 1. 2.127 7. Recommendations from the 1959 Johannesburg Pneumoconiosis Conference have formed the basis for dust measurements monitoring in the years following..BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY particles and this was first described in the proceedings from the Pneumoconiosis Conference held in Johannesburg in 1959.132) 2 th Page 10 © AMC Consultants Pty Ltd 2005 . Below 0. the remaining particles have a high probability of deposition.2 Deposition in at these sites was shown to depend on three factors: (1) the percentage removal of particles before reaching the pulmonary lobules as the inhaled air passed through the nasal chamber and air passages. The proportion deposited falling off as the size of the particle decreases. and zero efficiency for particles of 7 microns and upwards. For particles below 2 m there is insufficient time for settlement to occur. In short this experimental work shows that: (1) Particles with a diameter larger than 10 m are deposited in the nasal passages. (2) the fraction of tidal air volume which reaches the pulmonary spaces. “Respiratory Dust Retention and Elimination” Proceedings of the Pneumoconiosis Conference. the probability for deposition increases due to the bombardment of these very fine particles by molecules. 50 % efficiency at 5 microns. p 113. (3) Because of the high retention time in the lungs. (2) Particles with a diameter larger than 2 m tend to be deposited in the branching ducts leading to the lungs (bronchial tubes). (3) the dust collection efficiencies of the pulmonary spaces. (the ‘equivalent diameter’ of a particle is the diameter of a spherical particle of unit density having the same falling velocity in air as the particle in question.5 m. all sizes refer to the equivalent diameters. T. Johannesburg 9 – th 24 February 1959.)”3 HATCH. Virtually no 1 m particles are deposited in the nasal passages. One of the most significant recommendations adopted from this conference was: “That measurements of dust in pneumoconiosis studies should relate to the ’respirable fraction’ of the dust cloud. this fraction being defined by a sampling efficiency curve which depends on the falling velocity of the particles and which passes through the following points: effectively 100% efficiency at 1 micron and below. Johannesburg 9 th – 24 February 1959. it is also the duration of exposure and the rate of deposition to the critical area.2 Effects of Dust Because the pre filters of the respiratory system are not developed to cater for the much finer dusts produced with mining activities. Of those particles. Diffusion as applied to microscopic particles and. breathlessness and a lessened capacity for work. The respiratory system is very selective with respect to the size and quantity of dust retained in the lungs. About 50% of these particles (usually less than 3 m) deposit mainly due to diffusion and impaction. and. 2. The remaining 50% will remain airborne and will be exhaled. Impacting due to inertia. Continued accumulation may eventuate with the formation of plaques on the alveoli walls causing shortness of breath and an increase in the frequency of colds and influenza etc. other modes being absorption and ingestion.g. Dusts that cause little or no chemical reaction and subsequent tissue scarring are classified as inert. Chemically active dusts (e. In these areas the length becomes the controlling factor for deposition.Proceedings of the Pneumoconiosis Conference. which causes the condition known as pneumoconiosis (from two Greek words meaning dust and lungs).2. The terminal settling velocity of airborne fibres is almost independent of length. Deposition from gravitational settlement and impaction may be avoided in the upper respiratory tract allowing the fibre to penetrate into the fine air passages of the lungs. although this may be misleading. Interception due to the physical size of the particles. The long term effect of dust inhalation is not necessarily confined to the respiratory system and there is some research that suggests that the respiratory system merely provide the mode of entry into the body. The deposition in the respiratory tract occurs according to the following mechanisms: a) b) c) d) Gravitational settlement as determined by the free falling terminal velocity. It is this accumulation of dust in the lungs. 50% of 5 m particles and. silica) decrease the active life of the macrophages and eventually result in permanent alteration or destruction of the alveoli. as excessive inhalation will result in accumulation in the alveoli region causing mobilisation of the macrophages (which engulf small particles) and are the last line of defence of the respiratory system. South Africa in 1959. A number of health problems may be caused by the excessive and or prolonged inhalation of dust. chemical and toxicological properties of the dust involved. p 619 th Page 11 © AMC Consultants Pty Ltd 2005 . It is not simply a matter of the quantity of dust in the atmosphere that dictates the amount deposited in the lungs. 20% of 6 m particles. 0% of particles > 7 m will enter the human lung. some of this dust manages to enter the finer passages of the lungs and remain there. This becomes very evident with a decreased lung expansion. The biological response is dependent upon the physical. These permanent changes cause scarring of the lung tissue and result in a reduction of the elasticity of the lung tissue and a subsequent less efficient oxygen intake. This curve has since become known as The Johannesburg Curve and clearly demonstrates that 100% of particles <1 m and. Interception becomes the mechanism. less than 5 m only 50% penetrate into the alveoli region of the lungs. therefore it is the dust particles less than 7 m that are the primary concern for mines. Fibres of 50 m and up 3 Recommendations Adopted by Pneumoconiosis Conference .BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY A simplification of the dust deposition curve was constructed on this basis and recommended by the International Pneumoconiosis Conference held in Johannesburg. as excessive inhalation will result in accumulation in the alveoli region thus causing mobilisation of the macrophages (which engulf small particles) and are the last line of defence of the respiratory system.3 Dust Exposure Standards Allowable concentrations of dusts in work places have been determined from epidemiological studies that by their very nature extend over 20 to 30 year periods. Fibrous materials include asbestos. calcite. This may be misleading. The longest fibres are usually found in the bronchi and alveoli. As a consequence exposure standards are constantly being reviewed and updated. or by experimental work on animals. breathlessness and a lessened capacity for work. magnesite.4 Explosive Dusts The most common explosive dust in metalliferous mining is sulphide dust.gov. The biological response is dependent upon the physical.nohsc. Page 12 © AMC Consultants Pty Ltd 2005 . the diameter of these fibres is almost always less than 3 m.au for definition of “inspirable” 2. chemical and toxicological properties of the dust involved. Chrysotile Where there is no exposure standard Exposure Standard (TWA) 0.GOV. The biological response is dependent upon the physical. Chemically active dusts (e. Continued accumulation may eventuate with the formation of plaques on the alveoli walls causing shortness of breath and an increase in the frequency of colds and influenza etc. Some current dust exposure standards from this internet site which are relevant to the mining industry are: Selected Exposure Standards (FROM HTTP://WWW. Reference should be made to http://www.2.NOHSC.2 mg/m3 (respirable) 3 mg/m3 (respirable) 0. silica) decrease the active life of the macrophages and eventually result in permanent alteration or destruction of the alveoli.au/databases/ for the most up to date information on exposure standards. In short.gov. the probability of a fibre impacting the wall of an airway becomes greater as the fibre becomes longer.2.g. This becomes very evident with a decreased lung expansion. Dusts that cause little or no chemical reaction and subsequent tissue scarring are classified as inert. other forms or mixtures. This is because any physiological damage to workers is not usually detected in the early years of exposure and respiratory problems manifest only after a number of years of exposure.nohsc. mesothelioma and lung cancer. Diseases caused by exposure to various types of dust can range from lung tissue scarring to pneumoconiosis. A number of health problems may be caused by the excessive and/ or prolonged inhalation of respirable dust. Sulphide dust explosions can cause considerable damage to underground facilities and will cause the release of poisonous gasses (primarily SO2).AU/DATABASES/) Dust Type Quartz Coal Dust Asbestos including: Amosite. Crocidolite.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY to 200 m have been found in human lungs. A number of health problems may be caused by the excessive and or prolonged inhalation of dust.1 f/ml (respirable) 1 f/ml (respirable) 10 mg/m3 (inspirable*) *refer to http://www. 2. These permanent changes cause scarring of the lung tissue and result in a reduction of the elasticity of the lung tissue and a subsequent less efficient oxygen intake. chemical and toxicological properties of the dust involved. apatite gypsum and talc. mica. .BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Sulphide dust explosions generally occur at firing time in massive pyritic or pyrrhotitic ore bodies and have been documented since at least the early 1920’s. such as heat stroke. The effect is similar in humans and machinery working in a confined space such as an underground mine. As air passes through the mine ventilation circuit it is subject to a number of sources of heat. Up to a point the faster the flow the faster the heat removal. “AMIRA – Sulphide Dust Explosions Volume 1 – Cause and Prevention in Development Headings Project P316-P316A (1990-1994)” (11 May 1995) ENRIGHT.J. LEONTE. R. Air at normal atmospheric temperature flowing through the radiator will absorb some heat from it. These include: ENRIGHT. the car engine will quickly overheat because there is insufficient airflow passing through the radiator.g. machinery and the surrounding rock to a temperature equal to the temperature of the person. This simple cause and effect is often not fully appreciated and a number of mines attempt to “soldier on” without ever facing up to what can be a very important and significant problem which impacts on employee health. For example if a car is allowed to idle for extended period of time (such as when caught in a traffic jam in the middle of summer). Even relatively low levels of heat can lower the workforce morale. diesel and electrical powered equipment) and need to be considered at the early stages of any project. Project P316A-P316B (1990 –1995)” (1996). though to life threatening illness. is the same as the principle of a car radiator. The principle for the control of heat build up in a mine. M. The following procedures should be adopted in orebodies that are known to have the potential to produce sulphide dust explosions: – Adequate stemming should be used – The use of detonating cord should be eliminated – All personnel should be removed to a safe place before firing Enright .3 Heat 4 & 5 The adverse effects of heat range from discomfort.J. re-entry into the mine is extended beyond what could normally be expected. ambient air temperatures and auto compression) or artificial (e. and the radiator will be kept at a lower temperature.. with all the attendant problems of high accident rates and low productivity. Which ever is the highest? Sources of heat in mines can be categorised as either natural (e. “AMIRA – Sulphide Dust Explosions Volume 2 – Detection and Preventative Measures. safety and mine productivity. If the air is constantly flowing through the radiator then the heat will be removed. (1996) when discussing preventative measures states “Murphys Law” applies with a vengeance in underground mining and it is inevitable that despite all reasonable precautions sulphide dust explosions will occur. Because of this the recommended approach is to eliminate the explosions by adoption of preventative measures prior to and during blasting. high concentrations and toxicity of the sulphur dioxide gas produced with these explosions. rock or machinery. The explosions are known to occur in ore and waste rock containing 20% sulphur with reporting’s of explosions in rocks with as little as 11%. LEONTE. Because of the large quantities.g.” 2. These explosions are significantly more destructive when they occur in stope blasting than in development headings. 5 4 Page 13 © AMC Consultants Pty Ltd 2005 . The surrounding air absorbs the heat generated by humans. rock temperatures. R. M. The following points should be noted: Autocompression is not strictly speaking a heat source (it results from a conversion of energy.000m shaft into a mine would increase by 9. If the water is free flowing then this temperature increases to 2. For dry air. For example the rock temperatures in Tasmania are hotter than the rock temperatures in the Barkley Tableland of Northern Territory. Page 14 © AMC Consultants Pty Ltd 2005 . the temperature of dry air flowing down a dry 1.81 kJ/kg/1. assuming no heat flow and no work done: H2 Where: H1 g( Z1 Z2 ) Equation 2-3 Auto Compression H = enthalpy (J/kg) Z = elevation (m) g = acceleration due to gravity (9. resulting from the random motion of the air molecules. It is also important to note that water temperature will increase with depth. its elevation decreases. rather than from the addition of an external heat source). Autocompression causes the air temperature to increase.340C per 1000m.000m. In some places the rocks are hotter than others simply because they are newer and have yet to cool down and this varies considerably. 6 Enthalpy is the energy per unit mass (in this case of the air). Elthalpy includes the thermal energy and the energy due to the pressure of the air.000m decrease in elevation.76 °C/ 1. If the water is contained in pipes then this increase in temperature is in the order of 0.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Auto Compression: . In contrast. the thermal capacity is 1. As we get deeper it gets hotter because the rock hasn’t transferred its heat to the air. It does not always follow that cold places have cold rocks. the temperature rise due to other sources of heat decreases.76 °C (assuming there is no heat exchange between the air and the rock surrounding the shaft). In other words. Transfer from the surrounding rock: Surface rock temperature is around the annual average air temperature and can provide either cooling or heating depending on the air temperature passing over the rock.81 kJ/kg for every 1. therefore as the mining depth increases. There is a corresponding conversion of potential energy into enthalpy6.000m ÷ 1.005 kJ/°C and the theoretical dry bulb temperature increase is 9.81 m/s2) The enthalpy thus increases by 9.20C per 1000m.005 kJ/kg°C = 9. the ventilation air has less ability to remove heat. as the airflow increases. The magnitude of the change in enthalpy can be estimated using the steady flow energy equation for a flow from a higher elevation (Z1) to a lower one (Z2). The temperature rise due to autocompression is independent of the airflow rate.As air travels down the intake airways form the surface. water should be collected in drains and kept off declines). As cemented backfill cures in the stopes. All of the other fill types are non-draining and. to the mine environment. Machine Heat Except in cases of hoisting. oxidation of exposed minerals can also be a significant source of heat. 33% of the fuel energy value is converted to flywheel power (almost all of which eventually converts to heat anyway).e. The ground water temperature is almost always the same temperature as the virgin rock temperature. For example. the heat flow from the surrounding rock to the ventilation air is proportional to the difference between the virgin rock temperature and the air temperature. depending upon the ventilation rate and the rock surface exposure. a fan consuming 180kW of electrical energy does no useful work in a thermodynamic sense and hence all of the 180 kW of electrical energy is converted to heat. the other 66% is converted directly to heat). For dry airways. In some mines. 20 – 30m below surface. heat is produced due to the exothermic reaction of the cement and water. At full power.g. except for the flushing water used with Paste Fill. it is converted into heat). however typical gradients in Australia range from 1 to 3 °C per 100m of vertical depth. In hotter mines heat may flow from the rock to the fill until equilibrium is reached. Most of this heat will be absorbed into the surrounding rock and slowly released and generally this would be insignificant on a mine wide basis. It is now more widely accepted that this heat is transferred to the broken rock and liberated over a much longer period of time and is variable. However. The geothermal gradient varies depending on many factors. In underground mines. they are about 33% efficient (i. where temperatures are largely unaffected by surface climatic variations) is close to the average annual ambient dry-bulb temperature. Ground Water Ground water flowing from the rock into an airway acts to transfer heat from the rock to the air. secondary ventilation fans are also a major source of heat. should have minimal impact. a diesel truck operating on a level gradient and producing 200 kW of engine power would emit about 600 kW of heat. it may be significant locally during the first few days after placement. The radiant heat from the fill in this case would Page 15 © AMC Consultants Pty Ltd 2005 . For many years it was thought that this heat was dissipated directly to the ventilation system and removed during the re-entry period. For example. hauling or pumping (where potential energy is raised). The surface rock temperature (i. This is sometimes known as the thermal flywheel effect. Diesel engines are thermally inefficient and generate significant heat loads. The amount of heat transfer can be limited by use of efficient pumping and drainage practices (e. the remaining 95% is released as heat. The rock surrounding an airway has the ability to absorb and subsequently release thermal energy. Cement Fill Only Hydraulic Fill would add significant quantities of water and therefore heat. If the paste is placed at a temperature of 30ºC and rises by 10ºC then this will raise the temperature of the surrounding rock to 40ºC. depending on the difference between the rock temperature and the air temperature.e. almost all of the output power of underground machines is used to overcome friction (i. The rate of heat flow from the rock to the air increases when the airway is wet. Explosives Only 5% of the energy produced by blasting is used to break the rock.e.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY The rate of temperature increase with depth is known as the geothermal gradient. which is based on heat load calculations performed for the North Broken Hill mine.1 Air Temperature Temperature should not be confused with heat.bulb temperature is the actual air temperature. the higher the humidity If required. For example a bath full of water at 30° contains more heat than a cup of water at 70°. or wet and dry bulb thermometer. The frame is attached to a handle via a spindle and is free to rotate. In mining. the Page 16 © AMC Consultants Pty Ltd 2005 . Dry. An appreciation of the proportion of the total heat load contributed by the various heat sources can be gained from the example opposite. the dry-bulb and the wet-bulb. expressed as a percentage. where high surface temperatures and humidity can give rise to heat problems. In the worst case some of the ‘excess’ heat would be released to the ventilating airflow and rejected to the exhaust ventilating system. Temperature is a state and is measured. There are two measurements of air temperature are important to ventilation practitioners. and the cooling process slows. to monitor potential heat stress conditions. As humidity increases. 2. Together they measure relative humidity. the most widely used instrument to determine wet and dry bulb air temperature is the whirling hygrometer (sling psychrometer). even in relatively shallow mines. The ability to measure both the wet and dry bulb air temperature is essential. The thermometers are graduated from -5 C to +50 C. The smaller the difference between the two temperatures. The bulb of one thermometer is surrounded by a cotton wick that is kept moist by a small supply of distilled water in a reservoir. When the air is humid. The difference being the thermal capacity which is the ability to raise the temperature of 1kg by 1°C.3. When the air is dry. Humidity is the ratio. very little moisture evaporates from the wet cloth. At the time the calculations were performed. It consists of two identical thermometers (usually the mercury type) mounted side by side in a rigid plastic frame. the moisture in the wet cloth will evaporate faster and the temperature will cool. Heat is a form of energy and is calculated. This is known as the wet-bulb. of the water vapour present in the atmosphere to the amount required to saturate the air at the same temperature. particularly in hot or poorly ventilated mines. the mine was operating at a depth of about 1. the cooling from evaporation of sweat decreases. measured with a standard thermometer and the wet-bulb temperature is the measure of the evaporative capacity of the air.600m below the surface. These two properties are also required to accurately determine the air density. The dry bulb thermometer provides the sensible temperature of the air. The wet bulb thermometer provides a measure of the evaporative rate of the air. This is particularly the case in northern Australia.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY almost be imperceptible. It should also be noted that surface ambient conditions can also be an important contributor to underground heat conditions. respiratory heat exchange accounts for about 5% of metabolic energy production. In fact.e. the human body is a biological engine of with low mechanical efficiency. In particular. 2. This heat loss is generally considered to be small enough to be ignored. That part of the metabolic process not used to provide the mechanical work (i. it also varies with: Condition of the individual’s health. and Change in mass (body growth) The latter is negligible (usually!) and can be ignored. This heat is transferred to the external environment and.3. otherwise the body’s core temperatures will increase.2 Body Heat Balance Food (fuel) is oxidised in the metabolic process and converted to energy. Page 17 © AMC Consultants Pty Ltd 2005 .BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY relative humidity can be determined by equating these two temperatures using a table or slide rule supplied with the instrument. Physical fitness. if none of the metabolic heat could be rejected. Although metabolic heat production depends primarily on muscular activity (i. the body temperature would rise by 1°C (the maximum ISO recommended acceptable rise) in 12 minutes during moderate exercise and 4 minutes during strenuous exercise. it is related to the rate of work). possibly to life threatening levels. in the forms of: Metabolic heat Mechanical work. they do not compete with the simplicity and reliability of the sling psychrometer. however. if the rate of generation is greater than the rate of transfer the body temperature will rise. Heat transfer between the body and the environment occurs via: Respiration (breathing) Radiation Conduction Convection. Equivalent electronic instruments are available. very expensive units are used.e. and Evaporation Respiratory Heat Exchange. Less than 20% (usually much less than 20%) of the available energy is converted into usable mechanical energy. The removal of heat generated by the human body is reliant upon our ability to sweat and the rate at which it can be evaporated. In a typical hot underground environment. and Emotional state In essence. This heat storage is called the “metabolic heat generation” or the “metabolic heat production rate”. As we work we release energy in the form of heat and understandably the harder we work the higher is the metabolic heat generation process. the humidity sensors on electronic instruments seem to cause trouble unless very good quality. >80%) will always appear in the body as heat. This metabolic heat must be rejected from the body to the environment. humidity. As the air is replaced with cooler. it becomes necessary to also lower the wet bulb air temperature (e. These include: Cold – Skin blood flow is reduced to reduce heat losses to environment. acclimatisation (training the body to sweat efficiently) and on the body having sufficient fluid. for example personnel are wearing cooling jackets). it rises. taking the heat away from the skin. The effectiveness of this form of heat transfer is dependent upon: efficiency and rate of sweating and. Convective Heat Exchange Convection occurs when a layer of cool air comes in contact with warm skin. more dense air.3. To do this. the body invokes its thermoregulation processes. conductive heat transfer to or from the human body is usually negligible (unless. It depends on the temperature difference between the skin and the dry bulb temperature of the air. There is considerable variation in the sweat rate of individuals and this is partly associated with the degree of acclimatisation (it also depends on general health and genetic factors). and type of clothing). Sweating increases to maximise evaporative heat loss. the process of heat exchange continues. Sweat begins to drip when the skin surface is approximately 50% wet.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Radiant Heat Exchange The magnitude and direction of radiant heat transfer depends on the temperature difference between the human body (skin) and the object. the evaporative capacity of the environment (depends mainly on air temperature. Heat –Skin blood flow is increased to increase heat transfer rate.3 Thermoregulation The core of the body must be maintained at a stable temperature of between about 35OC and 40OC. In some instances. In normal mining activities. This type of heat transfer is usually only significant in mines with hot rock temperatures. the most effective place for sweat to evaporate is from the skin. Shivering commences to raise the metabolic rate. air velocity. contributing about two thirds of total cooling. Evaporative Heat Exchange Evaporation is the main cooling mechanism for the body. The air increases in temperature and its density decreases. Conductive Heat Exchange Conductive heat transfer occurs when two bodies come into contact. Evaporative cooling relies on the latent heat of vaporisation of sweat from the body. by reducing moisture pick-up in intake airways or through the use of refrigerative mine air cooling). This is primarily because some areas of the human body produce more sweat than others. as well as the relative air velocity and body surface area.g. and in the vicinity of hot diesel equipment. serves no cooling function and it begins to drip from the skin surface well before the body is fully wetted. Sweat that drips from the body. In terms of maximising the cooling effect. the evaporative capacity of the environment can be increased primarily by increasing the air velocity. The ability of the body to sweat depends on physical fitness. 2. Clothing (particularly clothing made of artificial fibres) can significantly reduce the amount of heat rejected from the body via evaporative heat exchange (it also reduces convective heat exchange). Convective heat transfer to the surrounding air is typically 15% to 20% of total cooling. In underground mines. Page 18 © AMC Consultants Pty Ltd 2005 . As the air becomes lighter. Some personnel are heat intolerant and can never be successfully acclimatised to hot working conditions. reducing the body’s ability to reject heat to the environment. Most of the effects of acclimatisation are generally developed within a week of working in hot conditions. Significant fluid intake is required to counter losses through sweating in hot conditions. Obtained from Chapter 20 of “Environmental Engineering in South African mines”. Hydration Levels are critical. even across a relatively narrow sample group (in this case. Hydration levels can also be compromised by diuretics (alcohol. Even a small decrease in hydration levels will lead to a substantial reduction in the ability to work effectively in heat. including: Fitness Age Obesity results in excessive fat insulating the body. acclimatisation is lost after a period of 7 to 14 days away from hot conditions. 99 acclimatised. Conversely.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY The effectiveness of the body’s thermoregulation system is dependent on a large number of factors. The degree of acclimatisation is related to the level of heat stress experienced on the job. reducing heat loss Acclimatisation is the adaptation of the body’s thermoregulatory systems to working in hot conditions. essentially nude men working at the same rate in the same environment). caffeine etc) and also by illness. published by the Mine Ventilation Society of South Africa in 1989. Page 19 © AMC Consultants Pty Ltd 2005 . The illustration below shows the Temperature Response to Heat Stress there is a tremendous spread in the effectiveness of the body’s thermoregulation system. Clothing acts as insulation. but the process continues for at least 14 days. High body temperatures associated with heat stroke can result in irreversible damage to organs (especially the brain. Its development is usually attributed to the inability of the circulation system to meet the demands of thermoregulation (i. Don't massage affected limbs. The symptoms and treatments for some of the many classifications of heat illnesses are listed below (in order of increasing severity): Heat Cramps result from an imbalance in the body electrolytes. Give sips of water to drink (after nausea has passed). after nausea has passed). Sweating Cramping pains (in the limbs and/or abdomen). the diversion of significant quantities of blood flow to the skin) whilst also maintaining sufficient blood flow to the vital organs (brain and skeletal muscle). dehydration and high temperatures. This fluid debit causes muscles to lose their vital electrolyte balance (complex salts). caused by vigorous activity. Discourage any further exercise.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY 2. unconsciousness (coma) and death. The body loses more fluids than it is replacing. Over-exposure to heat may quickly progress to collapse. Signs and Symptoms Pale. Mining Industry heat stroke in countries such as South Africa. kidneys and liver) and the nervous system. The main causes of heat stroke in the mining industry7 are overly strenuous work in hot environments and dehydration (often associated with excessive alcohol consumption). 7 Page 20 © AMC Consultants Pty Ltd 2005 . If appropriate treatment is not instigated promptly.4 Heat Related Illness It is important to be able to recognise the causes and symptoms of overexposure to heat and to know the treatment for these illnesses. Over-exposure to heat occurs when the body’s temperature controlling mechanism (thermoregulation) cannot cope with the thermal environment and rate of exertion. Treatment Rest the victim in a cool location. Heat Exhaustion occurs after prolonged moderate elevations of core temperature. clammy skin. clammy skin. Restlessness Cramps in the limbs and/or abdomen Nausea and/or vomiting Headache Weakness Fatigue Treatment Rest the victim in a cool location Discourage any further exertion. (use tepid water) Give cool water to drink (cautiously. Signs and Symptoms Pale.3. Cool down casualty by sponging. Spasms (in the affected limb or limbs). Note that it is unlikely that there has ever been an underground mining fatality directly attributed to heat stroke in Australia. Nausea. It occurs as a result of thermoregulatory failure. heat stroke carries a mortality rate of up to 80%. Heat Stroke is a very serious condition known as a Core Temperature Emergency. thus causing muscular contraction (cramps).e. Prepare to resuscitate if required.3. During the 1900’s over 90 heat stress indices have been developed and used around the world with varying success and acceptance by the international community. standing etc) Variability in human thermoregulatory response. it does not indicate a reason for the problem and hence any possible solution.3. whether sitting. Give frequent small drinks of water if patient is conscious. heart rate.5 Heat Stress Indices Measurement of hot conditions can either be by measuring the climate. Parameters Contributing to Heat Stress Metabolic rate Ambient and radiant temperature Water vapour pressure Air velocity Barometric pressure Amount and type of clothing Skin surface area and “view factor” (e. The four main parameters for directly evaluating heat strain are body core temperature.1 Single Measurements Although there has been some attempt to use a single measurement to determine heat stress conditions. Generally these indices combine one or two parameters into a single number and therefore only partially represent the complexity of the human thermoregulatory system and the climatic conditions encountered. If possible. the effect on persons working there. Development of a measure to determine safe levels for work in hot places has been debated over many years. Dizziness or Faintness Vomiting Collapse and seizures Coma Treatment Cool down the casualty immediately by gently splashing with cool (but not icy) water. weight loss through sweating.5°C Often a cessation of sweating. Even if heat strain could be measured accurately. 2.5. and Rational indices 2. that is the cooling power of the environment or by measuring the heat strain. The “degree” of heat stress is a function of the parameters outlined in the table below. there is no single parameter that provides a reliable indicator of physiological reaction.g.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Signs and Symptoms Body core temperature above 40. Broadly heat stress indices can be classified into three types: Single measurements Empirical methods. Aggressive or irrational behaviour Staggering. increase evaporative cooling by fanning patient. Page 21 © AMC Consultants Pty Ltd 2005 . Continue treatment until medical help arrives. Although all of these can be measured it is not practical to do so in the workplace. skin temperature and. 2 Empirical Methods The most commonly used empirical methods have been.5 m/s to 3.5. that in wet-bulb temperatures above 37°C.3. and wet-bulb globe temperatures index (WBGT). It is not possible to reduce these nomograms to a simple mathematical expression over the entire range. It worthy to note.5 m/s Page 22 © AMC Consultants Pty Ltd 2005 . 27°C or 28°C as a trigger point for modified work conditions such as reduced work hours or the introduction of regular rest periods.5 m/s) air velocities.1 Psychometric Wet-bulb Temperature For many years. it is normal to refer to empirically constructed nomograms such as :1.2 Dry-bulb Temperature Dry-bulb temperature above 45°C can give a burning sensation to exposed skin and is generally accepted as the upper limit for work being allowed to continue.5. Basic scale developed for essentially nude men and. and The velocity of air is within the range from 0. 2. Kata thermometer.3. Australian mining legislation uses a wet-bulb temperature of 25°C. The ET of an environment is the temperature of a saturated environment without movement of air that would produce the same instantaneous thermal sensation as the environment being considered. predicted four-hourly sweat rate.1.1. 2.1 Effective Temperature (ET) ET was developed in 1923 as a measure of comfort by the American Society of Heating and Ventilating Engineers and primarily for use in offices.2. The psychometric wet-bulb temperature is a measure of the evaporative cooling power of the environment and is therefore of limited value especially in high air velocities and high radiant temperatures.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY 2. the environment is unable to support human life for any extended period of time. The Basic ET may be calculated to within 0.2OC from the following equation given:The difference between the wet-bulb and dry-bulb temperature is less than 5OC The wet bulb temperature is within the range from 25OC to 35OC. effective temperature (ET).5. the wet-bulb temperature has generally been considered as the easiest and simplest measure of heat stress and has been used widely in many Australian mines as the sole indicator for climatic acceptability. As this index is based on subjective thermal sensation it has shortcomings in either low (<0.5m/s) or high (>3. Although the value can be calculated. Normal scale for lightly dressed men. 32°C is usually set as the upper limit for work being allowed to continue. 2.5.3. 2.3. The assumption is to take into account the effects of thermal radiation.5 m/s.7 (1) (a) provides that no person shall be employed where the effective temperature in the workplace is or exceeds 29.5.0.25 [ ( TA .1. greater than 3. ET has been extensively used in the European and British mining industries. ET is least accurate in velocities less than 0.TWB ) + 141.5 m/s and.2°C.1.15e-2V TA = Ambient dry-bulb temperature (°C) TWB = (°C) Ambient wet-bulb temperature V = Velocity of air (m/s) e = vapour pressure of the air (kPa) Subsequent to the development of these nomograms.35 ) ( TA .0354TWB . 3.35 ) ( TA .2 Page 23 © AMC Consultants Pty Ltd 2005 .27 + 1.86 + 0.33 ( TWB – 20 ) ] / [ ( X3 .TWB ) + 141.133V + 0.3V – 1.4129 Where X1 = [ 8. Kata Thermometer 2. Measurements using the blackened sphere are termed corrected effective temperature.4°C and Part 2.07V2 + (4.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY ET = 20. In Queensland the Coal Mining Act – General Rules for Underground Coal Mines Part 2.1. The use of ET as a tool for prevention of heat related illness has a number of problems 1. 4.6 X2 = 4. 2.2.X1 + X2 ) / 0. it has become customary to use the temperature of a blackened 150 mm hollow copper sphere in place of the dry bulb temperature.7 (3) specifies a shortened shift strategy when the ET exceeds 27.TWB ) X3 +8.3.33 { 17X3 – ( X3 .6 X3 = 5.12 . ET exaggerates the effects of thermal sensations at high relative humidity Only accounts to climatic conditions and does not consider work rates ET scales are most accurate in warm climates and low heats stress conditions.35 ) ( TWB 20 ) } ] / [ ( X3 . if the air cooling power is less than 115 W/m2.725 modified DuBois formula.5 m /s 1m /s 5 /s 5 m/s 4m /s m m /s 3 2 /s m Air Cooling power (M scale) or Metabolic Heat W/m2 0 m/s 300 5 m/s 3 m/s 2 m/s 1 m/s 0. then there will be less than a one in one million chance of the healthy. The 2 0.8 m . By definition. kg) and height (h. 5m/s Air Velocity & Light Clothing) 2 18 20 22 24 26 28 30 32 34 36 Wet Bulb Temperature t w C Radiant Temperature = Dry Bulb Temperature Dry Bulb Temperature = Wet Bulb Temperature + 5°C (Note that the graph may be used without undue error for differences between wet bulb and dry bulb temperatures of between 2 and 8 °C) Figure From “The Generalisation of Air Cooling Power” by M. The calculations require inputs including. amount and type 8 0. This index was however specific to South African mining practices (in particular.5 m/s 0 m/s 200 5 m/s 3 m/s 1 m/s 0 m/s 100 Unclothed Light Clothing (Thin Trousers. it requires fairly complex calculations (ideally requiring a computer) to solve. provided the air cooling power is equal to. There have been a number of updates and modifications to the original scales and it is important to state which air cooling power scale is being used.6 Air Cooling Power A complete and supportable heat stress index must account for all of the contributing parameters. the average skin surface area of a 1. Short Sleeved Shirt) Heavy Clothing (Long Sleeved Overalls and Long Sleeved Shirt) 115 W/m Line (Light Work. m ) to body mass (m. Johannesburg. A widely used thermal acceptance criterion is a minimum air cooling power of 115 W/m2 (i. 9 2 Page 24 © AMC Consultants Pty Ltd 2005 . 60. Currently. McPherson Fifth International Mine Ventilation Congress The Mine Ventilation Society of South Africa. referred to as the “M” (McPherson’s) Scale Air Cooling Power. McPherson (1992)8 describes how to calculate air-cooling power. acclimatised and “self pacing” individual developing dangerous body core temperatures (>40°C). “The Generalisation of Air Cooling Power” M.e.217m h (From “The Mine Ventilation Practicioner’s Data Book” Second Edition.425 0. 1.J. The scale used to determine the rate of generation of heat by the human body and also air-cooling power is 400 W/m2 of body (skin) surface area9. Fifth International Mine Ventilation Congress The Mine Ventilation Society of South Africa. Whilst air-cooling power is the most complete heat stress index. al. the most complete and supportable index of heat stress is the concept of air-cooling power. For reference.5 kg South African miner has been determined to be 1.7m tall. Johannesburg. This is held to be an “acceptable” risk. potentially leading to heat stroke. or greater than the metabolic rate. relating skin surface area (As. Johannesburg. 1992.J. 1992. Andrew Patterson et. McPherson.3.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY 2. which was developed by the South African Chamber of Mines. then an individual could not even sustain a “moderate” work rate without incurring an unacceptable (greater than one in one million) chance of a healthy acclimatised individual suffering from heat stroke. The concept of air-cooling power relies on the quantification of the ambient environment’s ability to remove metabolic heat from the human body. m) is As = 0. it assumed personnel were essentially nude and fully wetted by perspiration). 1999 The Mine Ventilation Society of South Africa. The protective clothing worn underground in Australian operations would fall somewhere between the “Light” and “Heavy” categories.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY of clothing worn. In other words. barometric pressure and the work rate of the individual. wet bulb temperature.) The majority of underground temperatures except near diesel radiators etc will fall within this range. air velocity (air speed over the individual). For mines which do not have access to the heat stress meter. at the conditions and work rate outlined. Dry-bulb temperature is equal to the wet-bulb temperature + 5°C (Note that the graph may be used without undue error for differences between wet bulb and dry bulb temperatures of between 2 and 8°C. Page 25 © AMC Consultants Pty Ltd 2005 . it should be noted that normal ranges of some of the factors mentioned above in the underground mining context have a relatively weak effect on air cooling power.5°C will ensure that there is less than a one in one million chance of heat stroke occurring in a healthy. which only considers wet-bulb temperature. Air cooling power is largely unaffected by normal range of pressures found within underground mines. The large number of required inputs and requirement for a computer to calculate air-cooling power has limited its use to date as a practical tool for determining on the spot whether the thermal conditions in an underground environment are “acceptable”. Recently this problem has to a large extent been overcome with the development of a robust. Radiant temperature of surroundings is equal to the dry-bulb temperature (This is usually the case. dry bulb temperature. Clothing . an acceptable air cooling power can not be provided for even a “light” work rate at wet bulb temperatures above 32 °C.Assumptions were also made about the thermal resistance and area factor of different clothing specifications and also regarding the body posture factor. It assumes “light” clothing. The above assumptions allow an air-cooling power graph to be produced. An example has been outlined with the heavy dashed line in the “M” scale chart. It can however be concluded that based on all the assumptions implied in McPhersons ‘M’ Scale. “light” work rate (115 W/m2) and air velocity of 0. a wet bulb temperature of less than 29. there will be variation in many of the variables listed earlier . radiant temperature of surroundings. In any mining operation.5°C.5 km/h Building brick walls Scaling Hand-held drilling 2 Very Hard Work >240 W/m2 Shovelling Timbering Barometric pressure – Assume P = 100 kPa. This line projects down to a wet-bulb temperature of 29. acclimatised individual. except near hot surfaces such as diesel radiators etc). A generalised Air Cooling Power Chart that assists in the rapid manual assessment of the acceptability of the thermal environment can be produced on this basis. The meter uses algorithms based on air-cooling power and is based on an instrument that was originally developed for use by the US military in “Operation Desert Storm” in Kuwait. portable heat stress meter designed for use underground. (See McPherson’s “M” Scale Air Cooling Power Chart opposite) The following assumptions were made in order to produce such a chart: Typical Metabolic Work-rate Classifications for Healthy Adults Light Work < 115 W/m Sleeping 40 Seated 60 Standing 70 2 Moderate Work 115 to 180 W/m Walking 5 km/h Trades people Jumbo drilling Diesel Operator 2 Hard Work 180 to 240 W/m Walking 6.5 m/s. and clothing type. air velocity. g. conditions which could lead to the development of heat stroke could occur at wet bulb temperatures below 32°C. The protocols should spell out the policy regarding those who fail the hydration test (second chance etc). those who are ill or those who are heat intolerant). 2. This temperature cut-off is combined with a requirement that the air velocity must be greater than 0. a “stop work” cut-off of 32°C wet bulb is supported.g. again referring to McPhersons ‘M’ Scale. Some mines preclude those with certain medical conditions.g. Another example is the use of cooling jackets (ice vests). how to recognise and treat the symptoms of heat illness. the importance of drinking sufficient water. The criterion must be fully supported by management and strict guidelines established to ensure that the criterion is respected under all but exceptional circumstances (and these should be defined in the protocol). those not drinking sufficient fluid. once the wet bulb temperature exceeds about 32°C. a “diminishing return” effect is apparent. refer to W. heavier work rates). it is necessary to boost the miners’ ability to reject metabolic heat by employing one or more of the following methods: Increase the air velocity to improve the air-cooling power. “Refresher” training courses should be re-run on a regular basis (ideally just before the onset of summer) Hydration testing – e. the need to “self-pace” according to conditions and the mechanism of acclimatisation. it is very difficult to maintain ambient conditions that allow even a light rate of work without incurring an unacceptable risk of the development of heat stroke. This is effective at lower wet bulb temperatures.A.5 m/s at wet bulb temperatures over 25°C (e. those who are overweight.7 Management of Hot Working Conditions Human heat stress is a health hazard that can be managed by: Instigating “working in heat” protocols Controlling the underground ambient heat conditions Hot working condition protocols can include the following aspects: Worker training and education – e. It is very important that a cut-off criterion with respect to acceptable/ unacceptable underground ambient conditions is established. it can be seen that increasing the air velocity has very limited effect on the air cooling power. They are primarily intended for use in emergency Page 26 © AMC Consultants Pty Ltd 2005 . Staff selection. In these mines. In a number of deeper mines (or shallower mines hosted in hot rock). The tests quickly show those who are not coping with hot working conditions (e. however it only deals with part of the problem. It should also be noted that there is a considerable cost penalty associated with increasing the airflow rate: Power Cost Increase New Flow Rate Old Flow Rate 3 Microclimate Cooling. One example is the use of air-conditioned cabins on mobile equipment. This involves cooling the localised area around the miner. As the wet-bulb temperature increases. For the purposes of providing a simple. personnel over a specified age and females with “child bearing capacity” from working in thermal conditions which are beyond a specified level.g. practical measurement to determine the thermal “acceptability” of an underground environment.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY It is also important to note that for a range of circumstances (e.3. Regulations). which special pockets in an insulated vest. These use flexible frozen gel-packs (similar to those used for sports injuries). “Stop work”. Urine tests on personnel who work in “hot” areas of the mine. In fact.g. Establishing working in heat protocols is of fundamental importance. For example.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY situations (and for sports competitors). Make-up water requirements for a 1 MW plant are typically 1. a 1MW plant circulates about 25 l/s in each of the (hot and cold) water circuits. A simplified line diagram showing a “typical” mine refrigeration circuit is shown below. Refrigerative Mine Air-cooling In spite of the sometimes considerable capital and operating costs. A proportion of this flow evaporates and some is also dumped. This system is simple and easy to maintain. The amount of (potable) water circulated in the plants can be considerable. The air is cooled at the intake raise collar. large underground pump stations and Pelton wheels. refrigerative cooling of mine air is often the only supportable option for control of heat stress in very hot mines. Surface Plant with Underground Coolers. Chilled water is reticulated underground to cooling towers that are close to the locations where cooling is required. but may potentially have some applications for more regular underground use. With this system. forgetting to change the cooling jacket gel-packs and subsequently getting “stuck” in a hot mining area). The figure opposite is an illustration of a Micro-climate cooling vest. The gel packs are cooled in a chest freezer (in the crib room) and have a useful life of about 2 hours. the plant and heat rejection towers are mounted on the surface. (Reference http://www. As a rule of thumb.steelevest. batch cooling of water. Advantages of this system are that cooling can be more precisely and more directly delivered to the required locations. Some of the “coolth” is also inevitably lost in the mine intake airways. Page 27 © AMC Consultants Pty Ltd 2005 . It is not well suited to mines with complex ventilation systems (some of the cooled air may find its way to locations where chilled is not required). The refrigerant is usually ammonia for surface plants and R134 for underground plants. This is seldom a satisfactory “total” solution. The disadvantages are high pumping costs (high volume. The refrigeration machine generally consists of a screw compressor coupled to plate type heat exchangers (condenser and evaporator).com/).g. underground cooling towers which can be fouled with dust etc). the compressor motor power draw is 1/4 to 1/5th the nominal refrigerative cooling capacity. All of the equipment is located on the surface. high head pumping although some energy losses can be recovered with the use of a Pelton wheel turbine coupled to a generator) and significant maintenance costs (complex system with cold and hot water storage dams insulated chilled water pipes. Rated capacity of machines used in Australian Mines ranges from about 500 kW to 10 MW of refrigerative cooling capacity. Several plant configurations are possible: Hot Air Reject ed t o At mosphere Cooling T ower Hot W er Circuit at Refrigerat ion Machine Condenser Evaporat or Cooled Air T Mine o Chilled W er Circuit at Cooling T ower Surface Bulk Air Cooling. since there is a very real chance of something going wrong (e.5 l/s in the hot water circuit and 1 l/s on the cold-water circuit. The capacity of refrigeration machine is restricted to a size which can be physically transported underground on a skid (e. There are many disadvantages including high maintenance costs due to arduous operating environment and difficult maintenance access as well as logistics problems (e. As a result. the machine generally only has sufficient capacity to cool one or two headings. The cooling tower supplies chilled air to a specific location (often to the inlet of a secondary ventilation fan).5 l/s of potable make-up water) Some examples of Australian mine air cooling plants are shown in the following illustrations: 600kW Refrigeration Set for Underground Spot Cooler (WMC Olympic Dam) Cooling and Heat Rejection Towers Not Shown Page 28 © AMC Consultants Pty Ltd 2005 .g.g. All of the equipment is located underground. supply of 1. maximum of about 1MW cooling capacity).5 to 2.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Underground Spot Cooling. The refrigeration plant and heat rejection tower are located in a return airway. 1 MW NH3 Surface Plant at Telfer (1 of 2) (Plant is being gassed up with NH3) Heat rejection tower Telfer Bulk Air Cooler Installation Near Collar of VR2 Intake Raise Page 29 © AMC Consultants Pty Ltd 2005 .BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY 1. BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY 10 MW K61 NH3 Refrigeration Plant – Mt Isa Cold water storage dam Heat rejection towers Chilled water is reticulated U/G via insulated pipes to underground cooling towers Close up of one of the Mt Isa K61 Compressors Page 30 © AMC Consultants Pty Ltd 2005 . Any additional gasses or variation in the proportions of the gases normally found in the atmosphere are regarded as contaminants.0 3.4. severe headache.03 0.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY 2. It is also produced by diesel engines. irritant. leading to fatigue.11 0.93 Variable Because this air is a mechanical mixture. Physiological Effect of Carbon Dioxide Percentage in Air 0. Any other substance or variation of these gases contained in the atmosphere are contaminants and are subject to Exposure Standards under legislation.4. The most noticeable effect of the gas is to cause the respiration rate to increase. Some of these gasses may be poisonous. abandoned workings and caves. 2.000 ppm and a STEL of 30.53 (significantly heavier than air) and will not support combustion. CO2 has a TWA exposure limit of 5. rapid exhaustion and collapse Page 31 © AMC Consultants Pty Ltd 2005 . such as limestone. Composition of Air GAS Oxygen (O2) Nitrogen (N2) Carbon Dioxide (CO2) Minor Inert Gases Water Vapour VOLUME (%) 20. 2. It can be found in coal mines and in mines hosted in carbonaceous rocks.0 5 – 10 10 – 15 Effects None (Normal atmospheric concentration) Respiration increases by 5% Respiration increases by 50% Respiration increases by 200%. It has a specific gravity relative to air of 1.03 0. asphyxiant. The gas is about 20 times more soluble than Oxygen and diffuses rapidly into the bloodstream. It doesn’t liquefy but will form dry ice at –78°C.5 2. Violent panting. it is possible to separate and identify each of the gases in the mixture. which serves to alert the miner to the presence of the gas.93 78.4 Mine Gases There are a surprisingly wide variety of gasses that can be found in underground mines.2 Carbon Dioxide (CO2) Carbon dioxide is colourless.1 Constituent Gases of the Atmosphere The atmosphere (fresh air) surrounding the earth surface contains a number of different gases combined as a mixture. Mine ventilation systems are required to dilute and remove atmospheric contaminants caused by mining operations. Headache Intolerable panting. has a pungent or acrid smell and a “soda water” taste. Some characteristics of the more commonly found mine gases are discussed below.000 ppm. radioactive or explosive and are hence of particular interest from a ventilation design viewpoint. CO Hb) is significantly more stable than that formed by a combination of Oxygen and Haemoglobin (Oxyhaemoglobin) and does not readily decompose. CO has a TWA exposure limit of 50 ppm and an STEL of 400 ppm. Fainting.g. probable death. blasting etc). Nausea and headache develop slowly and may become very severe. more and more CO is taken up by the blood. with a specific gravity relative to air of 1. Oxygen is the only gas whose concentration should be maintained above a recommended value. Page 32 © AMC Consultants Pty Ltd 2005 . Exertion leads unconsciousness to 10. unconsciousness. therefore reducing the concentration of O2. diesel engines.0 Typical Physiological Effects (Vary with individuals and period of exposure) Normal content of atmospheric air Lowest allowable concentration (variable in mine legislation) Noticablely faster and deeper breathing rate (equivalent to 1. with each breath. May lose consciousness if exposure prolonged.1. Dizziness. Concentration (by Vol.97 (almost exactly the same as air). This automatic adjustment by the body to oxygen deficiency ends at about 17% oxygen and mental processes begin to become impaired although of course humans are not aware that they are being affected.4.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY 2. making escape difficult. buzzing in ears. it is an extremely dangerous gas. rapid heart beat Work is difficult.0 15. Depletion of Oxygen also results from combustion (e.0 6.3 Oxygen (O2) Oxygen is a colourless. Breathing becomes rapid and lips become blue.0 17.)in Air % 20. Dangerous for exposures over half to one hour. the rate of breathing tends to increase to maintain the oxygen intake required. odourless and tasteless. The compound in red blood cells which transports Oxygen (haemoglobin) has an affinity for CO which is about 300 times greater that that for O2.0 9. To further exacerbate the problem. Rapid unconsciousness and death A safety lamp flame will go out at some point in this range. Oxygen depletion is caused by oxidation of minerals (e. tasteless gas.0 7.0 < 6. the resulting compound (Carboxyhaemoglobin .0 13.500m ASL elevation). The physiological effect of various levels of Oxygen concentrations is shown below. 2.g.0 to 20. In severe poisoning. Carbon Monoxide has a specific gravity relative to air of 0.0 Note: If the oxygen content falls. Candle will not burn below 16%.93 17. A deficiency of Oxygen implies greater than normal atmospheric concentrations of other gasses (even inert gasses). Liable to faint and become unconscious.5 and 74% in air. Life endangered Convulsive movement. The effect is cumulative ie. Because of this and the fact that it is colourless. The result of Carbon Monoxide exposure is that the red blood cells have a reduced ability to transport Oxygen. the effect may be very sudden and the first warning may be lack of response of the limbs.4 Carbon Monoxide (CO) Carbon Monoxide has a high toxicity. Sulphides and Coal).4. It is flammable at concentrations of between 12. odourless. weakness. Oxides of Nitrogen are primarily produced by internal combustion engines and are also a significant constituent of blast fumes. 2. disturbed judgement Slow weak pulse. In sufficient concentration. tightness of the chest or perhaps pain in chest and a cough). the oxidation processes (e. blasting) and sometimes issues from rock strata (especially in coal mines). As yet an STEL for NO has not been set. Dangerous if exposed for ½ to 1 hour. but for NO2 the STEL is 5 ppm. The proportion of NO is usually small and NO also readily converts to NO2 in the presence of air and water vapour.g.4. dimming of vision Possible collapse Collapse Collapse at rest. increased lung ventilation and pulse. dizziness Severe headache. respiratory failure and death. loss of judgement. this may be delayed for several hours. The most important of these are Nitric Oxide (NO) and Nitrogen dioxide (NO2). Physiological Effects of NO2 Concentration ppm 3 50 100 200 250 TWA Moderately irritating to eyes and nose Irritant to respiratory passages and to the eyes. probably fatal. coma. nausea. This can occur up to 24 hours after exposure. convulsions Convulsions. depressed lung ventilation and pulse. This gas is brown in colour and dissolves readily in water to form Nitrous (HNO2) and Nitric (HNO3) acids. Severe pulmonary oedema. even after an apparently early recovery. Effect Carbon monoxide is produced by fires. NO2 is the oxide of most interest. The associated bleeding and accumulation of fluid in the lungs can culminate in death from pulmonary oedema (flooding of the lungs). (Headache. Consequently. these acids cause irritation and corrosion of the respiratory system and eyes. It is also a component of combustion engine exhaust emissions. The TWA exposure limit for NO is 25 ppm and that for NO2 is 3 ppm.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Effects of Carbon Monoxide in the Blood Stream Blood Saturation (% CO Hb) 0-10 10-20 20-30 30-40 40-50 50-60 60-70 >70 None Possible headache Headache. Breathed for 20 minutes may cause collapse.5 Oxides of Nitrogen (NOx) Oxides of Nitrogen covers a mixture of gases usually found together. both of which are classified as toxic. Typical Physiological Effects for NO2 Page 33 © AMC Consultants Pty Ltd 2005 . meaning that the sense of smell cannot thereafter be relied upon.000 Detectable by smell Irritation to eyes and respiratory tract. It is sometimes also noticed in mines that have their intake airways close to smelter stacks. palpitation. The gas has a specific gravity relative to air of 1. H2S has a TWA of 10 ppm and a STEL of 15 ppm. Unfortunately.26 and is soluble in water. and acidic taste.7 Hydrogen Sulphide (H2S) Hydrogen Sulphide is colourless and is readily detected in small concentrations by its unpleasant rotten eggs odour. uncomfortable to breathe. Effect 2. Effects of Sulphur Dioxide Concentration (ppm) 3 100 500 Detectable by its odour. It has specific gravity relative to air of 2.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY 2. Acidic action or effects of heating on Sulphide ores produce H2S. Paralysis of respiratory system and death. making it readily detectable. It is incombustible and is also not flammable. Dangerous to life after only short exposures. Serious effects after a few minutes. coughing. It has a specific gravity relative to air of only 0. Of particular importance is the fact. and death. bronchitis and chest pain. It is associated with oxidation of reactive sulphide ores. It is highly toxic. Intense irritation of eyes and throat. with a bright blue flame producing Sulphur Dioxide (SO2).6 Sulphur Dioxide (SO2) In massive sulphide orebodies there can be spontaneous oxidation and heating resulting in sulphur dioxide being released to the ventilating air. stupor. fainting. cold sweats. It is sometimes noticed near stagnant pools of water underground. suffocating sulphurous odour.5% to 45%).8 Methane (CH4) Methane is colourless. unconsciousness.4. odourless and non-toxic. It is also formed as a result of the decomposition of organic compounds.4. continued exposure to the gas (even for relatively short periods of time) leads to paralysis of the olfactory nerves. Hydrogen Sulphide Effects Concentration (ppm) 0. Irritating to eyes and nose. Sulphur dioxide is colourless and even at relatively low concentrations has a pungent. After 30 mins serious inflammation of eyes and throat. Effect 2. Depression.4. tends to layer against the backs in areas of low air velocity (laminar flow Page 34 © AMC Consultants Pty Ltd 2005 . It is often associated with methane.55 and as a result.19 and burns in air (in concentrations ranging from 4.1 – 1 100 200 500 600 700 1. forming sulphurous acid. that sulphur dioxide is produced by sulphide dust explosions. SO2 exposure limits are a TWA of 2 ppm and an STEL of 5 ppm. Hydrogen Sulphide is sometimes associated with natural gas and oil reservoirs and can migrate through strata in solution. predominantly hydrogen. It is often noted during diamond drilling. (Distillation is the heating of a substance in an atmosphere low in oxygen.9 Coal Damps Damp is an old miners term for gaseous products formed in coal mines to distinguish them from pure air. The presence of methane in coal mines results from chemical and bacterial action on organic material.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY conditions). It is found in all coalmines. Although still in use they are not commonly used in today’s mining. Coward’s Diagram shows the relationship between methane and oxygen concentration and explosibility. many thousands of coal mining deaths directly as a result of methane explosions.g. This prevents oxidation if the heating was to take place in fresh air.4.) Page 35 © AMC Consultants Pty Ltd 2005 .1 Fire Damp A combustible gas formed by the decomposition or distillation of coal or other carbonaceous matter. Methane is also surprisingly prevalent in metalliferous mining. 2. The most dangerous situations arise in metalliferous mining where large amounts of methane accumulate (e. Methane is of course very dangerous in mines because it forms an explosive mixture with air at concentrations of between 5 and 15 % (it produces an explosion of greatest force at a concentration of 9%).9. and has been responsible for many. the stope backs after firing). Consisting mainly of Methane.4. 2. or after the explosion as a result of Carbon Monoxide poisoning (CO is a product of incomplete methane oxidation). Methane is often associated with other flammable/ explosive hydrocarbon gasses. 4. (Some times referred to as “after gasses”. Formed when water is hosed onto incandescent masses of coal when extinguishing the fire.9.9. generally caused by the oxidation of carbonaceous material or coal and A typical mixture would be 15% CO2 and 85% N2.6 White Damp The term applied to carbon monoxide or more specifically atmospheres containing lethal quantities of CO. Produced during mine fires by the distillation of coal. 2. A change in barometric pressure may cause this to be released to the ventilation system.4. barometric pressure may cause this to be released to the ventilation system.5 After Damp That mixture of gasses remaining after. that may replace the oxygen content of the air. Page 36 © AMC Consultants Pty Ltd 2005 . Sometimes simply referred to as “gas”. Basically Black Damp is an extinctive atmosphere.8 Fire Stink This is the smell indicating a spontaneous combustion.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Usually lighter than air and can accumulate in unventilated mine workings. 2. Could be any combination of CO2 and CH4 or other gasses or products of fires.9. 2. The water gas produced could produce a secondary explosion. hence its name “bottom”.4.4 Illawarra Bottom Gas Any mixture of CO2 and CH4 ranging from almost 100% CO2 to almost 100% CH4 and a little N2 that is capable of forming a flammable or explosive mixture when mixed with air. Usually heavier than air and can accumulate in unventilated mine workings.2 Black Damp An atmosphere depleted of oxygen. 2. 2.9. In it simplest form is the name given to CO2. 2. CH4. 2. hence the term “black”.9. a fire or explosion. The odour is often associated with benzene. More specifically an atmosphere containing variable mixtures of Carbon Dioxide (CO2) and nitrogen (N2). Because of its density it tends to layer at the bottom of the drive.9.9. smoke included.3 Choke Damp A change in A mine atmosphere that causes ‘choking’ or suffocation due to insufficient oxygen. 2. In some places the name given to black damp.9 Water Gas A combustible mixture of gases with a typical composition being 45% each of CO and hydrogen with smaller amounts of CO2.4. Considered poisonous because of its high concentration of CO.9.4. N2 and oxygen or after damp. It is worthy to note that when concentrations exceed 50 ppm the sense of smell may be affected and the odour becomes undetectable.4.4.4.7 Stink Damp Atmospheres containing hydrogen sulphide with the odour the predominate factor. There are two main sources of ammonia in mines: As a refrigerant gas in mine cooling plants Chemical reaction involving ANFO explosive. cement and water. Inhalation of ammonia vapours my result in pulmonary oedema (flooding of the lungs) and chemical pneumonitis. water. An isotope may have the same atomic number (number of protons in the nucleus of the atom). wheezing.9. Because of the toxic and irritant effects of ammonia. The reaction is as follows: Calcium Oxide (a component of the cement) reacts with water to produce an alkali – Calcium Hydroxide: CaO H2 O Ca(OH)2 Next.4.11 Radon (Rn) and Radon Daughters Radon is a colourless and odourless gas. A typical mixture would be 10% CO2. but different masses. The ammonium nitrate is sourced from spilt. Depending on the concentration. ANFO or cement). Naturally occurring elements comprise a mixture of isotopes. 74% N2 and up to 1% of other gasses including CH4. The cement source is generally shot-crete rebound (an increasing problem with more shot-crete usage). 2.10 Producer Gas A combustible mixture of gasses formed commercially by the action of air passing through a layer of incandescent fuel (coal.65 and as a result. 15% CO. 2. For example. it is not used as a refrigerant in cooling plants where there is a possibility of the gas leaking into the mine atmosphere (although it is otherwise a particularly suitable gas for the purpose).4. fresh ANFO “blow-back”. headache. working shortly after shot-crete applied). working close to face in poor ventilation. NH3 has a TWA of 25 ppm and a STEL of 35 ppm Ammonia readily passes into and out of solution in water. the ammonium nitrate from the ANFO reacts with Calcium Hydroxide to produce ammonia gas (2NH3). 10 Page 37 © AMC Consultants Pty Ltd 2005 . shortness of breath. U238 has 92 protons and 146 neutrons. coughing. especially the eyes and the upper respiratory system. It has a specific gravity relative to air of only 0. It is one of the isotopes10 produced by the radioactive decay of uranium to lead. An identical mixture may be formed in mine fires. pungent odour (the smell is familiar to those who have used certain disinfectant and window cleaning products). cement and water. The only solutions are to remove or isolate one or more of the components of the chemical reaction (i. Ca(NO3)2 and water: 2NH 4NO 3 Ca(OH)2 2NH3 Ca(NO 3 ) 2 2H2 O There have been an increasing number of ammonia “fumings”. tends to layer against the backs in areas of low air velocity (laminar flow conditions).e. nausea and eventual collapse may be experienced. and has a very distinctive. symptoms such as burning sensations.10 Ammonia (NH3) Ammonia is colourless. The main source of ammonia in mines is from a chemical reaction involving ammonium nitrate. Worst affected personnel seem to be those on charge-up (working at height. or un-detonated ANFO.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY 2.4. whereas the isotope U235 has the same number of protons (92). coke or charcoal). but only 143 neutrons. Ammonia is irritating or corrosive to exposed tissue. The uranium ore emanates gamma radiation. which also contributes to the total radiation exposure of the workforce.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Decay Series . it doesn’t tend to expose the lungs to a significant amount of radiation energy. it is managed by physically Page 38 © AMC Consultants Pty Ltd 2005 .5 billion yrs 24 days 1. In underground uranium mines. various forms of radiation are released including Alpha ( ) and Beta ( ) particles as well as gamma ( ) radiation. During the decay process. positively charged particles that can travel a few centimetres in air. As a result.8 days). Gamma radiation is electromagnetic radiation that can penetrate deeply into the body.2 minutes 250. The half-life of radon is relatively long (at 3. radon daughters and radioactive dust particles are just some of the radiation hazards.Uranium to Lead (NOTE THAT THE ISOTOPES IN BOLD ARE RADON DAUGHTERS) Nuclide Uranium 238 Thorium 234 Protactinium 234 Uranium 234 Thorium 230 Radium 226 Radon 222 (gas) Polonium 218 (RaA) Lead 214 (RaB) Bismuth 214 (RaC) Polonium 214 (RaC’) Lead 210 Bismuth 210 Polonium 210 Lead 206 Radiation Half-life 4.600 yrs 3. but alpha particles do not penetrate the skin surface. In contrast to dust and radon daughters. Radon daughters tend to attach themselves to surfaces such as dust particles and aerosols. Alpha particles are low energy. Gamma radiation exposure can’t be controlled by ventilation.000 yrs 80. mandatory respiratory protection is sometimes used as a method to limit radon daughter exposure.000 yrs 1. stable seconds The half-life is the time taken for one half of the atoms in a radioactive substance to decay. As a result. The respiratory system can be damaged by inhaled alpha particles. When all else fails. It is a different story with the relatively shortlived radon daughters (referred to radon progeny in these more politically correct times)! Inhalation of radon daughters in sufficient concentration over a long enough period of time will increase the likelihood of exposed personnel developing lung cancer.8 days 3 minutes 27 minutes 20 minutes 160 22 yrs 5 days 140 days infinite. It is also important in order to reduce the exposure to alpha emitting dust particles. They can penetrate the skin and cause damage to the body’s cells and organs. the control of ambient dust (especially respirable dust) and diesel soot levels in uranium mines is of particular importance. Instead. Beta particles are electrons. considerable care with mine design and scheduling is required in uranium mines and accordingly. Once the radon emanates from the rock. averaged over 5 yrs. ventilation design criteria can specify underground air residence times (after exposure to rock containing uranium) of less than 10 to 15 minutes. with high ore rock surface exposure (e. Note that practice of the “ALARA” (As Low As is Reasonably Achievable) principle is always the recommended approach with respect to radiation doses and a number of operations have adopted internal standards which aim to achieve dosages that are less than a third or a quarter of the prevailing limits. Depending on the ore grade. it becomes a “time bomb”. At one. Page 39 © AMC Consultants Pty Ltd 2005 . In order to limit exposure of personnel to radon daughters. The aim of the ventilation system design is to remove the radon gas from the underground environment as quickly as possible after it is produced. the approximate contributions to the total radiation dose are: Radon daughters Gamma Radiation Airborne alpha emitting dust 40% 40% 20% Assuming the ventilation system is well designed and managed. and begins immediately to disintegrate into radon daughters. Determination of a “safe” or “acceptable” exposure standard for radon and radon daughters is complex. This contaminated air should flow to a surface exhaust airway via as direct a route as possible. Personnel should not be exposed to the resulting high radon daughter concentrations in the air leaking or exhausted from these locations. It is important to note that the concept of residence time is of critical importance when designing ventilation systems for uranium mines.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY shielding the workforce from the ore (particularly high grade ore) and by mine design and shift rotation to limit the time spent in areas where the gamma radiation levels are high. Exposure to these gasses constitutes just one of several contributors to the total radiation exposure. The total effective radiation dose is measured in units of Sieverts (Sv). low grade underground uranium mine. The Sievert is a unit of radiation derived health risk. stopes and sealed off workings) are radon daughter “breeding grounds”. The ventilation system design should ensure that personnel work in “fresh” air that has travelled from the surface to the working place via a direct route in low-grade (waste) rock. ventilation considerations are often the most important mine design criterion. The gas is found in underground mines (not just uranium mines) and sometimes also in caves (many of which have poor ventilation and therefore long residence times). The prevailing annual limit for radiation workers is 20 mSv/ year. Areas of low velocity.g. The source of radon in mines is primarily via emanation from rock containing uranium and radium. the relative contribution to total dose from gamma radiation will increase for mines with higher uranium grades. 74% 50 0.04 Carbon Dioxide Hydrogen Hydrogen Sulphide Nitrogen CO2 H2 H2S N2 Colourless Soda taste Colourless Tasteless Colourless Sweet taste Colourless Tasteless Slight pungent Nil Rotten Eggs Nil Non-flammable 4.0% .14.0 in mines) STEL (ppm) (%) 13.5 0.0003 5 0.BASIC MINE VENTILATION SUMMARY OF GASSES Name of Gas Symbol Properties Smell Flammable Limits (ppm) Oxygen O2 Colourless Tasteless Nil In contact with oil or grease TWA (%) 17.005 400 0.5% Sulphur Dioxide Colourless Acid taste Burning Sulphur Pungent Suffocating Oedema Non-flammable 2 0.001 - 30000 15 - 3.25% Remove people when= or > 2.5% .0 - - 200 ppm After 20 mins may cause collapse usually delayed 400 ppm after 15 mins exposure may be fatal 50 ppm Irritating to eyes and nose Nitrogen Dioxide NO2 Brown colour Acrid taste Firing fumes Acrid Non-flammable 3 0.0 (19.0015 - Oxides of Nitrogen NOx Firing fumes 25 0.0% Methane CH4 Colourless Tasteless Nil 5.74% 4.0 OCCUPATIONAL HEALTH AND SAFETY Physiological Effects Essential to maintain life Displaces oxygen in blood 200 ppm Drowsiness.0002 5 0.0005 250 ppm severe pulmonary oedema collapse is usually delayed Non-poisonous Asphyxiant Stop diesel engines when = or > 1.0% .0005 SO2 Page 40 © AMC Consultants Pty Ltd 2005 .0 0.0% Turn off electrical power when = or > 1.5% .45% Non-flammable 5000 10 - 0. Headache after 2 hours work 400 ppm Headache after 45 mins work 1200 ppm Palpitations after 10 mins work 2000 ppm Unconsciousness after 10 mins work >3000 ppm Death possible Increased respiration Depression of breathing Non-poisonous Asphyxiant 100 ppm Irritation to eyes and throat : Headache 1000 ppm Immediate unconsciousness Non-poisonous Asphyxiant 100 ppm irritant to respiratory passage and eyes Carbon Monoxide CO Colourless Tasteless Nil 12. PC engines are considered to be more acceptable for use in underground workings because they generally have lower gas emissions. either direct injection (DI). Complete combustion of 1kg of diesel fuel would result in Carbon Dioxide (CO2) water vapour (H2O) and Sulphur Dioxide (SO2) in the following proportions CO2 = 0. Diesel engines are considered to be reliable. For this to occur. Engines used in mining can be broadly classified as. indirect injection (IDI or otherwise referred to as pre combustion PC) they can be naturally aspirated or turbo charged for increased power and performance. Other fuels such as hydrogen have been investigated since the 1960’s and there is one hydrogen engine operating in Canada today but generally speaking there use remains in the laboratories until all the safety implications have been overcome. well above the ignition point for diesel fuel. The exception being some electric LHD’s and trucks. As the cylinder nears the top of it stroke the temperature of the gases rise to temperatures in excess of 540°C. robust and relatively easy to maintain.5%) and Hydrogen (15%) with a small amount of Sulphur (0.845 × 44 12 = 3. The diesel engine as it is now known.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY 2.5. air is injected into the cylinder and compressed to a high pressure with a corresponding temperature rise. but it is worth a note that electronic fuel management systems have yet to be introduced into underground coal mines and this will only occur once they are able to provide “intrinsically safe” mechanisms. Diesel fuels consist primarily of Carbon (84. for ignition of the injected fuel. A fine mist of fuel is injected into the gap where it combusts. Electronic fuel management systems are progressively being introduced more extensively into underground hard rock mines. Although this fuel management system has helped reduce the more visible DPM the side effect has been the increase (albeit minor) in levels of oxides of nitrogen (NOX).5 Diesel Engines Dr. is used almost exclusively as the engine of choice in Australian Mines. 2.1 Diesel Exhaust Emissions (DEE) The production and concentrations of gases in DEE is dependent upon Engine type and manufacturer Engine speed Engine adjustment and maintenance Working load of the engine Type of fuel Because of these variables it is extremely difficult to provide absolute values of the quantity and concentrations of DEE gases. generated on the compression stroke.5%). and particularly efficient at partial loads. The resulting physical and chemical processes lead to auto-ignition just prior to the cylinder reaching top dead centre.10kg Page 41 © AMC Consultants Pty Ltd 2005 . the combustion energy released forces the piston down to bottom dead centre in the power stroke. Rudolf Diesel first patented the device and principles for a compression engine in Germany in 1892. These engines do not rely on spark plugs for fuel ignition but rely on the in-cylinder temperature. Typically diesel fuels contain two hydrogen atoms for each carbon atom and can therefore be represented as C12H24. 08kg but at this ratio there is a large amount of unburnt fuel emitted.2 Diesel Particulates COMPOSITION OF DPM Sulphate + Water Diesel particulate matter (DPM) is the soot particles emitted with diesel engine exhaust.005 18 2 = 1.5. Because there is a large amount of Nitrogen in the injected air used for combustion this along with the pressure and temperature of combustion some of the nitrogen is oxidised to NO and this then oxidises at a much slower rate to NO2 to the extent that only 10% is oxidised by the time it is exhausted from the engine. or alternatively each 0. the air required for complete combustion is 3.06kg.35kg 64 32 0. hauling full. Maximum fuel consumption is achieved when the engine is operating at “torque stall”.05kg at full throttle up to a maximum of 0.46kg of gas.46 – 1.045kg) and 25:1 (0. Carbon Polyaromatic Hydrocarbons (PAH) Hydrocarbons (HC) Metals Page 42 © AMC Consultants Pty Ltd 2005 . The size of the particles is almost totally within the respirable range. Carbon (soot defined as diesel particulate matter) – (DPM).46 0.150 × SO 2 0. Other toxic substances like polyaromatic hydrocarbons (PAH) are also found in both the HC and DPM component of the DEE.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY H 2 O = 0. dumping full. For example a LHD cycle would include loading. When averaged over a full shift the fuel to air ratio would typically be between 22:1 (0.46kg and as standard air contains 23.0kg of air for complete combustion. Hydrocarbons (including aldehydes) – (HC).e. Fuel consumption is related to work load on the engine (i. DPM is thought to be a “potential carcinogen” but no unequivocal evidence on this matter is currently available and the subject is as a result.15% Oxygen. The particles contain hundreds of adsorbed compounds.95kg . In the case of mining equipment this would be when a LHD unit is bogging and when a truck is hauling fully loaded up an incline. At full throttle full load this could be as high as 0. some of which are known to be carcinogenic.95. Although the liquid fuel droplets in the injected mixture begin to decompose on ignition the fuel rich zones associated with them result in incomplete combustion and the formation of CO rather than CO2 and as the load increases the amount of excess Oxygen decreases and tends to increase the formation of CO.04kg fuel) In reality diesel engines never operate at 100% efficiency. hauling empty and Idle.01kg A total of 4. In other words an air to fuel ratio of 1:14.2315 = 14. the higher the work load the greater the fuel consumption).00 = 3. Fuel to air ratios in normal conditions are 0. seldom at full load and consequently complete combustion is never achieved. therefore maximum concentrations and emission levels of DEE gases.0669kg of fuel requires 1. 2. by mass. For complete combustion the amount of Oxygen required is 4.01kg at idle and 0. The products of this incomplete combustion are Carbon Monoxide (CO). The concentrations of gasses in DEE are directly related to the quantity of fuel used. Oxides of Nitrogen (NOX) including Nitric Oxide (NO) and Nitrogen dioxide (NO2). Ideally exhaust gas emission rates should be obtained for all normal operating situations. still somewhat controversial. More particularly since the formation of a task force initiated by Coal Services Pty Ltd (formally the Joint Coal Board) in 1997 to determine the management and control of DPM in Coal mines. such as the CO catalytic converters have been highly successful whilst others are still in development stage. Some. The 1990’s has seen some major advances in engine technology to reduce DEE. if we were to follow the USA lead then an exposure standard of 0. The obvious problem is to get a single conditioner for all contaminants as experience has shown that one problem is solved and another created. and the higher in-cylinder temperatures have subsequently increased the amounts of nitrogen that are oxidised to Nitric Oxide (NO). A number of “exhaust conditioners” have been developed over the years. and a standard along these lines was introduced for the USA mining industry in 2001. Hence a dilemma.15 mg/m3. some of which is re-oxidised to Nitrogen Dioxide (NO2). Available methods for reducing underground DPM include: Use more efficient diesel engines (eg engines with electronic engine fuel-air mixture control systems) Page 43 © AMC Consultants Pty Ltd 2005 . Combustion chambers have been redesigned to achieve better mixing resulting in improved combustion and decreased DPM and hydrocarbons Oil control has been improved significantly as prior to 1990 as much as 30% of DPM was attributed to lubricating oil. This improvement has reduced DPM by as much as 10%. As yet the hard rock industry has not embraced these studies but will be keeping a watchful eye on proceedings since the introduction of control legislation in the USA in 2001. Improved intake manifold and port configurations have achieved better in-cylinder air distribution eliminating fuel rich spots and inturn decreasing DPM and hydrocarbons emissions. The formation of NOX is the sole function of the available oxygen and the temperature.4mg/m3 (eight-hour exposure) will be introduced some time in the future. The American Conference on Governmental Industrial Hygienists (ACGIH) has proposed a general exposure standard for Diesel Particulates (DP) of 0. It is understood that establishing a diesel particulate exposure standard for underground mines in Australia is not on the short-term agenda. decreased DPM but at the expense of increased NOX emissions. but has failed so far to achieve worldwide recognition.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY DPM is a complex substance and has been to object of constant investigation for a number of years. Fuel injector design have allowed manufacturers to control the rate of fuel injection resulting in lower emissions of DPM and NOX Fuel injector pressure has been increased resulting in better atomisation of the fuel in the combustion chamber resulting in decreased DPM Turbo-charging has resulted in better combustion and decreased DPM whilst cooling the compressed air supplied to the intake manifold reduces the NOX that would result from the increased combustion temperatures. The USA control legislation is pointed at manufacturers and the reduction of DPM in the exhaust emissions. Adoption of the ALARA (As Low As Reasonably Achievable) principle to workforce diesel particulate exposures would however be a pragmatic and recommended response to the issue. Whilst there are currently no diesel particulate exposure standards for mines in Australia. In recent years design strategies have concentrated on the achieving more complete combustion and minimising the formation of in-cylinder particulate matter. These conditioners are extremely expensive and require a high level of maintenance. 5.000 EGER = Measured concentration x volume of exhaust gasses. A recommended reference is . some times referred to as the duty cycle.0 . emission characteristics. air cleaner maintenance etc) Use low Sulphur fuel (<0. 2.0015 m3/s per kW of installed power and an undiluted concentration of CO of 1500 ppm in the exhaust (i.0015 0.05% Sulphur).BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY Pay close attention to engine maintenance (tuning. Q 0. Based on the NOHSC 8 hour exposure standard of 30ppm for CO. a text book exhaust emission rate of 0. If the engine operating mode. It is good management to check this legislation for the state in which the mine is located. Use exhaust particulate filters especially on production equipment where high exhaust temperatures can be maintained for long enough to burn trapped particulates off catalysed ceramic filters.000.3 Dilution of Diesel Exhaust Emissions (DEE) The concentrations of contaminants in the ambient air are directly related to the total quantity of gases and particulates emitted from the diesel engine and the mine dilution ventilating air. October 1999. and could be as little as 20% to 40% of full load over the entire shift.0015 0.00003 .075 m3/s per kW. “More research into the effects of ventilation and diesel particulate exposure is required before comprehensive guidance can be provided on this issue” one can’t help but agree. One equation used to calculate this dilution factor is written as Q Qg AC NC Qg Equation 2-4 Dilution Equation Where Q = Qg = AC = NC = Notes: Quantity of airflow required for dilution (m3/s) Exhaust gas Emission Rate (EGER) (m3/s per kW) Maximum allowable gas concentration in the workplace. It states.“Diesel Emissions in Underground Mines – Management and Control” NSW Minerals Council. One of the questions asked of ventilation engineers is the quantity of ventilating airflow necessary to dilute these contaminants below statutory exposure limits.0. This type of fuel is now becoming more readily available in Australia.07499m3/s Page 44 © AMC Consultants Pty Ltd 2005 . Studies have shown that diesel engines in operating mines have a relatively low effective load factor. Up to 85% of particulates can be captured using particulate filters. the maximum allowable limit) the dilution airflow required for DEE is 0.0015 0. the quantity of emissions from the engine can be calculated.0. and the engine exhaust air volume are known. (m3/s) the normal concentration of gas present in the diluting air (m3/s) m3/s = ppm / 1.e. Most Australian state legislation provides some guideline for this dilution rate and in Western Australian legislation this is very specific.0015 = 0. TLV = 25ppm eight-hour exposure Q 0. For example consider the engine data provide by a engine manufacturer shown below.0015 1000 25 = 0.0600 m3/s per kW From this calculation the minimum dilution airflow should be 0. Q VC Y Equation 2-5 DEE Dilution (USBM) Where Q = V = C = Y = i. The use of these equations is fine but only IF the emission rate is known.0015 1500 30 = 0. the greater the speed of the engine the greater the rate of emission. Emission rate is a function of the number and dimensions of the cylinders and the speed of the motor.07500 m3/s per kW Similarly for NOX.lb (2101 Nm) @ 1200 RPM Rated Speed 432 degC 139mm 130mm Max Torque Speed 518 degC From this data we can estimate the exhaust flow (emission) rate for the engine Calculation of exhaust swept volume D b 2 2 S n 6 10 Equation 2-6 Engine Displacement Volume Where: D = Engine Displacement Volume (litres) b = Bore diameter (mm) Page 45 © AMC Consultants Pty Ltd 2005 . We can easily determine.e. by measurement the concentration of the contaminants whereas the rate of emission can be calculated from manufacturers data.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY The US Bureau of Mines (USBM) recommends the use of the following simplified formula to calculate the dilution factor for DEE. obviously. Quantity of airflow required for dilution (m3/s) Volume of gas produced (m3/s) Concentration of gas in the exhaust (ppm) Maximum allowable concentration in the workplace (ppm) Q 0. Knowing these the rate at which the gasses are forced from the engine enables the correct calculation of the rate of emission.075m3/s per kW of installed diesel power. Engine: Power Rating: Max Torque: Exhaust Temperature: Stroke: Bore: Inline 6 cylinder 4 stroke 475 HP (354kW) @ 2100 RPM 1550 ft. 8 x 1.7 m3/min at maximum torque (i.5 but will vary from engine to engine.5) and. 17.5 = 41. 26.8 m3 A further correction is then made for turbo charging and after cooling. 27.7 m3/min Correcting for temperature and assuming pressure (P) is constant (Universal Gas Law) Where: T = temperature in °K V = Swept Volume (m3) 11. Correcting for Turbo charging the emission rates now become 41.7 m3/min 11.1(litres) SEV Where: D s 2000 Equation 2-7 Swept Exhaust Volume (Four stroke Engine) SEV = Swept Exhaust Volume (m3/min) D = Engine displacement (litres) s = Engine speed (rpm) 2000 = Four Stroke engine factor SEV D s 1000 Equation 2-8 Swept Exhaust Volume (Two stroke Engine) Where: 1000 = Two Stroke engine factor 11.BASIC MINE VENTILATION OCCUPATIONAL HEALTH AND SAFETY = 3.7 m3 and similarly for maximum torque = 17.1 1200 2000 and at max torque speed Swept Exhaust Volume = P V1 1 T 1 P V2 2 T2 6.7 25 273 V2 432 273 at the rated speed = 27. Typically this 1.7).e.5 = 26.e.5 m3/min at the rated speed (i.7 x 1. Page 46 © AMC Consultants Pty Ltd 2005 .1 2100 The engine data provided is a four-stroke therefore at the rated speed Swept Exhaust Volume = 2000 11.1428 S = Stroke length (mm) n = Number of Cylinders Therefore D 130 2 2 139 6 6 10 = 11. T(K) T( C) 273. If we change the Celsius scale so that absolute zero (-273.g.e. When measuring dry-bulb air temperatures it is important to avoid the effect of radiative heat transfer (i.03% 0.15C° and 273.BASIC MINE VENTILATION PROPERTIES OF AIR “I can remember when the air was clean and sex was dirty. and will never separate again. Mine air also contains a percentage of water vapour. a meniscus can form at the boundary between the gas and the air. to ensure accurate reading. So 0 K = -273. leading to separation and layering.11% 0. It is useful to recall that at normal sea level pressure.93% Variable Note that layering of gasses (e. The vapour is regarded as being a separate component or impurity (i. which is heavier than air) sometimes occurs in mine airways. Dry-bulb temperature is simply the air temperature. methane. in spite of the fact that the various component gasses have different densities. wet cotton sleeve.1 m/s). temperature readings should not be taken near surfaces whose temperatures differ by more than several degrees form the air temperature – e.” George Burns 3 PROPERTIES OF AIR Air is a mixture of a number gasses. where the airflow is very low. are avoided. Page 47 © AMC Consultants Pty Ltd 2005 .15 Equation 3-1 – Relationship Between °C and K There are two types of air temperature readings that we deal with routinely in mining. which is lighter than air and Carbon Dioxide.g. The lowest (theoretically) possible temperature is –273.<<<0. Due to the effect of evaporation. wet bulb air temperature measurement near surfaces whose temperatures differ by more than a few degrees from the dry-bulb air temperature. or equal to the dry-bulb temperature. the wet bulb temperature will always be less than. Providing a turbulent air can easily break up this layering. Composition of Air Oxygen Nitrogen Carbon Dioxide Inert Gases Water Vapour 20. 3. Air is a perfectly mixed (homogeneous) mixture of gasses. In other words. The bulb must be aspirated by an airflow that is at least 3m/s.15°C) is reassigned the value of “0” then we will have what is known as the Kelvin temperature scale (K).15 K = 0°C. it is not viewed as being part of the air).1 Air Temperature Mine air temperatures are measured in SI units of Degrees Celsius. They are dry bulb and wet bulb temperatures. avoid measuring air temperature near a hot diesel engine) Wet-bulb temperature is measured with a thermometer whose bulb is covered with a thin. water freezes at 0°C and boils at 100°C. As with dry-bulb temperature readings.15°C (sometimes known as “absolute zero”). The gas will then mix evenly with the air.93% 78.e. If these gasses seep slowly into an area of very low airflow (laminar flow conditions . at constant pressure: T1 T2 Where: 3. 3. temperature (T) is in K and specific volume (V) is in m3/kg). specific volume.5 Density of Dry Air The density of dry air can now be readily determined using the Universal Gas Law. assuming pressure (P) is in kPa. R varies depending on the gas type. PV is a constant.e.4 Universal Gas Law Charles’ law and Boyle’s Law can be combined mathematically to produce what is known as the Universal Gas Law: P1V1 T1 P2 V2 T2 Equation 3-4 – Universal Gas Law Therefore. In other words if the pressure on the gases increases it’s volume will decreases. Conversely if the pressure decreases. kilogram of a given gas is known as R. An example calculation is outlined below: Example What is the density of dry air at a barometric pressure of 95 kPa and a dry bulb temperature of 25°C? Page 48 © AMC Consultants Pty Ltd 2005 . provided the temperature is kept constant.3 V1 V2 Equation 3-2 – Charles’ Law T = Absolute temperature (K) V = Volume occupied by gas Boyle’s Law Boyle’s law states that the volume occupied by a gas is inversely proportional to the absolute pressure exerted upon it. For dry air. for a given quantity (mass) of a given gas. Note that a Joule is 1 N m. provided the pressure is kept constant. The constant for one T Note that because we now specify that we have one kilogram of gas.BASIC MINE VENTILATION PROPERTIES OF AIR 3. In other words. the volume of the gas will increase: P1V1 Where: P2 V2 Equation 3-3 – Boyle’s Law P1 = Initial absolute pressure V1 = Initial volume occupied by gas P2 = Final absolute pressure V2 = Final volume occupied by gas 3.2 Charles’ Law Charles’ law states that the same rise of temperature produces in all gasses the same increase in volume. hence PV T R. R = 0. then the volume (V) is in units of m3/kg – i.2871 kJ/kg. it is said to be saturated.e.90 m3/kg Density ( ) kg/m3 = = 1. the amount of water vapour that the air can contain increases. The change in volume flow due to air compression is an important factor when designing and monitoring ventilation systems for deeper (e. Saturated air has a relative humidity of 100%. >1. In these deeper mines. kg/s). the air temperature is measured as 37°C and the barometric pressure is 102 kPa. This is a simplistic assumption since in mine airways.6 Moisture in Mine Air Up to now.g. it is therefore often more convenient to deal with air flow rates in terms of mass flow (i. The amount of water vapour contained in a volume of air is dependent on the temperature of the air. What is the flow rate at the base of the shaft if there is no leakage and no moisture pick-up in the shaft? Rearranging Equation 3. 1 V(m 3 / kg) Another useful application of the Universal Gas Law is illustrated below: Example 200 m3/s of dry air at a temperature of 30°C and barometric pressure of 95 kPa flows down an intake shaft into a mine. we have assumed “dry” air for all of our calculations. When air contains the maximum possible amount of vapour at a given temperature.11 kg/m3 This is a very useful “first pass” method to estimate the density of air. Page 49 © AMC Consultants Pty Ltd 2005 .000m below surface) mines. the change of volume due to compression of the air is small enough to be ignored. For the majority of mines however.BASIC MINE VENTILATION PROPERTIES OF AIR Rearranging Equation 3.4 V V RT and substituting
… P 0.5: V2 P1V1T2 T1P2 And substituting: V2 V2 95 200 (37 273) (30 273) 102 191 m 3 / s The result shows that we have “lost” 9 m3/s (4½%) of our airflow before it reaches the base of the shaft. It is accurate to within 0.2871 ( 25 273) 95 = 0. the air invariably also contains some water vapour. 3.5% for any condition between dry air at any temperature and saturated air (100% relative humidity) up to 25°C. At higher temperatures. At the bottom of the shaft. 4 is sufficiently accurate.325 Pa barometric pressure is 1.2 kg/m3 Unless otherwise stated. The vapour will condense out into water droplets. many mine fans operate in locations where the fan inlet air density is significantly different to standard air density. (kg of air/m3) Equation 3-5 Density of Humid Air Equation 3-6 Partial Pressure of Water Vapour esw = Saturated vapour pressure at the wet-bulb temperature (kPa) e sw = exp .287045 273.15 Where Air Density (kg/m3) (Some texts describe this as vair rather than air. The condensed water droplets can cause problems with surface fan operation.24t d 0.3 + t w Equation 3-7 Saturated Vapour Pressure at the Wet-bulb Temperature Page 50 © AMC Consultants Pty Ltd 2005 .378e 0. Condensation of water sometimes also occurs in upcast ventilation shafts – in this case the cooling of the mine air is caused by the reduction in air pressure as the air travels upwards (the opposite of autocompression). Equation 3. the performance figures supplied with mine fans assume that the fans will operate at standard air density.6t w 0. It is therefore necessary to understand how to calculate the actual air density against which the fans operate. The air density can be calculated using the relationship described as P 0. humid air is cooled below its dew point (e.) P = Atmospheric Pressure (kPa) tw = Wet-bulb temperature(°C) td = Dry-bulb temperature (°C) e = Partial Pressure of water vapour (kPa) e e sw 371. by a mine air cooler). 17. The density of air is the mass per unit volume and varies according to the water vapour contained in the air and three input values are required to determine the density of air which contains water vapour.04t d 0.7 Density of Humid Air The “Standard” density of dry air at 20°C and 101.4 0.BASIC MINE VENTILATION PROPERTIES OF AIR If air containing a certain amount of water vapour is cooled. They are: Barometric Pressure Dry Bulb Temperature Wet Bulb Temperature.4t w tw P td . Unfortunately. it is necessary to employ a calculation method that takes into account the effect of the moisture contained within the mine air.24 t d 371. Condensation of water vapour can cause “fogging” and can sometimes be a problem in mine airways where warm. 3. In many situations.g.27t w 237. a temperature will be reached where the air is unable to contain all of the water vapour. however where improved accuracy is important. This temperature is known as the dew point temperature.4 0. this is to distinguish between dry air and air containing water vapour. 8 Air Pressure Every person who works in an underground mine knows that the fan produces the airflow and generally accept this fact without needing (or wanting) to know any more.4 0. At this point we need to understand that fans create a pressure differential that causes the air to flow through the workings.6 25 0. when we pump up a tyre the pressure in the tyre becomes higher than the pressure of the atmosphere. More Accurate Method: Calculate the Saturated vapour pressure at the wet-bulb temperature e sw = exp .5 371.04 30 0.5 kg / m 3 0.3 + 25 = 3. use and placement of fans will be discussed later in these notes. Similarly if we were to suck the air from a vessel (create a vacuum) the pressure of the air out side the vessel would be greater than the pressure of the air inside the vessel.852 kPa Use Equation 3.5).4) and the more accurate method (Equation 3. 17. Page 51 © AMC Consultants Pty Ltd 2005 .287045 273.24 30 0.24 30 25 97. We will solve this problem using both the approximate method (Equation 3.378 2.4
… P and substituting
… RT 97.27 × 25 237. Approximate Method: Rearranging Equation 3.5 kPa. To assist with understanding consider the following.15 30 = 1.2871 (273 30 ) = 1.166 kPa Calculate the Partial Pressure of water Vapour e 3.108 kg/m3 3.5 to calculate the air density ( ): 97.BASIC MINE VENTILATION PROPERTIES OF AIR EXAMPLE What is the density of the air in a drive where the wet and dry bulb temperatures are (respectively) 25 and 30°C and the barometric pressure is 97. The operation.166 371. When this happens the flow will stop. When the tyre valve is opened the air flows from the tyre and if the vessel is opened the air will flow into the vessel.4 25 = 2. In both cases the air will flow from the high-pressure area to the low-pressure area until the pressure inside the vessel is the same as the pressure outside the vessel.4 0.121 kg/m3 In fact this is the density of dry air.5 0.852 0. The pressure shown on weather chats is usually expressed in millibars (mb) and often referred to as the Barometric Pressure. ie the pressure is used up overcoming resistance to the airflow. millimetres of mercury all of which are required to be converted to Pascals for use in mine ventilation calculations.1 Atmospheric Pressure The earth is contained in an atmosphere and by the force of gravity.8. 3.2 Barometric Pressure Barometric pressure is simply a description of the instrument used to measure the pressure of the atmosphere in which it is situated. If the pressure difference between two points remains the same and the resistance to airflow between these points is increased the air quantity will decrease (3) (4) Pressure is the force applied per unit area and in ventilating terms is usually expressed in Pascals. In ventilation (mines. This difference in pressure is known as the ventilating pressure and the following rules apply. Atmospheric pressure at sea level is equivalent to a mass of 10.000 kg on one square meter (m2) of surface and is expressed in the following ways: 1 Atmosphere. Of importance in to mine ventilation practitioners is the different types of pressure. The greater the pressure difference the faster the wind blows. 1013 mb. One Pascal (Pa) = One Newton per square metre (N/m2) There are may other expressions for pressure including inches of water gauge. In mine workings the pressure measured using a barometer includes pressure changes caused by fans and therefore is not always be a true indication of the atmospheric pressure outside the mine.325 kPa. air will continue to flow. Resistance to pressure reduces the ventilating pressure. buildings or otherwise) for air to flow from one point to another there must be a difference in pressure between the two points. Page 52 © AMC Consultants Pty Ltd 2005 .8. The larger the pressure difference between these two points the greater the quantity of air will flow. 1. 101.BASIC MINE VENTILATION PROPERTIES OF AIR This is also seen on a weather map where the wind blows from the HIGH pressure to the LOW pressure. 3. (1) (2) Air will always flow from a high pressure point to a low pressure point and as long as this pressure is maintained.013 Bar. This assumes the resistance between the two points remains unchanged. it exerts a pressure on the surface of the earth caused by the weight of the air above. BASIC MINE VENTILATION PROPERTIES OF AIR 3. The faster the air moves the greater velocity pressure will be and vice versa.3 Static Pressure (SP) Static pressure is the potential or stored energy of the air often called the “bursting” pressure and this term does in fact make it easier to visualise. For example when the tyre valve is opened the potential (static) pressure is then converted to kinetic Direction of Airflow energy as it flows from the tyre. In the case of a ventilation duct it is the pressure holding the duct open. which would exist if the air were not moving. however it can be measured indirectly using pitot tube. It is called static pressure because it is the same as the pressure of the air. To gauge In ventilation ducts the static pressure is measured with a side tube. 3. normal to the direction of airflow. In mine ventilation this is termed “Velocity Pressure”. because static pressure is the pressure exerted by the air on the walls of the containing vessel.8. Velocity pressure cannot be measured directly.5 Total Pressure (TP) v2 2 = = = Equation 3-8 Velocity Pressure Velocity Pressure (Pa) Density of air (kg/m3) Velocity (m/s) Total Pressure is the algebraic sum of the static pressure (potential energy) and the velocity pressure (kinetic energy) and is measured with a facing tube.8. Velocity pressure is calculated from VP Where VP v 3.4 Velocity (Dynamic) Pressure (VP) Moving air possess “kinetic energy” which is the energy associated with motion. Direction of Airflow To gauge Page 53 © AMC Consultants Pty Ltd 2005 . parallel to the direction of flow.8. 7 Natural Ventilating Pressure Airflow through a mine will occur whenever there is a pressure difference between the intake and exhaust. This is often referred to as the chimney effect where warm air rises up the opening displacing the colder air above and drawing more air into the bottom.BASIC MINE VENTILATION PROPERTIES OF AIR TP SP Where VP Equation 3-9 Ventilating Pressure TP = Total Pressure (Pa) SP = Static Pressure (Pa) VP = Velocity Pressure (Pa) 3. This method for ventilating underground was Page 54 © AMC Consultants Pty Ltd 2005 .6 Measuring Pressure in a Duct The static. Natural Ventilation Pressure (NVP) is formed when there is a difference in air temperature and density between a vertical column of air inside a mine and the corresponding column of air outside the mine.8.8. velocity and total pressure may be obtained for airflow in a duct using a tube and a manometer. When these columns are connected airflow will occur. Direction of Airflow Static Pressure Velocity Pressure Total Pressure 3. BASIC MINE VENTILATION PROPERTIES OF AIR practiced by the Greeks in 600BC when fires were lit at the bottom of shafts to create a draught of air.12 2 1. NVP Where NVP g h = = Pascals Acceleration due to Gravity (9. summer to winter and may in fact flow in opposite directions. For example the heat of summer may cause the air to flow into the workings.81m/s2) gh Equation 3-10 Natural Ventilating Pressure workings = Difference in height between start and finish of each branch (m) = Mean True Density in each branch (kg/m3) A = 1. whereas in the colder winter months the flow will be from the mine workings and will have an impact on the operating point of the primary ventilating fans. The variance of NVP is dependent upon a number of variables including elevation depth from surface geothermal gradient local climatic conditions In its simplest form NVP can be estimated by assuming a closed circuit (intake exhaust).105 (kg/m3) Page 55 © AMC Consultants Pty Ltd 2005 . Although this impact on mine fan performance is limited. In mines this occurs when there is a difference in temperature between the workings and the surface.09 1.3 kg/m3 B = 1. determine the mine Natural Ventilating Pressure in (Pa) 600m 600m C = 1. Variations of temperatures will occur form day to night.09 kg/m3 Example D = 1. the potential NVP needs to be quantified. Air will flow from the column with the lowest average temperature to the column with the highest average temperature.2 kg/m3 Calculate the mean density in each branch AB 1.15 kg/m3 From the data shown in the schematic. 13 2 1.140 6504 Pa 6710 Pa = 6504 . this equation can be simplified to: NVP Where MI ME gh MI ME = = Mean Density of the Intake (kg/m3) Mean Density of the Exhaust (kg/m3) Page 56 © AMC Consultants Pty Ltd 2005 .125 (kg/m3) 1.81 600 1.81 600 1.13 1.12 1.15 2 1.105 9.BASIC MINE VENTILATION PROPERTIES OF AIR BC CD 1.6710 = -206(Pa) For mines with surface intake and exhaust point at the same level.14 (kg/m3) Calculate NVP in each branch NVPAB NVPCD Total Mine NVP NVPAB NVPBC NVPCD 9. 9 5 1880 1560 320 22.1 Facing tube Side tube VP (Pa) v (m/s) Average Velocity Quantity of air Average Static Pressure Page 57 © AMC Consultants Pty Ltd 2005 . v = 2VP 4)
….Q=VA 1.0 101 19.3 8 1835 1550 285 21.7 97 25.5 6 1850 1555 295 21.200 mm diameter.4 1.2 [Q] Using a pitot static tube the following pressure readings were recorded in a flexible duct 1.131 8.1 (m3/s) 4 1920 1560 360 23. the average static pressure 2. v Q (m/s) 3) A 1.8 (m 2 ) 2)
….132 (m2) 3 1870 1555 315 22.3 1825 1490 335 23.000 mm 1. A Area of the duct Measuring Point 1 D2 4 2 1845 1545 300 21.1 [A] Calculate the velocity pressure for air quantities of 10 m3/s.9..9. VP = Density (kg/m3) Diameter (m) Area (m ) Q = 10 (m /s) Q = 20 (m /s) Q = 30 (m /s) 3 3 3 2 v2 (Pa) 2 2)
….539 6.1 [Q] 3.2 1.VP=TP-SP 3)
….9.5 25 13.0 0.2 [A] Equations used: 1)
….2 1.2 (m/s) 25. 20 m3/s & 30 m3/s in ducts with diameters of 1.2 875 3. Measuring Point 1 2 1845 1545 3 1870 1555 4 1920 1560 5 1880 1560 6 1850 1555 7 1845 1560 8 1835 1550 Facing tube Side tube 1825 1490 If the density of the air was 1. Assume the density of air is 1.785 v (m/s) VP (Pa) v (m/s) VP (Pa) v (m/s) VP (Pa) 12.5 228 (m 2 ) 1.2 kg/m3 Equations used: 1)
….4 312 (Pa) 22.200 mm & 1.7 188 26.5 389 38.9.8 47 17.400 mm.5 422 A D2 4 1. the average velocity pressure the quantity of air flowing in the duct 3.6 7 1845 1560 285 21.9 Assignments 3.26kg/m3 calculate 1.BASIC MINE VENTILATION PROPERTIES OF AIR 3. In addition he uses about forty percent basic knowledge and perhaps ten percent specialised knowledge” W. assume the fluid consists of layers parallel to each other and a force is applied. and the size of the opening. In a mine there is a constant conversion of energy from potential (static pressure) to kinetic (velocity pressure) and the energy source must be maintained to ensure that the air continues to flow. because in practice there are usually a number of factors involved which cannot be accurately evaluated. However if the surface roughness changes it becomes difficult to continue at the same velocity and more energy is required to maintain the velocity.BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW “Ventilation is a science. energy is required to change the velocity or direction. When something is moving in a straight line at a constant velocity. there are some similarities. or mine workings) is dependent upon: the difference in pressure at the start of the system and the end of the system. Again consider the tyre. Once something begins to move and the energy remains constant it continues to move at the same velocity. albeit not always a precise science. the fluid will flow relative to the other layers. These being: the roughness of the wall and. The more the valve is opened the faster the air escapes even though the pressure inside the tyre was the same to start with. which deforms continuously when subjected to shear stress. Page 58 © AMC Consultants Pty Ltd 2005 . A successful mine ventilation engineer uses about fifty percent common sense in solving the problems he is faced with. Although not strictly a fluid. These changes occur whenever the airway in which it is flowing changes direction. To explain. However there are other factors that cause more or less air to flow. shape or size. the severity and number of times the air has to change direction. in a direction parallel to its plane. With the valve opened the air rushes out until the pressure stops (equalises). This force divided by the area of the layer is called shear stress and as long as it is applied. The losses in energy due to the roughness of the wall are termed “frictional pressure losses”. If the energy source is removed the flow will stop. Lets now consider air as a fluid described as a substance. Le Roux Mine Ventilation for Beginners 3rd Edition 4 FUNDAMENTALS OF AIRFLOW The quantity of air that will flow through a “system” (duct. The losses in energy due to a change in direction of the airflow are termed “shock pressure losses”. L. Air as we know contains water (humidity) in various quantities. 2 for underground mines and approaching 1 in large voids where the airflow becomes laminar. however in some cases the resistance is small enough to be insignificant. This relationship has since been called the Ventilation Equation. or where low velocity leakage occurs. then the quantity of air flowing was also equal to zero. In the vast majority of cases the use of 2 is accepted as the standard. The shear resistance between these streamlines is caused by friction between the layers moving at different velocities. the flow pattern is streamlined (laminar) and therefore the 11 Numerous investigations showed that the index actually lies in the range 1. the fluid is called frictionless or ideal. Page 59 © AMC Consultants Pty Ltd 2005 . the pressure required increases as the square of the quantity11 (i.8 to 2.1.BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW 4. if the pressure was equal to zero. If the shear movement is resisted then the fluid is called real. This relationship was termed the resistance of the system and was expressed as R Where R P Q = = = Resistance (Ns2/m8) Pressure (Pa) Quantity of airflow (m3) P Q This held true whilst the airflow was laminar however. If there is no resistance to movement.1. the pressure is proportional to the quantity of airflow. They also recognised that as the pressure was increased then the airflow quantity also increased i.2 Turbulent Flow As the velocity is increased. Similarly.e.2 Airflow Equation Investigations undertaken in the 1800’s recognised that if there is no pressure difference between the start and end of an airway. In other words. Pressure is proportional to the quantity squared). the streamlines become randomly arranged and the flow becomes turbulent with the additional eddy currents adding to the shear resistance. 4. to increase the quantity three-fold. In reality ideal fluids do not exist. when air flows at low velocity through a worked-out area. 4.1 Laminar Flow At low fluid velocities the streamlines of flow are almost parallel to each other. P RQ 2 Equation 11 Ventilation Equation There can be speculation that.e. i. the pressure required was nine times the original pressure. it did not hold true for turbulent airflow and it was noted that in fully turbulent flows that to double the quantity of air flowing then a pressure four times the original was required.e. there will be no flow of air. Example Calculate the pressure loss when 4 m3/s of air flows through a duct having a resistance of 9.BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW formula relating P. We can therefore say that R = f(v. The non-dimensional group f1 2 2 2 2 Dv D2 v 2 D v D v the force or Euler coefficient. R and Q should revert to P = RQ. in reality the pressure differentials are small enough to be inconsequential and it is generally accepted in mine ventilation that all flows are turbulent and this relationship is seldom. For example. the lower the resistance (R) of the airway. Dv is referred to as Reynolds 12 The dimensional analysis and solution is described in “Environmental Engineering in South African Mines” Chapter 1.e. the larger the cross sectional area (A) of the airway. the density of the fluid ( ) and the cross sectional area (A) of the pipe. From the ventilation equation P = = = R Q2 9. In other words. the viscosity ( ) of the fluid and the relationship for R is rewritten as R = f(v. if one airway has a small cross sectional area and another a large cross sectional area. A. (pp1-27) Page 60 © AMC Consultants Pty Ltd 2005 . By analysis12 and substitution the equation is written as R R Dv R is referred to as or . In around 1850 Atkinson hypothesised that the value of R was dependant upon on certain characteristics of the airway or duct.3 x 42 149 Pa Calculate the pressure loss when 8 m3/s of air flows through the same duct. A) where f is some function of the variables. 4. used. . and all other factors (P and Q) remain constant. ).3 Ns2/m8 From the ventilation equation P = = = Example R Q2 9. i. Since there are four unknowns it is not possible to obtain a unique solution. air will flow more easily through the second airway. . denoted by Cf and the group Number (Re). if ever. Although this is true. By substituting C1 for f and completing a dimensional analysis the equation for this relationship can be written as R = C1v2 A and would assume C1 as a constant. Most of the early work on fluid flow was undertaken on the assumption of circular pipes and showed that the drag force (resistance = R) of a pipe depends on the flow velocity (v).3 x 82 595 Pa You should note that in the second example the quantity flowing is double that flowing in the first example and that the pressure required for this increased flow is four times that required in the first case. Measurements on different pipes and various velocities would show that C1 is NOT constant and there was a fourth variable.3 Resistance (The friction factor). BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW However in addition to Reynolds Number the surface roughness also influences the resistance force. The surface roughness (e) also has a relationship to the area or as above to the e . diameter (D), and this is described as the ‘relative roughness’ and defined as D Further evaluation and relating to Bernoulli’s Equation13 P1 it is shown that k v1 2 2 g H1 P2 V2 2 2 g H2 1 2 P and k is described as the friction component and expressed as v2 P 1 2 D and length L. It is also possible to equate this to rectangular ducts if the diameter (D) is replaced with the equivalent hydraulic diameter Dh Dh Where 4A C Equation 12 Hydraulic Diameter L v2 where P is the static pressure loss due to wall friction in a parallel duct diameter D Dh = Hydraulic diameter (m) A = Cross sectional Area of Airway (m2) C = Circumference of Airway (m) The equation for friction can now be rewritten as P v2 L 2 Dh A more complete analysis will show that the friction coefficient is a function of Reynolds Number (Re), relative roughness ( ) and duct shape (s) where Reynolds Number =Re = Surface roughness = Dv e and D s = the shape factor of the duct cross section. Experiments showed that the shape factor (s) had very little influence and the non-dimensional parameters had a major influence. After further studies and experimental work on smooth and rough walled ducts. The equation for the actual relationship shown in this test work can be represented by 1 Where Bernoulli’s Equation : Law of Conservation of Momentum is not discussed in these notes but can be found in many texts dealing with fluid flow. 13 1.74 2 log 2 18.7 Re Equation 13 Friction Factor Page 61 © AMC Consultants Pty Ltd 2005 BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW e = Relative roughness Dh e = Average height of surface irregularities or surface roughness (assume 0.35 m for rock wall, 0.02 m for raisebored) Dh = Hydraulic Diameter (m) Dv And Re = Density (kg/m3) = Viscosity (kg/ms) Dh = Hydraulic Diameter (m) V = Velocity (m/s) In mine ventilation the term Atkinson’s k Factor. 4.3.1 Atkinson’s Equation is usually replaced by ‘k’ known as the coefficient of friction or Atkinson also noted that if air has to rub against a larger area of surface in one airway than in another, the resistance will be higher in the airway with the largest “rubbing surface”. This rubbing surface is found by multiplying the perimeter (C) by the length (L). P Where P k C L A v = = = = = = Pressure (Pa) Atkinson’s Friction Factor with consideration to surface roughness. Circumference of the duct (m) Length of duct m) Cross sectional Area of the duct (m2) Velocity of the fluid (m/s) kCLv 2 A Equation 14 Atkinson’s Ventilation Equation (Velocity) If we substitute the physical values in the Atkinson equation N kCLv and the Right hand side 2 A m 2 k m m m2 Left hand side Pressure is Pa Combining both sides therefore k Ns 2 m4 N m2 m2 s km 2 . s2 km 2 s2 Substituting the dimensions of force N kg m then k s2 kg m s2 s2 m4 kg m3 This is important because it shows that Atkinson’s friction factor is not dimensionless and will kg vary according to the dimensions 3 which is the same dimensions as density. Atkinson had m Page 62 © AMC Consultants Pty Ltd 2005 BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW ignored density effects deriving this equation and therefore is valid only for air with standard density. The use Atkinson’s equation for any density it need to have a correction applied and it becomes kCLv 2 P A S Where = Density if air flowing in the duct (kg/m3) 3 S = Density of standard air (1.2 kg/m ) is in Atkinson’s formula to allow for the fact that the pressure requirements S The term depend on the density of the air. Obviously, more pressure will be required to pass heavier (denser) air through a system than the lighter air. In fact, the pressure (P) required is directly proportional to the air density ( ). More often than not it is convenient to express Atkinson’s equation in terms of quantity of air rather than velocity and since V = QA this equation is rewritten as; P kCLQ 2 A3 Where P K C L A Q = Pressure (Pa) = Atkinson’s Friction Factor (Ns2/m4) = Circumference of Airway (m) = Length of Airway m) = Cross sectional Area of Airway (m2) = Quantity of airflow (m3/s) = Density if air flowing in the duct (kg/m3) 3 S = Density of standard air (1.2 kg/m ) Equation 15 Atkinson’s Ventilation Equation (Quantity) S The values of ‘k’ are determined from measurement and calculation. The values below are sighted in texts, and generally hold up to scrutiny. Some mines may find differing results outside of these values. In practice all mine should measure and determine their specific factor(s) because there will always be more than one factor that could be used. Some Typical Values for Atkinson’s Friction Factor (k) at Standard air density Airway Type. Smooth pipe Normal rigid ducting Flexible ducting Concrete surfaced Rock surfaced Raise bored Timbered Airway Timbered rectangular Shaft k factor (Ns2/m4) 0.0028 0.0030 to 0.0035 0.0030 to 0.0065 0.0035 to 0.0040 0.0070 to 0.0200 0.0035 to 0.0050 0.0400 to 0.0600 0.0400 to 0.1000 Page 63 © AMC Consultants Pty Ltd 2005 the pressure required to overcome the friction in this drive is 54 Pa 4. obstruction. junction.BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Example Calculate the pressure required to overcome friction with an airflow of 60 m3/s in a 5. In short shock losses are the result of flow separation that occurs whenever the airflow changes direction.016 Ns2/m4.O m x 4. dimensions and characteristics. The pressure losses resulting from a change in direction can be determined from the Shock Loss Equation PSHOCK Where PSHOCK = Pressure loss due to shock (Pa) X = Dimensionless shock loss factor similar to Atkinson’s friction factor and is constant only for a given set of conditions depending upon shape.5 Pa 60 2 1 .0 m haulage drive that is 450 m long and has a friction factor (k) of 0. Given that k L Q C A = = = = = = 0.0 x 4.0 m2 kCLQ 2 A3 From Atkinson’s equation P S 0.016 Ns2/m4 450 m 1.16 18.4 Shock Losses Shock losses are the change in total pressure across all airway elements such as the entrance to a system.1 kg/m3. 2.0 3 = 53. Page 64 © AMC Consultants Pty Ltd 2005 . Air density in the haulage is 1. Angle of the change in direction.0) = 20.1 1 .1 kg/m3 60 m3/s 2(5 + 4) = 18 m (5.2 Therefore. Configuration and flow through the element.0 450 20. a bend. change in section and exit from the system. (See below) X VP VP = Velocity Pressure of the air (Pa) And Where VP v2 2 = Density of the air (kg/m3) v = Velocity of the air (m/s) The shock loss factor X is a function of the: 1. BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW 3. 4. 5. 6. 7. 8. 9. 10. 11. Degree the abruptness of the change, Radius of curvature, Ratio of the radius to width of the airway Aspect ratio between the height and width, Velocity in the airway Airway roughness Shape of the airway Airways immediately before and immediately after the change in direction, The number and type of complex elements i.e. two bends, bend followed by an expansion The large number of variables that contribute to shock losses causes the calculation of these losses is extremely complicated and seldom necessary in mine ventilation because of their small magnitude and the inaccuracy of the X value. WARNING- If airflow and pressure surveys have been used to determine the resistance of any part of the mine workings these measurements will include the losses due to shock and any use of additional factors will cause undetectable errors in the results. Shock losses are generally “over used” in computer ventilation modelling and the calculation methods shown below are approximations of the actual number taken from published texts14 and suitable for use in most computer ventilation models. Wherever possible ventilation practitioners should determine these values by direct measurement. 14 “Fan Engineering – Eight Edition” Published by Buffalo Forge Company. Buffalo, New York USA (1983) & DALY, B.B. “Woods Practical Guide to Fan Engineering” Published by Woods of Colchester Limited UK (1978) Page 65 © AMC Consultants Pty Ltd 2005 BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW 4.4.1 Entrance Shock losses occur at the entrance to any system due to the acceleration of air from zero velocity in the surrounding atmosphere to the velocity in the airway. Entrance Plain X = 0.9 Bell Mouth X = 0.05 Flanged X = 0.5 Notched X = 0.05 Note that the Notched entry approximates the Bell Mouth and apparently the vortex formed in the notch promotes a smooth flow into the airway. Conical X = 0.2 4.4.2 Outlet Losses Air exiting a system decelerates from the airway velocity to zero velocity in the atmosphere. The static pressure in the issuing air stream will be equal to the surrounding atmospheric pressure. If this is taken as a zero gauge pressure then the total pressure at the exit will be equal to the velocity pressure. To reduce this loss, the area of the outlet must be increased (ie the velocity is decreased) this is normally achieved with the use of a diffuser or evasè. The performance of a diffuser will vary with the inlet velocity pressure and the ratio of the outlet to inlet area, the centreline length and the angle of divergence. In an ideal diffuser the regain pressure would be equal to the change in velocity pressure and the loss in total pressure (shock loss) would be zero. In reality this will never occur. Outlets In all cases X = 1.0 and the velocity pressure is determined by the velocity in the plane of the exit area Plain Flanged A well-designed diffuser would have an outlet to inlet area ratio of 4:1 with an included angle of divergence between Diffused 8° and 11°. In practice the length required to regain pressure is excessive and generally the divergence angle is around 25°. As a rule of thumb if the length of the divergence is four times the diameter of the smaller airway, then the shock losses become negligible because the pressure regain of shock loss pressures are overcome by the frictional pressure losses. Page 66 © AMC Consultants Pty Ltd 2005 BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW 4.4.3 Elbows Circular Mitre Bend Rectangular Mitre Bend Elbows, bends and mitres are used to guide the change in direction of flow and restrict flow separation. The relative losses will depend upon the abruptness of the change in direction, Reynolds number (not discussed in these notes) and the wall roughness of the airway. Other considerations include geometrical shape i.e. circular or round, the angle of the bend and the radius ratio and the aspect ratio. Those of most importance in mines are mitre bends with curved bends having a lesser impact due primarily to their lengths such that shock losses are decreased to a point of insignificance compared to the frictional pressure losses. X = 1.15 X = 1.15 Mitre Bend other than 900 X = X90 x 90 Smooth Bend X = 0.25 x 2 m2 a0.5 902 Three Piece Bend 900 D R/D X 0.5 0.425 1.0 0.350 1.5 0.315 2.0 0.315 2.5 0.325 3.0 0.380 R Consider the case of a typical mine curve of radius 20 metres with a height of 4.5 metres and a width of 4.5 metres with a friction factor “k” of 0.015 Ns2m-4. The angle of the curve is 90° and the airflow is 200 m3/s The calculation for “X” in a smooth bend is described by McElroy (1935) X Where m is the radius ratio = = = a is the aspect ratio = = = Therefore X Centre line radius Width of the Airway 4.5 2 2.25 Height of the Airway Width of the Airway 4.5 4.5 1.0 90 90 2 0.60 2 m a 0 .5 2 90 0 .6 2 2.25 1.0 0.5 = 1.2 The velocity is 200/(4.5 x 4.5) = 9.87 (m/s) Therefore PSHOCK = 1.2 x (0.5 x 1.2 x 9.872) = 70Pa Page 67 © AMC Consultants Pty Ltd 2005 (((Q/Qb).5 Junctions and Splitting These losses depend upon 1. 2. To keep expansion losses to a minimum the change should take place over the longest available distance and the downstream duct must be at least 4 times the larger diameter to ensure full recovery of the pressure.5(Q / Qb)2) + ((Q / Qb)-1)2 + Xb Page 68 © AMC Consultants Pty Ltd 2005 .3((tan /2)–0.67).333 [ 1 – (A2 / A1 )] Note: If the length of contraction is 4 x the smaller diameter then the shock losses are negligible Abrupt Contraction A1 X = 0.4. 4. the branch area ratio.5) + Xb X = 0. the ratio of the downstream to upstream velocity of air and therefore the quantity of airflow.4 Expansions and Contractions Gradual Contraction A1 A2 Abrupt Expansion A1 X = ( 1 – [A1 / A2 ])2 Gradual Expansion A1 A2 X = 0.5 ((Q / Qb)-1)2.4. Junction Straight Branch X = 3.5 [ 1 – (A2 / A1 )] A2 A2 Note: Expansions are complicated by the regain in static pressure over the length of the change.BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW 4.((1/Cc)-1))2 Deflected branch Splitting Straight Branch X = (-0. 4. the geometrical aspect of each airway.5((Q / Qb)-1)2 v1 Ideal Junction = 300 & v1 = v 2 Deflected branch v2 X = (0. 3. the branching angle. Dh . “Mine Ventilation and Air-conditioning” Page 69 © AMC Consultants Pty Ltd 2005 .BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW In the deflected branch of a split the pressure loss can be reduced considerably by using a converging taper between the main and the deflected branch. The recommended procedure for development of a junction is to join the upstream main branch with the down stream main by means of a tapered convergence of at least two upstream diameters long made to join the branch to the taper at an angle of 30° with the upstream main branch.Mine ventilation computer programmes may include preset values for shock losses. One important aspect of junctions is that the pressure loss may in fact be negative depending of the ratio of the branch flow to the total flow. This method is inadvertently applied when the results of pressure quantity surveys are used to “back calculate” the friction factor “k” because the pressure losses due to shock are included in the measurements. In the equations for splits and junctions the following applies: Q = Total Airflow Qb = Airflow in the branch being evaluated Xb = X for the deflected branch Cc = Coefficient of Contraction = Ac Ao And 4. The method is tedious and prone to error due to the many variables and is not really recommended for use. Some of these values have been taken from a text that used drive sizes of only 2.L. H.” 15 15 HARTMAN.0m and therefore are not applicable to all mines.67k C WARNING . It is then used to calculate a resistance for the Le and is then added to the resistance of the airway. This involves the addition of an increment to the friction factor “k” for each and every airway.5 Ac = Area of vena contractor Ao = Area of orifice Other Methods of Expressing the Shock Factor X Some attempt to increase the friction “k” as a method to allow for shock losses. Obviously this is fine for a duct system in a building but extremely difficult to achieve economically in an underground mine. The idea is to maintain a constant velocity in the main branch. These values are expressed as an equivalent length (Le) of the airway. 6. “Shock losses do not lend themselves to precise calculation because of the great range of variability in occurrence and because of a lack of understanding of their very nature. This is due to the transfer of momentum from one branch to the other. To differentiate between the actual length (L) the subscript e is added to indicate equivalent X Dh 4A length Le where Dh is the hydraulic diameter of the airway.0m x 2. Use of the equivalent-length method is probably the most useful method for mine ventilation because it can be calculated by equating the formulas for friction loss and shock loss. where the air flows from the surface to the lowest working Page 70 © AMC Consultants Pty Ltd 2005 . i.e. This is a term used to describe a combination of airways with different resistances where the air flows through each in turn.10 (Ns2/m8).6 Series Circuits When one airway is followed by another airway and both have their own physical characteristics. the airways are said to be in series.17 = 0.e. Calculate the pressure (P) required to cause a flow of 100 m3/s RT = R1 + R2 = 0. Airway B a resistance of 0..e.34 x (100)2 = 3400 (Pa) Many Australian mines utilise “series ventilation” circuits in their design. PT = PA + PB + PC It then follows that the total resistance of the system is the sum of the resistance of airway ‘A’ and airway ‘B’ and airway ‘C’. This becomes obvious when we refer to the sketch below where the total quantity of air flowing through the system is equal to the quantity of air in ‘A’. RT = RA + RB + RC This relationship is usually expressed as RT R1 R 2 .17 (Ns2/m8). QT = QA = QB = QC Airway A Airway B Airway C The total pressure loss in the system is the sum of the pressure losses in airway ‘A’.34 (Ns2/m8) and PT = RT x QT2 = 0.R n Where Example R = Resistance (Ns2/m8) Referring to the sketch above Airway A has a resistance of 0.07 (Ns2/m8) and Airway C a resistance of 0.BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW 4. i.07 + 0.. i. This is a common practice in steeply dipping narrow vein mines.10 + 0. which is equal to the quantity of air flowing in ‘B’ and likewise in airway ‘C’.. airway ‘B’ and airway ‘C’. .e.e. Therefore the pressure loss across airway A is equal to the pressure loss across airway B and equal to the pressure loss across the system X-Y i.BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW level before being exhausted from the mine. PT = PA = PB Airway A X Airway B Common points Y The total quantity flowing in the system is equal to the quantity of air flowing in airway A and airway B. Page 71 © AMC Consultants Pty Ltd 2005 . Recirculate implies that the airs goes around in circles and never leaves the circuit. 4. QT = QA + QB and the overall resistance (RT) is given by the formula 1 RT 1 R1 1 R2 . This “reuse” of air is often confused when people talk of recirculation of air when in fact they mean re-used (series) air. 1 Rn Where R = Resistance (Ns2/m8) Parallel systems exist in mines when air is exhausted on a number of levels. i. In the sketch to the right the points X and Y are common to both airways...7 Parallel Airway Circuits Airways are in parallel when they have a common inlet and common outlet. Lets now consider the same sketch a new airway that connects Airway A with Airway B. Calculate the pressure required to cause a flow of 50 m3/s through each airway. In order to understand the complexity of network problems the following definitions apply 1. Every airway must be included once in any group of meshes. Page 72 © AMC Consultants Pty Ltd 2005 . Calculate the overall resistance (RT) 1 RT 1 RT 1 RA 1 1 RB 1 0. A mesh is any closed path that traverses the network.15 = 0.BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW EXAMPLE Three identical airways are developed in parallel.15 (Ns2/m8).0167 x 1502 = 375 Pa 4.15 0.0167 (Ns2/m4) Calculate the pressure PT = RT x QT2 = 0. A network is any complex ventilation circuit. Calculate the total airflow QT = QA + QB + QC QT = 50 + 50 + 50 = 150 m3/s. Airway A New airway Airway B After examining this sketch you will come to the conclusion It is not possible to reduce this circuit to a series or parallel circuit and an analytical or reiterative technique is required. A Junction is where two or more airways join 3.15 1 RC 1 0. 2. Complex circuits or networks rely on the use of computers to undertake the numerous calculations required. Each airway has a resistance of 0. A branch is any airway between two junctions 4.8 Complex Circuit (Networks) With reference to the sketch for parallel airways it is noted that whilst Airway A and Airway B are in parallel they are also in series with the airway preceding point X and the airway following point Y. P Q 2 R where R was the Pressure We have seen and discussed the relationship of pressure (P). Kirchoff’s 1st Law The algebraic sum of all air quantities at a junction is zero Kirchoff’s 2nd Law The algebraic sum of all pressure losses in a closed mesh is zero. Once this 0 calculation is complete we can determine the pressure necessary to cause various quantities of air to flow.e. The results of these calculations are then shown graphically to produce the “System Resistance Characteristic”. Page 73 © AMC Consultants Pty Ltd 2005 . Kirchoff’s electrical laws can be restated and will apply. quantity (Q) and resistance (R) in the previous sections. . For example the ventilation equation ( P RQ 2 ) shows the relationship between pressure (P) and quantity (Q) is High Resistance Low Resistance resistance for a particular system with a specific pressure and quantity.BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW 5. is determined by summation of all the Quantity appropriate resistance values. The “system”) resistance in any duct or mine. 4.9 System Resistance Curve proportional i. A system with a high resistance will be represented by a curve that is steeper than a system with a lower resistance. Comprehensive discussion of Network analysis can be found in Chapter 8 of “Environmental Engineering in South African Mines”. However if a fan is included in the mesh then the algebraic sum of all pressure losses is equal to the pressure provided by the fan. 3982 × 250 × 15 2 1.2 1 .10.2 = 1425 Pa 1. Equations used: 1) P= kCLQ 2 A3 × s 2) A D2 4 (m 2 ) 3) C = D (m) Determine area (A) and circumference (C) for ducts Diameter (mm) 1.400 Diameter P= × P= 0.5394 3 × 4.200 1.2 kg/m3.0035 × 3.10.2 1.10.1310 3 × 1 .15 = 1365 Pa 1.400 C (m) 3.5394 3 × 1.0035 P= kCLQ 2 A3 3 × s 1.25 kg/m3 0.2 1.400 Diameter P= 0.2 [A] Repeat 4.2 1.0035 × 3.1310 1.7699 × 250 × 25 2 1. State the k factors used and assume the density of air is 1.BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW 4.0035 × 3.15 = 632 Pa 1 .0035 × 4.2 = 659 Pa 1 .10.400 Diameter 1.200 Diameter P= 0.7699 × 250 × 25 2 1.15 kg/m3 and 1.15 = 227 Pa 1 .400 Diameter P= 0.2 [Q] 4.7699 4.0035 × 3.1310 3 × 1.3982 × 250 × 15 2 1.2 1.200 Diameter P= 0.1310 3 3 1.2 Page 74 © AMC Consultants Pty Ltd 2005 .2 = 237 Pa 1 .10 Assignments 4.0035 × 4.2 1.2 1.3982 × 250 × 25 2 1.3982 × 250 × 25 2 1.200 Diameter 1.0035 × 4.2 1 .25 = 534 Pa 1 .0035 × 3.1310 0.200 mm & 1.2 = 513 Pa 1 .1 [A] Calculate the pressure loss in 250 m of a rigid plastic duct with diameter of 1.1 but assume an air density of 1.10.5394 Calculate pressure assuming k = 0.3982 A (m3) 1.7699 × 250 × 15 2 1.200 Diameter P= × 1.400 mm for air quantities of 15 m3/s & 25 m3/s.1 [Q] 4.5394 3 × P= 0.0035 × 4.15 = 492 Pa 1 .200 Diameter 1.7699 × 250 × 15 2 1.7699 × 250 × 15 2 1.1310 0.5394 3 × P= × 1. 10.2 = 2647 Pa 1.400 Diameter P= 0.5 2 27.4 [A] Calculate the pressure loss for air quantities of 13.012 × 21.2 1.7699 × 250 × 25 2 1.012 × 21.10.0035 × 4.2 1 .0m wide.7 Pa P= 0.0065 × 4.25 = 1484 Pa 1. 55 m3/s & 165 m3/s in a decline 350 m long 5.2 = 441 Pa 1 .2 1 .2 1.0 A (m3) 27.5 3 kCLQ 2 A3 × s P= × 1 .0 × 350 × 55 2 27.400 Diameter P= 0.400 Diameter P= 0.2 1.2 = 0.2 = 1225 Pa 1 .200 Diameter 1.5 m3/s.5394 3 × 1 .3982 × 250 × 15 2 1. Determine area (A) and circumference (C) for drive Height (m) 5.0035 × 3.3982 × 250 × 25 2 1.2 1 .2 1.10.7699 × 250 × 25 2 1. State the k factor used and assume the density of air is 1.4 [Q] 4.2 1.0 × 350 × 13.5394 3 × 4.200 Diameter 1.1310 3 × 1.5 Calculate pressure assuming k = 0.012 P= 0.0065 × 3.2 kg/m3.3982 × 250 × 25 2 1.5394 3 × 1. Calculate pressure assuming k = 0.10.1310 3 × 1 .7699 × 250 × 15 2 1.2 = 953 Pa 1 .BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW 1.2 P= 0.1 using flexible ducting.3 [A] Repeat 4.0035 × 4.5394 3 × 4.0065 × 3.5m high and 5.3982 × 250 × 15 2 1.8 Pa Page 75 © AMC Consultants Pty Ltd 2005 .2 = 12.25 = 247 Pa 1 .0065 × 4.5 3 × 1 .10.5 Width (m) 5.3 [Q] 4.1310 0.200 Diameter P= 0.400 Diameter P= × P= 0.0 C (m) 21.25 = 686 Pa 1 .0065 P= kCLQ 2 A3 3 × s 1. 10.5 3 × 1 .5664 250 12.2 kg/m3 A (m3) 12.5664 × 350 × 60 2 12.2 1 .2 = 36 Pa P= 0.5 [Q] 4. 2 1. Assumptions: K Factor = 0. 2 1.0 Q A C (m) 12. 75m3/s 125 m3/s. 190 m3/s & 250 m3/s in a vertical raisebored shaft 350 m long and 4.5664 Determine area (A) and circumference (C) for raisebored shaft Diameter (m) 4.0m high and 5. 2 1 .0045 × 12.5 [A] Determine the pressure losses contributed by the shock in a 90 bend of a blasted rock airway 5.0045 × 12.5664 3 × = 156 Pa P= 0.5664 190 12. State your assumptions.5664 Calculate velocity v = v= v= v= v= 60 12.10.0045 × 12.5664 × 350 × 250 2 12.10.15 Determine area of drive = h x w = 5 x 5 = 25.5 [A] Calculate the velocity (m/s) and pressure loss (Pa) for air quantities of 60 m3/s.0045 Ns2/m4 Density of air 1.5664 × 350 × 190 2 12.BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW P= 0.2 1 . 125 m3/s.5664 3 × = 360 Pa P= × = 623 Pa 4.5664 125 12.0045 × 12.5664 = 4. Shock factor X for 90 rectangular bend = 1.5664 3 0.8 m/s = 9.0m wide for air quantities of 20 m3/s.2 1.10. Assume standard air density.5664 × 350 × 125 2 12.2 1 .0 × 350 × 165 2 27.9 m/s = 15.2 = 115 Pa 4.012 × 21.6 [Q] 4. 2 1.5664 3 1 .0m diameter.0 m2 Page 76 © AMC Consultants Pty Ltd 2005 .9 m/s P= kCLQ 2 A3 × × s Calculate pressure: P= 0.1 m/s = 19. 5 2 × 90 2 = 16.46 Pa = 6.0 Pa VP = VP = Calculate shock loss PSHOCK = XVP PSHOCK = 1. Shock factor X for 90 circular bend = X = m= a= X= 20 1.0 m/s = 5.1310 = 26.2 Pa = 17. Assume standard air density.4 Pa = 15.6 2 Calculate velocity in drive: v = v= 30 1.0 75 25.7 [A] Determine the pressure losses contributed by the shock in a 90 smooth bend with a centre line radius of 15 m in a 1. 8 2 2 1 . 0 2 2 = 0.4 PSHOCK = 1.25 Pa 4.8 m/s = 3.0 m/s VP = v2 (Pa) 2 Calculate velocity pressure VP = 1.25 m a 2 0 .2m diameter flexible duct with an air quantity of m3/s.5 m/s Page 77 © AMC Consultants Pty Ltd 2005 . 2 × 0 .2 0.1310 m2 Determine area of duct = r2 = Q A × 0 .15 × 15 = 0.15 × 0.0 125 25.15 × 5.2 16.0 Q A = 0. 0 2 2 1 .6667 = 1 0.4 PSHOCK = 1.25 × 90 2 90 2 1 . 2 × 5.0009 = 1.5 = 0.BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Calculate velocity in drive: v = v= v= v= 20 25.7 [Q] 4. 2 × 3.6667 210.4 Pa = 5.10.10.2 1 . 0463 Pa 36 2 Therefore PSHOCK = 0.25)2 = 0.4340 Pa Velocity in A1 = 100 1.5 (1 – (9/36) = 0.7778 2 = 2.(A2/A1)) A1 = 6 x 6 = 36 m2 A2 = 3 x 3 = 9 m2 X = 0.8 [A] Determine the equivalent airway length of shock losses in a 90 bend in a blasted rock airway 5.0m high and 3.0 m/s.10.0 m/s. 7. 5. 50 m3/s & 100 m3/s.5 (1 .5 m/s.375 Pressure loss occurs in the entry airway Velocity in A1 = 1.0m high and 5.0463 Pa Velocity in A1 = 1.2 × 2.2 × 26.1574 Pa 36 2 Therefore PSHOCK = 0.2778 m/s and VP = = 0.10 [Q] 4.10.0 m/s.67k Le = 1.7778 m/s and VP = = 4.1574 = 0.0m wide for velocities of 1.5m/s & 10.0.0009 × 422 = 0. 50 m3/s & 100 m3/s.8m and will be the same irrespective of flow.3889 m/s and VP = = 1.5625 Page 78 © AMC Consultants Pty Ltd 2005 .2 × 1.0m high and 6.6296 = 1.25) = 0.0.0m wide for air quantities of 10 m3/s.10.0m wide for air quantities of 10 m3/s.375 × 4.0m high and 6.0m high and 3.0m wide to an airway 3. Assume standard air density. Abrupt Expansion X= (1.5 (1.9 [Q] 4.7361 Pa 4.10.375 × 1.6296 Pa 36 2 Therefore PSHOCK = 0.3889 2 50 = 1.BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Calculate velocity pressure VP = VP = v2 (Pa) 2 1.10.67 × 0.2 × 0. Assume standard air density. 2.012 71.9 [A] Determine the pressure loss when an airway reduces abruptly in size from 6.10 [A] Determine the pressure loss when an airway increases abruptly in size from 6.8 [Q] 4.0m wide to an airway 3. 4. Abrupt Contraction X= 0.(A1/A2))2 A1 = 3 x 3 = 9 m2 A2 = 6 x 6 = 36 m2 X = (1 – (9/36))2 = (1 .375 × 0.2778 2 10 = 0.38 Pa 4. Assume standard air density Le = XDh 6.5 2 2 = 422 Pa Calculate shock loss PSHOCK = XVP PSHOCK = 0.10.15 × 5 6. 012 × 16 × 25 16 3 Airway A Area = 27.0739 Pa 9 2 Therefore PSHOCK = 0.0m wide A B C Airway C Raisebore shaft 125m long.10.4167 Pa Velocity in A1 = 100 1. R = kCL A3 Ns2/m8 0.11 [A] 1) Assume friction factor 0.5185 = 10. assumptions for Atkinsons factors.0m wide Airway B 100m long.5185 Pa 9 2 Therefore PSHOCK = 0.7407 Velocity in A1 = = 0.012 × 17 × 100 18 3 0.BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Pressure loss occurs in the entry airway Velocity in A1 = 10 1. 5.0m wide Airway C 25m long.5556 2 = 5.0035 = 0.012 Ns2/m4 for rock walled air way Determine the resistance for each airway.2 × 5.0m high x 4.5556 m/s and VP = = 18.4167 Pa 50 1.0m wide Airway B Level Development 200m long.11112 = 1.7407 Pa 9 2 Therefore PSHOCK = 0.0m wide ii) Airflow 100 m3/s Airway A Decline 750m long. 4.1111 m/s and VP = = 0.1111 m/s and VP = = 74.5m high x 5.11112 = 11.0739 = 41. 5.0006 = 0. 4. i) State your Airflow 30 m3/s C A B Airway A 50m long.5 m2 Circumference = 21 m and R A = Ns2/m8 Airway B Area = 18 m2 Circumference = 17 m and R B = Ns2/m8 Airway C Area = 16 m2 Circumference = 16 m and R A = = 0.6666 Pa 4.5625 × 0.5m high x 5.5625 × 74.11 [Q] Calculate the frictional pressure loss for the following systems.5m high x 4.0012 Page 79 © AMC Consultants Pty Ltd 2005 .5m high x 4. 4.0m diameter 4.5 3 0.2 × 1. Assume standard air density. 4.2 × 11.10.5625 × 18.012 × 21× 50 27. 0035 + 0.0045 Ns2/m4 for raise bored airway Determine the resistance for each airway.56 × 125 12.012 × 17 × 200 18 3 = 0.012 × 21× 750 27.56 m2 Circumference = 12. 4. Determine the airflow through each section of the mine 2.BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW Ns2/m8 RT = RA+RB+RC = 0.0012 = 0. Calculate the pressure drop necessary to achieve 100m3/s.1 Ns2/m8 1.5 2 3 = 0.0091 Ns2/m8 Airway B Area = 18 m Circumference = 17 m and RB = 0.56 m and RA = 0.3 Ns2/m8 100 m3/s 0.0036 Ns2/m8 RT = RA+RB+RC = 0.0053 Ns2/m8 Calculate frictional pressure loss P = RQ2 = 0.0053 x 302 = 5 Pa 2) Assume friction factor 0.012 Ns2/m4 for rock walled air way and 0.10.0070 Ns2/m8 Airway C Area = 12.0045 × 12.0006 + 0.0036 = 0.0197 Ns2/m8 Calculate frictional pressure loss P = RQ2 = 0.56 3 = 0. Calculate the resistance 1 RT = 1 R SECTION1 + 1 R SECTION2 Page 80 © AMC Consultants Pty Ltd 2005 . R = kCL A3 Ns2/m8 Airway A Area = 27.0197 x 1002 = 197 Pa 4.12 [Q] Two sections of a mine are depicted in the following figure Section 1 Section 2 0.5 m2 Circumference = 21 m and RA = 0.10.0070 + 0.0091 + 0.12 [A] Section 1 is in parallel with section two and the pressure is the same across both sections of the mine. The concrete will be applied to a thickness of 100mm.0402 × 100 2 =1.6 m3/s Similarly the airflow in Section 2 is 0.75 = 36.0402 x 1002 = 0. R = R= kCL A 3 4. 3 + 1 0.14 [Q] The figure below represents the workings of an underground mine.1 x Q12 Q2 = 63.13 [Q] The raise bored airway for a mine has become unstable and must be sprayed with shotcrete to prevent it collapsing. R = R= 0.42 × 200 7.13 [A] Ns2/m8 Diameter = 3. Assume the same pressure drop.0402 x 1002 = 402 Pa 4.3 x Q12 0.0174 Ns2/m8 Ns2/m8 Diameter = 3.8257 + 3.5 = 76.0174 × 90 2 0.0402 x 1002 = 0.4 m3/s.100) = 3.9880 RT 1 = 4.0m Determine the new resistance. Pressure is P = RQ2 = 0.9880 = 0. 1 2 = 1.0045 × 9.04 3 kCL A3 = 0.10. Determine the existing resistance.0045 × 10.05 × 200 8.1623 =4.3 Q12 = Q1 = 13387 .0240 Q 2 = 5872.0402 Ns2/m8 As P = RQ 2 and since P is constant RTQT2 = R1Q12 The airflow in Section 1 0.2m diameter and 200 m in length.3387. The shaft is 3.2 – (2 x 0. Page 81 © AMC Consultants Pty Ltd 2005 .75 0 .07 3 = 0.BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW 1 RT = 1 0.10.0240 Ns2/m8 Since pressure is constant R1Q12 = R2Q22 Q22 = 0.10. What will the airflow be once the shotecreting has been completed?.6 m3/s 4. The current airflow is 90 m3/s.2m 0. 0m diam. It is also necessary to provide equal air to each section of the mine. Area 2.14 [A] kCL A3 Determine the resistance of the decline.010 Ns2/m8 120 m3/s 240 m3/s It is proposed to develop a new shaft (FE) and increase the mine airflow from 125 m3/s up to 240 m3/s.0315 – 0.C R=0.012 Ns2/m4 R AB = 0.0215 + 0. 4.0165 Ns2/m8 Calculate the diameter Area = Area = D2 4 and Circumference = D kCL A3 R= k DL D2 4 3 Substituting in R = Solving for D Page 82 © AMC Consultants Pty Ltd 2005 .10.0215 Ns2/m8 Determine the resistance of A.0150 = 0. 200m long Decline 5m x 5m gradient 1:7 E B 120 m3/s Area 1= 0.0100 = 0.B.BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW A F Proposed Shaft D Shaft 4.012 × 20 × 1400 25 3 = 0. What diameter should the new shaft be? Assume the new shaft can be raisebored.0315 Ns2/m8 For an equal split the resistance in both sections must be equal RAB Area 2 C = RFE Area 1 C Therefore RFE = RAB Area 2 C – RArea 1 =0. R = Ns2/m8 At 1:7 the decline will be 200 x 7 = 1.400 m long Area = 25 m2 an Circumference = 20 m.015 Ns2/m8 C Area 2 = 0. Assume a friction factor of the decline = 0. 01651/3 )3/5(0.0045 D = 3.BASIC MINE VENTILATION FUNDAMENTALS OF AIRFLOW D =(4/R1/3 )3/5(k L)1/5 D =(4 / 0.2339m diameter 200)1/5 Page 83 © AMC Consultants Pty Ltd 2005 . but this requires a switch to be held down. with an absolute accuracy of 0. Electronic instruments will generally only provide spot readings. the airway cross-sectional area and air velocity need to be known. or better. Some can integrate. To measure airflow.” Robert G. making them ideally suited to traversing measurement techniques.2 m/s should be measured with another technique such as a smoke tube or hot wire anemometer. This can often be difficult to accomplish when the instrument is mounted on a pole. There are a large variety of air velocity measuring instruments. The mechanical instruments are preferred to the electronic ones for the following reasons: They automatically engage their clutch to commence measurement about five seconds after the mechanical start lever is depressed.BASIC MINE VENTILATION MEASURING AIRFLOW “Reason. however the following are most applicable to mining requirements: Vane Anemometer Hot Wire Anemometer Velometer Smoke Tube 5. Observation and Experience – the Holy Trinity of Science. they can integrate velocity readings over a fixed time period (usually one minute). 5 MEASURING AIRFLOW Airflow is measured in units of cubic metres per second (m3/s). Page 84 © AMC Consultants Pty Ltd 2005 .2 to 25 m/s. Ingersoll (1833-99) US Lawyer and Agnostic. Mechanical anemometers are delicate instruments and must be treated with care. The impeller rotational speed is converted into an air velocity reading using either electronic or mechanical means. They seem to also be more reliable and robust than their electronic counterparts. When they are fitted with a timing mechanism. with accuracy sufficient for a primary ventilation survey. Most anemometers used in mine ventilation survey work are capable of measuring velocities in the range of 0. The Gods. Air velocities below 0. Traversing is the fastest way of averaging air velocity over an airway cross-sectional area. Mechanical instruments are usually smaller and easier to carry. Mechanical anemometers (particularly the Lambrecht 1406a) are used in the majority of Australian mines.1 Vane Anemometer The instrument consists simply of a light impeller that rotates at a speed dependent on flow rate. They are ideally suited to conducting primary ventilation surveys and for routine determination of air velocity. Recalibration can be organised through the CSIRO or the supplier and should be undertaken at least annually. They should always be transported in the instrument case.5 m/s. This gives the operator sufficient time to move the instrument away from the body to the position where the traverse will be commenced. using smoke tubes.1 m/s to 0. This instrument provides fast. accurate measurements of velocities down to about 0. A port in the side of the instrument casing is connected to the passage. the wire is maintained at a constant temperature.5 m/s and a measurement distance of about 5m is usually therefore appropriate. The smoke is released in the centre of the airway about an arm's length upstream of the first mark.3 Velometer The velometer is a mechanical instrument that consists simply of a hinged vane that swings in a rectangular passage. Hot wire anemometers are generally not designed for use in the traversing measurement technique. They are suitable for taking spot measurements and most instruments have the facility to electronically average a number of spot readings. 5. then multiplied by a correction factor (typically 0. In the most popular type of instrument. The distance that the smoke travelled divided by the time taken. In hot. It is well suited to routine work such as determining face velocities in secondary ventilation surveys. a handful of fine dry dust or. Smoke tubes are used for velocities of less than 0. The distance should be that which the smoke travels in about 30 seconds (the smoke cloud usually dissipates after this period of time).BASIC MINE VENTILATION MEASURING AIRFLOW 5.2 m/s. Smoke tubes can also be used to trace air leakage (e. 5. into draw-points) and to help visualise the flow distribution. Before making a velocity measurement. The vane is connected directly to a velocity indication scale. Page 85 © AMC Consultants Pty Ltd 2005 . cigarette smoke! Measurements are taken by marking out a fixed distance in a drive with two paint lines on the roadway. The instrument contains a second internal hot wire to provide compensation for changes in air temperature. Smoke tubes give superior results to other less satisfactory improvised alternatives such as spray paint. It is always a good idea to check the flow distribution in the airway before commencing a smoke tube measurement. it is important that the flow distribution and direction be checked first.g.05 m/s). Two observers are required to determine the time interval between when the centre of the smoke cloud passes the first and second mark. When the instrument is held in an airstream.2 Hot Wire Anemometer The hot wire anemometer consists of an electrically heated wire at the end of an extendible wand.4 Smoke Tube A smoke tube consists of a glass tube (similar to a gas detector tube) that emits a highly visible smoke when air is aspirated through it via a rubber bulb. The amount of current required to do this is related to the speed of the air.8) calculates the velocity of the air. Pitot type tubes can be attached to the port with hosing to enable velocity to be checked in ducts. Velometers are not widely used in Australian mines. Hot wire anemometers are very useful for accurately measuring low air velocities (down to about 0. They are generally not directionally sensitive. The correction factor allows for the effects of smoke dispersal and the fact that the velocity in the centre of the drive is usually higher than the average velocity. the magnitude and even direction at the backs may be different to that on the floor. airflow through the port deflects the vane against spring pressure. inclined airways with low velocities. It must be read while being held by the observer and care must be taken to hold the instrument sufficiently far from the observer to avoid interference with the reading. The velometer is directionally sensitive and can only be used for spot surveys. 5% error in the velocity). A pitot static tube is used to determine pressure at a point. c) The tube diameter should not exceed 15 mm. The pitot-static tube can be used to measure static. The pitot static tube can be used successfully without the need for corrections given if: a) The head is aligned to the direction of airflow within 15 (2. Page 86 © AMC Consultants Pty Ltd 2005 . d) The velocity should be between 3m/s and 70m/s. A variety of designs have been developed with advantages between the different designs generally applicable to research work.BASIC MINE VENTILATION MEASURING AIRFLOW 5. b) The tube diameter must not exceed 1/25 the duct diameter in circular ducts and 1/20 the length of the smallest side in a rectangular duct.5 Pitot-Static Tube The Pitot-static tube (often referred to as the Pitot Tube) consists of two concentric "L" shaped tubes. total and velocity pressure when connected to a manometer. Air Velocity Measurement Instruments Instrument Vane Anemometer Hot Wire Anemometer Velometer Smoke Tube Pitot-Static Tube Velocity Range (m/s) 0. Enables air flow distribution to be "seen". Method not accurate enough for ventilation surveys. velocities can be measured to within 1% for velocities above 5 m/s.05 .2 . etc).5 5 – 50 Comments Versatile and accurate . a pitot-static tube would be used for fan testing and flow measurement in secondary ventilation ducts. Typically. The most useful length for many mines is 1. a vane anemometer. the measurement site should be located at least six drive diameters downstream and a minimum of three drive diameters upstream of any disturbing influence (bend. Summary .2 . Mechanical type is preferred.0. good measurement technique and steady flow conditions. This is will be an area in a drive that is: as straight as possible.25 * 0. they are not used for surveys in underground drives. In many cases this will mean taking extra measurements at site that better fit the selection criteria.15 0. Of the above instruments. * Instruments capable of reading up to 50 m/s are available. and a compromise is necessary.05 . The accuracy below 5 m/s is limited by the inability of most manometers to resolve very low pressures (less than 10 Pa). As a rule of thumb. routine spot air velocity measurement.high velocity measurement instrument.BASIC MINE VENTILATION MEASURING AIRFLOW With an accurate manometer. but not generally required for mine ventilation work. 5. of uniform shape and size and.5m.the most useful ventilation instrument – particularly for ventilation surveys. They are most useful for the measurement of the higher air velocities often found in ducts. smoke tube set and pitot-static tube are considered essential for any underground mine. This is often not possible in an underground operation. Good for accurate spot measurement of low velocities Useful for quick. Because Pitot-static tubes are essentially a medium . unobstructed.15 0.6 Selection of Measurement Site The ideal airflow-measuring site will have a ‘smooth’ or ‘undisturbed’ airflow distribution pattern. Page 87 © AMC Consultants Pty Ltd 2005 . obstruction. Cumbersome method to use Best instrument for measuring airflow in ducts. It is very important to note that in trackless mining.8 Traverse Velocity Measurement The traverse method is the quickest way to determine air velocity with sufficient accuracy for a ventilation survey.e. the ventilation station cross-sectional areas will change over time. (m) E = sum of the even offsets. and four-times the sum of the even offsets. 5. “The area enclosed by a curvilinear figure divided into an even number of strips of equal width is equal to onethird of the width of the strip. Page 88 © AMC Consultants Pty Ltd 2005 . (m) For example X A 3 2O 4E In this case Area X 3 O1 O7 2 O3 O5 4 O2 O4 O6 Note that the area is dived into an even number of sections i. it was found that over about 10 years. This is mainly due to extra road base material being applied. an odd number of offsets are measured. (m) O = sum of the remaining odd offsets. twice the sum of the remaining offsets. An integrating anemometer is required for this technique and the vane anemometer is generally the only instrument with this facility.7 Measuring the Airway Cross Sectional Area Several methods are available to determine ventilation station area. The station number and surveyed cross-sectional area should also be marked. In one mine. In recognition of this change ventilation stations maintained in main access declines should be remeasured at least every two years. the cross-sectional areas of a number of ventilation stations had decreased by over 10%. For primary ventilation surveys. permanent ventilation stations must be clearly marked with a paint line on the walls and backs.” Area Where X = distance between offsets. When conducting ventilation surveys that require a high level of accuracy the mine surveyors should be utilised to accurately determine the shape and area of all permanent ventilation stations. The most reliable method is to write this information on a steel or plastic tag that is attached to the wall using surveyor's putty.BASIC MINE VENTILATION MEASURING AIRFLOW 5. (m) A = sum of the first and last off sets. multiplied by the sum of the two extreme offsets. For temporary ventilation stations a tape measure is required to determine a minimum of five equally spaced heights (offsets). Using these measurements the area can be calculated using Simpson’s Rule. In order to ensure acceptable accuracy. Because of this.4 m/s (less than 0. It should be noted that for acceptable accuracy. The velocity for the area will be the average of all spot readings.9) therefore needs to be applied. A velocity reading is taken in the centre of each of these smaller areas. Multiple traverses readings will be undertaken until a minimum of two traverse sets agree to within ±5% of one another. When using an anemometer with a 60 second timer two readings will be required to complete one traverse – one for each side of the opening. It also requires smooth. traverse speed should be limited to less than 0.10 Single Spot Reading Method A simple. the airway cross-section is subdivided into a number of equal areas. 5. This method is useful for routine work. because the fastest velocity is usually found in the centre of the airway.9 Spot Reading Method For spot readings. Page 89 © AMC Consultants Pty Ltd 2005 . quick.2 m/s when measuring air velocities below 0. A correction factor (often between 0.BASIC MINE VENTILATION MEASURING AIRFLOW The principle of the traverse technique is to slowly traverse the anemometer across the airway at a uniform speed and in a pattern that ensures that the entire airway crosssectional area is evenly represented. or duct. and the velocity for the area will be the average of both of these readings). and rough form of spot reading is to take a single velocity measurement in the centre of a drive.8 and 0.75 m/s). it is not commonly used for routine work. the size of the squares should not be significantly larger than 1m x 1m. but also time-consuming method. unobstructed flow conditions in the airway. 5. This is a precise. but is not accurate enough for a primary ventilation survey. This reading will almost always over-estimate the average velocity. then the air does not replenish itself. or no drift from another shaft connects with it.67 revolutions per second (rps) (40 rpm) and 1. L. could not exist in the quantities required. airflow through the underground workings was generally provided only by natural draft. There is therefore a necessity for machines which enable the miners to breathe easily and carry on their work” Agricola “De Re Metallica” (1556) 6 UNDERSTANDING FANS In Chapter 3 we discussed the effect of natural ventilating pressure and how it can cause air to flow through mine workings. driven by large steam powered engines. The first evidence of mechanical methods for ventilating mine were described by Agricola in 1556 and involved methods such as human powered centrifugal fans. Samuel Davidson developed a forward curved multi bladed fan to handle hot air for the purpose of drying tealeaves from their Colombo plantations in Ceylon. causing them to breath with difficulty and some times they are even suffocated and burning lamps are also extinguished. If the shaft is very deep and no tunnel reaches to it. or when a tunnel is of great length and no shaft reaches it. J.H. It was not until the turn of the 20th century that fans were used extensively in mines. Typically.. One of the early makes of this type of fan was the double inlet Walker Indestructible16. (December 1986) Page 90 © AMC Consultants Pty Ltd 2005 .0 rps (60 rpm) and. 16 de la HARPE.W. between 240 inch (6. Airflow through the large mechanised mining operations of today. This requires mechanical energy input provided by fans. Although large centrifugal fans were in use in the early to mid 1850’s. JENNER. bellows connected to wooden conduits and shaft collar deflectors. In around 1900. In such a case it weighs heavily on the miners.BASIC MINE VENTILATION UNDERSTANDING FANS “I will now speak of ventilating machines. unless there was sufficient pressure difference to overcome the resistances in the circuit. The fan impeller was much smaller in diameter with forward curved blades designed to run at significantly higher speeds. The fan was called a Sirocco after the hot winds that blow across the Mediterranean from the coast of North Africa.0m) and 520 inch (13. “The History of Mine Fans in South Africa” The Journal of the Mine Ventilation Society of South Africa. now Sri Lanka.0m) diameter and rotating at very slow speeds between 0. these impellers (pictured opposite) were fitted with backward curved paddle blades. which divert winds into the mine workings. In a mixed flow fan the air enters parallel to the axis of the fan turns through an angle which may range from 30º to 90º The pressure rise is partially by direct blade action and partially by centrifugal action. This fan was installed around 1917 at on No.In an axial fan the air flows through the impeller parallel to and at a constant distance from the axis. Page 91 © AMC Consultants Pty Ltd 2005 . 4 Shaft Zinc Mine Broken Hill and had an airflow capacity of 45.000 cfm (21. the mechanical energy delivered to the fan is transformed into potential energy (pressure) and kinetic energy (velocity) by the fan. Mixed flow.BASIC MINE VENTILATION UNDERSTANDING FANS It was one of these new generation fans that are believed to be the first mechanical means of ventilation installed in Australia. 2. . The replacement was a larger Sirocco fan (pictured left). . This pressure is necessary to overcome the resistance of the particular duct or mine. The blade force is tangential causing the air to spin with the blades and the main pressure rise is attributed to the centrifugal force.0m3/s) and remained in operation at this location until it was replaced in 1921. The pressure rise is provided by the direct action of the blades. 6.0m) impeller designed to produce 195. In mining applications the main fan types are: 1. which was manufactured in Belfast Ireland by Davidson& Co.200 cfm (92m3/s) at 6 of inches water gauge (1495 Pa) when rotating at 244 rpm. This fan was fitted with a 119-inch (3. Axial-flow. Centrifugal or Radial-flow.e. .In centrifugal fans the air enters parallel to the axis of the fan turns through 90º and is discharged radially through the blades. 3.1 General Description of Fans A fan is a rotating machine in which air is continuously drawn in at one pressure and delivered at a higher pressure i. Ltd. Fans are named according to the type of impeller fitted into the casing. in which the fan is operating. The impeller is mounted on a shaft inside the housing. consisting of the hub and blades.BASIC MINE VENTILATION UNDERSTANDING FANS 6. Centrifugal Reproduced from Air Moving and Conditioning Association Inc. In addition. or casing. “AMCA Fan Application Manual” Page 92 © AMC Consultants Pty Ltd 2005 . There may also be guide vanes to control the direction of airflow through the fan.2 Fan Terminology The principal component of a fan is the impeller. the fan is generally equipped with an inlet cone and an outlet evasè to improve the flow characteristics of the fan. of the fan that is driven directly or indirectly by a motor. 3 Axial-Flow Fans Axial flow fans are divided into three categories 1. Tube axial .BASIC MINE VENTILATION UNDERSTANDING FANS Axial Reproduced from Air Moving and Conditioning Association Inc. Desk fan 2.The impeller is confined in a casing Page 93 © AMC Consultants Pty Ltd 2005 . “AMCA Fan Application Manual” 6.g.The impeller is not confined e. Free air . For a given overall diameter.BASIC MINE VENTILATION UNDERSTANDING FANS 3. The shape and pitch of the blades vary considerably in different designs. resulting in increased cost. rotating in a direction opposite to the first. obviously shorter blades and a larger hub indicates higher pressure and lower airflow. 6. The word centrifugal meaning ”moving or directed away from the centre”. the motor and the casing. high-pressure fans have a greater number of blades than low-pressure fans.4 Centrifugal or Radial-Flow fans When a stone attached to a string is swung in circles and then let go it will fly outwards. The impeller comprises two parts. The impeller of a centrifugal fan consists of a hollow “wheel”. The air leaving the axial-flow fan usually has a rotary motion. Blades may be manufactured from flat plate or cast from alloy in an aerodynamic shape. can also be fitted.3. The clearance between the blade tips and the casing must be kept small to prevent pressure loss.1 Construction of an Axial-Flow fan The principal components of an axial fan are the impeller. Generally speaking. or “swirl”. with a number of blades Page 94 © AMC Consultants Pty Ltd 2005 . Generally speaking the higher the solidity the higher the pressure. Vane axial . The hub to blade ratio is indicative of the performance of the fan. This calls for accurate machining of the casings and blades. long blades and a small diameter hub indicates high airflow and low pressure. the hub and the blades. In fact anything that revolves tends to move away from the centre of rotation with centrifugal force. Axial-flow fans are particularly suitable for mounting directly in ducts. A second impeller. This result in the swirl induced by the first set of blades being neutralised by the swirl imparted by the second set.Same as a tube axial except guide vanes are fitted inside the casing to reduce swirl The impeller may have two or more blades. This loss is reduced by the installation of vanes called guide vanes fitted to straighten the flow of air. Fans fitted with this type of additional impeller are known as contra-rotating fans 6. It is also possible that the blades are fixed or adjustable. The number of blades on an impeller may be expressed in terms of ‘solidity’ with 100% solidity the maximum number of blades for that particular design. This results in a loss of energy. “rotor” or “runner”. a certain amount of control of performance is provided by the installation of variable inlet guide vanes.4. As the pressure requirements increase. and can be arranged in three ways: Radially Forward-curved. the airflow volume decreases. the air between the blades is thrown outwards by centrifugal force and leaves the impeller at right angles to the axis. On some centrifugal fans. there are changes that cannot be predicted and are caused by dirty or worn fan blades. The power and fan efficiency is shown for each airflow point and similarly joined to form a curve. These changes can be predicted and incorporated into the design. and is then replaced by air that enters along the direction of the axis from either one side only.1 Construction of a Centrifugal Fan In practice the shapes of the blades differ considerably in different types of fans The performance of the fan depend upon the design of the blades and the design of the volute (scroll) which is the section of the fan casing along which the air flows after leaving the impeller. The air is guided by the shape of the fan casing to the fan outlet. However. It is the design of the volute that determines the amount of velocity pressure in the air after leaving the blades that will be converted into static pressure. or from both sides. or backward sloping. The blades are generally relatively short. Fan performance curves are supplied by fan manufacturers and show the predicted airflow volumes for a given pressure. Any variations of density along with blade pitch angle will result in a change to the characteristic. When the impeller rotates. It should be noted that these curves apply only for the particular fan and at a particular density of air. Pressure 0 Quantity Page 95 © AMC Consultants Pty Ltd 2005 . These points are obtained from tests where the actual fan performance is measured. A line joins these points in the form of a curve. or forward-sloping Backward-curved. 6. similar to the paddle wheel of old steamships. 6.5 The Fan Characteristic (Performance) Curve The performance of a fan is generally presented in the form of a graph on which is plotted the airflow quantity (Q) along the horizontal axis and the fan pressure (P) along the vertical axis.BASIC MINE VENTILATION UNDERSTANDING FANS around its circumference. when the fan is termed a “doubleinlet” fan. This curve is termed the fan characteristic curve. when the fan is termed a “single-inlet” fan. Some examples of fan curves are shown in the following figures. Fan performance curves are presented in many differing forms. Although only one of the curves shows the efficiency (for the pressure) drawn on the chart it is easily interpreted by calculation from the information provided. All curves show the fan shaft power expressed in different ways 3.BASIC MINE VENTILATION UNDERSTANDING FANS In order to make the correct selection people interpreting these curves should be aware of the following: 1. Two curves represent the total pressure performance whilst the other show static pressure performance. (this is discussed later in Section 6.14) Some examples of fan curves are provided below Page 96 © AMC Consultants Pty Ltd 2005 . 2.13 and Section 6. BASIC MINE VENTILATION UNDERSTANDING FANS Page 97 © AMC Consultants Pty Ltd 2005 . 0 24.0 36.0 38.BASIC MINE VENTILATION UNDERSTANDING FANS AL12-500 Ph: (08) 9455 4433 Fx: (08) 9455 1819 1800 x 1 fan Diameter: 1200 mm Speed: 1000 rpm (nominal) Power: 55 kW Single stage Axial Full bladed 80 75 1600 70 65 Pressure (Pa) 1200 60 55 1000 50 800 45 600 20.0 32.0 30.0 22.0 34.0 40 40.0 28.20 kg/m3 Page 98 © AMC Consultants Pty Ltd 2005 Absorbed power (kW) 1400 .0 Fan total pressure Absorbed power Air volume (m3/s) Density 1.0 26. BASIC MINE VENTILATION UNDERSTANDING FANS Page 99 © AMC Consultants Pty Ltd 2005 . number of blades. fan type. hub diameter. impeller diameter.2kg/m3 3500 Reference P'nW 2345 3000 Fan Static Pressure (Pa) 2500 Manufacturers Code for the fan type usually provides. MULGA HILL FAN COMPANY QWER 1250-2300-12 990 rpm 1.6 Interpreting Fan Performance Curves The correct interpretation of fan curves is essential to ensure that the fan selection will meet the requirements.BASIC MINE VENTILATION UNDERSTANDING FANS 6. fan Speed & air density Manufacturers reference number 2000 Fan performance sets Fan operating point AP = P x Q 70 60 50 40 1500 1000 500 Pressure sometimes given as Fan Total Pressure 20 80 100 30 120 0 0 700 600 20 40 60 10 140 160 180 200 Fan Shaft Power (kW) 500 400 300 200 100 0 0 20 40 60 10 80 20 100 120 140 160 180 30 70 Impeller blade pitch setting 60 Fan Shaft power at the 50 operating point 40 200 Volume (m 3/s) Page 100 © AMC Consultants Pty Ltd 2005 . both the fan characteristic and the system characteristic have a positive slope) this is opposed to the normal operation where the pressure increases as the quantity decreases. It may not be possible to increase the size of the motor because it must be small enough to fit inside the housing and retain the same centreline. The quantity and pressure points alter considerably Action to be taken Continued operation of a fan in stall may eventually cause damage to the fan and the blades may disintegrate. The fan vibrates excessively 2. At this point. This condition is known as 0 “hunting” or “stall”. causing excessive vibration. These vibrations may damage the fan if it is allowed to operate for any length of time. If a fan is operating in this stall zone. it should not be forgotten that mining by its very nature is dynamic. To remove the fan from this condition some air may be allowed to enter the system at a position close to the fan (ie short circuit the system) this will have the effect of reducing the overall system resistance). The fan makes unusual noises (whines because of increased pressure) 3. 6.8 Fan Performance Control Although fans are required for a particular duty. A fan designed and manufactured to operate at setting 40 does not mean that it can operate at settings above this point. In this case the fan would typically be fitted with a 300 kW electric motor and if the fan pitch angle were increased the potential for the fan to stall would be extremely high. Over the life of the mine. Input power amps show rapid oscillations or surging at a slower frequency (every couple of seconds) 4. the pressure and quantity become unstable and fluctuate Quantity wildly. but it can be assumed to occur above the highest pressure shown. This should only be a temporary solution until the cause of the stall is identified and rectified. the air tends to separate from the blade surfaces. It would be necessary to increase the size of the motor. This zone is usually not shown on manufacturers curves.7 Fan Stall A fan will “stall” if the resistance of the system is (or becomes) excessive and as this resistance curve becomes steeper the intersection point with the fan Un-stable portion of curve Stable portion of curve performance characteristic changes and moves to a point of higher pressure (lower quantity) on the fan characteristic. Some points to consider are: 1. Eventually. 6. This zone may be very noticeable in some fans and hardly noticeable in others. 2.e.BASIC MINE VENTILATION UNDERSTANDING FANS The example curve shown above represents an adjustable pitch axial flow fan. fans may be required to operate at a number of Page 101 © AMC Consultants Pty Ltd 2005 . Stall Zone Signs Pressure 1. both the fan pressure and airflow quantity increase simultaneously (i. D & E lie on the intersection of the fan curve and a number of parabolic system characteristics with the same origin. In this case the operating points D and E are potentially unstable and it would not be recommended to operate the fan with the damper set in this position. Points A. it will change the overall system characteristic by altering the resistance. inlet-box dampers. variable speed or varying the number of fans. C. Page 102 © AMC Consultants Pty Ltd 2005 . Point A would represent the damper wide open and the other points represent the damper at other settings up to point E fully closed (FC). This method is sometimes used to cause a fan to operate at a more efficient section of its performance characteristic. The fan will operate at different points on its characteristic without change to the pressure.2 Outlet Damper A fan outlet damper acts on the fan in the same way as a system damper i. at the cost of decreased airflow and some times increased power.e.BASIC MINE VENTILATION UNDERSTANDING FANS specific duties. B. 6. variable pitch. variable inlet vanes. In these cases efficiency may be improved but.1 System Damper Dampers (regulators) installed in fan ducts (mine openings) to act as throttling devices have the effect of altering the system resistance. Consider the graph to the left in the figure below.8. There is usually very little economic justification for the change and is not recommended as a control system. To cater for these changes. fans must have flexible characteristics. 6. quantity and power curves. These curves represent the combined system and damper at various settings of the outlet damper control. Some of the causes for differing fan duties include.8. Increased resistance increased airflow requirements change in air density power saving The output of a fan can be controlled by adjusting the system (mine resistance) or using outlet dampers. & E all lie on the negative section of the performance characteristics and the operation will be stable.8. Here again there is some evidence to suggest that IF significant swirl exists then the intersection points A.3 Inlet-Box Damper The performance of an inlet-box damper (IBD) is considered in two parts. Like the outlet damper the inlet-box damper is generally considered to be part of the system rather than part of the fan. D’. In essence the damper is considered to be part of the system rather than part of the fan. The first part is the pressure loss cause by the resistance of the damper. C. Again they have two components that caused by the resistance of the structure and that caused by the pre-swirl given to the air. D. Page 103 © AMC Consultants Pty Ltd 2005 . 6. There is some suggestion that because the intersection points A. B. D. B. C’. There is also some evidence that if the principle resistance is on the outlet side even without pre-swirl the operation will be stable. B’. Consider the point C (½ open). VIV’s provide the same effect on fan performance as the inlet-box damper because they are designed to create a pre-swirl to the air. 6. However. There is some evidence that outlet dampers can be evaluated in this way and IF the principle resistance is on the inlet side of the fan but it is not suitable if the principle resistance is on the outlet side of the fan. similar to the outlet damper. There is a caution when interpreting this graph.8. C. & E’ and in this case the points D’ & E’ lie on the positive part of the fan characteristic and therefore the operation is likely to be unstable. Obviously there are an infinite number of settings between fully open and fully closed. & E all lie on the negative section of the performance characteristics then the operation will be stable even when fully closed. This pre-swirl reduces the amount of work for the impeller therefore affecting the impeller output and resulting in a different performance characteristic.4 Variable Inlet Vanes Variable inlet vanes (VIV’s) are similar in appearance to a camera iris and is slightly superior to inlet damper control in respect of efficiency and stable operation. if the principle resistance is on the inlet side then the operating points should be considered as A’. In this case the vertical distance from the base line to C is the pressure loss in the system and the vertical distance C-C’ is the pressure loss caused by the outlet damper.BASIC MINE VENTILATION UNDERSTANDING FANS Reproduced from “Fan Engineering – Buffalo Forge Company Eighth Edition” It is possible to represent the various settings of the damper as fan characteristic curves similar to that shown to the right in the figure below. The second part is due to changes caused by the inlet-box damper to the swirl of the air onto the impeller. The performance of an inlet-box damper can be considered in the manner shown in the figure opposite. Because of this operating points are always considered to be points A. D. This is a very simple operation that can be undertaken automatically. The performance characteristic curves would be identical except that all devices to alter the speed must have some slip to transmit torque. & E and highly unlikely to operate in the unstable positive characteristic points D’ & E’. 6. A fan would normally be selected to operate a point A as this would be the most Page 104 © AMC Consultants Pty Ltd 2005 . The system is depicted by the curve drawn through points E. particularly given today’s technology of PLC’s. Exercising requires the vanes to be closed then again open to the desired setting. Reduction gearbox drives. Variable speed controllers Number Motor Speed of poles 120 Hz No of Poles in the motor (can only be an even number) Variable speed characteristics can easily be determined from the fan laws detailed in section 6. C. Maintenance of this component is usually very poor and most become seized at a particular setting.6 Variable Pitch The figure opposite shows the performance characteristic for a fan and the operation points with the blades set at different angles. 6. D. B. B.BASIC MINE VENTILATION UNDERSTANDING FANS VIV’s are always installed as part of the fan and very close to the impeller. The use of VIV’s in Australian mines is usually confined to primary centrifugal fans but their use with axial flow fans is common particularly in the deep mines of southern Africa. This component should be greased weekly and exercised daily. C.9.8. A & Z.8.5 Variable Speed Speed control can be achieved in a number of ways Changing drive pulley ratios. The nut is then again tightened to secure the blade in its new position. The Two Fans A One Fan B A’ Effect of NVP + NVP Pressure 0 . When two unlike fans are installed in series then the combined pressure generated at a given airflow quantity will be the sum of the pressures of the individual fans at that quantity.8. Altering the blade pitch is normally done by stopping the fan. Fan in series are generally well recognised as most auxiliary development fans are configured to operate in this manner and there are many instances where primary ventilation fans have two stages. D. On certain fans. NOTE that the NVP acts in the same way as a series fan with the exception that NVP can have a negative pressure that is subtracted form the fan pressure characteristic.BASIC MINE VENTILATION UNDERSTANDING FANS efficient use of power. this adjustment can be carried out by means of a single lever or series of linkages when the fan is in operation. C. 6. loosening the nut holding the blade to the hub and then turning the blade to the required pitch setting. & E. However it is possible to install unlike fans in series but this is the exception rather than the rule. In most cases fans installed in series are designed for that purpose. In the figure opposite one fan will operate in the system at B by adding an identical fan the combined operating point will be at A.7 Fans in Series If we assume that air is incompressible then the potential performance of two identical fans is obtained simply by multiplying by two the pressure at a particular quantity. Higher flow rates would be achieved at point Z and lower rates at points B. Fans are generally installed in series to overcome an increased system resistance or maintain a particular quantity. These are termed variablepitch in motion fans.NVP Quantity Page 105 © AMC Consultants Pty Ltd 2005 . only an increase in leakage along the length of the duct. In practice.8 Fans in Parallel The potential performance of two identical fans operating in parallel is obtained simply by multiplying by two the quantity at a particular pressure. The use of fans in parallel is not uncommon in mines and in fact many mine circulating large quantities use fans in parallel as it offers the opportunity for maintaining some airflow should one fan fail. the overall flow is increased with the installation of a second fan in series however. The important thing is to note is that both fans MUST operate at the same pressure. When unlike fans are installed in parallel they will provide different quantities of air but will operate at the same pressure. When combining parallel fan performance One Fan A’ A Two Fans B curves the only the quantities are added and the pressure will remain the same. When fans are selected to operate in parallel. it is essential to ensure they operate in the stable area of the combined characteristic.8. Some mine choose to install two or even three fans and use one as an insitu spare and only operated in an emergency when an operating fan fails. 6. In the figure opposite one fan will operate in the system at B by adding an identical fan the combined operating point will be at A. Page 106 © AMC Consultants Pty Ltd 2005 .BASIC MINE VENTILATION UNDERSTANDING FANS exception being contra rotating fans when the pressure can be three times that of each individual fan. in most auxiliary fan duct installations there will be little to no increase in flow discharged at the end of the duct. eventually destroying the impeller Fan 4 desired operating position Fan 3 Fan 2 Fan 1 6. The combined ‘Eck’ lines can be determined in the following manner. the stable portion of the fans is to the right of the curve ‘a-b’. The second unstable portion of the two-fan system is due to the unstable part of each fan and is shown as a dotted line. Usually the fan enters stall and never recovers. Operating two or more fans in parallel. The determination of this line will show the lower “maximum useful pressure” to ensure operation in the stable portion of the combined fan performance curve. Consider the combined curves for one.9 The ‘Eck’ Line When a fan enters the unstable part of its curve it will start to stall. For two fans. the curve for three fans in parallel (labelled 3 Fans) has three unstable portions: 17 ‘Eck’ .In recognition of the work undertaken by Professor Bruno Eck on this subject. T0 get to the desired position Fan 4 must pass through the dip in the curve. Page 107 © AMC Consultants Pty Ltd 2005 . Point ‘A’ on this curve is obtained by doubling the air quantity at point ‘a’ on the single fan curve. This portion is constructed by marking a point to the left of the combined curve at distance ‘a-c’ as measured for a single fan. For a single fan the unstable portion of the performance curve is shown as a dashed line and the fan can be operated at any point to the right of the dashed line. Finally. Other points on this unstable portion of the curve are constructed in the same manner to obtain the dotted line for two parallel fans.BASIC MINE VENTILATION UNDERSTANDING FANS The use of multiple fans in parallel may cause problems when starting. Hence for two fans in parallel. Fan manufacturers seldom show the positive slope side of the curve and it can be misleading. two and three identical fans in parallel shown in the figure below. As a precaution the fan manufacturer must be questioned specifically as to the possibility of having to pass through the dip on the stall side of the fan performance. This is because succeeding fans must start up against the pressure already being developed by the operating fan or fans. The first is due to the combination of the two fan curves and is shown as a bold black line. the combined curve (labelled 2 Fans) shows two unstable portions. will induce stalling at a lower operating pressure.8. The calculated unstable portion of the combined curve is known as the ‘Eck’ line17. Some fan performance curves have a decided dip in the performance and if the fan being started has to pass through this dip or the positive slope side of the performance characteristic then it will enter the “Stall” position and never recover. 500 Pa. 2. due to the combined P-Q curve for three fans. 6. 2000 b a c A a b Eck Lines (dotted) c Stable portion of the combined curve Pressure (Pa) 1000 X ce tan Y sis ce Re an t sis Re 1 Fan 0 10 20 30 40 Quantity (m3/s) 50 2 Fans 60 70 3 Fans 80 90 Diagrammatic only In the figure above. due to the unstable portion of a single fan. They vary in shape from rectangular to round and the included angle. The stable part of the curve lies to the right of the ‘Eck’ line. the third fan would run up to the system pressure by passing underneath the ‘Eck’ line. two system resistance curves are plotted. The diffuser may be fitted with an internal fairing.10 Fan Diffuser Fan diffusers ultimately cause a little extra airflow through the fan. the third fan would have to pass through the unstable part of the combined curve on the run up to the system pressure. In reality. Resistance X has a resistance higher than Resistance Y. and 3. this would not occur and the fan would stall.BASIC MINE VENTILATION UNDERSTANDING FANS 1. The best pressure regain is achieved on a diffuser without an inlet fairing. As shown in Section 2 system shock losses can be reduced by the installation of an effective diffuser at the discharge. and with an outlet to inlet area ratio of 4:1 and the optimum included angle between 8o and Page 108 © AMC Consultants Pty Ltd 2005 . If these fans were operated in parallel against Resistance Y. If these fans were operated in parallel against Resistance X. due to the unstable portion of two fans.8. the outlet to inlet ratio and the cross sectional shape affect the efficiency. In this case the probable maximum duty would be 65 m3/s at 1. Page 109 © AMC Consultants Pty Ltd 2005 . Fan performance testing is detailed in standards such as Australian Standard 2936 and British Standard 848 and is usually specified in fan tender documents as the measure of compliance. This is discussed more fully in “Woods Practical Guide to Fan Engineering” or “Fan Engineering” published by the Buffalo Forge Company. the following fan laws will apply. and if the size difference is great then it can be expected that the fan total pressure may be larger than that given by these laws (scale effect). The actual values of temperature. This is normally only of concern at pressures above 2.10 Measuring Fan Performance Performance testing is undertaken to determine the actual operating performance of fans particularly at time of installation for comparison with the manufacturer’s predicted performance.9 Fan Laws Fan performance curves are determined for a specific speed and density.2 kg/m3). Should the speed or density of the fan inlet air be altered. Change Quantity (Q) Density ( ) Speed (rpm) Diameter Q1 P1 P2 Q2 Q1 Q2 rpm1 rpm 2 Q1 Q2 2 D1 D2 3 Pressure (P) 1 2 P1 P2 1 2 rpm1 rpm 2 rpm1 rpm 2 1 P1 P2 3 D1 D2 D1 D2 1 2 Power (kW) Efficiency (%) kW1 kW2 1 kW1 kW2 kW1 kW2 5 = 2 = 2 = 2 When considering the diameter the fans must have the same geometric dimensions. Standard air is a definition of convenience that is widely adopted. Because of the length required for this optimum in practice this angle can be much larger (up to 25°) PV REGAINED = (PV INLET .5 kPa. 6. It is also possible that a change in density due to compression of the air will occur affecting the results from the use of these laws. Unless otherwise specified the density for a fan curve can be assumed as standard air (1.BASIC MINE VENTILATION UNDERSTANDING FANS 11°. pressure and moisture content are not important.PV OUTLET ) Where = Efficiency of the evasè (%) 6. The main objective of measurements is to accurately determine: 1. caused by differing temperature and pressure as well as airflow quantity caused by leakage into or out of the system. The installation of such components for site measurements is generally considered to be too costly and is seldom (if ever) used.1 Fan Total Pressure The fan total pressure (FTP) is equal to the total pressure at the fan outlet (TPO) minus the total pressure at the fan inlet (TPI). 6. After making an operational change to the fan to ensure the desired (predicted) result has been achieved. altering the speed.2 Fan Velocity Pressure The fan velocity pressure (FVP) is equal to the velocity pressure at the fan outlet (VPO).10. 2. exhausting. Prior to making an operational change to the fan (i. fan inlet airflow quantity 2. Aside from the regular three monthly intervals to comply with some mining legislation the measurement of fan performance is also undertaken: 1. Precision laboratory type testing cannot be carried out on site.e. in line. To determine if a measured decrease in system airflow quantity is due to system resistance or the operational performance of the fan. Page 110 © AMC Consultants Pty Ltd 2005 . For acceptance testing at time of purchase and commissioning. ducted outlet Measurements of fan performance are made to represent the actual airflow through the fan and must therefore be sited to ensure there is no change in the properties of the airflow between the measuring site and the fan inlet.). free outlet DIAPHRAGM FAN Free inlet. Fans are primarily categorised as pressure. fan pressure 3. or diaphragm mounted. ducted outlet INLINE FAN Ducted inlet. fan efficiency EXHAUST FAN Ducted inlet.10. FTP TPO TPI Equation 6-1 Fan Total Pressure 6. free outlet Fan Categories PRESSURE FAN Free inlet. 3. Measurements made to determine site performance must be agreed with the fan manufacturer at the time of the purchase order being placed. Such changes may include density. 4. changing a motor etc.BASIC MINE VENTILATION UNDERSTANDING FANS Standards tests are performed using standardised airways with devices fitted to straighten flow and alter the operating pressure. 5 duct diameters for each 12.10. a static pressure reading downstream of a pressure fan is equal to the Fan Static Pressure (minus the frictional pressure losses between the fan outlet and the measuring site).5 diameters from the fan outlet.3 Fan Static Pressure VPO Equation 6-2 Fan Velocity Pressure The fan static pressure (FSP) is equal to the FTP minus the fan velocity pressure. FSP 6. If it is necessary to measure downstream (fan discharge) this distance should be equal to the effective duct length (described in the figure opposite). From these measurements of pressure we can determine the Fan Pressures By definition in this case therefore By definition FTP = TPO – TPI TPI = 0 FTP = 2000 – 0 = 2000 Pa FVP = VPO ventilation From the equation for pressure TP = SP + VP then VPO = TPO .5 m/s and add 1 duct diameter for each additional 5. 25% Cutoff Blast Area Area Outlet Area Discharge Duct 6.SP0 = 2000 –1500 = 500 Pa = FVP and FSP = FTP – FVP = 2000 – 500 = 1500 Pa Therefore.0 m/s Example: 25 m/s = 5 duct diameters. If the duct is rectangular with side dimensions a and b. It is preferred that airflow measurements are made upstream of the fan (the fan intake).5 duct diameters upstream of the fan inlet or 2. This is to allow for the velocity profile to become evenly distributed in the duct.11. To calculate the effective duct length assume a minimum 2.BASIC MINE VENTILATION UNDERSTANDING FANS FVP 6.1 Selection of Measuring Site 50% 75% Fan Housing 100% Effective Duct Length Satisfactory measurements can only be made in a plane where the airflow is substantially free of swirl and air turbulence and generally should be no closer than 1. the equivalent duct diameter is equal to 4ab Page 111 © AMC Consultants Pty Ltd 2005 .11 Pressure Fans FTP FVP Equation 6-3 Fan Static Pressure The figure below shows the side tube and facing tube measurements for a pressure (forcing) fan (most mine secondary fans). TPI and as TPO . FSP FTP FVP = -1200 Pa = -1800 Pa = VPO = VP = (-1200)-(-1800) Page 112 © AMC Consultants Pty Ltd 2005 . Now as SPI = TPI .(TPI) . free outlet SP= -2600 Pa TPO . a facing tube measuring the inlet total pressure of an exhausting fan is equal to the FSP. Since TP = SP + VP And SP0 = 0 TP= -2580 Pa Then TPO = VPO By definition FSP = FTP – FVP And by substitution FSP = (TPO – TPI ) .BASIC MINE VENTILATION UNDERSTANDING FANS 6.VPO Since TPO = VPO Then by substitution FSP = VPO . Total Pressure 1200 Static Pressure 1800 (Ai) Both measurements would be negative ie. on the suction side of a fan. In this case.2580 Pa Therefore.VPI And TPO = VPO = VPI (no change in diameter) then by substitution Rearranging then SPI = TPI – TPO SPI = FTP = -SPI = -(-2000) = 2000 Pa Therefore. a side tube measuring the static pressure of an exhausting fan is equal to the FTP (fan total pressure). Examples EXHAUST FAN Ducted inlet.12 Exhausting Fans The figure below shows the side tube and facing tube measurements for a suction (exhausting) fan (as installed for most mine primary ventilation). FVP and FTP.TPI = . the static pressure at the fan outlet (SP0) would equal zero.VPO =. Determine the FSP. From these measurements we can determine the fan pressures.TPI = FTP (Qi) The following measurements were recorded at a surface fan installation exhausting air from a mine. BASIC MINE VENTILATION UNDERSTANDING FANS = -1200 + 1800 = 600 Pa Note Velocity Pressure is always positive.13 = 32m3/s and P = RQ2 duct losses = 0.037 x (32)2 = 37.003 0.77m K = 0.8 = Say 40Pa Fan SP = 2500 – 40 = 2460 Pa 6.2 = 0. FSP = SP0 = 2500 Pa less the frictional pressure losses in the duct.13 Air Power 3 R = 4 1 .13m2 Duct Perimeter Assume Then = 1. No duct was installed upstream of the fan. (Qii) The following measurements were made downstream of a development fan in a 1200 mm diameter duct at a site 4 duct diameters from the fan discharge.77 1. Duct area = 1 .13 2VP 2 480 1.3 x 1. Average velocity pressure 480 Pa Duct Static Pressure 2500 Pa Determine the FSP.3m/s Airflow = V x A = 28. (Aii) In a pressure system the FSP is equal to the static pressure of the duct.2 2 2 = 1.037Ns2m-8 Velocity of airflow Air power is the energy required to move a specific quantity (Q) of air over a specific resistance and can be calculated from AP Where AP = Air Power (watts) P Q Equation 6-4 Air Power Page 113 © AMC Consultants Pty Ltd 2005 .2 = 28.003 3.2 = 3. any speed change device between the motor and the impeller and any other source of power. Power costs at remote mine sites can be as high as $0. FOE Air Power 100 Motor Input Power (MIP) This is often mistaken as the Static or Total efficiencies that do not include the power losses for gearboxes. Because suitable dynamometers are not readily available this is usually measured as the motor input power (MIP). The efficiency ( ) of the fan is calculated from the equation The equation for fan efficiency ( ) is therefore usually written as AP MIP The efficiency of any fan can be expressed as either Fan Total Efficiency (FTE) where the FTP is used to determine the Airpower. and the “Fan Overall Efficiency” (FOE). therefore over one year the savings are considerable. The multiplication of air quantity (Q) and pressure (P) results in the power exerted to the air and is simply termed “Airpower” (AP). Some curves show static Of particular interest to ventilation practitioners is the overall fan efficiency as this determines the final electrical input power to the motor. Q P .17/kW hour.000watts 6. Fan Static Efficiency (FSE) where the FSP is used to determine the Airpower. Caution must be used when interpreting fan curve efficiency.14 Fan Efficiency Fan efficiency is important as it determines the cost of power necessary to operate the fan. In this case $116. In the case of FOE this includes losses in the electric driving motor. In this equation “W” is W the impeller power measured with a swinging frame dynamometer.BASIC MINE VENTILATION UNDERSTANDING FANS P = Pressure (Pa) and also = N/m2 Q = Quantity of air (m3/s) Substituting P x Q = N/m2 x m3/s = Nm/s and 1 Nm = 1 Joule and 1 Joule/second = 1 watt therefore AP = watts Example A fan requiring 1500Pa to move 400m3/s of air has an air power of AP = 1500 x 400 = 600. motors etc. Page 114 © AMC Consultants Pty Ltd 2005 .800 each year of operation. For example a primary ventilation fan providing 250m3/s at a pressure of 2000Pa will absorb 667kW of electrical power when operating at an efficiency of 75% and only 588kW when operating at an efficiency of 85%. Others show total efficiency. efficiency. Anemometers are used most often in walk-in airways with velocities between 0. The duct is divided into equal areas and a measurement made at the centre point of each area. For an exhausting fan FSP = Total Pressure measured at the Fan Inlet = 1500Pa Overall FSP efficiency APFSP MIP 1.15 Measurement of Airflow The most common methods used to determine airflow in ducts is with an anemometer or a pitotstatic tube.2m/s and 14m/s. The airflow quantity is determined by Q v * A The figure below shows measuring sites in circular and rectangular ducts derived from the British Fan Test Code. Page 115 © AMC Consultants Pty Ltd 2005 . The Velocity at each point is calculated and the arithmetical average of all sections is determined and used as the duct velocity. The motor input power is 700kW. 2VP The velocity at a point is calculated from the equation for velocity pressure v The velocity in a duct will vary from point to point and the more points measured (on a designed basis) the more accurate is the result.500 300 700 450 700 = 64% and FTP = Static pressured at the fan outlet relative to atmosphere = -(-2000) = 2000Pa Therefore the Total Efficiency APFTP MIP 2. as velocities can be greater than 25m/s.000 300 700 600 700 = 86% 6. The fan inlet total pressure has been determined as 1500Pa and the Inlet Static pressure as 2000Pa. Fan ducts usually require the use of a pitot static tube.BASIC MINE VENTILATION UNDERSTANDING FANS Example Determine the FSE and FTE for a mine exhausting fan delivering 300m3/s of air. 847d 0.655d 0.153d 0.117d 0.783d 0.217d 0.019d 0. The 8-point measuring system is for general use with the 10 measuring point system used for swirling flow in circular ducts Measurement Distances for Pitot Static Tube in Circular Ducts 8 Point System 0.979d 10 Point System 0.345d 0. as opposed to the 4 diameters in the British Standard.883d 0.021d 0.981d Note d = diameter Page 116 © AMC Consultants Pty Ltd 2005 .077d 0.639d 0.923d 0.184d 0.361d 0.BASIC MINE VENTILATION UNDERSTANDING FANS The Australian Standard AS 2936 does not identify sites for rectangular ducts and for circular ducts shows 8 or 10 measuring sites on 3 diameters.816d 0. 16.BASIC MINE VENTILATION UNDERSTANDING FANS 6.1 Density ( ) Change Quantity (Q) Pressure (P) Q1 Q2 1 2 1 2 2 P1 P2 kW1 kW2 1 Power (kW) Efficiency ( ) 6. speed or density of the fan inlet air be altered. Standard air is a definition of convenience that is widely adopted. the following fan laws will apply. If density for a fan curve is not shown it can be assumed as standard air (1.2 Speed Change Quantity (Q) Q1 Q2 P1 P2 kW1 kW2 rpm1 rpm 2 rpm1 rpm 2 2 Pressure (P) Power (kW) Fan total efficiency ( ) 6.2 kg/m3).3 Diameter Change rpm1 rpm 2 1 2 3 When the diameter (D) is increased and the fan is geometrically similar the following laws apply: Quantity (Q) Q1 Q2 P1 P2 kW1 kW2 D1 D2 D1 D2 3 2 Pressure (P) Power (kW) D1 D2 5 If the size difference is great then it can be expected that the fan total pressure may be larger than that given by these laws (scale effect).16 Fan Laws Fan performance curves are determined for a specific speed and density. 6.16. Page 117 © AMC Consultants Pty Ltd 2005 .16. Should the diameter. The actual values of temperature. pressure and moisture content are not important. 5 kPa.3 m3/s The pressure change can be calculated by combining the effects of density and speed changes. These laws should be used with caution as they are not applicable to all fans. This is discussed more fully in “Woods Practical Guide to Fan Engineering” or “Fan Engineering” published by the Buffalo Forge Company.16.BASIC MINE VENTILATION UNDERSTANDING FANS It is also possible that a change in density due to compression of the air will occur affecting the results from the use of these laws. Quantity (Q) = Pressure (P) = Power (kW) = 20 m3/s 1520 Pa 40 kW What is the expected operating performance at 1470 rpm at standard air inlet density of 1.1 and 6.16.2 1. Example A 1000m diameter fan tested at 1380 rpm and an inlet airflow density of 1.16 1790 Pa The change in power change can also be calculated by combining the effects of density and speed changes. kW1 kW2 Therefore 1 2 and kW1 kW2 3 1 2 rpm1 rpm 2 3 kW1 kW2 rpm1 rpm 2 Page 118 © AMC Consultants Pty Ltd 2005 .2 kg/m3. This is normally only of concern at pressures above 2. P1 P2 Therefore rpm1 rpm 2 2 and P1 P2 1 2 P1 P2 P2 rpm1 rpm 2 = = 2 1 2 And 1520 1470 1380 2 1 .16 kg/m3 gave the following results. From equations in sections 6. Q1 Q2 Therefore Q2 rpm1 rpm 2 = = 20 1470 1380 21.2 Note that density change has no affect on the quantity. can become caught on an impeller. 6. If a fan is allowed to run for extended periods while out of balance it can potentially cause bearing failure and fatigue cracking in either the impeller. Page 119 © AMC Consultants Pty Ltd 2005 . 2.16 50 kW 6. the shaft or the fan casing. All of which cause the fan to run out of balance. c) Rocks and other foreign materials are often found in fan housings and simple things like rags. This could be 70%.2 1. particularly if aerofoil blades are used A centrifugal fan will deliver a reduced volume in the same direction at a greatly reduced pressure and efficiency There is often suggestion that fans can be reversed in times of emergency to reverse the direction of flow in the mine. b) Unrecognised increasing fan pressure caused by increasing mine resistance. d) An accumulation of dust and salts on impellers may also cause the fan to run out of balance. Although this is true the fan performance is significantly reduced.BASIC MINE VENTILATION UNDERSTANDING FANS And kW2 40 = 1470 1380 3 1 .18 Effect of Reversal of Rotation 1.17 Fans Failure Fan failure is more often than not caused by: a) Poor preventative maintenance including regular cleaning of guide vanes and impellers. An axial flow fan will deliver a reduced volume of air in the opposite direction at a greatly reduced pressure and efficiency. plastic etc. Page 120 © AMC Consultants Pty Ltd 2005 . tested and evaluated long before it becomes part of any emergency procedure.BASIC MINE VENTILATION UNDERSTANDING FANS Before attempting this in an emergency the final affect must be completely understood and more importantly tried. BASIC MINE VENTILATION MANAGEMENT “It remains for me to speak of the ailments and accidents of miners and the methods by which they can guard against these, for we should always devote more care to maintaining our health, that we may freely perform our bodily functions, than to making profits.” Agricola - “De Re Metallica” (1556) 7 MANAGEMENT There has been significant change in underground metalliferous mine design and operations over the past ten to fifteen years. Hoisting shafts are now rare in all but very deep, high tonnage operations. In most mines, all ore and waste is brought to the surface in diesel trucks. More diesel equipment per tonne of ore is therefore required. The use of ancillary diesel equipment (e.g. cable bolting, mechanical scaling, charge-up secondary breaking and shot-creting equipment) is increasing. There is a greater prevalence of mining methods that require little permanent development apart from the decline. This has made the establishment of appropriately placed primary ventilation infrastructure difficult and increased the reliance on secondary ventilation techniques. The regulatory framework has changed and is now much less prescriptive. Instead of designing to satisfy minimum statutory requirements, there is now much more reliance on the principle of an employer’s duty of care. There has been a dilution of technical expertise brought about by a number of factors, including the recent rapid growth in the industry. As a result, there is an increasing requirement for ventilation systems to be simple, robust and reliable so that minimal intervention or management is required. Mine ventilation practice has had to evolve to keep pace with these changes. And many long established rules of thumb are now no longer appropriate. Of all the ventilation problems encountered in mines, the vast majority are caused by higher than acceptable concentrations of smoke, dust and heat. Smoke reported during the shift is generally from poorly tuned and/or maintained diesel engines. Dust is almost always from handling of dry broken rock, drilling and raiseboring operations. Increases in temperature are due to change in ambient surface conditions or ventilation flows being reduced (changes due to rock temperatures should be well recognised long before they cause problems). Identification of the source of the contaminant provides the opportunity to control the problem at this point. However, solutions of this type are more often than not met with resistance from production and maintenance personnel. Most cases are resolved by a compromise between removing the source and increasing the airflow. In those situations where the source cannot be successfully controlled, for whatever reason, then rescheduling of activities may remove the symptoms and allow work to continue. Unfortunately it is only the most severe cases of undesirable conditions that are adequately dealt with and the others are allowed to continue because “we will be out of there soon”. As a consequence operators are usually only looking for a “quick fix”. Of all the problems identified the solutions could quite easily be found in the “Top Ten Solutions” below 1. Holes in auxiliary ventilation duct Page 121 © AMC Consultants Pty Ltd 2005 BASIC MINE VENTILATION MANAGEMENT 2. 3. 4. 5. 6. 7. 8. 9. 10. Excessive tees NOT tied off Fan re-circulation Poor fan selection Leaking ventilation walls Poor primary airflow distribution (caused by incorrectly adjusted and/or lack of controls) Lack of dust control measures when loading and transporting broken dirt Short-circuiting of air through stope voids, ore passes and disused vertical openings. Activities and diesel equipment has outgrown the original ventilation system design. Poor records of airways (particularly vertical openings), dimensions, development method, location and purpose All are problems that could (and should) have been avoided by better planning and management. 7.1 Primary Airflow Requirements There are many “Rules of Thumb” (ROT) and a few empirical equations that have been developed to estimate the airflow requirements for mines. Some are realistic and based on recent mechanised mines but many are unrealistic and based on older non-mechanised mines. All are based on past experience. There use is acceptable as long as they are taken exactly for what they are that is an idea of the magnitude of the result that will be achieved by calculation. Some time the results will be surprisingly close to a calculated result and many times it will be way off the mark. Determination of the primary airflow requirement is the starting point for ventilation design. The design airflow needs to be known before the required number, and size of surface ventilation shafts can be estimated. Design primary airflow requirements are almost always under-estimated, probably due to the use of ROT or some empirical equation, but also due to a failure to allow for increases in mine size, depth and complexity beyond initial estimates. Even then the cost of providing the necessary airflow under-goes “pruning” in an effort to keep project capital and operating costs to the minimum. Under-estimated (or reducing) primary airflow rates will adversely affect the project economics in the following ways: Operating Costs: Power costs increase dramatically with airflow rate. If airflow rates need to be increased beyond initial estimates, there will be a substantial increase in operating costs, particularly if airways are inadequately sized: Power Cost Increase New Flow Rate Old Flow Rate 3 Capital Costs: An increase in airflow rate may require the purchase of new fans and excavation of new airways. The cost and just as importantly the disruption to mining in doing so are usually considerably greater than would be the case if the original airways sizes were based on realistic primary airflow estimates. 7.1.1 Determining Primary Air Quantities. When estimating primary airflow requirements, we need ask ourselves why ventilation is being provided in the first place. In many cases, in mechanised mines the criterion for dilution of diesel exhaust emissions is the overriding factor. It is however also necessary to consider equally Page 122 © AMC Consultants Pty Ltd 2005 BASIC MINE VENTILATION MANAGEMENT relevant requirements such as control of thermal conditions and adequate dilution of dust and mine gasses. Analysis of airflow requirements for individual work places is usually carried out when determining primary airflow requirements. Design airflow rates are often based on exceeding 0.04 to 0.06 m3/s of airflow per rated kW of diesel engine power in all active mining areas. This analysis can become quite complex for larger operations and requires a thorough understanding of the individual facets of the development and production process. The design airflow rate must include an allowance for leakage (both primary leakage and leakage in secondary ventilation ducts) and service areas such as ore passes, grizzlies, crushers, conveyor drives, fuel bays, pump stations, workshops etc. The first process is to work with the designers and schedulers to allocate air quantities and with consideration to predicted heat loads, strata gas emissions, diesel exhaust emissions, legislation, OH&S and Industrial relations to allocate airflow requirements for; Location Scheduled production activity Drilling, blasting, loading, filling. Scheduled development activities Airflow required for Equipment in use in each area Dimensions and layout of access and loading routes Equipment in use in each area Dimensions and layout of access and loading routes Auxiliary ventilation system Equipment in use in each area Dimensions and layout of access and loading routes Equipment in use in each area Dust dilution/collection/removal Operator protection Equipment in use in each area Dust & fume dilution/collection/removal Fire protection Operator protection Equipment in use in each area Dust & fume dilution/collection/removal Fire protection Operator protection Airflow Temperature Haulage routes Rock handling including: Rock breaking Crushing, Loading station, Hoisting Servicing areas including: Maintenance workshops, Electrical substations, Pumping stations, General maintenance and construction work areas, Refrigeration plants Storage and supply areas: Explosive, Diesel fuel, General consumables and stores Lunch rooms and waiting areas Obviously not all of the above locations/activities will apply to all mining operations. Circuit design is ultimately determined by the production schedule. The siting of dedicated ventilation airways will be determined by mining methods and production design layouts. The determination of total mine airflow is only the first step toward a mine ventilation system and requires the most attention because it is at this point that the final and cost to the operation will be determined. Ventilation planning and design is complicated and those who are responsible for ventilation and believe otherwise have the potential to cost their organisation a great deal of money. Example Lets consider a new narrow vein mine with an optimum production rate of 300,000 tonnes per year. It has been decided that predominately one pass ventilation will be required. Ore will be loaded from the stope to an orepass from where it will be trucked in the main decline out of the Page 123 © AMC Consultants Pty Ltd 2005 raise bore location. production bogging location or stope filling location.5 m3/s per 1000 tonne. the air quantities for each activity have been determined as: Activity Decline development In ore Development Production Raiseboring Backfill Airflow (m3/s) 80 12 5 5 8 This airflow was then allocated to the respective activity and summed for each month. Active Locations 160 140 120 Number 100 80 60 40 20 0 0 6 12 18 24 30 36 42 48 54 60 Month Development Raisebore Mining Backfill After consideration to diesel exhaust emissions. (0. Page 124 © AMC Consultants Pty Ltd 2005 . In this case an active location is taken as any development face. This particular schedule will require primary airflow ranging from 80 m3/s during initial development peaking at 227 m3/s during the start up of production then tapering off to less than 50 m3/s toward the end of the scheduled period. For this example assume the results shown graphically below. Backfill will delivered to the stope void using a 10 tonne truck. Assume a “ROT” for narrow vein mechanised mine to be 0. production drilling location. The number of active locations during any one-month is then summed.5 x 300 = 150 m3/s) The production and development schedule has been evaluated and the active locations during each month have been determined.BASIC MINE VENTILATION MANAGEMENT mine. dust and heat etc. changing economics etc most mine schedules beyond year three do not have the same confidence level contained in the three-year plan. 1. 3. A detailed mining schedule is only valid until the next update. and year to year. Because of the very nature of mining there will be an end and the tapering off period will vary from mine to mine. Main production period (month 19 to 46).BASIC MINE VENTILATION MANAGEMENT Airflow Requirements 250 200 Production Initial Development Start up 191 m 3/s Production Development Raiseboring Mining Backfill Production Taper Quantity (m /s) 150 100 50 0 157 m3/s 3 6 12 18 24 Month 30 36 42 48 54 60 There are four distinct periods that require some comment. The alternative is to purchase and install primary fans with some form of control that will enable the airflow requirements to be “turned down” after production settles down. Because of increasing geological information. types and locations. (Always round UP its hard enough to get so don’t give it away). The peak airflow during this period is 227 m3/s. Axial or centrifugal. 2. Single or multiple fans. For example they could be any combination of Forcing or exhausting. The difficulty of this period is the cost for providing extra air when it is not required over the longer term. Most designers opt to bypass this period and attempt to manage their way through it.2 Primary Ventilation Fans Primary ventilation fans are found in many different sizes. In a new mine there will be ‘teething problems’ and the production and development schedules will undergo constant updating before eventually settling down. This occurs because of the flurry of activities necessary to bring the mine into full production in as short a time as possible. 7. (Not a good time to be the ventilation officer). Initial development (month 1 to 12) to establish the access decline and the exhaust ventilation shaft will be ventilated with secondary fans and will not form part of the primary ventilation requirements. Any schedule beyond three years should be viewed with some scepticism. This peak at the end of initial access development and the commencement of production is common. 4. Production Start-up (month 13 to 18). Page 125 © AMC Consultants Pty Ltd 2005 . With input from the ventilation engineer the airflow peaks and troughs will be smoothed settling somewhere around the median of 160 m3/s. End of the life of the project (month 47 onwards). Most fans are selected to meet the immediate short-term budget and not the long-term future ventilation requirements of the mine.1 Surface Fan Installation Arrangements Primary ventilation fans are arranged in many different ways some of which are depicted in the figure below. Horizontal or vertical discharge. Because of this they are not suitable for the life of the mine and have to be either upgraded or replaced both very expensive options. 7. Surface or underground.2. Some are designed to meet predicted requirements and some are found lying around and installed in the hope that they will provide the necessary airflow. environmental issues and capital cost. Horizontal or vertical mounted.BASIC MINE VENTILATION MANAGEMENT Single or multiple shafts. The preference of any particular combination is usually a matter of individual choice driven by past experience. Page 126 © AMC Consultants Pty Ltd 2005 . Each has their advantages and disadvantages. Construction is more difficult as the use of large mobile cranes is restricted. 2.3 Circuit Booster Fans Circuit booster fans are used to alter the pressure distribution and supply ventilating air to specific areas of the mine.BASIC MINE VENTILATION MANAGEMENT 7.3 Forcing or Exhausting The vast majority of primary fans installed in Australian mines are located on the surface to exhaust air from the mine.2. 7. The choice of location is usually made as a matter of convenience rather than any specific engineering aspect.2 Underground Primary Fan Arrangements Primary ventilation fans may also be installed underground. Excavation and preparation of the site is costly. If the fan is installed in the intake airway it limits the accessibility to the shaft for the movement of men and equipment. 7. For example a simple mine will have one primary intake airway (be it shaft or decline) and one primary exhaust shaft. If the fan fails access for repairs is restricted because the only ventilation flow is from the natural ventilation pressure. The underground locations could be at the bottom of the shafts or at some intermediate point between the surface and the bottom of the mine. centrifugal are also used. They are often necessary when a mine has Page 127 © AMC Consultants Pty Ltd 2005 . Although underground fans installations are predominantly the axial flow type.2. The use of primary fans installed underground has generally been avoided for a couple of reasons: 1. Exhaust shafts are by their very nature dirty and the air contaminated with dust and fumes making it undesirable for the movement of men and equipment as it is much more desirable to enter the mine in clean intake air. 3. 7. 7. and 2. They are also misused in many mines as a method to supply air to areas of mines in an attempt to counteract the poor management of the primary ventilation circuit.4 Primary Ventilation Circuits Primary ventilation circuits are designed to supply fresh air to workplaces and dilute and remove contaminants resulted from the mining processes. This concept ideally lends itself to large tonnage stopes or stoping blocks and may not be suitable for use in some narrow vein steeply dipping orebodies. In this situation. as they tend to pressurise the exhaust system forcing the out to flow back into the primary intake airflow. Both have their advantages and disadvantages and many mines use a combination of both circuit types. This is particularly important in the event of a fire occurring in the work place as it minimises the areas (and personnel) affected by the smoke. For example they may result in recirculation of large quantities of air.1 Parallel (One Pass) Circuits Parallel circuits adopt a general design philosophy of ‘one pass. Series circuits. as time lost on production waiting for fumes to Stope Void clear is very costly. it is necessary to control the air entering the activity area (usually by regulation of the exhaust).BASIC MINE VENTILATION MANAGEMENT been developed below the mining area defined in the original mine designs. The down side of this To Primary Exhaust 0m Than 25 er Not Long TYPE A: End Access To Primary Exhaust TYPE B: Central Access Page 128 © AMC Consultants Pty Ltd 2005 . It is usual for return air circuits to be areas requiring minimal access and therefore all contaminants are removed directly from the mine.4. With multiple level accesses. Parallel circuits. flow through’ air. The time required to flush blasting contaminants from the mine can range from a few minutes up to many hour. gases and particulates. Poor selection of fan location and capacity has potential to create more problems that they solve. Stope Advance There are two basic circuits used 1. The effective and timely removal of contaminants particularly after blasting is high on the priority lists for mine managers. a circuit is established to direct air from the primary intake circuit over the areas of activity and exhaust directly to the return air circuit. These circuits have disadvantages including (but not limited to): The need for high pressure fans (hence higher power costs). and Contaminants from activities (and fires) affect all down stream personnel. In these circuits. Although not encouraged. 7. air intakes via the access (decline) and is returned to the primary exhaust at each orebody access. These circuits rely on secondary fans to ventilate in orebody development and production with the return air from these activities being mixed with the primary intake airflow and re-used at the next activity. Because stope voids form connections between levels they create airways parallel to the ramp or intake shaft. This type of circuit has the advantage of simplicity of control and minimal development for ventilation. Obviously if the air in the ramp is up casting then it follows that the air in the stope void will also upcast. This provides flexibility to move from one location to another without the necessity to adjust ventilation circuits.BASIC MINE VENTILATION MANAGEMENT type of circuit is that short-circuiting occurs each time a stope is opened or a ventilation control is damaged. 7. For this type of circuit to be successful.3 Series Ventilation Circuits A system most often used in narrow plunging orebodies. Although the utilisation rate (total airflow to the working areas / total airflow through the mine) can be as high as 75%. it is recognised that this is the system used in development areas and in reality will continue to be used in some production areas.4.4 Use of Stope Voids as Airways There is often a misconception that stope voids will upcast airflow causing much frustration when the air downcasts through the stope. Generally the pressure distribution is such that the air in the ramp (intake system) is down casting and it follows that the air in the stope will also downcast air. 7. occurs and all locations operate with less than desirable airflow rates. Because of the geometry of narrow vein orebodies. however experience tells us that this seldom. is a simple series ventilation circuit. Decreasing airflow with depth. these circuits also decrease re-entry times but only if the access does not form part of the return air circuit. even when not in use. ventilation controls must be well maintained. This type of circuit is normally adapted to narrow vein orebodies with long strike lengths. LHD tramming distances are usually kept below 250m. Mine operators often plan to minimise total airflow by campaigning air from one location to another. Page 129 © AMC Consultants Pty Ltd 2005 . Whilst providing improved conditions in work areas. Low fan power efficiency for the majority of the operating period (the fan only operates at maximum efficiency in a fully developed mine).4. if ever.2 Secondary Fans and Parallel Ventilation Circuits.4. it may prove difficult to maintain the philosophy of flow through ventilation without the need for extensive development and therefore the use of secondary fans during production must be considered. it is typically 65% with 40% not uncommon. It is usual to provide airflow to all scheduled production locations. BASIC MINE VENTILATION MANAGEMENT If stope voids are required to up cast air. Similarly if the pressure across the plate is known. Considering a mine regulator.6132 or 2. as in series ventilation circuits.5 Recirculation Recirculation occurs when air is kept within a closed circuit. then it is necessary to design and install the appropriate ventilation controls to cause the pressure distribution required. At the vena contracta the velocity pressure is 1. contaminants in the airflow and the clearing time for blasting gasses remain within acceptable levels. the primary return airway must not be lower than the top of the stope void.613 times greater than in the orifice itself. work place temperature. depending upon the siting of the fan in the airway. It should not be confused with the situation when air is reused. This frustration is a result of the lack of understanding of the pressure distribution across the mine and the fact that altering one regulator effects the WHOLE mine distribution and not just the area being adjusted.3 times its open circuit capacity. Recirculation occurs when a fan is installed in an airway in which the natural flow of air along the airway is less than the operating capacity of the fan. which is very thin. This area is called the vena contracta and at this point the velocity of the air is 1.4. It is normal for persons to open or close a regulator in order to increase or decrease airflow to a certain area. Even then minor recirculation is possible.5 times higher than the orifice.0m x 2. Other less common regulators are the louvre type (either vertical or horizontal). There is often an attempt to compare the opening in a wall to an orifice (vena contracta). Although not recommended. In some Australian legislation there is a requirement to install secondary fans such that the air delivered to the fan is greater than 1.5 Ventilation Controls Regulators commonly used in Australian mine are rectangular openings in walls that are open or closed by the placing or removal of boards. 7. or a sliding door (again either vertical or horizontal). In general. Sometimes this is meet with much frustration because the desired airflow cannot be achieved. the wall thickness can be proportionally greater Page 130 © AMC Consultants Pty Ltd 2005 . Using the equation for velocity pressure v2 VP and knowing the velocity we 2 can determine the velocity pressure. As a general Rule of thumb an airflow of at least 1. This legislation was introduced in times when small drives (2. then the velocity in the area of vena contracta can be determined and we can back calculate the area of the orifice. some minor recirculation may be acceptable provided the.0m) and low capacity fans (5 to 7 m3/s) were common. 7. if stope voids are required to upcast.5 times the open circuit capacity of the fan is required in airways with large cross sections and higher capacity fans. In a perfect orifice the opening is circular and relatively small compared to the plate (wall). As the air flows through the opening it converges and at a distance equal to half the orifice diameter the jet is at its smallest area. The reliance on stope voids also has the high probability of production blasting covering the stope brow thus preventing flow through ventilation. As rock falls down the pass it generates dust and acts like a pump compressing air in the pass and forcing it out on to each open sub-level below. Efforts to prevent this by creating a positive airflow into the ore pass from all access points are generally unsuccessful. Forcing. ALL other openings should be sealed or otherwise connected to the RAR system via a dedicated airway. In addition to short-circuiting airflows. It is often the case that operators. quantity or pressure at a regulator the following algorithm can be used A Where 1. All other adjustments are then made to this opening. if necessary with temporary seals. Exhaust overlap Page 131 © AMC Consultants Pty Ltd 2005 . to gain increased airflow. all but one of the tipping points. In practice the airflow through regulators is set by trial and error until the desired. 7. The suggested method for any adjustment programs it to go to the bottom of the mine (lowest pressure area) and fully open this regulator. when empty. Commence adjustment (setting the desired airflow) at the top of the mine (highest pressure) and progress to the bottom of the mine (lowest pressure). The problem is best managed by sealing.6 Multiple Access Orepasses Multiple access and uncontrolled orepasses will. For any calculation to be reasonably accurate the area of the regulator should be no greater than onetenth the size of the airway in which it is constructed. To estimate the area. 1. By the time you get to the lowest regulator a measurement of the airflow should show that the airflow is around the quantity required. All adjustment to regulators should only be undertaken once the airflow distribution across the mine has been planned and scheduled as it may be necessary to adjust more than one opening to achieve the desired result for all areas.BASIC MINE VENTILATION MANAGEMENT than the thin orifice plate and the ratio of the area of the opening to the area of the wall is different and this affects the coefficient of contraction (1. form an airway parallel to the decline potentially reducing the airflow on the decline to unacceptable levels.7 Secondary Ventilation Systems There are three predominant secondary ventilation systems used. or at least close to the desired result is achieved. adjust regulators. multiple access orepasses are often a significant source of dust.613) that becomes larger as opening increases in size forming an increase in percentage of the opening to the airway wall. Exhausting and 3. 2. 7. Although they achieve their desired result it is more often than not that they have caused a detrimental effect else where in the mine.2Q P Equation 5 Area of a Regulator opening A = the area of the opening (m2) Q = Quantity of airflow (m3/s) P = Pressure across the opening (Pa) = Density of the air flowing (kg/m3) Like the calculation of shock losses in practice there are so many unknown factors that the calculated result is seldom correct and further adjustment is required. no matter how “bad” conditions become. In most cases once the fan is installed it is seldom relocated. it is the accepted practice in coalmines and many tunnelling operations that use cutting or boring machines. The use of two exhausting fans was simply to standardise the fans being used. Because the fans are located in the developing heading if the was to be a power failure to both fans then repairs are restricted until the area is ventilated by another fan. Because of the cost of rigid ducting as opposed the less expensive flexible type this arrangement lost favour. This can go undetected simply because the fan “is running” and you can feel the breeze at the face. However. It is also inconvenient to move the position of the overlap as it is necessary to remove and relocate the exhausting fans. 7.BASIC MINE VENTILATION MANAGEMENT Forcing ventilation system is the predominant system used in hard rock mines. These systems provide advantages including The fan is located in clean intake air making it accessible for maintenance for maintenance and repair Allows the use of flexible ventilation ducting (less expensive than rigid ducting) Exhaust ventilation systems require the use of rigid ducting and because of the extra cost involved with the purchase and installation of rigid ducting. was installed clean air and used rigid ducting. This allowed air to flow in the overlap position and prevented recirculation. Page 132 © AMC Consultants Pty Ltd 2005 .7.1 Installing Secondary Ventilation Fans Auxiliary ventilation fans are a fact of life and used in ALL mines yet they are still installed where it is convenient rather than where it is best suited. Although not commonly used this system has benefits when developing long drives. There have been instances where fans have been poorly located to the extent that the recirculation is almost 100%. Re-entry times may be reduced by the use of an exhausting or exhaust overlap ventilation system where the air is removed via the ducting allowing immediate re-entry to the face in fresh air. systems of these types are seldom used in development headings in hard rock mining. Poor location of auxiliary fans will result in recirculation of air and obviously recirculation of contaminants with the resultant “less than desirable” conditions at the working face. In its original concept the exhausting fan was slightly larger than the forcing fan. In recent times it has been adapted for use using flexible ducting and two exhausting fans. If this is not achieved the truck loading area very quickly becomes contaminated with high concentrations of dust and diesel exhaust emission. The seal around the fan is damaged. 7. In the same way that the exhausting fans are sized to cause a flow in the overlap. and there is a “rule of thumb” that the airflow passed the fan should be 1. One of the simplest means for detecting recirculation is to use a smoke tube (particularly near the backs) to check the direction of the exhausting airflow. Sometimes it is extremely difficult to get close enough to the backs and it will be necessary to undertake measurements of air flowing in the drive and in the duct down stream of the fan. This allows contaminated air to be exhausted from the mine without being reused. In all cases the airflow in the drive must be greater than the airflow in the duct.2 The “Reuse” of Air As discussed above.BASIC MINE VENTILATION MANAGEMENT The ultimate reason that fans recirculate is the lack of air flowing passed the fan inlet.7. In general auxiliary fans should be located approximately 20m upstream of the drive they are ventilating. The success or otherwise of this practice in force ventilated areas lies in the correct selection and location of secondary fans. If one or both of these factors does not apply the fan must be sealed into and appropriate airway to prevent any recirculation. 2. it is an acceptable practice to “reuse” ventilating air. (See “Secondary Fans and Parallel Ventilation Circuits” above). Some options are shown in the figure opposite.3 to 1. a flow must be caused between the fan and the exhausting point. There is insufficient airflow in the drive. Many mine designs now incorporate the return air rise (RAR) adjacent to the intake air decline.5 times the open circuit capacity of the fan. In many of these cases the truck is loaded near the stockpile bay adjacent to the RAR and care must be taken to ensure that there is a flow of air in this area. Many attempts are made in development areas to install multiple Page 133 © AMC Consultants Pty Ltd 2005 . This can occur for three reasons: 1. The fan is to close to the exhaust 3. increase the primary intake air. In the vast majority of these installations the airflow passed the fans is insufficient. using duct size which is smaller than the fan diameter is not acceptable. 7. Like Page 134 © AMC Consultants Pty Ltd 2005 . There are a number of solutions the obvious ones being. only operate one fan at a time. No one seems to get particularly concerned with holes and rips in ventilation duct.BASIC MINE VENTILATION MANAGEMENT parallel fans in an effort to get extra fresh air to the working faces.8 Ventilation Duct. Unfortunately. construct a seal around the fans to prevent the recirculation. its limitations are very poorly understood. Another solution is to relocate one of the secondary fans. In almost all cases. resulting in the “recirculation” of the return air through the fans. Flexible ventilation duct is an extremely versatile and convenient method of providing secondary ventilation. Only increasing the primary airflow would not restrict the flexibility of multiple workplaces or cause some interference with activities in the area. The final result is increased heat and contaminants in the working areas. Some practical tips for installation include: The largest possible ventilation duct size should be used to lower resistance and hence reduce leakage. Secondary to this is the ease and convenience of installation and thirdly there may be occasional consideration of the material friction factor but very seldom is any consideration given to the rate of leakage from the duct. There is a perception that “more air” can be supplied to the face by using a more powerful fan. For comparison. The knocker line must be hung straight from lined up attachment points (not from the nearest convenient split set). These hoops were overlapped one inside the other and prevented from coming apart by tying a length of wire around the duct in between the hoops. Use of the low leakage ducting described above can also enable large amounts of capital to be saved. With the use of low leakage. 7. or are simply ignored. Lay-flat flexible ventilation ducting has been used extensively in Australian Mines since around the middle of the 1960’s. not only with the original purchase price but also with the cost of transport and handling. the very high cost of these problems are often not appreciated. The last one or two ventilation ducts should be sacrificial “face bags” to avoid the rest of the duct sustaining blast damage. This is incorrect.BASIC MINE VENTILATION MANAGEMENT compressed air leaks. Page 135 © AMC Consultants Pty Ltd 2005 . a fan would consume $149.9 Duct Leakage Generally. The importance of ensuring adequate clearance between mobile equipment and the duct is also not clearly understood.200 mm low leakage ducting using a 1. There seems to be a common belief that an unlimited number of “T” pieces can be connected to a ventilation duct and left open. It is not unusual to find 1400 mm diameter fan and duct installations. 110 kW fan. with very well installed 1. This may result in the savings of many millions of dollars by not having to excavate ventilation airways at various points along the development heading. It is a common experience to almost have one’s head blown off by leakage from a ventilation duct near the fan and to then be asked why there doesn’t seem to be much flow at the face. Every eyelet must be used when connecting “Lo k®” or similar joints. the prime consideration for the purchase of ventilation ducting is cost. Care must be taken to ensure that “Minsup®” clips are not left in the ends of ventilation duct when new bag is connected. well installed flexible ventilation ducting it is possible to advance development headings in excess of 2000 m. This wasn’t the case in the old days when steel duct was used! The equipment and drive size must be selected so that there is no chance of the duct being hit. In it’s original form it was manufactured from a terylene material with wire hoops sewn into each end. 23 m3/s can be delivered. The importance of installation standards is also not often appreciated.000 per annum in power costs. Prior to the 1960’s the ventilation ducting of choice was usually a rigid type manufactured from galvanised iron or plastics of some type. With electrical power costs of 10¢ per kWh. which over 500 m deliver only 7 m3/s to the face! This is insufficient flow for even one LHD. possibly two and all other “T” pieces should be tied off. There is usually only sufficient flow to ventilate one face. and 170 kW power draw.200 mm diameter. Sharp corners require the use of specially manufactured elbow pieces. The high leakage rates from some spigot low cost ducting currently available in Australia limits its use to lengths of up to 400m in some cases this can be as little as 200 m. In the example shown opposite a two-stage contra rotating fan in a “leakless” duct will provide 43 m3/s at 200m and 32 m3/s at 800m. In response to a need to lower operating costs in the 1970’s different materials were introduced as was a different type of join (spigot type).e. Calculating the resistance curves for various duct lengths can also allow us to predict the airflow achievable at various lengths. the material. With leakage in a good quality ducting the airflow through the fan at a distance of 800m. After this point leakage from the system can be as high as 50% of the air produced by the fan. The leakage rate in a well installed and well maintained low cost ducting may cause only slight inconvenience in short (less than 400m) development headings and the use of the lower cost stitched. The air that leaks from a duct is a function of many variables including. This development process has introduced three potential areas of leakage. type of joint.3 page 93 we showed how we could predict the airflow through a system using a fan performance curve and the system resistance curve. Although ventilation ducting with a high leakage factor may be considered suitable for short development headings. holes created for stitching the seams and. The requirement for increased airflow has grown to the extent that auxiliary ventilation fans now provide up to 50m3/s at pressures in excess of 4000Pa resulting in increased leakage quantities. These improvements have all come at increased purchase price. performance of the fan. and the number and size of holes in the duct. Because most mines have spare development fans any excessive leakage is “fixed” by installing an additional fan either in series or parallel. its use in long development headings is questionable. airflow requirements for auxiliary fans have increased and as a consequence so have fan pressures. Page 136 © AMC Consultants Pty Ltd 2005 . lay flat types of ducting. ducting and the spigot joint continues to serve this purpose. Since the late 1960’s and the introduction of diesel powered trackless equipment.BASIC MINE VENTILATION MANAGEMENT Prior to the introduction of trackless diesel equipment auxiliary fans had relatively low airflow rates (6 to 7 m3/s) and low pressures (2000Pa). The combined affect is reduced airflow discharged to the working face. Many of the early development problems have been recognised and material coatings have been improved. In Section 6. Stitching has been replaced with welding and the hoop type joint has been resurrected and improved by holding it together with a specifically designed clamp. another fan in the duct) will deliver the required quantity of airflow to the face. In reality ducts are seldom (if ever) free of leaks and this is particularly true of flexible. There are some who believe that the introduction of extra fan power (i. and as a consequence the pressure requirement is reduced and the stall point is seldom reached. the type of join. would be slightly higher (say 38m3/s) and the flow to the face would be significantly less and would probably be closer to 20m3/s. The shortfall in this methodology is that it assumes “leakless” ducting. and is barely adequate for the operation of one truck and one LHD. type of material. The leakage resistance is often expressed as a leakage flow per unit length for a given duct diameter at a given pressure.BASIC MINE VENTILATION MANAGEMENT The air that leaks from a duct is a function of many variables including.S. Sydney (1984) Page 137 © AMC Consultants Pty Ltd 2005 . consideration of duct leakage resistance on its own is relatively simple. effect on equipment in the airway (harmonics in rope guides in hoisting shafts). 7. type of equipment to be used for development of the airway. In the case of a 1400mm diameter fan this is 67. The only constant in ventilation duct system is the fact that it will leak but how much is anyone’s guess. conveyors in drives. If this airflow is not available then it may be necessary to install a seal around the fan to prevent any recirculation. “Design of Auxiliary Ventilation Systems for Long Drives” Fifth Australian Tunnelling Conference. In particular. 7. because the flow rate along the duct is not constant.0 m/s to be used in declines and other access drives.5 times the open circuit capacity of the fan. Vutukuri (1984)18 developed a methodology for use in a computer program necessary to solve the complexity of two components: Duct friction resistance Duct leakage resistance Without leakage. With this in mind the location of the fan becomes important if recirculation is to be avoided. pressure losses caused by conveyances (cages in shafts. Similarly. or more intuitively. The combined affect is reduced airflow discharged to the working face. trucks in declines etc.1 Velocities in Access Drives There is a generally accepted “guideline’ for a maximum air velocity of 5. or any combination of these and other factors.5 x 45). as an equivalent mm2 of holes per m2 of duct. determining duct friction resistance is straightforward enough. cooling power of the air. determining fan pressure requirements for a given flow is difficult. V. and the number and size of holes in the duct. performance of the fan.10. As discussed earlier a general ‘rule of thumb’ for auxiliary ventilation fans is to locate them in airflow that is equal to 1. dust entrainment. type of joint. type of material. Other engineering factors include. The purpose of this is to ensure that dust is not entrained in 18 VUTUKURI.).10 Velocities in Primary Airways The economic optimum diameter of any ventilation airway can be determined by the total development and operating costs over the useful life of the airway. It can be determined simply using Atkinson’s equation. The other important point to note is the air through the fan has not significantly changed and is operating very low on its performance characteristic curve. activities being undertaken in the airway. The problems commence when the interaction of the above two resistances is considered.5 m3/s (1. If allowed to continue unchecked this may eventually cause mechanical failure of the fan. 7. A large water droplet of greater than 3mm diameter has a terminal velocity of 8.0m/s should be avoided. to some degree.0m/s and 12.12 Equipment Movement in Underground Airways Trucks (or other vehicles) travelling in underground drives can cause pressure losses up to 200Pa depending upon a number of variables such as the size of the vehicle in relation to the cross sectional area of the drive and the direction of the airflow in the ramp.BASIC MINE VENTILATION MANAGEMENT the primary airflow and that unnecessarily high ventilation pressures (and consequently high electric fan power costs) are not imposed on the mine ventilation system. Consider the following: A truck having dimensions of 3.0m/s and 12. and roadway surfaces are sufficiently stable (wetted) to prevent dust pick up from tyres being entrained into the ventilating air.0 m/s can be cost effective over short distances providing that good dust management systems in place to ensure that: dirt in the trucks is sufficiently wetted. This results in a ‘critical range’ of air velocity between 7. At times this may be sufficient to cause the fan to go into stall.0m/s then the water droplet will fall down the shaft and if the velocity is greater than 8. As this saturated air rises from the bottom to the top (surface) of the exhaust shaft the barometric pressure is constantly decreasing and as a consequence the temperature of the air. Velocities above 6. As the ventilating air flows through the mine workings it takes up this water as vapour until it becomes. and water vapour mix. Although 8.0m/s the water droplet will be pulled up the shaft.5m wide is travelling at 20kmph against an airflow of 100 m3/s in a drive 5.0m/s. and the air velocity in the shaft will vary inversely according to the density. saturated. 7.0m/s in which this phenomenon occurs. is also decreasing. The shock loss pressure drop can be calculated from Page 138 © AMC Consultants Pty Ltd 2005 .0m/s is seen as the critical velocity this is not an exact figure and will vary according to a number of factors. When designing exhaust ventilation shafts in deep mines with potential for saturated air the velocity range between 7.5 m high and 5. If the velocity of the air is less than 8.11 Water in Upcast Shafts The processes of mining rely on the use of water for dust suppression and air-cooling.0 m/s it stands to reason that the water droplet will neither rise nor fall and will remain suspended at this critical velocity.1m high x 3. As droplets accumulate they form a ‘water blanket’ that increases the resistance in the shaft thus lowering the quantity of air flowing. This condensation process is evident by a ‘foggy’ appearance of the air. Water droplets may coagulate to larger droplets. As the stall point is reached the water blanket drops out and the fan may recover to recommence the cycle of water blanket formation and drop out. The effect is not as pronounced in shallow dry mines but the ‘critical velocity range’ should be avoided if there is potential for ground water to be present in the shaft. This results with water condensing out of the air. Obviously if the velocity of the air is 8.2 m wide. This ‘fog’ is small droplets of water that may coagulate to form larger droplets. 7m/s. For example.5 5 . In the second case.5 m/s.8 m/s) and the airflow in the 5.e.659 2 = 185 Pa In the same situation and only 25 m3/s the pressure drop would be 94 Pa In some cases the airflow in the decline may in fact reverse direction as the truck travels in the drive.2 kg/m3 then the pressure drop caused by the truck is 185 Pa. which in turn increases the turbulence of air around the vehicle causing the envelope to break up and significantly reduce the level of exhaust emission and dust contamination to which the operator is potentially exposed. This fluctuation of airflow may also occur in workings connected via a hoisting shaft. i.since the truck is travelling against the airflow) m/s Substituting these values into the equation: PShock 1.6 m2 y = 0. The consequences of any fluctuation cause by vehicles travelling around the mine are seldom great enough to warrant rectification.5 m x 5. it should be noted that the truck is travelling faster than the air.85 m2 Area of the drive = 28. This increases the relative velocity between the air and the truck.5 m ramp is 50 m3/s then the air velocity in the ramp is 1. if we assume trucks travel up ramps at a speed of 10 kph (2.BASIC MINE VENTILATION MANAGEMENT PShock Where: 2 y VA VT 1 y 2 PShock = the shock loss pressure drop (Pa) = the density of the air (kg/m3) y VA VT = Area of the truck (m 2 ) Area of the Drive (m 2 ) = Velocity of the air in the unobstructed drive (m/s) = Velocity of the truck relative to the airflow (m/s) Assuming standard air density of 1.56 (.659 VA = 3. with the air flowing down the ramp and 1.1 m/s with the air flowing up the ramp. To achieve a reduction in exhaust emission contamination levels the direction of airflow should be down the ramp. Area of the truck = 18. This gives a relative velocity between the truck and the air of 4. This only occurs in areas with extremely low ventilating pressure and other connections that operate in parallel with the decline. The main area for concern is when trucks travel up ramps as they do so in an envelope (recirculation) of engine exhaust contaminants.5 m/s VT = -5. usually returning to “the norm” once it has passed. Page 139 © AMC Consultants Pty Ltd 2005 . This occurs irrespective of the direction of airflow but when the direction of flow is UP the ramp and the truck is travelling in the same direction there is an increase in the potential for contaminants to build up to levels that will exceed the recommended TWA limits.6 1 0.2 2 0.659 3. The velocity in the drive (Q/A) is 1. Planning and scheduling for rates of advance are usually based upon experience of crews and the normal geotechnical and materials handling requirements of short development headings. This has the disadvantage of providing contaminated airflow to the working face whilst the trucks (or for that matter any other diesel powered equipment) are operating in the ramp. 7.e. Because of duct leakage. To reduce potential for exhaust emissions to build up to concentrations in excess of the MAC’s while travelling up ramps it is vital to ensure that engine performance is matched to the work rate required of the vehicle (i. would be only 8.e. For this reason estimates for long heading development rates can and are usually overstated as most neglect to consider the extended re-entry time as a direct result of the length of the heading and the subsequent time required to clear the blasting fumes. The concentration of contaminants in the affected parts of the mine often greatly exceeds the maximum TWA concentrations for a brief period of time until the fumes are diluted by the ventilation currents and removed from the mine.BASIC MINE VENTILATION MANAGEMENT In development headings causing air to flow down the ramp will require the installation of an exhaust overlap ventilation system. and an airflow of 25m3/s delivered in a forcing system.13 Re-entry after Blasting in a Development Heading Blasting is an intermittent activity carried out when people are removed from the underground areas affected by the fumes (gases and dust) generated by the blast. Because of the relative periods of time spent at the face and the hauling in the ramp. For example consider a long development heading 5. duct discharge velocity profiles and the distance of the duct discharge from the face it can be expected that these times could be increased by a minimum of 15 to 25 minutes (i. Gases produced by blasting are to a significant and variable degree either trapped in the blasted muck pile to be released slowly as the muck is removed or dissolved in water naturally present in Page 140 © AMC Consultants Pty Ltd 2005 . It is also essential to ensure that the engine is tuned and maintained to manufacturers specifications. re-entry times from 20 minutes up to 35 minutes).0m x 500m.3 minutes and in the scheme of things this is not considered to be of any concern. Assuming that all contaminants are contained in the plug that is being removed and all of the 25m3/s is sweeping the face the minimum clearing time from the face to the primary ventilation circuit. forcing ventilation systems are almost always used.0m x 5. These peaks generally have duration of a few minutes and occur whenever blasting takes place. the power to weight ratio).0m/s. Skochinsky (1969) 1 2 3 t t Q 7 . Gases produced from blasting include carbon monoxide (CO). Factors that impact on gas production include product manufacture and quality control.5 m3 And t 7 . Assuming 200 kg of explosives used in the blast and 20 m3/s is sweeping the face then Volume of the drive = 5.e. ammonia gases (NH3). Skochinsky (1969) and De Sousa (1993) have developed algorithms for calculation of gas clearance after blasting in development headings. the degree of confinement of the explosives (i.587 2 1 3 = 1.8 20 200 10.BASIC MINE VENTILATION MANAGEMENT the mine or used for dust suppression.5 x 350 = 10587.5m high and 5. A wide range of estimates exists of the amount of gas produced per kg of explosives used.5m wide 350 metres from the secondary fan. hole burden and spacing).t Q 2A x vt 4Et 2 Et Equation 7 Blast Gas Clearing (deSousa (1993)) C(x. moisture in the drill holes and the effectiveness of the initiating process. These algorithms are useful to gain some idea of what to expect but should not be relied on as the sole indicator of when it is safe to return to a blasted area. In the case of oxides of nitrogen the range is from 19 litres/kg to 33 litres/kg. In the case of CO references have been found to gas production rates between 1.t) = Gas concentration (multiply by 106 to get ppm) t x Q = Time after blast (seconds) = Distance to face (m) = Quantity of Contaminant (m3) Page 141 © AMC Consultants Pty Ltd 2005 . carbon dioxide (CO2).097 seconds = 18. It is estimated that up to 60% of the gases produced by blasting are either trapped in the muck pile or removed by dissolution. The only real indicator for safe re-entry is accurate measurement of the contaminants involved.5 x 5. sulphur dioxide (SO2) and oxides of nitrogen (NOX). The key contaminants are considered to be CO and NOx.8 Q MExplosives VDrive Equation 6 Blast Gas Clearing (Skochinsky (1969)) =Time for the air to clear (seconds) =Quantity of air sweeping the face (m3/s) MExplosives=Mass of explosives used in the blast (kg) VDrive=Volume of the excavated drive prior to the blast (m3) EXAMPLE Consider a development heading 5.2 minutes deSousa (1993) C x.25 litres per kg and 50 litres per kg. 5 = 30.977 1. Page 142 © AMC Consultants Pty Ltd 2005 .BASIC MINE VENTILATION MANAGEMENT A V E = Cross sectional area of the drive (m2) = velocity of the ventilating air (m/s) = Dispersion co-efficient (m2/s) E 28.142 38.17 (m2/s) Rh = (30. EXAMPLE Consider the development heading above and calculate the gas concentration for NO2 19 minutes after the blast.66 (m/s) E = Dispersion co-efficient (m2/s) E 28.17 1.17 1.140 = 0.25 3.8 0.008) r Rh = Hydraulic Radius (Area/[height + width]) (m) = Friction factor of the drive (if unknown use 0.015) This methodology will determine the concentration of the particular gas at a particular time.36 0.000005 (m3) or 5 (ppm) EXAMPLE 2 This methodology was used to estimate the clearing times for nitrogen dioxide (NO2) from a development heading 5.5m high and 5.5]) = 2.25 = 0.5m wide 350 metres from the secondary fan.5147 (m3) from table below Gas produced / kg of explosives (kg/kg) Density of gas 3 (g/m ) Volume of gas produced / kg of explosives 3 (m ) Mass of explosives used in firing (kg) Volume of gas produced from firing 3 (m ) Gas CO CO2 NO2 0.015 350 0.5 x 5.25 (m2) V = 20/30.082903 0.140 4 38.25/[5.75 0.75(m) = 0.1639 0.008 0.140 2 And C x.0035 1. (0.5 + 5. t = 19 x 60 = 1.008 r= 0.015 = 38.58 0.002574 200 200 200 2.66 1.140 (seconds) x = 350 (m) Q = 0.5147 A = 5.t 0.25 1.01304 0.5147 2 30.8 v Rh v r = Velocity of the ventilating air (m/s) = Friction Factor of a smooth walled drive.0163 0.66 2.61 16. “Advanced Ventilation Workshop” (1998) Page 143 © AMC Consultants Pty Ltd 2005 . 40 35 Concentration (ppm) 30 25 20 15 10 5 0 1 11 21 31 41 51 61 71 81 91 101 111 121 131 20 m 3/s Blasting Fume Clearing Times 15 m 3/s 5 m 3/s Safe re-entry level 2ppm 10 m 3/s Time (minutes) This clearly demonstrates the importance of adequate airflow sweeping the workplace. tC Where: V Q ln GC GR t = Time to achieve the require gas concentration (seconds) V = Volume of the gas filled space (m3/s) Q = Quantity of air sweeping the face (m3/s) GC = Initial gas concentration (ppm) GR = Gas concentration required (ppm) There are a number of steps required before the use of this equation 1..BASIC MINE VENTILATION MANAGEMENT The gas NO2 has been used because of its high toxicity. low exposure standard and the fact that it will take longer to dilute to safe levels than other gasses produced by blasting. Howes (1982)19 The following methodology has been adopted by some Australian mining companies as a standard to establish the earliest re-entry time. M. The results are shown graphically below.J. Calculate the fume throwback distance. (This is the initial volume occupied by the blast fumes L Where: K M FA D A L = Length of the fume throwback (m) K = Constant (Assume 25 for development headings) 19 HOWES. 0m.25 1.36 0.1639 0.0163 0.082903 0.977 1.Distance of throwback zone (m)] Area of drive (m 3 ) Airflow (m 3 / s) 5. Calculate the time for dilution to the exposure standard using the Blast Clearing G V Equation above t C ln C GR Q 6.BASIC MINE VENTILATION MANAGEMENT M = Mass of explosives used. 1.1 (kg/tonne). (kg) FA= Face advance (m) D = Density of the rock (kg/m3) A = Area of the face (m2) 2.002574 3. Assuming the face advance is 3.75 (m) Page 144 © AMC Consultants Pty Ltd 2005 . the rock density is 3. Calculate the time taken to mix in the drive.5m wide 350 metres from the secondary fan.1 (kg/m3) A = 30. Calculate the fume throwback distance L Where: L = 350 (m) K = 25 M = 200 (kg) FA= 3 (m) D = 3. 200 kg of explosives used in the blast and 20 m3/s is sweeping the face.01304 0. Calculate the concentration of gas in the in the drive. (At this step assume perfect mixing of the gas and the ventilating air) Time for mixing (s) [Length of drive (m) .0035 1.25 (m2) K M FA D A = 97.5m high and 5. Assume the drive volume after the blast GDRIVE GPRODUCED (m3 /kg) Quantity of explosives (kg) Volume of the Drive (m ) 3 10 6 (ppm) 4. Calculate the Volume of gas produced (m3) (A) (B) Density of gas (g/m ) 3 (C) (A) x (B) Volume of gas produced / kg of 3 explosives (m ) Gas Gas produced / kg of explosives (kg/kg) CO CO2 NO2 0. Determine the total time for clearing in seconds Clearing Time (s) Time for mixing Time for dilution EXAMPLE Consider a development heading 5. 064 seconds 34.BASIC MINE VENTILATION MANAGEMENT 2.25 1. Calculate the time taken to dilute the gas.01304 0.4 minutes 6.5] 30.36 0.4 + 24. tC 10542 20 ln 49 2 = 2.5 = 30. Calculate the concentration in drive GDRIVE 0.9 30.4 minutes 5.0163 0.14 Gases from Sulphide Orebodies See Section 2.002574 3.1639 0.2 25. Calculate the time taken for re-entry Time before re-entry = 6.9 minutes SUMMARY OF EXAMPLES Method Skochinsky (1969) De Sousa (1993) Howes (1988) Result (minutes) 18. Calculate the Volume of gas produced (m3/kg) (A) (B) Density of gas (g/m ) 3 (C) (A) x (B) Volume of gas produced / kg of 3 explosives (m ) Gas Gas produced / kg of explosives (kg/kg) CO CO2 NO2 0.977 1.082903 0.4 Explosive Dusts page 12 Page 145 © AMC Consultants Pty Ltd 2005 .0035 1. 7.002574 200 10 6 10542 = 49 ppm 4.25 20 =382 seconds = 6. Calculate the mixing time Time for mixing (s) [350 .97.9 Re-entry times are best established by measurement of the relevant contaminants combined with the local knowledge and experience of the people directly involved in the blasting and reentry process.2. 15 Gasses from Diesel Engines See Section 2.16.gas drainage. It is normally wise to vent the voids to exhaust. Methane drainage boreholes are bored into gassy strata in advance of the face. shaft hoisting etc).5 Diesel Engines page 41 7. An example includes: Bulk-heading off old workings. Examples include: Uranium mine .3 Isolation This involves separating personnel from areas where high concentrations of harmful gasses are known to be present. The required airflow rate can be calculated from the following formula: Q Where: Q = The required fresh air flow rate (m3/s) Qg = The gas flow rate (m3/s) AC = The target gas concentration Qg AC NC Equation 8 Dilution Equation Page 146 © AMC Consultants Pty Ltd 2005 .BASIC MINE VENTILATION MANAGEMENT 7. (i. Ammonia formation can be controlled by reducing ANFO spillage and shot-crete rebound.5 Dilution Dilution of undesirable gasses with fresh air represents a simple and effective method of control.ventilation system.2 Extraction The aim with this option is to extract gasses via as direct a route as possible to the surface. Coalmine .16. Sealing agents can include shot-crete or urethane coatings. 7. electric LHD’s.g. Mine locations that may be affected by blast fumes at firing time. 7. those in which harmful gasses are known to occur).16. Gas is extracted from the boreholes. Examples include: Uranium mine and coalmine return airways.1 Prevention Preventing the formation of harmful mine gasses is a simple and obvious control method. 7. since even with extremely efficient sealing. Examples of this approach include: Diesel exhaust gas concentrations can be reduced by using high efficiency engines with electronic mixture control or by using alternative power sources (e.e.16 Control of Mine Gases 7.16.4 Containment It is sometimes possible to seal off areas (dangerous gas concentrations occur) from the rest of the mine. it is difficult to control leakage due to changes in barometric pressure etc. 7. Radon daughter laden air is extracted from the stope void and flows directly to the exhaust ventilation system.16. The greater the volume of the goaf the more gas will be forced into the ventilation system. (a) (b) (a) (b) Sufficient airflow to dilute the gases to harmless mixtures Directing them away from men and machinery. These areas are usually sealed off and this allows the accumulation of gases such as methane. the pressure on the gas decreases and therefore the volume of the gas increases (Boyle’s Law). which receive little or no ventilation. However.17 Effect of Atmospheric Changes on Mine Strata Gases Many underground coalmines have goaf areas (old worked out areas). when the atmospheric conditions change and the pressure falls.e. Because the volume of the goaf cannot change some of the gas will be forced out into the ventilation system.04 0.BASIC MINE VENTILATION MANAGEMENT NC = The normal concentration of the gas in fresh air Example: Methane at 2% concentration has been detected in air flowing out of a stope via a drill drive. The total volume of the goaf.18 Spontaneous Combustion Although coal is considered to be a commonplace commodity it is extremely complex and differs widely from seam to seam. Designing the ventilation system to prevent this must include.01 0 4m3 / s i. Substituting
… Q 0. Page 147 © AMC Consultants Pty Ltd 2005 . As long as the gases remain within the goaf area there is no safety problem. thick or a composite. The quantity of air will depend on: The best way to ensure the gas is directed away from the work areas is to ensure that the goaf is connected directly to the exhaust air system. 7. The actual size of the fall is less important than the rate at which it occurs. Certain coal seams and carbonaceous shales have a tendency to oxidise at normal working temperatures and others are prone to spontaneous combustion. are of inferior quality. How much fresh air needs to be supplied to the drill drive (with a flame-proof fan and anti-static vent duct) to bring the methane concentration down to 1%? Methane flow rate = 2 100 2 m3 / s 0. since the pressure drop determine the rate of expansion of the gas. 4m3/s of fresh air is required to dilute the methane to 1% concentration. The measured flow out of the drill drive is 2 m3/s. A great deal of work has taken place over many years in an attempt to identify the exact components of coal that cause self-heating but as yet it is still not fully understood. What is known is seams liable to spontaneous combustion are those. The rate of fall of the atmospheric pressure. 7.04 m 3 / s The normal concentration (NC) of methane in air is 0. It is important to note that even if the goaf is sealed off they will nearly always “breath”. This hot now humid air condenses on the cooler surfaces outside the goaf. 4. As the longwall face retreats this region also retreats and remains at the same distance behind the face. humidity If the oxygen used up in the oxidation process is not replenished the rate of oxidation will slow and eventually cease when the content fall below 2%. ‘Smoke’ a fire is imminent. Deep within the goaf the quantity of air is insufficient to allow the oxidation process to continue and in fact the oxidation process uses up the oxygen. readily adsorb and desorb moisture when there is a large gap in humidity between the coal and the air.e.BASIC MINE VENTILATION MANAGEMENT are low rank (i. There are a number of signs that indicate a heating is in progress. In a longwall retreat goaf there is a region immediately behind the face in which the quantity of air is sufficient to remove the heat of oxidation. ribs or metal straps and washers used in ground support. a poor extraction sequence that leaves large stocks of broken coal. ‘Sweating’ is the condensation of moisture on the roof.100 C the oxidation process rapidly increases until the temperature reaches 650 C and ignition occurs. Between these regions there is a region that is conducive for spontaneous combustion. percentage of oxygen and. contain pyrites. 3. 5. Page 148 © AMC Consultants Pty Ltd 2005 . If sufficient heat is removed in the ventilating air then the heating will slow and temperatures will remain below ignition temperatures. Spontaneous combustion is most likely the result of poor mining practices such as: leakage of air through the goaf (this could be the result of high ventilation pressures) or. The heat produced by the oxidation process causes a rise in temperature. The airflow would be in sufficient quantities to replenish the oxygen but insufficient to remove the heat. increasing the rate of oxidation and again increasing the temperature of the coal. This results from high temperatures in the goaf area driving out the moisture contained in the coal. The presence of fine coal increases the rate of oxidation due to the relatively large surface area exposed to the ventilating air. ‘Hot air’ from the goaf is an indication that a heating is well advanced. Once the temperature reaches 80 . ‘Haze’ or ‘fog’ caused when the hot humid air from the goaf condenses in the cooler ventilating airflow. The circuits commonly used in Australia to prevent spontaneous combustion are shown below. A ‘smell’ comes under many names such as ‘goaf stink’. and have a high moisture holding capacity The spontaneous combustion process starts with oxidation at normal temperature (say 20 C) and the rate of oxidation is dependant upon the temperature. relatively young). 1. The classic spontaneous combustion occurs in broken ‘dry’ coal of mixed size with sufficient fines to have a large surface exposure and large lumps that create the voids for the passage of humid air. 2. ‘fire stink’ or ‘stink damp’. BASIC MINE VENTILATION MANAGEMENT Bleeder headings must be adopted with extreme caution as they pose a risk of promoting a heating or conversely having an unventilated goaf allowing a build up of gases that could be forced out by a change in atmospheric pressure. GOAF GOAF Tailgate Bleeder Heading GOAF Main Returns Maingate GOAF R Main Intakes Bleed Regulator should be kept adjacent to the face line to minimise leakage into the goaf Basic Longwall Ventilation (“R” System) GOAF GOAF R Return Maingate Intake Tailgate Intake Tailgate Return Maingate Intake Tailgate Intake Back Return System 7.19 Control of Dust “Y” Return System Once dust is liberated from the rock, it is transported to various parts of the mine in airborne form via the mine airways. When the relative velocity between a rock surface and the ventilating air exceeds 5.0 m/s the inspirable dust fraction adhered to the rock surface may be dislodged and will become entrained into the air stream. In underground mines this may occur whenever rock is moved from one point to another. The dust may come from two sources the exposed surface of the rock being transported or, from the roadway surface when dust, picked up by the tyres of vehicles, is entrained into the airstream. These occurrences are usually overcome by wetting the rock on either the load being transported or the roadway surface. Obviously in roadways with air velocities less than 5.0 m/s the problems associated with dust from tyre pick up is much reduced. Page 149 © AMC Consultants Pty Ltd 2005 BASIC MINE VENTILATION MANAGEMENT It is normal practice to apply water from either a water cart or overhead sprays onto underground roadways to allay dust pick up from tyres. The consequences of these systems are either not enough water or some times excessive water, particularly from overhead sprays, that causes erosion of the roadway that in turn requires constant maintenance to the roadway surface. In open-pit mining the use of additives to water has been used in attempts to reduce the roadway maintenance requirements. In recent years a number of underground mines have trailed these additives with varying degrees of success. Dust suppression agents come generally as water additives and are described by their respective manufacturers as either, Soil wetting agents (detergents), Binding agents (surfactants), or Compaction enhancers. Most of these agents have been manufactured with the objective to reduce roadway surfaces breaking up therefore reducing maintenance costs. It is important to note that all products are susceptible to water and have the same requirements for well constructed roadways, sloped to prevent water pooling. Some binding agents cause surfaces to become very slippery and any use of these products must be carefully considered. Water is the main cause of roadway erosion and poorly constructed roadways will always have high maintenance costs irrespective of the use of any wetting or binding agent for dust suppression. The three main methods for controlling dust in underground mines include: Application of water Dilution Ventilation Localised extraction ventilation Water. Application of water is by far the most popular (and usually the most practical) dust control method. Wetting the dust prevents it from becoming airborne. To be effective, the water should be applied (by spray jets) to the point at which the dust is liberated (e.g. at the drill bit, on the roadway, at the drawpoint etc). It is important to try to ensure that the spray water is as clean as possible. Muddy re-cycled mine water may introduce more dust into the mine when the water evaporates. Some dust types may be difficult to wet effectively with water and wetting agents called surfactants may need to be added to the water. A rule of thumb design criterion is to aim to supply between 1 and 5% of water to broken rock (on a weight for weight basis). It is not usually considered safe or advisable to apply water at ore handling facilities. This is because of the serious danger of mud rushes occurring in vertical storage facilities if an excessive build-up of water occurs. Dilution. In most underground mines, dust is produced at diverse and often numerous locations. The amounts of dust produced at the individual locations are sometimes quite small. In these circumstances, the reduction of dust concentration by dilution with an appropriate airflow rate is a legitimate method of dealing with airborne dust. Determining the amount of airflow required to adequately dilute dust on a mine wide basis is surprisingly difficult. The determination is complicated by the cyclic and dynamic nature of the mining process, the effectiveness of watering down dust and many other factors. Some design factors, which may assist, are listed below, however it must be emphasised that no two mines are the same and application of the factors must be tempered with practical experience: Page 150 © AMC Consultants Pty Ltd 2005 BASIC MINE VENTILATION MANAGEMENT In many mines, it has been found that satisfactory dust levels can be maintained if sufficient air is circulated to satisfy diesel exhaust dilution criteria (e.g. 0.05 m3/s per kW of rated diesel engine power). In all cases, the minimum air velocity to ensure adequate mixing and dilution must be greater than the lower limit of turbulent flow (about 0.1 m/s). Air velocities in intake airways and in airways in which men travel should be less than about 6 m/s. At higher velocities, increasing problems with re-entrainment of settled dust will be experienced. 7.19.1 Dust Extraction This involves exhausting dust-laden air from a point as close as possible to where the dust is generated, so that dust can be prevented from entering the main intake mine airways. This type of system is best suited to fixed facilities, such as ore passes, crushers and conveyor belt transfer points. In underground mines, it is almost always preferable from an overall cost (capital + operating) viewpoint to exhaust the dusty air directly to an exhaust airway. There may be some circumstances where the dust may need to be filtered so that the extracted air can be re-used. The most suitable filtration systems for the underground environment are generally wet type dust scrubbers, although fabric bag-house type filtration is sometimes also used. Dust is a result of the disintegration of matter and the size of the dust particle produced is determined by the impact per unit area. For example striking a rock with a hammer will split the rock into large pieces forming coarse dust particles. If we were to use the same force using a chisel it would break only a small piece of the rock into fine dust particles because the force is directed onto a much smaller area. Disintegration processes occur in many ways with crushing, grinding, blasting and drilling being the obvious ones. Other processes that cause dust particles to become airborne are those involving the transportation of previously broken material by loaders, uncovered trucks and conveyor belts. The liberation of dust particles to the atmosphere occurs when the velocity of the air relative to the vehicle is sufficiently high enough to cause dust pick up. Particle Size( m) 75 to 100 Pick Up Velocities (m/s) Quartz 6.3 5.3 3.1 7.4 6.3 4.2 Coal 5.3 4.2 3.2 6.3 5.3 4.2 Dry 35 to 75 10 to 35 75 to 100 Semi Dry 35 to 75 10 to 35 Dust is also liberated to the atmosphere whenever broken material is transferred e.g. conveyor, loading and unloading processes. The initial step in the design of a ventilation extraction system requires an accurate assessment of the volume flow required to effectively remove the hazard. If this calculation is incorrect then all following decisions regarding the ducting, fans and filters are also likely to be incorrect. Because a suction exhaust type system requires most of the principles of ventilation to be applied (also that the laws of airflow apply equally to both pressure and exhaust systems) we will focus our attention on the design considerations for an exhausting system. Ensuring adequate 'capture' of the contaminant is the first consideration and must take into account the following variables of the contaminant to be handled. Page 151 © AMC Consultants Pty Ltd 2005 7.g. This site must be chosen to take account not only of the thermal properties of the process but also the effects of gravity so as to avoid the larger particles falling out before reaching the influence of the hood. As shown in the figure below. if we were to hold a piece of string of length X at the centre of the duct and moved Page 152 © AMC Consultants Pty Ltd 2005 .BASIC MINE VENTILATION MANAGEMENT VELOCITIES FOR CAPTURE HOODS Type Of Emission Lazy Emission Low Velocity Emissions points Active Emissions mechanical screens High Velocity Capture Velocity 0. It is also important to site the hood in a position that will not allow personnel to come between it and the process source. Having determined the capture velocity and angle of the hood the next step is the siting of the hood and unfortunately the economic and engineering importance of this procedure is usually ignored or at least misunderstood. Transfer Points.g.5 m/sec 1. Transfer Points.0 to 10.5 m/sec 05 to 1.1. Grinding.g. Polishing Wherever possible capture hoods should be designed to enclose the entire process source.1 Hood Design Each hood is designed to control the velocity in all directions at a given distance from a point of exhaust.g. The efficiency of exhaust hoods can be greatly improved if they are shaped to gradually merge into the ducting and thereby improving the aerodynamics of the airflow.0 m/sec Fume Control Example Manual Activities e. Vibratory Screens.25 to 0.19. Aspiration Low speed Emissions e.0 m/sec 1. If this is not possible the hood should be located as close to the source as is practical and sited to make use of the direction of flow of the particles caused by the process. This is illustrated in the figure opposite that shows the rapid velocity decrease in the vicinity of an exhaust intake.0 to 2. Sawing. Vibratory Screens e. High Speed and rotary emissions e. 45 (m3sec) 2 2 2 If this same dust hood was repositioned 200 mm from the dust source and the capture velocity remains unchanged then the air volume becomes: Q = = = V(10 x X2+ A) 3([10 x 0.142 x 0.0 m/sec Q = = = V(10 x X + A) 3([10 x 0. and the cost of the installation is reduced as a smaller fan will be required. Page 153 © AMC Consultants Pty Ltd 2005 .32 ] + [3. they should only be used for hood face areas that are either square or circular.BASIC MINE VENTILATION MANAGEMENT it in any direction we would circumscribe a semi-circle and finally a hemisphere of radius X.22 + [3. it must never hinder the process otherwise the operator may remove it. the velocity pressure must exceed the thermally induced draught.58 (m2/sec) These results shows that by moving the hood closer the volume of air required is halved. Although we have shown that the closer the hood is to the source. Aspect ratio = Example Width Length What quantity of airflow is required when a hood of 400 mm diameter is placed 320 mm from a dust source with a capture velocity of 3.e. The airflow required to maintain this velocity may be calculated by the equation: Q = VA3 Where Q = Exhaust airflow quantity (m3/sec) V = Required capture velocity (m/sec) A = Area of the geometric shape (m2) Dalla Valle in the 1930's refined this equation to cater for circular or rectangular hood faces: Q = V (10 x X2+ A)3 Where Q V= X= A= = Exhaust airflow quantity (m3/sec) Required capture velocity (m/sec) The distance from the hood face to the process source (m) Area of the hood face (m) However this equation also has its limitations as shown by Fletcher in the '80's and should not be used for rectangular hood face areas with an aspect ratio not equal to 1 i.22) 1. To maintain the capture velocity at any point on the surface of this hemisphere we must ensure that sufficient air is drawn through the duct. In general hoods should be designed to approximately cover the area (larger never smaller) of the contaminant source and if this source process is hot.142 x 0.2 ]) 3. Air Velocities for Dust Transport Type of Dust (or vapour) Paint fumes Limestone Metal fumes (welding) Sandblasting Coal Lead dust Branch Duct Velocity (m/s) 8 to 10 13 15 18 to 22 20 28 Either making use of system damper plates or changing the cross-sectional area of the duct can achieve control of velocity inside ducts. particularly bends and it is therefore necessary to provide protection at these points.e. This velocity should be such to prevent any settling out of the particles as they are transported through the system. Duct material. Duct design should provide for maintenance after the plant has been installed and should therefore provide sufficient inspection and cleaning openings. Page 154 © AMC Consultants Pty Ltd 2005 . The other occasion they are used is when the installation space available prevents the use of the desired duct configuration. Ventilation circuits are designed to fit the operational requirements for a specific mine.19. to receive the maximum return on the investment.1. Many times. if however it is intended to expand either the system or the process they must be considered. 7. Any economic evaluation is carried out to determine the most cost effective alternative to meet these requirements. Branch pipe sizes must then be calculated to provide the volume of air required at each point.20 Economics of Airflow The objective of ventilation economics does not differ from the principles of any investment i. branching and bends are all critical as they all have the potential to provide excessive resistance (pressure loss) and add to the size of the fan. The use of damper plates is very expensive as far as system pressure losses are concerned and should be avoided wherever possible. To keep these pressure losses to a minimum ducting should be streamlined as far as possible by avoiding sharp bends or sudden changes of cross-section or cross-sectional area. It is also important to take precautions against corrosion and abrasion as particles may cause rapid wear in ducts. Alternatives evaluated may not necessarily include the optimum economic situation. size.2 Duct Design After having decided the capture velocities and calculated the airflow requirements for each hood the next step is to determine the optimum transport velocity inside the duct. it is a compromise between the engineering and the scheduling requirements to determine the most cost effective alternative.BASIC MINE VENTILATION MANAGEMENT Finally the hood face should be designed to have the smallest possible area that will be acceptable to the process operator. It should be noted at this point that the transport velocities should be slightly higher in main ducts than in branch ducts. 7. shape. 1 Cost of Airflow If the cost per unit of power to operate the fans is known and the airflow and pressure losses in an airway can be determined then it is possible to calculate the cost of power to provide the airflow.0m then the cost of power would be: P= P= × Q2 × 150 2 0.004 Ns2/m4) = 0.566 × 200 12.566 3 =114 Pa and Air Power (P x Q) =114 x 150 Page 155 © AMC Consultants Pty Ltd 2005 . ground conditions. 7.425 × 200 7.10/kW hour.10/kW per hour then = AP x unit cost of power = = or = kCL A3 72 x $0.064 3 × 150 2 = 481 Pa the airpower is AP = = = = Cost of Power PxQ 481 x 150 72.004 × 9. accounting procedures of the mine etc.20.BASIC MINE VENTILATION MANAGEMENT Ventilation costs should be regularly monitored as changing cost in any of the variables may alter the cost effectiveness of circuit design. what would be the annual cost of power for a flow of 150m3/s in a 3. rock type.0m diameter 200m long concrete lined airway? From Atkinson’s ventilation equation P= KCL A3 × Q2 then determine the pressure losses for the airway (for a concrete line airway assume k = 0.004 × 12.20/hour $63. Example If the cost of electrical is $0.072/year If the diameter of the shaft was increased to 4.150 watts 72 kW and the cost of power is $0. It is extremely difficult to provide a single set of economic factors for ventilation studies as costs such as development and power will vary from mine to mine (due to location of the mine from services).10 $7. and cost of power for 1 year would be: = 17.BASIC MINE VENTILATION MANAGEMENT =1710 Watts or = 1. In all cases it is simply that point where the total cost over the life of the airway (or system) is at it’s lowest. I.979 Cost of Power + Cost ($) From this it becomes obvious that the cost of power decreases as the cross sectional area of the airway increases. the airways of highest resistance are the primary intake and exhaust airways. + + 0 Using the variable operating (power) cost and Airway Diameter (m) fixed capital (development and fans) the airway can be evaluated to determine the lowest total cost for a specific quantity of air over the life of the airway.710 kW. 7.10 x 24 x 365 = $14. This is achieved by the simple addition of the operating costs (power) and the capital costs (development and fans) for a number of airway diameters. “optimum velocity” or “optimum cross-sectional area”.1 x 0. the cost for development increase as the cross sectional area of the airway increases. Cost ($) 0 Besides the operating costs of power there is also the capital cost for development of the airway. Simplistically the larger the cross sectional area of the airway. Page 156 © AMC Consultants Pty Ltd 2005 . The pressure loses in these airways can be 90% of the total mine losses and therefore require most consideration.2 Optimum Airway 0 0 Airway Diameter (m) + In most mines. the more rock to be broken and removed therefore the higher the cost.20.e. Although the cost of power initially decreases quite rapidly it then levels out until the cost savings become relatively insignificant with each incremental increase in airway cross sectional area. Capital Cost One of the frequently used terms associated with ventilation economics is “optimum diameter”. This is because inflation influences the purchasing power of the money not the amount of money.e.BASIC MINE VENTILATION MANAGEMENT Project Cost + Decreasing Operating Costs Operating + Capital Cost Cost ($) Economic Diameter Increasing Capital Costs 0 0 Airway Diameter (m) + 7.000 in 10 years discounted at 10% is $385.000 at the end of 6 years if interest is 10%? F = P(1 + i)n = 1. we should consider that the money need not be spent and it could be invested. the expenditure must return the original and operating expenditure equivalent to interest rates which could be earned by investing the money.000 at 10% it would be worth $2.000(1 + 0. The Time Value of money refers to the effect that interest rates (as returns from potential investment opportunities) can have on the value of money and not the effect of inflation.75 in 10 years time (excluding tax) and if you wanted to have $1.3 Time Value of Money When considering the operating costs particularly over a long period of time it is important to consider the time value of money. the Present Value of $1.593.54 at 10% today i.20. Thus for a given project.1)6 Page 157 © AMC Consultants Pty Ltd 2005 . This concept of Present Value makes no mention of inflation. The future sum of our investment can be calculated from F = P(1 + i)n Where F = Future Value ($) P = Present Value invested ($) i = Interest rate % (rate of return on capital) n = Number of interest compounding periods usually yearly Example What is the future value (F) of $1. When considering expenditure on ventilation airways. For example if you were to invest $1.54.000 in 10 years time you would have to invest $385. BASIC MINE VENTILATION MANAGEMENT = $1. i.61 This shows the future value of yearly investments of equal value.1 0 .000 at 10% interest.26.355. A (1 + i)n 1 P= 1 i(1 + i) = 1.156. If we were to invest money as a series of equal investments. 7.56 Similarly. When using any Page 158 © AMC Consultants Pty Ltd 2005 .20)20 = $26. each investment draws compound interest for a different number of periods. many are contradictory and many are now no longer applicable.000 = (1 + 0.1)6 1 0. The future amount of money from this type of investment is calculated by: F A 1 i i n 1 Where A = Amount Invested ($) Example Calculate the future value (F) 6 years from now with yearly investments of $1.000 payments made at the end of each year of 6 years if the compound interest is 10% per year.21 Rule-of-Thumb Principles and Design Factors There are a large number of ventilation rule-of-thumb (ROT) principles that have evolved over many years.08 This shows that $26.000 × (1 + 0.000 1 0. P= F (1 + i)n 1. if we know the value of a future sum we can determine the Present Value by solving for P.000. Both of these functions deal with single payment present values. Should we wish to know the present value (P) of a series of $1.355.000 payments made each year for 6 years with a compound interest of 10% $4.1(1 + 0.e.26 Thus the Present Value of a series of $1. 1.08 invested today for 20 years at 20% interest will grow to $1.1 6 1 = $77.771. We can use the following equation.1)n = $4. Listed below are some factors encountered by the author over many years.20.000 people underground and the airflow would be between 188 and 940 m3/s.15.000 kW will require 252 and 504 m3/s (b) (c) Velocities in airways Service Shaft 5.5 – 5.1 Exhaust mains 10. Before using any of these values the origin and circumstances of the factor should be fully understood.6 Conveyor tunnels.094 – 0.2 . One site on the Internet (www.6 – 10.5 m/s in saturated airways.3 Exhaust shafts (rock section) 10. Page 159 © AMC Consultants Pty Ltd 2005 .7.024 – 0.5 m3/s.6 .094 m /s per tonne of ore and waste produced in the mine (it is assumed that this refers to a daily production rate) 0. but mine ventilation systems must be designed specifically for each and every mine.063 – 0. Rule-of-thumb factor Fresh air quantities (a) 0.2 .1 Inlet and exhaust rises (no access) 10.2 Avoid 7.2 Main Entry 2. There is some basis for the use of ROT principles particularly when attempting to “get a feel” for what may be required.000 tonne of ore and waste.0 Inlet and exhaust rises (access required ) 2. For diesel equipment 4.1 – 7.5 to 12.000. declines 2. However in a labour intensive operation there could be 2.7 and 23. as no two mines are identical.5 – 5.BASIC MINE VENTILATION MANAGEMENT ROT they must be placed in the correct context and this can only be done successfully if there is a good understanding of the basis from which the specific ROT has been derived. 3 Comment Consider a modern mechanised mine producing 1. Although experience should not be ignored and basing ventilation design specification on past and present practices in comparable mines can and has led to near disastrous consequences of over and under ventilated mines. From (a) the quantity of air should lie between 65 and 257 m3/s A modern mine may have 50 people underground therefore from (b) the quantity of air required is between 4.mcintoshengineering.2 Exhaust shafts (concrete lined) 15.6 Production Shaft 7.com) provides a comprehensive list of ROT principles.126 m3/s per kW of operating diesel equipment.47 m3/s per man underground 0.2 – 15. At first a simple series circuit. DEF. DY. companies must rely more and more on individuals to come up with new ideas. competitive and fast moving world.“The Change Masters” 8 8.1 NETWORKS AND COMPUTER MODELLING Ventilation Networks In section 4 we looked at simple series and parallel circuits. Innovations.) interconnected in such a way that it is impossible to reduce them to simple series or parallel circuits.BASIC MINE VENTILATION NETWORKS AND COMPUTER MODELLING “in today’s increasingly uncertain. YF and FGH. CXYFEDC and ABCXYGHA. expanding when a new area is opened up creating a parallel circuit and finally the connection of the two working areas resulting in a network of airways. market strategies. to develop creative responses and push for changes before opportunities disappear or minor irritants turn into catastrophes. This network of airways can. DYFED. Y and F.” Rosabeth Moss Kanter . (Total 4) D Area 1 E B C F G Parallel circuits CDEF and CXYF with common junctions C and F Page 160 © AMC Consultants Pty Ltd 2005 . D. Consider the following figure to represent three possible stages for development of a mine. junctions and meshes. CXY. with the use of computers be analysed to predict airflow quantities and pressures. CD. Mines consist of many airways (including stope voids open orepasses etc. are designed not by machines but by people. technological processes or work practices. Branches (connect junctions) and are ABC. whether in products. (Total 6) Note: a branch is any series of airways and may have different dimensions and must be included at least once in the group of meshes Junctions (two or more branches) C. A H A H D Area 1 E D Area 1 E B C Series circuit ABCDEFGH F G B C F G X A H Area 2 Y Compound or Network System The construction of airway DY now presents a different problem consisting of branches. (Total 4) X Area 2 Y Meshes (and closed circuit) CXYDC. The sum of the pressure changes in a mesh is zero. The solution of networks is undertaken with the following assumptions: 1. The airflow in the network obeys Atkinson’s law Kirchhoff’s electrical laws can be restated and applied to ventilation networks i.e. M. b – j +1 meshes m and writing equation. However only j – 1 of these are independent because the jth junctions are already defined by flows at other junctions and therefore there are b – (j – 1) equations to construct.J.BASIC MINE VENTILATION NETWORKS AND COMPUTER MODELLING The solution of the series and parallel was explained in section 4. The total quantity of air entering a junction is equal to the total quantity leaving the junction. For a network containing m meshes the powers of Q would be 2 m -1 For a detailed discussion on Network analysis refer to McPHERSON. Pi Pfi NVP m 0 for each of them.239 20 Environmental Page 161 © AMC Consultants Pty Ltd 2005 . pp211 .2 Analysis of a Network20 The solution of a network requires the determination of the characteristic of each and every airway. (1989) Chapter 8. m Pi i 1 Pfi NVP m 0 Where density is constant m = number of branches forming a closed mesh Pi = frictional pressure drops. Air is incompressible and. These are obtained by choosing a minimum of. 1. “Ventilation Network Analysis” Engineering in South African Mines. When written in terms of P = RQ2 a quadratic equation for each mesh can be developed to find the solution. the number of branches. Pfi = total pressure drop across the fan NVP = natural ventilating pressure. From Kirchhoff’s 1st law for a network containing ‘b’ branches and ‘j’ junctions there will be ‘b’ airflows to determine and therefore ‘b’ equations must be solved. Similarly from Kirchhoff’s 2nd law there will be ‘j’ equations to be solved. 2.. In the simplest case of a mesh without a fan and no NVP this reduces to m Pi i 1 0 These equations are only correct when all terms are considered at standard density 8. This gives j –1 junction equations from Kirchhoff’s 1st law and b – j +1 mesh equations from Kirchhoff’s 2nd law. S Qi i 1 0 2. the number of junctions and the number of meshes. P = RQn P = RQn Pressure drop P Q P P = RQan Qa Quantity Q Q n is the constant for the range of flow considered. Q Q a Q where Q is the error for quantity.1 Hardy Cross The technique of fluid network analysis involves making an initial estimate of the flow distribution and calculating an approximate correction to be applied to the flow in each branch and then iterating the correction until and acceptable result has been achieved. and other techniques should be considered. Similarly P is the corresponding error for pressure. Consider the figure below and assume a quantity Q passing through a duct.e. The technique that has found its place in mine ventilation calculations is the one developed by Professor Hardy Cross in 1936.BASIC MINE VENTILATION NETWORKS AND COMPUTER MODELLING In relatively simple networks there is an application of this method but it falls short in large networks in much the same way as simple series and parallel circuits in networks.2. To determine Q an estimate of Qa is made i. 8. Differentiating P=RQn we find Slope of the curve Or at point Pa P Q Q nRQ a P nRQ a RQ n n 1 n n 1 P Q nRQ n 1 But P RQ a Page 162 © AMC Consultants Pty Ltd 2005 . but the answers are often wrong. the supplied shock loss equivalent lengths are grossly misleading and should never be used. but computer literate engineers to have a go. Repeat steps (c) and (d) until values of Qm are below the prescribed value. of junctions + 1 (c) (d) (e) (f) 8. Computer Modelling Modelling of ventilation systems with computers can be an excellent tool to assist with ventilation system design. The user of computer simulation software should have a very clear idea of what questions need to be answered – before any data is entered. Considering a network with b branches and applying Kirchhoff’s laws and assuming the index n = 2 for a fully turbulent flow we can derive the mesh correction factor Qm to be b R i Q ia Q ia Qm i 1 b Pfi S fi 2R i Q ia i 1 Q ia is the absolute value and S is the slope of the fan characteristic. The aim of this section is to provide some practical advice so that some of these problems can be avoided. Repeat steps (b) to (e) for each of a number of changes to the network. ventilation simulations are not a magic panacea. particularly if the model contains a large number of short airways. Impressive graphical output is produced. The main reasons for undertaking a simulation are listed below: Page 163 © AMC Consultants Pty Ltd 2005 . The minimum number is determined by No. However. In one popular computer package.BASIC MINE VENTILATION NETWORKS AND COMPUTER MODELLING Therefore Q RQ n RQ a n 1 n nRQ a which is the “out of balance” equation in a single duct. This can cause significant problems. The models are often not checked against “reality”.3 For each mesh evaluate the mesh correction factor Qm. Some computer packages add shock loss factors automatically (by default) to every mine airway. This appears to be due to a basic unawareness of how to take simple ventilation pressure measurements and compare these with simulated values. of branches – No. The procedure for the use of this method is described as follows: (a) (b) Estimate the quantity of air flow through each branch Decide on a pattern of closed meshes and determine the number. Inexperienced users often use the default input values (because the user is often unsure what the proper values should be). They do not replace a good working knowledge of basic ventilation theory and practice and the following problems are very common: The “user friendliness” of the latest software and the ability to directly import 3D mine design data has encouraged large numbers of inexperienced. Correct the flow in each branch. which they won’t do. Before importing the data into the simulation package. means that ventilation models can be constructed to represent every opening in the mine. small escape rises etc which do not carry significant airflow) are excluded. Computer simulations will not design your ventilation system for you! Important aspects like the economically optimum shaft sizes etc must be determined by separate calculations. Some brief information is provided here on some aspects of input data. For example. or where the driving pressures in individual parallel circuits are low).4 Input Data The old adage of “garbage in.BASIC MINE VENTILATION NETWORKS AND COMPUTER MODELLING Estimation of fan duty requirements (for primary fans and circuit fans). ore passes or stopes being bogged empty). Page 164 © AMC Consultants Pty Ltd 2005 . in more complex ventilation circuits. 8. This along with the ability to import data from other software used to design mine openings. including: Standard (non thermodynamic) computer simulations will not estimate airflow distribution where natural ventilation pressures are significant (i. There are a number of advantages in this approach including: The model is a more manageable size. Computer simulations will not provide an accurate estimation of all airflows in every part of the ventilation circuit. and they are generally the only person who understands it. Estimation of general airflow distribution. it is wise to reduce the number of points used to define the model.2 Number of Airways Modern simulation programmes have the facility to import centre line string data from 3D mine planning packages. In many mines (particularly larger ones).1 Simulation Model Layout For many years the use of a “skeleton” model has been seen as the best approach. where significant temperature differentials exist. It should be appreciated that computer simulations are not a ventilation design “black box” There are a number of things.000) of branches to be used. 8.e. for any real certainty in all predicted airflows. whereas this could perhaps be reduced to three or four points.4. 8. whilst still retaining a presentable 3-D format. In these models main airways are included. This provides the advantage of other people being able to ‘view’ the network in the same manner they would view survey or design plans.4. garbage out” well and truly applies with ventilation simulations. reducing the chances for data entry error Quicker simulation time and faster screen manipulation for 3-D programs Minimal loss in accuracy if removal of unimportant airways is done with care As always there are also a number of disadvantages The person who developed it owns the model.g. Does not allow for any predictive work other than primary fan duty to be undertaken Does not allow the model to be used to “problem solve” the ventilation system Today’s software packages allow the use of a large number (20. there are too many variables.g. The advantages are a less unwieldy simulation model with very little reduction in accuracy. but minor ones (e. the raw data may use 20 or more points in series to define a bend in a decline. which change on a regular basis (e. 4.4 Shock Losses Shock losses seem to be a major source of misunderstanding and error in ventilation simulation work. Note that the Atkinson Friction Factor for drives. right angle bend). If at all possible. (m) It can be seen from the above equation that the equivalent length is directly proportional to the hydraulic diameter and inversely proportional to the Atkinson friction factor of the equivalent length airway (i.4.2m airleg rise (k = 0. Shock factors generally only need to be applied to “dog legs”. Some notes outlining the problem in more detail are presented below: The equation for the equivalent length of a shock loss is given as Le Where: Le = equivalent length of shock loss (m) X = shock factor k = Atkinson Friction Factor). 8. One program misleads the user into believing that an “equivalent length” shock factor can be used to accurately describe a particular shock loss (e.5 Fans XDh 6. (1978) is a very useful source of information on shock factors. rather than ‘X’) 8. inlet losses and discharge losses in main ventilation raises etc.015) = 12m of 1. For illustration. using the above formulae. equivalent length for a given shock loss is not constant. regardless of the airway size or roughness. the equivalent length of the same discharge loss (X=1) from a 4m diameter raise bored hole (k = 0. B. Until there are some changes made in how shock losses are dealt with in some of the simulation packages. “Woods Practical Guide to Fan Engineering” Daly. Most programs require fan pressure in terms of fan static pressure. That's quite a difference in equivalent length! It is important to recognise and understand the problem outlined above. etc includes an allowance for “normal” shock losses (decline bends etc). it is strongly recommended that all shock losses be calculated separately. gauge and tube pressure surveys should be undertaken to determine “typical” local friction factors.2m airleg rise. some fan suppliers only provide fan total pressure Page 165 © AMC Consultants Pty Ltd 2005 .3 Friction Factors Friction factors vary for different types of airways (and different airway sizes). Two common problems are evident: One program applies a shock factor to every new airway by default.2m x 1. (Note that Daly uses ‘K’ for the shock factor.e. Ns2m-4 Dh = Hydraulic diameter (m) =(4 * A)/ C A = cross-sectional area (m2) C = drive perimeter. Unfortunately.4. the resulting combination of default shock losses can cause the simulation model to substantially overestimate the total mine resistance. In contrast.BASIC MINE VENTILATION NETWORKS AND COMPUTER MODELLING 8.g. If the model is constructed from a large number of very short airways in series. B. The problems caused by the equivalent length concept are almost universal.67k Ventilation programs have the facility to enter fan curves. the equivalent length of a discharge loss (X=1) from a 1.004) = 150m of 4m raise bore. but depends on airway size and roughness characteristics). Page 166 © AMC Consultants Pty Ltd 2005 . Excessive use of fixed airways will overly constrain the simulation model and may result in errors or program crashes. regulator pressures and major airway flows should always be made. The required fan static pressure can be read off the simulation results.BASIC MINE VENTILATION NETWORKS AND COMPUTER MODELLING curves. 8. (i. “Calibration checks” against existing fan pressures. Most of the time. before using simulation models to predict future ventilation system performances.e. the flow in a decline should never normally be fixed. Fixed airways should never be applied to locations where there are no ventilation controls (e. A fan static pressure curve (including pressure losses or regains from associated fan inlet and discharge ducting) should always be requested when ordering primary mine fans. the required fan static pressures can be determined by “fixing” the flow in the primary exhaust airway(s). unless a control such as a set of doors or booster fan is planned). Even then this should be a temporary fix and once the resistance has been determined the fixed airflow should be replaced with the appropriate resistance.) 8. If a large number of fixed airflows are required.g. it generally means that airway resistances have been incorrectly determined and therefore need to be adjusted. the only airways that should be fixed are airways with ventilation controls (e.6 Fixed Airways Fixed airways should be used very sparingly. the wall roughness or the cross sectional area needs to be looked at. An appreciation of the limitations in accuracy with the technique (due to uncertainties in input values) is required. When simulating a new mine to determine the required primary fan duties.g.g. Agreement to within 15% of actual airflows is about as good as can be expected. fans or regulators). Fixed airways are generally only used for airways where the resistance is difficult to measure (e. lack of accessibility etc).5 Results: For existing mines.4. S. “Occupational Exposure Limits for Novel Work Schedules. (Editor. J.J. M. (Chapter 29 pp773-790) Published by The Mine Ventilation Society of South Africa. R.H. June 21-23. SCALA. 5.J. p 113.. Australian institution of Mining and Metallurgy. 12. 16. M.L.J..R.J. H.. BOSSARD.. . N. 1988”. Johannesburg 9th – 24th February 1959. Bossard . 1993.W..C.H. (Editor. A. 8. R.Environmental Engineering in South African Mines”. “Particulate Clouds: Dusts. 9. 13. R. P. “The History of Mine Fans in South Africa” The Journal of the Mine Ventilation Society of South Africa. Proceedings of the 6th US Mine Ventilation Symposium. “Woods Practical Guide to Fan Engineering” (Published by Woods of Colchester 1978) de la HARPE. 14. Published by The Institute of Mining and Metallurgy. 10.J. 1984” The institution of Mining and Metallurgy (1984) Page 167 © AMC Consultants Pty Ltd 2005 . E. and LANE.D.) Proceedings of “Fourth International Mine Ventilation Congress Brisbane. (1988) GREEN. “Filtration Of Underground Ventilation Air by Wet Dust Scrubbing”.. 4. R. (1989) HOWES. GILLIES. “Psychrometry and Psychrometric Charts – Third edition” Chamber of Mine of South Africa. F. L. JENNER. Society for Mining. A.J.” American Industrial Hygiene Association Journal. F.“Mine Ventilation and Air Conditioning” HATCH. 11. & F. London (1964) HARTMAN. LEONTE.J. 1975 DALY. M. H. “Air Pollution . (December 1986) DeSOUSA. M. Australia. Spoon Ltd. E. A. ENRIGHT. “AMIRA – Sulphide Dust Explosions Volume 2 – Detection and Preventative Measures..W. BLUHM. JONES. LANCASTER.T.Manual of Mine Ventilation Design Practice References & Further Reading 1.B. Smokes and Mists”. “Advanced Ventilation Workshop” (1998) 17. Metallurgy and Exploration Inc...J. T.. H. 2. et al (1993) Blasting Fume Prediction and Control as a Means of Reducing Ventilation Costs. R. (Editor. W. England. M. LEONTE. 36: 467-469. B. If a person is devoted full time to the study and practice of mine ventilation and has access to another well qualified mine ventilation engineer the average engineer will start to become reasonably proficient in the basics of mine ventilation after a period of one to two years” F. London (1984) BRIEF.. 3.. AMIRA “Mine Ventilation Measurements . “A Manual of Mine Ventilation Design Practices Second Edition (1983) BOOTH-JONES. HOWES. HEMP.BASIC MINE VENTILATION References & Further Reading “the best way to learn the practice of mine ventilation is to slug it out in an environmentally tough underground mine for several years. ANNEGARN. 18. Harrogate.A Manual of Recommended Practice” BARENBURG.) Proceedings of “International Mine Ventilation Congress – Johannesburg 1975” Mine Ventilation Society of South Africa (1976) HOWES.. “Respiratory Dust Retention and Elimination” Proceedings of the Pneumoconiosis Conference. (pp209-213) Proceedings of the 3rd International Mine Ventilation Congress. Project P316A-P316B (1990 –1995)” (1996). “AMIRA – Sulphide Dust Explosions Volume 1 – Cause and Prevention in Development Headings Project P316-P316A (1990-1994)” (11 May 1995) ENRIGHT. M.) Proceedings of “Third International Mine Ventilation Congress.132) 15. 7. 6. L. S. (pp219-228) Proceedings of the 3rd International Mine Ventilation Congress. H. . JORGENSEN.H.E. Colorado. USA 1997”. (Chapter 12 pp313-335) Published by The Mine Ventilation Society of South Africa. W. KRYNICKI. R. R. (Churchill Ltd.. and Petroleum Engineers. “Characterisation of Sonically Atomised Water Spray Plumes”. (1989) SCHRÖDER. M. J. Published by Society for Mining.. J.Environmental Engineering in South African Mines”. Metallurgy. Published by The Institute of Mining and Metallurgy.A. V.. “Blast –Induced Dust” Proceedings of the 6th International Mine Ventilation Congress.. “Mines Rescue and Gas Detection” (1985) BURROWS. Inc.. 28.“Guidelines for Safe Mining” (2001) SKOCHINSKY. J. (Editor) “Proceedings of Sixth International Mine Ventilation Congress Pittsburgh. 31.J.H. Pennsylvania.Johannesburg 9th – 24th February 1959. Mine Ventilation. (1989) SHRÖDER.J. M.L.. Inc (1980) ORENSTEIN. KOMAROV. J. 27. (1997) SANDYS. Metallurgy. (Editor) “Proceedings of the Pneumoconiosis Conference . KRÜSS. Society for Mining. (Editor) Proceedings of “Second International Mine Ventilation Congress 1979” American Institute of Mining. 34. J.. Moscow (1969) STRANG. H. Page 168 © AMC Consultants Pty Ltd 2005 . 32. London (1984) New South Wales Department of Mineral Resources . (Chapter 15 pp379-394) Published by The Mine Ventilation Society of South Africa.E. and SZYMANSKI. 33. RUNGGAS. (Editor) “Fan Engineering” Published by Buffalo Forge Company (1983) Le ROUX. A. Inc Littleton. (1997) “Proceedings of Fifth International Mine Ventilation Congress” (1993) RAMINI. 26. MIR Publishers.BASIC MINE VENTILATION References & Further Reading 19. “Design of Auxiliary Ventilation Systems for Long Drives” Fifth Australian Tunnelling Conference. “Sources and Methods of Dust Control Environmental Engineering in South African Mines”. and Exploration. “ The Properties and Effects of Dust . PARTYKA.“Subsurface Ventilation and Environmental Engineering” MOUSSET-JONES. (Editor) “Environmental Engineering in South African Mines” Published by The Mine Ventilation Society of South Africa (1989) VUTUKURI.. “Mine Environmental Control Fourth Edition (1990)” McPHERSON. and Exploration. P. 30. J.P. 29. J. London 1960) 23.S. 24...H. Metallurgical..J. MacKENZIE-WOOD. 22. V. P. QUILLIAM. F. A.” South African Council for Scientific and Industrial Research. 21. 20.V. Sydney (1984) 25.M. au PERTH 9 Havelock Street West Perth WA 6005 Australia Telephone: +61 (0)8 9481 6611 Facsimile: +61 (0)8 9481 6622 email:
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