MAJOR TESTTARGET : PRE-MEDICAL 2014 Path to Success CAREER INSTITUTE KOTA (RAJASTHAN) T M FORM NUMBER CLASSROOM CONTACT PROGRAMME (ACADEMIC SESSION 2013-2014) PAPER CODE 0 1 C M 4 1 3 0 9 9 Corporate Office CAREER INSTITUTE “SANKALP”, CP-6, Indra Vihar, Kota (Rajasthan)-324005 Trin : +91 - 744 - 2436001 Fax : +91-744-2435003 E-Mail:
[email protected] Website: www.allen.ac.in ENTHUSIAST, LEADER AND ACHIEVER COURSE INSTRUCTIONS ( f u n s Z ' k ) 1. A seat marked with Reg. No. will be alloted to each student. The student should ensure that he/she occupies the correct seat only. If any student is found to have occupied the seat of another student, both the students shall be removed from the examination and shall have to accept any other penalty imposed upon them. ¤ · ¤ + l ¤ ¤| · | i + | · l ¤ª º ™ z | - - + ~ - =| · ª · | | - l - ¤ - t - · | | ¤ ~ ¤ - l - ¤ - ª · | | - ¤ · t i ¤ a + ¤ l · + | : l ¤ ¤| · | i l + =i · ¸ =· l ¤ ¤| · | i + ª · | | - ¤ · ¤ a | ¤ | ¤ | ª ¤ | - | · | - | l ¤ ¤| l · | ¤ | + | ¤ · i - | | + - | = ¤ | t · + · l · ¤ | ¤| ( ª | ~ | · · | - | + | + | : ~ - ¤ ¤ n | - | · | i ª ¤ i + | ¤ t | ª | + 2. Student can not use log tables and calculators or any other material in the examination hall. l ¤ ¤| · | i ¤ · i - | | + - | n n | ª º ¤ n , + - + ¸ n º · ¤ | l + =i ~ - ¤ =| n ª i + | - ¤ ¤ | ª - t i + · =+ - | t + 3. Student must abide by the instructions issued during the examination, by the invigilators or the centre incharge. ¤ · i - | | + =n ¤ l ¤ ¤| · | i + | ¤ · i ¤ i - | + , | · | l · ¤ ª ¤ l - · z | | + i ¤ | n - | + · - | ~ | ¤ z¤ + t + 4. Before attempting the question paper ensure that it contains all the pages and that no question is missing. ¤ z - ¤ z t n + · - = ¤ t n l ¤ ¤| · | i ~ | z ¤ ª - t | ¤| ( l + : =n =· | i ¤ ¤ = n · - t ~ · | ¤ | - t i + 5. Each correct answer carries 1 marks, while one third mark will be deducted from the total of individual subject for each incorrect answer. ¤ · ¤ + =t i - Ÿ | · + 1 ~ + t ¤¤ l + ( + l - t | : ~ + , ª n - - Ÿ | · + | - = l ¤ · | ¤ + + n ~ + | n = + n + · l n ¤ | ¤| ¤ ª | + Do not open this Test Booklet until you are asked to do so / : = ¤ · i - | | ¤ l ª - + | + | ¤¤ - + - | º | | n ¤¤ - + + t | - ¤| ( + Note : In case of any Correction in the test paper, please mail to
[email protected] within 2 days along with Your Form No. & Complete Test Details. - | º · ¤ l · : = ¤ z - ¤ z n + | : Correction t | - | œ ¤ ¤ | ~ | ¤ + Form No. ( ¤ ¤ ¸ º | Test Details + =| · | z l · - + ~ - · ·
[email protected] ¤ · mail + · + Your Target is to secure Good Rank in Pre-Medical 2014 FULL SYLLABUS AIIMS # 04 DATE : 22 - 05 - 2014 22–05–2014 PRE-MEDICAL : ENTHUSIAST, LEADER & ACHIEVER COURSE 1/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST AIIMS 1. Cell wall of Archaebacteria is made up of :- (1) Peptidoglycan only (2) Carbohydrates only (3) Protein and polysaccharids (4) Lipids only 2. Which one group of ribs are included in vertebrochondral ribs ? (1) 7 th , 8 th & 9 th paris (2) 8 th , 9 th and 10 th pairs (3) 9 th , 10 th and 11 th pairs (4) 11 th and 12 th pairs 3. Respiratory central chemoreceptor are. (1) Bathed in CSF, (2) Respond to increase in pH (3) Bathed in ECF (4) All of above 4. Which of the following statement is incorrect? (1) The first mammals were like shrew (2) Mammals were more intelligent in sensing and avoiding danger at least (3) When reptiles came down mammals took over this earth (4) Due to continental drift when north America joined south america these animals were overridden by South American fauna. 5. If a prokaryotic cell has following properties then identify the type of cell. (i) High content of peptidoglycan in cell wall (ii) Presence of Techoic acid (iii)Sensitivity with penicilline antibiotic (iv) Thick cell wall Options :- (1) Gram -ve bacteria (2) Gram +ve bacteria (3) Mycoplasma (4) All of the above 6. The first heart sound "Lubb" is associated with :- (1) Opening of semilunar valves (2) Opening of AV values (3) Closure of AV valves (4) Closure of semilunar valve 1. ~ | ¤ ¤i ¤ | º | + i + | l z | + | l · | l Ÿ | ¤ - i t | - i t :- (1) + ¤ n ¤ - º i ÷ | · n | : + - + i (2) + ¤ n + | ¤ | t : ÷ ™ º ¸ = + i (3) ¤ | º i - ( ¤ ¤ | n i = + · | : ÷ ¸ = + i (4) + ¤ n l n l ¤ ÷ + i 2. l - - - l n l º | - n = ¤ =l n ¤ | + | + | - = | ( + =n ¸ t ' ' ¤ l º ¤ | + | º ÷ ™ n ¤ =l n ¤ | ' ' n =l - n l n - t · (1) 7 th , 8 th & 9 th ¤ · n (2) 8 th , 9 th and 10 th ¤ · n (3) 9 th , 10 th and 11 th ¤ · n (4) 11 th and 12 th ¤ · n 3. z ¤ =- + + - : i ¤ · =| ¤ - = ¤ · | ª t | - t + (1) CSF n ÷ ¤ t ( , (2) ¤ ÷ i t : pH n - ª i - - t | - t + (3) ECF n ÷ ¤ t ( + (4) - ¤ · | + - =· | i 4. l - - - n = + | - =| + · | - ª n - t ? (1) ¤ t n ª - - · | | · i ¤ | º | i ¬ ¸ ( n ¤| · -) · | (2) ª - - · | | · i ¤ | º | i ¤ | º = ¤ | º º | - · | + ¤ l - =- + · t - ¤ ¤ - | ¤ + · - n ¤ l zn | - t | - · | + (3) ¤¤ =· i = ¤ | + i + n i t : , - ¤ ª - - · | | · i ¤ | l º | ¤ | - ª · | n ¤ · + · ¤| + · l n ¤ | (4) n t | l , ¤ i ¤ l ¤ - n - + + | · º | ¤¤ - Ÿ | · i ~ n · i + | , · l - | º | i ~ n · i + | = l n n ª ¤ | - | ¤ ¤i ¤ · l - | º | i ~ n · i + | + ¤ - ~ | + · ¤ | ¤ n ~ | ª ¤ 5. ~ ª · (+ ¤ | + l · ¤ | l º + + | l z | + | n l - - - l n l º | - n - | º | ¤ | ¤ ¤| - t - | + | l z | + | + i ¤ t - | - + · :- (i) + | l z | + | l · | l Ÿ | n ¤ - º i ÷ | · n | : + - + i º ¤ | · | n | z | (ii) l º + | : + ~ - n + i - ¤ l ª · | l - (iii) ¤ l - l =n i - ¤ l - ¤ l ¤ + + ¤ l - = ¤ · - z | i n (iv) n | º i + | l z | + | l · | l Ÿ | l ¤ + - ¤ :- (1) ª | n l - ª l º ¤ ¤i ¤ | º | (2) ª | n ¤ | l ¤l º ¤ ¤i ¤ | º | (3) n | : + | - n | º n | (4) - ¤ · | + - =· | i 6. ¤ · | n ‚ · ¤ · ¤ - i ' ' n ¤ ' ' + | =- ¤ - · | t :- (1) ~ · | - - : | + | · + ¤ | º | + º | n - = (2) AV + ¤ | º | + º | n - = (3) AV + ¤ | º | + ¤ - · t | - = (4) ~ · | - - : | + | · + ¤ | º | + ¤ - · t | - = BEWARE OF NEGATIVE MARKING HAVE CONTROL HAVE PATIENCE HAVE CONFIDENCE 100% SUCCESS 22–05–2014 TARGET : PRE-MEDICAL 2014 2/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST AIIMS 7. Select the answer with correct matching of the structure, its location and function :- Structure Location Function 1 Eustachian tube Anterior part of internal ear Equalizes air pressure on either sides of tympanic membrane 2 Cerebellum Fore brain Controls respiration and gastric secretions 3 Hypothalamus Fore brain Controls body temperature, eating and drinking 4 Blind spot Near the place where optic nerve leaves the eye Rods and cones are present but inactive here 8. Cancer cells and virus infected cells can be killed before activation of acquired immunity by :- (1) Phagocytes (2) T–lymphocytes (3) Natural killer cells (4) Dendritic cells 9. How many nodes and internodes respectively are present in a typical dicot flower ? (1) 1 and 1 (2) 2 and 3 (3) 3 and 4 (4) 4 and 3 10. Cockroach blood does not contain respiratory pigment, it means. (1) It does not respire (2) Cockroach respires anaerobically (3) Oxygen passes to all the tissues through alary muscles (4) Oxygen reaches tissue through tracheoles 11. How many hormone in given list are releated with immune system : Thyroxine, Aldosterone, Thymosine, Glucagon, Growth hormone Cortisole, Testosteron - (1) Six (2) Four (3) Two (4) One 7. = · - - | , ª · | | - ¤ + | ¤ n =t i l n l n - - Ÿ | · + | - ¤ - + i l ¤( :- =· - - | ª · | | - + | ¤ 1 ¤ ¸ ª º l + ¤ - - n i ~ - · + º | + | ~ ª · | | ª l º - ¤ l - + l ¤ - n i + · | - | - · + ¤ | ¤ · | ¤ + | =n | - + · - | t + 2 ~ - n l ª · | · + ~ ª n l ª - · + z ¤ =- ¤ ¤a · ª z ¤ º | + | l - ¤ z º | 3 t | : ¤ | · | n n = ~ ª n l ª - · + z | · i · - | ¤ , · | ¸ º | ¤ - ¤ | = l - ¤ z º | 4 ~ · | l ¤ - · - z = · + - l z + | + l - + n - + =n i ¤ + | ª · | | - z | + ¤ z n | + | - ¤ l ª · | - ¤ · - ~ l + ¤ ~ ¤ ª · | | 8. + =· ¤ l ¤ · | | º | = + l n - + | l z | + | ~ | + | ~ l ¤ - ¤ l - · - | | + =l + ¤ º | + ¤ ¸ ¤ : - + , | · | - · º l + ¤ | ¤| =+ - | t :- (1) · | - | + | º | (2) T– n =i + | º | (3) ¤ | œ l - + n | · + + | l z| + | ¤ (4) ÷ - ÷ ™ | : l º + + | l z| + | ¤ 9. ( + ¤ | ªl ¤ + l , ¤ i ¤¤ z i ¤ ¤ · ¤ n + n z | · l + - - i ¤ ¤ =l - · | ( ¤ ¤ ¤ ¤ | ¤ ¤| - t · (1) 1 ( ¤ 1 (2) 2 ( ¤ 3 (3) 3 ( ¤ 4 (4) 4 ( ¤ 3 10. + | + · | - + · + - n z ¤ =- ¤ º | + - t i ¤ | ¤ | ¤| - | : =+ | n - n ¤ (1) : =n z ¤ =- - t i t | - | (2) + | + · | - n ~ ¤ | ¤ ¤ i ¤ z ¤ =- t | - | t + (3) ~ | + =i ¤- =· | i ≈- + | n ( n · i ¤ l z | ¤ | = ¤| - i t + (4) ~ | + =i ¤- ≈- + | n º ™ l + ~ | - = = ¤| - i t + 11. - i - · i ª ¤ i =¸ - i n l + - - t | n | - ¤ l - · - | | - z = =- ¤ l - · | - t : · | | ¤ · | l + =- , ( - ÷ | ª º i · | - , · | | ¤ n | l =- , · n ¸ + | ª | - , ¤ l zt | n | - , + | º i =| n , º ª º | ª º i · | - - (1) ¤ · (2) - | · (3) · | (4) ( + t n z | | n ª + · | - · t + 22–05–2014 PRE-MEDICAL : ENTHUSIAST, LEADER & ACHIEVER COURSE 3/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST AIIMS 12. Which option is incorrect :- (1) Myasthenia gravis Auto anti bodies to acetylcholine receptor Depressed muscle function (2) Allograft Graft between dizygotic twins Intraspecies graft (3) Turner's syndrome 44 + XO Cardio vascular abnormalities (4) Mycobacterium leprae Treatment by DOTS Mantoux test 13. Which type of vascular bundle is found in Yucca and Dracena stem ? (1) Radial (2) Conjoint (3) Concentric (4) Bicolleteral 14. Observe the following demonstration :- .5 M .6 M .7 M x y z When carrot cubes are kept in above solutions & concluded that carrot cubes swell in tube x & shrinks in tube z then :- (1) Concentration of x tube is hypertonic (2) Concentration of y tube is hypertonic (3) Concentration of z tube is hypotonic (4) Concentration of tube z is hypertonic 15. The protein rich structure present in the maize grain, is a part of :- (1) Perisperm (2) Endosperm (3) Nucellus (4) Scutellum 16. Several chemotherapeutic drugs are used to kill the cancerous cells. These drugs show effects during following phase of cell cycle :- (1) G 0 – stage (2) S – stage (3) M – stage (4) G 2 – stage 12. + | - =| l ¤ + - ¤ ~ =· ¤ t :- (1) n | ¤ ª · | i l - ¤ | ª l ¤ = ( =i º | : n + | l n - ª | t i + l ¤ ªz ª ¤ ¤ l - + | ¤ ¤ z | i + | ¤ n ª+ | ¤ º (2) ( n | ª | ∂ º l , ¤ · n - ¤i ¤ ÷ ¤ | ¤ - - | + ¤ i - ª | ∂ º ~ - · | ¤ ¤| l - ¤ l - · | ¤ (3) º · - · l =- ÷ ™ | n 44 + XO ‚ · ¤ ¤ l · = - · º | ~ =| n | - ¤ - | ¤ (4) n | : + | ¤ + º i l · ¤ n n ¤ DOTS , | · | - ¤ - | · n - º ¸ + = º ª º 13. ¤ + + | ( ¤ ÷ ™ l =- | + - - n l + = ¤ + | · + | = ¤ t - ¤ ¸ n ¤ | ¤ | ¤| - | t · (1) ~ · i ¤ (2) = ¤ + - (3) = + - : i (4) - · | ¤ ∂ n | ( n i 14. l - - - l n l º | - ¤ · z | - + | ¤ l - | - + i l ¤¤ :- .5 M .6 M .7 M x y z ¤¤ - ¤ · | + - · | | n | n , ª | ¤· + ¤ ¸ ¤ · º | ª ¤ ¤ l - · + · | = ¤ - | - n | l + ª | ¤· + ¤ ¸ ¤ x - n i n + ¸ n ¤| - t ¤ z - n i n l =+ ÷ - t , - | :- (1) x - n i + i =| : - | ~ l - ¤ · | =· i t + (2) y - n i + i =| : - | ~ l - ¤ · | =· i t + (3) z - n i + i =| : - | ~ · | | ¤ · | =· i t + (4) z - n i + i =| : - | ~ l - ¤ · | =· i t + 15. n + + | + · | - n ¤ | ¤ i ¤| - ¤ | n i ¤ | º i - ¤ - · = · - - | l + =+ | · | | ª t ? (1) ¤ l · · | ¸ º | ¤ | · | (2) · | ¸ º | ¤ | · | (3) ¤ i ¤| º ÷ + | ¤ (4) ¤ ªl · | + | 16. l ¤ l · | - - · =| l - l + · =i ¤ ~ | · | l · | ¤ | + | + =· + | l z | + | ~ | + | - · º + · - n ¤ ¤ + - l + ¤ | ¤| - | t + + | l z | + | - + + i + | - =i ~ ¤ ª · | | n ¤ ~ | · | l · | ¤ | ~ ¤ - | ¤ · | | ¤ · z | | - i t :- (1) G 0 – ~ ¤ ª · | | (2) S – ~ ¤ ª · | | (3) M – ~ ¤ ª · | | (4) G 2 – ~ ¤ ª · | | 22–05–2014 TARGET : PRE-MEDICAL 2014 4/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST AIIMS 17. Characteristic of class insecta is :- (1) Cephalothorax, book lungs and chitinous exoskeleton (2) Head, thorax & abdomen, tracheal system and chitinous exoskeleton (3) Head & thorax, biramous appendages and book lungs (4) Cephalothorax, biramous appendages and gills 18. Nearly all enzymes are proteinaceous in nature, but few are nucleic acids that behave like enzyme. Non protein enzymes were discovered by T. Cech and Altman. In the absence of enzymes biochemical process become very slow and enzymes speed up the rate of reactions, which carbohydrate is present in non protein enzyme of cell ? (1) Triose (2) Tetrose (3) Pentose (4) Erythrose 19. A boy is albino but his brother has normal skin. What is the chance that at least one of his parents has normal skin ? (1) 50% (2) 25% (3) 100% (4) 0% 20. Column - I (i) A species B species population time (ii) A species B species population time (iii) A species B species Time population (iv) B species A species population Time Column - II (a) Mutualism (b) Competition (c) Amensalism (d) Predation (e) Commensalism Match the Column-I with Column-II :- (1) (i)-e, (ii)-d, (iii)-b, (iv)-a (2) (i)-e, (ii)-b, (iii)-d, (iv)-a (3) (i)-c, (ii)-d, (iii)-a, (iv)-b (4) (i)-c, (ii)-b, (iii)-d, (iv)-b 17. ¤ ª : - = + º | + ~ l · | n | - | l º | + ª º | t (1) l =· | ¤ - | , ¤ ª - + + ∂ + = - · | | + | : l º - ¤ + - ¤ | t ¸ ¤ + + | n (2) l =· , ¤ - | - · | | - · · , º ™ l + ¤ | - z ~ | · + | : l º - ¤ + - ¤ | t ¸ ¤ + + | n (3) l =· ¤ ¤ - | , l , z | | l º | - - ¤ | ª - · | | ¤ ª - + + ∂ + = (4) l =· | ¤ - | , l , z | | l º | - - ¤ | ª ¤ + n | n 18. n ª · | ª =· | i ¤ l + º ¤ ¤ œ l - n ¤ | º i - i t | - t , l + - - + ¤ + - : + i ~ - n · | i ¤ l + º ¤ + i - · t · ¤ ¤ t | · + · - t + ~ ¤ | º i - i ¤ l + º ¤ º i = + ¤ ~ | - º n - , | · | º | | ¤ ª ¤ · | + ¤ l + º ¤ + i ~ - ¤ l ª · | l - n ¤ ¤ · | =| ¤ l - + ¤ l + ¤ | ¤ t - t i · | i n i t | - i t - · | | ¤ l + º ¤ l + ¤ | ~ | + i · · + | : - + · · - t + + | l z | + | + ~ ¤ | º i - ¤ l + º ¤ n + | - =| + | ¤ | t | : ÷ ™ º - ¤ l ª · | - t | - | t · (1) Triose (2) Tetrose (3) Pentose (4) Erythrose 19. ( + n ÷ + | ( l - ¤ - | t l + - - - =+ · | | : + i · ¤ - | =| n | - ¤ t + : =+ i l + - - i = · | | ¤ - | t l + - =+ ¤ - + | n + n = + n + | : ( + =| n | - ¤ · ¤ - | ¤ | n | t · (1) 50% (2) 25% (3) 100% (4) 0% 20. ª - - · | - I (i) A species B species population time (ii) A species B species population time (iii) A species B species Time population (iv) B species A species population Time ª - - · | - II (a) =t ¤i ¤ - (b) ¤ l - ª ¤ · | | (c) ¤ l - ¤ l ¤ + - | (d) ¤ · · | - | º | (e) =t · | | l ¤- | ª - - · | -I ¤ ª - - · | -II + | n n + · | : ¤ :- (1) (i)-e, (ii)-d, (iii)-b, (iv)-a (2) (i)-e, (ii)-b, (iii)-d, (iv)-a (3) (i)-c, (ii)-d, (iii)-a, (iv)-b (4) (i)-c, (ii)-b, (iii)-d, (iv)-b 22–05–2014 PRE-MEDICAL : ENTHUSIAST, LEADER & ACHIEVER COURSE 5/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST AIIMS 21. Correct order or excretory organs in Apis, Nereis and Ancylostoma respectively :- (1) Malpighi tubules, Nephridia, excretory tube (2) Nephridia, Malpighi tubules, kidney (3) Malpighi tubules, Nephridia, kidney (4) Nephridia, kidney, green gland 22. CAM plants :- (1) Performing Calvin cycle at night. (2) Using PEPcase enzyme to fix CO 2 with RuBp. (3) Keeping stomata closed during night. (4) Fixing CO 2 into organic acids in night and it releases CO 2 in day. 23. Biogas released during sewage treatment is a mixture of :- (1) CH 4 , H 2 S, CO 2 (2) C 2 H 4 , H 2 S, NO 2 (3) CH 4 , H 2 S, SO 2 (4) CH 4 , N 2 O, CO 2 24. Study the four statements (a-d) given below and select the two correct ones out of them - (a) a lion eating a deer and a sparrow feeding on grain are ecological similar in being consumer. (b) Predator star fish Pisaster helps in maintaining species diversity of some invertebrates (c) Predators ultimately leads to extinction of prey species (d) Production of chemicals such as nicotine, strychnine by the plants are metabolic disorder The two correct options are :- (1) a & b (2) b & c (3) c & d (4) a & d 25. Identify the correct statements from the following with reference to cartilaginous fishes :- (A) In Males pectoral fins bear clasper (B) Notochord is persistent throughout life (C) Air bladder is absent so that they have to swim constantly to avoid sinking (D) They have four pairs of gills, which are covered by an operculum on each side (1) (A), (B) and (C) (2) (C) and (D) (3) (A) and (B) (4) (B) and (C) 26. Avena curvature test is used for :- (1) Gibberellin (2) Auxin (3) Cytokinin (4) Abscisin 21. l - - - n = l + = n ( l ¤ = , - · i ¤ ~ | · ( - =| : n | ª º | n | n - · =¤i ~ ª | + | + n z| · =t i + n t :- (1) n n ¤ i ª i - l n + | , - l ›l ÷ ¤ | , - · =¤ + - | n (2) - l ›l ÷ ¤ | , n n ¤ i ª i - l n + | , ¤ + + (3) n n ¤ i ª i - l n + | , - l ›l ÷ ¤ | , ¤ + + (4) - l ›l ÷ ¤ | , ¤ + + , ª i - ª l · | 22. CAM ¤ | · ¤:- (1) + l - ¤ - - + · | l z n =- ¤ | l · - + · - t + (2) RuBp + =| · | CO 2 l ª · | · i + · º | n PEPcase + | - ¤ ¤ | ª + · - | t + (3) · | l z + · | · | - · · | | + | ¤ · · º | - t + (4) · | l z n CO 2 + | + | ¤ l - + ~ - n n l ª · | · i œ - + · - | t ( ¤ ¤ t l · - n CO 2 n + - + · - | t + 23. ¤ | l t - n n + - ¤ - | · + =n ¤ l - + n - ¤ | n i ¤ | ¤ | ª = l + =+ | l n ¬ º | t | - i t ? (1) CH 4 , H 2 S, CO 2 (2) C 2 H 4 , H 2 S, NO 2 (3) CH 4 , H 2 S, SO 2 (4) CH 4 , N 2 O, CO 2 24. - i - l · ( ¤| · t - | · + · | - | (a-d) + | ~ · ¤ ¤ - + i l ¤¤ ~ | · - - n = · | =t i + · | - | + | - l - ¤ - (a) ( + z | · ¤| l t · º | + | º | | · t | t ~ | · ( + ª | · ∏¤ | ¤| · | - | - ª · t i t , ¤ · | - | - ¤ · | | + - | t | - + ª¤ n ¤ | l · l ª · | l - + · l · º = =n | - t + (b) ¤ · · | - | i ª º | · l + z| ¤ | : = ª º · + ¤ ~ + z | ªl + ¤ | + i ¤| l - l ¤ l ¤ · | - | ¤ - | ¤ · º | - n =t | ¤ - | + · - i t + (c) ¤ · · | - | i ¤ | º | i ~ - - - · ~ | º | º ¤| l - + l ¤ n | ¤ + | + | · º | ¤ - ¤| - t + (d) ¤ | · | | , | · | l - + | º i - , l ª º ™ + - i - ¤ = · =| ¤ - | + | - · ¤ | · - - - + - ¤ | ¤ - ¤ i · | · | t | - t + : - n = · | =t i + · | - + | - = t · (1) a ¤ b (2) b ¤ c (3) c ¤ d (4) a ¤ d 25. - ¤ | l ª · | n n ¤ l n ¤ | + = · · | n =t i + · | - | + | ¤ t - | l - ¤ :- (A) - · ~ z | ¤ º | | n + n ª ¤ · ¤ | ¤ | ¤| - | t + (B) ¤ · a · º ¤ l - · ª · | | : t | - i t + (C) : - n ¤ | ¤ + | · | ~ - ¤ l ª · | - t | - | t , : =l n ¤ ÷ ¸ ¤ - = ¤ - - + l n ( n ª | - | · - · - · t - t + (D) : - n - | · ¤| ÷ i + n | n ¤ | ¤ ¤| - t , ¤| ¤ · ¤ + - · + ~ | ¤ · + n n = · + · t - t + (1) (A), (B) ~ | · (C) (2) (C) ~ | · (D) (3) (A) ~ | · (B) (4) (B) ~ | · (C) 26. ¤: ¤ + - | ¤ · i - | º | l + =+ l n ( ¤ ¤ + - + · - t ? (1) l ¤¤ · l n - (2) ~ | l + =- (3) =| ¤ º | + | : l - - (4) ( l · =l =- 22–05–2014 TARGET : PRE-MEDICAL 2014 6/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST AIIMS 27. The genes that help in identifying and eleminating nontransformants and selectively permitting the growth of the transformants are present in :- (1) Cloning vector (2) Foreign DNA (3) Host DNA (4) All of these 28. Choose the correct identification for the given stage of succession and it will proceed to which stage respectively ? Options : (1) Marsh meadow, Reed swamp (2) Submerged / floating, reed swamp (3) Submerged plant, scrub stage (4) Phytoplankton, marsh meadow 29. Consider the following statements :- Duri ng the alternati on of generation or metagenesis in coelenterates, the polyps are necessarily. (A) Free living (B) Sedentary (C) Polyp form medusae sexually (D) Polyp form medusae asexually (1) (A), (B) & (C) are correct (2) (A), (B) & (D) are correct (3) (B), (C) & (D) are correct (4) Only (B) is correct 30. How many statements are correct in a to e ? (a) Mitochondria and chloroplasts are semi autonomous organelle. (b) Nucleolus and Ribosomes are non-membranous structures of cell. (c) Kinetosome is a part of chromosome (d) Chromatin contains DNA, RNA, Histones and non histone proteins. (e) Meiosis occurs only in life cycle of Diploid plants. (1) Two (2) One (3) Four (4) Three 27. ¤ ¤i - ¤| ~ ª¤ | - · ¤| + i ¤ t - | - ¤ - - t =n | - - + · - n =t | ¤ + t | - t ~ | · ¤| ª¤ | - · ¤| + i - ¤ - | · n + ¤ l z + | t | - · - t , + t | ¤ | ¤ ¤| - t · (1) + n | l - ª ¤ | t + ¤ · (2) ¤ | t · iDNA ¤ · (3) ¤ | · | + DNA n (4) - ¤ · | ‰ =· | i 28. l · ( ª ( ~ - + n º | ~ ¤ ª · | | + i =t i ¤ t - | - + i l ¤( ( ¤ ¤ t + | - =i ~ ¤ ª · | | + i - · + + n z | · ª n - + · ª i ? l ¤ + - ¤ : (1) + - ¤ z | | , n , - ÷ ~ - ¸ ¤ ~ ¤ ª · | | (2) l - n · - ! - n | ¤ i , - ÷ ~ - ¸ ¤ ~ ¤ ª · | | (3) l - n · - ¤ | · ¤ , ª - n ~ ¤ ª · | | (4) ¤ | · ¤ - n ¤ +, + - ¤ z | | , n ~ ¤ ª · | | 29. l - - - l n l º | - + · | - + | ~ · ¤ ¤ - + i l ¤¤ :- =i n - º ™ º ¸ = n ¤ i · i (+ | - - · º | ¤ | n º | l ¤- l == + =n ¤ ¤ | l n ¤ ~ | ¤ z ¤ + ª¤ = t | - t + (A) n + - ¤i ¤ i (B) ª · | | - ¤ z (C) ¤ | l n ¤ n l ª + ¤- - , | · | n ÷ ¸ =| + | l - n | º | + · - | t + (D) ¤ | l n ¤ ~ n l ª + ¤- - , | · | n ÷ ¸ =| + | l - n | º | + · - | t + (1) (A), (B) ~ | · (C) =t i t (2) (A), (B) ~ | · (D) =t i t (3) (B), (C) ~ | · (D) =t i t (4) + ¤ n(B) =t i t 30. a = e n l + - - + · | - =· ¤ t ? (a) =¸ z + l º | + | ¤ ( ¤ t l · - n ¤ + ~ z ª ¤ | ¤ Ÿ | · + | l z | + | ª t | - t + (b) + l - : + | ( ¤ · | : ¤ | =| n , + | l z | + | + i l ¤ - n i · l t - = · - - | ¤ t + (c) + | : - º | =| n , ª º | =¸ z + | · | | ª t | - | t + (d) + | n l º - n DNA, RNA, l t ª º | - - · | | ~ l t ª º | - ¤ | º i - · t - i t + (e) ~ · | =¸ z i l ¤ · | | ¤- + ¤ n l , ª l º | - ¤ | · ¤ | + ¤i ¤ - - + n t | - | t + (1) · | (2) ( + (3) - | · (4) - i - 22–05–2014 PRE-MEDICAL : ENTHUSIAST, LEADER & ACHIEVER COURSE 7/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST AIIMS 31. For permanent cure of ADA deficiency, the ADA producing gene should be introduced into the cells at :- (1) Early embryo stage (2) Just after birth (3) Before reaching sexual maturity (4) In the gamete of parents 32. Which of the following characters are changed with altitude & Latitude ? (a) Temperature (b) Vegetation (c) Species Diversity (d) Species composition Options : (1) Only a (2) Only a & b (3) a, b & c (4) a, b, c & d 33. Tubular secretion helps to maintain a proper acid- base balance by removing one of the following from blood :- (1) H + ions and Ammonia (2) Uric Acid (3) H + ions and urea (4) Ammonia and creatinine 34. Which one of the following characters choosen by mendel can express in hetrozygous condition? (1) Green seed colour (2) Constricted pod shape (3) Terminal flower position (4) Green pod colour 35. Read the following statements about universe :- (i) The universe is very old-almost 10 billion year old (ii) Huge clusters of galaxies comprise the universe (iii)Considering the size of universe, earth is indeed a speck (iv) The big bang theory attempts to explain about the origin of earth (v) The big bang theory talks of a singular huge explosion unimaginable in physical terms How many statements are not correct. (1) One (2) Two (3) Three (4) Four 31. ADA - ¤ ¸ - - | + ª · | | ¤ i : n | ¤ + l n ¤ ADA - · ¤ - - + · - ¤ | n | ¤i - + | l z | + | ~ | n l + = ~ ¤ ª · | | n ÷ | n - | - | l t ¤ · (1) ¤ | · l · | + · | ¸ º | i ¤ ~ ¤ ª · | | (2) ¤- n + - · - ¤ | · (3) n l ª + ¤ l · ¤ + ¤ - | ¤ | - - + · - = ¤ t n (4) ¤- + | + ¤ · n + | n 32. l - - - l n l º | - n = + | - = n - | º | ≈ - | : ( ¤ ~ - | | z | + =| · | ¤ l · ¤ l - - t | - t ? (a) - | ¤ n | - (b) ¤ - ª ¤ l - (c) ¤| l - ¤ l ¤ l ¤ · | - | (d) ¤| l - ¤ = · | a - l ¤ + - ¤: (1) + ¤ na (2) + ¤ n a ( ¤ b (3) a, b ( ¤ c (4) a, b, c ( ¤ d 33. ' ' - l n + | + | · ª z ¤ º | ' ' l - - - l n l º | - n = + | - = (+ l ¤ + - ¤ + · | º + | + | · + - n = t º | + · ' ' ~ - n - | | · =- - n - ' ' + | l ª · | · ¤ - | - n =t ¤ | ª · - | t ? (1) H + ~ | ¤ - = ¤ ~ n | l - ¤ | (2) ¤ ¸ l · + ~ - n (3) H + ~ | ¤ - = ¤ ¤ ¸ · i ¤ | (4) ~ n | l - ¤ | ¤ l + ( l º l - - 34. n º ÷ n , | · | - - ª ¤ l - - - l n l º | - n - | º | | n = + | - =| l ¤ · | n ¤ · n ¤i ~ ¤ ª · | | n ¤ · l z | - t | =+ - | t ? (1) ¤ i ¤ + | t · | · ª (2) l =+ ÷ i t : + n i (3) ~ - ª · | ¤ · ¤ + i l ª · | l - (4) + n i + | t · | · ª 35. ¤ „ | ÷ + ¤ | · n l - - - + · | - | + | ¤ l · ¤ + (i) ¤ „ | ÷ ~ · ¤ - - ¤ | - i - n ª · | ª 10 l ¤ l n ¤ - ¤ · | ¤ · | - | t (ii) ¤ „ | ÷ n ~ | + | z| ª ª | ~ | + l ¤ z | | n =n ¸ t =n l + - t (iii) ¤ „ | ÷ + ~ | + | · + | · ¤ | - n · º | - t ¤ ¤ · ¤ i + ¤ n ( + l ¤ - · ¸ ¤ | + l º | + | n | z t (iv) l ¤ ª ¤ ª - | n + n t | l ¤ ª + | º + + | l =z| - - t n ¤ · ¤ i + i - · ¤ l Ÿ | + ¤ | · n ¤ - | - | t + (v) · | | l - + ª¤ n l ¤ ª ¤ ª l =z| - - ( + ~ - ¸ a i + - ¤ - | = ¤ · n t | l ¤ ª + | º + | + l · | - ª¤ t + : - n = l + - - + · | - =t i - t i t :- (1) ( + (2) · | (3) - i - (4) - | · ~ ¤ - i - | n - | + | ¤ ¸ · | ¤ =¸ n - + | ¤ ¤ | = + · + 22–05–2014 TARGET : PRE-MEDICAL 2014 8/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST AIIMS 36. Which type of relation shown by given graph? population time (a) Predation (b) Parasitism (c) Competition (d) Mutualism Options :- (1) Only a (2) a and c (3) Only b (4) a and b 37. How many animals in the list given below are homeothermal and have complete four chambered heart ? Crocodilus, Columba, Struthio, Naja, Equus, Hyla, Delphinus, Macaca, Chelone, Psittacula (1) Six (2) Seven (3) Eight (4) Five 38. Deficiency of which vitamin can lead to blood clotting disorder due to defect in the formation of factors VII and IX ? (1) Vitamin A (2) Vitamin D (3) Vitamin B (4) Vitamin K 39. Which of the following statement is correct :- (1) Homology is based on convergent evolution (2) Analogy is based on divergent evolution (3) Analogy is based on convergent evolution (4) Adaptive radiation also known as convergent evolution 40. During a visit to a desert ecosystem, a student observes the following :- A Hawk eats a snake A lizard eats a fly A tortoise eats small patches of grass A snake eats a mouse Based on student's observations of how each of these organisms obtain energy, which of the following statements is the best conclusion ? (1) The Hawk is a primary consumer (2) The grass and the desert tortoise both are primary consumers (3) The lizard is a tertiary consumer (4) The lizard and the snake are secondary consumers. 36. - ¤ · | + - ª | + l - - - n = l + = =- ¤ - · | + | ¤ · l z | - + · - | t ? population time (a) ¤ · · | - | º | (b) ¤ · ¤i ¤ - (c) ¤ l - ª ¤ · | | (d) =t ¤i l ¤ - | l ¤ + - ¤:- (1) + ¤ n a (2) a - · | |c (3) + ¤ n b (4) a - · | |b 37. - i - · i ª : =¸ - i n = l + - - ¤ | º | i =n - | ¤ i t - · | | ¤ ¸ º | - | · + - | i ¤ ‚ · ¤ · º | - t · + | + | ÷ i n =, + | n - ¤ | , ª º ™ l · | ¤ | , - | ¤| , : + ¤ =, t | ¤ n | , ÷ l n l + - =, n + | + | , + i n | - , l =º + ¤ n | (1) ¤ · (2) =| - (3) ~ | a (4) ¤ | - 38. l + = l ¤ º | l n - + i + n i = · + - + | · | + + | ¤ - - + | · | ª t | =+ - | t l ¤=+ | + | · º | + | · + VII - · | | IX + l - n | º | n l ¤ + l - ~ | - | t ? (1) l ¤ º | l n - A (2) l ¤ º | l n - D (3) l ¤ º | l n - B (4) l ¤ º | l n - K 39. l - - - n = + | - =| + · | - =t i t :- (1) =n ¤| - - | , ~ l · | =| · i l ¤ + | = ¤ · ~ | · | | l · - t (2) - - ¤ ª¤ - | , ~ ¤ =| · i l ¤ + | = ¤ · ~ | · | | l · - t (3) - - ¤ ª¤ - | , ~ l · | =| · i l ¤ + | = ¤ · ~ | · | | l · - t (4) ~ - + ¸ n i l ¤ l + · º | + | ~ l · | =| · i l ¤ + | = + i + t | ¤| - | t 40. n ª ª · | n i ¤ ¤ | l · l ª · | l - + i - z + ~ · ¤ ¤ - + · | · | - ¤ | z , | · | l - - - l - · i - | º | l + ¤ ¤| - t :- ( + ¤ | ¤, =| ¤ + | º | | - | t + ( + l ¤ ¤ + n i , + i º + | º | | - i t + ( + + ¤ ~ | , · | | = + | º | | - | t + ( + =| ¤ , - ¸ t | + | º | | - | t + ¤ | z , | · | · º | ª ¤ ¤ - | º | | n ¤i ¤ l + = ¤ + | · ≈ ¤| ¤ | - - + · - | t + : = = · · | n l - - - n = + | - =| + · | - ~ l · | + l - · + · | º | | · n + t · (1) ¤ | ¤ ( + ¤ | · | l n + - ¤ · | | + - | t + (2) · | | = - · | | n ªª · | n i ¤ + ¤ ~ | · | - | t i ¤ | · | l n + - ¤ · | | + - | t + (3) l ¤ ¤ + n i - - i ¤ + - ¤ · | | + - | t + (4) l ¤ ¤ + n i - · | | =| ¤ l , - i ¤ + - ¤ · | | + - | t + Time Management is Life Management 22-05-2014 9/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST AIIMS PRE-MEDICAL : ENTHUSIAST, LEADER & ACHIEVER COURSE 41. 26.8 gm of Na 2 SO 4 .nH 2 O contains 12.6 gm of water. The value of 'n' is ? (1) 1 (2) 10 (3) 6 (4) 7 42. If r = k [A] 0 2 [B] 0 for a reaction, by what factor is the initial rate multiplied if the [A] 0 is multiplied by 1.5 and the [B] 0 is tripled? (1) 4.5 (2) 2.25 (3) 6.75 (4) None of these 43. What is the correct order of spin only magnetic moment of Mn 2+ , Cr 2+ and V 2+ :- (1) Mn 2+ > V 2+ > Cr 2+ (2) V 2+ > Cr 2+ > Mn 2+ (3) Mn 2+ > Cr 2+ > V 2+ (4) Cr 2+ > V 2+ > Mn 2+ 44. A compound contains 69. 5% oxygen and 30.5% nitrogen and its molecular weight is 92. The formula of the compound is :- (1) N 2 O (2) NO 2 (3) N 2 O 4 (4) N 2 O 5 45. A single electron system has ionization energy 11180 kJmol –1 . Find the number of protons in the nucleus of the system ? (1) 1 (2) 3 (3) 2 (4) 4 46. What are the number of atoms per unit cell and the number of nearest neighbours in a body centered cubic structure? (1) 4, 12 (2) 1, 6 (3) 2, 8 (4) 2, 5 47. When benzene sulphonic acid and p-nitro phenol are treated with NaHCO 3 , the gases released are respectively :- (1) SO 2 , NO 2 (2) SO 2 , NO (3) SO 2 , CO 2 (4) CO 2 , CO 2 48. In an experiment, 4g of M 2 O x oxide was reduced to 2.8 g of the metal. If the atomic mass of the metal is 56 g mol –1 . The number of O atoms in the oxide is :- (1) 1 (2) 2 (3) 3 (4) 4 49. The enthalpy of combustion at 25°C of H 2 , cycl ohexane and cyclohexene are – 241, – 3920 and – 3800 kJ/mol respectively. The heat of hydrogenation of cyclohexene is? (1) – 121 kJ/mol (2) + 121 kJ/mol (3) – 242 kJ/mol (4) + 242 kJ/mol 50. Ionisation energy of Cl – is 349 kJ mol -1 . The electron gain enthalpy of chlorine would be :- (1) –349 kJ mol -1 (2) –175 kJ mol -1 (3) +349 kJ mol -1 (4) + 175 kJ mol -1 41. 26.8 gm Na 2 SO 4 .nH 2 O n 12.6 gm ¤n - ¤ l ª · | - t - | 'n' + | n | - a | - + i l ¤( ? (1) 1 (2) 10 (3) 6 (4) 7 42. ¤ l · (+ ~ l · | l + ¤ | t - r = k [A] 0 2 [B] 0 t | - | ¤ | · l - · | + · · l + = ª º | | + = ¤ l · ¤ l - - t | ª i ¤ l · [A] 0 + | 1.5 = - · | | [B] 0 + | - i - ª - | l + ¤ | ¤| ¤ + (1) 4.5 (2) 2.25 (3) 6.75 (4) : - n = + | : - t i 43. Mn 2+ , Cr 2+ ¤ V 2+ + - + º | - - ¤ + i ¤ ~ | · | ¸ º | + | + n t | ª | :- (1) Mn 2+ > V 2+ > Cr 2+ (2) V 2+ > Cr 2+ > Mn 2+ (3) Mn 2+ > Cr 2+ > V 2+ (4) Cr 2+ > V 2+ > Mn 2+ 44. ( + ¤ | l ª + n 69.5% ~ | + =i ¤- - · | | 30.5% - | : º ™ | ¤- - ¤ l ª · | - t ~ | · : =+ | ~ º | · | | · 92 t + ¤ | l ª + + | =¸ z t :- (1) N 2 O (2) NO 2 (3) N 2 O 4 (4) N 2 O 5 45. ( + n : n + º ™ | - - z 11180 kJmol –1 ~ | ¤ - - ≈¤| · º | - | t - | - z + - | l · | + n - ¤ l ª · | - ¤ | º | - + i = º ¤ | a | - + i l ¤( ? (1) 1 (2) 3 (3) 2 (4) 4 46. ( + + | ¤ + l - · - · | - i ¤ = · - - | n ¤ l - : + | : = n n ¤ · n | º | ~ | + i = º ¤ | - · | | l - + º - n ¤ ÷ | =i ¤ · n | º | ~ | + i = º ¤ | t ? (1) 4, 12 (2) 1, 6 (3) 2, 8 (4) 2, 5 47. ¤¤ ¤ - ¤i - =- + | l - + ~ - n - · | | p- - | : º ™ | l + - | n + i l + ¤ | NaHCO 3 = + · | - t , - | + | - =i ª = - · ¤ - - t | - i t :- (1) SO 2 , NO 2 (2) SO 2 , NO (3) SO 2 , CO 2 (4) CO 2 , CO 2 48. ( + v ¤ | ª n M 2 O x + 4g ~ | + =| : ÷ · | | - + 2.8g n ~ ¤ ¤ l - - t | ¤| - t , ¤ l · · | | - + | ¤ · n | º | · | | · 56g mol –1 t , - ¤ ~ | + =| : ÷ n O ¤ · n | º | ~ | + i = º ¤ | t | ª i :- (1) 1 (2) 2 (3) 3 (4) 4 49. 25°C - | ¤ ¤ · H 2 , =| : + n | t + = - - · | | =| : + n | t + =i - + i · t - + i ( - · | - ¤ i + n | - + n z| – 241, – 3920 - · | | – 3800 kJ/mol t - | =| : + n | t + =i - + i t | : ÷ ™ | ¤- i + · º | + i - · n | a | - + i l ¤( ? (1) – 121 kJ/mol (2) + 121 kJ/mol (3) – 242 kJ/mol (4) + 242 kJ/mol 50. Cl – + i ~ | ¤ - - ≈¤| 349 kJ mol -1 t + chlorine + i : n + º ™ | - n · · | i ( - · | - ¤ i t | ª i :- (1) –349 kJ mol -1 (2) –175 kJ mol -1 (3) +349 kJ mol -1 (4) + 175 kJ mol -1 Take it Easy and Make it Easy 22-05-2014 TARGET : PRE-MEDICAL 2014 10/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST AIIMS 51. IUPAC name of compound is :- C–Ph O (1) Phenyl phenone (2) Diphenyl methanone (3) Benzophenone (4) Phenyl benzoate 52. Which of the following is not a characteristic of chemisorption :- (a) Adsorption is irreversible (b) It results into multimolecular layer (c) Enthalpy of adsorption is 80–240 KJ Mol –1 (d) Adsorption is not specific in nature (1) a, b, c, d (2) b & d only (3) c & d only (4) a, b & c only 53. What is the standard potential of the T 3+ /T electrode ? if 3 0 T / T E 1.26 V + + = , 0 T / T E 0.336 V + + = ÷ (1) 0.728 V (2) 0.118 V (3) 1.728 V (4) 2.728 V 54. The formation of ( ) 2 g O ÷ starting from O (g) is endothermic by 639 kJ mol -1 . If electron gain enthalpy of O (g) is –141 kJ mol -1 , the second electron gain enthalpy of oxygen would be :- (1) –780 kJ mol -1 (2) + 780 kJ mol -1 (3) + 498 kJ mol -1 (4) – 498 kJ mol -1 55. Number of possible primary carbocations formed by the molecular formula C H 5 11 © :- (1) 2 (2) 3 (3) 4 (4) 5 56. Match List-I with List-II and select the correct answer using codes given below in the lists: List-I List-II A. Cyanide process 1. Ultra pure Ge B. Floatation process 2. Pine oil C. Electrolytic reduction 3. Extraction of Al D. Zone refining 4. Extraction of Au Codes : A B C D (1) 3 1 4 2 (2) 4 2 3 1 (3) 3 2 4 1 (4) 4 1 3 2 51. ¤ | l ª + + | IUPAC - | n t :- C–Ph O (1) Pheyl phenone (2) Diphenyl methanone (3) Benzophenone (4) Phenyl benzoate 52. · =| ¤ l - + ~ l · | z | | · | º | + + | - = ª º | =t i - t i t :- (a) ~ l · | z| | · | º | ~ - · + n - i ¤ t + (b) ¤ t ¤ · - i ¤ =- t + | l - n | º | t | - | t + (c) ~ l · | z | | · | º | + i ≈· n | 80–240 KJ Mol –1 t + (d) ~ l · | z| | · | º | ¤ + l - n l ¤ l z | · º - t i t | - t + (1) a, b, c, d (2) + ¤ n b - · | | d (3) + ¤ n c - · | | d (4) + ¤ n a, b - · | | c 53. T 3+ /T : n + º ™ | ÷ + n | - + l ¤ · | ¤ + | n | - + ¤ | t | ª | ? ¤ l · 3 0 T / T E 1.26 V + + = , 0 T / T E 0.336 V + + = ÷ (1) 0.728 V (2) 0.118 V (3) 1.728 V (4) 2.728 V 54. O (g) = ( ) 2 g O ÷ + | l - n | º | - · n | z | | · | i (639 kJ mol -1 = ) t + ¤l · O (g) + i l , - i ¤ : n + º ™ | - n · · | i ( - · | - ¤ i –141 kJ mol -1 t - ¤ oxygen + i l , - i ¤ : n + º ™ | - n · · | i ( - · | - ¤ i t | ª i :- (1) –780 kJ mol -1 (2) + 780 kJ mol -1 (3) + 498 kJ mol -1 (4) – 498 kJ mol -1 55. C H 5 11 © + l + - - ¤ | · | l n + + | ¤ · | - | ¤ - = · | ¤ t :- (1) 2 (2) 3 (3) 4 (4) 5 56. =¸ - i -I - · | | =¸ - i -II + | l n n | - + i l ¤( - · | | - i - l · ( ª ¤ + | ÷ + ~ - ª¤ =t i - Ÿ | · ¤ t - | l - ( + =¸ - i -I =¸ - i -II A. =| ¤ - | : ÷ ¤ + n 1. ~ l - z | zGe B. - n ¤ - ¤ + n 2. ¤ | : - - n C. ¤ ¤ - i ¤ ~ ¤ - ¤ - 3. Al + | l - · + · | º | D. ¤| - z | l z+ · º | 4. Au + | l - · + · | º | Codes : A B C D (1) 3 1 4 2 (2) 4 2 3 1 (3) 3 2 4 1 (4) 4 1 3 2 l + =i ¤ z - ¤ · · · - + ª+ | - t i + 22-05-2014 11/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST AIIMS PRE-MEDICAL : ENTHUSIAST, LEADER & ACHIEVER COURSE 57. First order reaction 2N 2 O (g) ÷÷ 2N 2g + O 2(g) has a rate constant of 1.3 × 10 –11 S –1 at 270C and 4. 5 × 10 –10 S –1 at 350°C. What is the activation energy for this reaction ? (1) 15 kJ (2) 30 kJ (3) 68 kJ (4) 124 kJ 58. The ONO angle is minimum in :- (1) 3 NO ÷ (2) 2 NO ÷ (3) 2 NO (4) 2 NO + 59. Cl O AlCl 3 A HNO 3 H SO 2 4 B B is :- (1) O N 2 O (2) NO 2 NO 2 (3) NO 2 O (4) NO 2 NO 2 60. Which one of the following cyano complexes would exhibit lowest paramagnetic behaviour? (1) [Cr(CN) 6 ] 3– (2) [Co(CN) 6 ] 3– (3) [Fe(CN) 6 ] 3– (4) [Mn(CN) 6 ] 3– 61. One of N 2 is mixed with 3 mole of H 2 in a closed vessel of 3 ltr. 20% of N 2 is converted into NH 3 then K c for 1 2 N 2 + 3 2 H 2 NH 3 is : (1) 0.36 lit/mole (2) 0.46 lit/mole (3) 0.50 lit/mole (4) 0.2 lit/mole 57. ¤ · | n + | l º + i ~ l · | l + ¤ | 2N 2 O (g) ÷÷ 2N 2g + O 2(g) t - ¸ 270° - · | | 350° - | ¤ ¤ · · · l - ¤ - | + + n | - + n z| · 1.3 × 10 –11 S –1 - · | | 4.5 × 10 –10 S –1 t - | ~ l · | l + ¤ | + i =l + ¤ º | ≈¤| + | n | - a | - + i l ¤( ? (1) 15 kJ (2) 30 kJ (3) 68 kJ (4) 124 kJ 58. + | - = ~ º | n ONO + | º | - ¤ ¸ - - n t :- (1) 3 NO ÷ (2) 2 NO ÷ (3) 2 NO (4) 2 NO + 59. Cl O AlCl 3 A HNO 3 H SO 2 4 B B t :- (1) O N 2 O (2) NO 2 NO 2 (3) NO 2 O (4) NO 2 NO 2 60. l - - - n = + | - =| =| ¤ - | = + n =¤ = + n ~ - - - ¤ + i ¤ · ¤ ¤ t | · ¤ · l z | - + · ª | ? (1) [Cr(CN) 6 ] 3– (2) [Co(CN) 6 ] 3– (3) [Fe(CN) 6 ] 3– (4) [Mn(CN) 6 ] 3– 61. N 2 + 1 n | n H 2 + 3 n | n + =| · | 3 ltr. ¤ | z n l n n | ( ª ( , 20% N 2 l ¤ ¤ | l ¤- t | + · NH 3 n ¤ l · ¤ l - - t | ¤| - | t , - | K c t 1 2 N 2 + 3 2 H 2 NH 3 is : (1) 0.36 lit/mole (2) 0.46 lit/mole (3) 0.50 lit/mole (4) 0.2 lit/mole ª ¤ ª · | · t | , n ª - · t | - · | | ¤ · | : n · ¤ ª - · t | + 22-05-2014 TARGET : PRE-MEDICAL 2014 12/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST AIIMS 62. Match the compounds in the List I with that in List II :- List I List II A XeO 3 (i) Planar triangular B XeOF 4 (ii) T-shape C CO 3 2– (iii) Trigonal pyramid D ClF 3 (iv) Square pyramid E I 3 – (aq.) (v) Linear (vi) Bent (1) A-i, B-iv, C-iii, D-ii, E-v (2) A-ii, B-iv, C-i, D-iii, E-vi (3) A-iii, B-iv, C-i, D-ii, E-vi (4) A-iii, B-iv, C-i, D-ii, E-v 63. Which of the following ether is not synthesise by Williamson on reaction : (a) CH –CH –O–C–CH 3 2 3 CH 3 CH 3 (b) Ph–O–CH=CH 2 (c) (CH 3 ) 3 C–O–Ph (d) CH 3 –O–CH 2 –CH=CH 2 (1) a,d (2) a,c,d (3) b,c (4) a,b,d 64. The crystal field stabilization energy (CFSE) is the highest for : (1) [CoF 6 ] 3– (2) [Co(NCS) 4 ] 2– (3) [Co(NH 3 ) 6 ] 3+ (4) [CoCl 4 ] 2– 65. For the rx :÷ CO (g) + 1 2 O 2(g) CO 2(g) P C K K is : (1) RT (2) (RT) –1 (3) (RT) –1/2 (4) (RT) 1/2 66. Which of the following forms oxide on heating :- (1) LiNO 3 (2) Li 2 CO 3 (3) LiOH (4) All of these 67. The number of optically act ive products obtained from the complete ozonolysis of the given compound is :- CH –CH=CH–C–CH=CH–C–CH=CH–CH 3 3 H CH 3 CH 3 H (1) 0 (2) 1 (3) 2 (4) 4 62. = n l n - + i l ¤( :- List I List II A XeO 3 (i) l z + | º | i ¤ =n - n i ¤ B XeOF 4 (ii) T- ~ | + | · C CO 3 2– (iii) l z + | º | i ¤ l ¤ l · l n ÷ i ¤ D ClF 3 (iv) ¤ ª | + | · l ¤ l · l n ÷ i ¤ E I 3 – (aq.) (v) · º | i ¤ (vi) n ÷ i t : (1) A-i, B-iv, C-iii, D-ii, E-v (2) A-ii, B-iv, C-i, D-iii, E-vi (3) A-iii, B-iv, C-i, D-ii, E-vi (4) A-iii, B-iv, C-i, D-ii, E-v 63. l - - - n = + | - l ¤ l n n =- ~ l · | l + ¤ | , | · | ¤ - | ¤ | - t i ¤| =+ - | · : (a) CH –CH –O–C–CH 3 2 3 CH 3 CH 3 (b) Ph–O–CH=CH 2 (c) (CH 3 ) 3 C–O–Ph (d) CH 3 –O–CH 2 –CH=CH 2 (1) a,d (2) a,c,d (3) b,c (4) a,b,d 64. l + ª º n - | z l ¤ ¤ | º - ≈¤| (CFSE) =¤ | l · | + t | ª i : (1) [CoF 6 ] 3– (2) [Co(NCS) 4 ] 2– (3) [Co(NH 3 ) 6 ] 3+ (4) [CoCl 4 ] 2– 65. CO (g) + 1 2 O 2(g) CO 2(g) + l n ( P C K K + | n | - t | ª | (1) RT (2) (RT) –1 (3) (RT) –1/2 (4) (RT) 1/2 66. l - - - n = l + = - · n | ¤ · | - + · - ¤ · oxide + | l - n | º | t | - | t :- (1) LiNO 3 (2) Li 2 CO 3 (3) LiOH (4) All of these 67. ¤ | l ª + + | ~ | ¤| - i + · º | + · | - ¤ · - == l + - - ¤ + | z | i ¤ =l + ¤ - · ¤ | · ¤ | - - t | ª :- CH –CH=CH–C–CH=CH–C–CH=CH–CH 3 3 H CH 3 CH 3 H (1) 0 (2) 1 (3) 2 (4) 4 22-05-2014 13/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST AIIMS PRE-MEDICAL : ENTHUSIAST, LEADER & ACHIEVER COURSE 68. Classical Smog is a :- (1) Reducing mixture (2) Oxidising mixture (3) Both the oxidising and reducing mixture (4) None of the above 69. A certain weak acid has K a = 1 × 10 –4 . Calculate the equilibrium constant for its rx with a strong base : (1) 10 –10 (2) 10 10 (3) 10 4 (4) 10 –4 70. The liquefied metal expanding on solidification is (1) Al (2) Cu (3) Ga (4) Zn 71. Most stable resonating structure is :- (1) CH –CH=CH–CH=N 3 CH 3 CH 3 © (2) CH –CH=CH–CH=N 3 CH 3 CH 3 © (3) CH –CH–CH=CH–N 3 CH 3 CH 3 © (4) CH –CH–CH–CH=N 3 CH 3 CH 3 © 72. Which is most stable ? (1) CH –OH 2 © (2) CH –Ph 2 © (3) CH –Cl 2 © (4) CH –NH 2 2 © 73. A living cell contains a solution which is isotonic with 0.2 M glucose solution. What osmotic pressure develops when the cell is placed in 0.05 M BaCl 2 solution at 300 K? (1) 1.23 atm (2) 3.69 atm (3) 6.15 atm (4) None of these 74. How many of the following compounds have used their d-orbital in hybridisation CF 4 , SF 4 , 3 I ÷ , SOF 4 , PF 3 Cl 2 , SnCl 2 , 2 4 SO ÷ (1) 6 (2) 5 (3) 3 (4) 4 75. Which of the following most reactive towards Hoffman bromamide reaction ? C–NH 2 CH 3 (A) O C–NH 2 OCH 3 (B) O C–NH 2 (C) O C–NH 2 NO 2 (D) O (1) A (2) B (3) C (4) D 68. =| n | - ¤ · | ¸ n + | t · | (Classical Smog) :- (1) ~ ¤ - | ¤ + l n ¬ º | (2) ~ | + =i + | · + l n ¬º | (3) ~ | + =i + | · + ( ¤ ~ ¤ - | ¤ + · | - | l n ¬ º | (4) · | - | n = + | : - t i 69. ( + · ¤ n ~ - n + | K a = 1 × 10 –4 t , : = · ¤ n ~ - n + | ¤ ¤ n - | | · + =| · | ~ l · | l + ¤ | =| - ¤ l ª · | · | + t | ª | (1) 10 –10 (2) 10 10 (3) 10 4 (4) 10 –4 70. · ¤ i œ - · | | - ¤| a | = ¤ - | - ¤ · ¤ =| l · - t | - | t + :- (1) Al (2) Cu (3) Ga (4) Zn 71. =¤ | l · | + ª · | | ¤ i ~ - - | · i = · - - | t :- (1) CH –CH=CH–CH=N 3 CH 3 CH 3 © (2) CH –CH=CH–CH=N 3 CH 3 CH 3 © (3) CH –CH–CH=CH–N 3 CH 3 CH 3 © (4) CH –CH–CH–CH=N 3 CH 3 CH 3 © 72. + | - =| =¤ | l · | + ª · | | ¤ i t ? (1) CH –OH 2 © (2) CH –Ph 2 © (3) CH –Cl 2 © (4) CH –NH 2 2 © 73. ( + ¤i l ¤ - + | l z| + | n ( + l ¤ n ¤ - t ¤| 0.2 M · n ¸ + | ¤ l ¤ n ¤ - + =n ¤ · | =· i t + ¤ l · + | l z | + | + | 0.05 M BaCl 2 l ¤ n ¤ - n · º | | ¤| ¤ - | 300 K ¤ · - · ¤ · | ¤ · | =· º | · | ¤ t | ª | ? (1) 1.23 atm (2) 3.69 atm (3) 6.15 atm (4) : - n = + | : - t i 74. l - - - n = l + - - ¤ | l ª + | n = + · º | n ~ ¤ - d- + - | + + | - ¤ ¤ | ª l + ¤ | t CF 4 , SF 4 , 3 I ÷ , SOF 4 , PF 3 Cl 2 , SnCl 2 , 2 4 SO ÷ (1) 6 (2) 5 (3) 3 (4) 4 75. t | + n - ¤ | n | : ÷ ~ l · | l + ¤ | + l n ¤ + | - =¤ | l · | + l + ¤ | z | i n t ? C–NH 2 CH 3 (A) O C–NH 2 OCH 3 (B) O C–NH 2 (C) O C–NH 2 NO 2 (D) O (1) A (2) B (3) C (4) D 22-05-2014 TARGET : PRE-MEDICAL 2014 14/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST AIIMS 76. Which of following is not correctly matched ? (1) (N–CH –C–N–(CH ) C 2 2 5 n ) H O H O ÷÷ Biodegradable Polymers (2) O–CH –CH –O–C 2 2 C [ O O n ÷÷ Fibre Polymer (3) C–(CH ) –N 2 5 H n O ] [ ÷÷ Thermoplastic polymer (4) CH –C=CH–CH 2 2 n ] [ Cl ÷÷ Weakest polymer 77. Which of the following aqueous solutions should have the highest osmotic pressure? (1) 0.011 M AlCl 3 at 50ºC (2) 0.03 M NaCl at 25ºC (3) 0.012 M (NH 4 ) 2 SO 4 at 25ºC (4) 0.03 M NaCl at 50ºC 78. Acidified K 2 Cr 2 O 7 turns green when Na 2 SO 3 is added to it. this is due to the formation of :- (1) Cr 2 (SO 4 ) 3 (2) 2 4 CrO ÷ (3) Cr(SO 4 ) 2 (4) CrSO 4 79. The empirical formula of compound is CH 2 O. 0.084 moles of the compound contains 1.0 g of hydrogen. Moleculoar formula of the compound is:- (1) C 6 H 12 O 6 (2) C 5 H 10 O 5 (3) C 4 H 8 O 8 (4) C 3 H 6 O 3 80. o-amino acid when heated with NaOH/ CaO forms :- (1) o, |-unsaturated acid (2) o, |-unsaturated amine (3) Carboxylic acid (4) Amine 76. l - - - n = + | - =t i = - n l n - - t i t ? (1) (N–CH –C–N–(CH ) C 2 2 5 n ) H O H O ÷÷ ¤ ¤ l - - - + · º | ¤ t n + (2) O–CH –CH –O–C 2 2 C [ O O n ÷÷ · z | ¤ t n + (3) C–(CH ) –N 2 5 H n O ] [ ÷÷ - | ¤ = · | º ¸ ¤ ¤ t n + (4) CH –C=CH–CH 2 2 n ] [ Cl ÷÷ · ¤ n - n ¤ t n + 77. l - - - n = l + = ¤n i ¤ l ¤ n ¤- + | - - - - n ¤ · | =· º | · | ¤ t | ª | ? (1) 0.011 M AlCl 3 at 50ºC (2) 0.03 M NaCl at 25ºC (3) 0.012 M (NH 4 ) 2 SO 4 at 25ºC (4) 0.03 M NaCl at 50ºC 78. ~ - n i ¤ K 2 Cr 2 O 7 , Na 2 SO 3 l n l ¬ - + · - ¤ · l + =+ l - n | º | = t · | t | ¤| - | t :- (1) Cr 2 (SO 4 ) 3 (2) 2 4 CrO ÷ (3) Cr(SO 4 ) 2 (4) CrSO 4 79. ( + ¤ | l ª + + | n ¸ n | - ¤ | - i =¸ z CH 2 O t + ¤ l · ¤ | l ª + + 0.084 n | n n 1.0 ª | n t | : ÷ ™ | ¤- - ¤ l ª · | - t - | ¤ | l ª + + | ~ º | =¸ z t :- (1) C 6 H 12 O 6 (2) C 5 H 10 O 5 (3) C 4 H 8 O 8 (4) C 3 H 6 O 3 80. o- ~ n i - | ~ - n + | NaOH/ CaO + =| · | ª n + · - ¤ · ¤ - - | t :- (1) o, |- ~ = - - - ~ - n (2) o, |- ~ = - - - ( n i - (3) + | ¤ | l + =l n + ~ - n (4) ( n i - 22–05–2014 15/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 PRE-MEDICAL : ENTHUSIAST, LEADER & ACHIEVER COURSE MAJOR TEST AIIMS 81. The period of oscillation of a simple pendulum is given by T 2 g = t where is about 100 cm and is known to have 1mm accuracy. The period i s about 2s. The time of 100 oscillations is measured by a stop watch of least count 0.1s. The percentage error in g is :- (1) 0.1 % (2) 1% (3) 0.2% (4) 0.8% 82. A small block of mass 20 kg rests on a bigger block of mass 30 kg which lies on a smooth horizontal plane. Initially the whole system is at rest. The coefficient of friction between the blocks is 0.5 and a horizontal force of 50 N is applied on the lower block then work done by frictional force on upper block in t = 2 sec is :- (1) 40 J 20 kg 30 kg F = 50 N (2) –40 J (3) 80 J (4) –80 J 83. A source emits a sound of frequency 400 Hz but the listener hears it to be 390 Hz then :- (1) The listener is moving towards the source (2) The source is moving towards the listener (3) The listener is moving away from the source (4) The listener has defective ear. 84. A 100 O resistance is connected in series with a 4H inductor. The voltage across the resistor is V R = 2 sin (10 3 t) then inductive reactance is :- (1) 8t × 10 3 O (2) 4 × 10 3 O (3) 8 × 10 –3 O (4) None 85. When the capillary is inclined at angle 30º and 60º with the vertical, the lengths of liquid columns inside the capillary are found to be 1 and 2 respectively. The ratio of 1 to 2 is:- (1) 1 : 2 (2) 1 : 2 (3) 1 : 3 (4) 3 :1 86. A wooden block of mass 10 gram is dropped from the top of a tower of height 100 m. Simultaneausly a bullet of mass 10 g is fired from the foot of the tower vertically upwards with a velocity of 100 m/s. If the bullet is embedded in it, how high will the block rise above the tower before it starts falling? (g = 10 m/s 2 ) :- (1) 75 m (2) 85 m (3) 80 m (4) 10 m 81. =· n n | n + + | · | n - + | n T 2 g = t = l · ¤ | ¤| - | t , ¤t | n ª · | ª100 cm t - · | | - ¤ ¸ - - n 1mm - + z| z- | = n | ¤ | ¤| - | t + · | n - + | n (T) n ª · | ª 2 = + º ÷ t + ¤ l · 100 · | n - | + =n ¤ + | - = · | ÷ i = n | ¤ | ¤| ( l ¤=+ | ~ - ¤ - n | + 0. 1 = + º ÷ t , - | g n ¤ l - z | - z l º t | ª i :- (1) 0.1 % (2) 1% (3) 0.2% (4) 0.8% 82. l - + - i - | l - ¤ =- t ¤ · · º | ª ¤ 30 l + ª | : · ¤ n | - + · n | + ¤ · 20 kg l + ª | : · ¤ n | - + | ( + ¤ | º | · n | + · º | | ¤| - | t + ¤ | · · | n =- ¤ ¸ º | l - + | ¤ l ¤ · | n n t + · | - | · n | + + n · ¤ · | · | º | ª º | | + 0.5 t - · | | - i - ¤ | n · n | + ¤ · 50 N + | - | l - ¤ ¤ n ~ | · | l ¤ - l + ¤ | ¤| - | t - | t = 2 = + º ÷ n · | · | º | , | · | ≈¤ · ¤ | n · n | + ¤ · l + ¤ | ª ¤ | + | ¤ t | ª | :- (1) 40 J 20 kg 30 kg F = 50 N (2) –40 J (3) 80 J (4) –80 J 83. ( + ª z | - 400 Hz ~ | ¤ l Ÿ | + i · ¤ l - - · =l ¤ - + · · t | t ¤ · - ¬ | - | + | 390 Hz ~ | ¤ l Ÿ | = - | : · · t i t | - | :- (1) ¬ | - | , ª z | - + i - · + ª l - z | i n t + (2) ª z | - , ¬ | - | + i - · + ª l - z | i n t + (3) ¬ | - | , ª z | - = · ¸ · ª l - z | i n t + (4) ¬ | - | + + | - n º | · | ¤ i t + 84. ( + 100 O ¤ l - · | · | ( + 4H ¤ · + · ¤ + =| · | ¬ º | i + n n = ¤ | l ¤- t + ¤ l · ¤ l - · | · | + l =· | ¤ · l ¤ · | ¤ | - - · V R = 2 sin (10 3 t) t | - | ¤ · + i ¤ ¤ l - · | | - t | ª i :- (1) 8t × 10 3 O (2) 4 × 10 3 O (3) 8 × 10 –3 O (4) None 85. ( + + z| - n i + | ≈ · ¤ | · | · = + n z| · 30º ( ¤ 60º ¤ · · º | - ¤ · + z | - n i + · ¤ + ª - - · | | + i n - ¤ | : ¤ | + n z| · 1 ¤ 2 ¤ | : ª : + 1 ¤ 2 + | ~ - ¤ | - t :- (1) 1 : 2 (2) 1 : 2 (3) 1 : 3 (4) 3 :1 86. 10 ª | n : · ¤ n | - + ( + n + ÷ i + · n | + + | 100 n i ≈ - i n i - | · + z | i · | = n + - l + ¤ | ¤| - | t - · | | : =i - | º | n i - | · + - i - = 10 ª | n : · ¤ n | - + i ( + ª | n i 100 m/sec. = ≈¤ · + i ~ | · - n | : ¤| - i t + ¤ l · ª | n i · n | + n + = ¤| - i t - | · n | + - i - l ª · - = ¤ t n n i - | · + z | i · | = l + - - | ≈¤ · ¤| ¤ ª i ·(g = 10 m/s 2 ) :- (1) 75 m (2) 85 m (3) 80 m (4) 10 m 22–05–2014 TARGET : PRE-MEDICAL 2014 16/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST AIIMS 87. One of the mode of resonance in a tube containing water at one end has been shown. The tube in the present case is in :- (1) First harmonic (2) Third harmonic (3) Fourth harmonic (4) Fifth harmonic 88. A plano-convex lens has focal f = 20 cm. If its plane surface is silvered, then the new focal length will be :- (1) 10 cm (2) 15 cm (3) 20 cm (4) 25 cm 89. A solid sphere of radius R and of bulk modulus K is immersed in a liquid contained in a cylindrical vessel. A piston of area A and of negligible weight floats on the surface of the liquid. When a weight M is placed on the piston to compress the liquid, the variation oR/R in the radius of the sphere will be:- (1) Mg/AK (2) Mg/3AK (3) 2Mg/3AK (4) 3Mg/AK 90. A particle of mass m 1m 1m O B C E D A moves wit h a const ant velocity. Whi ch of the following statements is not correct about its angular momentum about point O ? (1) It is zero when it is at A and moving along OA (2) It is same at all points along the line DE (3) It is of the same magnitude but oppositely directed at B and D (4) It increases as it moves along the line BC. 91. A satellite whose mass is M, is revolving in circular orbit of radius r around the earth. Time of revolution of satellite is (1) · 5 r T GM (2) · 3 r T GM (3) · 2 r T GM / 3 (4) 3 r T GM/ 4 · 87. ( + l =· n ¤ | - i = · | · i ( + - n i n ~ - - | · + i ( + l ¤ · | | · z | | ¤ i ª : t + · z | | ¤ i ª : ~ ¤ ª · | | n - n i t | ª i :- (1) ¤ · | n =- - | · i (2) - - i ¤ =- - | · i (3) - - · | =- - | · i (4) ¤ - n =- - | · i 88. 20 = n i + | + = · ¸ · i + | ( + =n - n | Ÿ | + n - = t + ¤ l · : =+ =n - n ¤ · a ¤ · - | · i + i + n : + i ¤| - i t - | - ¤ i + | + = · ¸ · i t | ª i :- (1) 10 = n i (2) 15 = n i (3) 20 = n i (4) 25 = n i 89. R l z º ¤ | - · | | K ~ | ¤ - - ¤ · ¤ | ª · | - | ª º | | + + ¤ · | · | + | ( + a | = ª | n | l + =i ¤ n - | + | · ¤ | z n · ¤ + ¤ l · ¤ z | n · º | | t + A - | z + n + | ( + · · ¤ n | - · l t - l ¤ ª º - · ¤ + i =- t ¤ · - · · t | t + ¤¤ l ¤ ª º - ¤ · M · · ¤ n | - + | = ¤ i l ÷ - + · - + l n ( · º | | ¤| - | t - | ª | n + i l z º ¤ | n ¤ l · ¤ - - oR/R t | ª | :- (1) Mg/AK (2) Mg/3AK (3) 2Mg/3AK (4) 3Mg/AK 90. m · · ¤ n | - + | ( + + º | l - ¤ - 1m 1m O B C E D A ¤ ª = ª l - + · - | t + l ¤ - · O + ¤ l · - · : =+ + | º | i ¤ ¤ ª + =- ¤ - · | n l - - - n = + | - =| + · | - ~ =· ¤ t ? (1) ¤ t z | ¸ - ¤ t ¤¤ + º | A ¤ · t - · | | OA + ~ - l · z | ª l - z | i n t + (2) DE + ~ - l · z | =· | i l ¤ - · ~ | ¤ · ¤ t =n | - t + (3) B - · | | D ¤ · : =+ | ¤ l · n | º | =n | - ¤ · - - l · z | | l ¤ ¤ · i - t + (4) BC + ~ - l · z | ª l - + · - ¤ · : =+ | n | - ¤ · - | t + 91. M : · ¤ n | - + | ( + - ¤ ª t , ¤ · ¤ i + - | · | ~ | · r l z º ¤ | + i ¤ Ÿ | i ¤ + - | | n - + + · n ª | · t | t + - ¤ ª t + | ¤ l · + n º | + | n t :- (1) · 5 r T GM (2) · 3 r T GM (3) · 2 r T GM / 3 (4) 3 r T GM/ 4 · + | : · | i ¤ z - Key Filling = ª n - - t i t | - | - | l t ( + 22–05–2014 17/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 PRE-MEDICAL : ENTHUSIAST, LEADER & ACHIEVER COURSE MAJOR TEST AIIMS 92. The plane faces of two identical plano-convex lenses, each having a focal length of 50 cm are placed against each other to form a usual biconvex lens. The distance from this lens combination at which an object must be placed to obtain a real, inverted image which has the same size as the object is :- (1) 25 cm (2) 40 cm (3) 50 cm (4) 100 cm 93. A projectile of mass 2kg has velocities 3m/s and 4m/s at two points during its flight in the uniform gravitational field of the earth. If these two velocities are perpendicular to each other, then the minimum kinetic energy of the particle during its flight is:- (1) 6.32 J (2) 8.40 J (3) 16.32 J (4) 5.76 J 94. A rigid body rotates about a fixed axis with variable angular velocity equal to o-|t at time t, where o and | are constants. The angle through which it rotates before it comes to rest is :- (1) 2 2 o | (2) 2 2 2 o ÷| o (3) 2 2 2 o ÷| | (4) ( ) 2 o o÷| 95. A geo-stationary satellite is orbiting the earth at a height of 6R above the surface of earth, R being the radius of earth. The time period of another satellite at a height of 2.5 R from the surface of earth is :- (1) 10 hr (2) 6 2 hr (3) 6 hr (4) 6 2 hr 96. When angle of incidence on a material is 60°, the reflected light is completely polarised. The velocity of the refracted ray inside the material in m/s is :- (1) 3 × 10 8 (2) 8 3 10 2 × (3) 3 × 10 8 (4) 0.5 × 10 8 92. · | ( + ¤ = 50 = n i + | + = · ¸ · i + =n - n | Ÿ | + n - =| + =n - n ¤ · a (+ · ¸ =· + l ¤ ¤ · i - · º | + · (+ =| n | - ¤ ¤ - l n - l , - Ÿ | n n - = ¤ - | ¤ | ¤| - | t + : = n - = = ¤ | ¤- = ¤ ª - + | l + - - i · ¸ · i ¤ · · º | - | - | l t ¤ l ¤== l + ¤ ª - + | ¤ | ª - l ¤ + , - - º | - · | | ¤ ª - l ¤- - =| : ¤ + | ¤ l - l ¤ - ¤ ¤ | - - t | =+ :- (1) 25 = n i (2) 40 = n i (3) 50 = n i (4) 100 = n i 93. ¤ · ¤ i + (+ =n | - ª ª · ¤ i ¤ - | z n - ÷ | - + · | · | - · | l ¤ - · ~ | ¤ · 2 kg · · ¤ n | - ¤ | n ¤ - | - ¤ + | ¤ ª 3m/s ~ | · 4m/s t + ¤ l · ¤ · | - | ¤ ª (+ · ¸ =· + n ¤ ¤ - t - | ¤ - | - ¤ + | - ÷ | - + · | · | - - ¤ ¸ - - n ª l - ¤ ≈¤| t | ª i :- (1) 6.32 J (2) 8.40 J (3) 16.32 J (4) 5.76 J 94. ( + · · ¤ ª - ( + l ª · | · ~ - | + ¤ l · - · ¤ l · ¤ - i + | º | i ¤ ¤ ª , f tld k e k u t =n ¤ ¤ · o-|t t , = · | ¸ n - i t + ¤t | o - · | | | l - ¤ - | + t + l ¤ · | n n ~ | - = ¤ ¸ ¤ : =+ , | · | · | ¸ n | ª ¤ | + | º | t :- (1) 2 2 o | (2) 2 2 2 o ÷| o (3) 2 2 2 o ÷| | (4) ( ) 2 o o÷| 95. ( + - - ¤ + | n i - ¤ ª t ¤ · ¤ i - n = 6R ≈ - | : ¤ · ¤ · ¤ i + - + + · n ª | · t | t , ¤t | R ¤ · ¤ i + i l z º ¤ | t + (+ ~ - ¤ - ¤ ª t + | ¤ l · + n º | + | n + ¤ | t | ª | ¤| ¤ · ¤ i - n = 2.5R ≈ - | : ¤ · - + + · n ª | · t | t :- (1) 10 hr (2) 6 2 hr (3) 6 hr (4) 6 2 hr 96. l + =i ¤ · | · | ¤ · ~ | ¤ - - + | º | 60° + l n ¤ ¤ · | ¤ l - - ¤ + | z | ¤ ¸ º | - ¤ | · | l ¤ - t | - | t + - ¤ n | · ¤ n ~ ¤ ¤ l - - ¤ + | z | + | ¤ ª t :- (1) 3 × 10 8 (2) 8 3 10 2 × (3) 3 × 10 8 (4) 0.5 × 10 8 ¤ · ¤ + ¤ z - + | ~ ¤ - ¤ - + · + · | + 22–05–2014 TARGET : PRE-MEDICAL 2014 18/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST AIIMS 97. A ball is projected upwards from the foot of the tower. The ball crosses the top of the tower twice after an interval of 6 sec and the ball reaches the ground after 12 sec. The height of the tower is (g= 10 m/s 2 ):- (1) 120 m (2) 135 m (3) 175 m (4) 80 m 98. 5 gm of steam at 100ºC is passed into 6 gm of ice at 0ºC. If the latent heats of steam and ice in cal per gm are 540 and 80 respectively, then the final temperature is :- (1) 0ºC (2) 100ºC (3) 50ºC (4) 30ºC 99. A capacitor having initial charge q 0 = CE/2 is connected to a cell of e. m. f. E through a resi stor R as shown. Find the total heat generated in the circuit after the switch S is closed :- + – C q 0 E S R (1) (1/12) CE 2 (2) (1/8)CE 2 (3) (1/4) CE 2 (4) None of these 100. A parallel beam of light of wavelength 6000 Å falls normally on a single slit of width 1 mm and the diffraction pattern is observed on a screen 2 m away. Fi nd the distance between the first dark fringes on either side of central bright fringe :- (1) 2.4 mm (2) 3.2 mm (3) 1.2 mm (4) None 101. A particle of mass 1 kg is moving along the line y = x + 2 (here x and y are in meter) with speed 2 m/sec. The magnitude of angular momentum of particle about origin is [kg m 2 /sec]:- (1) 4 (2) 2 2 (3) 4 2 (4) 2 97. º | ¤ · + ¤ | · = ( + ª · + | ≈¤ · + i ~ | · + + | ¤| - | t + ª · º | ¤ · + i ¤ - + | 6 = + º ÷ + =n ¤ ~ - · | n ¤ · · | ¤ | · ¤ | · + · - i t ~ | · ª · 12 = + º ÷ ¤ | · ¤n i - ¤ · ¤ t - - i t + º | ¤ · + i ≈ - | : t + (g= 10 m/s 2 ):- (1) 120 m (2) 135 m (3) 175 m (4) 80 m 98. 100ºC + i 5 ª | n · | | ¤ + | 0ºC + i 6 gm ¤ + n v ¤ | l t - + · - t + ¤ l · + n | · i ! ª | n n · | | ¤ - · | | ¤ + + i ª - - ≈· n | ( + n z | · 540 - · | | 80 t , - ¤ ~ l - - n - | ¤ t | ª | :- (1) 0ºC (2) 100ºC (3) 50ºC (4) 30ºC 99. ( + = · | | l · z l ¤=n ¤ | · l - · | + ~ | ¤ z | q 0 = CE/2 t , l - z | - =| · ( + ¤ º · i - · | | ¤ l - · | · | = ¤| ÷ | ª ¤ | t , + - ¤i S + | ¤ - · + · - + ¤ | · ¤ l - · | · | n + n - · ¤ - - - · n | t | ª i :- + – C q 0 E S R (1) (1/12) CE 2 (2) (1/8)CE 2 (3) (1/4) CE 2 (4) - ¤ · | + - = + | : - t i 100. 6000 Å - · ª · · ¤ + | =n - n ¤ + | z | ¤ ¤ ( + n l ª n º ¤ · n - ¤ ¤ - ~ | ¤ - i - t | - | t ¤ l · l ª n º + i - | ÷ | : 1 n i n i ( ¤ l ¤ ¤ - - ¤ l - ª¤ 2 n i · ¸ · ¤ · ¤ · ¤ | - - t | - ¤ + l - : ¤ - l - · a + · | - | ~ | · ¤ · | n + | n i l › ¤| + ¤ i - + i · ¸ · i t | ª i :- (1) 2.4 mm (2) 3.2 mm (3) 1.2 mm (4) None 101. ( + 1 l + ª | · · ¤ n | - ¤ | n | + º | · º | | y = x + 2 + ~ - l · z | 2m/sec. + i - | n = ª l - + · · t | t + ( ¤ t | x - · | | y n i º · n t ) n ¸ n l ¤ - · + ¤ l · - · + º | + + | º | i ¤ = ¤ ª + | ¤ l · n | º | [kg m 2 /sec]:- (1) 4 (2) 2 2 (3) 4 2 (4) 2 22–05–2014 19/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 PRE-MEDICAL : ENTHUSIAST, LEADER & ACHIEVER COURSE MAJOR TEST AIIMS 102. The figure shows a system of two concentric spheres of radii r 1 and r 2 and kept at temperatures T 1 and T 2 respectively. The radial rate of flow of heat in a substance between the two concentric spheres is proportional to :- r 1 r 2 T 1 T 2 (1) 1 2 2 1 r r (r r ) ÷ (2) (r 2 – r 1 ) (3) 2 1 1 2 (r r ) r r ÷ (4) log 2 1 r r | | | \ . 103. For the potentiometer arrangement shown in the figure, length of wire AB is 100 cm and its resistance is 9 O. Find the length AC for which the galvanometer G will show zero deflection :- r = 1 O E = 10 V E = 5 V r = 2 O G C A B (1) 66.7 cm (2) 60 cm (3) 50 cm (4) 33.3 cm 104. Nuclear reactions are given as - (i) (n, p) 15 p 32 (ii) (p, o) 8 O 16 (iii) 7 N 14 ( , p) 6 C 14 missing particle or nuclide (in box in these reactions are respectively :- (1) S 32 , F 19 , 0 n 1 (2) F 19 , S 32 , 0 n 1 (3) Be 9 , F 19 , 0 n 1 (4) None of these 102. l - z n r 1 - · | | r 2 l z º ¤ | ~ | + · | = + - : i (Concentric) ª | n | + | · z| | ¤ | ª ¤ | t ¤| l + + n z| · - | ¤ T 1 - · | | T 2 ¤ · l ª · | - t + · | - | = + - · i ª | n | + ¤ i - l ª · | - ¤ · | · | n l z º ¤ | + ~ - l · z | ≈· n | v ¤ | t + i · · = n | - ¤ | - i t | ª i :- r 1 r 2 T 1 T 2 (1) 1 2 2 1 r r (r r ) ÷ (2) (r 2 – r 1 ) (3) 2 1 1 2 (r r ) r r ÷ (4) log 2 1 r r | | | \ . 103. l · ¤ ª ¤ ¤ l · ¤ · | - | · AB + i n - ¤ | : 100 cm t - · | | : =+ | ¤ l - · | · | 9 O t + · | | · | n | ¤ i n z | ¸ - ¤ l ¤ - | ¤ + l n ( n - ¤ | : AC + | n | - + ¤ | t | ª | :- r = 1 O E = 10 V E = 5 V r = 2 O G C A B (1) 66.7 cm (2) 60 cm (3) 50 cm (4) 33.3 cm 104. - | l · | + i ¤ ~ l · | l + ¤ | ( - i - · i ª : t - (i) (n, p) 15 p 32 (ii) (p, o) 8 O 16 (iii) 7 N 14 ( , p) 6 C 14 : - ~ l · | l + ¤ | ~ | n ¤ | ÷ l · ¤ ª ¤ - | l · | + ( ~ · | | - ¸ ¤ | + = n ) + n z| · t :- (1) S 32 , F 19 , 0 n 1 (2) F 19 , S 32 , 0 n 1 (3) Be 9 , F 19 , 0 n 1 (4) : =n = + | : - t i Use stop, look and go method in reading the question 22–05–2014 TARGET : PRE-MEDICAL 2014 20/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST AIIMS 105. A block A with mass 100 kg is resting on another block B of mass 200 kg. As shown in figure a horizontal rope tied to a wall holds it. The coefficient of friction between A and B is 0.2 while coefficient of friction between B and the ground is 0.3. The minimum required force F to start moving B will be B A F Ground (1) 900 N (2) 100 N (3) 1100 N (4) 1200 N 106. Two containers of equal volumes are joined by a pipe. They cont ain the same gas at pressure P 0 and temperature T 0 K. One of the containers is heated to 2T 0 . The number of moles in this container at this temperature is :- (1) 0 0 0 P V 2RT (2) 0 0 0 P V RT (3) 0 0 0 2P V 3RT (4) 0 0 0 P V 3RT 107. In the figure shown, find the ratio of the linear charge densities ì 1 (on semi-infinite straight wire ) and ì 2 (on semi-circular part), that is, 1 2 / ì ì so that the field O is along y direction :- R O y ì 1 x ì 2 (1) 2 (2) 1 (3) 2 (4) 3 108. Light from a hydrogen discharge tube is incident on the cathode of a photoelectric cell the work function of the cathode surface is 4.2 eV. In order to reduce the photocurrent to zero the voltage of the anode relative to the cathode must be made :- (1) –4.2 V (2) –9.4 V (3) –17.8 V (4) +9.4 V 105. ( + ª º + | A l ¤=+ | : · ¤ n | - 100 kg t , ( + ~ - ¤ 200 kg + ª º + B + ≈¤ · l - z | - =| · l ª · | - t + · i ¤ | · = ¤ · | i ÷ | · i , | · | : = l ª · | · · º | | ª ¤ | t + A - · | | B + n · ¤ · | · | º | ª º | | + 0.2 t , ¤¤ l + B ¤ ¤ · ¤ i + n · ¤ 0.3 t + B + | ª l - n | - + · - + l n ( ~ | ¤ z ¤ + - ¤ ¸ - - n ¤ n F t | ª | B A F Ground (1) 900 N (2) 100 N (3) 1100 N (4) 1200 N 106. =n | - ~ | ¤ - - | + · | ¤ | z ( + ¤ | : ¤ = ¤ - | ¤ ª ¤ t + : - n · | ¤ P 0 - · | | - | ¤ T 0 K ¤ · =n | - ª = · | · i t + ( + ¤ | z + | - | ¤ 2T 0 - + ª n + · - t + : = - | ¤ ¤ · ¤ | z n n | n | + i = º ¤ | :- (1) 0 0 0 P V 2RT (2) 0 0 0 P V RT (3) 0 0 0 2P V 3RT (4) 0 0 0 P V 3RT 107. l · ¤ l - z n ~ z ~ - - - · | | ª + · º | i ¤ ~ | ¤ z | · | - · ¤ ì 1 - · | | ~ z ¤ Ÿ | | + | · · | | ª + · º | i ¤ ~ | ¤ z | · | - · ¤ ì 2 + | ~ - ¤ | - 1 2 / ì ì a | - + · l ¤== O ¤ · l ¤ ¤ - - | z y ~ - | + ~ - l · z | t | ¤| ¤ :- R O y ì 1 x ì 2 (1) 2 (2) 1 (3) 2 (4) 3 108. t | : ÷ ™ | ¤- l ¤ =¤ - - l n + | = - · =l ¤ - ¤ + | z | , ( + ¤ + | z | l ¤ ¤ - = n + + · | | ÷ ¤ · l ª · - | t + = n + + · | | ÷ + | + | ¤ + n - 4.2 eV t + ¤ + | z | l ¤ ¤ - · | | · | + | n | - z | ¸ - ¤ + · - + l n ( + · | | ÷ + =| ¤ - | ( - | ÷ + | l ¤ · | ¤ t | ª | :- (1) –4.2 V (2) –9.4 V (3) –17.8 V (4) +9.4 V 22–05–2014 21/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 PRE-MEDICAL : ENTHUSIAST, LEADER & ACHIEVER COURSE MAJOR TEST AIIMS 109. A block of mass 200 kg is being pulled up by men on an inclined plane at angle of 45° as shown. The coefficient of static friction is 0.5. Each man can only apply a maximum force of 500 N. Calculate the number of men required for the block to just start moving up the plane : 45° (1) 10 (2) 15 (3) 5 (4) 3 110. A particle of mass m moving along x-axis has a potential energy U(x) = a + bx 2 where a & b are postive constant. It will execute SHM with a frequency determined by the value of :- (1) a alone (2) a, b both (3) b and m both (4) b, a, m 111. A circular arc carrying current I is placed in uniform magnetic field B as shown in diagram. then force on arc is :- (1) BIR tan o × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × A B I B o R (2) 2BIR cos(o/2) (3) 2BIR sin (o/2) (4) None of these 112. The curve drawn between velocity and frequency of photon in vacuum will be a :- (1) Straight line parallel to frequency axis (2) Straight line parallel to velocity axis (3) Straight line passing through origin and making an angle of 45° with frequency axis. (4) Hyperbola 113. A position dependent force, F = 7 – 2x + 3x 2 N, acts on a small body of mass 2 kg and displaces it from x = 0 to x = 5m. The work done (in joule) is :- (1) 70 (2) 270 (3) 35 (4) 135 109. · ¤ l + - 45° ¤ + | ¤ + - - - n ¤ · l - z | - =| · 200 kg : · ¤ n | - + | · n | + ≈¤ · º | i - - t + ª · | l - + · | · | º | ª º | | + 0.5 t + ¤ · ¤ + · ¤ l + - ~ l · | + - n 500 N + | ¤ n ~ | · | l ¤ - + · =+ - | t + · n | + + | - n ¤ · a i + ≈¤ · ª l - n | - + · - + l n ¤ ~ | ¤ z ¤ + · ¤ l + - ¤ | + i = º ¤ | t | ª i + 45° (1) 10 (2) 15 (3) 5 (4) 3 110. ( + m : · ¤ n | - + | + º | x- ~ - | n l ª · | l - ¤ - · ¤| U(x) = a + bx 2 + =| · | ª l - + · · t | t + ¤ t | a - · | | b · | - | · n + l - ¤- | + t + t + ¤ t l ¤= ~ | ¤ l Ÿ | = =· n ~ | ¤ - ª l - + · - | t ¤ t l - · | | l · - t | ª i :- (1) a alone (2) a, b · | - | (3) b ¤ m · | - | (4) b, a, m 111. ( + ¤ Ÿ | i ¤ - | ¤ n I · | | · | ¤ ¤ | l t - t : = l - z | - =| · =n ª¤ - - ¤ + i ¤ - | z B n · º | | ª ¤ | t + - | - | ¤ ¤ · ¤ n t | ª | :- (1) BIR tan o × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × × A B I B o R (2) 2BIR cos(o/2) (3) 2BIR sin (o/2) (4) None of these 112. l - ¤ | - n + | º | - + ¤ ª ~ | · ~ | ¤ l - + n · ¤ º | i - | ª ¤ | ¤ + :- (1) ~ | ¤ l Ÿ | ~ - | + =n | - - · ( + =· n · º | | t | ª i (2) ¤ ª ~ - | + =n | - - · ( + =· n · º | | t | ª i (3) n ¸ n l ¤ - · = t | + · ¤| - ¤ | n i ( ¤ ~ | ¤ l Ÿ | ~ - | = 45° + | º | ¤ · l ª · | - (+ =· n · º | | t | ª i (4) ~ l - ¤ · ¤ n ¤ 113. l ª · | l - ¤ · l - · | · + · - ¤ | n | ( + ¤ n F = 7 – 2x + 3x 2 - ¤ ¸ º - 2 l + ª | · · ¤ n | - + i ( + ¤ | º i ¤ ª - ¤ · ~ | · | l ¤ - t | - | t - · | | : = x = 0 = x = 5 n i º · - + l ¤ ª · | | l ¤ - + · · - | t + ¤¸ n n l + ¤ | ª ¤ | + | ¤ t :- (1) 70 (2) 270 (3) 35 (4) 135 22–05–2014 TARGET : PRE-MEDICAL 2014 22/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST AIIMS 114. A spring balance has a scale that can read from 0 to 50 kg. The length of scale is 20 cm. A body suspended from this balance when displaced and released oscillate harmonically with a time period of 0.6 sec. The mass of body is : [g = 10 m/sec 2 ] (1) 10 kg (2) 25 kg (3) 18 kg (4) 22.8 kg 115. A magnet 10 cm long and having a pole strength 2 A-m is deflected through 30° from the magneti c meridi an. The horizontal component of earth' s induction is 0.32 × 10 –4 T, Then the value of deflecting couple is :- (1) 32 × 10 –7 N-m (2) 16 × 10 –7 N-m (3) 64 × 10 –7 N-m (4) 48 × 10 –7 N-m 116. The output of the given circuit :- R V 0 V sin t m m e (1) Would be zero at all times (2) Would be like a half wave rectifier with positive cycles in output (3) Would be like a half wave rectifier with negative cycle in output (4) Would be like that of a full wave rectifier 117. A bomb of mass 9 kg explodes into two pieces of masses 3 kg and 6 kg. The velocity of mass 3 kg is 16 m/s. The KE of mass 6 kg in joule is :- (1) 96 (2) 384 (3) 192 (4) 768 118. In brass the velocity of longitudinal wave is 100 times the velocity of the transverse wave. If Y = 10 11 N/m 2 then stress in the wire is :- (1) 10 13 N/m 2 (2) 10 9 N/m 2 (3) 10 11 N/m 2 (4) 10 7 N/m 2 119. In the figure shown current i = 10e –4t A. Value of V L and V a – V b is :- R = 4O L = 2H a b i (1) –80 e –4t , –40 e –4t (2) 80 e –4t , 10 e –4t (3) –40 e –4t , –80 e –4t (4) Zero, Zero 114. ( + l ª ¤ ª - n | 0 = 50 kg - + + | n | ¤ - + · =+ - | t + ª + n + i n - ¤ | : 20 cm t + ( + ¤ ª - + | : = - n | = n º + | ¤ | ¤| - | t | - · | | l ¤ ª · | | l ¤ - + · - ¤ · ¤ t ~ | ¤ - + | n 0.6 sec = · | n - + · - | t + ¤ ª - + | : · ¤ n | - t | ª | : [g = 10 m/sec 2 ] (1) 10 kg (2) 25 kg (3) 18 kg (4) 22.8 kg 115. ( + - - ¤ + + i n - ¤ | : 10 cm - · | | · | ¤ =| n · ¤ 2 A-m t ¤ t - - ¤ + i ¤ ¤ | - ¤ | Ÿ | · = 30° + | º | = l ¤ - | l ¤ - t ¤ · ¤ i + - - ¤ + i ¤ - | z + | - | l - ¤ · | º + 0.32 × 10 –4 T t - | l ¤ - | ¤ + ¤ n ¤ · n t | ª | :- (1) 32 × 10 –7 N-m (2) 16 × 10 –7 N-m (3) 64 × 10 –7 N-m (4) 48 × 10 –7 N-m 116. l · ( ª ( ¤ l · ¤ · | + | l - ª - t | ª | :- R V 0 V sin t m m e (1) t · =n ¤ z | ¸ - ¤ (2) ~ z - · ª l · · º + | · i l + - · t l ¤=n · | - | · n + - + l - ª - n t + (3) ~ z - · ª l · · º + | · i l + - · t l ¤=n Ωº | | · n + - + l - ª - n t + (4) ¤ ¸ º | - · ª l · · º + | · i l + - · t + 117. 9 l + ª | · · ¤ n | - + | ( + ¤ n , 3 l + ª | ( ¤ 6 l + ª | + · | º + ÷ | n + º ¤| - | t + 3 l + ª | · · ¤ n | - + | ¤ ª 16 n i/ = t + 6 l + ª | · · ¤ n | - + i ª l - ¤ ≈¤| ¤¸ n n t :- (1) 96 (2) 384 (3) 192 (4) 768 118. ¤ i - n n ~ - · · ¤ - · ª + | ¤ ª , ~ - ¤ ª · | - · ª + ¤ ª + | 100 ª - | t + ¤ l · Y = 10 11 N/m 2 t | - | - | · n ¤ l - ¤ n t | ª | :- (1) 10 13 N/m 2 (2) 10 9 N/m 2 (3) 10 11 N/m 2 (4) 10 7 N/m 2 119. · z | | ¤ ª ( l - z n · | | · | i = 10e –4t A. V L - · | | V a – V b + | n | - t | ª | :- R = 4O L = 2H a b i (1) –80 e –4t , –40 e –4t (2) 80 e –4t , 10 e –4t (3) –40 e –4t , –80 e –4t (4) Zero. Zero 22–05–2014 23/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 PRE-MEDICAL : ENTHUSIAST, LEADER & ACHIEVER COURSE MAJOR TEST AIIMS 120. The logic circuit shown below has the input waveform 'A' and 'B' as shown. Pick out the correct output waveform : A B y Input A Input B Out put is :- (1) (2) (3) (4) DIRECTIONS FOR Q. NO. 121 TO 180 These questions consist of two statements each, printed as Assertion and Reason. While answering these Questions you are required to choose any one of the following four responses. A. If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion. B. If both Assertion & Reason are True but Reason. is not a correct explanation of the Assertion. C. If Assertion is True but the Reason is False D. If both Assertion & Reason are false. 121. Assertion :- Usually bacterial cells are haploid. Reason :- Merozygots are partially diploid bacterial cell. (1) A (2) B (3) C (4) D 122. Assertion :- Vitamins are essential for healthy life. Reason :- Vitamins regulate metabolism (1) A (2) B (3) C (4) D 120. l · ( ª ( - | l + + ¤ l · ¤ · | n · z| | ¤ ª ( l - ¤ z | i - · ª 'A' - · | | 'B' t + =t i l - ª - - · ª t | ª i : A B y Input A Input B Out put is :- (1) (2) (3) (4) ¤ z - = º ¤ | 121 = 180 + l n ( l - · z | ¤ · ¤ + ¤ z - n + · | - - · | | + | · º | l · ( ª ¤ t + ¤ z - | + | t n + · - =n ¤ - i - l · ( ª ( - | · | l ¤ + - ¤ | n = =t i l ¤ + - ¤ + | - l - ( + A. ¤ l · + · | - ( ¤ + | · º | · | - | =· ¤ t - · | | + | · º | + · | - + | =t i ª ¤ · º i + · º | t + B. ¤ l · + · | - ( ¤ + | · º | · | - | =· ¤ t , n l + - + | · º | , + · | - + | =t i ª ¤ · º i + · º | - t i t + C. ¤ l · + · | - = · ¤ t , n l + - + | · º | ~ =· ¤ t + D. + · | - ¤ + | · º | · | - | ~ = · ¤ t + 121. + · | - :- =| n | - ¤ - ¤ | ¤i ¤ | º | + | z | i + | ~ ª l º | - t | - i t + + | · º | :- l n · | ¤| : ª | º ~ | l z | + l , ª l º | - ¤i ¤ | º | + | l z | + | t + (1) A (2) B (3) C (4) D 122. + · | -:- l ¤ º | l n - ª ¤ ª · | ¤i ¤ - + l n ¤ ~ | ¤ z ¤+ t + + | · º | :- l ¤ º | l n - - ¤ | ¤ - ¤ + | l - ¤ l n - + · - | t + (1) A (2) B (3) C (4) D 22–05–2014 TARGET : PRE-MEDICAL 2014 24/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST AIIMS 123. Assertion :- A flower with more number of whorls are primitive then a flower with less number of whorls. Reason :- Trees are more advance then shurbs. (1) A (2) B (3) C (4) D 124. Assertion :- Hypothalamus acts as a osmoregulatory centre. Reason :- Paraventricular Nuclei of hypothalamus controls the concentration of water. (1) A (2) B (3) C (4) D 125. Assertion :- Animal belonging to phylum Arthropoda are fundamentally characterised by the presence of jointed appendages and chitinous exoskeleton. Reason :- These are enterocoelomic and deuterostomate animals. (1) A (2) B (3) C (4) D 126. Assertion :- In Polygonum all the 8 nuclei of an embryosac are genetically similar. Reason :- In Polygonum single microspore forms the embryosac. (1) A (2) B (3) C (4) D 127. Assertion :- Retrogressive metamorphosis is found in tadpole larva of Herdmania. Reason :- Tail and notochord are absent in adult Herdmania. (1) A (2) B (3) C (4) D 128. Assertion :- Epistasis is between non allelic genes. Reason :- Epistatic gene and hypostatic gene are present on different locus. (1) A (2) B (3) C (4) D 129. Assertion :- Uric acid is produced by metabolism of purine and pyrimidine Reason :- Uric acid has high toxicity and soluble in water. (1) A (2) B (3) C (4) D 130. Assertion :- In rural area white winged moth were less than melanic moth. Reason :- In rural area, Industrilisation occur. (1) A (2) B (3) C (4) D 131. Assertion :- Ca +2 play important role in the muscle contraction Reason :- Ca +2 combine with troponin chain, displacing tropomyosin, allowing the myosin head part to combine with actin to form actomyosin complex. (1) A (2) B (3) C (4) D 123. + · | - :- ~ l · | + ¤ · ¤ - + ¤ | n | ¤ · ¤ , + n ¤ · ¤ - + ¤ | n ¤ · ¤ = ¤ · | - - t | - | t + + | · º | :- ¤ - | , - | ¤ = ~ l · | + ~ ª º | i t + (1) A (2) B (3) C (4) D 124. + · | - :- t | : ¤ | · | n n = ¤ · | =· º | + - : + i - · t + | ¤ + · - | t + + | · º | :- t | : ¤ | · | n n = + | ¤ · | ¤ - º ™ i + ¸ n · + - : + ¤n + i =| - : - | + | l - ¤ l z - + · - | t + (1) A (2) B (3) C (4) D 125. + · | -:- ~ | · | | ¤ | ÷ | = · | + ¤ | l º | ¤ | n l ¤ l z | · º n - | º | + ª¤ n = l · | ¤ + - ¤ | · ~ | · + | : l º - ¤ + - ¤ | t ¸ ¤ + + | n ¤ | ¤ | ¤| - | t + + | · º | :- ¤ ( - º · | l =n | n º - · | | ÷ ¸ ¤ ¸ º · | ª º | n º ¤ | º | i t | - t + (1) A (2) B (3) C (4) D 126. + · | -:- ¤ | n i ª | - n n ( + · | ¸ º | + | · | + =· | i 8 + - · + ~ | - ¤ | l z | + ª¤ = =n | - t | - t + + | · º | :- ¤ | n i ª | - n n · | ¸ º | + | · | + | l - n | º | (+ n n · | ¤ i ¤| º | = t | - | t + (1) A (2) B (3) C (4) D 127. + · | -:- t ÷ n | l - ¤ | + º ÷ ¤ | n n | ¤ | n ¤ l - ª | n i + | ¤ | - - · º | ¤ | ¤ | ¤| - | t + + | · º | :- · ¤ ª + t ÷ n | l - ¤ | n ¤ ¸ ¤ ( ¤ - | º | + | ÷ ~ - ¤ l ª · | - t | - i t + (1) A (2) B (3) C (4) D 128. + · | - :- : ¤ i ª º l == ~ ¤ · n l ¤ + - ¤ i ¤i - | + ¤ i - t | - | t + + | · º | :- : ¤ i ª º l º + ¤i - - · | | t | : ¤ | ª º l º + ¤i - l · | - - ª · | | - : n | + =| ¤ · - ¤ l ª · | - t | - t + (1) A (2) B (3) C (4) D 129. + · | -:- - ¤ ¸ l · - ¤ l ¤ · i l n l ÷ - + - ¤ | ¤ - ¤ , | · | ¤ ¸ l · + ~ - n ¤ - - | t + + | · º | :- ¤ ¸ l · + ~ - n ~ l · | + l ¤ · | | + - - · | | ¤n n · | n - z| i n t | - | t + (1) A (2) B (3) C (4) D 130. + · | -:- ª | n i º | : n | + | n z ¤ - ¤ º | i z | n + | + i = º ¤ | + n t | - i t + ¤¤ l + ~ z ¤ - z| n + | + i = º ¤ | ~ l · | + t | - i t + + | · º | :- ª | n i º | : n | + | n ~ | ¤| l ª + · º | t | - | t + (1) A (2) B (3) C (4) D 131. + · | -:- ¤ z | i = + - - n Ca +2 n t · ¤ ¤ ¸ º | · | ¸ l n + | ~ · | + · - t + + | · º | :- Ca +2 º ™ | ¤ | l - - ¬ º | n | + =| · | ¤ l - · | - t | - t , º ™ | ¤ | n | ¤ | l =- + | t º | - t - · | | n | ¤ | l =- + l =· · | | ª + | ( l + º - + =| · | ¤ ÷ + · ' ' ( + º | n | ¤| l =- ¤l º n ' ' ¤ - ¤ | - n n t · ¤ ¤ ¸ º | · | ¸ l n + | ~ · | + · - t + (1) A (2) B (3) C (4) D 22–05–2014 25/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 PRE-MEDICAL : ENTHUSIAST, LEADER & ACHIEVER COURSE MAJOR TEST AIIMS 132. Assertion :- Those who take drugs intravenously are much more likely to acquire serious infections like AIDS and hepatitis B. Reason :- The viruses, which are responsible for these diseases are transferred from one person to another by sharing of infected needles. (1) A (2) B (3) C (4) D 133. Assertion :- The Ethylene is a fruit ripening hormone of plants. Reason :- Ethylene is a gaseous plant growth regulator (PGR) (1) A (2) B (3) C (4) D 134. Assertion :- PET technique is based on pietzo- electric effect. Reason :- MRI, is suitable technique to investigate fractures in bones. (1) A (2) B (3) C (4) D 135. Assertion :- Hexokinase and phosphofructokinase are regulatory enzymes of glycolysis. Reason :- These are allosteric enzymes in glycolysis. (1) A (2) B (3) C (4) D 136. Assertion :- Association of Algae and fungi in lichens is mutualism. Reason :- In this interaction fungus behave as a slave and algae act as a master. (1) A (2) B (3) C (4) D 137. Assertion :- Photorespiration is a double waste process in C 3 plants. Reason :- NO production of NADH or ATP in the process but it reduces glucose production. (1) A (2) B (3) C (4) D 138. Assertion :- Earth is a closed system for materials (minerals). Reason :- Earth does not receive any material (minerals) from outside. (1) A (2) B (3) C (4) D 139. Assertion :- Topoisomerase enzyme prevents supercoiling of DNA. Reason :- Topoisomerase enzyme acts on hydrogen bond. (1) A (2) B (3) C (4) D 140. Assertion :- In most favourable environmental conditions organism has maximum biotic potential. Reason :- Biotic potential is a maximum reproduction capacity of an organism. (1) A (2) B (3) C (4) D 132. + · | -:- ¤| ~ - · l z | · | , | · | ~ | · | l · | + | = ¤ - + · - t - - + | AIDS ¤ ¤ œ - z | | · | B ¤ = ª - · | i · = + n º | | + t | - + i º ¤ | · | =- · | | ¤ - | t | - i t + + | · º | :- : - · | ª | + l n ¤ - Ÿ | · · | ¤ i l ¤ · | | º | ~ | + | ( + · ¤ l + - = · ¸ =· n ª · | | - | - · º | = + l n - = : + =| ¤ | + · - = t | - | t + (1) A (2) B (3) C (4) D 133. + · | -:- ( · | i n i - ¤ | · ¤ | + | + n ¤ l · ¤ + ¤ - t | n | - t + + | · º | :- ( · | i n i - ª =i ¤ ¤ | · ¤ ¤ l z l - ¤ | n + (PGR) t + (1) A (2) B (3) C (4) D 134. + · | -:- PET - + - i + l ¤ ¤| l ¤ ¤ - ¤ · | | ¤ ¤ · ~ | · | | l · - t | - i t + + | · º | :- MRI ~ l ª · | ¤ | + › + - · + | ¤ - | n ª | - + l n ¤ - ¤ ¤ + - - + - i + t + (1) A (2) B (3) C (4) D 135. + · | -:- t + ¤| + | : - ¤ ( ¤ + | ª + | ›+ º | + | : - ¤ · n | : + | l n l == + l - ¤ | n + l ¤ + · t | - t + + | · º | :- ¤ · n | : + | l n l == + ( n | ª º l · + l ¤ + · t + (1) A (2) B (3) C (4) D 136. + · | -:- n | : + - n + ¤ + - · | | z| ¤ | n + | = ¤ · | =t | ¤ + | l · - | t + + | · º | :- : = ~ - - = - ¤ - · | n + ¤ + , ª n | n + i - · t · ¤ ¤ t | · · z | | - | t - · | | z | ¤ | n , n | l n + + i - · t + (1) A (2) B (3) C (4) D 137. + · | -:- ¤ + | z | z ¤ =- C 3 ¤ | · | | n · | t · i t | l - l + ¤ | t + + | · º | :- : = ¤ l + ¤ | n NADH ¤ | ATP + | - · ¤ | · - - t i t | - | t , ¤ · - - ¤ t · n ¸ + | ¤ + - · ¤ | · - + | · | º | · - i t + (1) A (2) B (3) C (4) D 138. + · | -:- ¤ · | · | | : º | l - ¤| | + l n ( ¤ · ¤ i ( + ¤ - · - z t + + | · º | :- ¤ · ¤ i l + =i · | i - · t + ¤ · | · | : º | l - ¤| | + | ¤ | t · = ª t º | - t i + · - i t + (1) A (2) B (3) C (4) D 139. + · | - :- º | ¤ | ~ | : =| n · ¤ ( ¤| : n DNA n ~ · ¤ l · | + + º ÷ n - + | · | + - | t + + | · º | :- º | ¤ | ~ | : =| n · ¤ ( ¤| : n t | : ÷ ™ | ¤- ¤ · | ¤ · l + ¤ | + · - | t + (1) A (2) B (3) C (4) D 140. + · | -:- ~ l · | + - n ~ - + ¸ l n - ¤ ¤ | ¤ · º | i ¤ ¤ l · l ª · | l - ¤ | n l + =i · | i ¤i ¤ + | ¤ l ¤ + l ¤ · | ¤ ~ l · | + - n t | - | t + + | · º | :- ¤ l ¤ + l ¤ · | ¤ l + =i · | i ¤i ¤ + i ~ l · | + - n ¤ ¤- - - | n - | t + (1) A (2) B (3) C (4) D 22–05–2014 TARGET : PRE-MEDICAL 2014 26/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST AIIMS 141. Assertion :- The molecularity of the reaction H 2 + Br 2 ÷÷ 2HBr is 2. Reason :- The order of reaction is 3/2. (1) A (2) B (3) C (4) D 142. Assertion :- Na 2 SO 4 is soluble in water while BaSO 4 is insoluble. Reason :- Lattice energy of BaSO 4 exceeds its hydration energy. (1) A (2) B (3) C (4) D 143. Assertion :- Activity of an enzyme is pH dependent. Reason :- Changes in pH affect the solubility of the enzyme in water. (1) A (2) B (3) C (4) D 144. Assertion :- Nitration of benzene with nitric acid requires the use of concontrated sulphuric acid. Reason :- The mixture of concentrated sulphuric acid and concentrated nitric acid produces electrophile © NO 2 (1) A (2) B (3) C (4) D 145. Assertion :- Noble gases can be easily liquefied. Reason :- Attractive forces can exist between non polar molecules. (1) A (2) B (3) C (4) D 146. Assertion :- o-H in carbonyl compound is less acidic. Reason :- The anion formed after the loss of o-H atome is resonance destabilised. (1) A (2) B (3) C (4) D 147. Assertion :- The pH of pure water is less than 7 at 60°C. Reason :- As temperature increases, pure water becomes slightly acidic (1) A (2) B (3) C (4) D 148. Assertion :- In monohaloarenes, further electrophilic substitution occurs at ortho and para position. Reason :- Halogen atom is ortho and para directing group. (1) A (2) B (3) C (4) D 149. Assertion :- An increase in surface area increases the rate of evaporation. Reason :- Stronger the inter-molecular attraction forces, faster is the rate of evaporation at a given temperature. (1) A (2) B (3) C (4) D 141. + · | -:- ~ l · | l + ¤ | H 2 + Br 2 ÷÷ 2HBr + l n ( ~ º | = º ¤ - | + | n | - 2 t + + | · º | :- ~ l · | l + ¤ | + i + | º i 3/2 t + (1) A (2) B (3) C (4) D 142. + · | - :- Na 2 SO 4 ¤n n l ¤ n ¤ t BaSO 4 ~ l ¤ n ¤ t + + | · º | :- BaSO 4 + i ¤| n + ≈ ¤| , ¤n ¤ | ¤- ≈¤| = ~ l · | + t + (1) A (2) B (3) C (4) D 143. + · | -:- ( - ¤| : n + i =l + ¤ - | pH ¤ · l - · | · + · - i t + + | · º | :- pH n ¤ l · ¤ - - ( - ¤| : n + i ¤n n l ¤ n ¤ - | + | ¤ · | | l ¤ - + · - i t + (1) A (2) B (3) C (4) D 144. + · | -:- ¤ ¤i - + - | : º ™ i + · º | + l n ¤ =| - · =- ∂ ¤ l · + ~ - n + i ~ | ¤ z ¤ + - | t + + | · º | :- =| - · =- ∂ ¤ l · + ~ - n - · | | =| - · - | : º ™ i + ~ - n + | l n ¬ º | © NO 2 : n + º ™ | - ª - t i - · ¤ - - + · - | t + (1) A (2) B (3) C (4) D 145. + · | -:- - · œ · a ª =| + | ~ | =| - i = · ¤ i œ - l + ¤ | ¤| =+ - | t + + | · º | :- ~ · | ¤ i ¤ ~ º | ~ | + n · ¤ ~ | + · | º | ¤ n - ¤ l ª · | - t | =+ - | t + (1) A (2) B (3) C (4) D 146. + · | -:- + | ¤ | l - n ¤ | l ª + + | o-H - ¤ - - n ~ - n i ¤ t + + | · º | :- o-H + l - + n - ¤ · ¤| Ωº | | ¤ - ¤ - | t ¤ t ~ - - | · , | · | ~ ª · | | ¤ i t + (1) A (2) B (3) C (4) D 147. + · | - :- 60°C ¤ · z | z ¤n + i pH '7' = + n t | - i t + + | · º |:- - | ¤ ¤ · | - ¤ · , z | z ¤n ~ - n i ¤ t | ¤| - | t (1) A (2) B (3) C (4) D 148. + · | -:- n | - | t n | ( · i - n , : n + º ™ | - ª - t i ¤ l - ª · | | ¤ - ~ | · | | - · | | ¤ · | l ª · | - i ¤ · t | ª | + + | · º | :- t n | ¤- ¤ · n | º | ~ | · | | - · | | ¤ · | l - · z | i =n ¸ t t + (1) A (2) B (3) C (4) D 149. + · | - :- ¤ · a i ¤ - | z + n n ¤ l z t | - ¤ · ¤ | · ¤ - + i · · n ¤ l z t | - i t + + | · º | :- l · ¤ ª ¤ - | ¤ ¤ · ~ - - · ~ | º | l ¤ + ~ | + · | º | ¤ n ¤ ¤ n t | - ¤ · ¤ | · ¤ - + i · · - i ¤ t | - i t + (1) A (2) B (3) C (4) D 22–05–2014 27/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 PRE-MEDICAL : ENTHUSIAST, LEADER & ACHIEVER COURSE MAJOR TEST AIIMS 150. Assertion :- Acetanilide is more basic than aniline. Reason :- Acetylation of aniline results in increase of electron density. (1) A (2) B (3) C (4) D 151. Assertion :- The plot of k versus 1/T is linear. Reason :- E /(RT) k A.e o ÷ = (1) A (2) B (3) C (4) D 152. Assertion :- Bond angle in ethers is slightly less than tetrahedral angle. Reason :- There is repulsion between two Bulky (–R) groups. (1) A (2) B (3) C (4) D 153. Assertion :- Mn atom loses ns electrons first during ionisation as compared to (n –1)d electrons. Reason :- The effect ive nuclear charge experienced by (n-1)d electrons is greater than that of ns electrons. (1) A (2) B (3) C (4) D 154. Assertion :- Equivalent weight of Cu in CuO is 31.8 and in Cu 2 O 63.6. Reason :- Equivalent weight of an element = Atomic weight of the element Valency of the element (1) A (2) B (3) C (4) D 155. Assertion :- K 2 CrO 4 is a yellow coloured compound. Reason :- Chromate i on has tetrahedral geometry. (1) A (2) B (3) C (4) D 156. Assertion :- Ni(CO) 4 is an organometallic compound. Reason :- The geometry of Ni(CO) 4 is tetrahedral. (1) A (2) B (3) C (4) D 157. Assertion :- Aufbau rule is violated in writing electronic configuration of Pd. Reason :- Pd shows diamagnetic nature. (1) A (2) B (3) C (4) D 158. Assertion :- CH 3 OH and Benzyl magnisium halide give toluene. Reason :- CH 3 OH is less acidic than toluene. (1) A (2) B (3) C (4) D 150. + · | -:- ( l =º - i n | : ÷ ( - i n i - = º ¤ | · | - | | · i ¤ t + + | · º | :- ( - i n i - + | ( =i º i n i + · º | + · | - = : n + º ™ | - · | - · ¤ ~ l · | + t | ¤| - | t + (1) A (2) B (3) C (4) D 151. + · | - :- k ¤ 1/T + n · ¤ ª | + · º | i ¤ t | - | t + + | · º | :- E /(RT) k A.e o ÷ = (1) A (2) B (3) C (4) D 152. + · | -:- : · | · + | ¤ · | + | º | - - · + n i ¤ + | º | = + n t | - | t + + | · º | :- : =n · | ¤ ÷ (–R) =n ¸ t | + | ¤ l - + · | º | t + (1) A (2) B (3) C (4) D 153. + · | - :- ~ | ¤ - i + · º | n Mn ~ ¤ - ns electrons + | (n –1)d electrons + i - n - | n ~ | =| - i = l - + | n - | t + + | · º | :- ns electron + i - n - | n (n-1)d electrons + | ¤ · | | ¤ i - | l · | + i ¤ ~ | ¤ z| ~ l · | + t + (1) A (2) B (3) C (4) D 154. + · | - :- CuO n Cu + | - - ¤ | + i · | | · 31.8 t ~ | · Cu 2 O n 63.6 t + + | · º | :- l + =i - · ¤ + | - - ¤ | + i · | | · = - · ¤ + | ¤ · n | º | · | | · - · ¤ + i = ¤ | ¤ + - | (1) A (2) B (3) C (4) D 155. + · | - :- K 2 CrO 4 ( + ¤ i n · ª + | ¤ | l ª + t + + | · º | :- + | n º ~ | ¤ - + i º ¤ | l n - i - - · + n + i ¤ t | - i t + (1) A (2) B (3) C (4) D 156. + · | - :- Ni(CO) 4 ( + + | ¤ · | | l · ¤ + ¤ | l ª + t + + | · º | :- Ni(CO) 4 + i º ¤ | l n l - - - · + n + i ¤ t + (1) A (2) B (3) C (4) D 157. + · | - :- Pd + | l ¤ - ¤ | = l n º | - =n ¤ Aufbau l - ¤ n + i ~ ¤ t n - | t | - i t + + | · º | :- Pd + | ¤ l - - - ¤ + i ¤ ª º | t + (1) A (2) B (3) C (4) D 158. + · | - :- CH 3 OH - · | | ¤ l - ¤n n l · - l z| ¤ n t n | : ÷ , º | n ¸ : - · - t + + | · º | :- CH 3 OH , º | n ¸ : - = + n ~ - n i ¤ t + (1) A (2) B (3) C (4) D 22–05–2014 TARGET : PRE-MEDICAL 2014 28/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST AIIMS 159. Assertion :- Both NH 3 and H 2 O molecules have pyramidal shape. Reason :- Bond angles in both the molecules are same. (1) A (2) B (3) C (4) D 160. Assertion :- When o-D glucose [Specific rotation + 112.2º) dissolve in water. It specific rotation decrease from + 112. 2º up to a constant value + 52.4º. Reason :- In aquous solution glucose exist in equilibrium with cyclic hemiacetal form as well as open chain structure. (1) A (2) B (3) C (4) D 161. Assertion :- Light year and year, both measure time. Reason :- Because light year is the time that light takes to reach the earth from the sum. (1) A (2) B (3) C (4) D 162. Assertion : Two tuning forks having frequencies 410 Hz and 524 Hz are kept close and made to vibrate. Beats will not be heard. Reason : Sound wave super impose only when the frequencies of superposing waves are equal or nearly equal. (1) A (2) B (3) C (4) D 163. Assertion :- Aeroplanes are made to run on the runway before take off, so that they acquire the necessary lift. Reason :- According to Beronoulli's theorem, as velocity increases pressure decreases and viceversa. (1) A (2) B (3) C (4) D 164. Assertion : Gravitational force between two particles is negligibly small compared to the electrical force. Reason : The electrical force is experienced by charged particles only. (1) A (2) B (3) C (4) D 165. Assertion : The difference in the value of acceleration due to gravity at pole and equator is proportion to square of angular velocity of earth. Reason : The value of acceleration due to gravity is minimum at the equator and maximum at the pole. (1) A (2) B (3) C (4) D 159. + · | - :- NH 3 , H 2 O · | - | l ¤ l · l n ÷ i ¤ ~ | + | · t | - | t + + | · º | :- · | - | n ¤ · | + | º | =n | - t (1) A (2) B (3) C (4) D 160. + · | - :- ¤¤ o-D · n + | = [ l ¤ l z | · º · | ¸ º | - + 112.2º) ¤n n · | | n | ¤| - | t - | : =+ | l ¤ l z | · º · | ¸ º | - + 112.2º = l - ¤ - n | - + 52.4º - + · | º - | t + + | · º | :- ¤n i ¤ l ¤ n ¤ - n · n + | = - l + ¤ t n i ( =i º n ª¤ - · | | º | n i ¬ º | n | = · - - | n =| - ¤ ª¤ = ~ l ª - · ¤ · º | - | t + (1) A (2) B (3) C (4) D 161. + · | -:- ¤ + | z| ¤ · | ( ¤ ¤ · | · | - | =n ¤ + | n | ¤ - + · - t + + | · º | :- + ¤ | l + ¤ + | z | ¤ · | ¤ t =n ¤ t ¤| ¤ + | z | =¸ ¤ = ¤ · ¤ i - + ¤ t - - n n - | t + (1) A (2) B (3) C (4) D 162. + · | - : 410 Hz - · | | 524 Hz ~ | ¤ l Ÿ | ¤ | ¤ | n · | ª ¤ l · z | + | l - + º · º | | ª ¤ | t - · | | - - t + - ¤ i - + · ¤ | ¤ | ¤| - | t - | l ¤ ª ¤ · - t i = - | : · ª + | · º | : · ¤ l - - · ª n ~ · ¤ | · | ¤ º | + ¤ n - ¤ t i t | - | t ¤¤ ~ · ¤ | · | l ¤ - t | - ¤ | n i - · ª | + i ~ | ¤ l Ÿ | ¤ | =n | - ¤ | n ª · | ª =n | - t | + (1) A (2) B (3) C (4) D 163. + · | -:- - ÷ | - · | · - + ¤ ¸ ¤ ¤ | ¤ ¤ | - · - ¤ : t ¤ | : ¤ ¿ i | ¤ · · | ÷ - t , - | l + ¤ | ¤ ¤ | - ~ | ¤ z ¤ + - a | ¤ ¤ | - - + · =+ + + | · º | :- ¤ · - | n i ¤ n ¤ + ~ - =| · , ¤ = t i ¤ ª ¤ · - | t , · | ¤ · | º ¤| - | t ~ · | ¤ | : =+ | l ¤ ¤ · i - · | i =· ¤ t | - | t + (1) A (2) B (3) C (4) D 164. + · | - : · | + º | | + ¤ i - n ª - ¤ | n | ª ª· ¤ | + · | º | ¤ n ¤ ¤ - ¤ n + i - n - | n - ª º ¤ t | - | t + + | · º | : ¤ ¤ - ¤ n + ¤ n ~ | ¤ l z | - + º | | , | · | t i ~ - · | ¤ l + ¤ | ¤| =+ - | t + (1) A (2) B (3) C (4) D 165. + · | - : ª ª · ¤ i ¤ · ¤ · º | + · | ¤ ¤ · | ¸ n · ¤ · º | | + n | - n ~ - · ¤ · ¤ i + + | º | i ¤ ¤ ª + ¤ ª + =n | - ¤ | - i t | - | t + + | · º | : ª ª · ¤ i ¤ · ¤ · º | + | n | - · | ¸ n · ¤ · º | | ¤ · - ¤ ¸ - - n ¤ · | ¤ | ¤ · ~ l · | + - n t | - | t + (1) A (2) B (3) C (4) D 22–05–2014 29/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 PRE-MEDICAL : ENTHUSIAST, LEADER & ACHIEVER COURSE MAJOR TEST AIIMS 166. Assertion :- Upon displacement of a charge within a closed surface, E at any point on the surface will change. Reason :- The flux crossing through a closed surface is independent of the location of charge within the surface. (1) A (2) B (3) C (4) D 167. Assertion : Aeroplanes always fly at low altitudes. Reason : According to Newton's third law of motion, for every action there is an equal and opposite reaction. (1) A (2) B (3) C (4) D 168. Assertion :- Direction of current cannot be from negative potential to positive potential. Reason :- Direction of current is opposite to the flow of electrons. (1) A (2) B (3) C (4) D 169. Assertion :- Mechanical energy of a body or a system can be negative. Reason :- Potential energy of a body can be negative and in magnitude it can be more then kinetic energy . (1) A (2) B (3) C (4) D 170. Assertion :- A bulbs and air core solenoid is connected in series with dc source, if iron is placed inside solenoid, then final brightness of bulb remains unchanged. Reason :- On inserting iron core insolenoid, resistance of circuit remains unchanged (1) A (2) B (3) C (4) D 171. Assertion : A particle strikes head-on with another stationary particle such that first particle comes to rest after collision. The collision should necessarily be elastic. Reason : In an elastic collision between two bodi es, momentum of indivi dual bodies remains conserved. (1) A (2) B (3) C (4) D 172. Assertion :- When D. C. current flow in conducting rod, magnetic field produces only outside the rod. Reason :- No charge flow inside the rod. (1) A (2) B (3) C (4) D 166. + · | -:- ( + ~ | ¤ z| ¤ - · ¤ · a + ~ - · · l ¤ ª · | | l ¤ - + · - ¤ · , ¤ · a + l + =i l ¤ - · ¤ · E + | n | - ¤ · n ¤| ¤ ª | + + | · º |:- ¤ - · ¤ · a = ¤ l · - ∂ n + = ¤ · a + ~ - · · ~ | ¤ z | + i l ª · | l - ¤ · l - · | · - t i + · - | t + (1) A (2) B (3) C (4) D 167. + · | -: ¤ | ¤ ¤ | - t n z | | + n ≈ - | : ¤ · - ÷ - t + + | · º | : - ¤ ¸ º - + - - i ¤ l - ¤ n + ~ - =| · , ¤ · ¤ + l + ¤ | + ¤ · | ¤ · - · | | l ¤ ¤ · i - ¤ l - l + ¤ | t | - i t + (1) A (2) B (3) C (4) D 168. + · | - :- · | | · | + i l · z | | Ωº | | · n + l ¤ · | ¤ = · | - | · n + l ¤ · | ¤ + | ~ | · - t i t | =+ - i t + + | · º | :- · | | · | + i l · z | | : n + º ™ | - + ¤ ¤ | t + l ¤ ¤ · i - t | - i t + (1) A (2) B (3) C (4) D 169. + · | -:- l + =i ¤ ª - ¤ | l - + | ¤ + i ¤ | l z + ≈¤| Ωº | | · n + t | =+ - i t + + | · º |:- ¤ ª - + i l ª · | l - ¤ ≈¤| Ωº | | · n + t | - · | | ¤ l · n | º | n ª l - ¤ ≈¤| = ~ l · | + t | =+ - i t + (1) A (2) B (3) C (4) D 170. + · | -:- ( + ¤ - ¤ - · | | ¤ | ¤ + l - : - ¤ l · - | l n + | + | ¬ º | i + n n (+ l · · º · | | · | n | - = = ¤ | l ¤- l + ¤ | t + ¤ l · ¤ l · - | l n + | n n | t + i ¤ ÷ · º | · i ¤| ( - | ¤ - ¤ + i - n + ~ ¤ l · ¤ l - - · t - i t + + | · º | :- ¤ l · - | l n + | n n | t + i ¤ ÷ ¤ l ¤ · º + · | - ¤ · ¤ l · ¤ · | + | ¤ l - · | · | ~ ¤ l · ¤ l - - · t - | t + (1) A (2) B (3) C (4) D 171. + · | -: ( + + º | l ¤ · | n n l ª · | - ( + ~ - ¤ ( + =n | - + º | = =i · | : = ¤ + | · º + · | - | t l + º + + · + ¤ z- | - ¤ t n | + º | l ¤ · | n | ¤ ª · | | n ~ | ¤| - | t + : = l ª · | l - n º + + · + | ¤ · ¤ | ª · | t | - | ~ | ¤ z ¤ + t + + | · º | : · | ¤ ª - ~ | + i ¤ · ¤ | ª · | º + + · n · | - | ¤ ª - ~ | + | = ¤ ª ¤ · | + ª¤ = = · l - | - · t - | t + (1) A (2) B (3) C (4) D 172. + · | -:- ( + · | | l · ¤ + ¤ ÷ = l · · º · | | · | ¤ t - i t - | ¤ t + ¤ n ¤ ÷ + ¤ | t · - - ¤ + i ¤ - | z - · ¤ - - + · - i t + + | · º | :- ¤ ÷ + ~ - · · ~ | ¤ z| ¤ | t + | + | + | : ¤ ¤ | t - t i t | - | t + (1) A (2) B (3) C (4) D 22–05–2014 TARGET : PRE-MEDICAL 2014 30/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST AIIMS 173. Assertion :- A body rolling without slipping has only rotational kinetic energy. Reason :- The centre of mass of a rolling body does not move forward. (1) A (2) B (3) C (4) D 174. Assertion :- If objective and eye lenses of a microscope are interchanged then it can work as telescope. Reason :- The objective of telescope has very large focal length as compared to eye lens. (1) A (2) B (3) C (4) D 175. Assertion :- A room can be cooled by opening the door of a refrigerator in a closed room. Reason :- Heat flows from lower temperature (refrigerator) to higher temperature (room). (1) A (2) B (3) C (4) D 176. Assertion :- Transparent film having thickness of the order of a few centimeters does not show interference pattern. Reason :- To observe interference pattern the path difference between the waves should be of the order of a few wavelength. (1) A (2) B (3) C (4) D 177. Assertion :- As temperature of a black body is raised, wavelength corresponding to maximum energy reduces. Reason :- Higher temperature would mean higher energy and hence higher wavelength. (1) A (2) B (3) C (4) D 178. Assertion :- z X A undergoes 2o –decays, 2| –decays and 2¸ – decays and the daughter product is z – 2 Y A – 8 . Reason :- In o-decay the mass number decreases by 4 and atomic number decreases by 2. In |-decay the mass number remains unchanged, but atomic number increases by 1 only. (1) A (2) B (3) C (4) D 179. Assertion :- If the amplit ude of simple harmonic motion is doubled its total energy become four times. Reason :- The total energy directly proportional to the square of the amplitude of vibration of the harmonic motion. (1) A (2) B (3) C (4) D 173. + · | -:- l ¤ - | l + =n n | º - i ª l - + · - i ¤ ª - + ¤ | = + ¤ n · | ¸ º | - ª l - ¤ ≈¤| t | - i t + + | · º | :- n | º - i ª l - + · - i ¤ ª - + | · · ¤ n | - + - · ~ | ª ª l - - t i + · - | t + (1) A (2) B (3) C (4) D 174. + · | -:- ¤ l · (+ =¸ - n · z| i + | ~ l · | · z¤ + - · | | - l z + | ¤ · ª ¤ · ¤ · n l · ¤ ¤| ¤ - | ¤ t · ¸ · · z | i + i · | | l - + | ¤ + · - n ª - | t + + | · º | :- ( + · ¸ · · z| i + ~ l · | · z¤ + + i + | + = · ¸ · i - l z + | + i + | + = · ¸ · i + i - n - | n ¤ t - ~ l · | + t | - i t + (1) A (2) B (3) C (4) D 175. + · | -:- l + =i ¤ - · + n · n · º | v z | i l - z + · · ¤ | ¤ + | º | | n + · + n · + | a º ÷ | l + ¤ | ¤| =+ - | t + + | · º | :- ≈· n | + n - | ¤ ( v z | i l - z ) = ~ l · | + - | ¤ ( + n · ) + i ~ | · ¤ t - i t + (1) A (2) B (3) C (4) D 176. + · | -:- ~ - ¤ n | º | : + i = n i + i ~ | ÷ · + i ¤ | · · z | i ¤ · - · ¤ l - + · º | ¤ l - ª¤ ¤ · z | i - - t i + · - i + + | · º | :- · ¤ l - + · º | ¤ l - ª¤ ¤ | - - + · - + l n ¤ - · ª | + n · ¤ ¤ · | | - · - · ª · · ¤ + + n + | t | - | - | l t ( + (1) A (2) B (3) C (4) D 177. + · | -:- l + =i œ l · º | + | + | - | ¤ ¤ · | - ¤ · ~ l · | + - n ≈¤| + = ª - - · ª · · ¤ · | º ¤| - | t + + | · º | :- ~ l · | + - | ¤ + | ~ · | t | ª | , ~ l · | + ≈¤| ~ | · : =+ | ~ · | ~ l · | + - · ª · · ¤ + (1) A (2) B (3) C (4) D 178. + · | - :- z X A - | l · | + 2o, 2| ( ¤ 2¸ l ¤ · | º - | = ª ¤· - | t , - ¤ ¤ z i - | l · | + z – 2 Y A – 8 t + + | · º | :- o- l ¤ · | º - n · · ¤ n | - = º ¤ | n 4 + i + n i t | ¤| - i t ( ¤ ¤ · n | º | = º ¤ | n 2 + i + n i t | ¤| - i t + |- l ¤ · | º - n · · ¤ n | - = º ¤ | ~ ¤ l · ¤ l - - · t - i t (¤ ¤ · n | º | = º ¤ | n 1 + i ¤ l z t | ¤| - i t + (1) A (2) B (3) C (4) D 179. + · | -:- ¤ l · =· n ~ | ¤ - ª l - + | ~ | ¤ | n · ª - | + · l · ¤ | ¤| ( - | + n - · ¤| - | ª - i t | ¤| ( ª i + + | · º | :- + n - · ¤| =· n ~ | ¤ - ª l - + · | n - + ~ | ¤ | n + ¤ ª + =n | - ¤ | - i t | - i t + (1) A (2) B (3) C (4) D 22–05–2014 31/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 PRE-MEDICAL : ENTHUSIAST, LEADER & ACHIEVER COURSE MAJOR TEST AIIMS 180. Assertion :- Current gain for common base configuration is less then one and for common emitter configuration greater then one. Reason :- In transistor I E > I C >> I B (1) A (2) B (3) C (4) D 181. When is World Cancer Day observed ? (1) 4 th March (2) 4 th February (3) 1 st April (4) 1 st May 182. Thomas cup is associated with which of the following sports ? (1) Table Tennis (2) Lawn Tennis (3) Badminton (4) Football 183. Which country is the largest producer of tea in the world ? (1) India (2) China (3) Kenya (4) Sri Lanka 184. Which one is the smallest ocean in the world:- (1) Indian (2) Atlantic (3) Arctic (4) Pacific 185. What was the name of Arjuna in the thirteenth year of his exile at king Virat's Kingdom ? (1) Uttara (2) Brihannala (3) Urvashi (4) Sathyavathi 186. Who build t he palace for Pandavas at Khandavprastha ? (1) Vishwakarma (2) Mayasura (3) Krishna (4) Balaram 187. Which of the following pairs is not correct ? (1) Birbal Sahni - Paleobotanist (2) Sir CV Raman - Physicist (3) Sir JC Bose - Physicist - Botanist (4) Ramanujan Srinivasa - Chemist 188. What does white colour in our National Flag stands for ? (1) Courage (2) Renunciation (3) Truth and Peace (4) Faith 189. Which state of India has negative population growth rate as per Census 2011:- (1) Nagaland (2) Tripura (3) Arunachal Pradesh (4) Goa 180. + · | - :- - · | ¤ l - · a ~ | · | | · ~ l · | l · | - ¤ | = + | · | | · | n | · | ( + = + n - · | | - · | ¤ l - · a - · =¤ + ~ l · | l ¤ - ¤ | = + | · | | · | n | · | ( + = ~ l · | + t | - | t + + | · º | :- º ™ | l ¤ª º · n I E > I C >> I B (1) A (2) B (3) C (4) D 181. l ¤ z ¤ + - =· l · ¤ = + ¤ n - | ¤ | ¤| - | t ? (1) 4 n | - (2) 4 + · ¤ · i (3) 1 ~ ¤ n (4) 1 n : 182. · | | n = + ¤ l + = º | n = =- ¤ l - · | - t ? (1) º ¤ n º l - = (2) n | - º l - = (3) ¤ ÷ l n - º - (4) + º ¤ | n 183. l ¤ z ¤ n - | ¤ + | =¤ = ¤ ÷ | - · - | | · + · z| + | - =| t ? (1) · | | · - (2) - i - (3) + - ¤ | (4) ¬ i n + | 184. l ¤ z ¤ n =¤ = ¤ | º | n t | =| ª · + | - =| t :- (1) l t - · (2) ~ º n | l º + (3) ~ | + l º + (4) ¤ z| | - - 185. ¤ | ÷ ¤ | + l - ¤ | =- + | n + - · t ¤ ¤ · | n · | ¤| l ¤ · | º + · | º ¤ n ~ ¤ - + | + ¤ | - | n · | | ? (1) - Ÿ | · | (2) ¤ t - - n | (3) - ¤ z| i (4) =· ¤¤ - i 186. º | | ÷ ¤ ¤ ª · | n ¤ | ÷ ¤ | + l n ¤ n t n + | l - n | º | l + =- l + ¤ | · | | ? (1) l ¤ z ¤ + n | (2) n | ¤| = · (3) + · º | (4) ¤ n · | n 187. l - - - l n l º | - n = + | - =| ¤ · n = n l n - - t i t ? (1) ¤ i · ¤ n =| t - i - ¤ · | ¤ - ª ¤ l - a (2) =· =i ¤ i · n - - · | | l - + z | | ª z i (3) =· ¤ =i ¤ | = - · | | l - + z | | ª z i ¤ - ª ¤ l - a (4) · | n | - ¤- ¬ i l - ¤ | = - · =| ¤ - z | | ª z i 188. t n | · · z| + · | · º ™ i ¤ · ¤ ¤ n =+ · · ª + ¤ | l - ªl ¤ - + · - | t ? (1) =| t = (2) · ¤ | ª (3) =· ¤ ( ¤ z | | l - (4) l ¤ z¤ | = 189. ¤ · | 2011 + i ¤- ª º | - | + ~ - =| · · | | · - + l + = · | º ¤ + i ¤- = º ¤ | ¤ l z · · Ωº | | · n + t :- (1) - | ª | n º ÷ (2) l z ¤ · | (3) ~ ªº | | - n ¤ · z | (4) ª | ~ | 22–05–2014 TARGET : PRE-MEDICAL 2014 32/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST AIIMS 190. Match the following :- Author Book (A) Mahatma Gandhi (i) India Wins Freedom (B) Maulana Abul Kalam Ajad (ii) India Divided (C) Dr. Rajendra Prasad (iii) Hind Swaraj (D) Ram Manohar Lohia (iv) The wheels of History Codes A B C D (1) i ii iii iv (2) iv iii ii i (3) iii i ii iv (4) ii iii iv i 191. Dual Energy X-ray Absorptiometry (DEXA) is used to measure :- (1) Bone density (2) Spread of solid tumour (3) Ulcerous growth in stomach (4) Extent of brain haemorrhage 192. The phenomenon of Total Internal Reflection is observed in which one of the following :- (1) Twinkling star (2) Glowing tube light (3) Light passing through lens (4) Sparkling diamond 193. Which of the following is a secondary pollutant? (1) Carbon (2) Radon (3) Sulphur dioxide (4) Sulphuric acid 194. Which of the following is not a world heritage site of India :- (1) Simlipal National Park (2) Sunderban National Park (3) Kaziranga National Park (4) Manas wildlife sanctuary 195. Which one of the following states shares boundaries with the maximum number of other states of India :- (1) Madhya Pradesh (2) Bihar (3) Assam (4) Rajasthan 196. Decimal system was introduced by :- (1) Aryabhatta (2) Bhaskara (3) Brahmagupta (4) Varahamihira 190. l - - - l n l º | - + | l n n | - + i l ¤¤ :- n º | + ¤ ª - + (A) n t | · n | ª | · | i (i) : l ÷ ¤ | l ¤ - = ›i ÷ n (B) n | n | - | ~ ¤ n + n | n ~ | ¤| · (ii) : l ÷ ¤ | l ÷ ¤ | : ÷ ÷ (C) ÷ | · | ¤ - · ¤ =| · (iii) l t - · ª ¤ · | ¤ (D) · | n n - | t · n | l t ¤ | (iv) · · t i - = ~ | + l t ª º ™ i Codes A B C D (1) i ii iii iv (2) iv iii ii i (3) iii i ii iv (4) ii iii iv i 191. ÷ ¸ ¤ ¸ n ( - ¤i ( + = · ( · ¤| ¤ z | | n º ™ i (DEXA) + | ¤ ¤ | ª l + =+ n | ¤ - + l n ¤ l + ¤ | ¤| - | t :- (1) ~ l ª · | · | - · ¤ (2) a | = ª | a + | ¤ =| · (3) ¤ º n ~ - =· + i ¤ l z (4) ¤ - t n · ¤ + | l ¤ ª - | · - | z 192. l - - - n = l + =n ¤ ¸ º | ~ | - - l · + ¤ · | ¤ - - + i ¤ l · · | º - | ¤ l - | - t | - i t :- (1) - | · | + | l º n l º n | - | (2) º ¸ ¤ ¸ ¤ n | : º + | ¤n - | (3) ¤ + | z | + | n - = = ª ¤· - | (4) t i · + | - n + - | 193. l - - - n = + | - =| ( + l , - i ¤ + ¤ · ¸ · | + t ? (1) + | ¤ - (2) · ÷ | - (3) =- + · ÷ | : ~ | + =| : ÷ (4) =- ∂ ¤ ¸ l · + ~ - n 194. · | | · - + l ¤ z¤ l ¤ · | =- ª · | n | n l - - - n = + | - =| ( + =l - n l n - - t i t :- (1) l =n n i ¤ | n · | · º ™ i ¤ - ¤| - (2) = - · · ¤ - · | · º ™ i ¤ - ¤| - (3) + | ¤i · ª | · | · º ™ i ¤ - ¤| - (4) n | - = ¤ - ¤ ¤i ¤ ~ · | ¤ | · º ¤ 195. l - - - n = ¤ t · | º ¤ + | - =| t l ¤=+ i =i n | · | | · - + ~ - ¤ =¤ = ~ l · | + · | º ¤ | + =| · | ¤ ÷ i t : t :- (1) n · ¤ ¤ · z | (2) l ¤ t | · (3) ~ =n (4) · | ¤ª · | | - 196. · z | n n ¤ ¤ º | | n i + i z | ª~ | - l + =- + i · | i · (1) ~ | ¤ · | º ¸ º (2) · | | ª + · (3) ¤ t ¸ n ª - - (4) ¤ · | t l n l t · 22–05–2014 33/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 PRE-MEDICAL : ENTHUSIAST, LEADER & ACHIEVER COURSE MAJOR TEST AIIMS Your moral duty is to prove that is 197. Which of the following rulers was adorned with the title of 'Maharajadhiraj' (King of Kings) ? (1) Chandragupta Maurya (2) Ashoka (3) Chandragupta I (4) Kanishka 198. Which cricket player was banned by Anti Doping Tribunal of BCCI ? (1) S. Sreesanth (2) Ankit Chavan (3) Ajit chandila (4) Pradeep Sangwan 199. Which Indian writer was killed by Taliban in Afghanistan ? (1) Asha Devi (2) Sushmita Banerjee (3) Rita Basu (4) Anita Kumari 200. Who is the recipient of the first National Yash Chopra Memorial Award ? (1) Subhash Ghai (2) Lata Mangeshkar (3) Dilip Kumar (4) Amitabh Bachchan 197. l - - - n l + = z| | =+ + | ' n t | · | ¤| l · | · | ¤' + i - ¤ | l · | = ~ n œ - l + ¤ | ª ¤ | · | | · (1) - - : ª - - n | ¤ (2) ~ z| | + (3) - - : ª - - ¤ · | n (4) + l - · + 198. · | | · - i ¤ l + + º + º ™ | n ¤ | ÷ + ÷ | l ¤ ª · | · | i ~ | ¤ | ª , | · | l + = l + + º l º | n | ÷ i ¤ · ¤ l - ¤ - · | n ª | ¤ | ª ¤ | ? (1) ( = ¬ i = - (2) ~ l + - - · t | º | (3) ~ ¤i - - · i n | (4) ¤ · i ¤ =| ª ¤ | - 199. ~ + ª | l - ª - | - n - | l n ¤ | - , | · | l + = · | | · - i ¤ n l º | + | + i t · ¤ | + i ª : ? (1) ~ | z| | · ¤ i (2) = l · n - | ¤ - ¤i (3) · i - | ¤ | = (4) ~ l - - | + n | · i 200. l - - - n = l + = ¤ · | n · | · º ™ i ¤ ¤ z | - | ¤ ÷ | ª n l - ¤ · ª + | · = =- n | l - - l + ¤ | ª ¤ | t ? (1) = · | | · | · | : (2) n - | n ª z | + · (3) l · n i ¤ + n | · (4) ~ l n - | · | ¤ - - - 22–05–2014 TARGET : PRE-MEDICAL 2014 34/34 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST AIIMS SPACE FOR ROUGH WORK / · + + | ¤ + l n ¤ ¤ª t HINT – SHEET DATE : 22 - 05 - 2014 AIIMS # 04 TARGET : PRE-MEDICAL 2014 DATE : 10 - 01 - 2010 MAJOR TEST ENTHUSIAST, LEADER & ACHIEVER COURSE ANSWER KEY FULL SYLLABUS HS - 1/5 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 2. NCERT XI(H) Page No. 310 4. NCERT Pg.# 140, para 2 nd 6. NCERT XI(H) Page No. 285 para 3 rd 7. NCERT-XI Page No.-321-326 8. NK cells are part of innate immunitiy and are active against cancer and virus infected cells. NK + | l z| + | n ¤- n ¤| - ¤ l - · - | | + | · | | ª t ¤| + =· - · | | l ¤ · | | º | = + l n - + | l z | + | ~ | + | - · º + · =+ - i t + 10. NCERT(E) Page # 113, Para no. 7 NCERT (H) Page # 114, Para no. 8 11. NCERT-XI Page No.-332,333,334 12. Mycobacterium laprae causes leprosy whereas DOTS and Mantoux test are used for tuberculosis. n | : + | ¤ + º i l · ¤n n ¤ , + · a · | ª + · - | t ¤¤ l + DOTS ¤ n º ¸ + = º ª º , º ¸ ¤¸ ¤ · + ¤¸ n | l == : - | ¤ · | ª | + l n ¤ - ¤ ¤| ª i t + 15. NCERT XI Page # 77 16. Chemotherapeutic drugs inhibit DNA synthesis in cancer cells, so they work during S-stage. · =| l - l + · =i ¤ ~ | · | l · | ¤ | DNA = z n · | º | + | = · l n - + · - i t : =l n ¤ ¤ S ~ ¤ ª · | | n + | ¤ + · - i t + 21. NCERT-XI Page No.-52-53 22. NCERT XI Pg.# 219 23. NCERT XII Page # 184 25. NCERT-XI Page No.-56-57 27. NCERT XII Page # 199 31. NCERT XII Page # 210 33. NCERT XI(H) Page No. # 294, 3rd para 34. NCERT Pg.# 70 35. NCERT Pg.# 127, para 1 st 37. NCERT XI(H) Page No. 58, 59, 60 39. NCERT Pg.# 130 Que. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 Ans. 3 2 3 4 2 3 3 3 4 4 3 4 3 4 2 2 2 3 3 3 Que. 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 Ans. 1 4 1 1 4 2 1 2 2 4 1 4 1 4 2 4 1 4 3 4 Que. 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 Ans. 4 3 3 3 2 3 4 3 1 1 2 2 1 2 3 2 4 2 3 2 Que. 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 Ans. 1 4 3 3 3 4 1 1 2 3 1 4 1 4 2 3 4 1 1 4 Que. 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 Ans. 3 1 3 2 3 1 4 1 2 4 2 3 4 1 4 3 2 2 2 1 Que. 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 Ans. 2 1 1 1 3 3 1 2 3 3 3 1 4 4 1 2 3 4 1 3 Que. 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 Ans. 2 1 3 3 3 3 1 1 4 4 1 1 2 4 1 3 1 1 3 2 Que. 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 Ans. 2 1 2 1 4 4 3 1 3 4 4 4 1 1 2 2 1 3 4 1 Que. 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180 Ans. 4 3 1 2 2 2 1 2 1 1 4 4 4 4 4 1 3 1 1 2 Que. 181 182 183 184 185 186 187 188 189 190 191 192 193 194 195 196 197 198 199 200 Ans. 2 3 2 3 2 2 4 3 1 3 1 4 4 1 3 2 4 4 2 2 22–05–2014 TARGET : PRE-MEDICAL 2014 HS - 2/5 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST : AIIMS 41. Na 2 SO 4 .nH 2 O Molar mass = (142 + 18n) Mass of water = 12.6 26.8 × (142 + 18n) 18n = 12.6 26.8 × (142 + 18n) n = 7 42. 2 0 0 1 2 0 0 K[A ] [B ] r r K[1.5A ] [3B ] = ¬ 1 r r = 1 6.75 r 1 = 6.75 r 43. Mn 2+ Cr 2+ V 2+ No. of unpaired electrons 5 4 3 Mag. moment · No. of unpaired electrons 45. I.E. = 2 –19 2 Z 21.69 10 J n × × 3 2 –19 23 2 11180 10 Z 21.69 10 6.023 10 1 × = × × × Z 3 46. bcc z = 1 8 1 2 8 | | × + = | \ . C.N. = 8 49. (i) H 2 (g) + 1 2 O 2 (g) ÷ H 2 O() AH = – 241 kJ (ii) C 6 H 10 + 17 2 O 2(g) ÷ 6 ( g) 2 CO + 5H 2 O() AH= – 3800 kJ (iii) C 6 H 12 + 9O 2(g) ÷ 6 ( g) 2 CO + 6H 2 O() AH= – 3920 kJ (i) + (ii) – (iii) give AH = – 241 – 3800 (– 3920) = – 121 kJ 50. Ionisation enthalpy of Cl – and electron gain enthalpy of chlorine are numerically equal with opposite sign. 52. Fact 53. T 3+ + 2e – ÷ T + ; nFE° = 2 × 1.26 × F = 2.52F T + + e – ÷ T; nFE° = 1 × (–0.336) × F = –0.336 F Adding T 3+ + 3e – ÷ T E 0 = 2.52F 0.336F 2.184 nF 3 ÷ = = 0.728 V 54. O (g) + 2e – ÷ ( ) 2 g O ; AH = 639 kJ mol -1 ..(i) O (g) + e – ÷ ( ) – g O ; AH = –141kJ mol -1 ..(ii) Subtracting equation (ii) from equation (i) ( ) – g O + e – ÷ ( ) 2– g O ; AH = 639 + 141 = 780 kJ mol -1 . 57. log 2 1 1 2 k Ea 1 1 k 2.303R T T | | ( = ÷ ( | \ . ¸ ¸ Ea = 124 kJ 58. In 2 NO + , N atom has sp-hybridisation, thus, bond angle is 180°. In other species the angle is near about 120°. 60. Co 3+ , E.C. = [Ar]3d 6 x x x x x x x x x x x x d sp -hybridization 2 3 No, unpaired electron is present. Hence, paramagnetism in this complex is zero. Co 3+ , E.C. = [Ar]3d 6 x x x x x x x x x x x x d sp - 2 3 = + · º | ( + · | i ~ ¤ l · n - : n + º ™ | - - t | - + + | · º | , ¤ | l ª + + | ~ - - - ¤ + · ¤ z | ¸ - ¤ t | ª | + 64. Higher the oxidation state of the metal, greater is the crystal field splitting. The species(C) is in +3 oxidation state while others are in +2 state. ~ | + =i + · º | = º ¤ | ~ l · | + t | - ¤ · l + ª º n - | z l ¤ ¤ | º - · | i ~ l · | + t | ª | + C n +3 ~ | + =i = º ¤ | t , ¤¤ l + ~ - ¤ n +2 + 66. 2LiNO 3 ÷ Li 2 O + 2NO 2 + 2 1 O 2 Li 2 CO 3 ÷ Li 2 O + CO 2 2LiOH ÷ Li 2 O + H 2 O 69. K C = a h w 1 K K K = 70. Gallium expands by about 3% when it solidifies. 73. t = (iC 1 –i 2 C 2 ) RT ¬ (1 × 0.2 – 3 × 0.05) 0.0821 × 300 ¬ 1.23 atm 77. t = i C R T t · i C T (1) 0.011 × 4 × 323 = 14.2 (2) 0.03 × 2 × 298 = 17.8 (3) .012 × 3 × 298 = 10.7 (4) 0.03 × 2 × 323 = 19.4 option (4) has max value of t 22–05–2014 PRE-MEDICAL : ENTHUSIAST, LEADER & ACHIEVER COURSE HS - 3/5 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST : AIIMS 78. K 2 Cr 2 O 7 +3Na 2 SO 3 + 4H 2 SO 4 ÷ K 2 SO 4 + 3Na 2 SO 4 + Cr 2 (SO 4 ) 3 + 4H 2 O Green 81. % error in length = 1mm 100cm × 100 = 0.1% % error in time = 0.1sec 200sec × 100 = 0.05% % error in g = % c in + 2 times (% c in T) = 0.2% 82. The two blocks moves together with acceleration 50 a 30 20 = + 20 kg 30 kg F = 50 N f f a = 1 m/s 2 Friction force on upper block = f = ma = 20 × 1 = 20 N f max = µmg = 0.5 × 20 × 10 = 100 N Thus no slipping occurs Distance travelled = S = ut + 2 1 at 2 2 1 0 1 (2) 2 = + × × = 2m Work = F S (F) (S) cos 0 · = ° = (20) (2) (1) = 40 J 84. X L = eL 85. h = 1 cos 30° = 2 cos 60° 1 2 cos60 1 cos60 3 ° = = ° 86. The bullet and block will meet after time, rel h 100 t v 100 = = = 1sec. distance travelled by block during this time S = 1 2 gt 2 = 5m distance travelled by bullet, 100 – 5 = 95 m Velocity of bullet before collision ¬ v 1 = u – gt = 100 – 10 × 1 = 90 m/sec Velocity of block before collision ¬ v 2 = gt = 10 m/sec m 1 v 1 + m 2 v 2 = (m 1 +m 2 )v ¬ 1 1 2 2 1 2 m v m v v 40m / sec m m + = = + max. height reached by block = 2 v 80 m 2g = from the top of tower = 80 – 5 = 75 m 88. A plano-convex lens with its silvered plane surface behaves like a concave mirror of focal length l l l m m 1 1 1 1 2 1 F f f f f f = + + = + = 2 1 1 10 10 + = · or F = 10 cm 89. AP = Mg V r K K 3 A V r A A | | = ÷ = ÷ | \ . 92. On joining the plane surfaces of two identical plano-convex lenses the biconvex lens so formed has focal length ( ) 1 2 1 1 1 µ 1 F R R | | = ÷ ÷ | \ . where, R 2 = – R 1 = R or 1 F = ( ) 2 1 R µ ÷ ..(i) For each plano-convex lens, ( ) 1 1 1 1 1 f R R µ ÷ ( = µ÷ ÷ = ( · ¸ ¸ ..(ii) From eqs. (i) & (ii), we get 1 2 2 1 F f 50 25 = = = or F = 25 cm For obtaining a real, inverted image of the object size, the object must be placed at a distance R = 2F = 2 × 25 = 50 cm 95. Distances of the satellite from the centre are 7R and 3.5R respectively. | | | | = ¬ = = | | \ . \ . 3/ 2 3/ 2 2 2 2 1 1 T R 3.5R T 24 6 2 hr T R 7R 22–05–2014 TARGET : PRE-MEDICAL 2014 HS - 4/5 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST : AIIMS 96. µ = tan i p µ = 3 Since, µ = C V ; V = × = × 8 8 3 10 3 10 m/ s 3 99. Final charge on capacitor q f = CE Charge flown = CE – CE/2 = CE/2 Work done by battery: W b = E (CE/2) = 1 2 CE 2 Change in energy of capacitor is AU = 2 2 f 0 1 q – q 2C ( ¸ ¸ = 1 2C ( ) 2 CE – (CE/ 2) 2 ( ¸ ¸ = 2 3CE 8 Heat = W b – AU = 2 1 CE 8 100. Linear width of central maximum w x = ÷ ÷ ì × × × = × 10 3 2 D 2 6000 10 2 a 1 10 w x = 2.4 mm 102. d dT KA dt dr | = ÷ = – 2 dT K4 r dr t 2 1 r 2 r d dr dt r | } = 2 1 T T 4 K dT ÷ t } 1 2 1 2 r r d dt r r | · ÷ 103. Potential difference across AC is zero. r = 1 O E = 10 V E = 5 V r = 2 O G C A B 5 – 2I = 0 I = 2.5 A Let the resistance of part BC be r Applying KVL, we get 10 + 5 – 2I – Ir – I = 0 2.5r = 7.5 ¬ r = 3 O All resistance of part AB = 9O, length AC = 66.7 cm 104. a X b (n,P) 15 P 32 a X b + 0 n 1 ÷ 1 P 1 + 15 P 32 b + 1 = 33 ¬ b = 32 a + 0 = 16 ¬ a = 16 105. B Ground A f AB f BG F F = f AB + f BG = µ AB m a g + µ BG (m A + m B ) g = 0.2 × 100 × 10 +0.3(300) × 10 = 200 + 900 = 1100 N. 107. Electric field due to semicircular part. E 2 = 2 0 2 R ì tc R E 1y ì 1 E 2 ì 2 E 1x Electric field due to straight part : E 1x = E 1y = 1 0 4 R ì tc For the net field to be along the y-axis : E 2 = E 1x ¬ 2 1 1 0 0 2 2 R 4 R ì ì ì = ¬ tc tc ì = 2 108. ev 0 = E–| = 13.6 – 4.2 ev 0 = 9.4 ev v 0 = –9.4 v 109. 45° N 2 0 0 g s i n 4 5 ° 2 0 0 g c o s 4 5 ° 2 0 0 k g fr nF Let n number of men are required for the block to just start up the plane nf = mgsin u + f r n = 5 22–05–2014 PRE-MEDICAL : ENTHUSIAST, LEADER & ACHIEVER COURSE HS - 5/5 Your Target is to secure Good Rank in Pre-Medical 2014 01CM413099 MAJOR TEST : AIIMS 110. F = dm dx ÷ = –2bx a = f m = 2b m ÷ x ¬ –w 2 x w = 2b m F = 1 2b 2 m t 111. L = Rsin 2 o + Rsin 2 o = 2Rsin 2 o m F BI L = 2BI R sin o/2 L A B R R o/2 o/2 113. F = (7 – 2x + 3x 2 ) N x = 5 W = x 5 x 0 Fdx = = } W = ( ) 5 2 0 7 2x 3x ÷ + } dx W = 5 2 3 0 7x x x ( ÷ + ¸ ¸ W = [(35 – 25 + 125) – 0 ] W = 135 J 114. F = Kx 500 = 20 K 100 × ¬ K = 2500 N/m T = m 2 k t ¬ .6 = m 2 2500 t m = 22.8 kg 115. t = MB H sinu 117. According to law of conservation of momentum 0 = m 1 v 1 + m 2 v 2 K 2 = ( ) ( ) 2 2 2 2 2 2 2 2 2 1 1 2 2 2 2 3 16 1 1 m v m v m v 192J 2 2 m 2m 2 6 × = = = = × 118. L T 2 Y T T stress v , v m r = = = = µ µ t µ L T v Y v stress = Stress = 11 7 2 2 4 L T Y 10 10 N/ m 10 v v = = | | | \ . 119. V L = + di L dt = +2 d dt (10e –4t ) = –80e –4t Now V a – iR – Ldi dt = V b V a – V b = iR + Ldi dt = 40 e –4t – 80 e –4t = –40 e –4t 125. NCERT-XI (E) Page No.-53 126. NCERT XII Page # 26 133. NCERT XI Pg.# 237 157. Pd has 4d 10 5s 0 configuration rather than 4d 8 5s 2 configuration and thus, it is diamagnetic in nature. 164. For two electron ÷ = g 43 e F 10 F i.e. gravitational force is negligible in comparison to electrostatic force of attraction. 174. The focal length of lenses in microscope are very small of the order of few cm and the difference f 0 - f e is also very samll. While the telescope objective has a very large focal length as compared to the eye lens of microscope therefore we cannot interchange the objective and eye lens of a microscope to make a telescope. 179. TE = 2 1 KA 2 E · a 2