1. (07.01) What is the solution to the equation 9(x – 2) = 27? (1 point) x = 2.5 x = 0.5 x = –0.5 x = 3.5 2. (07.01) What is the solution to the equation = 4(m + 2)? (1 point) m =– m =– m= m= 3. (07.01) The value of a dirt bike decreases by 20% each year. If you purchased this dirt bike today for $500, to the nearest dollar how much would the bike be worth 5 years later? (1 point) $84 $119 $164 $222 4. (07.01) What is the exponential function modeled by the following table? x f(x) 2 5 3 4 9 17 (1 point) f(x) = 2x The population can be modeled by f(x) = 15(2)x and f(6) = 960.01) The amount of a radioactive isotope decays in half every year. This can be modeled by f(x) = 4(3) x and f(5) = 972.400 . What does the 173 represent? (1 point) The starting amount of the isotope The amount of the isotope after one year The rate the isotope decreases The number of years that have passed 7.01) The population of a species of rabbit triples every year.01) A painting is purchased for $350. (07. What is the value of the painting ten years after its purchase? (1 point) $1. What does the 15 represent? (1 point) The population after six weeks The starting population The rate the population increases The number of weeks that have passed 6. then its value is given by the function V(t) = 350 • 2t/5. (07.000 $1. (07. What does the 3 represent? (1 point) The starting population of the rabbits The population of the rabbits after five years The rate the population increases The number of years that have passed 8. If the value of the painting doubles every 5 years. (07. where t is the number of years since it was purchased and V(t) is its value (in dollars) at that time.f(x) = 2x + 1 f(x) = 3x f(x) = 3x + 1 5.01) The frog population at a lake doubles every three weeks. The amount of the isotope can be modeled by f(x) = 346( )x and f(1) = 173. 22)x where .460 last year and has been increasing by 1.800 $2.35 is the rate of growth f(x) = 1. once a year. at a rate of 22%.$1. How can Wes develop a function to model this? (1 point) f(x) = 3460(1.22 is the interest rate A(x) = 750(1 + 22)x where 22 is the interest rate 11. How can George set up a function to track the amount of money he has? (1 point) A(x) = 750(1 + .35 where 3460 is the rate of growth 10. (07. (07. The population was 3.02) If Joe wanted to create a function that modeled a base of 8 and what exponents were needed to reach specific values.22)x where .02) What is the logarithmic function modeled by the following table? x f(x) 8 16 3 4 32 5 (1 point) f(x) = logx2 f(x) = log2x f(x) = 2 log10x f(x) = x log102 12.35)x where 1.35 times each year. (07.35(3460)x where 3460 is the rate of growth f(x) = 3460(x)1. how would he set up his function? (1 point) f(x) = x8 .000 9.35 is the rate of growth f(x) = (3460 • 1.35)x where 1.22 is the interest rate A(x) = 750(22)x where 22 is the interest rate A(x) = 750(. George puts $750 in the account as the principal.01) Wes has been tracking the population of a town. (07.01) A savings account compounds interest. (1 point) log4x = 64 log464 = x log644 = x log64x = 4 14.02) What is the solution of log2x + 727 = 3? (1 point) x = –2 x=2 x=3 x=4 17.02) Express 64 = 4x as a logarithmic equation. (07. (07.02) What is the solution of log2x + 3125 = 3? (1 point) x= x=1 x= x=4 16.f(x) = log8x f(x) = logx8 f(x) = 8x 13.03) . (1 point) log3x = 2 log32 = x log23 = x log2x = 3 15.02) Express 32 = x as a logarithmic equation. (07. (07. (07. 5 1.04) The function f(x) = 10(5)x represents the growth of a lizard population every year in a remote desert.1 r = 2.726 8 18.01% 1% 1. A(x) = P(1.04) Given an exponential function for compounding interest.1 r=0 r = 0. Which function is correct for Crista's purposes? (1 point) f(x) = 10(52) .010 0.01) x. not every year.1 20. what value for r will make the function a decay function? (1 point) r = –2.03) Which of the following is equivalent to log507 rounded to three decimal places? (1 point) 2. (07. what is the rate of change? (1 point) 0. (07.Which of the following is equivalent to log432? (1 point) 0.01% 10% 21.04) Given the exponential function A(x) = P(1 + r) x. (07. Crista wants to manipulate the formula to an equivalent form that calculates every halfyear. (07.4 2.615 –0.497 –0.854 19. 867 x ≈ 4.154 24.376 x = 0.04) What is the solution to the equation 21 x–3 = 14? (1 point) x ≈ –2.295 x = –0.f(x) = (5)x f(x) = 10(5)x f(x) = 10( )2x 22. (07.295 x = –0.133 x ≈ –1.04) What is the solution to the equation 9 3x ≈7? (1 point) x = 0.06) .846 x ≈ 3. (07.376 25.04) What is the logarithmic form of the equation e 2x ≈1732? (1 point) ln 1732 = 2x log2x1732 = e 2 logxe = 1732 ln 2x = 1732 26. (07. (07. (07. Which of the following equations would be equivalent to his original expression? (1 point) 6 log 3x = log 18 3 log 6 = x log 18 x log 3 = 6 log 18 3x log 6 = log 18 23.04) Phillip is using logarithms to solve the equation 63x = 18. Which of the following represents the graph of f(x) = 27. (07.06) What function is represented below? ? (1 point) . which one will have the highest y-intercept? f(x) Blake is tracking his savings account with an interest rate of 5% and a original deposit of $6. (07.(1 point) f(x) = f(x) = +2 f(x) = f(x) = –2 28.06) Given four functions. g(x) h(x) x g(x) 1 6 j(x) j(x) = 10(2)x 2 8 3 12 (1 point) f(x) g(x) . j(x). h(x). j(x). f(x) g(x) g(x) = 3(20)x h(x) Al is monitoring the decay of a population of fungi. g(x).25 (1 point) g(x). The population started at 14. (07.00 2 2. j(x).50 3 1. f(x) 30. j(x) x j(x) 1 5.h(x) j(x) 29. f(x) f(x). f(x) h(x). calculate the average rate of change from x = 0 to x = 1. place them in order of their y-intercept. h(x). g(x). It is reducing in half every four weeks. . from highest to lowest.06) For the graphed exponential equation. h(x) j(x). g(x). (07.06) Given four functions. calculate the average rate of change from x = 1 to x = 4.06) For the graphed exponential equation.(1 point) 3 4 31. (1 point) – . (07. (07.5) x to its new appearance shown in the graph below? . (07.– – – 32.06) What transformation has changed the parent function f(x) = (.06) What transformation has changed the parent function f(x) = 3(2) x to its new appearance shown in the graph below? (1 point) f(x) + 2 f(x) + 4 f(x + 2) f(x + 4) 33. 07) Which of the following represents the graph of the function f(x) = log 3(x+2)? (1 point) . (07.(1 point) f(x) – 2 f(x + 2) f(x) + 1 –1 • f(x) 34. 35.07) Which graph represents the function f(x) = log10(x + 2)? (1 point) . (07. (07.07) What function is graphed below? (1 point) f(x) = log (x – 3) f(x) = log (x + 3) f(x) = log x + 3 f(x) = log x – 3 36. . 48 y ≈ 0.07) Using the graph of f(x) = log10x below.01 y ≈ 1. approximate the value of y in the equation 10 y = 5. approximate the value of y in the equation 2 2y = 4.37. (07. (1 point) y ≈ 0.01 38. (07.07) Using the graph of f(x) = log2x below.70 y ≈ –2. . (1 point) y≈2 y≈1 y ≈ 0.07) What transformation has changed the parent function f(x) = log 2x to its new appearance shown in the graph below? (1 point) f(x + 3) f(x – 3) .47 y ≈ 4. (07.01 39. (07.07) What transformation has changed the parent function f(x) = log 3x to its new appearance shown in the graph below? (1 point) f(x – 2) f(x + 2) f(x) – 2 f(x) + 2 41.07) What transformation has changed the parent function f(x) = log 2x to its new appearance shown in the graph below? . (07.f(x) + 3 f(x) – 3 40. What is the population of flies after two weeks with the introduced spider? (1 point) 15 flies 23 flies 32 flies . A device is added that aids in cooling according to the function h(x) = –x – 3. (07. where x is measured in hours.5) x – 11. What will be the temperature of the metal after five hours? (1 point) –8° Celsius 26° Celsius 32° Celsius 56° Celsius 43. where x is measured in weeks. A local spider has set up shop and consumes flies according to the function s(x) = 2x + 5.(1 point) –2 • f(x) 2 • f(x) f(x) – 2 f(x) + 2 42.08) A population of flies grows according to the function p(x) = 2(4) x.08) A heated piece of metal cools according to the function c(x) = (. (07. How many points will a player need on the hardest setting of level 5? (1 point) 15 points 512 points 527 points 7680 points 45. (07. The hardest setting promises to multiply the points needed in each level according to the function h(x) = 3x. find the value of f–1(3). (1 point) f–1(32) = 0 f–1(32) = 1 f–1(32) = 5 f–1(32) = 16 46.08) Given the function f(x) = 2x. find the value of f–1(32).36 flies 44. (1 point) f–1(3) = 7 f–1(3) = 12 f–1(3) = 23 f–1(3) = 31 .08) A video game sets the points needed to reach the next level based on the function g(x) = 8(2) x + 1.08) Given the function f(x) = log3(x + 4). (07. where x is the current level. (07.